What percentage of the participants lie within one standard deviation unit of the mean (i.e., on both sides of the mean) in a normal distribution?

Answer:  The required percentage is 40%.

Step-by-step explanation:  We are given to find the percentage of the first 20 natural numbers that are prime.

We know that

first 20 natural numbers are 1, 2, 3, 4,  .  .  .  , 19, 20.

And, the prime numbers among them are 2, 3, 5, 7, 11, 13, 17 and 19.

So, if S be the sample space for the experiment and A be the event of selecting a prime number.

Then, we have

n(S) = 20  and  n(A) = 8.

Therefore, the probability of event A is given by

[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{8}{20}=\dfrac{2}{5}\times100\%=40\%.[/tex]

Thus, the required percentage is 40%.  

Approximately it takes 6.85 minutes to complete 1 task.

Given that, a robot can complete 7 tasks in 4/5 hour.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

It takes 4/5 hour (48 minutes) to complete 7 tasks.

Now, 48/7 = 6.85 minutes

So, it takes 6.85 minutes to complete 1 task.

Therefore, approximately it takes 6.85 minutes to complete 1 task.

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"Your question is incomplete, probably the complete question/missing part is:"

A robot can complete 3 tasks in 4/5 hour. Each task takes the same amount of time.

How long does it take the robot to complete one​ task?

The distance covered by an airplane flying at 300mph for 7 hours is 2100 miles.

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Given that, an airplane flying at 300mph for 7 hours,

Speed = distance/time

Distance = speed×time

Distance covered in 7 hours = 300×7 = 2100

Hence, the distance covered by the airplane is 2100 miles.

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To find the cost of the washer and the dryer when the total cost is known along with the difference in their costs, we used a simple algebraic method of solving equations to determine that the dryer costs $650 and the washer costs $850.

The question involves solving a system of linear equations to find the cost of two items whose total and difference in cost are known. To find the cost of each appliance, let's denote the cost of the dryer as x dollars. According to the problem, the washer costs $200 more than the dryer, so the washer's cost would be x + $200. The total cost of both appliances is $1500.

We can set up the following system of equations:

Solving the equations, we combine like terms:

Now we know the dryer costs $650 and the washer costs $650 + $200 = $850.

By breaking down each number into its place value parts, performing six separate multiplications, and then adding those products together, you can multiply a three-digit number by a two-digit number.

The multiplication of a three-digit number by a two-digit number can be accomplished via place value and partial products. To illustrate, consider multiplying 123 by 25. Begin by breaking down 123 into 100 + 20 + 3 and 25 into 20 + 5.

Next, multiply each part of the three-digit number by each part of the two-digit number, which gives us 100 * 20, 20 * 20, 3 * 20, 100 * 5, 20 * 5, and 3 * 5. When you add these six products together, you get: 2000 + 400 + 60 + 500 + 100 + 15 = 3075, which is the result of 123 * 25.

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Final answer:

There are 800 possible area codes and exchange numbers each, following the given digit restrictions. The total number of unique 10-digit phone numbers given these rules is 6,400,000,000, which is sufficient considering a population of about 400,000,000.

Explanation:

The question addresses how many different area codes and phone numbers are possible given certain digit restrictions for both the United States and Canada. For the area code, the first digit can be any from 2 to 9, which gives us 8 possibilities, and the second and third digits can be any from 0 to 9, which provides 10 possibilities each. Therefore, the number of different area codes is 8 × 10 × 10 = 800.

Applying the same rules to the exchange number, which also has three digits, we have another 800 possibilities. Considering there are 10,000 combinations for the last four digits (from 0000 to 9999), we can calculate the total number of unique 10-digit phone numbers by multiplying the possibilities for the area code, exchange number, and the last four digits: 800 × 800 × 10,000 = 6,400,000,000 possible phone numbers.

Since the combined population of the United States, Canada, and a few islands is about 400,000,000, this amount of possible phone numbers is more than sufficient to provide a unique phone number for every individual.

Divide 5 on each side. Then that would be the answer,f=-8

Saying a characteristic f is continuous whilst x=c is the same as announcing that the characteristic's two-side restrict at x=c exists and is identical to f(c).

Continuous variables are numeric variables that have a limitless quantity of values among any two values. A non-stop variable may be numeric or date/time. For example, the length of a part of the date and time a payment is acquired.

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Answer:

its d

Step-by-step explanation:

Answer with explanation:

Number of oak trees =54

Number of pine trees =27

→Abe would like to plant the trees in rows that all have the same number of trees and are made up of only one type of tree.

We, will take H CF that is highest common factor of 54 and 27.

54 = 2×3×3×3

27=3×3×3

→H CF(54,27)=3 × 3×3=27

So, greatest number of trees Abe can have in each row =27,and there will be maximum of 3 rows, 2 containing oak tree because [tex]\frac{54}{27}=2[/tex], and one containing pine tree because[tex] \frac{27}{27}=1[/tex].

The greatest number of trees in each row is 27.

The factors of a number are numbers that divide the original number into equal numbers. They are numbers that when they are used to divide another number, the result is an integer.

What is the greatest number of trees that can be in each row?

In order to determine the required value, we have to determine the common factors of 27 and 54.

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The required two consecutive even integers that add up to 218 are 108 and 110.

Integers are numbers that can be written without a fractional or decimal component, such as -3, -2, -1, 0, 1, 2, 3, and so on. They include the positive whole numbers (1, 2, 3, etc.), the negative whole numbers (-1, -2, -3, etc.), and zero.

To find the two consecutive even integers that add up to 218, we can use algebra.

Let's represent the first integer "x".

Since it is even, we know that it can be divided by 2 with no remainder.

Since it is also consecutive to the second integer, we can say that the second integer is "x + 2".

We can set up the equation:

x + (x + 2) = 218

Simplifying, we get:

2x + 2 = 218

2x = 216

x = 108

So the two consecutive even integers that add up to 218 are 108 and 110.

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Answer:

26/2

Step-by-step explanation:

i just know its right cause i got it right

Answer:

[tex]2d+35[/tex]

Step-by-step explanation:

Let d represents the number of dogs that will attend the event.

She wants to have 2 biscuits per dog plus an additional 35 dog biscuits.

So, the expression that represents the number of dog biscuits Nicole will need for the event is :

[tex]2d+35[/tex]

2d because 2 biscuits for each dog where 'd' is the number of dogs. And 35 is constant because she will be taking extra 35 with her.