What is the zero r(x)=3/8x-16 ?

Answers

Answer 1
Add 16 to both sides
Multiply both sides by 8/3 x= 128/3
Simplify : x= 42.66repeating so 42 and 2/3rds

Related Questions

ABC is reflected across x = 1 and y = -3. What are the coordinates of the reflection image of B after both reflections?
A. (-7, -1)
B. (-7, 1)
C. (7, 1)
D. (7, -1)

Answers

Answer:

The correct option is C

Step-by-step explanation:

From the given figure it is noticed that the coordinates of point B are (-5,-7).

If a figure is reflected across x = 1, then

[tex](x,y)\rightarrow (1-(x-1),y)[/tex]

[tex](x,y)\rightarrow (2-x,y)[/tex]

So the coordinates of B after reflection across x = 1 are

[tex](-5,-7)\rightarrow (2-(-5),-7)[/tex]

[tex](-5,-7)\rightarrow (7,-7)[/tex]

If a figure is reflected across y = -3, then

[tex](x,y)\rightarrow (x,-3-(y+3))[/tex]

[tex](x,y)\rightarrow (x,-6-y)[/tex]

So the coordinates of B after reflection across x = 1 followed by reflection across y= -3 are

[tex](7,-7)\rightarrow (7,-6-(-7))[/tex]

[tex](7,-7)\rightarrow (7,1)[/tex]

Therefore the coordinates of the reflection image of B after both reflectionsthe are (7,1) and option C is correct.

What is the gcf of a^2b^5 and a^2b^6

Answers

They both have a^2 in common, so a^2 is part of the GCF.
Then you have b^5 and b^6, so they both have b^5 in common.
The GCF is a^2b^5

this is my home work of 8th ducking grade butch so see if you could answer it

Answers

So 4/5 times "something" = 32.
That means that something = 32 / (4/5) = 40.

To turn this multiplication around, it helps to think about 2 * 3 = 6, how would you write 3 = ?. You quickly :"see" that it should be 3=6/2.

find the sale price of the item.round to two decimal places if necessary.

Original price $89.00

Markdown:33%

The sale price is $___

Answers

Here is one way of doing it.
The original price of the item is $89.
$89 is 100% of the original price.
You want to take off 32%.
100% - 32% = 67%
That means you want to find out how much 68% of $89 is.
68% of $89 =
= 0.68 * 89
= 60.52
Answer: $60.52

You asked for a 33% markdown, but the pic shows 32%, so I did 32%.

Inventory for a company is taken hourly from 10 to 4:00. At the start of the day, the warehouse had 65 boxes. Between 10 and 11, 7 boxes were shipped. From 11 to noon, 5 were sent, and another 9 between noon and 1 p.m.

Answers

What is the question?

What is the slope-intercept form of this equation?

3x + 9y = 18

A. y = -1/3x + 6

B. y = -1/3x + 2

C. y = 1/3x + 6

D. y = 2/3x + 2

Answers

Slope intercept for is y=mx+b

So to solve this, get y by itself, and move everything else to the other side of the equation.

3x + 9y = 18

first subtract 3x from each side

9y = 18 - 3x

Then divide each side by 9

y = [tex] \frac{18-3x}{9} [/tex]

Simplify by dividing both 18 and -3 by 9

y = 2 - 1/3x

Rearrange it so that -1/3x comes first

y = -1/3x + 2

ANSWER:

B. y = -1/3x + 2

I hope this helps!

The correct answer is B. y = -1/3x + 2


Sorry if I am wrong, but I believe that this is the correct answer.

All of the following have the same unit price except _____.
2 for $5.08
5 for $12.70
1/2 for $1.27 2
2 1/2 for $6.25

Answers

2 1/2 for $6.25 is the answer

Answer:

2 1/2 for $6.25

Step-by-step explanation:

Hello

the unit price is the price that you pay for a unit of product, you must find each unit price and compare

the unit price is given by

[tex]Unit\ price = \frac{amount\ paid}{number\ of\ products} \\[/tex]

Step 1

find each unit price

1).2 for $5.08

[tex]Unit\ price = \frac{amount paid}{number of products} \\Unit\ price = \frac{ 5.08}{2}\\\\Unit\ price =2.54[/tex]

unit price =2.54 $

2).5 for $12.70

[tex]Unit\ price = \frac{amount paid}{number of products} \\Unit\ price = \frac{ 12.7}{5}\\\\Unit\ price =2.54[/tex]

unit price =2.54 $

3) 1/2 for $1.27 2

[tex]Unit\ price = \frac{amount paid}{number of products} \\Unit\ price = \frac{ 1.27}{0.5}\\\\Unit\ price =2.54[/tex]

unit price =2.54 $

4) 2 1/2 for $6.25

[tex]Unit\ price = \frac{amount paid}{number of products} \\Unit\ price = \frac{ 6.25}{2.5}\\\\Unit\ price =2.5[/tex]

unit price =2.5 $

Step 2

define

Now, we can define that the unit price of 2 1/2 for $6.25 is different to the others.

2.5 ≠ 2.54

Have a great day

Find all the real square roots of 0.0625.



-0.25 and 0.25
-0.025 and 0.025
0.25
-0.025

Answers

Factor

0.0625
0.25 * 0.25

Square root is a 2nd root which is even so there can be negative solutions.

Sqrt(0.0625) = 0.25 or -0.25
Final answer:

The real square roots of 0.0625 are -0.25 and 0.25, as both of these numbers squared equal 0.0625.

Explanation:

The student has asked to find all the real square roots of 0.0625. The square root of a number is a value that, when multiplied by itself, gives the original number. In this case, we're looking for a number which, when squared, equals 0.0625.

To find this, we can recognize that the square root of 0.0625 could be thought of in fraction form as the square root of 625/10000, which simplifies to the square root of 625 divided by the square root of 10000. This reduces to 25/100 because 625 is a perfect square (25 * 25) and 10000 is also a perfect square (100 * 100). Therefore, the principal square root of 0.0625 is 0.25.

However, since every positive number has two square roots, one positive and one negative, and because the square of both -0.25 and 0.25 gives 0.0625, we conclude that the real square roots of 0.0625 are -0.25 and 0.25.

Which equation represents a line with a slope of zero?

Answers

Y = 4 is the answer.
Thanks (:

Explain what it means to have a correlation in a scatterplot.

Answers

Correlation is used to show trends in a scatter plot

The following are the possible correlation types in a scatter plot

Positive correlationNegative correlation

When the x value and the y values increase at the same time, then the correlation is positive.

However, when the x value and the y values increase at the same time, then the correlation is negative.

Read more about correlation at:

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Answer:

Sample Response/Explanation: A correlation exists in a scatterplot if there is a general trend in the outputs as inputs increase. If the outputs generally increase in value, then there is a positive correlation. If the outputs generally decrease in value, then there is a negative correlation.

Step-by-step explanation:

i did it

A university would like to create a circular eating area with picnic tables. the eating area will have small plants that make a path to create individual sections that form sectors. the angle formed by the plants is 0=120 degrees, and the radius is r = 9m. find the area of each sector. a. 3(pi)m(squared) b. 6(pi)m(squared) c. 27(pi)m(squared) d. 54(pi)m(squared)

Answers

Area of each of the three sectors is equal to one-third of the circular area, which is
A=pi r^2 = pi (9)^2=81 pi
So area of each of the three sectors is 81pi /3=27 pi  (m^2).

Examine the function for relative extrema and saddle points. (if an answer does not exist, enter dne.) h(x, y) = x2 − 9xy − y2

Answers

The given function is
h(x,y) = x² - 9xy - y²

Calculate partial derivatives.
[tex]h_{x} = 2x \\ h_{xx} = 2 \\ h_{y} = -2y \\ h_{yy} = -2 \\ h_{xy} = 0 [/tex]
For the critical points,
[tex]h_{x} = 2x=0 \, \Rightarrow \, x=0 \\h_{y}=-2y=0 \,, \Rightarrow \, y=0[/tex]

To perform a test for a saddle point, calculate
[tex]D = h_{xx}(0,0) h_{yy} (0,0) -[ h_{xy}(0,0)]^{2} = (2)(-2) - (2)^{2} = -8[/tex]
Because D < 0, a saddle point exists at (0,0).


What numbers multiply to -30 and add to -3

Answers

Let the numbers be x and y.  Then xy = -30 and  x+y = -3.

Solve xy = -30 for y:    y = -30/x

subst. -30/x for y in   x+y= -3:     x  -  30/x = -3

Multiply all 3 terms by x:  x^2 - 30 = -3x, so   x^2 + 3x - 10 = 0

Solve this quadratic equation for x.     x: {-5, 2}

If x = -5, then   x+y = -3 becomes -5 + y = -3, and y = 2.

You should check to determine whether x=2 is also correct.  If it is, what is the corresponding y value?

WORTH 20 POINTS
Which functions are equivalent to f(x)= 4√162? Check all that apply

A)f(x)= 162 x/4

B)f(x)=(3 4√2)x

C)f(x)=9 4√2 x

D)f(x)=162 4/x

E)f(x)=[3 (2 1/4)]x

Answers

[tex]\bf 4\sqrt{162}\qquad \begin{cases} 162=2\cdot 3\cdot 3\cdot 3\cdot 3\\ \qquad 2\cdot 3^4\\ \qquad 2\cdot (3^2)^2 \end{cases}\implies 4\sqrt{2\cdot (3^2)^2}\implies 4\cdot 3^2\sqrt{2} \\\\\\ 4\cdot 9\sqrt{2}\implies 36\sqrt{2}[/tex]

The options that are equivalent to the given function are;

Option A

Option B

Option E

The correct options are;

A) f(x) = [tex]162^{x/4}[/tex]

B) f(x) = (3∜2[tex])^{x}[/tex]

C) f(x) = [tex]9\sqrt[4]{2^{x} }[/tex]

D) f(x) = [tex]162^{4/x}[/tex]

E) f(x) = [tex](3(2^{1/4}))^{x}[/tex]

We are given the function; f(x) = [tex](\sqrt[4]{162})^{x}[/tex]

Now, when we have something like; [tex]\sqrt[b]{2}^{a}[/tex]

This expression can also be expressed as; [tex]2^{a/b}[/tex]

Therefore our function can also be expressed as; f(x) = [tex]162^{x/4}[/tex]

Option A; This is correct because it is equal to our function gotten

Option B; f(x) = (3∜2[tex])^{x}[/tex]

From earlier, we will have;  (3 × [tex]2^{1/4}[/tex][tex])^{x}[/tex]

Now, 3 can also be expressed as [tex]81^{1/4}[/tex]

Thus, we now have;

([tex]81^{1/4}[/tex] × [tex]2^{1/4}[/tex][tex])^{x}[/tex]

Factorizing out the 1/4 exponent gives;

(81 × 2[tex])^{x/4}[/tex]

⇒ = [tex]162^{x/4}[/tex]

This is same with our function and it is correct

Option C; f(x) = (9∜2[tex])^{x}[/tex]

This is similar to our equation in option B which was correct but the difference here is 9 instead of 3 and clearly this option is not correct.

Option D; f(x) = [tex]162^{4/x}[/tex]

This is not the same with our function and so it is wrong

Option E; f(x) = [tex](3(2^{1/4}))^{x}[/tex]

As seen in option B;

3 can also be expressed as [tex]81^{1/4}[/tex]

Thus, we now have;

;([tex]81^{1/4}[/tex] × [tex]2^{1/4}[/tex][tex])^{x}[/tex]

Factorizing out the 1/4 exponent gives;

(81 × 2[tex])^{x/4}[/tex]

⇒ = [tex]162^{x/4}[/tex]

This is same with our function and it is correct

Read more at; https://brainly.com/question/6504126

if 8 pens and 7 pencils cost $3.37 while 5 pens and 11 pencils cost $3.10, how much does each pen and pencil cost?

Answers

Let a=number of pens and b=number of pencils.
8a+7b=3.37; 5a+11b=3.10.
To eliminate a variable multiply the first eqn by 5 and the second by 8:
40a+35b=16.85, 40a+88b=24.80.
Subtract these equations: 53b=7.95, b=$0.15. So 5a=3.10-1.65=$1.45, a=$0.29.
Pens are $0.29 each and pencils $0.15.

Answer with Step-by-step explanation:

Let x be the cost of 1 pen and y be the cost of 1 pencil

8 pens and 7 pencils cost $3.37 while 5 pens and 11 pencils cost $3.10

8x+7y= 3.37  -----------------(1)

and 5x+11y= 3.10  -----------------(2)

equation (1)×5-equation(2)×8

5(8x+7y)-8(5x+11y)=3.37×5-3.10×8

40x+35y-40x-88y= -7.95

-53y = -7.95

y= 0.15

Putting y=0.15 in equation (1), we get

8x+7×0.15=3.37

8x+1.05=3.37

8x=2.32

x=0.29

Hence, Cost of 1 pen=$ 0.29

Cost of 1 pencil= $ 0.15

Maya is showing her work in simplifying (5.2 − 4.5) − 5.5 + 4.8. Identify any error in her work or reasoning.

Answers

if putting 5.2 and 4.5 in fraction form, her error must have been timing 3 by 3 to 5.2 and 4.5 as a fraction. Meaning that 5.5 and 4.8 is wrong

Which of the following describes the zeroes of the graph of f(x) = 3x6 + 30x5 + 75x4?

Answers

ANSWER

The zeros are:
[tex]x = 0 \: \: or \: \: x = - 5[/tex]
with multiplicity of 4 and 2 respectively.


EXPLANATION

The given function is

[tex]f(x) =3 {x}^{6} + 30 {x}^{5} + 75 {x}^{4} [/tex]
We want to find

[tex]3 {x}^{6} + 30 {x}^{5} + 75 {x}^{4} = 0 [/tex]

We can find the zeros of this function by factorizing the greatest common factor to obtain,

[tex]3 {x}^{4} ( {x}^{2} + 10x + 25) = 0[/tex]

The expression in the bracket can be rewritten as,

[tex]3 {x}^{4} ( {x}^{2} + 2(5)x + {5}^{2} ) = 0[/tex]

We can see clearly that, the expression in the bracket is a perfect square that can be factored as,

[tex]3 {x}^{4} ( x+ 5)^2 = 0[/tex]

This implies that,

[tex]3 {x}^{4} = 0[/tex]
or

[tex](x + 5) ^{2} = 0[/tex]

This gives,

[tex] {x}^{4} = 0 \: \: or \: \: x + 5 = 0[/tex]

This finally gives,

[tex]x = 0 \: \: or \: \: x = - 5[/tex]

Answer:

–5 with multiplicity 2 and 0 with multiplicity 4

Step-by-step explanation:

I just got it wrong on edge 2020

If $2300 is spent on vacations or travel each year, estimate how much should be set aside each month for those expenses?
a.
Approximately $200 per month should be set aside for vacation or travel expenses.
b.
Approximately $2300 per month should be set aside for vacation or travel expenses.
c.
Approximately $1250 per month should be set aside for vacation or travel expenses.
d.
Approximately $230 per month should be set aside for vacation or travel expenses.

Answers

A: Approximately 200.00 a month. as you would divide the 2300.00 by 12. you get the answer of 191. it's safer to round up so you have a little extra. it's better to over estimate than under estimate

The estimate should be set Approximately $200 per month aside for vacation or travel expenses.

What is estimation?

It is a rough calculation of the value, number, quantity, etc. It doesn't use real calculation but estimation by some method like prediction, using approximation etc.

Given that  $2300 is spent on vacations or travel each year.

It is known that 12 months in a year

= 2300/12

we can round 2300 to 2400 because it is an estimatation value and divide by 12

= 2400/12

= 200

Thus, an approximation of $200 each month.

The estimate should be set Approximately $200 per month aside for vacation or travel expenses.

Learn more about estimation here:

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A certain product has a unit price of 9.5 cents per ounce. The product sells in bottles of 14 ounces and is priced at $1.30.

As compared to the unit price, the $1.30 price of the 14-ounce bottle _____.

is too low
is too high
is correct
can't be determined

Answers

The answer would be "is too low." Hope this helps!

Answer: the answer is too low i really hope this hepls

Step-by-step explanation:

Pin Numbers A student loan administrator distributes pin numbers to its debtors. Each pin consists of two letters followed by three numbers. (Assume repetition is allowed, and order is important.) (a) How many different pin numbers are there? (b) What is the probability a pin number selected at random ends in 000? (c) What is the probability a pin number selected at random begins with AA?

Puppies of the Dow Refer to Problems 41 and 43. (a) If five stocks from the Dogs of the Dow list are randomly selected, what is the probability all five will be Puppies of the Dow? (b) If five stocks from the Dogs of the Dow list are randomly selected, what is the probability exactly three will be Puppies of the Dow? (c) If five stocks from the Dogs of the Dow list are randomly selected, what is the probability at least two will be Puppies of the Dow?


40. Hockey There are 15 teams in the Eastern Conference of the National Hockey League for the 2009–2010 season, divided

Answers

I will just answer the problem about Pin numbers because the other questions lack other given values.

a. How many different pin numbers are there?

There are 26 letters in total and 10 numbers in total (including zero), therefore the total number of different pin numbers are:

Total possible = 26 * 26 * 10 * 10 * 10

Total possible = 676,000 different pins

 

b. What is the probability a pin number selected at random ends in 000

The total possible numbers with ending of 0 0 0 is:

Possible numbers = 26 * 26 * 1 * 1 *1

Possible numbers = 676

 

Therefore the probability is:

Probability = 676 / 676,000

Probability = 0.001 = 0.10%

 

c. What is the probability a pin number selected at random begins with AA?

The total possible numbers starting with A A is:

Possible numbers = 1 * 1 * 10 * 10 * 10

Possible numbers = 1000

 

Therefore the probability is:

Probability = 1000 / 676,000

Probability = 1.48 x 10^-3 = 0.148%

Jake is comparing the prices of two mattress cleaning companies. Company A charges $30 per mattress and an additional $13 as service charges. Company B charges $28 per mattress and an additional $15 as service charges.

Part A: Write an equation to represent each company's total charges for cleaning a certain number of mattresses. For both equations (one for Company A and one for Company B), define the variable used. (4 points)

Part B: Which company would charge less for cleaning 4 mattresses? Justify your answer. (3 points)

Part C: How much money is saved by using the services of Company B instead of Company A to clean 7 mattresses? (3 points)


Answers

A)
y= total charges
x=number of mattresses
Company A: y=$30x+13 Company B: y=$28x+15

B)
plug x=4 into both equations to get
A: y=30(4)+13=$133
B: y=28(4)+15=$127
Company B charges less because 127<133

C)
Plug in 7 for x
A: y=30(7)+13=$223
B: y=28(7)+15=$211
A-B=223-211
=$12 Saved

The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 0}}\quad ,&{{ -2}})\quad % (c,d) &({{ 6}}\quad ,&{{ 0}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-(-2)}{6-0}\implies \cfrac{0+2}{6-0} \\\\\\ \cfrac{2}{6}\implies \cfrac{1}{3}[/tex]

[tex]\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=\cfrac{1}{3}(x-0) \\\\\\ y+2=\cfrac{1}{3}x\implies y=\cfrac{1}{3}x-2[/tex]

Answer:

y = 1/3x - 2

Step-by-step explanation:

the graph of g(x) is the graph of f (x)=x+9 reflected across the y axis.

which equation describes the function g?

1. g(x)=x-9
2. g(x)=-x-9
3. g(x)=-9x+9
4. g(x)=-x+9

Answers

Answer:

4. g(x)=-x+9

Step-by-step explanation:

The correct answer is actually g(x)=-x+9. Just took the text. XD

Answer-

[tex]g(x)=-x+9[/tex]

Solution-

The given function is,

[tex]f(x)=x+9[/tex]

Given that g(x) is the reflection of f(x) over y-axis.

The reflection of the point (x, y) across  the y-axis is the point (-x,y).

So, in case of reflection over y-axis the sign of only x-coordinate is changed and y-coordinate remains same.

So changing the sign of x in f(x) will yield its reflection over y-axis i.e g(x)

Therefore, g(x) is,

[tex]g(x)=-x+9[/tex]

If you fly from Los Angeles California to Miami Florida. the plane travels a distance of 3772 km in the air. the flight takes 6 hours and 15 minutes. what is the playing the average speed?

Answers

3772 Km divided by 6 hours and 15 minutes (375 minutes) = 10.05866666666667 per minute multiply my 60 =603.52 miles /hr average speed.

Jessie has a piece of wood that is 8 feet long. He needs to cut pieces that are 7/8 of a foot long. How many pieces will he be able to make?

Answers

8 / (7/8) =
8 * 8/7 =
64/7 =
9.14.....so he can cut 9 full pieces

Answer:

9 full pieces.

Step-by-step explanation:

In order to solve this we have to divide the total feets of wood that Jessie has, by the size of the pieces that Jessie needs:

[tex]\frac{8}{\frac{7}{8} }\\\frac{\frac{8}{1} }{\frac{7}{8} }\\\frac{8*8}{7*1}\\\frac{64}{7} =9.14[/tex]

Since Jessie will be able to cut 9.14 pieces of wood, he will have only 9 full pieces, so the total amount of pieces that he would be able to cut will be 9.

Ralph sold brownies for ​$0.66 a piece in order to earn money to buy baseball cards. If the cards cost ​$0..90 per​ pack, and if Ralph had no money left over after buying​ them, what is the least number of brownies he must have​ sold?

Show method for answer if possible?

Answers

he would have to sell at least 2 brownies because then he would have more than $.90

If he only sold one he wouldn't have enough money, he also can't sell part of a brownie

Ralph must have sold at least 9 brownies at $0.66 each to be able to buy a pack of baseball cards for $0.90 with no money left.

Ralph sold brownies for $0.66 each to earn money to buy baseball cards that cost $0.90 per pack. To find the least number of brownies Ralph must have sold, we need to determine how many brownies he needs to sell to make at least $0.90, with no money left over after the purchase.

Since Ralph has no money left over, the total amount he earned from selling brownies should be a multiple of $0.90.

To find the least number of brownies, we perform the following calculation:

Find the smallest multiple of $0.90 that is also a multiple of $0.66.

Divide that amount by the price of each brownie, which is $0.66.

By performing this calculation, we find that the least number of brownies sold would have to be a number that, when multiplied by $0.66, is both a multiple of itself and $0.90. The least common multiple (LCM) of 66 and 90 cents is $5.94, which corresponds to selling 9 brownies (because $5.94 divided by $0.66 per brownie equals 9).

Therefore, Ralph must have sold at least 9 brownies to buy a pack of baseball cards with no money left over.

If sales tax is 5%, what is the sales tax on an item costing $65?

Answers

The tax on the item is $3.25
Mult. $65 by 0.05 to obtain this tax amount.

Given the expression −10p2q + 7p3q − 5q, do the following as instructed below: A: Write the polynomial in descending order. B: Classify the polynomial by the number of terms. C: State the degree of the polynomial.

Answers

If we are to rewrite the equation such that we are able to clearly distinguish the exponents of each of the variables, this is,
 
     -10p²q + 7p³q - 5q

(A) Writing this polynomial in descending order, we properly looked the exponent of the first variable and arrange it from highest to least. 
    7p³q - 10p²q - 5q

(B) There are three terms in the polynomial given above. Hence, the given is TRINOMIAL.

(C) The degree of the polynomial is 4 since it is the highest exponent of the term in the given. 

change the mixed number to percentage

7 7/8

Answers

well, the idea being, that 1 is the 100% unit, so say 0.5 is 50% and so on.

so, let's convert 7 and 7/8 from mixed to improper first.

[tex]\bf 7\frac{7}{8}\implies \cfrac{7\cdot 8+7}{8}\implies \cfrac{63}{8}\implies 7.875\\\\ -------------------------------\\\\ \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&100\\ 7.875&p \end{array}\implies \cfrac{1}{7.875}=\cfrac{100}{p}\implies p=\cfrac{7.875\cdot 100}{1}[/tex]

At time t = 0 a car moves into the passing lane to pass a slow-moving truck. The average velocity of the car from t =1tot =1+his
v = 3(h+1)2.5 +580h−3 ave 10h
Estimate the instantaneous velocity of the car at t = 1, where time is in seconds and distance is in feet.

Answers

The correct given equation is:

v = [3 (h + 1)^2.5 + 580 h – 3] / 10 h

So to solve for the instantaneous velocity at t = 1, we must set h = 0. However we cannot do that since h is in denominator and a number divided by a denominator is infinite. Therefore we must set h to something almost zero. In this case, h = 0.0000001, so that:

 

at t = 1

v = [3 (0.0000001 + 1)^2.5 + 580 (0.0000001) – 3] / 10 * 0.0000001

v = 58.75 ft/s

Final answer:

The question is asking for the instantaneous velocity of a car at t = 1 second, which would normally be found by differentiating the position function. However, due to potential typos in the provided equation, the instantaneous velocity cannot be calculated directly.

Explanation:

The problem asks for the instantaneous velocity of the car at time t = 1 second. To find the instantaneous velocity, we would typically take the derivative of the position function with respect to time. However, the given equation v = 3(h+1)2.5 + 580h - 3 ave 10h appears to have some issues, possibly due to typos, and cannot be processed as is. In general, if the average velocity function over time h was given correctly, we would evaluate the derivative of that function at h = 0 to find the instantaneous velocity at t = 1 second.

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