SOMEONE PLEASE HELP ME ASAP!!!
1. In recent years, there has been considerable discussion about the appropriateness of the body shapes and proportions of the Ken and Barbie dolls. These dolls are very popular, and there is some concern that the dolls may be viewed as having the "ideal body shape," potentially leading young children to risk anorexia in pursuit of that ideal. Researchers investigating the dolls' body shapes scaled Ken and Barbie up to a common height of 170.18 cm (5'7") and compared them to body measurements of active adults. Common measures of body shape are the chest (bust), waist, and hip circumferences. These measurements for Ken and Barbie and their reference groups are presented in the table below.
Ken Barbie
Chest Waist Hips | Chest Waist Hips
Doll: 75.0 56.5 72.0 | 82.3 40.7 72.7
Human x-bar: 91.2 80.9 93.7 | 90.3 69.8 97.9
Human S: 4.8 9.8 6.8 | 5.5 4.7 5.4
Suppose that the researchers' scaled-up dolls suddenly found themselves in the human world of actual men and women.
Convert Ken's chest, waist, and hips measurements to z-scores. Which of those measures appears to be the most different from Ken's reference group (human males)? Justify your response with an appropriate statistical argument.
2. In recent years, there has been considerable discussion about the appropriateness of the body shapes and proportions of the Ken and Barbie dolls. These dolls are very popular, and there is some concern that the dolls may be viewed as having the "ideal body shape," potentially leading young children to risk anorexia in pursuit of that ideal. Researchers investigating the dolls' body shapes scaled Ken and Barbie up to a common height of 170.18 cm (5'7") and compared them to body measurements of active adults. Common measures of body shape are the chest (bust), waist, and hip circumferences. These measurements for Ken and Barbie and their reference groups are presented in the table below.
Ken Barbie
Chest Waist Hips | Chest Waist Hips
Doll: 75.0 56.5 72.0 | 82.3 40.7 72.7
Human x-bar: 91.2 80.9 93.7 | 90.3 69.8 97.9
Human S: 4.8 9.8 6.8 | 5.5 4.7 5.4
Suppose that the researchers' scaled-up dolls suddenly found themselves in the human world of actual men and women.
Convert Barbie's chest, waist, and hips measurements to z-scores. Do these z-scores provide evidence to justify the claim that the Barbie doll is too thin of a representation of adult women? Justify your response with an appropriate statistical argument.
3. Jill scores 680 on the mathematics part of the SAT. The distribution of SAT scores in a reference population is normally distributed with the mean 500 and standard deviation 100. Jack takes the ACT mathematics test and scores 27. ACT scores are normally distributed with mean 18 and standard deviation 6.
Find the standardized scores for both students.
4. Jill scores 680 on the mathematics part of the SAT. The distribution of SAT scores in a reference population is normally distributed with the mean 500 and standard deviation 100. Jack takes the ACT mathematics test and scores 27. ACT scores are normally distributed with mean 18 and standard deviation 6.
Assuming that both tests measure the same kind of ability, who has the higher score, and why?
5. A lunch stand in the business district has a mean daily gross income of $420 with a standard deviation of $50. Assume that the daily gross income is normally distributed.
If a randomly selected dat has a gross income of $520, then how many standard deviations away from the mean is that day's gross income?
Write an equation of the circle with center , −45 and radius 6 .
Factor out the greatest common factor. 2s4 - 4s2
An article considered the use of a uniform distribution with A = 0.20 and B = 4.25 for the diameter X of a certain type of weld (mm).
Using the formula f(x) = 1/(b-a), where B is 4.25 and A is 0.20. Substituting these values to the formula, we get f(x) = 1/(4.25-0.2) = 0.24691358. Therefore, we get the answer f(x) = 0.24691358, 0.20<x<4.25. Otherwise, it is 0.
Using the formula f(x) =1/(b-a)
B is 4.25 and A is 0.20.
Put these values to the
We get f(x) = 1/(4.25-0.2) = 0.24691358.
f(x)= 0.24691358, 0.20<x<4.25.
Further Explanation:
uniform distribution:
A uniform distribution, some of the time otherwise called a rectangular circulation, is a dispersion that has steady likelihood. The likelihood thickness work and combined circulation work for a nonstop uniform appropriation on the interim are (1) (2).
we use uniform distribution:
The uniform circulation gets its name from the way that the probabilities for all results are the equivalent. Rather, every result is similarly prone to happen. Not at all like a chi-square dissemination, there is no skewness to a uniform dispersion. Accordingly, the mean and middle concur.
diameter:
In geometry, a breadth of a circle is any straight line portion that goes through the focal point of the circle and whose endpoints lie on the circle. It can likewise be characterized as the longest harmony of the circle. The two definitions are likewise substantial for the measurement of a circle.
formula of diameter:
In the event that you know the zone of the circle, separate the outcome by π and locate its square root to get the sweep; at that point increase by 2 to get the distance across. This returns to controlling the equation for finding the zone of a circle, A = πr2, to get the distance across. You can change this into r = √(A/π) cm.
Subject: mathematics
Level: High School
Keywords: uniform distribution, we use uniform distribution, diameter, formula of diameter.
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Which graph describes the open sentence –1 ≤ n + 2 ≤ 6?
A. Number line showing range from negative four to four. There are two rays on the graph. The first has a right end point with a closed dot at negative two with a ray pointing left past negative four. The second has a left end point with an open circle at three with a ray pointing right past four.
B. Number line -5 to +5 in single-integer increments - assessment graphic
C. Number line showing range from negative three to three The left end point is an open circle halfway between negative one and zero. There is a closed dot at three, and a ray points past three.
D. Number line showing range from negative eight to eight. There are two rays on the graph. The first has a right end point with an open circle halfway between negative six and negative four with a ray pointing left past negative eight. The second has a left end point with an open circle at four with a ray pointing right past eight.
The value of n≥-3 and n≤4 describes the open sentence -1≤n+2≤6
What will be the range of n for -1 ≤ n+2 ≤ 6 ?If we follow the above condition for the different values of n
At value of n=-3 we will get n+2=-3+2=-1
similarly at n=-2 we will get n+2=-2+2=0
and at n=-1 we will get n+2=-1+2=1
all three (-1,0,1) follow the condition -1 ≤ n+2
Similarly at n=(0,1,2,3,4) condition n+2 ≤ 6 is followed
Hence value of n≥-3 and n≤4 describes the open sentence -1≤n+2≤6
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The correct graph is option C.
Sure, let's break down the steps to understand why option C is the correct graph for the open sentence [tex]\(-1 \leq n + 2 \leq 6\)[/tex]:
1. Identify the Middle Term: The middle term in the open sentence is [tex]\(n + 2\)[/tex]. This means our focus is on the expression [tex]\(n + 2\)[/tex].
2. Understand the Inequality: The inequality [tex]\( -1 \leq n + 2 \leq 6\)[/tex] can be understood as "n + 2 is greater than or equal to -1 and less than or equal to 6".
3. Subtract 2 from Each Part: To isolate [tex]\(n\)[/tex], subtract 2 from each part of the inequality:
[tex]\[ -1 - 2 \leq n + 2 - 2 \leq 6 - 2 \][/tex]
Which simplifies to:
[tex]\[ -3 \leq n \leq 4 \][/tex]
4. Draw the Number Line: Draw a number line ranging from -3 to 4, inclusive.
5. Plot the Endpoints: On the number line, mark endpoints at -3 and 4.
6. Determine the Endpoints: Since the inequality includes "equal to" signs, the endpoints should be marked with closed dots (indicating inclusion).
7. Determine the Direction of the Ray: Since the inequality does not include strict inequality signs (< or >), the rays should extend in both directions from the endpoints.
8. Indicate the Rays: Draw rays to the left of -3 and to the right of 4, indicating the range extends indefinitely in both directions.
9. Mark the Open Circle: Since the inequality involves strict inequality at -1 and 6, mark an open circle at the points halfway between -1 and -3, and 6 and 4, respectively.
10. Verify the Result: The resulting graph should have closed dots at -3 and 4, indicating the range includes those values, and open circles at -1 and 6, indicating exclusion.
Option C correctly represents these steps, making it the correct graph.
The graph is given below:
The average rate of change of the function f(x)=4x^3 + 4 over the interval [66,88] is
Assume that you pay $2,849.84 in state property taxes every year. If your property has an assessed value of $41,302, what is your state’s property tax rate? a. 0.077 b. 0.032 c. 0.014 d. 0.069
Answer:
Therefore, The correct option is D. 0.069
Step-by-step explanation:
Amount of the money paid in the state property taxes every year = $2849.84
The property owned has an assessed value.
Now, the assessed value of the property is $41302
We need to find the state's property tax rate.
[tex]\text{So, State's property tax rate = }\frac{\text{state's property tax}}{\text{assessed value}}\\\\\text{State's property tax rate = }\frac{2849.84}{41302}\approx 0.069[/tex]
Therefore, The correct option is D. 0.069
Given equal probabilities of the birth of a boy or girl, what is the probability that a group of four siblings includes all boys? all girls? all boys or all girls?
The probability of a group of four siblings being all boys or all girls is 1/8, with each individual probability being 1/16.
Probability of All Boys:
Probability of a boy birth: 1/2
Probability of all boys among 4 siblings:
(1/2) × (1/2) × (1/2) × (1/2) = 1/16
Probability of All Girls:
Probability of a girl birth: 1/2
Probability of all girls among 4 siblings:
(1/2) × (1/2) × (1/2) × (1/2) = 1/16
Probability of All Boys or All Girls: Since these are mutually exclusive events, add their probabilities:
1/16 (all boys) + 1/16 (all girls) = 1/8
How to prove system of nonlinear equations has finite solutions?
Identify the degree of the polynomial 6xy2 − xy + 8 + 12y.
If cats prowl, mice will scatter. Mice are scattering
Which choices are equivalent to the fraction below? Check all that apply.
Write an equation in point-slope form of the line through point J(-8,10) with slope -5.
A. y + 10 = -5(x + 8)
B. y - 10 = 5(x + 8)
C. y - 10 = -5(x + 8)
D. y - 10 = -5(x - 8)
The gasoline prices in seven states are $1.96, $2.09, $1.79, $1.61, $1.75, 2.11, and $1.84 what is the median gas price and the difference of the first and third quartiles
Answer:
Median = $1.84
The difference of the first and third quartiles = $0.34
Step-by-step explanation:
Median
How to calculate the median of a small data or ungrouped data;
1. Arrange the data in ascending or descending order.
2. Choose the middle value. The middle value can be a single value or two value. If the middle value is a single value, then, that value is the median but if the middle values are two, the mean of the two middle values is evaluated to get the median.
Arranging the gasoline prices given in ascending order;
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The middle value is a single number $1.84 in bold. Therefore, the median is $1.84.
Median = $1.84
First (Lower) Quartile
To calculate for the First (Lower) quartile,
1. Arrange the data give in ascending order.
2. The First (Lower) quartile, Q1 is then calculated using;
[tex]Q1 =\frac{1}{4} (n + 1)^{th}[/tex] term
where n is the total number of terms of the data. In the given question, the total number of terms, n = 7
[tex]Q1 =\frac{1}{4} (7 + 1)^{th}[/tex] term
[tex]Q1 =\frac{8}{4}^{th}[/tex] term
Q1 = 2nd term
3. Select the 2nd term of the given data already arranged in ascending order.
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The First Quartile, Q1 = $1.75
Third (Upper) Quartile
To calculate for the third (upper) quartile,
1. Arrange the data give in ascending order.
2. The third (upper) quartile (Q3) is then calculated using;
[tex]Q3 =\frac{3}{4} (n + 1)^{th}[/tex] term
where n is the total number of terms. In the given question, the total number of terms, n = 7
[tex]Q3 =\frac{3}{4} (7 + 1)^{th}[/tex] term
[tex]Q3 =\frac{24}{4}^{th}[/tex] term
[tex]Q3 = 6^{th} term[/tex]
3. Select the [tex]6^{th} term[/tex] of the given data already arranged in ascending order.
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The third (upper) quartile Q3 = $2.09
The difference between the first and third quartiles is called interquartile range.
Now, calculating the difference of the first and third quartiles
Interquartile Range = Q3 - Q1
$2.09 - $1.75 = $0.34
The difference of the first and third quartiles, Interquartile Range = $0.34
Question Down Below...
Cameron bought four begonias in 6-in pots and a $19 fern at a fundraiser. he spent a total of $63. how much is each begonia?
The cost of each begonia is $11 at a fundraiser.
What is the equation?The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.
Let's assume the cost of each begonia x.
Since Cameron bought four begonias, the total cost of the begonias was 4x.
The total cost of the plants was the cost of the begonias plus the cost of the fern, or 4x + 19.
As per the question, the total cost was $63, so we can set up the equation:
4x + 19 = 63
To solve for x, we need to get x by itself on one side of the equation. We can do this by subtracting 19 from both sides:
4x + 19 - 19 = 63 - 19
This simplifies to:
4x = 44
To solve for x, we need to divide both sides by 4:
4x / 4 = 44 / 4
This simplifies to:
x = 11
Therefore, each begonia cost $11.
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Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 = 16
The local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] are -18 at points (0, 4) and (0, -4).
To find the local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] using Lagrange multiplier techniques, we need to set up the Lagrangian function:
[tex]\[ L(x, y, \lambda) = f(x, y) - \lambda(g(x, y) - c) \][/tex]
where [tex]\( g(x, y) \)[/tex] is the constraint, c is a constant, and [tex]\( \lambda \)[/tex] is the Lagrange multiplier.
In this case, [tex]\( g(x, y) = x^2 + y^2 \)[/tex] is the constraint, and c = 16 .
So, the Lagrangian function is:
[tex]\[ L(x, y, \lambda) = x^2 - y^2 - 2 - \lambda(x^2 + y^2 - 16) \][/tex]
Now, find the partial derivatives of L with respect to ( x, y, ) and[tex]\( \lambda \)[/tex] and set them equal to zero to find critical points:
[tex]\[ \frac{\partial L}{\partial x} = 2x - 2\lambda x = 0 \]\[ \frac{\partial L}{\partial y} = -2y - 2\lambda y = 0 \]\[ \frac{\partial L}{\partial \lambda} = x^2 + y^2 - 16 = 0 \][/tex]
Solving the system of equations, we get two critical points:
1. When [tex]\( x = 0, y = 4, \lambda = -\frac{1}{4} \)[/tex]
2. When [tex]\( x = 0, y = -4, \lambda = -\frac{1}{4} \)[/tex]
Now, evaluate f(x, y) at these critical points:
1. f(0, 4) = 0 - 16 - 2 = -18
2. f(0, -4) = 0 - 16 - 2 = -18
Therefore, the local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] are -18 at points (0, 4) and (0, -4).
Anthony has 115 book in his room .He is storing them in boxes .Each box holds 17 book .How many boxes does Anthony need?
Anthony need 7 boxes to hold 115 books.
What is Division method?
Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.
For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
Given that;
Anthony has 115 books in his room.
And, He is storing them in boxes.
Each box holds 17 books.
Now,
Since, Total number of books = 115
And, Each box holds 17 books.
Hence, Number of boxes to cover 115 books = 115 ÷ 17
= 7
Since, We get the quotient after divide 115 by 17 is 13.
So, Anthony use 1 box extra to keep 13 remaining books.
Thus, Anthony need 7 boxes to hold 115 books.
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A student has some 1 bills and $5 bills in his wallet. he has a total of 15 bills that are worth $47. how many of each type of bill does he have?
Answer:
B. seven $1 bills and eight $5 bills.
Step-by-step explanation:
n = number of $1 bills
m = number of $5 bills
Given:
n + m = 15
n($1) + m($5) = $47
Just solve 2 equations in 2 unknowns n and m:
(i) n + m = 15
(ii) n + 5m = 47
Subtract (i) from (ii) and get
4m = 32
m = 32/4 = 8
Then from (i) get
n = 15 - m = 15 - 8 = 7
There are 7 $1 bills and 8 $5 bills.
The equation y=-5.131x^2 31.821x-3.333 approximates the number of people standing in line to catch commuter train x hours after 5am what is the best estimate for the number of people in line at 9am
41 is the best estimate for the number of people in line at 9am
What is Equation?Two or more expressions with an Equal sign is called as Equation.
y equal to minus five point one three one x square plus Thirty one point eight two one x minus three point three three three.
y=-5.131x²+ 31.821x-3.333 approximates the number of people standing in line to catch commuter train x hours after 5am.
There is 4 hours in between 9 am and 5 am. so x=4
Substitute x=4 into the equation
y=-5.131(4)²+ 31.821(4)-3.333
y=-5.131(16)+127.284-3.333
y=-82.096+127.284-3.333
y=41.855
Hence 41 is the best estimate for the number of people in line at 9am
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Please help me with 3 math questions!!! I will give 30 points and brainliest to whoever answers the best!
1. Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type your answers in the box.
ƒ -1(x) = (answer) x (answer)(answer)
ƒ -1(4) = (answer)
2. Match each function with the expression representing its inverse function. Match one of the numbers with the correct letter.
1. y = x - 4
2. g(x) = -0.5x
3. k(x) = x
4. p(x) = x + 4
5. h(x) = 4x
6. ƒ(x) = x/2
a. 2x
b. x + 4
c. x - 4
d. -2x
e. 0.25x
f. x
3. The graph of a function g is shown below.
Find its inverse.
(picture below, my answer is NOT correct)
what is the answer to algebra with pizzazz page 100; what should you say if you see a tall, wrought-iron tower in paris, france?
there are 24 blanks
Answer: That’s really quite an eyeful
Step-by-step explanation:
The bottom answer to all of it is
That’s really quite an eyeful.
△FEB≅△CNB.
What is length of BN¯¯¯¯¯¯ ?
we know that
The CPCTC states that corresponding parts of congruent triangles are congruent
so
△FEB≅△CNB
that means
[tex]FE=CN\\FB=CB\\EB=NB[/tex]
we have
[tex]FE=6.1\ units\\FB=4.8\ units\\EB=3.8\ units[/tex]
therefore
[tex]BN=3.8\ units[/tex]
the answer is
the length of BN is [tex]3.8\ units[/tex]
What is the equation of the line that is perpendicular
If r^n=a, then which of the following are true statements? Check all that apply.
a. a^1/n=r b. a^r=n c. n sq a =r d. n^1/r=a
There are 20 counters in a box. A counter is chosen and replaced 100 times, the results are 32 blue and 68 red. How many of each color do you think there are in each box ?
Krista is planning to mow her grandparents lawn the rectangular yard is 10 yards by 12 yards but there is a square patio that has 12 foot sides in the middle of Krista kenmo 15 square feet per minute about how long will it take to finish the yard
what is the slope of the line (2,5) and 7,25)
Choose the correct answer.
You are offered an item for $22.85. If the seller states he normally sells the same item for $29.95, what percentage discount is he offering you
A. 24.22
B.23.96
C.23.71
29.95 - 22.85 = 7.10
7.10 / 29.95 = 0.23706 = 23.71 percent
Answer is C
Answer:
23.71%
Step-by-step explanation:
Given :You are offered an item for $22.85. If the seller states he normally sells the same item for $29.95,
To Find :what percentage discount is he offering you
Solution :
The original price is $29.95
The offered price is $22.85
So the discount percentage = [tex]\frac{\text{original price-offered price}}{\text{original price}}*100[/tex]
= [tex]\frac{29.95-22.85}{29.95}*100[/tex]
= [tex]\frac{7.1}{29.95}*100[/tex]
= 23.71%
Thus the percentage of discount is 23.71%
The following temperatures were recorded in Pasadena for a week in April: 87, 85, 80, 78, 83, 86, 90. Determine the interquartile range