A football player carrying the ball runs straight ahead at the line of scrimmage and directly into a wall of defensive linemen. The ball carrier has an initial speed of 7.68 m/s and is stopped in a time interval of 0.202 s. Find the magnitude and direction of his average acceleration.
Final answer:
The magnitude of the average acceleration the football player experiences is 38.02 m/s², and the direction of the acceleration is backward, towards the line of scrimmage.
Explanation:
To calculate the magnitude and direction of the average acceleration experienced by the football player, we use the following kinematic equation:
a = (v_f - v_i) / t
Where:
v_f is the final velocityv_i is the initial velocityt is the time taken to stopGiven:
v_i = 7.68 m/s (Initial speed of the player)v_f = 0 m/s (The player comes to a stop)t = 0.202 s (Time interval)Now we can plug these values into our equation to find a:
a = (0 - 7.68 m/s) / 0.202 s
a = -7.68 m/s / 0.202 s
a = -38.02 m/s2
The negative sign indicates that the acceleration is in the opposite direction of the player's initial motion. Since the player was moving forward and came to a stop, the acceleration is directed backward, towards the line of scrimmage.
You are in a hot air balloon, 100 m above the flat Texas plains. You look out toward the horizon.
How far out can you see-that is, how far is your horizon? The Earth's radius is about 6400 km.
Express your answer using one significant figure.
Actually we could create a triangle in this case. The hypotenuse is the radius of Earth plus the height above the earth, while the two sides are the radius of Earth and the scope of vision.
That is:
(6,400,000 m + 100 m)^2 = (6,400,000 m)^2 + b^2
b^2 = 1,280,010,000
b = 35,777.23 m
You can see 35,777.23 m far.
The specific heat of ice is 0.5 calories/gram°C. 20 grams of ice will require _____ calories to raise the temperature 1°C. 0.5 1.0 5.0 10
Answer:
10 calories
Explanation:
The thermal energy needed to increase the temperature of a substance is given by
[tex]Q=m C \Delta T[/tex]
where
m is the mass of the substance
C is the specific heat of the substance
[tex]\Delta T[/tex] is the increase in temperature
In this problem, the mass of the ice is m=20 g, the specific heat is C=0.5 calories/gram°C, and the increase in temperature is [tex]\Delta T=1^{\circ}[/tex]. Therefore, the energy required is
[tex]Q=(20 g)(0.5 cal/g^{\circ}C)(1^{\circ}C)=10 cal[/tex]
Which term does not describe a conversion between states of matter?
A student at a window on the second floor of a dorm sees her physics professor walking on the sidewalk beside the building. she drops a water balloon from 18.0 meters above the ground when the professor is 1.00 meter from the point directly beneath the window. if the professor is 1.70 meters tall and walks at a rate of 0.450 m/s, does the balloon hit her? if not, how close does it come? (10 pts)
According to the calculations, the water balloon does not hit the professor. It comes closest to her when it is approximately 0.316 meters away.
Explanation:In order to determine if the water balloon hits the professor, we need to calculate the time it takes for the balloon to reach the ground. The time can be found using the equation:
t = \sqrt{\frac{2h}{g}}
Where t is the time, h is the height (18.0 meters), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we find that it takes approximately 1.52 seconds for the balloon to reach the ground.
We also need to calculate the horizontal distance the professor walks in that time. The distance can be found using the equation:
d = vt
Where d is the distance, v is the velocity (0.450 m/s), and t is the time (1.52 seconds). Plugging in the values, we find that the professor walks approximately 0.684 meters during that time.
Therefore, since the professor is 1.00 meter from the point directly beneath the window, the balloon does not hit her. It comes closest to her when it is 0.316 meters away from her.
A 1200-kg car starts from rest and accelerates with constant acceleration, traveling 200 m in 9.00 s. what is the force of the road on the car during this acceleration?
First calculate the acceleration using the formula:
d = v0 t + 0.5 a t^2
where d is distance = 200 m, v0 = initial velocity = 0, t is time = 9s, a = acceleration (?)
200 = 0 + 0.5 * a * 9^2
a = 4.94 m/s^2
Force is mass times acceleration, therefore:
F = m a = 1200 kg * 4.94 m/s^2
F = 5,925.93 N
To calculate the force exerted on the car by the road, we first find the acceleration of the car using the formula: a = Δv/Δt. After calculating the acceleration to be approximately 9.88 m/s², we then use Newton's second law, F = ma, which results in the force being approximately 11856 N.
Explanation:In physics, to find the force exerted, we need to apply Newton's second law of motion which states that the force acting on an object is equal to the mass of that object multiplied by its acceleration (F = ma). Given the mass of the car (1200 kg) and the need to find acceleration, we can use the formula for acceleration: a = Δv/Δt, where Δv is the change in velocity and Δt is the change in time. Initially, the car is at rest so initial velocity is zero and the final velocity can be calculated as v = a*t. Now substituting the values into the equation, 200m = 0.5*a*(9s)^2, we find acceleration a=9.88 m/s². Then, applying Newton's second law F = 1200kg * 9.88m/s² we get the force exerted on the car by the road is approximately 11856 N.
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How many unique values of x solve x2 + 4x + 4 = 0?
The electrolyte in a typical wet storage cell or battery is a mixture of water and
Answer:
Sulfuric acid.
Explanation:
A battery is a device which contains one or more electrical chemical cells which are connected in a electrical circuit to power the objects like flashlight, speaker, etc.
When a battery is supply electric power then its positive terminal classified as cathode and negative as anode.
And as we know that the electrolyte in a typical wet storage battery or cell contains 67% water and 33% of sulfuric acid.
If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal force.
Answer:
[tex]108\ N[/tex]
Explanation:
Mass of object, [tex]m=1.50\ kg.[/tex]
Length of string, [tex]r=0.50\ m.[/tex]
Tangential speed, [tex]v_t=6.0\ m/s.[/tex]
Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.
Here , object moves along the ends of string. Therefore, radius is equal to length of string.
[tex]F=\dfrac{m \times v_t^2}{r}.[/tex]
Putting values of m,v and r in above equation.
We get, [tex]F=\dfrac{1.50\times (6.0)^2}{0.50} \ N=108 \ N.[/tex]
Hence, this is the required solution.
"if a stream flow measures 12 meters in 60 seconds, what is the stream's average rate of flow?"
Identify the energy transformations in the following actions.
*Turning on a space heater
*Dropping an apple core into the garbage
*Climbing up a rope ladder
*Starting a car
*Turning on a flashlight
Answer:
a)Mechanical to heat energy.
b)potential to kinetic energy
c)kinetic to potential energy
d)kinetic to heat energy.
While standing at the edge of the roof of a building, you throw a stone upward with an initial speed of 5.55 m/s. The stone subsequently falls to the ground, which is14.7 m below the point where the stone leaves your hand. At what speed does the stone impact the ground? How much time is the stone in the air? Ignore air resistance and take g = 9.81 m/s2.
What is the Impact Speed:____m/s
What is the Elapsed Time:____s
A(n) ____ stores data as a trail of tiny pits or dark spots on its surface. select one:
a. hard disk
b. magnetic storage device
c. optical storage device
d. solid state storage device
Shakina and Juliette set the car's initial velocity to zero and set the acceleration to +1.2 m/s2, then clicked "start." Answer the following questions.
What is the car's displacement between 0 and 10.0 s?
What was the total distance traveled by the car during this time interval?
a(n) ? can be used to represent the direction and strength of a force
Final answer:
A vector is used to represent the direction and strength of a force. Force is a vector quantity depicted in diagrams with arrows indicating magnitude and direction, with positive and negative vectors designating direction relative to a reference point.
Explanation:
A vector can be used to represent the direction and strength of a force. Force is a vector quantity, which means it has both a magnitude (strength) and a direction. For example, to represent a force of 20 N towards the East, you would draw an arrow 10 cm long towards the right if using a scale of 1 cm = 2 N. The direction of the force can be indicated using compass points or arrows showing the reference direction, and negative vectors represent forces in the opposite direction of the chosen positive reference direction.
The study of forces is known as dynamics, which considers how forces act on objects to cause motion. Vectors are used to visually represent forces in diagrams and can be added together using the head-to-tail method or trigonometric methods to determine the resultant force when multiple forces are acting.
When multiple forces are at work, such as two people pushing on a third person in different directions, the total force acting on the person can be represented by adding the vectors to find the resultant. This addition takes into account both the magnitude and direction of each force.
If the work put into a lever is 25.0 joules and the work done by the lever is 20.0 joules, what is the efficiency of the lever? 100% because energy must be conserved. 80.0% 45.0% 5.0%
Answer: The efficiency of the lever is 80%.
Explanation:
An efficiency is the measure of how much wok or energy is conserved in a given process. It is defined as the ratio of output work and input work. If the energy is totally conserved in a process, the the percentage efficiency will be 100%.
Mathematically,
[tex]\%\text{ efficiency}=\frac{W_{out}}{W_{in}}\times 100[/tex]
Where,
[tex]W_{out}[/tex] = Work done by the lever = 20 J
[tex]W_{in}[/tex] = Work put in the lever = 25 J
Putting values in above equation, we get:
[tex]\%\text{ efficiency}=\frac{20}{25}\times 100\\\\\%\text{ efficiency}=80\%[/tex]
Hence, the efficiency of the lever is 80%.
10 Points.) A stone weighing 0.7 kilograms rolls down the inclined plane from position B to position A. Position A is located at sea level. The Inclined Plane is 0.25 Meters high. The difference in the gravitational potential energy of the ball between positions A and B is about___ joules. (Use PE = m × g × h, where g = 9.8 N/kg.)
Answer:
1.715 Joules
Explanation:
ΔPE = m * g * Δh = 0.7 kg * 9.8 N/kg * 0.25 m = 1.715 N*m = 1.715 J
The gravitational strength at the poles is greater than the gravitational strength at the equator. What will happen to an object when it moves from the poles to the equator?
A.Its mass will increase.
B. Its mass will decrease.
C. Its weight will increase.
D.Its weight will decrease
We must always take note that mass is an inherent property of an object. It never change unless there is change in size of the object. While weight is the product of mass and gravity, so it changes depending on the gravitational pull.
If the gravitational pull decreases as he moves from the poles to the equator, therefore its weight will decrease.
Answer:
D.Its weight will decrease
Mayan kings and many school sports teams are named for the puma, cougar, or mountain lion felis concolor, the best jumper among animals. it can jump to a height of 13.7 ft when leaving the ground at an angle of 42.7°. with what speed, in si units, does it leave the ground to make this leap? m/s
The puma, cougar, or mountain lion leaves the ground to make a leap with a speed of approximately 8.32 m/s.
Explanation:To find the speed at which the animal leaves the ground, we can use the kinematic equation for projectile motion:
[tex]\[v = \sqrt{2gh},\][/tex]
where [tex]\(v\)[/tex] is the speed, [tex]\(g\)[/tex] is the acceleration due to gravity (approximately [tex]\(9.81 \, \text{m/s}^2\))[/tex], and [tex]\(h\)[/tex] is the vertical height.
Given that the height [tex]\(h\)[/tex] is 13.7 ft, we first convert it to meters:
[tex]\[h = 13.7 \, \text{ft} \times 0.3048 \, \text{m/ft} = 4.1756 \, \text{m}.\][/tex]
Substituting [tex]\(h\)[/tex] into the equation, we have:
[tex]\[v = \sqrt{2 \times 9.81 \, \text{m/s}^2 \times 4.1756 \, \text{m}} \approx 8.32 \, \text{m/s}.\][/tex]
What best explains why a person can become sunburned by spending too much time at the beach
When you take off in a jet aircraft, there is a sensation of being pushed back into the seat. explain why you move backward in the seat—is there really a force backward on you? (the same reasoning explains whiplash injuries, in which the head is apparently thrown backward.)?
Answer:
Newton's third law of motion
Explanation:
As per Newton's third law of motion, every action has its equal and opposite reaction.
When a jet aircraft takes off it exerts a force and gains upward acceleration, the same force is applied on your body as it is moving along the jet hence this force tries to push you back into the seat.
For instance, while rowing a boat you try to apply force on water with paddles in backward direction, the same amount of force is reverted by water thus moving the boat in forward direction.
Hence Newton's third law of motion explains the phenomena.
Answer:
Newton's third law of motion
Explanation:
As per Newton's third law of motion, When two bodies interact they apply force to one another that are equal in magnitude and opposite in direction.
During the take off a jet aircraft it exerts a force and gain upward acceleration, the same amount of force is applied on our body because we are in contact with jet due to third law we pushed back into the seat..
[tex]F_1=-F_2[/tex]
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A thief plans to steal a gold sphere with a radius of 28.5 cm from a museum. if the gold has a density of 19.3 g/cm3, what is the mass of the sphere in pounds? [the volume of a sphere is v=(4/3)Ïr3.]
In 1967, new zealander burt munro set the world record for an indian motorcycle, on the bonneville salt flats in utah, with a maximum speed of 82.1 m/s. the one-way course was 8.045 km long. if it took burt 4.00 s to reach a velocity of 26.82 m/sec, how long (in seconds) did it take burt to reach his maximum speed? how far (in meters) did he travel during his acceleration? look at the equations in the last section. find acceleration first, then the time to accelerate to 82.1 m/s, then the x displacement during the time elapsed.
A blue ball is thrown upward with an initial speed of 21.8 m/s, from a height of 0.9 meters above the ground. 2.7 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 10.4 m/s from a height of 26.6 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.
To go through the basket, the ball needs to be thrown with an initial speed of approximately 25.2 m/s.
Explanation:The initial speed at which the ball needs to be thrown in order to go through the basket can be determined using the equations of projectile motion. We can break the initial velocity of the ball into its horizontal and vertical components. The horizontal component will determine the distance the ball will travel, and the vertical component will determine the height at which the ball will pass through the basket.
Using the given information, including the angle at which the ball is released and the height of the basket, we can calculate the initial speed of the ball using trigonometry and projectile motion equations. The initial speed required for the ball to go through the basket is the magnitude of the total initial velocity, which is the vector sum of the horizontal and vertical components.
The initial speed required for the ball to go through the basket is approximately 25.2 m/s.
Write an expression for the magnitude of the normal force, fn, acting on the block, in terms of f2 and the other variables of the problem. assume that the surface it rests on is rigid.
The magnitude of the normal force, fn, for a block on a horizontal rigid surface with a gravitational force fg of 40 N is equal to the gravitational force, making fn also 40 N.
Explanation:The magnitude of the normal force, fn, acting on a block on a horizontal surface is equal to the weight of the block when the surface is rigid and there are no other vertical forces except gravity. If we denote the gravitational force as fg, which in this case is 40 N, and given that there are no additional vertical forces and the surface is horizontal, the normal force will balance the gravitational force. Therefore, we have fn = fg, so the normal force fn is also 40 N.
In scenarios where there are additional vertical forces or the surface is not horizontal, the normal force is calculated by summing all vertical forces, where forces pushing the block into the surface increase the normal force and forces lifting the block reduce the normal force. However, in this example, such complexities are absent, making the calculation straightforward.
Estimate by what factor a person can jump farther on the moon as compared to the earth if the takeoff speed and angle are the same. the acceleration due to gravity on the moon is one-sixth what it is on earth.
By six times, a person should jump farther on the moon as compared to the earth if the takeoff speed and angle are the same.
The height of the earth can be computed using the third equation of motion. The third equation of motion, referred to as one of the kinematic equations, relates the final velocity, initial velocity, acceleration, and displacement of an object.
The height of the earth is given as:
[tex]v^2-u^2= 2gH_e\\v^2 = 2\times9.8\timesH_e\\H_e = v^2/2g[/tex]
The height of the moon is given as:
[tex]v^2-u^2 = 2(g/6)H_m\\v^2 = g/3H_m\\H_m = 3v^2/g[/tex]
The ratio of both heights is given as:
[tex]H_m/H_e = 3v^2/g/(v^2/2g)\\H_m/H_e = 6\\H_m = 6H_e[/tex]
Hence, by six times, a person should jump farther on the moon as compared to the Earth if the takeoff speed and angle are the same.
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A person can jump about six times further on the Moon compared to Earth given the same initial angle and speed. This is because the acceleration due to gravity on the moon is one-sixth that of Earth, resulting in a weaker gravitational pull.
Explanation:The topic in question involves the concept of gravitational forces and its influence on the jump length of a person on Earth versus the Moon. The acceleration due to gravity on the Moon is about one-sixth that of Earth, meaning the gravitational force is much weaker. Therefore, if a person jumps with the same speed and angle on the moon as on Earth, they would be able to jump approximately six times farther due to the weaker gravitational pull.
For better understanding, consider this example. If a person jumps and covers a certain distance on Earth in a given time, the same person would be airborne six times as long on the Moon if they jumped with the same velocity. This is due to the inverse relationship between the time of flight (airborne time) and acceleration due to gravity (g). Since g for the Moon is one-sixth that of Earth, a person can jump about six times further.
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Which clue can be used to identify a chemical reaction as a replacement reaction?
The reaction has two reactants with ions that seem to switch places.
The reaction has a single reactant that changes into two or more products.
The reaction involves oxygen reacting with a hydrocarbon and giving off heat.
The reaction involves a single product forming from two or more reactants.
Answer: Option (a) is the correct answer.
Explanation:
When only one element gets displaced upon chemical reaction between a compound and an element then it is known as a single replacement reaction.
For example, [tex]Fe_{2}O_{3}(s) + 2Al(s) \rightarrow Al_{2}O_{3}(s) + 2Fe(l)[/tex]
On the other hand, when two compounds chemically react together and their ions get replaced by each other then it is known as a double replacement reaction.
For example, [tex]AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)[/tex]
Thus, we can conclude that the reaction which has two reactants with ions that seem to switch places clue can be used to identify a chemical reaction as a replacement reaction.
How much energy does the electron have initially in the n=4 excited state?what is the change in energy if the electron from part a now drops to the ground state?
Answer:
Energy the electron have initially [tex]E_4=-0.85 \rm ev[/tex],
The change in energy if the electron from part a now drops to the ground state is [tex]12.75\rm ev[/tex]
Explanation:
Given information:
Electron have initially in the n=4 excited state,
We know,
Energy of an electron is given by,
[tex]E_n=-13.6\rm ev\times\frac{z^2}{n^2}[/tex]
On substituting n=4 for excited state energy,
[tex]E=-13.6\rm ev\times\frac{1^2}{4^2}=-0.85\rm ev[/tex]
Change in energy from excited state to ground state,
For ground state n=1,
[tex]E=-13.6\rm ev\times z^2\times( \frac{1}{(n_2)^2}-\frac{1}{(n_1)^2})[/tex]
On substituting [tex]n_1=1[/tex],[tex]n_2=4[/tex],
[tex]\Delta E=E_4-E_1=-13.6\rm ev\times 1^2\times( \frac{1}{(4)^2}-\frac{1}{(1)^2})=12.75ev[/tex]
Hence, energy the electron have initially [tex]E_4=-0.85 \rm ev[/tex],
NOTE:- [tex]1\rm ev=-1.602\times 10^{-19}joule[/tex]
Energy the electron have initially [tex]E_4=-0.85 \rm ev[/tex],
The change in energy if the electron from part a now drops to the ground state is [tex]12.75\rm ev[/tex]
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the quality and pitch of a note depends respectively on?
The pitch of a note is determined by its frequency, with higher frequencies leading to higher pitches. The quality, or timbre, of a note depends on the shape of the waveform, influenced by various frequencies and phases of sound waves. These aspects combine to give each note its unique character.
Explanation:The quality and pitch of a note depend on different aspects of sound waves. The pitch of a note is primarily determined by its fundamental frequency, which is measured in hertz (Hz). A higher frequency results in a higher pitch, making a note sound “sharper” or higher on the musical scale. For example, the piano note middle C has a frequency of 261.63 Hz. Musical intervals, like the octave, are based on the doubling of frequencies.
On the other hand, the quality or timbre of a note depends on the waveform's shape, which is influenced by the frequencies and phases of other sound waves produced alongside the fundamental frequency. This complexity allows us to distinguish between different instruments playing the same note due to the variety in waveforms. The timbre is what makes the same note played on a trumpet distinctly different from the same note played on a clarinet.
In summary, while pitch is a direct correlation to the frequency of sound, quality or timbre involves the intricate interplay of multiple frequencies and their waveform shapes, contributing to the unique character of each musical note.
A place kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. when kicked, the ball leaves the ground with a speed of 23.4 m/s at an angle of 50.0° to the horizontal. (a) by how much does the ball clear or fall short of clearing the crossbar