A. All matter in the universe was compressed Into a single point.
(apex)
A. All matter in the universe was compressed Into a single point. this option describes the big bang theory.
What is the Big Bang theory?The Big Bang hypothesis states that all of the current and past matter in the Universe came into existence at the same time, roughly 13.8 billion years ago.
At this time, all matter was compacted into a very small ball with infinite density and intense heat called Singularity.
The universe begin;
The Big Bang was the moment 13.8 billion years ago when the universe began as a tiny, dense, fireball that exploded.
Here Most astronomers use the Big Bang theory to explain how the universe began, But what caused this explosion in the first place is still a mystery.
Thus matter was compressed into a single point and then exploded outward to form the universe describes the big bang theory.
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One property of an electron is Question 1 options: a net charge of 0. a charge of +1. a charge of -1. an atomic mass of -1.
Which statement about the effect of sunlight on the earth is true? A. Sunlight warms the earth unevenly. B. Sunlight warms the poles more than the equator. C. Sunlight warms the earth evenly. D. The Coriolis effect does not distribute heat.
The maximum speed of a mass m on an oscillating spring is vmax . what is the speed of the mass at the instant when the kinetic and potential energy are equal?
Final answer:
The speed of the mass at the instant when the kinetic and potential energies are equal is v = vmax / √2, which is 0.707 times the maximum speed vmax.
Explanation:
When dealing with an oscillating mass on a spring, the maximum kinetic energy occurs when the potential energy is at a minimum, which is at the equilibrium position. Conversely, the potential energy reaches its maximum value when the kinetic energy is zero, which occurs at the maximum displacement from equilibrium. According to the conservation of mechanical energy, the total energy in the system is constant and is shared between the kinetic and potential energies.
The condition where the kinetic energy (K) and potential energy (U) are equal can be represented by the equation K = U. Since the total energy is the sum of the kinetic and potential energies, we can derive an expression where E = K + U, and at the point where K = U, they each are equal to E/2, where E is the total energy of the system. Thus, K = 1/2 mv2 = E/2. We know that the maximum kinetic energy (when the potential energy is zero) is given by Kmax = 1/2 mvmax2, which is equal to the total energy E.
To find the speed v when kinetic and potential energies are equal, we set the kinetic energy expression to E/2 and solve for v:
1/2 mv2 = 1/2 mvmax2 / 2
v2 = vmax2 / 2
v = vmax / √2
Therefore, the speed of the mass when the kinetic and potential energies are equal is vmax / √2, which is 0.707 times the maximum speed vmax.
A car starts from xi = 19m at ti = 0 and moves with the velocity graph shown in figure below. What is the objects position and t=2s, t=3s, and t=4s?
A solid round bar with diameter of 2-in has a groove cut to a diameter of 1.8-in, with a groove radius of 0.1-in. the bar is not rotating. the bar is loaded with a repeated bending load that causes the bending moment at the groove to fluctuate between 0 and 25000 lbf-in. the bar is hot-rolled aisi 1095, but the groove has been machined. determine the factor of safety for fatigue based on infinite life (use the asme elliptical criteria) and the factor of safety for yielding.
Water, initially saturated vapor at 4 bar, fills a closed, rigid container. the water is heated until its temperature is 4008c. for the water, determine the heat transfer, in kj per kg of water
The heat transfer, in kJ per kg of water, is 2510.4 kJ.
Explanation:The heat transfer, in kJ per kg of water, can be calculated using the formula:
Heat transfer = specific heat capacity × mass of water × change in temperature
Given that the specific heat capacity of water is 4.184 J/g °C and the mass of water is 1 kg, the heat transfer can be calculated as:
Heat transfer = (4.184 J/g °C) × (1000 g) × (400 - 100) °C = 2510400 J = 2510.4 kJ
Therefore, the heat transfer is 2510.4 kJ per kg of water.
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The frequency of an FM radio station is 89.3 MHz. Calculate its period.
Answer:
T= 1 / 8.93 . 10^7
Explanation:
In a bwr or pwr, steam is generated with a temperature of about 290 °c. if river water used to receive waste heat has a temperature of 20 °c, what is the maximum possible (ideal) conversion efficiency of the reactor's thermal energy into electrical energy? nuclear power plants typically have conversion efficiencies of 34%. why is this efficiency less than the ideal efficiency?
Final answer:
Efficiency comparison between theoretical and actual values in power plants due to various factors.
Explanation:
The maximum theoretical efficiency of a heat engine operating between 300°C and 27°C can be calculated using the Carnot efficiency formula.
The ideal efficiency in this case would be 67%.
The actual efficiency of nuclear power plants is lower than the ideal efficiency due to losses in energy conversion, limitations of materials, and safety considerations.
Efficiency in real-world applications is affected by factors like temperature limitations, friction losses, and energy transfer inefficiencies.
A coil of wire that carries an electric current is a(n) _______.
Solenoid
A coil of wire that carries an electric current is a solenoid
Explanation;Solenoid refers to the coil of a wire that is used as an electromagnet. Solenoid creates magnetic field from electric current and uses the magnetic field to generate motion. The magnetic field generated by a solenoid may be controlled by varying the amount of electric current in the circuit. Electromagnet are types of magnets whose strength can be varied using various variation in a solenoid such as the amount of electric current and also the number of coils in the solenoid.(b) suppose two telephone poles are 40 ft apart and the length of the wire between the poles is 41 ft. if the lowest point of the wire must be 19 ft above the ground, how high up on each pole should the wire be attached? (round your answer to two decimal places.)
Final answer:
To find the heights at which the wire should be attached to each pole, we can use the concept of similar triangles. By setting up an equation involving the height of one pole and the height difference between the poles, we can solve for the heights. The wire should be attached to the first pole at a height of approximately 39.64 ft and to the second pole at a height of approximately 0.36 ft.
Explanation:
To determine the heights at which the wire should be attached to each pole, we can use the concept of similar triangles. Let's call the height at which the wire is attached to the first pole h1, and the height at which it is attached to the second pole h2.
Since the lowest point of the wire is 19 ft above the ground, and the poles are 40 ft apart, we can use the Pythagorean theorem to find the length of the vertical leg of the right triangle formed by the wire and the ground. This will be the difference between the heights of the two poles:
|h1 - h2| = sqrt(41^2 - 19^2)
We know that the wire is 40 ft above the ground at its highest point. So if we subtract the height at which it is attached to one pole from 40 ft, we can find the height at which it is attached to the other pole:
h2 = 40 - h1
By substituting this expression for h2 into the equation |h1 - h2| = sqrt(41^2 - 19^2), we can solve for h1:
|h1 - (40 - h1)| = sqrt(41^2 - 19^2)
Simplifying further, we get:
2h1 - 40 = sqrt(41^2 - 19^2)
Adding 40 to both sides of the equation:
2h1 = 40 + sqrt(41^2 - 19^2)
Finally, dividing both sides by 2, we find:
h1 = (40 + sqrt(41^2 - 19^2))/2
By plugging in the values and performing the calculations, we find that h1 ≈ 39.64 ft and h2 ≈ 0.36 ft.
A small block is placed at height h on a frictionless 30 degree ramp. Upon being released the block slides down the ramp and then falls 1.0m to the floor. A small hole is located 1.0 m from the end of the ramp. From what height h should the block be released in order to land in the hole?
After leaving the plane, the block will have an unknown speed (S),
which can be broken into x,y components.
The x,y kinematics are: x – 1
x0 - 0 V - ? V0 - Scos(-30)
a – 0
t - t
y - 0
y0 – 1
V - ?
V0 - Ssin(-30)
a - -9.8
t – t
We then use x=x0+v0t+.5at^2
in the x case: 1=0+Scos(-30)+.5(0)t^2
Solving for t gives t=1/ Scos(-30)
in the y case,
with t-substitution:
0=1+Ssin(-30)*1/Scos(-30)+.5(-9.8)(1/Scos(-30))^-2
In the middle velocity term, S cancels out. Multiplying all known numbers as well as squaring the third term gives:
0=1-.5774-6.5333/S^2
Solving for S = S = 3.9319 m/s
Now with a mark on final ramp speed, we can now make a 3rd kinematics equation. The acceleration will be altered from gravity:
Slide force = 9.8*sin(30) = 4.9 m/s^2.
x - ?
x0 – 0
V - 3.9319
V0 – 0
a - 4.9
t - ?
So the equation we use is V2 = V02+2a(x-x0). 3.93192=0+2*4.9*(x-0)
Solving for x gives x=1.5775 m up the ramp.
So we now look for the y component of the ramp length:
1.5775*sin(30) = .78875 m 'high' on the ramp.
Final answer:
The block should be released from a height of h = 1.732m (rounded to three decimal places) in order to land in the hole.
Explanation:
The block will land in the hole if it is released from a certain height h on the ramp. To find this height, we can break down the problem into two parts:
From the released height to the ground: The block travels along a frictionless ramp with a angle of 30 degrees. We can calculate the horizontal distance D it will travel using the formula D = h/tan(30), where h is the released height. From the ground to the hole: The block falls 1.0m vertically to reach the hole. Therefore, the released height h should be equal to the horizontal distance D.So, the block should be released from a height of h = 1.0m/tan(30) = 1.732m (rounded to three decimal places) in order to land in the hole.
If an object is traveling east with a decreasing speed, the direction of the objects acceleration is?
If an object is traveling east and slowing down, its acceleration is westward or negative when east is considered positive. This negative acceleration is indicative of deceleration.
Explanation:If an object is traveling east with a decreasing speed, the direction of the object's acceleration is to the west. Acceleration is defined as the rate of change of velocity. If an object is slowing down, its acceleration is in the opposite direction of its velocity. When we consider east as the positive direction, and the object is moving east but slowing down, it means the object has a negative acceleration because it is accelerating toward the west. This is often referred to as deceleration. A real-world example could be an airplane landing on an eastward facing runway; as it comes to a stop, it experiences negative acceleration.
A calculus book weighing 20 N rests on the floor of a classroom. The reaction to the force of the floor on the book is a force of
Complete the sentence with the word "element" or "compound." O is a(n) and H2O2 is a(n) .
Answer:
O is an element, And H2O2 is an compound
Explanation:
Answer:
the other person is correct
Explanation:
A low-pass first-order instrument has a time constant of 20 ms. find the frequency, in hertz, of the input at which the output will be 93% of the dc output.
Which formula can be used to calculate the horizontal displacement not of a horizontally launched projectile
Answer:
Δx=vₓΔt
Explanation:
edge 2020 answer (D)
A cheetah spots a thomson's gazelle, its preferred prey, and leaps into action, quickly accelerating to its top speed of 30 m/s, the highest of any land animal. however, a cheetah can maintain this extreme speed for only 15 s before having to let up. the cheetah is 170 m from the gazelle as it reaches top speed, and the gazelle sees the cheetah at just this instant. with negligible reaction time, the gazelle heads directly away from the cheetah, accelerating at 4.6 m/s2 for 5.0 s, then running at constant speed. does the gazelle escape? if so, by what distance is the gazelle in front when the cheetah gives up?
The gazelle escapes the cheetah by 7.5 meters. This is calculated by determining the distance the cheetah and gazelle each cover in the given time. The gazelle's distance includes both the acceleration phase and the constant speed phase.
Explanation:To determine if the gazelle escapes from the cheetah, we need to calculate the distance both the gazelle and the cheetah cover separately within the same time frame. The cheetah can maintain its top speed of 30 m/s for only 15 seconds. Therefore, the total distance covered by the cheetah while it's at top speed is given by:
Distance covered by the cheetah = speed × time = 30 m/s × 15 s = 450 m
The gazelle starts accelerating at 4.6 m/s2 for 5.0 seconds. The distance covered by the gazelle during acceleration can be calculated using the equation:
Distance = 0.5 × acceleration × time2 = 0.5 × 4.6 m/s2 × (5.0 s)2 = 57.5 m
After 5 seconds of acceleration, the gazelle will be running at a constant speed, which we can find using the formula:
Final velocity = initial velocity + (acceleration × time) = 0 + (4.6 m/s2 × 5.0 s) = 23 m/s
For the remaining 10 seconds (since the cheetah runs at top speed for 15 seconds and the gazelle has already spent 5 seconds accelerating), the gazelle travels at this constant speed, covering:
Distance at constant speed = speed × time = 23 m/s × 10 s = 230 m
The total distance covered by the gazelle is the sum of the distance covered during acceleration and the distance covered at constant speed:
Total distance covered by gazelle = 57.5 m + 230 m = 287.5 m
Now we need to add the initial distance between the gazelle and the cheetah to the distance covered by the gazelle, to find out how far the gazelle is when the cheetah stops:
Total distance from cheetah = initial distance + distance covered by gazelle = 170 m + 287.5 m = 457.5 m
Since the cheetah covers only 450 m and the gazelle is 457.5 m away from the cheetah's starting point, the gazelle escapes, and the distance by which it's in front when the cheetah gives up is:
Escape distance = total distance from cheetah - distance covered by cheetah = 457.5 m - 450 m = 7.5 m
Therefore, the gazelle escapes the cheetah by 7.5 meters.
Justin, with a mass of 30 g, is going down a 8.0 m high water slide. he starts at rest, and his speed at the bottom is 11 m/s. how much thermal energy is created by friction during his descent
Final answer:
The amount of thermal energy created by friction during Justin's descent is 0.537 J.
Explanation:
To calculate the thermal energy created by friction during Justin's descent, we need to find the change in mechanical energy. The mechanical energy at the top consists of gravitational potential energy and kinetic energy. At the bottom, it consists of only kinetic energy. Since there is no change in the height, the change in mechanical energy is equal to the work done by friction, which can be calculated using the equation:
Work = Change in mechanical energy = Kinetic energy at the bottom - Gravitational potential energy at the top
First, we need to calculate the gravitational potential energy at the top:
Gravitational potential energy (PE) = mass * gravity * height
Substituting the given values:
PE = 0.03 kg * 9.8 m/s² * 8.0 m = 2.352 J
Next, we need to calculate the kinetic energy at the bottom:
Kinetic energy (KE) = 0.5 * mass * velocity²
Substituting the given values:
KE = 0.5 * 0.03 kg * (11 m/s)² = 1.815 J
Now we can calculate the work done by friction:
Work = KE - PE = 1.815 J - 2.352 J = -0.537 J
Since work is a scalar quantity with no direction, the negative sign indicates that the work is done by friction rather than by the object. Therefore, the amount of thermal energy created by friction during Justin's descent is 0.537 J.
A yo-yo falls through a distance of 0.60 m as its string unwinds. if it starts from rest, what is its speed? (model the yo-yo as a solid disc.) m/s
In the United States, most of our energy comes from this non–renewable resource, which has a negative effect on the environment.
coal
nuclear
natural gas
petroleum
#NED ANSWER ASAP!
Answer:
the answer is natural gass
Explanation:
A good quarterback can throw a football at 27 m/s (about 60 mph ). How long is the ball in the air?
The ball is in the air for about 5.5 seconds when it is thrown vertically up.
Further explanationAcceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem!
This problem is about Projectile Motion
Given:
initial speed = u = 27 m/s
Unknown:
time interval of the ball in the air = t = ?
Solution:
[tex]h = u \sin \theta ~t - \frac{1}{2}gt^2[/tex]
[tex]0 = u \sin \theta ~t - \frac{1}{2}gt^2[/tex]
[tex]u \sin \theta ~ t = \frac{1}{2}gt^2[/tex]
[tex]u \sin \theta = \frac{1}{2}gt[/tex]
[tex]t = \boxed {\frac{ 2u \sin \theta }{g}}[/tex]
If the angle of projection = θ = 90° , then :
[tex]t = \boxed {\frac{ 2(27) \sin 90^o }{9.8}}[/tex]
[tex]t \approx 5.5 ~ seconds[/tex]
If the angle of projection = θ = 45° , then :
[tex]t = \boxed {\frac{ 2(27) \sin 45^o }{9.8}}[/tex]
[tex]t \approx 3.9 ~ seconds[/tex]
Learn moreVelocity of Runner : https://brainly.com/question/3813437Kinetic Energy : https://brainly.com/question/692781Acceleration : https://brainly.com/question/2283922The Speed of Car : https://brainly.com/question/568302Answer detailsGrade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle
Suppose you are holding a basketball while standing still on a skateboard. You and the skateboard have a mass of 50kg. You throw the basketball with a force of 10N. What is your acceleration before and after you throw the ball?
Answer:
Acceleration after throwing is 0.2m/s²
Acceleration before throwing is 0 m/s² since the force is zero
Explanation:
By Newtons third law we have force applied by ball on person = 10 N
Mass of person plus skateboard = 50 kg
We also know the equation
Force, F = mass x acceleration
F = ma
Here F = 10 N
m = 50 kg
Substituting,
10 = 50 x a
[tex]a=\frac{10}{50}=\frac{1}{5}=0.2m/s^2[/tex]
Acceleration after throwing is 0.2m/s²
Acceleration before throwing is 0 m/s² since the force is zero
The following forces act on an object: 20 N north, 40 N south, and 40 N west. What is the magnitude of the net force?
The north and south forces first cancel each other out, leaving a net force of 20 N towards the south. Adding this to the westward force of 40 N using the Pythagorean theorem results in a net force of 44.7 N.
Explanation:The forces acting on the object in this problem are 20 N north, 40 N south, and 40 N west. When combining these forces, we consider that the forces act in different directions, and so the north-south forces will cancel each other out to some extent. The net north-south force is 40 N south minus 20 N north, resulting in a 20 N force towards south. The westward force is 40 N, and the net force of the object can be calculated using the Pythagorean Theorem:
Net Force = √ [ (20 N)² + (40 N)² ] = √ [ 400 + 1600] = √ [ 2000 ] = 44.7 N
Thus, the magnitude of the net force on the object is 44.7 N.
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A car weighing 15,000 n is speeding down the highway at 90 km/h. what is its momentum?
How does a rubber rod become negatively charged through friction?
Answer:Explained
Explanation:
When a rubber rod is rubbed against, let's say animal fur the electrons from the animal is being transferred to rubber rod as rubber rod has greater attraction for electron i.e. rubber rod has higher electron negativity .That's why it become negatively charged.
A car traveling 92 km/h is 130 m behind a truck traveling 75 km/h. how long will it take the car to reach the truck?
The car will catch up to the truck in approximately 0.459 minutes, or about 27.54 seconds, by traveling at a relative speed of 17 km/h faster than the truck.
To determine how long it will take for the car traveling at 92 km/h to reach the truck traveling at 75 km/h, we need to calculate the relative speed between the two vehicles and then use that information to find out how long it takes to cover the distance between them.
Step 1: Calculate Relative Speed
The car's speed is 92 km/h and the truck's speed is 75 km/h. To find the relative speed, we subtract the slower speed (truck) from the faster speed (car):
92 km/h - 75 km/h = 17 km/h
Step 2: Calculate Time to Cover the Distance
Now that we have the relative speed, we can calculate the time it will take for the car to cover the 130 meters (0.130 kilometers) separating it from the truck.
Time = Distance / Speed
Time = 0.130 km / 17 km/h
Time = 0.00765 hours
Converting 0.00765 hours into minutes (as there are 60 minutes in an hour) gives us:
Time = 0.00765 hours x 60 minutes/hour = 0.459 minutes
Thus, it will take approximately 0.459 minutes, or about 27.54 seconds, for the car to reach the truck.
Is the wavelength of a microwave longer or shorter than the wavelength of visible light? is the wavelength of a microwave longer or shorter than the wavelength of visible light? the wavelength of a microwave is longer than the wavelength of visible light. the wavelength of a microwave is shorter than the wavelength of visible light. the wavelength of a microwave is equal to the wavelength of visible light. submitmy answersgive up correct part b by how many orders of magnitude do the two waves differ in wavelength? by how many orders of magnitude do the two waves differ in wavelength? the two waves differ in wavelength by 1-2 orders of magnitude. the two waves differ in wavelength by 3-5 orders of magnitude. the two waves differ in wavelength by 8-10 orders of magnitude. the two waves differ in wavelength by 6-8 orders of magnitude?
The wavelength of a microwave is longer than that of visible light, with microwaves typically ranging from 1 millimeter to 1 meter while visible light ranges between ~400 and 700 nanometers. In terms of scale, these differ by about 6-8 orders of magnitude.
Explanation:The wavelength of a microwave is indeed longer than that of visible light. To understand this, it helps to remember that the type of wave - whether it's a microwave, visible light, ultraviolet light, etc. - is determined by its frequency or wavelength in the electromagnetic spectrum. Microwaves, used largely in radar and communications, possess longer wavelengths ranging from 1 millimeter to 1 meter. Visible light, on the other hand, has shorter wavelengths, between approximately 400 and 700 nanometers.
In terms of the orders of magnitude difference, we can observe a substantial difference. The difference in wavelength between visible light and microwaves is generally in the range of 6-8 orders of magnitude, taking the range of both wavelengths into account. This significant disparity illustrates the vast variety and scale within the electromagnetic spectrum.
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How many kilocalories are generated when the brakes are used to bring a 1200-kg car to rest from a speed of 95 km/h ? 1 kcal = 4186 j?
To calculate the kilocalories generated when the brakes are used to bring a car to rest, determine the initial kinetic energy of the car using the formula KE = 0.5 * mass * velocity^2, and then convert it into kilocalories using the conversion factor 1 kcal = 4186 J.
Explanation:To calculate the kilocalories generated when the brakes are used to bring a car to rest, we need to determine the initial kinetic energy of the car and then convert it into kilocalories using the conversion factor provided.
The initial kinetic energy of the car can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the given values, KE = 0.5 * 1200 kg * (95 km/h)^2 = 0.5 * 1200 kg * (95^2) km^2/h^2.
Now, to convert the kinetic energy from joules to kilocalories, we can use the conversion factor: 1 kcal = 4186 J. Thus, the kilocalories generated when the brakes are used to bring the car to rest would be the kinetic energy in joules divided by 4186 J/kcal.
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how does gravity affect objects with greater mass
Dr Spock would have supported which of the following actions by parents
According to Dr. Spock's child-rearing philosophies, parents ought to respect and foster children's individuality and decision-making skills. Therefore, he would likely endorse parental actions such as allowing the 2-year-old to pick her clothes, letting the infant explore her surroundings, and supporting the 18-year-old's life choices.
Explanation:Dr. Spock, well-known pediatrician and author, strongly believed in the importance of recognizing a child's individuality and fostering independence. Hence, he would likely endorse the parents' actions in C. Your two-year-old daughter refuses to wear the clothes you pick for her every morning, which makes getting dressed a twenty-minute battle. Spock would perceive this as the child developing personal decision-making skills. He would also support A. Your infant daughter puts everything in her mouth, including the dog's food.
For him, exploring the environment plays a crucial role in a child's early development. However, he would suggest that parents keep a close eye on their child to ensure safety. Finally, he might approve of E. Your 18-year-old daughter has decided not to go to college. Instead she's moving to Colorado to become a ski instructor, recognizing it as the young adult exercising her rights to make life choices.
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