Which graph BEST represents the motion of an airplane flying with equal amounts of thrust and air resistance?

The claim that only an odd number of orbitals is possible for any electron sublevel is incorrect. There can be both odd and even numbers of orbitals, such as 1 orbital in the s subshell and 3 in the p subshell.

The statement that 'only an odd number of orbitals is possible for any electron sublevel' is not accurate according to quantum theory and the rules for assigning electrons to orbitals. In atomic structure, orbitals are spaces where electrons are likely to be found. These orbitals come in various shapes (s, p, d, f) and each type has a specific number of orbitals that can contain electrons. According to the Pauli Exclusion Principle, an orbital can hold a maximum of two electrons with opposite spins. Therefore, the s subshell has 1 orbital for 2 electrons, the p subshell contains 3 orbitals for up to 6 electrons, the d subshell consists of 5 orbitals for up to 10 electrons, and the f subshell has 7 orbitals for up to 14 electrons. This shows that the number of orbitals in a sublevel can be both even and odd.

For example, the electron configuration for fluorine is 1s² 2s² 2p⁵, illustrating how electrons fill into s and p orbitals. Furthermore, Hund's rules dictate that electrons are added to sublevels with every orbital singly occupied before any orbital is doubly occupied, reflecting the conservation of orbitals in quantum mechanics.

Final answer:

The indication of a chemical change is the transformation of one substance into another, which is represented by option C) Change in the type of substance present. It involves observable signs like temperature change, color change, light production, gas formation, and precipitate formation.

Explanation:

What indicates a chemical change is a fundamental concept in understanding reactions and transformations in chemistry. The correct answer to the student's question is C) Change in the type of substance present. This occurs when a substance is turned into another as a result of a chemical reaction. Such changes are typically hard to reverse.

Observations that help indicate a chemical change include temperature changes, light given off, unexpected color changes, formation of bubbles that aren't due to boiling, and the formation of a precipitate. A change from a liquid to a gas or a change in texture, for example, can be attributed to physical changes, which do not alter the substance's molecular composition. The student's question relates to identifying chemical changes, focusing specifically on transformations that result in new substances with different chemical properties.

Final answer:

Overheating in a hydration experiment of copper sulfate can cause decomposition of the substance, leading to an elevated calculation of water content due to additional weight loss incorrectly assumed to be water.

Explanation:

In the experiment involving hydrated copper sulfate, overheating can lead to a high calculated percent value for water because it may cause the copper sulfate to decompose further into copper oxide and sulfur dioxide, or lose additional bound water that is not part of the water of crystallisation. These additional losses are assumed to be water, resulting in an incorrect, elevated calculation of the water content. The precise weighing of starting and ending products is crucial to determine the amount of water in copper sulfate accurately.

The possible values of all quantum numbers for the electron gained by Br atom to form [tex]{\text{B}}{{\text{r}}^-}[/tex] is [tex]\boxed{n=4,\;l=1,\;{m_l}=1,\;{m_s}=-\frac{1}{2}}[/tex]

Further explanation:

Quantum numbers:

Quantum numbers govern the size, energy, shape, and orientation of an orbital. The four quantum numbers are as follows:

1. Principal Quantum Number (n): It denotes the principle electron shell. The values of n are positive integer (1, 2, 3,…).

2. Angular Momentum Quantum Number (l): It represents the shape of an orbital. The value of l is an integer from 0 to (n-1). (Refer to the table in the attached image)

3. Magnetic Quantum Number[tex]\left( {{m_l}} \right)[/tex]: This quantum number represents the orientation of the orbital in space. The value of [tex]{m_l}[/tex]lies between –l to +l. The formula to calculate the value of [tex]{m_l}[/tex] is as follows:

[tex]{m_l}=-l,(-l+1),.....,0,1,2,.....,(l-1),l[/tex]

Therefore, the total number of [tex]{m_l}[/tex] values for a given value of l is 2l+1.

4. Electron Spin Quantum Number[tex]({m_s})[/tex]: It represents the direction of the electron spin. Its value can be [tex]+ \frac{1}{2}[/tex]or[tex]- \frac{1}{2}[/tex].

The atomic number of bromine (Br) is 35 and its electronic configuration is [tex]\left[ {{\text{Ar}}} \right]\;3{d^{10}}4{s^2}4{p^5}[/tex]. When it gains an electron, it forms [tex]{\text{B}}{{\text{r}}^ - }[/tex] whose electronic configuration becomes [tex]\left[ {{\text{Ar}}} \right]\;3{d^{10}}4{s^2}4{p^6}[/tex].

The principal electron shell in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 4p. So its principal quantum number for the added electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 4.

The angular momentum quantum number for p orbital is 1. So the value of l for the added electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 1.

The value of magnetic quantum number for the electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] ranges from -1 to 1, including 0. But by convention this electron is added to [tex]{p_z}[/tex] orbital so the value of [tex]{m_l}[/tex] for the added electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 1.

The spin quantum number has two values, either [tex]+ \frac{1}{2}[/tex] or [tex]- \frac{1}{2}[/tex]. But the electron added in Br is the second electron being added to [tex]{p_z}[/tex] orbital so by convention, the value of [tex]{m_s}[/tex] for the added electron in [tex]{\text{B}}{{\text{r}}^-}[/tex] is [tex]{\mathbf{ - }}\frac{{\mathbf{1}}}{{\mathbf{2}}}[/tex].

The possible set of four quantum numbers for the electron gained by Br atom to form [tex]{\text{B}}{{\text{r}}^ - }[/tex] is n = 4, l = 1, [tex]{m_l} = 1[/tex] and [tex]{m_s} =  - \frac{1}{2}[/tex].

Learn more:

1. Allowed values of [tex]{m_l}[/tex]: https://brainly.com/question/2920448

2. Calculation of volume of gas: https://brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Structure of the atom

Keywords: quantum numbers, Br, Br-, electron, 35, electronic configuration, n, l, ml, ms, principal quantum number, angular momentum quantum number, electron spin quantum number, magnetic quantum number, n = 4, ml=1, ms=-1/2, l=1.

Answer:

415.825 kJ/mol.

Explanation:

Average enthalpy = [tex]\Delta H_f(CH_4)-4\Delta H_f(H)-\Delta H_f(C)[/tex]

Now, [tex]\Delta H_f(CH_4)=-74.6 kJ/mol[/tex]

         [tex]\Delta H_f(H)=218 kJ/mol[/tex]

         [tex]\Delta H_f(C)=716.7 kJ/mol[/tex]

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Putting all these values above.

We get,

Average enthalpy=-1663.3 kJ.

Therefore, averagemolar bond enthalpy= [tex]\dfrac{1663.3 }{4}=415.825\ kJ/mol.[/tex]

Hence, this is the required solution.

For a 0.28M HCl solution, the concentration of H3O+ ions is assumed to be 0.28M due to the full ionization of strong acid. OH- concentration is obtained from the ion-product of water, and the pH is calculated from the negative log of H3O+ concentration.

The concentration of hydronium ions [H3O+] in a 0.28M solution of HCl, a strong acid, can be assumed to be 0.28M. This is due to the complete ionization of a strong acid.

The OH- concentration [OH-] can be obtained from Kw, the ion-product of water (1x10^-14 at 25 degree Celsius). Knowing [H3O+] and Kb, we can calculate [OH-] using this relationship: [H3O+].[OH-] = Kw. The pH is then calculated from the [H3O+] using the relationship pH = -log([H3O+]).

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Isotopes are the forms of same element with same atomic number but different mass number due to different number of neutrons. The name of isotope of oxygen is Oxygen-17.

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same. Different element have different types of atoms.

Oxygen-16 has atomic number 8, which means number of electron is 8 , number of proton is 8 and number of neutron is also 8. If we increase the number of neutron by 1 that is 9 then the mass number of oxygen will be increased by 1 that is 17. Now the new element is oxygen-17 which is an isotope.

Therefore, the name of isotope of oxygen is Oxygen-17.

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Data:

Hooke represented mathematically his theory with the equation:

F = K * x  

On what:

F (elastic force) = ?

K (elastic constant) = 3 N/cm

x (deformation or elongation of the elastic medium) = 2cm

Solving:

[tex]F = K * x[/tex]

[tex]F = 3\:\dfrac{N}{\diagup\!\!\!\!\!\!cm}*2\:\diagup\!\!\!\!\!\!cm[/tex]

[tex]\boxed{\boxed{F = 6N}}\end{array}}\qquad\checkmark[/tex]

Answer:

C. 6 N

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The force needed to stretch the spring 2 cm is 6 N.

Hooke's Law states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position, and this force is expressed as [tex]\( F = k \Delta x \),[/tex]  where [tex]\( F \)[/tex] is the force exerted by the spring, [tex]\( k \)[/tex]  is the spring constant (elastic constant), and [tex]\( \Delta x \)[/tex]  is the displacement from the spring's equilibrium position.

Given:

- The displacement [tex]\( \Delta x \)[/tex] is 2 cm.

- The spring constant [tex]\( k \)[/tex] is 3 N/cm.

Using Hooke's Law, we can calculate the force [tex]\( F \)[/tex] as follows:

[tex]\[ F = k \Delta x \] \[ F = (3 \, \text{N/cm}) \times (2 \, \text{cm}) \] \[ F = 6 \, \text{N} \][/tex]

Therefore, the force needed to stretch the spring 2 cm is 6 N.

To answer this question, we must first look at the reactivity series table. From the table, we can see that those which are located above are the most reactive while those below are less reactive. Which means that elements cannot replace those elements which are above them.

From the series, platinum is below lead, hence there will be no reaction.

Answer:

No reaction

Final answer:

Platinum (Pt) does not react with a lead(II) nitrate solution because of its low reactivity, indicated by its position near the bottom of the activity series, which means it will not displace lead to form a new compound.

Explanation:

Platinum metal (Pt) is a highly inert metal and does not react easily with other substances. In the activity series, which is a list of metals arranged in order of their reactivity with acids and water, platinum is near the bottom, indicating very low reactivity. Considering the context provided about reactions of lead compounds, such as the reaction of lead(II) nitrate with potassium iodide to form a precipitate of lead(II) iodide, we can infer a similar lack of reactivity would apply to platinum in this case.

While lead(II) nitrate reacts with potassium iodide to form a precipitate of lead(II) iodide, such a double-replacement reaction is not likely to occur between platinum and lead(II) nitrate. The reason is that platinum will not displace lead from its salt because lead is above platinum in the activity series. Therefore, no reaction between Pt metal and lead(II) nitrate solution would be expected. Since the question appears to be about the reaction profiles of different metals, we have determined that there is no reactive interaction between these specific substances.

Assuming that the reaction is unimolecular on both reactant and product sides such that:

HA  +  OH-   -->  A-  +  H2O

Therefore the amount of A- left is:

mmol HA = 9.00 - 3.00 = 6.00 
mmol A- = 3.00 

pKa = - log Ka = 5.25 

Calculating for pH:
pH = 5.25 + log 3.00/6.00

To calculate the resulting pH of a solution made by mixing 9.00 mmol of HA and 3.00 mmol of a strong base, you need to determine the concentrations of the acid and base, calculate the concentration of the resulting solution, find the pOH using the concentration of the conjugate base, and finally convert the pOH to pH.

The pH of the solution can be calculated using the concentrations of the acid and the base. We can assume that the strong base reacts completely with the acid, so the resulting solution will contain only the conjugate base and water. Since we know the concentrations of the acid and base, we can determine the moles of each and calculate the new concentrations of the resulting solution. Finally, we can use the concentration of the conjugate base to find the pOH and then convert it to pH.

Given:
moles of HA = 9.00 mmol
moles of strong base = 3.00 mmol
Total volume of solution = unknown

Let's assume the total volume of the solution is 1 L for easier calculations. The concentration of the acid (HA) is 9.00 mmol / 1 L = 9.00 mM. The concentration of the conjugate base (A-) is also 9.00 mM since the acid and base react in a 1:1 ratio. The pOH of the solution can be calculated using the concentration of the base:

pOH = -log([OH-])
Since the concentration of the base is 9.00 mM, the pOH = -log(0.009) = 2.05

The pH of the solution can be calculated by subtracting the pOH from 14:
pH = 14 - pOH = 14 - 2.05 = 11.95

Therefore, the resulting pH of the solution is approximately 11.95.

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The formula relating the sample variance, SS and n can be written as:

sample variance = SS / (n – 1)

so let us take that:

SS = 40

n = 5

calculate variance using the formula:

sample variance = 40 / (5 – 1)

sample variance = 10

Therefore the answer is:

False

The mass number of the atom is 45.

Given:

An atom contains 21 electrons, 21 protons, and 24 neutrons.

To find:

The mass number of an atom.

Solution:

Number of protons in atom = p = 21

Number of neutrons in atom = n = 24

Mass number of an atom = A

[tex]A = p + n \\\\A = 21 + 24 \\\\A = 45[/tex]

The mass number of the atom is 45.

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Answer:- The limiting reactant is HCl.

Explanation: The balanced equation is:

[tex]2HCl+Ca\rightarrow CaCl_2+H_2[/tex]

It's a stoichiometry problem. Masses of both the reactants are given and the questions asks to find out the limiting reactant.

We convert the given grams of each reactant to moles on dividing by its molar mass. Now, we can calculate the moles of any of the product on multiplying the moles of the reactant by mole ratio.

We do this starting with both the reactants and see which one gives less number of moles of the product. The limiting reactant is the one giving least number of moles of the product.

Molar mass of HCl is 36.46 gram per mol and that of Ca is 40.08 gram per mol.

Let's say we calculate the moles of hydrogen gas produced in the reaction. Mole ratio of [tex]H_2[/tex] to HCl is 1:2 and the mole ratio of [tex]H_2[/tex] to Ca is 1:1 .

The calculations are as shown below:

[tex]100gHCl(\frac{1molHCl}{36.46gHCl})(\frac{1molH_2}{2molHCl})[/tex]

= 1.37 mol [tex[H_2[/tex]

[tex]100gCa(\frac{1molCa}{40.08gCa})(\frac{1molH_2}{1molCa})[/tex]

= 2.50 mol [tex]H_2[/tex]

From above calculations, we get the least moles of hydrogen gas from 100 grams of HCl. So, the limiting reactant is HCl.

I do believe is Mechanical Energy

Hey Brainly Student! Your answer us true, SUPRISE FACT ABOUT ATOMS!!: When you think of an atom what do you think of? Problily a small circle with afew rings around it right? Well, actually an atom doesnt look like that at all!! An atom looks sort of like the Solar System, and the little rights are like the rotation the planets spin in, also the little star like balls/dots dont actually go around the atom's center, but go in many diffrent places it can be far from the atom, or can be very close! An atom is unpredictable, so there is no correct answer to where the atom's little balls/dots will end up next. I hope this helped, and also hope you liked/loved the Fun-Fact!! Your fellow Brainly user, GalaxyGamingKitty

Answer:

Argon ( Ar)

Explanation:

Answer: This is known as non-polar covalent bond.

Explanation:

A covalent bond is formed when sharing of electrons takes place between the atoms forming a bond.

A polar covalent bond is formed when the atoms forming a bond have significant difference in electronegativities. This leads to the formation of poles in the atoms. For Example: HCl

A non-polar covalent bond is formed when the atoms forming a bond dpes not have significant difference in electronegativities or have similar electronegativity. For Example: [tex]H_2[/tex]

Hence, the bond is known as non-polar covalent bond.

The total number of iron (Fe) atoms in 6 L of blood in an adult human can be found by converting the volume of blood to the mass of hemoglobin, converting that to the moles of hemoglobin, and then considering how many Fe atoms that would be. It turns out to be approximately 3.44 x 10^23 Fe atoms.

To approximate the number of iron (Fe) atoms in the 6 L of blood in an adult human, we must first convert the volume of blood to the mass of hemoglobin it contains. From the information provided, we know that blood contains about 15.4 g of hemoglobin per 100 ml. Therefore, in 6 L of blood, we have approximately 9240 g of hemoglobin, obtained by a simple conversion from liters to milliliters, then multiplying by the concentration of hemoglobin (15.4 g/100ml).

Next, we need to understand how many moles of hemoglobin that would be. The molar mass of hemoglobin is around 64500 g/mol. So, 9240 g of hemoglobin is about 0.143 mol.

Because there are four Fe atoms in each hemoglobin molecule, this is equivalent to 0.572 mol of Fe atoms. To calculate the actual number of Fe atoms, we multiply this by Avogadro's number (6.022 x 10^23 mol^-1), resulting in about 3.44 x 10^23 Fe atoms.

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