When given a raw score, explain how to use the normal curve to compare to the population

Answers

Answer 1
The problem ask to explain the use if the normal curve to compare that score to the population and the best explanation is that the normal curve depends on a lot of assumptions. If the population score are normally distributed, we will know its mean and standard deviation, so can tell that our particular individual's row score falls on that distributions.

Related Questions

Find the slope and y intercept

Answers

Y-intercept is the y-value when x = 0. Let's consider coordinates (1, 11) and (2, 14). The x-value increased by 1 and the y-value increased by 3. If we assume this is linear, which it is, then the slope is 3. y = 3x + b. We solve b by plugging in a random set of coordinates, such as (1, 11).

11 = 3(1) + b
b = 11 - 3
b = 8

y = 3x + 8 is the equation, slope of 3 and y-intercept is 8.

Evaluate ƒ(x) = 3x + 8 for x = 1.

Answers

f equals 11 because it three times 1 plus eight.

Answer:  The required value of f(x) for x = 1 is 11.

Step-by-step explanation:  We are given to evaluate f(x) for x = 1, where

[tex]f(x)=3x+8~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

To evaluate the required value, we need to substitute x = 1 in expression (i).

So, putting x = 1 in (i), we get

[tex]f(1)=3\times1+8=3+8=11.[/tex]

Thus, the required value of f(x) for x = 1 is 11.

Tony ran laps around a track to raise money for a hospital. Tony raised $15 plus $1.50 per lap that he ran. He raised a total of $255.

Let x represent the number of laps Tony ran.

What expression completes the equation to determine the total number of laps Tony ran?

How many laps did Tony run?

Answers

Let x represent the number of laps Tony ran,

15 + 1.5x = 255
1.5x = 240
x = 160

Tony ran 160 laps.

15 + 1.5x = 255

and 160 laps


Expressions to Radical Form
I always have a hard time with radicals...

Answers

To do this, take the cube root of every term:

The cube root of -64 is -4
The cr of x^6 is x^2
The cr of y^9 is y^3

Now put these all together:

-4x^2y^3

Hope this helped!

Help please algebra

Answers

B, C, E, F  are your answer

hope this helps

Suppose that receiving stations​ X, Y, and Z are located on a coordinate plane at the points ​(3,3​), ​(-13​, −5​), and ​(-5​,3), respectively. The epicenter of an earthquake is determined to be 5 units from X​, 13 units from​ Y, and  5 units from Z. Where on the coordinate plane is the epicenter​ located?

Answers

Final answer:

The epicenter is located at (-5, 1) on the coordinate plane.

Explanation:

To find the coordinates of the epicenter, we need to find the average of the coordinates of the three receiving stations. The x-coordinate of the epicenter is (3 - 13 - 5)/3 = -5, and the y-coordinate is (3 - 5 + 3)/3 = 1. Therefore, the epicenter is located at (-5, 1) on the coordinate plane.

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The coordinates of the epicenter of earthquake are (-1, 0).

The epicenter of the earthquake is the point that is equidistant from stations X, Y, and Z. This is essentially the solution to a system of three equations representing the distances from the epicenter to each of the three stations.

The equations are derived from the distance formula, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex] ,

where [tex](x_1,y_1)[/tex] and [tex](x_2, y_2)[/tex] are the coordinates of the two points and d is the distance between them.

For station X at (3,3), the distance to the epicenter (x,y) is 5 units. So, the equation is:

[tex](x - 3)^2 + (y - 3)^2 = 5^2 = 25 \text{ ....(1)}[/tex]

For station Y at (-13,-5), the distance to the epicenter is 13 units. So, the equation is:

[tex](x + 13)^2 + (y + 5)^2 = 13^2 = 169\text{ ....(2)}[/tex]

For station Z at (-5,3), the distance to the epicenter is 5 units. So, the equation is:

[tex](x + 5)^2 + (y - 3)^2 = 5^2=25 \text{ ....(3)}[/tex]

Solving this system of equations will give the coordinates of the epicenter.

Subtract equation (1) from equation (2), we get:

[tex](x^2+26x+169+y^2+10y+25)-(x^2-6x+9+y^2-6y+9) = 144\\\\\text{Simplifying, we get:}\\32x+16y+176=144\\32x+16y = -32\\\text{Divide by 16 on both sides of the equation, we get:}\\2x + y = -2[/tex]

Subtract equation (1) from equation (3), we get:

[tex](x+5)^2+(y-3)^2-(x-3)^2-(y-3)^2 = 0\\x^2+10x+25-(x^2-6x+9)=0\\16x + 16 = 0\\\text{Dividing by 1 on both sides, we get}\\x + 1 =0\\\text{We get:}\\x = -1[/tex]

Putting x = -1 in the equation 2x + y = -2, we get:

2(-1) + y = -2

We get,

y = 0

So, the coordinates of the epicenter of earthquake are (-1, 0).

Mei draws three pairs of parallel lines that are each intersected by a third line. In each figure, she measures a pair of angles. What is a reasonable conjecture for Mei to make by recognizing a pattern and using inductive reasoning? A. When a pair of parallel lines are intersected by a third line, the alternate interior angles are congruent. B. When a pair of parallel lines are intersected by a third line, the alternate interior angles are acute. C. When a pair of parallel lines are intersected by a third line, all of the angles formed are obtuse. D. When a pair of parallel lines are intersected by a third line, all of the angles formed are congruent.

Answers

The only correct statement among the choices is:

A. When a pair of parallel lines are intersected by a third line, the alternate interior angles are congruent.

 

This statement can actually be proven by measuring the angles of the alternate interior angles. We can actually see that they have equal measurements. While the adjacent interior angles are supplementary angles.

Why are volumetric measurements defined as a cubed unit?

Answers

A unit, such as a cubic foot, or a system of units used to measure volume or capacity
When you are measuring a volumetric figure, you use the cubic units as a measurements because it is the most precise way to figure out the measurements of any volumetric figure.

does anyone understand how to do this? Solve r4<−5 or −2r−7 ≤ 3 . The solution is _or_

Answers

Final answer:

The given problem consists of solving two inequalities. The first one, r4<−5, is invalid since the 4th power of any real number cannot be a negative number. For the second inequality, −2r−7 ≤ 3, the solution is r ≥ -5.

Explanation:

The subject of this question is Mathematics, specifically relating to solving inequalities. To answer your question, let's solve the two given inequalities independently. Starting with the first one, r4<−5, this inequality is invalid as the 4th power of any real number (r) cannot be less than -5. Moving on to the second inequality, −2r−7 ≤ 3, we first add 7 to both sides to isolate the term with the variable, giving us -2r ≤ 10. Dividing both sides by -2 (remember to flip the inequality sign when multiplying or dividing by a negative number) gives us r ≥ -5. Therefore, the solution to the given inequalities is r ≥ -5.

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Milk cartons come in crates of 24. how many crates does a school need to order to serve to 400 students

Answers

divide 400 by 24

400 / 24 = 16.666

 so they would need to buy 17 crates

What is the value in dollars of a stack of dimes that is 10 cm high? (1mm = 1 dime?

Answers

$10 because:

Since a dime is about 1 mm thick (10mm equals 1 cm), 10 cm high would be 100 dimes.

10 dimes = $1
$1 times 10 = $10

The value in dollars of a stack of dimes that is 10 cm high is $10.

What are nickles, dimes, quarters and cents?

A dollar is further divided into some majorly used parts as:

A cent = 100th part of a dollar = $1/100 = $0.01

A nickle= 20th part of a dollar = $1/20 = $0.05

A dime = 10th part of a dollar = $1/10 = $0.10

A quarter = 4th part of a dollar = $1/4 = $0.25

If each dime is 1 mm then 10 dimes will be 1 cm high;

1 dime / 1 mm = x dimes / 10 mm Cross multiply

1 dime * 10 mm = x * 1 mm

10 dimes = x The mm

Since a dime is about 1 mm thick (10mm equals 1 cm), 10 cm high would be 100 dimes;

10 dimes = $1

$1 times 10 = $10

Hence, The value in dollars of a stack of dimes that is 10 cm high is $10.

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simplify

3m^-2
over
5n^-3

Answers

3m^-2           3n^3
---------    =  -----------
5n^-3            5m^2

hope it helps
reember
[tex]\frac{x^m}{x^n}=x^{m-n}[/tex]
[tex]x^{-m}=\frac{1}{x^m}[/tex]


[tex]\frac{3m^{-2}}{5n^{-3}}=[/tex]
[tex]frac{\frac{3}{m^2}}{\frac{5}{n^3}}=[/tex]
[tex]\frac{3n^3}{5m^2}[/tex]

The number of minutes taken for a chemical reaction if f(t,x). it depends on the temperature t degrees celcius, and the quantity, x grams, of a catalyst present. when the temperature is 30 degrees celcius and there are 5 grams of catalyst, the reaction takes 50 minutes. increasing the temperature by 3 degrees reduces the time taken by 5 minutes. increasing the amount of catalyst by 2 grams decreases the time taken by 3 minutes. use this information to find the partial derivatives fx(30,5) and ft(30,5). use the tangent plane approximation to find f(33,4).

Answers

Final answer:

The partial derivatives fx(30,5) and ft(30,5) can be calculated using the given information, and the tangent plane approximation can be used to estimate f(33,4).

Explanation:

The chemical reaction time is represented by the function f(t,x), where t is the temperature in degrees Celsius and x is the quantity of a catalyst present in grams. We are given that when the temperature is 30 degrees Celsius and there are 5 grams of catalyst, the reaction takes 50 minutes. Additionally, increasing the temperature by 3 degrees reduces the time taken by 5 minutes, and increasing the amount of catalyst by 2 grams decreases the time taken by 3 minutes.

To find the partial derivative fx(30,5), we need to find the rate of change of the reaction time with respect to the quantity of catalyst, while holding the temperature constant. Using the given information, we can calculate:

fx(30,5) = (f(30,5+2)-f(30,5))/2 = (-3)/2 = -1.5

To find the partial derivative ft(30,5), we need to find the rate of change of the reaction time with respect to the temperature, while holding the quantity of catalyst constant. Using the given information, we can calculate:

ft(30,5) = (f(30+3,5)-f(30,5))/3 = (-5)/3 = -1.67

Using the tangent plane approximation, we can estimate f(33,4) by calculating the change in reaction time by adjusting the temperature to 33 degrees Celsius and the quantity of catalyst to 4 grams.

f(33,4) = f(30,5) + ft(30,5) * (33-30) + fx(30,5) * (4-5)

f(33, 4) = 50 + (-1.67) * 3 + (-1.5) * -1 = 50 - 5.01 + 1.5 = 46.49

[tex]\( f_t(30,5) = -\frac{5}{3} \)[/tex], [tex]\( f_x(30,5) = -1.5 \)[/tex], [tex]\( f(33,4) \approx 46.5 \)[/tex] minutes.

ft (30, 5) =_[tex]\(-\frac{5}{3} \)[/tex]_ fx (30,5) =_-1.5_ f (33,4)=__46.5 minutes__

To find the partial derivatives [tex]\( f_t(30,5) \)[/tex] and [tex]\( f_x(30,5) \)[/tex], we'll use the given information about how changes in [tex]\( t \) and \( x \)[/tex] affect the time [tex]\( f(t,x) \)[/tex].

Given:

- [tex]\( f(30,5) = 50 \)[/tex] minutes

- Increasing [tex]\( t \)[/tex] by 3 degrees Celsius reduces [tex]\( f \)[/tex] by 5 minutes.

- Increasing [tex]\( x \)[/tex] by 2 grams decreases [tex]\( f \)[/tex] by 3 minutes.

1. Partial derivative with respect to [tex]\( t \) at \( (30,5) \)[/tex]:

  - Change in [tex]\( t \): \( \Delta t = 3 \)[/tex] degrees Celsius

  - Change in [tex]\( f \): \( \Delta f = -5 \)[/tex] minutes

  - Using the definition of partial derivative:

    [tex]\[ f_t(30,5) = \frac{\Delta f}{\Delta t} = \frac{-5}{3} = -\frac{5}{3} \text{ minutes/degree Celsius} \][/tex]

2. Partial derivative with respect to [tex]\( x \) at \( (30,5) \)[/tex]:

  - Change in [tex]\( x \): \( \Delta x = 2 \)[/tex] grams

  - Change in [tex]\( f \): \( \Delta f = -3 \)[/tex] minutes

  - Using the definition of partial derivative:

    [tex]\[ f_x(30,5) = \frac{\Delta f}{\Delta x} = \frac{-3}{2} = -1.5 \text{ minutes/gram} \][/tex]

Now, to find [tex]\( f(33,4) \)[/tex] using the tangent plane approximation, we'll use the partial derivatives we found and the point [tex]\( (30,5) \)[/tex] as a reference:

The tangent plane approximation formula is:

[tex]\[ f(t,x) \approx f(30,5) + f_t(30,5)(t-30) + f_x(30,5)(x-5) \][/tex]

Substituting the values:

[tex]\[ f(33,4) \approx 50 + \left(-\frac{5}{3}\right)(33-30) + (-1.5)(4-5) \][/tex]

[tex]\[ f(33,4) \approx 50 - 5 + 1.5 \][/tex]

[tex]\[ f(33,4) \approx 46.5 \text{ minutes} \][/tex]

So, [tex]\( f(33,4) \approx 46.5 \)[/tex] minutes.

Thus:

- [tex]\( f_t(30,5) = -\frac{5}{3} \)[/tex] minutes/degree Celsius

- [tex]\( f_x(30,5) = -1.5 \)[/tex] minutes/gram

- [tex]\( f(33,4) \approx 46.5 \)[/tex] minutes

The correct question is:

The number of minutes taken for a chemical reaction if f(t,x). It depends on the temperature t degrees Celsius, and the quantity, x grams, of a catalyst present. When the temperature is 30 degrees Celsius and there are 5 grams of catalyst, the reaction takes 50 minutes. Increasing the temperature by 3 degrees reduces the time taken by 5 minutes. Increasing the amount of catalyst by 2 grams decreases the time taken by 3 minutes. Use this information to find the partial derivatives fx(30,5) and ft(30,5). Use the tangent plane approximation to find f(33,4). ft (30, 5) =__________ fx (30,5) =__________ f (33,4)=__________

A wire is first bent into the shape of a triangle. Each side of the triangle is
12cm long. Then the wire is unbent and reshaped into a square. What is the length of a side of the square?

Answers

First find the area of the wire. The wire is 36 square root of 3 or approximately 62.35 cm. Then divide that by 4.
The length of a side is 9 square root of 3 or approximately 15.588 cm

Final answer:

By dividing the total length of the wire (36 cm) by the number of sides of a square (4), we find that the length of one side of the square is 9 cm.

Explanation:

We start by calculating the total length of the wire when it was bent into an equilateral triangle. Since each side is 12 cm long and there are three sides, the total wire length is 3 × 12 cm = 36 cm. When the wire is unbent and reshaped into a square, the total wire length remains the same; thus, the perimeter of the square is also 36 cm. A square has four equal sides, so the length of each side of the square is the perimeter divided by four.

Length of one side of the square = Total wire length ÷ 4

Length of one side of the square = 36 cm ÷ 4

Length of one side of the square = 9 cm

two parallel lines are coplanar (always,sometimes, or never true)

Answers

Two lines are parallel lines if they are coplanar and do not intersect. Lines that are not coplanar and do not intersect are called skew lines. Two planes that do not intersect are called parallel planes. Therefore two parallel lines are always coplaner.

Hope this helps! If you have any questions just ask!
never true i think i mean if you look at it good you would know what i mean

The half-life of rhodium, Rh-106, is about 30 seconds. You start with 500 grams.

Answers

I think the logical question for this would be to find the reaction rate constant, k, for radioactive decay of Rhodium. The general formula is:

ln A/A₀ = -kt,
where 
A is the amount of substance after time t,
A₀ is the original amount of substance
t is the time

After 30 s, the amount of Rhodium would be in half. So, A/A₀ = 1/2

ln(1/2) = -k(30 s)
k = 0.023 s⁻¹

whats the area of a cardboard In one carton if the length is 9 inches height is 9inches width is 4 inches and is 240 ml as well as also in a 946 ml container and a 1.89 L container?

Answers

Assuming that the cardboard forms a regular rectangle, therefore the area of the cardboard is simply taken to be the product of length and width. Therefore:

A = l w

A = (9 inches) * (4 inches)

A = 36 square inches = 36 inches^2

Suppose Mrs. Reyes would like to save Php 1,000.00 at the end of each month for 9 months in a fund that gives 5% per annum compounded monthly. How much would the value of her savings be after 7 months?

Answers

The rate is r = 5% = 0.05
Compounding interval, n = 12, monthly compounding
Therefore
r/n = 0.05/12 = 0.004167

The first deposit has a duration of 7 months. Its value is
a₁ = 1000*(1.004167)⁷

The second deposit has a duration of 6 months. Its value is
a₂ = 1000*(1.004167)⁶
and so on.

The values after each month from a geometric sequence with
a = 1000*(1.004167)
r = 1.004167

Over 7 months, the total sum is
[tex] \frac{1000*1.004167*(1-1.004167^{7} )}{1-1.004167} =7117.64[/tex]


Answer: Php 7,117.64

After 7 months her savings will be 7117.64.

Step-by-step explanation:

Given :

Rate is r = 5% = 0.05

Compounding interval, n = 12

Solution :

Now,

[tex]\rm \dfrac{r}{n} = \dfarc{0.05}{12}[/tex]

[tex]\rm \dfrac{r}{n} = 0.004167[/tex]

Now first deposit duration is 7 months. Therefore, its value is  [tex]\rm a_1 = 1000\times (1.004167)^7[/tex]

Now second deposit duration is 6 months. Therefore, its value is

[tex]\rm a_2 = 1000\times (1.004167)^6[/tex]

Now third deposit duration is 5 months. Therefore, its value is

[tex]\rm a_3 = 1000\times (1.004167)^5[/tex]

and so on.

The values are in geometric sequence where

[tex]\rm a = 1000\times (1.004167)[/tex]

[tex]\rm r = 1.004167[/tex]

We know that the sum of the geometric sequence is given by,

[tex]\rm S_n = \dfrac{a (r^n-1)}{(r-1)}[/tex]    ------ (1)

Now put the values of a and r in equation (1),

[tex]\rm S_7=\dfrac{1000\times(1.004167)((1.004167)^7-1)}{(1.004167-1)}[/tex]

[tex]\rm S_7 = 7117.64[/tex]

After 7 months her savings will be 7117.64.

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a model car is 4inhes long actual car is 15ft long what is the reduced ratio of the model to the actual

Answers

15 ft = 15*12 = 180 inches

180/4 = 45

 so the scale is 1/45

How is the parent function y=x2 related to the given function Y=3(x+1)2?

Answers

parent function: y = f(x) = x^2

given function: y = g(x) = 3 (x+1)^2

=> g(x) = 3 * f(x + 1)^2

So, from the point of view of graphs, the given function, g(x), is the parent function, f(x) = x^2, shifted one unit to the left and amplified by a factor of 3.


We have 5 dice, 4 of these dice are the same, the fifth is not. find it!

Answers

The dice that we are examining are shown in the attached picture.

Now, notice the pattern shown on each dice.
You will find that the pattern is 6,5 and 4.

Now, notice the way that this pattern is ordered. You will find that:
for dice a,b,c and e : the pattern is shown in a clockwise direction order
for dice d: the pattern is shown in an anti-clockwise direction order.

This means that: dice D is the different one

The dice are illustrations of patterns

The fifth die that is different from the other four dice is die D

From the question, we have the following highlights

The pattern on all the 5 dice include 4, 5 and 6When the patterns are ordered, dice A, B, C and E have their pattern to be in a clockwise directionDie D has its pattern to be in a counterclockwise direction

Hence, the fifth die that is different from the other four dice is die D

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Find the slope of the line that passes through the pair of points.

Answers

Slope :  y2 - y1 / x2 - x1

( 2 , 6 ) (7 , 0) 

0 - 6 /  7 - 2

- 6 / 5 is the slope 

Answer:

Option B is correct

Slope of the lines that passes through the given points is, [tex]\frac{-6}{5}[/tex]

Step-by-step explanation:

Given: The points (2 , 6) and (7 ,0).

Slope of a line identify the direction of a line. To find the slope, you divide the difference of the y-coordinates of two points on a line by the difference of the x- coordinates of those same two  points.

For any two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] the slope(m) of a line is given by;

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

Now, substitute the point (2 ,6 ) and ( 7, 0) in the slope formula we have;

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}=\frac{0 - 6}{7-2}[/tex] = [tex]\frac{-6}{5}[/tex]

therefore, the slope of the line that passes through the pair of points is;   [tex]\frac{-6}{5}[/tex]

A Web music store offers two versions of a popular song. The size of the standard version is 2.1 megabytes (MB). The size of the high-quality version is 4.1 MB. Yesterday, there were 1010 downloads of the song, for a total download size of 2761 MB. How many downloads of the high-quality version were there?

Answers

If the number of downloads of the standard version is x, and the high quality is x, 2.1*x+4.1*y=2761 (not 1010 due to that this is multiplied by 2.1 and 4.1, therefore representing the total amount of megabytes) In addition, there are 1010 total downloads, and it's either 2.1 MB or 4.1 MB, so x+y=1010.

We have 
2.1x+4.1y=2761
x+y=1010

Multiplying the second equation by -2.1 and adding it to the first equation, we get 2y=2761-1010*2.1=640 and by dividing both sides by 2 we get y=320 downloads of the high quality version


If there are 62 values in a data set, how many classes should be created for a frequency histogram?

Answers

your answer would be 6

The ratio of boy to girls in a class is 3 : 2. There are 15 boys in the class. How many total boys and girls are in the class?

Answers

There should be 15 boys and 10 girls in the class, so there is 25 students in the class total.
if there are 15 boys then there are 10 girls so there are 25 boys and girls in the class

The table shows the heights in inches of trees after they have been planted. Determine the equation which relates x and y.

Height In Pot, x | Height Without Pot, y
30 | 18
36 | 24
42 | 30
48 | 36


A. y = x - 6
B. y = x - 10
C. y = x - 12
D. y = x + 6

Answers

To get the that relates x and y, we choose two points on the table and use the equation of a straight line as follows:

Recall that the equation of a staight line is obtained from the formula
[tex] \frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1} [/tex]

Using the points (30, 18) and (36, 24), we have
[tex]\frac{y-18}{x-30} = \frac{24-18}{36-30}= \frac{6}{6} =1 \\ \\ \Rightarrow y-18=x-30 \\ \\ \Rightarrow y=x-30+18 \\ \\ \Rightarrow y=x-12[/tex]

Suppose that a box contains one fair coin and one coin with a head on each side. suppose that a coin is selected at random and that when it is tossed three times, a head is obtained three times. determine the probability that the coin is the fair coin.

Answers

there is a 50% chance it is the fair coin

The trinomial x2 – 3x – 4 is represented by the model. What are the factors of the trinomial?

Answers

x^2 – 3x – 4 = (x - 4)(x +1 )
cause
(x - 4)(x +1 ) = x^2 - 4x + x - 4 = x^2 - 3x - 4

answer
 (x - 4)(x +1 ) are factors of x^2 – 3x – 4

Answer:

[tex](x+1)[/tex] and [tex](x-4)[/tex].

Step-by-step explanation:

We have been a trinomial [tex]x^2-3x-4[/tex]. We are asked to find the factors of our given trinomial.

We will use split the middle term to solve our given problem. We need to two number whose sum is [tex]-3[/tex] and whose product is [tex]-4[/tex]. We know such two numbers are [tex]-4\text{ and }1[/tex].

Split the middle term:

[tex]x^2-4x+x-4[/tex]

Make two groups:

[tex](x^2-4x)+(x-4)[/tex]

Factor out GCF of each group:

[tex]x(x-4)+1(x-4)[/tex]

[tex](x-4)(x+1)[/tex]

Therefore, factors of our given trinomial are [tex](x+1)[/tex] and [tex](x-4)[/tex].

What is the value of the expression 5x+2y y-x2 when x=2 and y =3

Answers

The answer to that question is 44 hope this helps :-)

How many solutions are there in the equation below 8x+11=8x+8

Answers

That is a no solution set, you have been bamboozled!
Other Questions
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