When markups are based on the selling price, the selling price is seen as 100% since markup is a percentage of the selling price. The cost and markup together make up 100% of the selling price.
Explanation:When markups are based on the selling price, the selling price can be seen as 100%.
This is because the markup is calculated as a percentage of the selling price rather than the cost of the item.
Assuming that the entire selling price is 100%, the markup portion and the cost portion together make up this 100%.
The cost and markup are represented as percentages of the selling price, so if you know the cost and markup percentages, you can calculate the selling price.
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find two consecutive odd integers such that 54 more than the lesser is five times the greater
When determining slope, data points do not usually fall within a straight line, so you need to draw a _____ line, with as many points above and below the line as possible.
accurate
precise
best fit
correct
Answer:
The correct option is 3.
Step-by-step explanation:
If a straight line passes through some of the points, none of the points, or all of the points of a scatter plot and best represents the data, then it is called a best fit line.
Best fit line minimizes the squared distance of each point. Some points of the scatter plot lie above and below the best fit line.
When determining slope, data points do not usually fall within a straight line, so you need to draw a best fit line, with as many points above and below the line as possible.
Therefore the correct option is 3.
Solve for q 8r-5q=3
94.99 in expanded form
Assume f(x)=4x+8 and g(x)=5. What is the value of (g o f)(-1)?
The pie below is cut into 6 equal slices. Show shade2/3 of this pie
Using place value to alter the amount of 194753 by two thousand
a tour bus cost $75 plus $6 for each passenger. write and evaluate an expression to find the total cost for 25 passengers. then. make a table showing the cost for 26, 30, 35, 40 passengers
Find a + b, 2a + 3b, |a|, and |a − b|. a = 5i + j, b = i − 3j
A soccer ball is kicked from the ground. After traveling a horizontal distance of 35m, it just passes over a 1.5m tall fence before hitting the ground 37m from where it was kicked. How far has the ball travelled horizontally to reach the maximum height?
Answer:
18.5 meters
Step-by-step explanation:
As the maximum height ona projectile motion that starts from the ground and finishes at the ground is simmetric, the maximum height of the projectile will be found exactly at half of the distance tranveled horizontally, so the exact half of the total distance traveled horizontally is 18.5 meters, since distance is 37 meters and divided by 2 is 18.5.
The ball will travel 18.5 meters to reach its maximum height.
please help 13(3+2x)−1=10
Yolanda walks 1.5km every day. How far does she walk in 9 days? Write your answer in meters.
Write 3.16 as a mixed number in lowest terms
5. Suppose that a and b are both real numbers such that a < b. What can you conclude about the inequality 1/a < 1/b?
a. 1/a < 1/b is always true.
b. 1/a < 1/b is sometimes true.
c. 1/a < 1/b is never true.
d. A valid conclusion cannot be determined from the given information.
For a school assembly, students sit in chairs that are arranged in 53 rows. There are 12 chairs in each row. About how many students can be seated?
In a certain grocery store, strawberries cost $5.92 per pound ( 5.92 dollars/lb ). what is the cost per ounce? express your answer numerically to the hundredths place.
a circus performer walks on a tightrope 25 feet above the ground. the tightrope is supported by two beams and two support cables. if the distance between each beam and the base of its support cable is 15 feet, what is the length of the support cable?
Answer:29.15475947 (not rounded)
Step-by-step explanation:
.002 is 1/10 of what
.002 is 1/10 of 0.02. To find this, we multiply .002 by 10. This is seen as moving the decimal point to the right once because we are multiplying by a power of ten.
Explanation:The student asked: ".002 is 1/10 of what". To find the answer to this question, we can set up a simple equation where we multiply .002 by 10 because we know that if .002 is 1/10 of a number, then multiplying it by 10 will give us that whole number.
So the equation is:
.002 x 10 = 0.02Therefore, .002 is 1/10 of 0.02.
This can also be understood by recognizing that when dividing by powers of 10, you move the decimal to the left by the number of zeros in the power of ten. So, in the reverse process, when we want to find a number that is ten times larger (i.e., 1/10 of the original), we move the decimal one place to the right.
solve the equation 0.4+0.5=-4.7-0.6z
Simplify the expression and eliminate any negative exponent(s). Assume that all letters denote positive numbers.
√s√s^9
What is the greatest whole number that rounds to 54,300
Simplify the expression 16 − x2 as much as possible after substituting 4 sin θ for x. (assume 0° < θ < 90°.)
The value of the expression [tex]16 - x^{2}[/tex] is 16 cos^2θ
Here,
The expression is [tex]16 - x^{2}[/tex]
We have to find the value of expression after substitute 4 sinθ for x.
What is substitution method?
Substitution method is algebraic method to solve the linear equations.
Now,
The expression is [tex]16 - x^{2}[/tex]
By putting x = 4 sinθ in above equation, we get;
[tex]16 - x^{2}[/tex] = 16 - ( 4 sinθ)^2
= 16 - 16 sin^2θ
= 16 ( 1 - sin^2θ )
= 16 cos^2θ
Since, 1 - sin^2θ = cos^2θ
Hence, The value of the expression [tex]16 - x^{2}[/tex] is 16 cos^2θ
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To simplify the expression 16 - x² after substituting 4 sin θ for x, you end up with 16 cos² θ, using the Pythagorean trigonometric identity.
Explanation:To simplify the expression 16 - x² after substituting 4 sin θ for x, where 0° < θ < 90°, we follow these steps:
Substitute 4 sin θ into the expression for x.Simplify the resulting expression.The substitution gives us 16 - (4 sin θ)².
To further simplify:
Calculate the square of 4 sin θ, which is 16 sin² θ.Subtract 16 sin² θ from 16, giving us 16 - 16 sin² θ.Factor out the common factor of 16, resulting in 16(1 - sin² θ).Recognize that (1 - sin² θ) is equal to cos² θ due to the Pythagorean identity.Finally, the simplified expression is 16 cos² θ.The dress store is having a sale where all merchandise is 1/4 off. A woman buys $48 of merchandise at the sale price
The woman should have paid \$64 for the regular price of the merchandise.
To find out what the woman should have paid for the regular price, we need to reverse engineer the discount. Here's the step-by-step calculation:
Calculate the Discount Amount: Since the sale is 1/4 off, the discount is 1/4 of the regular price. So, the discount is:
[tex]\[ \frac{1}{4} \times \text{Regular Price} \][/tex]
[tex]\[ \text{Discount} = \frac{1}{4} \times \text{Regular Price} \][/tex]
Subtract the Discount from the Regular Price to Get the Sale Price: The sale price is the regular price minus the discount:
[tex]\[ \text{Sale Price} = \text{Regular Price} - \text{Discount} \][/tex]
Calculate the Sale Price: We know the woman bought $48 worth of merchandise at the sale price, so:
[tex]\[ \text{Sale Price} = \$48 \][/tex]
Find the Regular Price: Now we can set up an equation using the information we have:
[tex]\[ \$48 = \text{Regular Price} - \text{Discount} \][/tex]
Substituting the discount calculated earlier:
[tex]\[ \$48 = \text{Regular Price} - \left(\frac{1}{4} \times \text{Regular Price}\right) \][/tex]
Solve for the Regular Price:
[tex]\[ \$48 = \left(\frac{4}{4}\right) \times \text{Regular Price} - \left(\frac{1}{4}\right) \times \text{Regular Price} \][/tex]
[tex]\[ \$48 = \left(\frac{3}{4}\right) \times \text{Regular Price} \][/tex]
To isolate the regular price, multiply both sides by [tex]\( \frac{4}{3} \)[/tex]:
[tex]\[ \text{Regular Price} = \$48 \times \frac{4}{3} \][/tex]
[tex]\[ \text{Regular Price} = \$64 \][/tex]
So, the woman should have paid $64 for the regular price of the merchandise.
Complete Question:
The dress store is having a sale where all merchandise is 1/4 off a woman buys $48 of merchandise at the sale price what should she have paid for the regular price
The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a mean of 235andastandarddeviationof235andastandarddeviationof 20. according to the standard deviation rule, how much did almost all (99.7%) of the students spend on textbooks in a semester?
Which is greater, the greatest whole number with 4 digits or the least whole number with 5 digits?
which undefined using the undefined terms point más line?
A angle
B circle
C parallel lines
D ray
the table represents a linear function?
Answer: 5
Step-by-step explanation:
In the given picture we have a table representing two columns as x and y.
We know that the slope of the function is given by :-
[tex]k=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Using points (0,4) and (2,14) from the table , we get the slope of the function will be :-
[tex]k=\dfrac{14-4}{2-0}\\\\\\=\dfrac{10}{2}=5[/tex]
Therefore, the slope of the given function in the table = 5
If g(t)=4t-t^2, find g(t+h)-g(t)/h.
Jesse was ranked 11th in his graduating class of 180 students. At what percentile is Jesse's ranking? (Round your answer to the nearest whole number.)
Find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (2, 4), and the x-axis.
The area of the region is [tex]\(\frac{64}{3}\)[/tex] square units.
To find the area of the region bounded by the parabola \(y = x^2\), the tangent line at the point (2, 4), and the x-axis, we'll first determine the points of intersection.
The tangent line at (2, 4) has the same slope as the derivative of the parabola at x = 2. The derivative of [tex]\(y = x^2\)[/tex] is [tex]\(2x\)[/tex], so at x = 2, the slope is [tex]\(2 \times 2 = 4\)[/tex]. Thus, the equation of the tangent line is [tex]\(y - 4 = 4(x - 2)\)[/tex].
Now, let's find the points of intersection between the parabola and the tangent line:
[tex]\[x^2 = 4(x - 2) + 4\][/tex]
Solving for x, we get [tex]\(x^2 - 4x = 0\)[/tex], which factors to [tex]\(x(x - 4) = 0\)[/tex]. So, [tex]\(x = 0\)[/tex] and [tex]\(x = 4\)[/tex].
Now, integrate the absolute difference of the functions from 0 to 4 to find the area:
[tex]\[A = \int_0^4 |x^2 - (4x - 4)| \,dx.\][/tex]
Evaluate the integral:
[tex]\[A = \int_0^4 (x^2 - 4x + 4) \,dx = \frac{1}{3}x^3 - 2x^2 + 4x \Big|_0^4 = \frac{64}{3}.\][/tex]
Therefore, the area of the region is [tex]\(\frac{64}{3}\)[/tex] square units.
The answer is: [tex]\frac{8}{3}[/tex].
The area of the region bounded by the parabola [tex]\( y = x^2 \)[/tex], the tangent line to this parabola at the point (2, 4), and the x-axis is given by the integral of the difference between the parabola and the tangent line from [tex]\( x = 0 \) to \( x = 2 \)[/tex].
First, we need to find the equation of the tangent line to the parabola at the point (2, 4). The slope of the tangent line is the derivative of the parabola's equation at \( x = 2 \). The derivative of [tex]\( y = x^2 \)[/tex] is [tex]\( y' = 2x \).[/tex] At[tex]\( x = 2 \)[/tex], the slope is [tex]\( 2 \cdot 2 = 4 \)[/tex].
Using the point-slope form of a line,[tex]\( y - y_1 = m(x - x_1) \)[/tex], where [tex]\( m \)[/tex] is the slope and [tex]\( (x_1, y_1) \)[/tex] is a point on the line, we get the equation of the tangent line as follows:
[tex]\[ y - 4 = 4(x - 2) \][/tex]
[tex]\[ y = 4x - 8 + 4 \][/tex]
[tex]\[ y = 4x - 4 \][/tex]
Now, we will find the area under the parabola and above the tangent line from [tex]\( x = 0 \) to \( x = 2 \)[/tex]. The integral of [tex]\( x^2 \)[/tex] from 0 to 2 is:
[tex]\[ \int_{0}^{2} x^2 \, dx = \left[ \frac{x^3}{3} \right]_{0}^{2} = \frac{2^3}{3} - \frac{0^3}{3} = \frac{8}{3} \][/tex]
The integral of the tangent line \( y = 4x - 4 \) from 0 to 2 is:
[tex]\[ \int_{0}^{2} (4x - 4) \, dx = \left[ 2x^2 - 4x \right]_{0}^{2} = (2 \cdot 2^2 - 4 \cdot 2) - (2 \cdot 0^2 - 4 \cdot 0) = (8 - 8) - (0 - 0) = 0 \][/tex]
The area between the parabola and the tangent line is the difference between these two integrals:
[tex]\[ \text{Area} = \int_{0}^{2} x^2 \, dx - \int_{0}^{2} (4x - 4) \, dx \][/tex]
[tex]\[ \text{Area} = \frac{8}{3} - 0 \][/tex]
[tex]\[ \text{Area} = \frac{8}{3} \][/tex]
Therefore, the area of the region bounded by the parabola [tex]\( y = x^2 \)[/tex], the tangent line at the point (2, 4), and the x-axis is [tex]\( \boxed{\frac{8}{3}} \)[/tex] square units.