What type of microscope is used to show the fine detail of cell organelles, as well as the spindle fibers and chromosomes as seen during anaphase? A) compound light microscope B) binocular stereomicroscope C) scanning electron microscope D) transmission electron microscope

The density of some unknown solid whose weight is 84.0 grams and volume is 30.0 cm3 is 2.8 g/mL.

Density may be defined as a type of physical property that significantly deals with the description of how much space an object or substance takes up with respect to the amount of matter in that object or substance.

In a more simple sense, it is characterized as the measurement of quantity or mass per unit of volume in a particular substance.

According to the question,

The mass of the unknown solid =  84.0 grams.

The volume of the unknown solid = 30.0 cm3.

Now, the formula for calculating the density is as follows:

                     = 84.0 g / 30.0 mL (1 cubic centimeter = 1 mL).

                     = 2.8 g/mL.

Therefore, the density of some unknown solid whose weight is 84.0 grams and volume is 30.0 cm3 is 2.8 g/mL.

To learn more about Density, refer to the link:

https://brainly.com/question/1354972

#SPJ5

Final answer:

The atomic mass closest to carbon without calculations is 12.00 amu since carbon's average atomic mass is listed as 12.011 amu on the periodic table, and it mostly consists of carbon-12.

Explanation:

The atomic mass of an element like carbon is the weighted average of the masses of its naturally occurring isotopes. Carbon is predominantly composed of carbon-12, which has an atomic mass of exactly 12 amu (atomic mass units), as this isotope makes up about 98.90% of naturally occurring carbon. Because of this, the average atomic mass of carbon is close to 12 amu, but slightly higher due to the presence of the carbon-13 isotope. The periodic table lists carbon's atomic mass as 12.011 amu, making 12.00 amu the mass closest to carbon's atomic mass without doing any calculations.

The net ionic equation for the precipitation of chromium(III) hydroxide is Cr³⁺ + 3OH⁻ → Cr(OH)₃(s). This is derived from the complete ionic equation by ignoring the spectator ions, which are sodium (Na⁺) and sulfate (SO₄²⁻) ions.

To write the net ionic equation for the precipitation of chromium(III) hydroxide from the aqueous solution, we first need to understand the balanced chemical equation for this reaction.

The balanced equation for the reaction of chromium sulfate (Cr₂(SO₄)₃) with Sodium Hydroxide (NaOH) resulting in the precipitation of chromium hydroxide (Cr(OH)₃) and Sodium Sulfate (Na₂SO₄) is:

Cr₂(SO₄)₃(aq) + 6NaOH(aq) → 2Cr(OH)₃(s) + 3Na₂SO₄(aq)

For net ionic equations, we only include the species involved in the reaction and leave out the spectator ions. Sodium (Na⁺) and sulfate (SO₄²⁻) are spectator ions in this case. They don't participate in the reaction or change during the process.

Consequently, the net ionic equation for the precipitation of chromium(III) hydroxide is represented as:

Cr³⁺ + 3OH⁻ → Cr(OH)₃(s).

This equation shows specifically the formation of the precipitate, chromium(III) hydroxide, in the reaction.

https://brainly.com/question/35304253

#SPJ12

Net ionic equation: [tex]\(Cr^{3+}(aq) + 3OH^-(aq) \rightarrow Cr(OH)_3(s)\)[/tex] represents chromium(III) ions reacting with hydroxide ions to precipitate chromium(III) hydroxide from solution.

The net ionic equation for the precipitation of chromium(III) hydroxide from aqueous solution can be represented as follows:

[tex]\[Cr^{3+}(aq) + 3OH^-(aq) \rightarrow Cr(OH)_3(s)\][/tex]

In this equation, chromium(III) ions [tex](\(Cr^{3+}\))[/tex] from the aqueous solution react with hydroxide ions [tex](\(OH^-\))[/tex] to form solid chromium(III) hydroxide [tex](\(Cr(OH)_3\))[/tex]. This equation represents only the ions involved in the precipitation reaction, excluding spectator ions.

Answer: I think it’s: Neutral, with The number of protons equaling to the number of electrons

Explanation:

The density of a metal given a mass of 5.23 g and a volume of 0.27 mL is calculated using the formula density = mass / volume, resulting in a density of 19.37 g/mL, with the final answer limited to four significant figures.

To identify the density of a metal given its mass and volume, you can use the formula for density, which is density = mass / volume. Given a 5.23 g sample of metal that occupies 0.27 mL, you first ensure the units are correct for density in g/mL. You then simply divide the mass by the volume.

So, density = 5.23 g / 0.27 mL = 19.37 g/mL.

This calculation gives us the density of the metal. Remember, when calculating density, it's important to ensure that your units are consistent, and for density, g/mL is a common unit. Additionally, when expressing your final answer, it matches the number of significant figures from the given data, in this case, being limited to four significant figures due to the precision of the volume measurement.

The element displayed by a topographic map is landforms. A topographic map accurately depicts the natural and artificial characteristics of the land, such as rivers, lakes, roads, trains, power lines, heights, and contours. Thus option B is correct

A topographic map is a precise representation of the ground's natural and man-made features, including rivers, lakes, roads, railways, power lines, altitudes, and contours.

The topographic map depicts the three-dimensional terrain of the Earth in two dimensions.

Topographic maps display boundary lines of all kinds, including international, provincial, and administrative ones, as well as contours, elevation, forest cover, marshlands, pipelines, and power transmission lines.

Therefore, Landforms is one element a topographic map shows.

Learn more about Topographic here:

https://brainly.com/question/1325156

# SPJ2

Answer:

Amount of ethyl butyrate formed = 11.3 g

Explanation:

The reaction between butanoic acid (C3H7COOH) and excess ethanol (C2H5OH) is:

[tex]C3H7COOH + C2H5OH \rightarrow C3H7COOC2H5 + H2O[/tex]

Since ethanol is the excess reagent, the formation of the product i.e. ethyl butyrate is influenced by the amount of butanoic acid present

Based on the reaction stoichiometry:

1 mole of butanoic acid produces 1 mole of ethyl butyrate

Mass of butanoic acid = 8.50 g

Molar mass of butanoic acid = 88 g/mol

[tex]Moles\ of \ butanoic\  acid = \frac{Mass}{Molar\ mass} =\frac{8.50g}{88g/mol}=0.097 moles[/tex]

Moles of ethyl butyrate = 0.097

Molar mass of ethyl butyrate= 116 g/mol

[tex]Mass\ of\ ethyl\  butyrate= 0.097*116 = 11.3 g[/tex]

Answer:

6 electrons are in the third level if the atom.

The first step to answering this item, is to balance first the chemical reaction. This is shown below.

      Mg(s) + 2HCl (aq) --> MgCl₂(aq) + H₂(g)

HCl is multiplied by 2 to equalize the number of the hydrogen and chlorine.

The molar masses of magnesium and hydrogen gas are 24.3 g and 2 g, respectively. Using dimensional analysis and conversions, mass of hydrogen is calculated through the equation,

 Mass of H₂ =    (0.373 g Mg)(1 mol Mg/24.3 g Mg)(1 mol H₂/ 1 mol Mg)(2 g H₂/1 mol H₂)

             Mass of hydrogen = 0.031 g of hydrogen

To reach a lethal dose of caffeine at a concentration of 1.87 mg/oz, one would need to consume approximately 446 cans of soda containing 12 oz each.

If the caffeine concentration in a certain brand of soda is 1.87 mg/oz, and considering that there are 12 oz in a can, then one can contains 1.87 mg/oz × 12 oz = 22.44 mg of caffeine. To reach a lethal dose of 10.0 grams (10,000 mg) of caffeine, you would need to drink 10,000 mg ÷ 22.44 mg/can ≈ 445.8 cans of soda. Therefore, drinking approximately 446 cans of soda could be lethal, based on this concentration.

Answer: The balanced chemical equation is written below.

Explanation:

Balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side will be equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.

The chemical equation for the reaction of lead (II) nitrate and potassium phosphate follows:

[tex]3Pb(NO_3)_2(aq.)+2K_3PO_4(aq.)\rightarrow Pb_3(PO_4)_2(s)+6KNO_3(aq.)[/tex]

By Stoichiometry of the reaction:

3 moles of aqueous lead (II) nitrate reacts with 2 moles of aqueous solution of potassium phosphate to produce 1 mole of solid lead (II) phosphate and 6 moles of aqueous solution of potassium nitrate.

Hence, the balanced chemical equation is written above.

The answer is: mass of the snack mix can you consume and still be within the FDA limit is 491 grams.

ω(Na) = m(Na) ÷ m(salt).

ω(Na) = 39.33 g ÷ 100 g.

ω(Na) = 0.3933; mass percentage of sodium in salt.

m(salt) = 2.4 g ÷ 0.3933.

m(salt) = 6.10 g; mass of salt recommended for consumation.

Make proportion: 1.24 g : 100 g = 6.10 g ÷ m(mix).

m(mix) = 491.93 g; mass of the snack mix.

The two Lewis structure for a compound with the formula [tex]\rm C_4H_{10}[/tex] are shown below in the attached image.

In a Lewis structure, an element's chemical symbol shows its nucleus and inner electrons, while dots or lines represent valence electrons. Valence electrons are the atom's outermost electrons and are important in chemical bonding.

Therefore, the two structure of [tex]\rm C_4H_{10}[/tex] are isomers of each other (refer to the attached image).

Learn more about Lewis structure here:

https://brainly.com/question/9908915

#SPJ6

Because they haare not made up of protons nuetrons or electrons

Answer:

2,2,3-trimethyl-butane

Explanation:

Hello,

On the attached picture, you will find one isomer with chemical formula C₇H₁₆ which is 2,2,3-trimethyl-butane as it has the required three methyl brances on the parent chain, therefore, they must be arranged in the inner carbons otherwise, they will be considered as part of the parent chain.

Best regards.

Final answer:

The structure of the 1 isomer of C7H16 with three methyl branches on the parent chain can be represented as 2,2,3-trimethylbutane, which has a butane backbone with two methyl groups on the second carbon and one on the third.

Explanation:

The student asked to draw the structure of the 1 isomer of C7H16 that contains 3 methyl branches on the parent chain. For heptane (C7H16), one possible isomer with three methyl branches on the parent chain could be 2,2,3-trimethylbutane. In this structure, we have a four-carbon (butane) chain as the parent, with methyl groups attached to the second and third carbons (two on the second and one on the third).

Here's how you could write it out in steps:

Answer:

The degree of rotation of racemic mixture will equal 0° 

Explanation:

Hello,

(-) isomer is in other words the Enantiomer of (+) isomer and as long as the statement indicates that (+)-isomer optical rotation is + 13.5°, the optical rotation of (-)-isomer will be the same value and degree but with the inverse sign which is -13.5°.

In such a way, the degree of rotation of the taken into account racemic mixture will equal 0° 

This is in this way due to the fact that the racemic mixture has equal amount of both enantiomers.

Best regards.

To determine the number of grams of sodium sulfate that can react with 20.8 g of barium chloride, we use the balanced chemical equation and molar masses of the compounds. The number of moles of Na2SO4 that can react with 20.8 g of BaCl2 is 15.44 g Na2SO4.

To determine the number of grams of sodium sulfate that can react with 20.8 g of barium chloride, we need to use the balanced chemical equation and the molar masses of the compounds involved.

The balanced chemical equation for the reaction is:

BaCl2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2NaCl (aq)

The molar mass of BaCl2 is 208.23 g/mol and the molar mass of Na2SO4 is 142.04 g/mol.

From the balanced equation, we can see that the ratio of BaCl2 to Na2SO4 is 1:1. Therefore, the number of moles of Na2SO4 that can react with 20.8 g of BaCl2 is:

20.8 g BaCl2 × (1 mol BaCl2 / 208.23 g BaCl2) × (1 mol Na2SO4 / 1 mol BaCl2) × (142.04 g Na2SO4 / 1 mol Na2SO4) = 15.44 g Na2SO4.

https://brainly.com/question/33355759

#SPJ11

To take the percent by mass of this element, we use the formula:

% mass = (mass of element / mass of ore) * 100%

% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*

% mass = 7.20 x 10^-3 %

Answer: The mass percent of element in the ore is 0.0072 %

Explanation:

To calculate the mass percentage of element in ore, we use the equation:

[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of ore}}\times 100[/tex]

Mass of element = 47.5 g

Mass of ore = 660 kg = 660000 g    (Conversion factor:  1 kg = 1000 g)

Putting values in above equation, we get:

[tex]\text{Mass percent of element}=\frac{47.5g}{660000g}\times 100=0.0072\%[/tex]

Hence, the mass percent of element in the ore is 0.0072 %