What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is w = 1.75 m wide and h = 8.00 m below the top of the cliff?

Answers

Answer 1
1.37 m/s Assuming her initial velocity is totally horizontal and her vertical velocity is only affected by gravity, let's first calculate how much time she has until she reaches the ledge 8.00 m below her. d = 1/2AT^2 8.00m = 1/2 * 9.8 m/s^2 * T^2 Solve for T 8.00 m = 4.9 m/s^2 * T^2 Divide both sides by 4.9 m/s^2 1.632653061 s^2 = T^2 Take square root of both sides 1.277753 s = T So we now know that she has 1.277753 seconds in which to reach a horizontal distance of 1.75 m. So how fast does she need to be going? 1.75 m / 1.277753 s = 1.369592 m/s Since we only have 3 significant figures in our data, round the result to 3 figures giving 1.37 m/s
Answer 2

Final answer:

To avoid hitting the ledge when jumping from a cliff, calculate the time of flight using the height of the cliff and gravity, then use that time to find the minimum horizontal velocity needed to clear the ledge width.

Explanation:

Minimum Speed to Miss the Ledge

To find the minimum speed required for a person to miss the ledge when jumping from a cliff, one must analyze the motion in two dimensions: vertical and horizontal. The vertical distance (h) and the width of the ledge (w) are crucial to determine the time in the air and the minimum horizontal velocity needed.

The vertical motion is independent of the horizontal motion and can be analyzed using the formula for the time of flight under gravity which is t = [tex]\sqrt(2h/g)[/tex], where g is the acceleration due to gravity. Once the time of flight is calculated, we use this time to find the minimum horizontal velocity (vmin) necessary to travel the width of the ledge w by the formula vmin = w/t. This is the minimum speed the person needs just as they leave the edge of the cliff.

For a ledge 1.75m wide and cliff 8.00m high, first, calculate the time of flight with t = [tex]\sqrt((2*8.00m)/9.81m/s2)[/tex]. Then, use this time to calculate the horizontal velocity with v min = 1.75m / t.


Related Questions

Michael jordan's vertical leap is reported to be 47.2 inches. what is his takeoff speed? give your answer in meters per second

Answers

Michael Jordan's takeoff speed for his 47.2-inch vertical leap would be approximately 4.85 m/s, calculated using the kinematic equation for vertical motion.

To find Michael Jordan's takeoff speed, we can use the kinematic equation for vertical motion without air resistance: vf^2 = vi^2 + 2 * a * d, where vf is the final velocity (0 m/s at the peak of the jump), vi is the initial velocity (takeoff speed we want to find), a is the acceleration due to gravity (-9.81 m/s^2), and d is the vertical leap distance.

First, we convert the vertical leap from inches to meters: 47.2 inches = 1.2 meters (approximately).

Now, we can set vf to 0 m/s and solve for vi:

0 = vi^2 + 2 * (-9.81) * 1.2

vi^2 = 2 * 9.81 * 1.2

vi = sqrt(2 * 9.81 * 1.2)

vi ≈ 4.85 m/s (rounded to two decimal places)

Therefore, Michael Jordan's takeoff speed would be approximately 4.85 m/s.

If one of the satellites is at a distance of 20,000 km from you, what percent accuracy in the distance is required if we desire a 2-meter uncertainty

Answers

The percent accuracy is 10⁻⁵%. It is determined by the formula of percent accuracy.

Given information:

Distance of satellite = 20,000km

= 2 x 10⁷ m

Uncertainty = 2 meter

Uncertainty refers to a lack of exactness or precision in measurement, calculation, or prediction. It represents the degree of doubt or error associated with a particular value or result. Uncertainty is an essential concept in various fields, including science, engineering, statistics, and decision-making.

The formula to determine percent accuracy is:

[tex]\rm Percent \ accuracy= \frac{Uncertainty}{Measured d\ distance} \times 100[/tex]

Substituting the values in the formula:

[tex]\rm Percent \ accuracy = \frac{2}{2\times 10^7}\times 100 \\\rm Percent \ accuracy = \frac{1}{10^5} \\[/tex]

Simplifying:

Percent accuracy = 10⁻⁵%.

Therefore, the percent accuracy is 10⁻⁵%.

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If the total charge on a rod of length 0.4 m is 2.6 nc, what is the magnitude of the electric field at a location 3 cm from the midpoint of the rod?

Answers

Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m). 

The point then lies on the y-axes at d = 0.03 m. 

from symmetry, the field at that point will be ascending along the y-axes. 


A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point. 

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength. 


All in all, the infinitesimal field strength from the charge between x and x+dx is: 


dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2) 


Therefore, upon integration, 


E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2. 


This gives:


E = k lambda L / (d sqrt((L/2)^2 + d^2) ) 


But lambda L = Q, the total charge on the rod, so 


E = k Q / ( d * sqrt((L/2)^2 + d^2) )

Final answer:

To calculate the electric field magnitude at a distance from a charged rod, determine the charge per unit length and use the electric field formula.

Explanation:

Electric Field and Charged Rod:

To find the magnitude of the electric field at a distance from a charged rod, you can use the formula for the electric field of a long, charged rod. Given the total charge on the rod and its length, you can calculate the charge per unit length. Then, apply the formula to find the electric field at the specified location.

Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m).

The point then lies on the y-axes at d = 0.03 m.

from symmetry, the field at that point will be ascending along the y-axes.

A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point.

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength.

All in all, the infinitesimal field strength from the charge between x and x+dx is:

dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2)

Therefore, upon integration,

E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2.

This gives:

E = k lambda L / (d sqrt((L/2)^2 + d^2) )

But lambda L = Q, the total charge on the rod, so

E = k Q / ( d * sqrt((L/2)^2 + d^2) )

A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no appreciable air drag. (a) how tall, in meters, is the building? (b) how fast is the brick moving just before it reaches the ground? (c) sketch graphs of this falling brickâs acceleration, velocity, and vertical position as functions of time.

Answers

initial velocity = 0
time = 2.50 s
acceleration = gravity, 9.8 m/s^2

use the equations for linear motion.
s = ut + (1/2)at^2
v = u + at

A. displacement given u, a and t.
s = (0)(2.50) + (1/2)(9.8)(2.50)^2
s = 0 + 4.9(6.25)
s = 30.625 m
three significant figures..
s = 30.6 m

B. final velocity given u, a and t
v = 0 + 9.8(2.50)
v = 24.5 m/s

C. graphs
s vs. t
object starts at zero and displacement increases linearly to (2.5, 30.6) and stops. slope of line is average velocity, s/t
v vs. t
object starts at zero velocity and increases linearly to (2.5, 24.5) and stops. slope of line is acceleration, v/t.
a vs. t
acceleration is gravity, it's constant horizontal line at; y = 9.8. stops at (2.5,9.8)

Answer:

Part a)

y = 30.625 m

Part b)

v = 24.5 m/s

Explanation:

Part a)

As we know that brick will hit the floor after t = 2.50 s

so here we will have

[tex]y = v_i t + \frac{1}{2}at^2[/tex]

[tex]y = 0 + \frac{1}{2}(9.8)(2.50^2)[/tex]

[tex]y = 30.625 m[/tex]

Part b)

velocity of the brick just before it will strike the ground is given as

[tex]v_f = v_i + at[/tex]

[tex]v_f = 0 + (9.8)(2.5)[/tex]

[tex]v_f = 24.5 m/s[/tex]

Part c)

The MSDS for chloroform indicates that it is a clear liquid that has a pleasant smell and substantial vapor pressure. People should avoid inhaling its vapors, and it is sensitive to light.

Answers

True.

According to MSDS for Chloroform, it is a clear, colorless liquid. it does have a pleasant and sweet smell and taste sweet as well as having a "burning" taste. It has a vapor pressure of 21.1 kPa ( @ 20 degrees Celsius ). It is sensitive to light and should be stored in light-resistant containers and should not be inhaled.

Brainlest answer is always appreciated !

A football player carrying the ball runs straight ahead at the line of scrimmage and directly into a wall of defensive linemen. The ball carrier has an initial speed of 7.68 m/s and is stopped in a time interval of 0.202 s. Find the magnitude and direction of his average acceleration.

Answers

Final answer:

The magnitude of the average acceleration the football player experiences is 38.02 m/s², and the direction of the acceleration is backward, towards the line of scrimmage.

Explanation:

To calculate the magnitude and direction of the average acceleration experienced by the football player, we use the following kinematic equation:

a = (v_f - v_i) / t

Where:

v_f is the final velocityv_i is the initial velocityt is the time taken to stop

Given:

v_i = 7.68 m/s (Initial speed of the player)v_f = 0 m/s (The player comes to a stop)t = 0.202 s (Time interval)

Now we can plug these values into our equation to find a:

a = (0 - 7.68 m/s) / 0.202 s

a = -7.68 m/s / 0.202 s

a = -38.02 m/s2

The negative sign indicates that the acceleration is in the opposite direction of the player's initial motion. Since the player was moving forward and came to a stop, the acceleration is directed backward, towards the line of scrimmage.

Select the correct statement to describe when a sample of liquid water vaporizes into water vapor. Question 12 options: Temperature increases and molecular motion increases while shape becomes less defined. Temperature increases and molecular motion decreases while shape becomes more defined. Temperature decreases and molecular motion decreases while shape becomes more defined. Temperature decreases and molecular motion increases while shape becomes less defined.

Answers

temperature increases and molecular motion increases while shape becomes less defined.


Astronomers have discovered several volcanoes on io, a moon of jupiter. one of them, named loki, ejects lava to a maximum height of 2.00 â 105 m. suppose another volcano on a different moon ejected lava at a height of 1.89 â 105 m where the acceleration of gravity is 1.72 m/s2.

Answers

The question seems to be incomplete. However, I can think of a possible logical question this problem could have. The equation for the maximum height attained by any object thrown upwards is:

H = v²/2g

I think the question would be determining the gravity in Io assuming that the initial velocity of the lava is the same. Then, the solution is as follows:

Let's use the other volcano to find v.
1.89×10⁵ m = v²/2(1.72 m/s²)
Solving for v,
v = 806.325 m/s

So, we use this to find g in Io.
2×10⁵ m = (806.325)²/2(g)
Solving for g,
g = 1.6254 m/s²

Final answer:

The question deals with the heights of volcanic lava ejections on moons within our solar system under varying gravitational conditions, highlighting Io, a moon of Jupiter. It emphasizes physics concepts like kinematics and gravitational force, and underlines the contribution of space exploration to our understanding of celestial phenomena.

Explanation:

The question explores the phenomenon of volcanic eruptions on moons in our solar system, focusing on Io, one of Jupiter's moons, and another hypothetical moon. Specifically, it mentions volcanoes ejecting lava to great heights under different gravitational conditions. The question implicitly asks for an analysis or comparison based on the given data, such as the maximum height of lava ejection and the acceleration due to gravity on another moon.

The subject matter delves into the principles of kinematics and gravitational force, which are fundamental concepts in physics. It exemplifies how extraterrestrial volcanism can offer insights into the geological and physical dynamics of celestial bodies other than Earth. Furthermore, the mention of Galileo and Voyager spacecrafts underlines the importance of space exploration in understanding these phenomena.

The average distance between the variable scores and the mean in a set of data is the __________. A. range B. standard deviation C. mean D. median

Answers

The average distance between the variable scores and the mean in a set of data is the standard deviation.

Answer: B. standard deviation

Explanation:

In statistics , Standard deviation is a term which is used to to represent the measure of dispersion of data from the mean-value.

It is used to determine how closely the data values are with the mean of the entire data.

It is the average distance from each data value to the mean.

Hence, the average distance between the variable scores and the mean in a set of data is the standard deviation.

An object is lifted to a certain height and then dropped. During the drop, which of the following is increased?

a) gravitational potential energy
b) kinetic energy
c) total mechanical energy
d) B and C

Answers

Kinetic energy increases as the object falls.

The tropical year, the time from vernal equinox to the next vernal equinox, is the basis for our calendar. it contains 365.242199 days. find the number of seconds in two and a half tropical years.

Answers

Final answer:

The length of a tropical year is approximately 365.242199 days, or approximately 31556926 seconds. Therefore, the number of seconds in two and a half tropical years is approximately 78892315 seconds.

Explanation:

The tropical year is based on the time it takes the Earth to revolve around the sun, and is the basis of our calendar. This time period lasts approximately 365.242199 days. To find the number of seconds in a tropical year, we need to first convert this period into hours, minutes, and then seconds. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. Here's the calculation:

1 tropical year = 365.242199 days = 365.242199 x 24 = 8765.812776 hours8765.812776 hours = 8765.812776 x 60 = 525948.76656 minutes525948.76656 minutes = 525948.76656 x 60 = 31556925.9936 seconds

So, one tropical year is approximately 31556926 seconds.

To find out the number of seconds in two and a half tropical years, we simply multiply this number by 2.5:

2.5 tropical years = 2.5 x 31556926 = 78892315 seconds

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Work is the transfer of _______ that occurs when a force makes an object move.

Answers

I think it is energy

If a microwave oven produces electromagnetic waves with a frequency of 2.70 ghz, what is their wavelength?

Answers

Ok this one is pretty straight forward :) This is what we know:

1. 2.7GHz is how many vibrations in 1 second. (2.7 x10^9 Hz)
2. Light always has a constant speed 2.9 x10^8 meters per second.

Therefore to find out the length of one of those vibrations you just divide        2.9 x10^8 by 2.7 x10^9
which looks like this in your calculator:
290000000 / 2700000000
= 0.107m
= 10cm

What is the uncertainty of the position of the bacterium? express your answer with the appropriate units?

Answers

For two un-related quantities, the Heisenberg uncertainty equations holds: the prduct of the two uncertainty quantities is greater than [tex]\hbar/2[/tex]
Example of unrelated quantities are position and momentum, energy and time. 
Thus
[tex]\Delta x*\Delta p \ \textgreater \ \hbar/2[/tex]
Knowing the speed of the bacteria the uncertainty in its position is
[tex]\Delta x \ \textgreater \ \hbar/(2 \Delta p) =\hbar/(2mv)[/tex]

"if the left-hand mass is 2.3 kg ,what should the right-hand mass be so that it accelerates downslope at 0.64 m/s2?"

Answers

Final answer:

In order to maintain equilibrium and have a downslope acceleration of 0.64 m/s² with a 2.3 kg mass, the right-hand mass should be approximately 0.15 kg.

Explanation:

In physics, the question is referring to the concept of equilibrium through the force of gravity. When a downtrend pushes left-hand mass with a certain acceleration, it implies that any other force (potentially from another mass on the opposite direction) counteracts. This counteraction or the right-hand mass is what we are now to calculate.

Assuming there is no friction, the force acting on the left-hand mass (F1) can be calculated using Newton's second law of motion, F = ma where m is the mass and a is the acceleration, yielding F1 = 2.3 kg * 0.64 m/s² = 1.472 N

For equilibrium to be maintained, the force due to the right-hand mass (F2) must equal F1. Therefore, if g is the acceleration due to gravity (9.81 m/s²), the right-hand mass (m2) can be found using the formula m2 = F1 / g, simplifying to m2 = 1.472 N / 9.81 m/s² = 0.15 kg.

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A package of chips weighs 45 grams. How much is that in kilograms?

Answers

There is 1000 grams in 1 kilogram, and so:

Your answer to this question is 0.045 kilograms

hope this helps
45 grams is 0.045 kilograms, i am 100% positive this is right. Good Luck

Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first. alice reaches the surface of the lake first. alice and tom will reach the surface of the lake at the same time.

Answers

Alice and Tom reach the lake simultaneously due to gravity's independence from their initial horizontal velocities. The correct answer is (E).

Let us consider the concept of horizontal motion and vertical motion of a projectile (in this case, Alice and Tom) are independent of each other when there is no air resistance.

This means that the horizontal velocity does not affect the vertical motion.

Both Alice and Tom are subject to the same gravitational acceleration, and since they are both falling vertically, they will reach the surface of the lake at the same time.

So, the correct answer is (E). Alice and Tom will reach the surface of the lake at the same time.

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Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below.

(A) alice and tom dive from an overhang into the lake below.

(B) tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s.

(c) neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first.

(D) alice reaches the surface of the lake first.
(E) alice and tom will reach the surface of the lake at the same time.

Both Alice and Tom will reach the surface of the lake at the same time because their times to hit the water depend only on the vertical distance and gravitational acceleration.

Alice and Tom both dive from the same overhang into a lake below.

Although Alice takes a running start and has an initial horizontal velocity of 25 m/s, the time it takes both of them to reach the lake is the same. This is because the vertical motion for both divers is under uniform acceleration due to gravity, which is not affected by their horizontal velocities.The time it takes to reach the surface is dictated by the height of the overhang and gravity alone.

Both Alice and Tom experience the same vertical acceleration and fall the same vertical distance, hence, they will both reach the surface of the lake at the same time.

Determine the vertical motion of each diver, which is independent of horizontal motion.Use the kinematic equation for vertical motion: h = 1/2 * g * t².Since both Alice and Tom start from the same height and are only influenced by gravity (9.8 m/s²), their times to hit the water are the same.

If the work put into a lever is 25.0 joules and the work done by the lever is 20.0 joules, what is the efficiency of the lever? 100% because energy must be conserved. 80.0% 45.0% 5.0%

Answers

80% , hope this helps 

Answer: The efficiency of the lever is 80%.

Explanation:

An efficiency is the measure of how much wok or energy is conserved in a given process. It is defined as the ratio of output work and input work. If the energy is totally conserved in a process, the the percentage efficiency will be 100%.

Mathematically,

[tex]\%\text{ efficiency}=\frac{W_{out}}{W_{in}}\times 100[/tex]

Where,

[tex]W_{out}[/tex] = Work done by the lever = 20 J

[tex]W_{in}[/tex] = Work put in the lever = 25 J

Putting values in above equation, we get:

[tex]\%\text{ efficiency}=\frac{20}{25}\times 100\\\\\%\text{ efficiency}=80\%[/tex]

Hence, the efficiency of the lever is 80%.

Sunspots _____. A) are found in the chromosphere B) are dark spots in the corona C) are areas where the photosphere is cooler D) happen when certain areas are hotter than others

Answers

C) are areas where the photosphere is cooler is the correct answer.
The answer is C, are areas where the photosphere is cooler. Hope this helps:)

A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.
a.how much time does ti take for the beetle to reach 60 mi/h?
b.a top - fuel dragster can go from 0 to 60 mi/h in 0.600 seconds. find the acceleration (m/s^2) of the dragster.

Answers

Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.

Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s

Answer: 11.4 s

Part b.
We already determined that v = 60 mi/h = 26.822 m/s.
t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²

Answer:  44.7 m/s²

If a flea can jump straight up to a height of 21.1 cm , what is its initial speed as it leaves the ground, neglecting air resistance?

Answers

The flea jumps at high velocity, reaches zero velocity at the maximum height 21.1 cm before starting to fall. Solve for initial velocity given final velocity is zero.
since time is not given, use the equation:
v^2 = u^2 + 2as
convert gravity or displacement to have same units. 9.8 m/s = 980 cm/s
0 = u^2 + 2(-980)(21.1)
41356 = u^2
sqrt(41356) = u
203.4 cm/s = u

Answer:

Initial speed, u = 2.03 m/s

Explanation:

Flea jumps to a height of, h = 21.1 cm = 0.211 m

As it leaves the ground, its final speed, v = 0

Acceleration, a = -g

Let u is the initial speed of the flea. It can be calculated as :

[tex]v^2-u^2=2as[/tex]

[tex]-u^2=2\times (-9.8)\times 0.211[/tex]

u = 2.03 m/s

So, the initial speed of the flea as it leaves the ground is 2.03 m/s. Hence, this is the required solution.

Bernoulli equation deals with the law of conservation of

Answers

Bernoulli's principle can be borrowed from the principle of conservation of energy. 

Hope this helped.

Final answer:

Bernoulli's equation is a form of the conservation of energy principle in fluid flow. It states that the sum of pressure, kinetic energy, and potential energy is constant at any two points in an incompressible, frictionless fluid.

Explanation:

Bernoulli's equation is a form of the conservation of energy principle in fluid flow. It states that the sum of pressure, kinetic energy, and potential energy is constant at any two points in an incompressible, frictionless fluid.

For example, if a fluid flows through a pipe with varying diameters, according to Bernoulli's equation, the pressure decreases as the fluid velocity increases.

This concept is important in the study of fluid mechanics and is used to analyze and predict the behavior of fluids in various applications.

if you used 16 gallons when driving 367 miles, what was your gas mileage over that distance

Answers

Your gas mileage would be 22.93 miles per gallon.

A basketball referee tosses the ball straight up for the starting tip-off. at what velocity (in m/s) must a basketball player leave the ground to rise 1.23 m above the floor in an attempt to get the ball?

Answers

The formular for solving this equation is 
mgh = mv^2/2
The M on both sides of the equation stand for mass and the two of them cancel each other out and the equation becomes:
gh = V^2 / 2
g = 9.8 m/s
h = 1.23 m
V ?
V is the velocity that we need to find, so we are going to make V the subject of the formular:
V = Square root of 2gh = square root of [2 * 9.8 * 1.23] = square root of [24.108]= 4.9 
Thus, the velocity = 4.90 m/s

 

A place kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. when kicked, the ball leaves the ground with a speed of 23.4 m/s at an angle of 50.0° to the horizontal. (a) by how much does the ball clear or fall short of clearing the crossbar

Answers

The ball clears by 11.79 meters Let's first determine the horizontal and vertical velocities of the ball. h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s Now determine how many seconds it will take for the ball to get to the goal. t = 36.0 m / 15.04 m/s = 2.394 s The height the ball will be at time T is h = vT - 1/2 A T^2 where h = height of ball v = initial vertical velocity T = time A = acceleration due to gravity So plugging into the formula the known values h = vT - 1/2 A T^2 h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2 h = 42.92 m - 4.9 m/s^2 * 5.731 s^2 h = 42.92 m - 28.0819 m h = 14.84 m Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m

When you lift a box off the ground, gravity opposes your lifting force.
A.True
B.False

Answers

That's true because every action has an equal and opposite reaction and weight is literally the force gravity has on an object.
true. When you lift the box, you are doing work, but gravity is using force to push it back down towards the center of earth. 
Hope I helped!

A crate pushed along the floor with velocity v⃗ i slides a distance d after the pushing force is removed. if the mass of the crate is doubled but the initial velocity is not changed, what distance does the crate slide before stopping?

Answers

If the mass of the crate is doubled but the initial velocity is not changed, the crate slides distance d before stopping.

[tex]\texttt{ }[/tex]

Further explanation

Let's recall the formula of Kinetic Energy as follows:

[tex]\large {\boxed {E_k = \frac{1}{2}mv^2 }[/tex]

Ek = Kinetic Energy ( Newton )

m = Object's Mass ( kg )

v = Speed of Object ( m/s )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial height = h₁ = 26 m

final height = h₂ = 16 m

initial speed = v₁ = 0 m/s

coefficient of friction = μ

gravitational acceleration = g

distance = d

Asked:

final speed = v₂ = ?

Solution:

We will use Work and Energy formula to solve this problem as follows:

[tex]W = \Delta Ek[/tex]

[tex]-f d = Ek_{final} - Ek_{initial}[/tex]

[tex]-\mu N d = \frac{1}{2}m (v_f)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2}m (v_f)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2}m (0)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2} m (v_i)^2[/tex]

[tex]\mu g d = \frac{1}{2} (v_i)^2[/tex]

[tex]d = \frac{1}{2} (v_i)^2 \div ( \mu g )[/tex]

[tex]\boxed {d = \frac { (v_i)^2 } { 2 \mu g } }[/tex]

[tex]\texttt{ }[/tex]

From information above we can conclude that the distance is independent to the mass of the crate.

If the mass of the crate is doubled but the initial velocity is not changed, the crate slides the same distance d before stopping.

[tex]\texttt{ }[/tex]

Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441Newton's Law of Motion: https://brainly.com/question/10431582Example of Newton's Law: https://brainly.com/question/498822

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

If the mass of the crate is doubled while maintaining the same initial velocity, the stopping distance will be halved. This is due to the doubled frictional force from the increased mass. Therefore, the crate will slide a distance of d/2 before coming to a stop.

Initial situation: Crate pushed with initial velocity v_i slides distance (d) after force is removed.Kinetic energy: [tex]\( K = \frac{1}{2} m v_i^2 \).[/tex]Friction stops crate: Work done by friction equals kinetic energy.- Frictional force proportional to normal force; if mass doubles, frictional force doubles.- Work done by friction over distance [tex]\( d \): \( W = \mu m g d \)[/tex] where [tex]\( \mu \)[/tex] is the coefficient of friction and g is acceleration due to gravity.- When mass doubles, frictional force becomes [tex]\( 2 \mu m g \)[/tex], work done becomes [tex]\( 2 \mu m g d \)[/tex]- To stop crate with doubled mass: [tex]\( \mu (2m) g d' = m v_i^2 \)[/tex]- Solving for new stopping distance [tex]\( d' \): \( d' = \frac{d}{2} \)[/tex]

Thus, the crate will slide half the distance before stopping if the mass is doubled but the initial velocity is unchanged.

When a 75 kg man sits on the stool, by what percent does the length of the legs decrease? assume, for simplicity, that the stool's legs are vertical and that each bears the same load?

Answers

Each leg of the stool decreases in length by approximately 1.40 × 10⁻⁴% when the 70 kg man sits on it.

Calculate the force exerted on each leg:

Given: mass (m) = 70 kg, acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mass × acceleration = 70 kg × 9.8 m/s² = 686 N

Determine the original length of the legs:

Let's assume the height of the stool is 1 meter (100 cm).

Calculate the cross-sectional area of each leg:

Given the diameter of each leg is 2.5 cm, the radius (r) is 1.25 cm or 0.0125 m.

Area (A) = π × r²

Area ≈ 3.14 × (0.0125 m)² ≈ 4.91 × 10⁻⁴ m²

Determine the modulus of elasticity of Douglas fir:

Let's assume E = 10 × 10⁹ N/m².

Calculate the change in length for each leg:

Using the formula for axial deformation:

Change in length (ΔL) = (Force × Length) / (Area × Modulus of Elasticity)

ΔL = (686 N × 1 m) / (4.91 × 10⁻⁴ m² × 10 × 10⁹ N/m²)

ΔL ≈ 1.40 × 10⁻⁶ m

Calculate the percentage decrease in length:

Percentage decrease = (Change in length / Original length) × 100%

Percentage decrease = (1.40 × 10⁻⁶ m / 1 m) × 100%

Percentage decrease ≈ 1.40 × 10⁻⁴ %

So, each leg of the stool decreases in length by approximately 1.40 × 10⁻⁴% when the 70 kg man sits on it.

The question probable may be:

A three-legged wooden bar stool made out of solid Douglas firhas legs that are 2.5 cm in diameter.

When a 70 kg man sits on thestool, by what percent does the length of the legs decrease?Assume, for simplicity, that the stool's legs are vertical and thateach bears the same load.

What is the resultant velocity vector when you add your swimming velocity and the current velocity? give the x and y components in meters per second separated by a comma?

Answers

The resultant vector, is the vector that adds the components x and y separately.

Since the two x components are 0.00 m/s and 1.00 m/s, the resultant x component will be:

0.0   m/s + 1.00 m/s = 1.00 m/s in + x direction

Similarly, the y components will be:

  -1.00 m/s + 0.00 m/s = -1.00 m/s in -y direction

So, the resultant vector will be: 

(1.00 m/s, -1.00 m/s)

The simultaneous vector of velocity in the form of components x and y is

1, -1 m / s

Further explanation

Vectors are quantities that have magnitude and direction

Vector can be symbolized in the form of directed line segments

One of the presentations of vector shapes is in geometric conditions where the vector components are expressed in the form of x and y coordinates which can be described in matrix form

The position vector of a vector starts from the starting point to the endpoint

Addition of two vectors is the addition of component x and component y

A (x1, y1) and B (x2, y2)

A + B = (x1 + x2, y1 + y2)

There is additional information on the problem:

a swimmer moves to the right with a speed of 1 m / s while the current from the river with the same speed down by 1 m / s (picture attached)

so the vector component position based on components x and y becomes:

swimmer (p): (1,0)

river current (s): (0, -1)

So if the two vectors are added it will become:

v = p + s

v = (1 + 0, 0-1)

v = (1, -1) m / s

Learn more

identify the components of a vector

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negative vectors

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add two velocity vectors

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Keywords: vectors, a swimmer, river, Addition of two vectors

Plyometric helps strengthen your bones true or false

Answers

plyometric does indeed help strengthen your bones
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