What is the sign of-5×-1/-2

Answers

Answer 1
The sign would be negative because there is an odd number of negatives. If there were an even number of negatives it would be positive.

Multiply -5 by -1

The answer would be -5/2

Related Questions

Roast beef has 25g of protein and 11g of calcium per serving. A serving of mashed potatoes has 2 g of protein and 25 g of calcuim. How many servings of each are needed to supply exactly 29g of protein and 61 g of calcuim?

Answers

1 serving of Roast beef and 2 servings of mashed potatoes.

How many feet are in 84 inches

Answers

all you have to do is 84in/12= 7ft
84in/12= 7ft is the answer...


i hope this helps and have a wonderful day!!

If f(x)=square root of 2-x and g(x)=x-1, then find the domain of h(x)=f(x)/g(x)

Answers

Let's examine what the conditions on the domains of f and g have to be before we examine h. Since f is defined:

[tex]f(x)= \sqrt{2-x} [/tex], we know that the function will be undefined when 2 - x < 0, or when x > 2, so we have the restriction on our domain that x ≥ 0.

g(x) has no such restrictions and is defined for all possible values of x, so its domain is all real numbers, or [tex]\mathbb{R}[/tex]. 

Since h(x) is a rational function, we know that it's undefined when its denominator is 0. In this case, our denominator is g(x), so the function is undefined when g(x)=0. x - 1 = 0 only when x = 1, so the second restriction on our domain for h is that x ≠ 1. Putting those two together, we find that the domain of h(x) is all values of x ≥ 0, where x ≠ 1.

Answer:

Domain of h(x) : [2,∞)

Step-by-step explanation:

Given: Two functions

[tex]f(x)=\sqrt{2-x}[/tex]

[tex]g(x)=x-1[/tex]

Composite function, [tex]h(x)=\dfrac{f(x)}{g(x)}[/tex]

[tex]f(x)=\sqrt{2-x}[/tex], It is square root function. As we know square root function is always greater than 0.

2-x ≥ 0

  2 ≥ x

Domain of f(x) : [2,∞)

[tex]g(x)=x-1[/tex], It is straight line equation (Linear function) As we know domain of linear function is all real number.

Domain of g(x) : (-∞,∞)

[tex]h(x)=\dfrac{f(x)}{g(x)}[/tex]

[tex]h(x)=\dfrac{\sqrt{2-x}}{x-1}[/tex] , It is rational function. Denominator can't be zero.

So, x-1 ≠ 0

        x ≠ 1

Now, we will see domain of h(x) common all three domain.

Domain of h(x): [2,∞)

Hence, The domain of h(x) is [2,∞)

find real numbers a and b such that the equation a+bi=13+9i is true.

Answers

Given:
a + bi = 13 + 9i

Equate the real parts:
a = 13
Equate the imaginary parts:
b = 9

Answer:
a =13
b = 9

Final answer:

The real numbers a and b that make the equation a+bi=13+9i true are a = 13 and b = 9. We match real and imaginary parts of the complex numbers to find a and b.

Explanation:

To find the real numbers a and b such that the equation a+bi=13+9i is true, we simply match the real parts and the imaginary parts of the complex numbers on both sides of the equation. The real part of a+bi is a, and the real part of 13+9i is 13. Therefore, a = 13. Similarly, the imaginary part of a+bi is bi and the imaginary part of 13+9i is 9i. Thus, b = 9. Hence, the values we are looking for are a = 13 and b = 9.

How to find the inverse of f(x) = -(3/-x-3) - 2

Answers

so, to get the inverse relation of anything, as you'd already know, we first do a quick switcharoo on the variables, and then solve for "y".

[tex]\bf \stackrel{f(x)}{y}=-\cfrac{3}{-x-3}-2\qquad inverse\implies \boxed{x}=-\cfrac{3}{-\boxed{y}-3}-2 \\\\\\ x+2=\cfrac{3}{-(-y-3)}\implies x+2=\cfrac{3}{y+3}\implies (x+2)(y+3)=3 \\\\\\ xy+3x+2y+6=3\implies xy+2y=3-3x-6 \\\\\\ y(x+2)=-3x-3\implies y=\cfrac{-3x-3}{x+2}\implies \stackrel{f^{-1}(x)}{y}=\cfrac{-3(x+1)}{x+2}[/tex]

The inverse is f⁻¹(x) = -3(x + 1)/(x + 2).

To find the inverse of the given function f(x), follow these steps:

Replace f(x) with y: y = -(3/(-x-3)) - 2Swap x and y to start finding the inverse: x = -(3/(-y - 3)) - 2Isolate the term with y: x + 2 = -(3/(-y - 3))Multiply both sides by (-y - 3) to get: (x + 2)(-y - 3) = -3Distribute x + 2: -xy - 3x - 2y - 6 = -3Collect y terms on one side: -xy - 2y = 3x + 3Factor out y: y(-x - 2) = 3(x + 1)Solve for y: y = -3(x + 1)/(x + 2)

Thus, the inverse function is f⁻¹(x) = -3(x + 1)/(x + 2).

Luis can drive 3 times as fast as rico can ride his bike. If it takes rico 4 hours longer than Luis to travel 72 miles, how fast can ricoride his bike

Answers

Let Rico's speed be S
Then Luis' is: 3S
We then get: seventy-two over s equals seventy-two over three s plus four 
216=72+12s  Multiplying by LCD, 3S
216-72=12s
144 = 12S
S, or Rico's speed would be 144 over 12 or 12mph

0.0013 in scientific notation

Answers

1.3 x 10^-3...............

The scientific notation of the decimal number 0.0013 is [tex]0.0013 \times 10^{-3}[/tex].

Scientific notation is a way to express numbers in a concise form, particularly useful for very large or very small numbers.

It consists of two parts: a coefficient and an exponent of 10.

In the case of 0.0013, we can convert it to scientific notation as follows:

[tex]0.0013 \times 10^{-3}[/tex].

Hence, the scientific notation of 0.0013 is [tex]0.0013 \times 10^{-3}[/tex].

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62.4 percent of what number is 17.16

Answers

62.4% of what number is 17.16
0.624x = 17.16
x = 17.16 / 0.624
x = 27.5 <==

Look at all the measurements in model 4. when a number in scientific notation is changed to expanded notation, are any of the added zeros significant

Answers

Yes, the added zeros are significant. Lets say you are converting 1.23 x 10 to the power of 4. The answer would be 12,300 in which case, if you took away the zeros, the number would be 123, which is an incorrect answer.

Hope this makes sense and helps!
Final answer:

The added zeros when changing a number from scientific notation to expanded notation are usually not considered significant. They primarily serve as placeholders and do not indicate precision of measurements.

Explanation:

In the field of Mathematics, specifically when working with numbers in scientific notation and expanded notation, the concept of significant zeros comes into play. When you convert a number from scientific notation to expanded notation, zeros that are included in this process are not considered to be significant. Rather, the concept of significant zeros mostly applies to measurements and the precision of those measurements. For example, in the measurement 300.0, the zero at the end is significant because it shows the measurement was precise to the tenth's place. However, in changing a number from scientific to expanded notation, any added zeros primarily serve as placeholders and are typically not considered significant.

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Drag each equation to show if it could be a correct first step to solving the equation
2 (x + 7) = 36.
_____________________________________
| (2 · x) + (2 · 7) = 36   | 2x + 7 = 36 |
| x + 7 = 18    |   2(x + 7) = 72 |
| 2x + 14 = 36  |  x + 14 = 36 


Yes              No             Not Enough Info


Answers

Answer:

Yes

(2 · x) + (2 · 7) = 36x + 7 = 182x + 14 = 36

No

2x + 7 = 362(x + 7) = 72x + 14 = 36

Step-by-step explanation:

It is appropriate to eliminate parentheses as a first step. This can be done using the distributive property, resulting in either of ...

2x +2·7 = 362x +14 = 36 . . . . . 2·7 evaluated mentally

or by dividing the equation by the factor outside parentheses, resulting in ...

x + 7 = 18

___

Any of the equations other than these represent violations of the equal sign. Something has been done to one side of the equation without the same thing being done to the other side.

Jose bought a bag of 6 oranges for $2.82. He also bought 5 pineapples. He gave the cashier $20 and received $1.43 change. How much did each pineapple cost?

Answers

Your answer is: $3.15 each.

Here are the steps:

First, I added $2.82 and $1.43. Then, I subtracted the sum ($4.25) from $20. Lastly, I divided the difference($15.75) by five because there were five pineapples. Which gave me the answer: $3.15.

Jose bought a bag of [tex]6[/tex] oranges for [tex]\$2.82[/tex] and Jose also bought [tex]5[/tex]  pineapples each cost [tex]\$3.15[/tex].

Explanation:

Given: Jose bought a bag of [tex]6[/tex] oranges for [tex]\$2.82[/tex]. He also bought [tex]5[/tex] pineapples. He gave the cashier [tex]\$20[/tex] and received [tex]\$1.43[/tex] change.

Let cost of a pineapple be [tex]x[/tex].

According to the question:

Cost of pineapple is calculated as [tex]20-(2.82+5x)=1.43[/tex]

                                                            [tex]20-2.82-5x=1.43\\[/tex]

                                                                               [tex]5x=17.18-1.43\\[/tex]

                                                                                 [tex]x=\frac{15.75}{5} \\x=3.15[/tex]

Therefore, cost of each pineapple is [tex]\$3.15[/tex].

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Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 > 30 for n. Show your work. (4 points)

Answers

Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer

52 thousandth scientific Notation

Answers

5.2 x 10^-2 is your answer. I hope this helps love! :)

An insufficient funds check was returned to your company. How does the bank treat this on your bank statement

Answers

a "bounced fund" or "bounced cheque" gets a fine for bank's account holder, so if someone gives you a cheque, you deposit it in your bank's account, and the bank tries to liquidate it and the other bank that's got the funds says, there isn't enough and therefore refuses to send anything, then your bank fines your account for the bouncing.
 
Depending on the bank could be more or less, in the US is more often than not about $20 or $25 for a bounced cheque.

Suppose that block m = .050kg, sometime after reaching the base of the incline, undergoes a completely inelastic collision with the stationary block m = .075kg. use the principle of conservation of linear momentum to determine the common speed of the blocks just after the collision. (carry the answer to one decimal place)

Answers

The common speed of the blocks just after the collision is 0.4 times the initial velocity of the first block (v₁).

To determine the common speed of the blocks just after the completely inelastic collision, we can use the principle of conservation of linear momentum.

According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Let's denote the velocity of the first block (m = 0.050 kg) before the collision as v₁ and the velocity of the second block (m = 0.075 kg) before the collision as v₂. Since the second block is stationary, its initial velocity, v₂, is 0.

1. Before the collision, the total momentum is given by:

Initial momentum = m₁v₁ + m₂v₂

where m₁ and m₂ are the masses of the first and second blocks, respectively.

Plugging in the values, we have:

Initial momentum = (0.050 kg) v₁ + (0.075 kg) 0

Initial momentum = (0.050 kg)v₁

2. After the collision, the two blocks stick together and move as a single unit with a common velocity, denoted as vf.

The final momentum is given by:

Final momentum = (m₁ + m₂) vf

where (m₁ + m₂) is the total mass of the system.

Plugging in the values, we have:

Final momentum = (0.050 kg + 0.075 kg) × vf

Final momentum = 0.125 kg × vf

According to the principle of conservation of linear momentum, the total momentum before the collision is equal to the total momentum after the collision:

0.050 kg × v₁ = 0.125 kg × vf

To determine the common speed of the blocks just after the collision, we need to solve for vf:

vf = (0.050 kg × v₁) / (0.125 kg)

Calculating the numerical value, vf = 0.4 ×  v1

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(1 over x^2+3x-10)-(6 over x-2)

Answers

[tex]\bf \cfrac{1}{x^2+3x-10}-\cfrac{6}{x-2}\implies \cfrac{1}{(x+5)(x-2)}-\cfrac{6}{x-2}\impliedby \stackrel{LCD}{(x+5)(x-2)} \\\\\\ \cfrac{(x-2)~~-~~(x+5)6}{(x+5)(x-2)}\implies \cfrac{x-2-6x-30}{(x+5)(x-2)}\implies \cfrac{-7x-32}{(x+5)(x-2)}[/tex]

the elementary school lunch menu repeats every 20 days. the middle school lunch menu repeats every 15 days. both schools are serving pizza today. in how many days with both schools serve pizza again?

Answers

60 days




hope it helps

Find the distributive property of 24+40

Answers

just add them together

Write 2.64 as a percent. Please help me thank you do much.

Answers

The answer to this is 264%. Because you have to multiply it by 100
To change numbers to percent, you have to move the decimal 2 places to the right.
So 2.64 = 264%

Help me with number 4...

Answers

It's (A)

(- 382/100) / (27/1000)= -141.481....
The answer is D. When dividing, the divisor has to be a whole number. The power of ten used, you use it for the dividend also. The dividend doesn't have to be a whole number.

A firm advertises for workers to address envelopes. Priscilla says she will work 100 hours. Herb will work for 80 hours. If each can address 10,000 envelopes in the time they work, how long would it take them to address 10,000 envelopes if they work together?

Answers

combined work problems
job/time + job/time = job/ total time

(1/80) + (1/100) = 1/T
(10/800) + (8/800) = 1/T
18/800 = 1/T
800/18 = T
44.44 hrs = T

Priscilla and Herb would take approximately 44.44 hours to address 10,000 envelopes together, as Priscilla can address 100 envelopes per hour and Herb can address 125 envelopes per hour.

The question asks about the combined work rate of Priscilla and Herb in addressing 10,000 envelopes. To solve this, we calculate each of their rates of work and then combine them to find the total rate. Priscilla completes 10,000 envelopes in 100 hours, so her rate is 100 envelopes per hour. Herb completes 10,000 envelopes in 80 hours, so his rate is 125 envelopes per hour. Working together, their combined rate is 100 + 125 = 225 envelopes per hour. To address 10,000 envelopes at this rate, we divide 10,000 by 225, which equals approximately 44.44 hours.

This is a question I don't quite understand, will someone please help me?

Answers

Problem 1) xy means "x times y". The multiplication symbol is left out because its implied. You can write x*y if you wish. Or we can say "product of two numbers" since a product in math terms is the result of multiplication.
---------------------------------------------
Problem 2) x/y means "x divided by y" which is a fraction
---------------------------------------------
Problem 3)
Writing "x-y" is the same as saying "x minus y"
---------------------------------------------
Problem 4)
x+y is "x plus y", or we can say "the sum of x and y". The "sum" is "result of adding two or more values"
---------------------------------------------
Problem 5)
y-x is "y minus x" or we can say "x subtracted from y"
---------------------------------------------
Problem 6)
y division symbol x is essentially the flip of problem 2. We'd say "y divided by x"
---------------------------------------------
Problem 7)
x+y = 6 is "the sum of two numbers is 6". See problem 4 above.
---------------------------------------------
Problem 8)
xy = 6 is "the product of two numbers is 6". This is an extension of problem 1.
---------------------------------------------
Problem 9)
6x = y is "six times a number equals y" when translated out
---------------------------------------------
Problem 10)
y = x-6 would translate to "six less than a number is y"
where the "a number" portion is represented by x

∠1 and ∠2 are supplementary and m∠1 = m∠3. Which one of these statements will always be true?

Answers

Depending on what you are looking for, based on the question alone, I think that m∠2 and m∠3 are supplementary

Given: Angle 1 and angle 2 are supplementary.

Angle 3 and angle 4 are supplementary.

Angle 1 is congruent to angle 3.

Prove: Angle 2 is congruent to angle 4.

Solve using the multiplication principle.​ Don't forget to perform a check.
48=6x
The solution is x=

Answers

x = 8

6 x 8 = 48

hope this helped
48=6x

Divide both sides by 6

X=48÷6

x=8

Which formula gives the area of rectangle EFHG? area = d × j area = (e + h) × (f + i) area = (e + h) × j area = (e + h) × (f + c) NextReset

Answers

The formula for the area of a rectangle is A = LW or in this case 
Area = d x j

I NEED THIS ASAP! 3(p+2)−7p=18

Answers

the answer should be p= -3
I got -3 as well for the answer!

Find the solution of the differential equation (6−8xy2)dy/dx=y3 such that x=2 when y=4 by regarding y as the independent variable rather than x.

Answers

Final answer:

To solve for the differential equation where y is the independent variable, one must interchange x and y, do some algebraic manipulations to separate the variables, and then integrate. Additional steps may be necessary to solve for individual constants in the equation, using given points such as x=2 when y=4. Given the absence of a starting function, a definite solution cannot be provided.

Explanation:

To find the solution of the differential equation (6−8xy2)dy/dx=y3 where y is the independent variable, we must first formulate the differential equation such that y is the independent variable. We do this by interchanging x and y, leading to (6-8x/y^2)dx/dy= x^3. By separating the variables and integrating, we will get the function y=f(x).

However, often with differential equations, a specific solution is also required. In this case, we know that x=2 when y=4. Plugging these into the function y=f(x) we can solve for the individual constant. Since no function f(x) is given in the question as a basis, it's impossible to come up with a definite solution, but I hope this general approach helps clarify how to solve such problems.

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A like is drawn through (-4,3) and (4,3). which describes whether or not the line is represents a direct variation?

Answers

I believe the answer is D, but I am not certain
the answer would be A.) the line represents a direct variation because of the -4/3 and the 4/3.

The LA theorem is a special case of the?

Answers

Answer:

The LA theorem is a special case of the AAS theorem and the ASA postulate.

Step-by-step explanation:

The LA theorem is a special case of the AAS theorem and the ASA postulate.

LA(Leg - Acute) theorem states that if the leg and one acute angle of one right triangle are congruent to the corresponding leg and acute angle of another right triangle, then the triangles are congruent.

AAS (Angle Angle Side) states that if two angles and the non included side of one triangle are congruent to two angles and the non included side of another triangle, then these two triangles are congruent.

ASA (Angle Side Angle) postulate states that if two angles and one included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

how do I get the answer for this

Answers

[tex]\bf \lim\limits_{x\to -\infty}~\cfrac{\sqrt{9x^2+2}}{2x-9}\implies \cfrac{\lim\limits_{x\to -\infty}~\sqrt{9x^2+2}}{\lim\limits_{x\to -\infty}~2x-9}[/tex]

now, for any "x" value, the numerator will give you a positive root, say x = -10, then 9(-10)^2 +2  will be 902, square root of that is about 30.

whilst for the denominator, that'd be 2(-100) -9, or -209.

as you can see, the denominator for any "x" value, has larger jumps then the numerator, and because of that the rational itself, will always have a larger and larger and negative denominator.

so it may go from say -1/100 to -1/1000000 and so on as "x" progresses, going ever closer and closer to 0.
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