What is the value of x? (7x-8) (6x+11)

1814400 ways can 8 students be assigned a seat in a classroom if there are 10 seats in a row.

A permutation is a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangement.

[tex]nP_{r} =\frac{n!}{(n-r)!}[/tex]

n=Total number of objects

r=Selected number of objects

Given,

There are ten number of seats

n=10

We have to arrange 8 students so r=8.

We need to arrange eight students in ten seats in a row.

So n=10, r=8

[tex]10P_{8} =\frac{10!}{(10-8)!}[/tex]

10P₈=10!/2!

=10×9×8×7×6×5×4×3×2/2

=10×9×8×7×6×5×4×3

=1814400

Hence in 1814400 ways can 8 students be assigned a seat in a classroom if there are 10 seats in a row.

To learn more on Permutation click:

https://brainly.com/question/1216161

#SPJ5

Final answer:

To solve the equation 4kx+10kx=7 for x, combine like terms to get 14kx = 7, then isolate x by dividing both sides by 14k, resulting in x = 1 / (2k).

Explanation:

The question asks: what is 4kx+10kx=7 solve for x. To solve this equation for x, we first need to combine like terms. We combine 4kx and 10kx to get 14kx. The equation then becomes 14kx = 7. To isolate x, we divide both sides of the equation by 14k. This gives us x = 7 / (14k). It simplifies further to x = 1 / (2k). Therefore, the solution to the equation is x = 1 / (2k).

The problem can be solved using the Pythagorean theorem. The lengths of the legs of the triangle are calculated as 15 inches for the shorter leg and 21 inches for the longer leg.

In solving this mathematical problem, we can employ the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides- This theorem is normally written as a² + b² = c². We can let one leg of the right triangle be 'a', the other leg be 'a+6' (since one leg is 6 inches longer than the other), and the hypotenuse is 25 inches. From the equation, we substitute a and b with the values and get:

a² + (a + 6)² = 25²

This equation is solved to get the lengths of the legs. Solving results in 'a' being 15 inches (the shorter leg) and 'a+6' equals to 21 inches (the longer leg).

https://brainly.com/question/28361847

#SPJ2

56.25 / 75 = 0.75 for each can

0.75 *3 = $2.25 for 3 cans

The depth of the water is increasing at a rate of approximately is 0.14 ft/min

To determine how fast the depth of the water is increasing when the water is 13 feet deep, we need to relate the volume of the water in the conical tank to its depth. We can use related rates and the geometry of the cone.

Given:

- The radius of the tank at the top R = 10 feet

- The height of the tank H = 27 feet

- The rate of water flow into the tank [tex](\(\frac{dV}{dt}\))[/tex] = 10 ft[tex]\(^3\)/min[/tex]

- The depth of the water h = 13 feet

First, let's find the relationship between the radius r of the water's surface at depth h.

Since the water forms a smaller cone similar to the tank, we can use the concept of similar triangles:

[tex]\[\frac{r}{h} = \frac{R}{H} \implies \frac{r}{h} = \frac{10}{27} \implies r = \frac{10}{27}h\][/tex]

Next, we use the volume formula for a cone:

[tex]\[V = \frac{1}{3} \pi r^2 h\][/tex]

Substitute [tex]\(r = \frac{10}{27}h\):[/tex]

[tex]\[V = \frac{1}{3} \pi \left( \frac{10}{27}h \right)^2 h = \frac{1}{3} \pi \frac{100}{729} h^3 = \frac{100\pi}{2187} h^3\][/tex]

Differentiate both sides with respect to t:

[tex]\[\frac{dV}{dt} = \frac{100\pi}{2187} \cdot 3h^2 \frac{dh}{dt}\][/tex]

Simplify:

[tex]\[\frac{dV}{dt} = \frac{300\pi}{2187} h^2 \frac{dh}{dt}\][/tex]

Given [tex]\(\frac{dV}{dt} = 10 \) ft\(^3\)/min[/tex], and [tex]\(h = 13\) ft:[/tex]

[tex]\[10 = \frac{300\pi}{2187} \cdot (13)^2 \cdot \frac{dh}{dt}\][/tex]

Solve for [tex]\(\frac{dh}{dt}\):[/tex]

[tex]\[10 = \frac{300\pi}{2187} \cdot 169 \cdot \frac{dh}{dt}\][/tex]

[tex]\[10 = \frac{50700\pi}{2187} \cdot \frac{dh}{dt}\][/tex]

[tex]\[\frac{dh}{dt} = \frac{10 \cdot 2187}{50700\pi}\][/tex]

[tex]\[\frac{dh}{dt} = \frac{21870}{50700\pi}\][/tex]

[tex]\[\frac{dh}{dt} \approx \frac{21870}{159252} \approx \frac{1}{7.29} \approx 0.137 \text{ ft/min}\][/tex]

Therefore, the depth of the water is increasing at a rate of approximately: [tex]\[\boxed{0.14 \text{ ft/min}}\][/tex]

kims sisters age = x

 kim = 2x

A) 2x +x = 36

B) 2x+ x = 36

3x =36

x = 36/3

x = 12

kim's sister is 12

kim is 24

Answer:

(1, -4) and (-11, 56)

The total number of different license plates that can be manufactured in this state is 676,000. This is calculated by multiplying the 676 combinations of letters by the 1,000 combinations of numbers.

To find out how many different license plates can be manufactured in this state,

Therefore, the total number of combinations for the letters is:

The total number of combinations for the numbers is:

By multiplying these together, we get the total number of license plates:

Therefore, there can be 676,000 different license plates manufactured in this state.

To simplify expressions with negative exponents, rewrite the negative exponent as the reciprocal of the base raised to the positive exponent.

When simplifying expressions with negative exponents, you can use the rule that states a negative exponent can be rewritten as the reciprocal of the base raised to the positive exponent. For example, x^-3 can be rewritten as 1/x^3. You can use this rule with negative exponents in the numerator or denominator, as well as with negative exponents inside parentheses. Here’s an example:

8x^-2 / (2y^-3) = 8 / (2y^3x^2)

https://brainly.com/question/28189657

#SPJ12

Jessie's total bus ride time, represented by y, is 5 minutes longer than [tex]\frac{2}{3}[/tex] of Robert's bus ride time, which is represented by x, leading to the equation y = ([tex]\frac{2}{3}[/tex])x + 5.

Jessie's bus ride to school is 5 minutes longer than [tex]\frac{2}{3}[/tex] the time of Robert's bus ride. Given that Jessie's time riding the bus is represented by y, and Robert's time riding the bus is represented by x, the equation to represent this situation is:

y = ([tex]\frac{2}{3}[/tex])x + 5.

This equation indicates that if you take [tex]\frac{2}{3}[/tex] of Robert's ride time (x) and then add 5 minutes, you'll get Jessie's bus ride time (y).

Answer:

919.5

Step-by-step explanation:

Answer:

Two lines are perpendicular then they cut at right angles to each other.

But, when two lines are parallel then they can never meet to each other.

Step-by-step explanation:

We are given that Martin drew a pair of perpendicular lines and a pair of a parallel lines.

We have to find which statement best describe these statements best compares the pairs of perpendicular and parallel lines.

We know that

Perpendicular lines: That lines which  intersect at right angles to each other.

Parallel lines: That lines which can never meet when the lines produced infinitely.

Hence, a pair of perpendicular lines intersect at right angles and a pair of parallel lines never meet to each  other.

Final answer:

To find out how many weights the personal trainer can purchase, subtract the cost of the weight bench from the budget and divide the remaining amount by the cost of each weight. The personal trainer can purchase 15 weights within the given budget.

Explanation:

To find out how many weights the personal trainer can purchase, we need to subtract the cost of the weight bench from the budget and divide the remaining amount by the cost of each weight.

Step 1: Subtract the cost of the weight bench ($500) from the budget ($860): $860 - $500 = $360.

Step 2: Divide the remaining amount ($360) by the cost of each weight ($24): $360 ÷ $24 = 15.

The personal trainer can purchase 15 weights within the given budget.

This budgeting approach demonstrates a systematic way for the personal trainer to allocate funds effectively, ensuring that both essential equipment and a sufficient quantity of weights can be acquired. By following these steps, the trainer maximizes the utility of the available budget, making informed decisions to support an efficient and well-equipped training environment.