What is the energy of a photon that has the same wavelength as an electron having a kinetic energy of 15 ev?

Answers

Answer 1

Answer: [tex]6.268(10)^{-16}J[/tex]

Explanation:

The kinetic energy of an electron [tex]K_{e}[/tex] is given by the following equation:

[tex]K_{e}=\frac{(p_{e})^{2} }{2m_{e}}[/tex]   (1)

Where:

[tex]K_{e}=15eV=2.403^{-18}J=2.403^{-18}\frac{kgm^{2}}{s^{2}}[/tex]

[tex]p_{e}[/tex] is the momentum of the electron

[tex]m_{e}=9.11(10)^{-31}kg[/tex]  is the mass of the electron

From (1) we can find [tex]p_{e}[/tex]:

[tex]p_{e}=\sqrt{2K_{e}m_{e}}[/tex]    (2)

[tex]p_{e}=\sqrt{2(2.403^{-18}J)(9.11(10)^{-31}kg)}[/tex]  

[tex]p_{e}=2.091(10)^{-24}\frac{kgm}{s}[/tex]   (3)

Now, in order to find the wavelength of the electron [tex]\lambda_{e}[/tex]   with this given kinetic energy (hence momentum), we will use the De Broglie wavelength equation:

[tex]\lambda_{e}=\frac{h}{p_{e}}[/tex]    (4)

Where:

[tex]h=6.626(10)^{-34}J.s=6.626(10)^{-34}\frac{m^{2}kg}{s}[/tex] is the Planck constant

So, we will use the value of [tex]p_{e}[/tex] found in (3) for equation (4):

[tex]\lambda_{e}=\frac{6.626(10)^{-34}J.s}{2.091(10)^{-24}\frac{kgm}{s}}[/tex]    

[tex]\lambda_{e}=3.168(10)^{-10}m[/tex]    (5)

We are told the wavelength of the photon  [tex]\lambda_{p}[/tex] is the same as the wavelength of the electron:

[tex]\lambda_{e}=\lambda_{p}=3.168(10)^{-10}m[/tex]    (6)

Therefore we will use this wavelength to find the energy of the photon [tex]E_{p}[/tex] using the following equation:

[tex]E_{p}=\frac{hc}{lambda_{p}}[/tex]    (7)

Where [tex]c=3(10)^{8}m/s[/tex]  is the spped of light in vacuum

[tex]E_{p}=\frac{(6.626(10)^{-34}J.s)(3(10)^{8}m/s)}{3.168(10)^{-10}m}[/tex]  

Finally:

[tex]E_{p}=6.268(10)^{-16}J[/tex]    


Related Questions

A car is traveling at an initial velocity of 25 m/s slows to a stop in 10 seconds. What is the acceleration of the car?

Answers

Answer:

2.5 m/s^2

Explanation:

the formula for acceleration (or the one you use in this case) is a=vf-vi/t

where vf is equal to final velocity, vi is equal to initial velocity, and t is equal to time.

vf= 25 m/s

vi= 0m/s

t=10s       25-0=25, 25/10=2.5 therefore it is 2.5m/s^2

The four inner planets of our solar system are

Answers

The four innermost planets in the Solar System (Mercury, Venus, Earth, and Mars)

The four inner planets of our solar system are Mercury, Venus, Earth, and Mars.

What is the solar system?

A solar system is a group of celestial bodies, which is constituted of stars, planets, asteroids, and so on.

here,
The four inner planets of our solar system, also known as the terrestrial planets, are,

Mercury: The closest planet to the Sun, and the smallest planet in our solar system.Venus: The second planet from the Sun, and the hottest planet in our solar system due to its thick atmosphere of carbon dioxide.Earth: The third planet from the Sun, and the only planet known to support life.Mars: The fourth planet from the Sun, often called the "Red Planet" due to its reddish appearance caused by iron oxide on its surface.

These four planets are called "terrestrial" because they are rocky and relatively small compared to the outer gas giants, such as Jupiter, Saturn, Uranus, and Neptune. They are also closer to the Sun and have shorter orbital periods than the outer planets.

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By what mechanism is a person injured when he or she falls from a significant height? Select one: a. Kinetic energy is converted to potential energy; the potential energy is then converted into the work of bringing the body to a stop. b. As the person falls, the amount of kinetic energy is converted into work; work is then converted to kinetic energy upon impact. c. Potential energy is created as the person is falling; the potential energy is then converted into kinetic energy upon impact. d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.

Answers

Answer:

d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop

Explanation:

- When the person starts his/her fall from a certain height h, he/she possesses gravitational potential energy:

[tex]U=mgh[/tex]

where m is the mass of the person, g is the acceleration due to gravity, h is the height.

- During the fall, the height h decreases, while the speed of the person increases, so gravitational potential energy is converted into kinetic energy:

[tex]K=\frac{1}{2}mv^2[/tex]

where

m is the mass of the person

v is the speed

- Just a moment before hitting the ground, h=0, so all the potential energy has been converted into kinetic energy

- When the person hits the ground, he/she comes a stop: this means that now the speed is zero (v=0), so the kinetic energy is zero as well. This occurs because all the kinetic energy has been converted into the work of bringing the body to a stop. (the work has been done by the ground on the person)

A sample of gas initially has a volume of 859 ml at 565 k and 2.20 atm. What pressure will the sample have if the volume changes to 268 ml while the temperature is increased to 815 k?

Answers

Answer:

10.2 atm

Explanation:

Use ideal gas law:

PV = nRT

Initial number of moles is:

(2.20 atm) (0.859 L) = n (0.0821 atm L / mol / K) (565 K)

n = 0.0407 mol

At the new volume and temperature, the pressure is:

P (0.268 L) = (0.0407 mol) (0.0821 atm L / mol / K) (815 K)

P = 10.2 atm

We have that the pressure the sample have if the volume changes to 268 ml while the temperature is increased to 815 k is

[tex]P_2=10atm[/tex]

From the question we are told

A sample of gas initially has a volume of 859 ml at 565 k and 2.20 atm. What pressure will the sample have if the volume changes to 268 ml while the temperature is increased to 815 k

Generally the equation for the ideal gas   is mathematically given as

PV=nRT

Where

[tex]\frac{P1V1}{T1}=\frac{P2V2}{T2}[/tex]

Therefore

[tex]P_2=\frac{P1V1T2}{V2T1}\\\\P_2=\frac{2.20*859*815}{268*565}[/tex]

[tex]P_2=10atm[/tex]

THEREFORE

the pressure the sample have if the volume changes to 268 ml while the temperature is increased to 815 k is

[tex]P_2=10atm[/tex]

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The escape speed from Planet X is 20,000 m/s. Planet Y has the same radius as Planet X but is twice as dense. What is the escape speed from Planet Y?

Answers

Answer:

the escape speed from planet Y is [tex]\sqrt{2}[/tex] times the escape speed from planet X.

Explanation:

The escape speed from a surface of a planet is given by:

[tex]v=\sqrt{\frac{GM}{R}}[/tex]

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Let's call M the mass of planet X and R its radius. So the speed

[tex]v_x=\sqrt{\frac{GM}{R}}[/tex]

corresponds to the escape speed from planet X.

Now we now that planet Y has:

- same radius of planet X: R' = R

- twice the density of planet X: d' = 2d

The mass of planet Y is given by

[tex]M' = d' V'[/tex]

where V' is the volume of the planet. However, since the two planets have same radius, they also have same volume, so we can write

[tex]M' = d' V= (2d)V = 2M[/tex]

which means that planet Y has twice the mass of planet X. So, the escape speed of planet Y is

[tex]v'=\sqrt{\frac{GM'}{R}}=\sqrt{\frac{G(2M)}{R}}=\sqrt{2}(\sqrt{\frac{GM}{R}})=\sqrt{2} v[/tex]

so, the escape speed from planet Y is [tex]\sqrt{2}[/tex] times the escape speed from planet X.

Final answer:

The escape speed from Planet Y, which has the same radius but twice the density as Planet X, would be approximately 28,300 m/s.

Explanation:

The escape speed, or escape velocity, from a planet is dependent on the mass and the radius of the planet, and it's calculated using the formula:

v = sqrt((2*G*M)/R)

Where v is the escape speed, G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet. If Planet Y has the same radius as Planet X but is twice as dense, its mass will be twice that of Planet X because mass is density times volume. Thus, the escape speed from Planet Y will be sqrt(2) or approximately 1.414 times the escape speed from Planet X. So, v_Y = 1.414 * 20,000 m/s, or about 28,300 m/s.

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The binding energy of a nucleus can be found using

Answers

Answer:

converting that mass to energy by using E=mc2. Mass must be in units of kg. Once this energy, which is a quantity of joules for one nucleus, is known, it can be scaled into per-nucleon and per-mole quantities.

Explanation:

Answer:

An elephants balls

Explanation:

A sound source A and a reflecting surface B move directly toward each other. Relative to the air, the speed of source A is 28.7 m/s, the speed of surface B is 62.2 m/s, and the speed of sound is 334 m/s. The source emits waves at frequency 1110 Hz as measured in the source frame. In the reflector frame, what are (a) the frequency and (b) the wavelength of the arriving sound waves? In the source frame, what are (c) the frequency and (d) the wavelength of the sound waves reflected back to the source?

Answers

(a) 1440.5 Hz

The general formula for the Doppler effect is

[tex]f'=(\frac{v+v_r}{v+v_s})f[/tex]

where

f is the original frequency

f is the apparent frequency

[tex]v[/tex] is the velocity of the wave

[tex]v_r[/tex] is the velocity of the receiver (positive if the receiver is moving towards the source, negative otherwise)

[tex]v_s[/tex] is the velocity of the source (positive if the source is moving away from the receiver, negative otherwise)

Here we have

f = 1110 Hz

v = 334 m/s

In the reflector frame (= on surface B), we have also

[tex]v_s = v_A = -28.7 m/s[/tex] (surface A is the source, which is moving towards the receiver)

[tex]v_r = +62.2 m/s[/tex] (surface B is the receiver, which is moving towards the source)

So, the frequency observed in the reflector frame is

[tex]f'=(\frac{334 m/s+62.2 m/s}{334 m/s-28.7 m/s})1110 Hz=1440.5 Hz[/tex]

(b) 0.232 m

The wavelength of a wave is given by

[tex]\lambda=\frac{v}{f}[/tex]

where

v is the speed of the wave

f is the frequency

In the reflector frame,

f = 1440.5 Hz

So the wavelength is

[tex]\lambda=\frac{334 m/s}{1440.5 Hz}=0.232 m[/tex]

(c) 1481.2 Hz

Again, we can use the same formula

[tex]f'=(\frac{v+v_r}{v+v_s})f[/tex]

In the source frame (= on surface A), we have

[tex]v_s = v_B = -62.2 m/s[/tex] (surface B is now the source, since it reflects the wave, and it is moving towards the receiver)

[tex]v_r = +28.7 m/s[/tex] (surface A is now the receiver, which is moving towards the source)

So, the frequency observed in the source frame is

[tex]f'=(\frac{334 m/s+28.7 m/s}{334 m/s-62.2 m/s})1110 Hz=1481.2 Hz[/tex]

(d) 0.225 m

The wavelength of the wave is given by

[tex]\lambda=\frac{v}{f}[/tex]

where in this case we have

v = 334 m/s

f = 1481.2 Hz is the apparent in the source frame

So the wavelength is

[tex]\lambda=\frac{334 m/s}{1481.2 Hz}=0.225 m[/tex]

The photoelectric effect tells us that __________.

Answers

hey

It describes the process by which surface electron's are emitted from a metal when light is shined on it.And it tells us that light at a higher intensity must contain more quanta of energy, known as protons.

What is the potential difference across a 15 Ω resistor that has a current of 3.0 A?

Answers

Answer:

45 V

Explanation:

Use Ohm's law:

V = IR

V = (3.0 A) (15 Ω)

V = 45 V

Answer:

45V

Explanation:

R=V/I

V=I/R

V=15ohms•3.0 A

V=45V

Why are metals generally good conductors of electricity?

Answers

Answer:

Let's start by explaining that a material is a good electrical conductor when it allows the flow of electric current without  much resistance.  

This is achieved because the atoms of which the material is composed have electrons in their valence shell, which is the outermost layer where the electrons (the particles responsible for transporting electricity) can be easily detached to form atomic bonds, so there is no need of a huge amount of energy for these electrons to jump from one atom to another and form stable chemical bonds.

This is what happens with metals, because they have an atomic structure so united and stable that when an electric flow passes through it, the electrons in the metal flow unimpeded.

Metals are good conductors because the molecules that are inside the metal are tightly packed together. This is why the heat moves through the metal quickly.

What is an elastic collision?

Answers

Answer:

A collision in which both total momentum and total kinetic energy are conserved

Explanation:

In classical physics, we have two types of collisions:

- Elastic collision: elastic collision is a collision in which both the total momentum of the objects involved and the total kinetic energy of the objects involved are conserved

- Inelastic collision: in an inelastic collision, the total momentum of the objects involved is conserved, while the total kinetic energy is not. In this type of collisions, part of the total kinetic energy is converted into heat or other forms of energy due to the presence of frictional forces. When the objects stick together after the collision, the collisions is called 'perfectly inelastic collision'

An elastic collision is where the total kinetic energy and total momentum before and after the collision are conserved. These collisions occur without permanent deformation or energy loss in other forms. This concept is important in physics, particularly in one-dimensional collisions involving atoms.

An elastic collision is a type of collision in which the total kinetic energy and total momentum of the system are conserved. This means that the kinetic energy before the collision is equal to the kinetic energy after the collision, and there is no permanent deformation of the objects involved or conversion into other energy forms like heat or sound. Elastic collisions are particularly relevant in atomic interactions, where collisions between atoms can often be considered elastic.

In one-dimensional collisions, conservation of kinetic energy and momentum allow us to calculate the final velocities of the colliding bodies using their initial velocities and their masses. A common example of nearly elastic collisions in a macroscopic context includes collisions of steel blocks on an icy surface or carts with spring bumpers on an air track, where friction is minimal.

which of the following represents thermal energy transfer through radiation
A)a thermometer sitting on top of a heat lamp
B)a person trying to unscrew a hot light bulb
C)a child sitting in front of a space heater
D)swimming in the pool and noticing that the deeper end of the pool is colder than the shallow end

Answers

C. since the the heat from the heater is going to the child in waves, it’s radiating

The transfer of thermal energy through radiation is exemplified by a thermometer sitting on top of a heat lamp, representing energy transferred through electromagnetic waves without direct contact.

The answer which represents thermal energy transfer through radiation is A) a thermometer sitting on top of a heat lamp. This is because radiation is a method of heat transfer that does not rely on any contact between the heat source and the heated object, as in the case of a thermometer receiving infrared radiation from a heat lamp.

Radiation is the transfer of energy by electromagnetic waves, and it can occur even through a vacuum. For example, the glow of the sun or a candle flame is heat transfer by radiation; the energy is transferred in the form of visible light and other electromagnetic waves. The amount of power radiated is proportional to the surface area of the radiating object and increases significantly with the absolute temperature of the object, adhering to the relationship P ≈ T4, where P represents the radiated power and T is the absolute temperature in Kelvin.

Which property describes the amount of energy that flows past a given area per unit of time?
A.Intensity
B.Pitch
C.Speed
D.Wavelength

Answers

it is intensity. Option A

What is the process of evaporation through plant leaves called

Answers

Answer: Transpiration

Vegetal transpiration is the loss of water in the form of vapor, in the plant through its different parts, especially its leaves.

In this process, soil water is absorbed by the roots of the plant and transported in liquid form to the leaves to be converted into water vapor, while a part is used in photosynthesis. That is why vegetal transpiration is considered a vital function in the photosynthesis process.

This is possible because the leaves have small pores that allow water to escape into the atmosphere in the form of vapor and absorb carbon dioxide. Then, most of the water in the plants is used in the process of transpiration and only a small percentage is retained in liquid state and used for its growth and storage.

Leap years _____. happen because the Earth revolves around the sun in less than 365 days make up for the extra one-fourth day the Earth needs to orbit the sun add an extra day to the end of December, making the month 32 days long subtract a day from February, making the month only 27 days long

Answers

The Earth takes (365 and 1/4) days to orbit the sun.  That's the length of our 'year'.

Since it's not really possible to make our calendar a quarter of a day longer every year, we make the calendar a whole day longer every 4 years.

So "Leap years" make up for the extra one-fourth day the Earth takes to orbit the sun.

A 2.0-kg ball moving eastward at 3.0 m/s suddenly collides with and sticks to a 4.0-kg ball moving northward at 2.0 m/s. What is the magnitude of the momentum of this system just after the collision?

Answers

Answer:

10 kg m/s

Explanation:

Due to the law of conservation of momentum, the total momentum after the collision must be equal to the total momentum before the collision.

The momentum of each ball is given by:

p = mv

where m is the mass of the ball and v its velocity.

The momentum of ball 1 is:

p = mv = (2.0 kg)(3.0 m/s) = 6.0 kg m/s in the eastward direction

The momentum of ball 2 is:

p = mv = (4.0 kg)(2.0 m/s) = 8.0 kg m/s in the northward direction

The two momenta are in perpendicular directions, so the magnitude of the total momentum can be found as:

[tex]p=\sqrt{p_1^2 + p_2^2 }= \sqrt{(6.0 kg m/s)^2 + (8.0 kg m/s)^2}=10 kg m/s[/tex]

and due to the law of conservation of the momentum, this is also equal to the total momentum after the collision.

The magnitude of the momentum of this system just after the collision is about 10.0 kg.m/s

[tex]\texttt{ }[/tex]

Further explanation

Let's recall Impulse formula as follows:

[tex]\boxed {I = \Sigma F \times t}[/tex]

where:

I = impulse on the object ( kg m/s )

∑F = net force acting on object ( kg m /s² = Newton )

t = elapsed time ( s )

Let us now tackle the problem!

[tex]\texttt{ }[/tex]

Given:

mass of first ball = m₁ = 2.0 kg

velocity of first ball = v₁ = 3.0i m/s

mass of second ball = m₂ = 4.0 kg

velocity of second ball = v₂ = 2.0j m/s

Asked:

magnitude of the final momentum = p = ?

Solution:

We will use Conservation of Momentum formula to solve this problem:

[tex]\texttt{Total Momentum Before Collision = Total Momentum After Collision}[/tex]

[tex]m_1 v_1 + m_2 v_2 = \overrightarrow{p}[/tex]

[tex]2.0 ( 3.0\ \widehat{i} ) + 4.0 ( 2.0 \ \widehat{j} ) = \overrightarrow{p}[/tex]

[tex]\overrightarrow{p} = 6.0 \ \widehat{i} + 8.0 \ \widehat{j}[/tex]

[tex]|\overrightarrow{p}| = \sqrt{ 6.0^2 + 8.0^2 }[/tex]

[tex]|\overrightarrow{p}| = 10.0 \texttt{ kg.m/s}[/tex]

[tex]\texttt{ }[/tex]

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[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

Which shows the correct order of events after the big bang occurred? strong force separated from the unified force, inflationary expansion occurred, quarks and electrons formed, electromagnetic and weak forces separated from the unified force, gravity separated from the unified force electromagnetic and weak forces separated from the unified force, gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, quarks and electrons formed gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed quarks and electrons formed, electromagnetic and weak forces separated from the unified force, inflationary expansion occurred, strong force separated from the unified force, gravity separated from the unified force

Answers

Answer:

C) gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed

Gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed.

What is big bang theory?

The big bang theory is a scientific theory that tries to explain the existence of the universe from the earliest known periods through small to large evolution.

In the first moments after the Big Bang, the universe was extremely hot and dense, and matter was formed as the universe cooled.

The formation of the matter is as a result of the following forces;

Gravity separated from the unified force, Strong force separated from the unified force, Inflationary expansion occurred, Electromagnetic and weak forces separated from the unified forceQuarks and electrons formed

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A Ping-Pong ball moving East at a speed of 4 m/s collides with a stationary bowling ball. The Ping-Pong ball bounces back to the West, and the bowling ball moves very slowly to the East. Which object experiences the greater magnitude impulse during the collision?

Answers

Answer:

They experience the same magnitude impulse

Explanation:

We have a ping-pong ball colliding with a stationary bowling ball. According to the law of conservation of momentum, we have that the total momentum before and after the collision must be conserved:

[tex]p_i = p_f\\p_p + p_b = p'_p+p'_b[/tex]

where

[tex]p_p[/tex] is the initial momentum of the ping-poll ball

[tex]p_b[/tex] is the initial momentum of the bowling ball (which is zero, since the ball is stationary)

[tex]p'_p[/tex] is the final momentum of the ping-poll ball

[tex]p'_f[/tex] is the final momentum of the bowling ball

We can re-arrange the equation as follows

[tex]p_p - p'_p = p_b'-p_b[/tex]

or

[tex]-\Delta p_p = \Delta p_b[/tex]

which means

[tex]|\Delta p_p | = |\Delta p_b|[/tex] (1)

so the magnitude of the change in momentum of the ping-pong ball is equal to the magnitude of the change in momentum of the bowling ball.

However, we also know that the magnitude of the impulse on an object is equal to the change of momentum of the object:

[tex]I=\Delta p[/tex] (2)

Therefore, (1)+(2) tells us that the ping-pong ball and the bowling ball experiences the same magnitude impulse:

[tex]|I_p| = |I_b|[/tex]

Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic field lines. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Answers

Answer:

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Explanation:

The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by

[tex]F=ILB sin \theta[/tex] (1)

where I is the current, L the length of the wire, B the strength of the magnetic field, [tex]\theta[/tex] the angle between the direction of the field and the direction of the current.

Also, B, I and F in the formula are all perpendicular to each other. (2)

According to eq.(1), we see that the statement:

"The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines."

is correct, because when the current is perpendicular to the magnetic field, [tex]\theta=90^{\circ}, sin \theta = 1[/tex] and the force is maximum.

Moreover, according to (2), we also see that the statements

"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "

"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "

because F (the force) is perpendicular to both the magnetic field and the current.

Final answer:

The magnetic force on a current-carrying wire in a uniform magnetic field is perpendicular to both the magnetic field lines and the direction of the current. The force is strongest when the current is perpendicular to the magnetic field lines, and is zero when the current runs parallel to the magnetic field lines.

Explanation:

According to the principles of magnetism and the right-hand rule, the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to both the magnetic field and to the current direction. The strength of the magnetic force on the wire is dictated by the equation F = I x B, where F is the force, I represents the current, and B is the strength of the magnetic field.

When the current flows parallel to the magnetic field lines, the force experienced by the wire is actually zero due to the nature of the cross product in the force formula. However, the magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines. This is because the effect of the magnetic force is most significant when these two quantities are at right angles to each other.

In terms of the direction of the force, you can use the right-hand rule. If you point your thumb in the direction of the current, and your fingers in the direction of the magnetic field, your palm will point in the direction of the force on the wire.

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The definition of parallel lines requires the undefined terms line and plane

Answers

Answer:

True

Explanation:

Answer:

Parallel lines never intersect, but they must be in the same plane. The definition does not require the undefined term point, but it does require plane. Because they intersect, perpendicular lines must be coplanar; consequently, plane is not required in the definition.

What did you include in your response? Check all that apply.

Parallel lines do not intersect.

Parallel lines must be coplanar.

Perpendicular lines intersect at one point.

Perpendicular lines intersect  so plane is not required in the definition.

An object of mass m is dropped from height h above a planet of mass M and radius R. Find an expression for the object's speed as it hits the ground. Express your answer in terms of the variables m, M, h, R and appropriate constants.

Answers

Answer:

v = √(2 MGh) / R

Explanation:

Assuming that h is much smaller than R, we can say the acceleration of gravity is approximately constant during the fall.

Potential energy = Kinetic energy

mgh = 1/2 mv²

v = √(2gh)

v = √(2 (MG/R²) h)

v = √(2 MGh) / R

How many category 5 hurricanes since 2000

Answers

Answer:

Explanation:

“Officially, the decade with the most Category 5 hurricanes is 2000–2009, with eight Category 5 hurricanes having occurred: Isabel (2003), Ivan (2004), Emily (2005), Katrina (2005), Rita (2005), Wilma (2005), Dean (2007), and Felix (2007).”

Find the angular speed of the minute hand and the hour hand of the famous clock in london

Answers

All clocks that keep the correct time have hands that move at the same speeds.  I only have to decide whether the famous clock in London keeps the correct time.  I'm thinking that if it didn't, it wouldn't have gotten to be so famous, or else the people of London would have fixed it by now.  So I'm going to assume that it keeps the correct time.

Since the famous clock in London keeps the correct time, its minute hand makes one complete revolution around the clock's face every hour, and its hour hand makes one complete revolution every 12 hours.  

When we're talking angular speeds, we usually talk in radians.  One complete revolution is an angle of 2π radians.

Minute hand speed:  2π radian/hour

Speed = (2π/hr) x (1 hr/3600 sec)

Speed = 2π/3600 sec

Speed = 1.75 x 10⁻³ radian/sec

Speed = 0.1 degree/sec

Hour hand speed = 2π / 12 hours = π/6 radian per hour

Speed = (π / 6 hour) x (1 hour / 3600 sec)

Speed = 1.45 x 10⁻⁴ radian/sec

Speed = 30 degrees/hour

Speed = 8.3 x 10⁻³ degree/second

Final answer:

The angular speed of the minute hand of a clock is 2π rad/hour, and for the hour hand, it’s 2π rad/12 hours. This calculation comes from dividing the total rotation angle (2π rad) by the time it takes to complete that rotation. This utilizes the principles of rotational motion in Physics.

Explanation:

To find the angular speed of the minute and hour hand on a clock, a concept from Physics, specifically rotational motion, is applied. The angular speed is defined as the change in angle per unit time. In a clock, a complete rotation, which is equal to 360° or 2π radians, takes an hour for the minute hand and 12 hours for the hour hand.

For the minute hand: it completes one rotation (360° or 2π radians) in 60 minutes (1 hour). So, its angular speed ω is equal to the total angle θ divided by the total time t: ω (minute) = θ / t = 2π / 1 hour.

For the hour hand: it completes one rotation in 12 hours. Hence, its angular speed is: ω (hour) = θ / t = 2π / 12 hours.

Please note that this calculation considers a simple ideal case. In real life scenarios, factors such as mechanism quality, temperature, even relativistic effects if the clock moves very fast, like the satellite clocks, can cause slight differences.

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Crime scene investigators find that a car hit the ground 60m from the point where it left the cliff. The cliff is 45 m high. Approximately what speed was the car going when it left the cliff (assume no air resistance)?

Answers

Answer:

20 m/s

Explanation:

In the y direction:

y = y₀ + v₀ᵧ t + ½ gt²

0 m = 45 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 3.03 s

In the x direction:

x = x₀ + v₀ₓ t + ½ at²

60 m = 0 m + v (3.03 s) + ½ (0 m/s²) (3.03 s)²

v = 19.8 m/s

Rounded to one sig-fig, the car's velocity was approximately 20 m/s.

please help on this one?

Answers

Answer:

A

Explanation:

a cell phone tower provides 1e+13 waves per second

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What type of electron is available to form bonds?

Answers

Answer:

Valence electrons

Explanation:

The valence electrons are found in the outermost shell of an atom. They are the most loosely held electrons found within an atom. These valence electrons are involved and are used to form bonds when atoms combines together.

The energy required to remove these loosely held electrons is relatively low compared to electrons located in the inner orbitals. This is why when atoms combines, they use the outermost electrons to form bonds and mimic stable atoms like those of the noble gases.

Final answer:

Valence electrons are those in the outermost shell of an atom; they are used to form bonds such as ionic and covalent bonds to achieve stable electron configurations. Atoms generally follow the octet rule where they seek eight valence electrons, although there are exceptions like hydrogen and transition elements.

Explanation:

The type of electron that is available to form bonds is known as the valence electron. Valence electrons are those electrons found in the outermost shell of an atom and are critical in determining how an atom will chemically interact with other atoms. Typically, atoms will form bonds to achieve a stable electron configuration, often striving to have eight valence electrons, following the octet rule. However, there are exceptions such as hydrogen, which only requires two electrons to fill its valence shell, and transition elements that do not always follow the octet rule due to their d and f electrons.

There are two main types of bonds that involve valence electrons: ionic bonds and covalent bonds. Ionic bonds occur when electrons are transferred from one atom to another, creating ions that are held together by electrostatic forces. Covalent bonds occur when electrons are shared between atoms, which can be envisioned as electron density located in space-symmetric wave functions between the nuclei of the bonded atoms.

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During a phase change, the temperature of a substance _____.

A)decreases


B)increases


C)stays the same

Answers

During a phase change, the temperature of a substance (c). stays the same.

The temperature remains same during the phase change.

Answer: Option C

Explanation:

The term “change of phase” is similar to “change of state”. When there is a change of substance from a state to the other state or phase, it is known as changes in its state. This change of state occurs due to the change of heat.

When a substance changes the phase, either the heat comes out or goes in the substance. Although there occur a change in the content of heat present in the substance, the temperature will not change. It remains constant.  When ice melts it becomes water and the water vaporizes which becomes water vapour.

A step up transformer used on a 120v line has 95 turns on the primary and 2850 turns on the secondary.what is the emf across the secondary

Answers

Answer:

3600 V

Explanation:

The transformer equation states that:

[tex]\frac{V_p}{N_p}=\frac{V_s}{N_s}[/tex]

where

[tex]V_p = 120 V[/tex] is the voltage in the primary coil

[tex]N_p = 95[/tex] is the number of turns in the primary coil

[tex]V_s[/tex] is the voltage in the secondary coil

[tex]N_s = 2850[/tex] is the number of turns in the secondary coil

Slving the equation for Vs, we find the emf induced in the secondary coil:

[tex]V_s = \frac{V_p N_s}{N_p}=\frac{(120 V)(2850)}{95}=3600 V[/tex]

A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a smooth, horizontal surface with no friction. The mass is pulled away from the equilibrium position by a distance A in the positive x-direction and then released so that it oscillates in simple harmonic motion with frequency f. What will happen to the frequency of the oscillation if the mass is doubled?

Answers

Explanation:

The frequency of a spring is:

f = 1/(2pi) sqrt(k / m)

If m doubles, then f decreases by a factor of 1/sqrt(2).

Final answer:

Doubling the mass attached to a spring in a frictionless simple harmonic oscillator will decrease the frequency of oscillation by a factor of √2, or approximately 0.7071 times the original frequency.

Explanation:

In a simple harmonic oscillator like the mass-spring system described, the frequency of oscillation is given by f = (1/2π) * √(k/m), where k represents the spring constant and m the mass attached to the spring. If the mass is doubled, the frequency of the oscillation will decrease because the frequency is inversely proportional to the square root of the mass. Therefore, if the mass increases by a factor of two, the new frequency will be f' = (1/2π) * √(k/2m), which is f' = f/√2. This implies that the frequency will decrease by a factor of √2, or approximately 0.7071 times the original frequency.

Plants get the energy they need for photosynthesis by absorbing

Answers

Chloroplast absorb solar energy to make food for the plant. So it’s solar energy
Final answer:

Plants absorb sunlight to fuel the process of photosynthesis, converting this light energy into chemical energy to produce glucose from carbon dioxide and water.

Explanation:

Plants get the energy they need for photosynthesis by absorbing sunlight. This light is captured primarily through their leaves, specifically, the chlorophyll in the chloroplasts, which converts light energy into chemical energy, a procedure known as light-dependent reactions.

This energy is then used to generate glucose from carbon dioxide and water in a process commonly referred to as the 'light-independent reactions', or the Calvin cycle.

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