Answer:
C: look left then right then left again
Explanation:
At an intersection, there three routes, the left, the right and straight ahead.
For a car stopped at an intersection, once the light turn green, it is advisable that the driver should watch the left and right then left again before accelerating. This is because there might be any car coming from any of the sides unnoticed which might leads to accident especially the first side u looked at (left) must be take much cognisance of hence the need to look left again before accelerating.
Final answer:
When stopped at an intersection and your light turns green, you should A. look right and then left before accelerating.
Explanation:
When stopped at an intersection and your light turns green, you should look left, then right, then left again before accelerating. This practice ensures that you are aware of any vehicles that may not have stopped at their red light or are trying to beat a yellow light, as well as any pedestrians or cyclists that may be crossing.
Remember that while traffic signals are there to regulate flow, driver vigilance is crucial in preventing accidents and ensuring safety. Thus, it is important to check both directions to ensure the intersection is clear before proceeding. Safe driving practices include being cautious and aware of potential risks on the road.
A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the tree. A burst of current lasting 43 µs passes through the ground; during this time the potential difference between his feet is 21 kV. If the resistance between one foot and the other is 550 Ω,
what is the current through his body and how much energy is dissipated in his body by the lightning?
Answer:
[tex]I=38.181\ A[/tex] is the current through the body of the man.
[tex]E=34.5\ J[/tex] energy dissipated.
Explanation:
Given:
time for which the current lasted, [tex]t=43\times 10^{-6}\ s[/tex]potential difference between the feet, [tex]V=21000\ V[/tex]resistance between the feet, [tex]R=550\ \Omega[/tex]Now, from the Ohm's law we have:
[tex]I=\frac{V}{R}[/tex]
[tex]I=\frac{21000}{550}[/tex]
[tex]I=38.181\ A[/tex] is the current through the body of the man.
Energy dissipated in the body:
[tex]E=I^2.R.t[/tex]
[tex]E=38.181^2\times 550\times 43\times 10^{-6}[/tex]
[tex]E=34.5\ J[/tex]
An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89)t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?
Answer:
a.V(t/365)=30,000(0.89)^(t/365).
b. V(5)=$17000
Explanation:
An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89)t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?
i will like to work back from te question by solving questin 2 first
V(t) = 30,000(0.89)^t
let t=5
V(5) = 30,000(0.89)^5
V(5)=$17000
2.yearly depreciation will be
30,000(0.89)^1
26700=it amounts to tis after a year,
so it depreciates by 3300 for one year
daily depreciation will be 3300/365 ,
since there are 365 days in a year
$9.041
the equation that satisfy this is
V(t/365)=30,000(0.89)^(t/365).
Final answer:
Mathematically, an automobile depreciating at 11% annually can be modeled for daily depreciation, but for the calculation of value after 5 years, we use the original annual model V(t) = 30,000(0.89)^t to find the car is worth approximately $13,000.
Explanation:
The student's question about the depreciation of an automobile can be classified under Mathematics, specifically dealing with exponential decay and depreciation models. To find the daily depreciation rate equivalent to 11% annual depreciation, we can use the formula for continuous compounding, where the annual rate is converted into a daily rate using the expression (1 + annual rate)^(1/365) - 1. However, since the problem does not ask for continuous daily depreciation but rather the equivalent discrete daily rate, we can instead divide the annual rate by 365, assuming each day the car depreciates by an equal fraction of the annual rate. Therefore, the daily depreciation rate would be 11% / 365.
However, because the student is seeking the value of the car after 5 years, we can directly use the provided equation V(t) = 30,000(0.89)^t, where t is the number of years. After 5 years, this gives us V(5) = 30,000(0.89)^5. Calculating this we get V(5) ≈ $13,000 when rounded to the nearest thousand.
If a star is moving away from you at a constant speed, how do the wavelengths of the absorption lines change as the star gets farther and farther?
When a star is moving away from an observer at a constant speed, the wavelengths of the absorption lines in its spectrum appear to shift to longer wavelengths. This is known as the redshift.
Explanation:When a star is moving away from an observer at a constant speed, the wavelengths of the absorption lines in its spectrum appear to shift to longer wavelengths. This phenomenon is known as the redshift. Redshift occurs because the motion of the star causes the wavelengths of light to stretch as the star moves away, just like the stretching of sound waves when a source moves away from an observer.
As the star gets farther and farther away, the amount of redshift increases, meaning the wavelengths of the absorption lines will shift even further towards the longer end of the spectrum. This shift in wavelengths can be measured using spectroscopy and is an important tool in determining the motion and distance of celestial objects. One example of redshift is the expansion of the universe itself, where galaxies are moving away from each other due to the expansion of space. The redshift of the light from distant galaxies provides evidence for this cosmic expansion.
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The wavelengths of absorption lines from a star moving away at a constant speed increase, exhibiting a redshift due to motion.
As a star moves away at a constant speed, the wavelengths of its absorption lines shift toward the red end of the spectrum. This is known as "redshift." It occurs because of the Doppler effect, where the motion of the source (star) affects the observed wavelength of light. When the star moves away, the observed wavelengths of light become longer, causing a redshift.
The Doppler effect explains that when an object is moving away from an observer, the waves it emits, including light, get stretched out, causing a shift to longer wavelengths. This redshift is used in astronomy to measure the recessional velocity of celestial objects, helping us determine the expansion of the universe and the distances between objects.
Redshift also plays a crucial role in the Hubble's law, which is fundamental in cosmology for understanding the universe's expansion.
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Magnetic orientation in rocks that is opposite to the current orientation of Earth's magnetic field is called ____ magnetic polarity.
Answer:
Normal Magnetic Polarity
Explanation:
Normal Magnetic polarity.
The polarity can be either normal or reversed Natural polarity is where the north magnetic points (roughly) towards the north pole. ... The reversed polarity is in the opposite direction and the northern end of the magnetic field is near the current southern pole.
"As an object falls into a black hole, it":
a. falls into a stable orbit around the black hole.
b. is broken up and heated before it reaches the event horizon.
c. passes into a location somewhere else.
d. can emit high energy (gamma-ray) electromagnetic radiation that can leave the black hole.
e. passes the event horizon intact.
Answer:D
Explanation:
Hawking showed that quantum effects allow black holes to emit exact black-body radiation. The
electromagnetic radiation is produced as if emitted by a black body with a temperature inversely proportional to the mass of the black hole. One of the pair falls into the
black hole while the other escapes
The cerebral cortex contains three types of areas. These are the _____, _____, and _____ areas.
Answer: sensory, motor, associative
Explanation:
Which heat transfer process is important in the transfer of energy from the Sun to Earth?
Answer: Radiation
Explanation:
The heat transfer process that is important in the transfer of energy from the Sun to Earth is Radiation.
Radiation is one of the mode of heat transfer which transfer energy/heat from one medium to another without any intervening medium. For example, heat from the sun reaches the earth through radiation. The sun hits the earth directly without any medium between the sun itself and the earth.
Radiation is the key heat transfer process by which energy is transferred from the Sun to Earth. It allows the transmission of energy through the vacuum of space and is integral to Earth's climate regulation, especially with respect to the natural greenhouse effect.
Explanation:The process of heat transfer that is important in the transfer of energy from the Sun to Earth is radiation. Unlike conduction and convection, radiation does not require a medium to transfer heat. This means that energy in the form of electromagnetic waves can travel through the vacuum of space from the Sun to the Earth. The Sun emits a tremendous amount of energy through nuclear reactions at its core, and this energy is transferred to Earth as electromagnetic radiation, primarily in the form of visible light and infrared radiation. When this radiation reaches Earth, it is absorbed and warms the planet's surface, playing a crucial role in Earth's climate and enabling life to exist.
The greenhouse effect also plays an important role in Earth's temperature regulation. Gases in Earth's atmosphere, such as carbon dioxide and water vapor, trap some of the heat that is radiated from the Earth's surface, keeping the planet warmer than it would be otherwise. Without this natural greenhouse effect, Earth's average temperature would be significantly lower, making it less hospitable for life as we know it.
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A spring has an equilibrium length of 2.0 meters and a spring constant of 10 newtons/meter. Alice is pulling on
one end of the spring with a force of 3.0 newtons. Bob is pulling on the opposite end of the spring with a force of
3.0 newtons, in the opposite direction. What is the resulting length of the spring?
(A) 1.7 m
(B) 2.0 m
(C) 2.3 m (correct answer)
(D) 2.6 m
(E) 8.0 m
Final answer:
When equal forces of 3.0 newtons are applied on both ends of a spring with an equilibrium length of 2.0 meters, the resulting length of the spring remains 2.0 meters because the forces cancel each other out.
Explanation:
To find the resulting length of the spring, we should first determine the amount of stretch or compression caused by the forces applying on the spring. Since Alice and Bob are both pulling with a force of 3.0 newtons each in opposite directions, the net force on the spring is zero. Therefore, the spring neither stretches nor compresses from its equilibrium length.
The spring has an equilibrium length of 2.0 meters and remains at this length because the forces applied by Alice and Bob cancel each other out. So, the resulting length of the spring when 3.0 newtons is applied at each end in opposite directions is 2.0 meters, which is answer (B).
Sprinters start their races from a crouched position with their bodies well forward of their feet. This position allows them to accelerate quickly without tipping over backward. Explain.
Answer:
We can explain it in term of center of mass and torque. When the sprinters start their race then the ground exerts the force towards the center of mass and thats how the torque can be prevented from acting on the sprinter.In this way the crouched position allows them to accelerate quickly without tipping over backward.
Explanation:
Johanna is studying what happens to the energy as a ball rolls down a ramp. What is she studying? Check all that apply.
1. gravitational potential energy
2. electrical energy
3. kinetic energy
4. mechanical energy
5. elastic potential energy
Answer:
Gravitational potential energy, kinetic energy and mechanical energy
Explanation:
The body is at a displacement to the gravity and therefore has energy stored in it as a result of its displacement against gravity. When this body is released the gravitational potential energy is converted to translational kinetic energy as well as rotational kinetic energy as it rolls down the the ramp. The sum of the kinetic energies and potential energy of the body amount to the mechanical energy of the ball down the ramp.
Submarine canyons were most likely formed by:Select one:a. scouring by glaciers during the last ice age.b. deposition of terrestrial sediment.c. earthquake activity.d. erosion by turbidity currents.e. erosion by major rivers in the past.
Answer:
Submarine canyons were most likely formed by erosion by major rivers in the past (option e)
Explanation:
A submarine canyon is a deep, relatively narrow, V-shaped depression whose bottom generally has a continuous slope. It can extend from the continental shelf to the great ocean depths.
Submarine canyons are habitats that appear interrupting the apparent homogeneity of the continental shelf. They play an important role in channeling organic matter. They transport sediments from the continental shelf to the deep ocean. Submarine canyons are usually found at the mouths of the rivers and are formed by the gigantic erosive power of the water that is slowly sculpting it from the continent, to the abysmal depths.
Submarine canyons were most likely formed by erosion by major rivers in the past (option e)
20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volume of the gas? (Assume that there's no change in temperature.)
A. 100 cubic inches
B. 10 cubic inches
C. 40 cubic inches
D. 5 cubic inches
Answer:
B. 10 cubic inches
Explanation:
Boyle's Law: States that the volume of a given mass of gas is inversely proportional to its pressure provided that temperature is constant.
Mathematically, Boyle's law can be expressed as
P₁V₁ =P₂V₂......................... Equation 1
making V₂ the subject of formula in the equation above,
V₂ = P₁V₁/P₂ ..................... Equation 2
P₁ =initial pressure, V₁ = initial volume, P₂ = final pressure, V₂ = final Volume.
Given: P₁ = 5 psi, V₁ = 20 cubic inches, P₂ = 10 psi.
Substituting these values into equation 2
V₂ = (5 × 20)/10
V₂ = 10 cubic inches.
Therefore the new volume = 10 cubic inches
The right option is B. 10 cubic inches.
2. According to research, what is the most reliable form of identifying potentially effective reinforcers?
The most reliable form of identifying potentially effective reinforcers is known as Preference Assessment. It is an adaptive procedure vastly used in the field of reinforcers.
Explanation:
Preference Assessment identifies items that are likely to be effective as reinforcers by identifying a particular learner's preference for them.
Reinforcement is an important part of being an effective behavior technician and the preference assessments are crucial.Plenty of research has shown that when you give the learner an opportunity to show you what they want that is a much better indication of what will work as a reinforcer rather than asking family.Preference assessments identify attention, objects or activities that have a strong potential for serving as reinforcers for target clients. There are ethical reasons to use them.Beyond the scope of the guide is the exhaustive review of the Preference assessment methodology and literature. However, interested readers go through Virus-Ortega et al(2014) for decision- making process and selecting an appropriate method of preference assessment for individuals with disabilities.The design phase in which a building project's basic functional requirements are first laid out (square footage, utility and equipment needs, and so on) is called the __________ phase.
a. contract
b. documents
c. design/development
d. schematic
e. design programming
Answer:
e. design programming
Explanation:
The planning techniques are responsible for structuring the tasks to be performed within the project, defining the duration and the order of execution of the same, while the programming techniques try to organize the activities so that the logical temporal relationships between them, determining the calendar or the moments of time in which each one must be realized. The programming must be consistent with the objectives pursued and respect existing restrictions (resources, costs, workloads).
The programming therefore consists in setting, in an approximate way, the moments of beginning and termination of each activity. Some activities may have slack and others are critical activities (fixed over time).
STEPS:
Build a time diagram (moments of beginning and slack of activities).
Establish the times of each activity.
Analyze project costs and adjust clearances (minimum cost project).
If the primary to secondary voltage ratio is 4:1 for a transformer, what is the secondary voltage if the primary voltage is 460 volts?
Explanation:
The primary to secondary voltage ratio is given as 4:1 .
That is
[tex]\frac{V_p}{V_s}=\frac{4}{1}=4[/tex]
We need to find what is the secondary voltage if the primary voltage is 460 volts.
That is
[tex]V_p=460V[/tex]
Substituting in ratio equation
[tex]\frac{V_p}{V_s}=4\\\\\frac{460}{V_s}=4\\\\V_s=\frac{460}{4}\\\\V_s=115V[/tex]
The secondary voltage is 115 V.
Final answer:
To find the secondary voltage in a transformer with a primary to secondary voltage ratio of 4:1 and a primary voltage of 460 volts, divide the primary voltage by 4, resulting in a secondary voltage of 115 volts.
Explanation:
To solve for the secondary voltage in a transformer when given a voltage ratio of 4:1 and a primary voltage of 460 volts, we can use the transformer equation.
This equation states the ratio of the secondary voltage (Vs) to the primary voltage (Vp) is equal to the ratio of the number of turns in the secondary coil (Ns) to the number of turns in the primary coil (Np).
In this question, the primary to secondary voltage ratio is 4:1. If the primary voltage (Vp) is 460 volts, we can calculate the secondary voltage (Vs) by dividing the primary voltage by the ratio, which in this case is 4. Therefore, Vs = 460 / 4 = 115 volts.
Sequence of analytic functions that map unit disk to unit disk and converge pointwise to 1 at some point. prove sequence converges normally to 1.
Answer:
Cause: If you have a disk that does not appear in File Explorer and is shown in Disk Management as Uninitialized, it may be because the disk does not have a valid disk signature. Basically, this means that it has never been initialized or formatted, or that the drive format has been damaged in some way.
It is also possible that the disk has hardware problems or problems connecting, but we will get to that in some paragraphs.
Solution: If the unit is completely new and should only be initialized, erasing the data it contains, the solution is easy: see Initialize new disks (Initialize new disks). However, there are many possibilities that you have already tried this and that it has not worked. Or maybe you have a disk full of important files and you don't want to erase it by initializing it.
There are a number of reasons why a disk may fail or that it did not have to be initially started, with a common reason why the disk is failing. There are many things that can be done to correct a disk error, but here are some steps to see if we get them to work again. If the disc works after performing one of these steps, do not worry about the following; just relax, celebrate it and, maybe, update the backups.
Examine the disk in Disk Management. If Disconnected appears as shown here, try to right-click on it and select Connected.
The disk appears as disconnected
If the disk appears in Disk Management as Connected and has a main partition that appears as Correct, as shown here, it is a good sign.
The disc is shown as connected with a correct volume
If the partition has a file system, but no drive letter (for example, E :), see Change a drive letter (Change a drive letter) to add a drive letter manually.
If you don't have a file system (NTFS, ReFS, FAT32 or exFAT) and you know the disk is empty, right-click on the partition and select Format. When formatting a disk, all the data it contains is erased, so don't do it if you are trying to recover files from the disk; instead, go to the next step.
If you have an external disk, disconnect it and reconnect it, and then select Action> Re-examine the disks.
Turn off your PC, disable the external hard drive (if it is an external drive with a power cable), and then reactivate your PC and disk. To deactivate your Windows 10 PC, select the Start button, then the power button, and then select Shut down.
Plug the disk into another USB port that you can find directly on your PC (not in a hub). Sometimes, USB disks do not have enough power from some ports or have other problems with certain ports. This is especially common with USB hubs, but sometimes there are differences between the ports of a computer, so you can try different ports, in case we have.
Try another cable. It might seem crazy, but the cables fail a lot, so you can try using another cable to connect the disk. If you have an internal disk on a desktop computer, you will probably need to turn off your PC before changing cables; Consult your PC manual for more information.
Composed by Device Manager to see if there are problems. Press and hold the Start button (or right-click on it), and then select Device Manager from the context menu. Search for devices with an exclamation point next to it or other problems, double-click on the device, and then read its status.
If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to the new value of the electric field at that same point?
a) 1:2
b) 1:3
c) 1:6
d) 1:9
Answer:
b)1 :3
Explanation:
Lets that
The value of a positive charge = q
As we know that electric filed on a point charge given as
[tex]E=\dfrac{Kq}{r^2}[/tex]
Where ,K=Constant
q=Charge ,r=Distance
If the value of the charge gets tripled ,q'= 3 q
Then electric filed E'
[tex]E'=\dfrac{Kq'}{r^2}[/tex]
[tex]E'=\dfrac{3Kq}{r^2}[/tex]
E' = 3 E
Therefore we can say that
[tex]\dfrac{E}{E'}==\dfrac{1}{3}[/tex]
therefore the answer will be --
b)1 :3
When the magnitude of a positive charge is tripled, the ratio of the original value of the electric field to the new value at the same point becomes 1:3. This is because the electric field is directly proportional to the charge. Therefore, if the charge is tripled, the electric field also triples.
If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to the new value of the electric field at that same point?
The electric field (E) created by a point charge (q) at a distance (r) is given by the equation:
[tex]E = k * q / r^2[/tex]
where k is the Coulomb constant. If the original charge is q and this creates an electric field E at distance r, then:
[tex]\text{Original Electric Field} (E_1) = k * q / r^2[/tex]
Now, if the charge is tripled, q becomes 3q. The new electric field (E2) is:
[tex]\text{New Electric Field} (E_2) = k * 3q / r^2[/tex]
Thus, the ratio of the original electric field (E1) to the new electric field (E2) is:
[tex]E_1 / E_2 = (k * q / r^2) / (k * 3q / r^2) = 1/3[/tex]
while tuning his violin the violinist compares the pitch his string produces to the pitch produced by an electronic tuner if the tuner produces a note with a frequency of 440 hz and the violine plays a note with a frequency of 443 hz what is the beat frequency produced?
Answer:
3 Hz
Explanation:
A beat is the pattern of interference among two waves with frequencies which are different.
The difference of the frequencies of the waves gives us the beat frequency.
Here, one frequency is [tex]f_1=440\ Hz[/tex], the other frequency is [tex]f_2=443\ Hz[/tex]
So, the beat frequency
[tex]\Delta f=|f_1-f_2|\\\Rightarrow \Delta f=|440-443|\\\Rightarrow \Delta f=3\ Hz[/tex]
The beat frequency that is produced is 3 Hz
The beat frequency is the difference between two interfering frequencies. In this case, it's the absolute difference between the violin string's frequency (443 Hz) and the electronic tuner's frequency (440 Hz), which results in a beat frequency of 3 Hz.
Explanation:In the context of music and acoustics, a beat frequency is the pulsating sound that results when two slightly different frequencies interfere with each other. It can be calculated by taking the absolute difference between the two frequencies. So when a violinist is tuning his violin and compares a string's frequency (443 Hz) with that of an electronic tuner (440 Hz), the beat frequency produced would be 443 Hz - 440 Hz = 3 Hz.
This means that the violinist would hear an oscillating sound 3 times per second due to the interference of the two frequencies. Just like a piano tuner, the violinist would then adjust the tuning of the string until this beat frequency is minimized, signifying that the string's frequency matches that of the tuner.
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A block floats partially submerged in a container of liquid. When the entire container is accelerated upward, which of the following happens? Assume that both the liquid and the block areincompressible.
(A) The block descends down lower into the liquid.(B) The block ascends up higher in the liquid.(C) The block does not ascend nor descend in the liquid.
(D) The answer depends on the direction of motion of the container.(E) The answer depends on the rate of change of the acceleration
When the entire container is accelerated upward, the block does not ascend nor descend in the liquid.
Explanation:The answer to the question is (C) The block does not ascend nor descend in the liquid.
When the entire container is accelerated upward, the liquid and the block inside it will experience the same acceleration. Since the block is partially submerged, both the liquid and the block will move together without any relative change in their positions. The buoyant force on the block remains the same, and the block does not ascend nor descend in the liquid.
At a place where an object is thrown vertically downward with a speed of while a different object is thrown vertically upward with a speed of Which object undergoes a greater change in speed in a time of 2 s?
Answer:
Both objects will undergo the same change in velocity
Explanation:
m = Mass of the Earth = 5.972 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Earth = 6371000 m
m = Mass of object
Any object which is falling has only the acceleration due to gravity.
[tex]ma=\dfrac{GMm}{r^2}\\\Rightarrow a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81364\ m/s^2[/tex]
The acceleration due to gravity on Earth is 9.81364 m/s²
So, the speeds of the objects will change at an equal rate of 9.81364 m/s² but the change will be negative when an object is thrown up.
Hence, both objects will undergo the same change in velocity.
The line of sight from a small boat to the light at the top of a 45-foot lighthouse built on a cliff 25 feet above the water makes a 20° angle with the water. To the nearest foot, how far is the boat from the cliff?
Answer:
The boat is 192 feet from the cliff.
Explanation:
Hi there!
Please see the attached figure for a graphical description of the problem.
Notice that the line of sight, the distance to the cliff and the height to the top of the lighthouse form a right triangle. Hence, we can apply trigonometric rules to find the distance from the boat to the cliff:
cos 20° = adjacent side / hypotenuse
sin 20° = opposite side / hypotenuse
The length of the opposite side is the height of the cliff plus the height of the lighthouse:
opposite side = 45 feet + 25 feet = 70 feet.
Using the equation of sin 20°, we can obtain the hypotneuse:
sin 20° = opposite side / hypotenuse
hypotenuse · sin 20° = opposite side
hypotenuse = opposite side / sin 20°
hypotenuse = 70 feet / sin 20°
hypotenuse = 205 feet
Now, using the equation of cos 20°, we can calculate the distance to the cliff (the length of the adjacent side):
cos 20° = adjacent side / hypotenuse
hypotenuse · cos 20° = adjacent side
205 feet · cos 20° = adjacent side
adjacent side = 192 feet (without rounding intermediate results)
The boat is 192 feet from the cliff.
Answer:
192 ft.
Explanation:
Tan (20) = Opp/Adj
Tan (20) = (45+25)/x
Tan (20) = 70/x
then x=70/Tan (20)
x= 192.3234 ft, and then rounded to the nearest foot...
x= 192 ft
PLLLZ HELP Compare and contrast electric potential energy and electric potential difference? Please use 2 content related sentences
The electric potential difference is the electric potential energy per unit charge
Explanation:
First of all, we define the concept of electric potential. The electric potential is a measure of the gradient of the electric field at a certain point of the space. The electric potential at a distance [tex]r[/tex] from a positive charge of magnitude [tex]q[/tex] is given by
[tex]V(r) = \frac{kq}{r}[/tex]
where k is the Coulomb's constant.
Now we can define the electric potential energy and the electric potential difference:
Electric potential energy is the energy possessed by a charge due to the presence of an electric field. For a charge of magnitude [tex]q[/tex] immersed in an electric field, its potential energy is given by [tex]U=qV[/tex], where V is the electric potential at the location of the charge.The electric potential difference is simply the difference in electric potential between two points in the space. For instance, if the potential at point A is V(A) and the potential at point B is V(B), then the potential difference is [tex]\Delta V = V(A)-V(B)[/tex]The electric potential energy is also defined as the work done on a charge q moved through a potential difference of [tex]\Delta V[/tex]. Consequently, the potential difference [tex]\Delta V[/tex] represents the work per unit charge done, i.e. the work done when moving a unitary charge through a potential difference [tex]\Delta V[/tex].
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Final answer:
Electric potential energy is related to the energy of a charge's position in a field, whereas electric potential difference, or voltage, relates to the work required to move a charge between two points in a field.
Explanation:
Electric potential energy is a measure of the potential energy stored in a system of charges based on their positions, much like gravitational potential energy in a system of masses. On the other hand, electric potential difference, often referred to as voltage, is the work needed to move a charge between two points in an electric field without producing an acceleration. An analogy that can be helpful in differentiating the two is thinking of electric potential energy as the energy associated with the charge's position, similar to a rock perched on a hill, while electric potential difference relates to the effort required to move a rock up or down that hill.
5. (II) A fisherman’s scale stretches 3.6 cm when a 2.4-kg fish hangs from it. (a) What is the spring stiffness constant and (b) what will be the amplitude and frequency of oscillation if the fish is pulled down 2.1 cm more and released so that it oscillates up and down?
The spring stiffness constant of the fisherman's scale, based on Hooke's Law, is 653.3 N/m. If a fish is pulled down further by 2.1 cm, it will oscillate with an amplitude of 5.7 cm and a frequency of approximately 0.816 Hz.
Explanation:To answer part (a) of your question about what the spring stiffness constant is, we use Hooke's Law. This law states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. This relationship is formally shown as F = k * x, where F is the force (in this case, the weight of the fish influences this force), k is what we are looking for (the spring stiffness constant), and x is the displacement (how much the spring stretches due to the force).
In this problem, the fish's weight becomes the force, which you can calculate as mass * gravity, or 2.4 kg * 9.8 m/s² = 23.52 N. The scale stretches 3.6 cm, or 0.036 m. Substituting these into Hooke's law gives us 23.52 N = k * 0.036 m, and solving for k provides a value of approximately 653.3 N/m. Thus, the spring stiffness constant is 653.3 N/m.
As for part (b) of the question, determining the amplitude and frequency of the oscillation if the fish is pulled down a further 2.1 cm and released, we know that the amplitude simply the displacement from the equilibrium position. Hence, total displacement from equilibrium is 3.6 cm (initial stretching) + 2.1 cm (additional pull) = 5.7 cm, or 0.057 m. This is the amplitude of the oscillation.
For the frequency of the oscillation, we need to understand the fish-spring system as a simple harmonic oscillator. The frequency (f) of a simple harmonic oscillator system is given by f = 1 / (2π) √(k/m), where k is the spring constant and m is the mass. Substituting our known values gives a frequency of approximately 0.816 Hz. Therefore, the oscillations will have an amplitude of 5.7 cm and a frequency of 0.816 Hz.
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A car traveling at 100 km/hr strikes an unfortunate bug and splatters it. The force of impact is:______
A) greater on the bug.
B) greater on the car.
C) the same for both.
Answer:
The force of impact is same for both objects.
Explanation:
It is given that,
Speed of the car, v = 100 km/h
It is understood that the mass of car is more than that of the bug. When one object strikes another object, they both applies a force on each other. One object applies the same force on another object when they strikes as per Newton's third law of motion.
In this case, when a car strikes a bug, the force of impact is the same for both. Hence, the correct option is (c).
According to Newton's third law, for every action, there is an equal and opposite reaction. Therefore, the force of impact when a car strikes a bug is the same for both. However, due to its smaller mass, the impact has a much larger effect on the bug.
Explanation:The subject of this question is Physics and it relates to the principle of Newton's Third Law which states that 'for every action, there is an equal and opposite reaction'. When the car and the bug collide, they apply forces to each other of equal magnitude and opposite direction. Thus, the force of impact is actually the same for both, as suggested by option C.
However, the consequences of this force are more notable for the bug due to its much smaller mass compared to the car. The high acceleration experienced by the bug (according to Newton's second law 'Force = Mass x Acceleration') causes it to splatter, while the car continues largely unaffected.
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When the dog shakes his body, his fur and the droplets of water clinging to it move in circular arcs. If the droplets leave the fur, what will be the subsequent motion? (For the short times in the video, motion due to gravity is negligible) A) The droplets will move in parabolic arcs. B) The droplets will move in straight-line paths C) The droplets will travel in circular arcs.
Applying Newton's laws of motion, the water droplets will continue in the direction they were moving at the moment of detachment, thus will travel in straight-line paths. This assumes that the effect of gravity is negligible.
Explanation:The subject of this question lies in the vicinity of Physics, specifically, the principles of Newton's laws of motion and projectile motion. To answer the question, when the dog shakes and the droplets leave the fur, the motion of these droplets will be in straight-line paths (Option B).
Let's consider why this happens. The movement of the water droplets is set in motion by the dog's shake, and upon detachment from the fur, the droplets will continue in the direction they were moving at the moment of detachment, following Newton's first law of motion. As we're assuming negligible gravity during this short time, the droplets will not fall towards the earth, hence move in straight-line paths rather than parabolic arcs.
It's important to remember the core tenets of Newton's laws of motion. An object at rest will stay at rest, and an object in motion will continue in a straight line unless acted upon by an external force.
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April works at the grocery store. She needs to move a heavy crate of bananas (m = 65 kg) to the produce section. She drags the crate along the floor by applying a force of 280 N at an angle of 35° above the horizontal.
a. If there is no friction, what is the acceleration of the crate? (5 points)
280/65=4.3
b. If the coefficient of kinetic friction between the crate and the floor is 0.4, what is the acceleration of the crate? (5 points)
a) The acceleration in absence of friction is [tex]3.5 m/s^2[/tex]
b) The acceleration in presence of friction is [tex]0.6 m/s^2[/tex]
Explanation:
a)
First of all, we notice that the crate accelerates only along the horizontal direction, since the forces in the vertical direction are balanced (in fact, the weight is balanced by the normal reaction + the vertical component of the applied force).
This means that we can consider only the horizontal component of the applied force, which is
[tex]F_x = F cos \theta = (280)(cos 35^{\circ})=229.4 N[/tex]
where
F = 280 N is the applied force
[tex]\theta=35^{\circ}[/tex] is the angle
Now we can find the acceleration of the crate, by using Newton's second law:
[tex]F_x = ma[/tex]
where
[tex]F_x = 229.4 N[/tex] is the net force along the horizontal direction
m = 65 kg is the mass of the crate
a is the acceleration
Solving for a, we find
[tex]a=\frac{F_x}{m}=\frac{229.4}[65}=3.5 m/s^2[/tex]
b)
In this case, we also have the force of friction, so we have to compute the force of friction.
We start by writing the equation of the forces along the vertical direction:
[tex]R+F sin \theta - mg = 0[/tex]
where
R is the normal reaction
[tex]F sin \theta[/tex] is the vertical component of the applied force
[tex]mg[/tex] is the weight
We can re-write this as
[tex]R=mg-Fsin \theta[/tex] (1)
Now we can write the equation of the forces along the horizontal direction
[tex]F cos \theta - \mu_k R = ma[/tex] (2)
where
[tex]F cos \theta[/tex] is the horizontal component of the applied force
[tex]\mu_K R[/tex] is the force of friction, with [tex]\mu_k = 0.4[/tex] is the coefficient of friction
By substituting (1) into (2) and solving for a, we find the new acceleration of the crate:
[tex]F cos \theta - \mu_k (mg-F sin \theta) = ma\\a=\frac{F cos \theta - \mu_k mg +\mu_k F sin \theta}{m}=\frac{(280)(cos 35)-(0.4)(65)(9.8)+(0.4)(280)(sin 35)}{65}=0.6 m/s^2[/tex]
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Answer:
3.53 m/s^2
Explanation:
Use the net x value.
Two long thin parallel wires 13.0 cm apart carry 25-A currents in the same direction.
1. Determine the magnitude of the magnetic field vector at a point 10.0 cm from one wire and 6.0 cm from the other.
2. Determine the direction of the magnetic field vector at that point.
Answer:
3.33 x 10⁻⁵ T
Explanation:
given,
current carried by two parallel wire = 25 A
distance between two wire = 13 cm
1) Let p be the distance between two wire
p = 13 cm = 0.13 m
a = 10 cm = 0.1 m
b = 6 cm = 0.06 m
using cosine law
[tex]p^2 = a^2 + b^2- 2ab cos\theta[/tex]
[tex]cos\theta =\dfrac{a^2+b^2}{2ab}[/tex]
[tex]\theta =cos^{-1}(\dfrac{0.1^2+0.06^2}{2\times 0.1 \times 0.06})[/tex]
θ = 105.96°
θ = 106°(approximately)
now, magnetic field on one wire
[tex]B_1 = \dfrac{\mu_oI}{2\pi r}[/tex]
[tex]B_1 = \dfrac{4\pi \times 10^{-7}\times 25}{2\pi (0.1)}[/tex]
B₁ = 5 x 10⁻⁵ T
now, magnetic field on another wire
[tex]B_2= \dfrac{\mu_oI}{2\pi r}[/tex]
[tex]B_2 = \dfrac{4\pi \times 10^{-7}\times 25}{2\pi (0.06)}[/tex]
B₂ = 8.33 x 10⁻⁵ T
resultant field,
= [tex]\sqrt{B_1^2+B_2^2 - 2 B_1B_2 cos \theta}[/tex]
= [tex]\sqrt{(5\times 10^{-5})^2+(8.33\times 10^{-5})^2 - 2\times 5 \times 10^{-5}\times 8.33 \times 10^{-5} cos 106^0}[/tex]
= 3.33 x 10⁻⁵ T
1) The magnitude of the magnetic field vector at the given point is; -3.195 * 10⁻⁵ T
2) The direction of the magnetic field vector at the given point is; 129.71° from the x-axis
What is the magnitude and direction of the magnetic Field?We will start with finding the direction of the field for each wire from the tangent to the circle around the wire.
For their magnitudes, we have;
B₁ = (µ₀/4π) * 2I₁/L₁
B₁ = (4π * 10⁻⁷/4π) * 2 * 25/0.1
B₁ = 5 * 10⁻⁵ T
B₂ = (µ₀/4π) * 2I₂/L₂
B₂ = (4π * 10⁻⁷/4π) * 2 * 25/0.06
B₂ = 8.33 * 10⁻⁵ T
If we draw a vector diagram, we will have;
B = B₁(-sin θ₁ i + cos θ₁ j) + B₂(-sin θ₂ i + cos θ₂ j)
B = (5 * 10⁻⁵ )(-sin 26.34 i + cos 26.34 j) + (8.33 * 10⁻⁵)(-sin 47.7 i + cos 47.7 j)
B = -(8.38 * 10⁻⁵) i + (10.09 * 10⁻⁵) j
Direction of the field is;
θ = tan⁻¹((10.09 * 10⁻⁵)/-(8.38 * 10⁻⁵)
θ = 129.71° from the x-axis
Thus, magnitude is;
B_mag = B₁ * cos 129.71°
B_mag = -3.195 * 10⁻⁵ T
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A student is pushing a 50 kg cart, with a force of 600 N. Another student measures the speed of the cart, and finds that the cart is only accelerating at 3 m/s^2. How much friction must be acting on the cart?
Answer:
450N
Explanation:
1) F=ma F2=50kg*3m/s^2=150N
2)Ff=F1-F2=600N-150N=450N
A student is pushing a 50 kg cart, with a force of 600 N. Another student measures the speed of the cart, and finds that the cart is only accelerating at 3 m/s². Friction force acting on the cart is 450 N.
What is force?
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given in the question a student is pushing a 50 kg cart, with a given force of [tex]F_1[/tex] = 600 N. Another student measures the speed of the cart, and finds that the cart is only accelerating at 3 m/s²,
F = ma
[tex]F_2[/tex] = 50 kg*3 m/s²
=150 N
Frictional force,
[tex]F_f[/tex] = [tex]F_1 - F_2[/tex]
= 600 N-150 N
= 450 N
A student is pushing a 50 kg cart, with a force of 600 N. Another student measures the speed of the cart, and finds that the cart is only accelerating at 3 m/s². Friction force acting on the cart is 450 N.
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If a wave hits a smooth surface at an angle of incidence of 40 degrees, the angle of reflection is
Answer:
Angle of reflection will be [tex]40^{\circ}[/tex]
Explanation:
We have given angle of incidence from the smooth surface is [tex]40^{\circ}[/tex]
So angle of incidence = [tex]40^{\circ}[/tex]
We have to find the angle of reflection
From l;aw of reflection we know that angle of reflection is equal to the angle of incidence
So angle of reflection will be equal to [tex]40^{\circ}[/tex]
Answer:
40 degrees
Explanation:
got it right
A PERT chart
a. is a numeric counterpart to the Gannt chart.
b. shows the variance of the critical path only.
c. is based on alpha distribution.
d. shows the variance of the critical path based on the alpha distribution
e. allows simulation of every path in the network, taking variances of each activity in consideration
Answer:
A.
Explanation:
A PERT chart is a project management tool that provides a graphical representation of a project's timeline. The Program Evaluation Review Technique (PERT) breaks down the individual tasks of a project for analysis. But PERT charts are considered preferable to Gantt charts because they identify task dependencies, but they're often more difficult to interpret.