Answer:
An acid
Explanation:
According to the Arrhenius theory of acids and bases "an Arrhenius acid is a compound that increases the concentration of H+ ions that are present when added to water"
If the half life for the radioactive decay of zirconium 84 is 26 minutes and i start with a 175 gram sample, how much will be left over after 104 minutes? show work or explain your answer.
After 104 minutes, or 4 half-lives, of the radioactive isotope zirconium 84 with a half-life of 26 minutes, the remaining quantity from an initial 175-gram sample would be 10.9375 grams.
Explanation:The question concerns the calculation of the amount of a radioactive substance remaining after a certain period, based on its half-life. In this case, we are looking at zirconium 84, which has a half-life of 26 minutes. To calculate how much of the substance remains after 104 minutes, we need to determine how many half-lives have passed in that time frame. Since 104 minutes is 4 times 26 minutes, that's 4 half-lives.
The amount of substance remaining after each half-life is reduced by 50%. Therefore, after one half-life, we will have 50% of the initial amount, after two half-lives, 25%, and so on. Applying this knowledge:
After 1st half-life (26 minutes): 175g / 2 = 87.5gAfter 2nd half-life (52 minutes): 87.5g / 2 = 43.75gAfter 3rd half-life (78 minutes): 43.75g / 2 = 21.875gAfter 4th half-life (104 minutes): 21.875g / 2 = 10.9375 gramsSo after 104 minutes, there would be 10.9375 grams of zirconium 84 remaining.
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The ratio of chlorine to hydrogen chloride in the reaction
H2(g) + Cl2 (g) -> 2 HCl(g) is
Answer:
1:2.
Explanation:
For the balanced reaction:H₂(g) + Cl₂(g) → 2HCl(g),
1.0 mole of H₂(g) reacts with 1.0 mole of Cl₂(g) to produce 2.0 moles HCl(g),
∴ The ratio of chlorine (Cl₂(g)) to hydrogen chloride (HCl(g)) is 1:2.
The ratio of chlorine to hydrogen chloride in the balanced reaction H2(g) + Cl2 (g) -> 2 HCl(g) is 1:2. This ratio is derived from the coefficients in the balanced chemical equation.
Explanation:In the balanced reaction H2(g) + Cl2 (g) -> 2 HCl(g), the ratio of chlorine (Cl2) to hydrogen chloride (HCl) is 1:2. This means that for every 1 mole of chlorine gas, 2 moles of hydrogen chloride are produced. The ratio does not represent the actual amount of substances, but rather the relative amounts of reactants and products based on their coefficients in the balanced equation.
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Which of the following is not equal to 0.1 centimeters?
0.000001 kilometers (km)
0.001 meters (m)
10 millimeters (mm)
1000 micrometers (µm)
Answer:
c) 10 millimeters (mm)
Explanation:
The unit conversions are as follows:
1 cm = 10 mm (millimeter)
1 cm = 0.01 m (meter)
1 cm = 0.00001 km (kilometer)
1 cm = 10000 μm (micrometer)
Based on the above conversions:
[tex]0.1 cm = \frac{10 mm*0.1 cm}{1 cm} = 0.1 mm[/tex]
[tex]0.1 cm = \frac{0.01 m*0.1 cm}{1 cm} = 0.001 m[/tex]
[tex]0.1 cm = \frac{0.00001 km * 0.1 cm}{1 cm} = 0.000001 km[/tex]
[tex]0.1 cm = \frac{10000 um*0.1cm}{1 cm} =1000 um[/tex]
Therefore, 0.1 cm = 10 mm is incorrect instead it is 0.1 mm
Answer:
Explanation:
the Americans maintained their control of Bunker Hill.
the British army sustained heavy casualties.
the Americans forced British soldiers to retreat to Boston.
the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because
the Americans maintained their control of Bunker Hill.
the British army sustained heavy casualties.
the Americans forced British soldiers to retreat to Boston.
the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because
A sample of argon has a volume of 6.0 cm 3 and the pressure is 0.87 atm. If the final temperature is 35 degrees celsius, the final volume is 10 cm 3 and the final pressure is 0.52 atm, what was the initial temperature of the argon
Answer:
= 36.185 °C
Explanation:
Using the combined gas law;
P1V1/T1 = P2V2/T2
In this case;
P1 = 0.87 atm
V1 = 6.0 cm³
T1 = ?
P2 = 0.52 atm
V2 = 10 cm³
T2 = 35 °C + 273 = 308 K
Therefore;
T1 = P1V1T2/P2V2
= ( 0.87 × 6.0 × 308)/( 0.52 ×10)
= 309.185 K
Therefore; Initial temperature = 309.185 K - 273 = 36.185 °C
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution
Answer:
16 Molarity
Step-by-step:
M= mols/L
M= 8mols/.5L
M= 16 Molarity
Answer:
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
Moles of NaOH = 8 moles
Volume of the solution = 0.5 L
[tex]Molarity=\frac{8 mol}{0.5 L}=16.0 M[/tex]
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
How many oxygen atoms are there in the product: 6Ca+4PO4→2Ca3(PO4)2? A. 16 B. 2 C. 4 D. 8
Answer:
The correct answer is option A.
Explanation:
[tex]6Ca+4PO_4\rightarrow 2Ca_3(PO_4)_2[/tex]
Number of molecules of [tex]Ca_3(PO_4)_2[/tex] =2
In 1 molecule [tex]Ca_3(PO_4)_2[/tex] , there are 8 oxygen atoms:
[tex]4\times 2 = 8 [/tex]oxygen atoms.
Then 2 molecules of [tex]Ca_3(PO_4)_2[/tex] :
[tex]2\times 8 = 16[/tex] oxygen atoms.
Hence, the correct answer is option A.
There are 16 oxygen atoms in the product of the reaction 6Ca + 4PO₄ rightarrow 2Ca₃(PO₄)₂, because each molecule of the product contains 8 oxygen atoms and the reaction produces two molecules.So,option A is correct.
The number of oxygen atoms in the product of the reaction 6Ca + 4PO₄ rightarrow 2Ca₃(PO₄)₂, we need to look at the chemical formula of the product, calcium phosphate, which is Ca3(PO4)2. This formula indicates that each molecule has two phosphate (PO₄) groups. Therefore, in total, there are 8 oxygen atoms within one formula unit of the product (4 x 2 = 8).
Since the balanced chemical equation shows the formation of two formula units of calcium phosphate, we need to multiply the number of oxygen atoms in one unit by 2 to get the total number of oxygen atoms in the product. That would be 8 oxygen atoms per unit x 2 units = 16 oxygen atoms in total in the products.
Thus, the correct answer to the question is A. 16 oxygen atoms.
Determine the original amount of Ba-142 after 1.25 hours if 9.25 mg remains. The half-life of Ba-142 is 10.6 minutes.
Answer:
1246 mg = 1.246 g.
Explanation:
The decay of radioactive elements obeys first-order kinetics.For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).Where, k is the rate constant of the reaction.
t1/2 is the half-life time of the reaction (t1/2 = 10.6 minutes).
∴ k = ln2/(t1/2) = 0.693/10.6 = 6.54 x 10⁻² min⁻¹.
For first-order reaction: kt = lna/(a-x).
where, k is the rate constant of the reaction (k = 6.54 x 10⁻² min⁻¹.).
t is the time of the reaction (t = 1.25 hr x 60 = 75.0 min).
a is the initial concentration (original amount) (a = ??? mg).
(a-x) is the remaining concentration (a-x = 9.25 mg).
∴ kt = lna/(a-x)
(6.54 x 10⁻² min⁻¹)(75.0 min) = ln a/(9.25 mg)
4.903 = ln a/(9.25 mg)
Taking e for the both sides:
134.7 = a/(9.25 mg)
∴ a = (134.7)(9.25 mg) = 1246 mg = 1.246 g.
Blood is a type of connective tissue. All of these make up blood tissue, except:
A) platelets
B) red blood cells
C) white blood cells
D) smooth muscle cells
Answer: Smooth Muscle Cells
Answer:
The answer is D
Explanation:
Calculate the density if the Mass = 25.69 g and the Volume = 10.5 g/mL
Answer:
d=2.44 g/ml
Explanation:
d=m/v
d=25.69g/10.5ml
d=2.44 g/ml
Final answer:
The density is calculated by dividing the mass of a substance by its volume. For the given mass of 25.69 g and volume of 10.5 cm³, the density is 2.45 g/cm³.
Explanation:
The question is asking to calculate the density of a substance when given the mass and the volume. To calculate density, the formula density = mass/volume is used.
It seems there is a typo in the given volume units (g/mL instead of cm³ or mL), I'll correct that and assume the volume is given in cm³ or mL, as density is typically expressed in g/cm³ or g/mL, and these units are equivalent.
For example, if we have a mass of 27.8 g and a volume of 25.3 cm³, the density would be calculated as 27.8 g ÷ 25.3 cm³ = 1.10 g/cm³. Following this method and using the student's values:
Mass = 25.69 g
Volume = 10.5 cm³
The calculated density would then be 25.69 g ÷ 10.5 cm³ = 2.45 g/cm³. This final answer is rounded to the second decimal place to match the precision of the given volume.
How many moles of chlorine are in 300 liters of chlorine
Answer:
13.39 mol ≅ 13.4 mol.
Explanation:
It is known that 1.0 mole of any gas occupies 22.4 L at STP conditions.Using cross multiplication:
1.0 mole of Cl₂ occupies → 22.4 L.
??? mole of Cl₂ occupies → 300.0 L.
∴ The no. of moles of Cl₂ are in 300 liters = (1.0 mol)(300.0 L)/(22.4 L) = 13.39 mol ≅ 13.4 mol.
Balance the following reaction. If a coefficient of "1" is required, choose "blank" for that box. C4H8 + Br2 → C4H8Br2
Please help fast
Answer:
C₄H₈ + Br₂ → C₄H₈Br₂
Explanation:
To balance a chemical equation, you need to ensure that the number of each element in the reactant side, matches the number of each element on the product side.
Reactants Product
C₄H₈ + Br₂ → C₄H₈Br₂
C = 4 C= 4
H = 8 H= 8
Br = 2 Br = 2
Since they match up on both sides, the chemical equation is balanced, so we keep it as is.
Answer:
blank for all
Explanation:
For Part 1, describe the changes in the colors of the well, if any, as you go from well 1 to well 9—that is, as you go from the well with the least copper(II) nitrate to the well with the most copper(II) nitrate. Which wells had the most distinct precipitate?
For Part 2, describe the changes in the colors of the well, if any, as you go from well 1 to well 9—that is, as you go from the well with the least iron(II) sulfate to the well with the most iron(II) sulfate. Which wells had the most distinct precipitate?
For Part 3, describe the changes in the colors of the well, if any, as you go from well 1 to well 9—that is, as you go from the well with the least iron(III) nitrate to the well with the most iron(III) nitrate. Which wells had the most distinct precipitate?
Answer:
Nitrate is a polyatomic ion with the molecular formula NO⁻₃ and a molecular mass of 62.0049 u. Organic compounds that contain the nitrate ester as a functional group are also called nitrates.
The color of the precipitate intensifies on moving from well 1 to well 9, as there has been an increased concentration of reactant and thereby the product.
The reaction of part 1 has been the reaction of copper nitrate with NaOH resulting in the formation of a precipitate of copper hydroxide. The precipitate has a blue color.Thus, for the copper hydroxide moving from well 1 to well 9, the blue color intensifies.
The reaction of part 2 has been the formation of iron hydroxide with the reaction of iron sulfate with NaOH. The color of the precipitate has been dark green.Thus, for the iron hydroxide moving from well 1 to well 9, the blue color intensifies.
The reaction for part 3 has been the formation of ferric hydroxide, with the reaction of Iron (III) nitrate with NaOH. The color of the precipitate has been red-orange.Thus, for the ferric hydroxide moving from well 1 to well 9, the red-orange color intensifies.
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when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced
Answer:
16.02 g
Explanation:
the balanced equation for the decomposition of CuCO₃ is as follows
CuCO₃ --> CuO + CO₂
molar ratio of CuCO₃ to CO₂ is 1:1
number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol
according to the molar ratio
1 mol of CuCO₃ decomposes to form 1 mol of CO₂
therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂
number of CO₂ moles produced - 0.364 mol
therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g
16.02 g of CO₂ produced
If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral
Answer:
The solution is basic.
Explanation:
We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):
If no. of millimoles of acid > that of base; the solution is acidic.If no. of millimoles of acid = that of base; the solution is neutral.If no. of millimoles of acid < that of base; the solution is basic.We need to calculate the no. of millimoles of acid and base:no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.
no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.
∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).
So, the solution is: basic.
which of the following is not a possible energy conversion for electricity?
a. mechanical
b. chemical
c. biological
d. thermal
please help me
A is the correct answer
Electrical energy may be produced from chemical energy. Heat energy may be produced from thermal energy. Electrical energy, potential energy, etc. can be created from mechanical energy. Mechanical energy is not a possible energy conversion for electricity
What is mechanical energy ?Potential energy plus kinetic energy are combined to form mechanical energy. According to the concept of mechanical energy conservation, mechanical energy remains constant in an isolated system when only conservative forces are acting on it.
If an object is moving or in a certain position in relation to the surface, it has mechanical energy.
A box placed vertically above the ground, for instance, will only contain potential energy. A moving object has mechanical energy, often known as kinetic energy, because of its motion.
Thus, option A is correct.
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0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution
Answer:
= 10 M or 10 moles/liter
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
In this case;
The number of moles = 0.5 moles
Volume = 0.05 liters
Therefore;
Molarity = 0.5 moles/0.05 liters
= 10 M or 10 moles/liter
Thus the molarity is 10 M or 10 moles/liter
Final answer:
To calculate the molarity, divide the number of moles of sodium chloride (0.5 moles) by the volume of the solution in liters (0.05 liters), resulting in a molarity of 10 M for the NaCl solution.
Explanation:
The question relates to the concept of molarity, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution. The student's question involves calculating the molarity given a certain amount of solute (sodium chloride, NaCl) and the volume of the resulting solution. To calculate molarity, you would divide the number of moles by the volume in liters. In the case of the student's question, if 0.5 moles of NaCl are dissolved to make 0.05 liters of solution, the calculation would be:
Molarity = moles of solute / liters of solution
Molarity = 0.5 moles / 0.05 liters
Molarity = 10 M (molar)
This result indicates a 10 M NaCl solution, which signifies a highly concentrated solution.
The diagram below shows two natural processes. Which of these statements is correct about Process 1 and Process 2?
A. Both processes create mid-ocean ridges
B. Both processes create high mountain ranges.
C. Process 1 creates mid-ocean ridges and Process 2 creates high mountains.
D.Process 2 creates mid-ocean ridges and Process 1 creates high mountains.
Answer:
C. Process 1 creates mid-ocean ridges and Process 2 creates high mountains.
Explanation:
The diagram shows two natural processes, process 1 creates mid-ocean ridges and Process 2 creates high mountains.
What is an ocean ridge?Ocean ridges are present in the base of oceans. They are of nearly 5 km to 2.6 km depth and thousands km wide.
The formation of an ocean ridge occurs when divergent boundaries plates separate and molten lava come upside.
Thus, the correct option is C. Process 1 creates mid-ocean ridges and Process 2 creates high mountains.
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What happens to the matter (bodies) of organisms after they die?
Answer:
they start to decompose
Explanation:
the easiest way to wxplain this is that all organic matter decomposees and turns into nutrients for other organisms, its a cycle. but after an organism dies then it starts to decompose and rot.
Answer:
they begin to rot
Explanation:
Which climate is most likely found in a high pressure belt
The climate most likely found in a high-pressure belt is a dry climate. An example of a high-pressure belt with a dry climate is the subtropical high-pressure belt.
Explanation:The climate most likely found in a high-pressure belt is a dry climate.
High-pressure systems are associated with sinking air, which inhibits the formation of clouds and precipitation. These areas tend to have clear skies and little moisture, resulting in dry conditions.
An example of a high-pressure belt with a dry climate is the subtropical high-pressure belt found around 30 degrees latitude in both the Northern and Southern Hemispheres, such as the Sahara Desert or the Mojave Desert.
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What is the relationship between wavelength and frequency
Answer:
Explanation:
are inversely proportional- the longer the wavelength the shorter the frequency.
Answer:
Inverse
Explanation:
Before the reaction occurs, the concentration of A is 0.071M. If the concentration of A at equilibrium is 0.03195M, what is the equilibrium constant? A(g) = 2B(g) + C(g)
Answer:
Assume that the initial concentration of both B and C are zero.
Kc = 7.5 × 10⁻³.
Explanation:
What's the expression for the equilibrium constant of this reversible reaction? Note that the steps here apply only to equilibriums where all species are either gaseous (g) or in an aqueous solution (aq). Solids and liquids (water in particular) barely influence the equilibrium; in many cases they should not appear in the expression for the equilibrium constant.
Raise the concentration of each product to their coefficient's power.
The coefficient in front of B is 2. Raise the concentration of B to the second power, which will give [tex][\text{B}]^{2}[/tex]. The coefficient in front of C is 1. Raise the concentration of C to the first power, which is the same as [tex][\text{C}][/tex].The product of these terms will be the numerator in the expression of the equilibrium constant. For this reaction, the numerator shall be [tex][\text{B}]^{2} \cdot[\text{C}][/tex].
Repeat these steps for the reactants:
The coefficient in front of A is 1. Raise the concentration of A to the first power, which is the same as [tex][\text{A}][/tex].If there are more than one reactants, multiple each of those terms. The product shall be the denominator of the expression for the equilibrium constant. For this reaction, the denominator shall be [tex][\text{A}][/tex].
Hence the equilibrium constant:
[tex]\displaystyle K_c = \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}[/tex],
where [tex][\text{A}][/tex], [tex][\text{B}][/tex], and [tex][\text{C}][/tex] are concentrations when the reaction is at equilibrium.
Construct a RICE table to find the equilibrium concentration of each species. R stands for reaction, I for initial conditions, C for change in concentration, and E for equilibrium conditions. Assume that only A is initially present in the system. Let the decrease in the concentration of [tex]\text{A}[/tex] be [tex]x\;\text{M}[/tex].
[tex]\begin{array}{c|ccccc}\text{R}&\text{A}\;(g) &\rightleftharpoons &2\;\text{B}\;(g)& +& \text{C}\;(g)\\ \text{I}& 0.071 \;\text{M} & & 0\;\text{M} && 0 \;\text{M} \\ \text{C} &-x \;\text{M}&&+2x\;\text{M} & & +x\;\text{M}\\\text{E}&0.071 - x\;\text{M} && 2x\;\text{M} & &x\;\text{M} \end{array}[/tex].
The coefficient in front of B is twice that in front of A. In other words, for each unit of A consumed, two units of B are produced. Assume that volume stays the same. The decrease in the concentration of [tex]\text{A}\;(g)[/tex] is [tex]x\;\text{M}[/tex]. Accordingly, the increase in the concentration of [tex]\text{B}\;(g)[/tex] shall be [tex]2x\;\text{M}[/tex].
The question states that the equilibrium concentration of [tex]A\;(g)[/tex] is [tex]0.03195\;\text{M}[/tex].
[tex]0.071 - x = 0.03195[/tex],
[tex]x = 0.03905[/tex].
At equilibrium:
[tex][\text{A}\;(g)] = 0.03195\;\text{M}[/tex] according to the question;[tex][\text{B}\;(g)] = 2 x \;\text{M}= 0.0781\;\text{M}[/tex] as in the RICE table;[tex][\text{C}\;(g)] = x = 0.03905\;\text{M}[/tex] as in the RICE table.Hence the equilibrium constant.
[tex]\displaystyle \begin{aligned}K_c &= \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}\\&=\frac{{0.0781}^{2} \times 0.03905}{0.03195}\\&=7.5\times 10^{3}\;\text{M}\end{aligned}[/tex].
If the concentration of A at equilibrium is 0.03195M,the equilibrium constant is Kc ≈ 0.0072 (option a).
To begin solving for the equilibrium constant (Kc), we first need to determine the changes in concentrations for each species.
Step-by-Step Solution:
1. Initial and equilibrium concentrations:
Initial concentration of A ([A]i) = 0.071 MEquilibrium concentration of A ([A]eq) = 0.03195 M
2. Change in concentration for A:
Change in [A] = 0.071 M - 0.03195 M = 0.03905 M
Since the reaction stoichiometry is 1A → 2B + 1C, the change in concentration will also affect B and C:
Change in [B] = 2 × 0.03905 M = 0.0781 MChange in [C] = 0.03905 M
3. Equilibrium concentrations:
Equilibrium concentration of A, [A]eq = 0.03195 MEquilibrium concentration of B, [B]eq = 0.0781 MEquilibrium concentration of C, [C]eq = 0.03905 M
4. Equilibrium constant expression:
The equilibrium constant expression for the reaction A(g) = 2B(g) + C(g) is:
Kc = [B]² [C] / [A]
5. Substituting the equilibrium concentrations:
Kc = (0.0781)² × 0.03905 / 0.03195
6. Calculating Kc:
Kc ≈ 0.0072
Therefore, the equilibrium constant for the reaction is approximately 0.0072.
Complete Question - Before the reaction occurs, the concentration of A is 0.071 M. If the concentration of A at equilibrium is 0.03195 M, what is the equilibrium constant? A(g) = 2B(g) + C(g) Select the correct answer below:
a. Kc - 0.0072
b. Kc - 0.095
c. Kc - 14
d. Kc - 130