When two parallel lines are cut by a transversal, angles A and B are alternate interior angles that each measure 105°. What is the measure of each of the other alternate interior angles?
75°
90°
105°
180°

The flea's acceleration is 1,000 m/s².

The problem we overlook this time is about uniformly accelerated motion.

The list of variables to be considered is as follows.

[tex]\boxed{u \ or \ v_i = initial \ velocity}[/tex]

[tex]\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}[/tex]

[tex]\boxed{a = acceleration \ (constant)}[/tex]

[tex]\boxed{d = distance \ travelled}[/tex]

Given that a take-off speed of 1.0 m/s over a distance of 0.50 mm.  

The initial speed was zero from rest.  It was asked about flea's acceleration when she extends her legs.

The formula we follow for this problem are as follows:

[tex]\boxed{ \ v^2 = u^2 + 2ad \ }[/tex]

Converted 0.50 mm to meters: [tex]\boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}[/tex]

Steps:

We set the formula so that the acceleration becomes the subject.

[tex]\boxed{ \ v^2 = u^2 + 2ad \ }[/tex]

[tex]\boxed{ \ v^2 - u^2 = 2ad \ }[/tex]

[tex]\boxed{ \ 2ad = v^2 - u^2 \ }[/tex]

[tex]\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }[/tex]

Substitute all data into equations.

[tex]\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }[/tex]

[tex]\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }[/tex]

[tex]\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }[/tex]

[tex]\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }[/tex]

We get the flea's acceleration, i.e., 1,000 m/s².

Keywords: flea, when jumping, rapidly extends its legs, take-off speed, initial velocity, distance, acceleration, uniformly accelerated motion, convert

The Flea acceleration as it extends its leg is [tex]\fbox{\begin\\\ 1000\ m/s^{2}\\\end{minispace}}[/tex].

Further explanation:

Given:

The takeoff speed of the flea is [tex]1.0\ \text{m/s}[/tex].

The distance cover by flea is [tex]0.50\ \text{m/s}[/tex].

To find:

The acceleration of the flea as it extended it legs.

Formula used:

The acceleration of the flea can be obtained by the given formula.

[tex]\fbox{\begin\\\ \math v^{2}=u^{2}+2as\\\end{minisapce}}[/tex]  ....(1)

Here, [tex]v[/tex] is the final velocity of flea, [tex]u[/tex] is the initial velocity of flea, [tex]a[/tex] is the acceleration of the flea, [tex]s[/tex] is the distance cover by the flea.

Calculation:

The initial velocity of flea is [tex]0[/tex].

The final velocity of flea is [tex]1.0\text{m/s}[/tex].

The distance cover by flea is in millimeter.

Convert millimeter into meter as follows.

[tex]\fbox{\begin\\\ \begin{aligned}0.50 \text{ mm}&=\dfrac{0.50}{1000}\text{ m}\\&=0.0005\text{ m}\end{aligned}\\\end{minispace}}[/tex]

Now substitute [tex]0[/tex] for [tex]u[/tex], [tex]1.0[/tex] for [tex]v[/tex] and [tex]0.0005[/tex] for [tex]s[/tex] in equation (1) to obtain the value of acceleration.

[tex]\begin{aligned}1^{2}&=0^{2}+(2a\times(0.0005))\\1&=0.001a\\a&=\dfrac{1}{0.001}\\a&=1000\end{aligned}[/tex]

Therefore, the acceleration of the flea is as it extends its leg is [tex]\fbox{\begin\\\ 1000\ m/s^{2}\\\end{minispace}}[/tex].

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Speed and distance

Keywords:  Flea, jump, legs, takeoff speed, acceleration , distance cover, 0.05 mm, 1000 meter per second square. Initial velocity, Final velocity

The proportion form of Newton’s second law is when finding the acceleration of a problem as this is the equation suitable of finding the acceleration and to be able to compute the missing answer to the problem. In the form of the equation, it is ‘a + f / m’.

The mean travel distance for the sample of 100 customers surveyed by the manager at First City Bank is considered a statistic.

The mean travel distance for the sample of 100 customers surveyed by the manager at First City Bank is considered a statistic.

In statistics, a parameter is a numerical characteristic of the whole population that can be estimated by a statistic. Since the manager is surveying only a sample of customers, the mean travel distance calculated from this sample is a statistic, not a parameter.

For example, if the manager had surveyed all customers of First City Bank, then the mean travel distance calculated from that data would be a parameter.

The solution after divide is,

⇒ 0.893

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

We have to given that;

To divide the numbers,

⇒ 25 divided by 28

Now, We can divide the numbers as;

⇒ 25 divided by 28

⇒ 25 ÷ 28

⇒ 25 / 28

⇒ 0.893

Thus, The solution after divide of the numbers is,

⇒ 0.893

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Julia estimated federal taxes will be $ 22,400.

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. With the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

Julia has just gotten a new job paying 80,000 a year .

From the figure the tax will be of 28%.

So, Julia estimated federal taxes will be

= 80,000 x 28/100

= 800 x 28

= $ 22,400

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Answer:

5 weeks 2 days

Step-by-step explanation:

A certain plant grows every week = [tex]1\frac{1}{6}[/tex] = [tex]\frac{7}{6}[/tex] inches

1 week = 7 days

Therefore in 1 day the plant grows = [tex]\frac{\frac{7}{6}}{7}[/tex]

                                                         = [tex]\frac{1}{6}[/tex] inch

Now we have to calculate number of days in which the plant grows  [tex]6\frac{1}{6}[/tex] inches ≈ [tex]\frac{37}{6}[/tex] inch

Number of days = [tex]\frac{\text{Total growth}}{\text{Growth in one day}}[/tex]

                           = [tex]\frac{37}{6}[/tex] ÷ [tex]\frac{1}{6}[/tex]

                           =  [tex]\frac{37}{6}[/tex] × 6

                           = 37 days ≈ 5 weeks and 2 days

It will take the plant 5 weeks 2 days to grow [tex]6\frac{1}{6}[/tex] inches.

To find out how many DVDs you can buy for the same price at both stores, you create a formula incorporating the cost per DVD and the shipping cost at the online store. Solving this equation will give you the number of DVDs where the cost will be equal at both stores. However, this might not always result in a whole number, indicating that there is no exact count of DVDs resulting in the same cost.

To determine how many DVDs you can buy for the same amount at both stores, you can set up a mathematical equation accounting for the cost of each DVD and the shipping cost in the online store. The equation would look like this:

15.49 x = 13.99 y + 6

where x and y represent the number of DVDs bought from the local and online store respectively. By solving this equation we're finding out for which number of DVDs the total costs at both stores are equal.

To find the exact number of DVDs where the total cost will be the same, the equation needs to be solved for a whole number. This may result in no exact integer solution, showing that there's no exact number of DVDs for which the cost will be the same at both stores.

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Answer:

The interest rate is 5.98%.  

Step-by-step explanation:

To find : What interest rate is needed for $9,500 to earn $900 in 19 months?

Solution :

The formula of interest is given by,

[tex]I=P\times R\times T[/tex]

Where,

I is the interest amount I=$900

P is the principle P=$9500

T is the time T=19 months= [tex]\frac{19}{12}[/tex] year.

R is the interest rate

Substitute the value in the formula,

[tex]900=9500\times R\times \frac{19}{12}[/tex]

[tex]R=\frac{900\times 12}{9500\times 19}[/tex]

[tex]R=\frac{10800}{180500}[/tex]

[tex]R=0.0598[/tex]

The rate of interest in percentage is [tex]R=0.0598\times 100=5.98\%[/tex]

Therefore, The interest rate is 5.98%.

To earn $900 from $9,500 in 19 months, an annual interest rate of approximately 5.97% is needed.

To determine the interest rate needed for $9,500 to earn $900 in 19 months, we can use the simple interest formula:

Simple Interest Formula: SI = P × R × T

SI: Simple Interest ($900)

P: Principal ($9,500)

R: Annual Interest Rate (as a decimal)

T: Time (in years)

Answer:

y=-2x-19

Step-by-step explanation:

this is the right answer , i tried the other answer for this and it said it was wrong so

Decimals can be found in various sources including the internet, and they are used in everyday activities like shopping online. The word problem involves a book sale where a discount is given in decimal form.

Decimals are usually found in various sources such as newspapers, magazines, television, and predominantly on the internet. For example, when we read about the latest international currency exchange rates or the percentage rates in the stock market, we encounter decimals.

Let's create a real-world problem involving decimals: Sam is browsing a popular online bookstore. He found a book he wanted to buy for $5.49. However, there is a pop-up stating that for today only, all books are discounted by 0.15 (or 15%). How much would the book cost after the discount?

To find the solution, subtract the discount from the original price in decimal form i.e., $5.49 * 0.15 = $0.82 (approx). Then subtract this amount from the original price, $5.49 - $0.82 = $4.67. So, Sam will pay $4.67 for the book after discount.

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Infinite is the answer

multiply:

360 * 3/8 = 360*3 =1080

1080/8 = 135 were apartment sized

xm-2m

x=-2, m = -3

xm = -2 *-3 = 6

2m = 2*-3 = -6

6- -6 = 6+6 = 12

Final answer:

The donations in 2012 had a more dispersed distribution than in 2013, as indicated by a higher coefficient of variation of 20% compared to 15% in 2013.

Explanation:

To determine which year had a more dispersed contribution distribution, we examine the coefficient of variation (CV), which is calculated by dividing the standard deviation by the mean and then multiplying by 100 to express it as a percentage. A higher CV indicates a more dispersed distribution.

For 2012:

For 2013:

Comparing the coefficients of variation, we can conclude that the donations in 2012 had a more dispersed distribution than in 2013 since the CV in 2012 was higher.