What is the difference between contact forces and forces that act through a force field?

Answers

Answer 1
Contact forces are forces that occur when two objects make contact, ex. Frictional Force. Non-contact forces occur without contact, ex. Gravitational Force or Electric Force.
Answer 2

Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.

What is force?

Force is the action of push or pull which cause an object to move or stop.

Contact forces are the forces that come into existence when two objects come in contact to apply a force, For example: Frictional Force.

Non-contact forces takes place without any physical contact. For example: Gravitational force, Electric force, Magnetic force.

Thus, Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.

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Related Questions

A 4-kg object falls vertically a distance of 5 m. its potential energy has changed by approximately how much?
a. it has increased by 200 j.
b. it has increased by 20 j.
c. it has decreased by 20 j.
d. it has decreased by 200 j.

Answers

Given:
m = 4 kg, the mass of the object
h = 5 m, distance fallen

Neglect air resistance.

The PE (potential energy) is 
PE = mgh = (4 kg)*(9.8 m/s²)*(5 m) = 196 J

The PE is converted into KE (kinetic energy) after the fall. 
Therefore the PE decreased by 196 J ≈ 200 J

Answer: d. It has decreased by 200 J

Final answer:

The potential energy of the object has increased by approximately 196 J.

Explanation:

The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height the object has fallen. In this case, the object has fallen a distance of 5 m. Given that the mass of the object is 4 kg and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the change in potential energy as follows:

Change in PE = mgh = (4 kg)(9.8 m/s²)(5 m) = 196 J

Therefore, the potential energy has increased by approximately 196 J. Since none of the provided options match this exact value, we can conclude that none of the given choices is correct.

Suppose you are a particle of water in a lake. Describe what happens to you when a motorboat passes by. Be sure to use words like vibration and crest in your description.

Answers

The boat could easily pass through me ( particle of water) because the forces of attraction between the particles and the density is less than the particles of a solid.

Elyse is explaining to a friend that she will be conducting a scientific investigation. Her question is "How many leatherback sea turtles will migrate to their home beach on the eastern coast of Australia this season?" Elyse states her hypothesis is "1,200 leatherback sea turtles will migrate to their home beach on the eastern coast of Australia this season." For her procedure, she and a team of scientists will be observing and counting the number of turtles that land on the beach. What is unusual about the description of her scientific investigation?

Answers

Final answer:

Elyse's scientific investigation into the migration of leatherback sea turtles on Australia's east coast is noted for its unusually precise hypothesis of "1,200" turtles migrating. Scientific hypotheses typically predict trends or relationships rather than exact figures. Understanding the broader context of sea turtle conservation is crucial.

Explanation:

Elyse is conducting a scientific investigation to determine how many leatherback sea turtles migrate to their home beach on the eastern coast of Australia this season. Her approach involves observing and counting turtles as they land on the beach. An unusual aspect of her description is the formulation of a very specific hypothesis stating "1,200 leatherback sea turtles will migrate to their home beach." Typically, a hypothesis in scientific investigations is a broader statement predicting a relationship or trend, rather than a precise number. Moreover, it's essential to understand the broader context of sea turtle conservation, including the various populations of leatherback turtles in the Pacific Ocean, and why certain beaches are critical to their survival. Factors like natural selection play a vital role in why leatherback turtles favor particular nesting sites, such as the types of beaches that provide suitable conditions for hatchling survival and thus contribute to the species' overall survival.

Which will result in positive buoyancy and cause the object to float?

Question 1 options:

When the buoyant force is equal to the force of gravity


When the force of gravity is more than the buoyant force


When the buoyant force is greater than the force of gravity


When the buoyant force is less than the force of gravity

Answers

When the buoyant force is greater than the force of gravity, the object will float.
the answer C I KNOS DAYS OLD BUT NO ONE ANSWER IT 

Which type of environmental science career involves collecting information about how human events impact the environment?
a.
Environmental journalist
b.
Environmental physician
c.
Environmental engineer
d.
Environmental designer

Answers

The correct answer is: a.  Environmental journalist

An environmental journalist is someone who collects information about matters relevant to the environment, and reports or publishes this information in journals, magazines and reports. On the other hand, environmental physicians, designers and engineers are not involved in collecting information regarding the environment. Instead they focus on designing and building tools and structures that benefit and conserve the environment. Thus, the correct answer is A: An environmental journalist's career involves collecting information about how human events impact the environment.

Which statement is true about the atoms in helium gas?
A. They have strong attractions to one another.
B. They are not closely packed.
C. They are arranged in an orderly pattern.
D. They travel in circular paths.

Answers

The appropriate answer is a. they are not closely packed. Molecules in a gas are not closely packed but a scattered in a rather disorderly fashion. Atoms packed or arranged in an orderly pattern are solids. Helium atoms would not have an attraction to each other because helium is an inert gas. Inert gases are nonreactive. 

The elements least likely to form bonds are found in what group

Answers

It is in the noble gas group which has a full valence electron shell found in group 18 

Answer:

Group 18

Explanation:

Group 18 comprises of Noble elements (Neon, Krypton, Argon etc). These elements have complete outer shell that is complete octet. According to octet rule, the elements which have less than 8 electrons in their valence shell tend to bond with another element in order to complete their outer shell configuration.

Thus, group 18 elements are least likely to form bonds.

Which statement about the effect of sunlight on the earth is true? A. Sunlight warms the earth unevenly. B. Sunlight warms the poles more than the equator. C. Sunlight warms the earth evenly. D. The Coriolis effect does not distribute heat.

Answers

Hi! It is A, I have had this question many times and has always got it right. thank you!

Why food coloring particles are first condensed into a single drop, but after revisiting the cup of water several minutes later, the entire cup of water is colored?

Answers

The molecules in water, being a non-frozen liquid, are constantly moving, as are the molecules in the food coloring particles. This movement causes the food coloring particles to expand, not unlike a gas, and fill the container and medium in which it exists.
Final answer:

This phenomenon is known as diffusion where food coloring particles move from a high concentration area to a lower one until a uniform concentration is achieved. Additionally, the food coloring acts as a colloidal system where particles of food coloring are dispersed in water.

Explanation:

What you're observing when you put a drop of food coloring into a clear glass of water is a phenomenon known as diffusion. Diffusion is the process by which particles of different concentrations spontaneously mix due to their inherent kinetic energy. When the food coloring is condensed into a small drop, it has a high concentration of coloring molecules compared to the surrounding water. Over time, these molecules spread out into the water, moving from an area of high concentration to one of lower concentration, until a uniform concentration is achieved throughout the entire cup.

Additionally, the food coloring operates as a colloidal system. Colloidal systems are substances microscopically dispersed evenly throughout another substance. They consist of particles of one substance (food color) dispersed in a continuous phase of another substance (water). In your scenario, the food coloring particles are initially condensed as a result of aggregation of food color molecules, forming colloidal particles.

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A light platform is suspended from the ceiling by a spring. A student with a mass of 90 kg climbs onto the platform. When it stops bouncing and reaches its new equilibrium position (x=0), the student notices that the spring has stretched 0.82 m. The student's friend pulls the platform down 0.32 m further and then releases it at t=0. What is the amplitude of the motion of the student on the platform?

Answers

Refer to the diagram shown.

When the student climbs onto the platform, the spring stretches by 0.82 m to reach the equilibrium position.
The mass of the student is m = 90 kg, so his weight is
mg = (90 kg)*(9.8 m/s²) = 882 N

By definition, the spring constant is
k = (882 N)/(0.82 m) = 1075.6 N/m

When the spring is stretched by x from the equilibrium position, the restoring force is
F = - k*x.

If damping is ignored, the equation of motion is
F = m * acceleration
or
[tex]m \frac{d^{2}x}{dt^{2}} = -kx \\ \frac{d^{2}x}{dt^{2}} + \frac{k}{m} x = 0[/tex]

Define ω² = k/m = 11.751 => ω = 3.457.
Then the solution of the ODE is
x(t) = c₁ cos(ωt) + c₂ sin(ωt)

x'(t) = -c₁ω sin(ωwt) + c₂ω cos(ωt)
When t=0, x' =0, therefore c₂ = 0

The solution is of the form
x(t) = c₁ cos(ωt)
When t = 0, x = 0.32 m. Therefore c₁ = 0.32

The motion is
x(t) = 0.32 cos(3.457t)
The single amplitude is 0.32 m, and the double amplitude is 0.64 m.

Answer: 
0.32 m (single amplitude), or
0.64 m (double amplitude)

A flagpole is perpendicular to the horizontal but iis on a slope that rises 10 degrees from the horizontal. the pole casts a 43-foot shadow down the slope and angle of elevation of the sun measured from the slope is 36 degrees. how tall is the pole?

Answers

36 ft. The flagpole and the shadow create a triangle with the angle at the base of the flagpole being 100 degrees. The angle at the end of the shadow being 36 degrees and the angle at the top of the flagpole is 180-100-36 = 44 degrees. We know the length of the shadow is 43 feet, and using the law of sines, we get sin(44)/43 = sin(36)/X where X is the height of the flagpole. So let's solve for X sin(44)/43 = sin(36)/X Xsin(44)/43 = sin(36) Xsin(44) = 43sin(36) X = 43sin(36)/sin(44) X = 43 * 0.587785252/0.69465837 X = 36.38445446 Rounding to 2 significant figures, gives us a height of 36 ft.
Final answer:

The height of the flagpole can be determined using the tangent function of geometry. It will be obtained by multiplying the tangent of 46 degrees with the length of shadow which is 43 feet.

Explanation:

This problem is a case of trigonometry, specifically dealing with the tangent of an angle. Since the pole is perpendicular to the horizontal, it forms a right triangle with the ground and the shadow. The angle of the sun and the slope of the ground at the base of the shadow form a combined angle of 46 degrees (36 degrees from the sun and 10 degrees from the slope).

According to the definition of the tangent function, which is the ratio of the length of the opposite side to the length of the adjacent side in a right triangle, we can write:

tan(46 degrees) = height of flagpole / length of shadow

Here, the shadow length is 43 feet. We can now solve for the height of the flagpole:

Height of flagpole = tan(46 degrees) * 43 feet

This calculation will give you the approximate height of the flagpole.

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How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?

450 kcal
430 kcal
280 kcal
130 kcal

Answers

Final answer:

To heat and melt 3.0 kg of copper initially at 83°C, we need to calculate the heat required for both steps: heating the copper to its melting point and then melting the copper. Heating the copper requires a certain amount of heat energy, while melting the copper requires another amount of heat energy. By adding these two amounts together, we can find the total energy needed.

Explanation:

To calculate the amount of energy needed to heat and melt 3.0 kg of copper initially at 83°C, we need to consider two steps: heating the copper to its melting point and then melting the copper.

First, we calculate the heat required to heat the copper from 83°C to its melting point (which is approximately 1084°C). We can use the formula Q = m * c * ∆T, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ∆T is the temperature change. In this case, ∆T = (1084 - 83)°C = 1001°C.

Second, we calculate the heat required to melt the copper. We can use the formula Q = m * L, where L is the latent heat of fusion. The latent heat of fusion for copper is approximately 334 kJ/kg. Since we have 3.0 kg of copper, the heat required to melt it is 3.0 kg * 334 kJ/kg = 1002 kJ.

Adding the two amounts of heat energy together, we get a total of 1002 kJ + Q from step one.

What area of the united states is characterized by fault block mountains with streams that drain into adjoining basins?

Answers

Examples of fault block mountains in the U.S. include the Sierra Nevada in California and Nevada, Death Valley and the Tetons in Wyoming. Forces of compression or tension can lead to the formation of fault block mountain ranges. The Sierra Nevada region is characterized by fault block mountains with streams that drain into adjoining basins. 

How many kilocalories are generated when the brakes are used to bring a 1200-kg car to rest from a speed of 95 km/h ? 1 kcal = 4186 j?

Answers

Answer: 1st, identify the givens and the unknown - this will give you parameter of what concept and formula are you going to use. Given: m= 1200kg v initial = 95km/hr v final = 0 2nd, focus on the units - in most cases units speak for the concept the unit of the unknown is kcal, thus its the unit of energy or work so, W = ? 3rd, provide the appropriate formula - give formula or equation that the given and the unknown are present since W = delta K.E =delta P.E W= 0.5m( vf^2 - vi^2) ---> best formula 4th, Substitute the given to the formula since 1 Joule = 1Nm 1N = 1kgms^-2 1cal = 4.19 J we express first 95 km/hr to m/s 95km/hr x 1000m/1km x 1hr/3600sec = 26.39 m/sec W= 0.5(1200kg)[(0^2- (26.39m/sec)^2] W=600 kg(0 - 696.43m^2/s^2) W=600kg(-696.43m^2/s^2) W=417859.3Nm or 417859.3 J W = 417859.3 J x 1 cal /4.19 J W = 99,727.7 cal or 99.728 kcal
Final answer:

To calculate the kilocalories generated when the brakes are used to bring a car to rest, determine the initial kinetic energy of the car using the formula KE = 0.5 * mass * velocity^2, and then convert it into kilocalories using the conversion factor 1 kcal = 4186 J.

Explanation:

To calculate the kilocalories generated when the brakes are used to bring a car to rest, we need to determine the initial kinetic energy of the car and then convert it into kilocalories using the conversion factor provided.

The initial kinetic energy of the car can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the given values, KE = 0.5 * 1200 kg * (95 km/h)^2 = 0.5 * 1200 kg * (95^2) km^2/h^2.

Now, to convert the kinetic energy from joules to kilocalories, we can use the conversion factor: 1 kcal = 4186 J. Thus, the kilocalories generated when the brakes are used to bring the car to rest would be the kinetic energy in joules divided by 4186 J/kcal.

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Calculate the orbital period of a spacecraft in an orbit 300 kilometers above earth's surface

Answers

The formula that will be used to solve this question is:
 P = 2π sqrt[ a^3 / (GM) ] where:
GM = 3.986004418 x 10^-14 m^3 sec^-2 
a = 6378000 + 300000 = 6678000 meters

Substitute in the equation to get the period as follows:
P = 2π sqrt [( 6678000 )^3 / (3.986004418 x 10^-14) ] 
P =  5431.0 seconds

The orbital period of a spacecraft at an orbit of 300 kilometers above the Earth's surface is around one hour and a half.

Further explanation

Objects, due to their inherent mass, tend to atract each other due to the laws of gravitation. In short words, objects with a huge ammount of mass atract other objects which are less massive, that is why we are all attracted towards the Earth (which is an incredible massive body).

In general this phenomenon is better seen at the astrological level, like planets attracting their moons or asteroids (this is the case of our problem). Even though, planets attract other bodies which are nearby, this doesn't mean that they will ever come into contact, this is the case for object which orbit those planets.

An orbit is a path which a certain body follows around a more massive object, like the moon orbiting the Earth, or the Earth orbiting around the Sun. These orbits are periodic, meaning they happen continuously over time, over and over again, the same way all times. By this reason, they have a period (which is the duration of such orbit).

At this point, there is a background theory that is necessary to derive the equation we're going to use to compute the orbital period, but it escapes the scope of this problem, so we're just going to use the equation. The equation to compute the orbital period is:

[tex]T= 2 \cdot \pi \cdot \sqrt{\frac{a^3}{\mu}}[/tex]

Where a is the distance between the orbiting object (in this case, the spacecraft) and the center of the orbited object (in this case the Earth), and [tex]\mu[/tex] is a constant dependent on the orbited object, it's called Standard Gravitational Parameter, for the Earth it has a value of [tex]3.986 \cdot 10^{14} \cdot \frac{m^3}{s^2}[/tex].

Since the radius of the Earth is 6371 Km, then a would be 6671 Km. Plugging values on the formula, and making sure to apply the correct units (notice how a is expressed in Km and [tex]\mu[/tex] has units of meter cube), we get that the orbital period is 5422 seconds, which is around one hour and half.

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Orbit, gravitation, Earth, attraction laws

What organic materials make up limestone? What type of mineral and what percent of it determine if a rock is limestone?

Answers

Limestone is a sedimentary rock composed primarily of calcium carbonate (CaCO3) in the form of the mineral calcite. It most commonly forms in clear, warm, shallow marine waters. It is usually an organic sedimentary rock that forms from the accumulation of shell, coral, algal, and fecal debris. It can also be a chemical sedimentary rock formed by the precipitation of calcium carbonate from lake or ocean water.

Calcium carbonate is one f the most commonly found material found in limestone rocks. The composition of calcium and magnesium as it commonly made of fossils, shells, and debris.

Calcite is a mineral that is highly found in limestone. More than 50 % of the rocks are made from this mineral. About 95% of calcite and 5% is dolomite. Other minerals include quartz, feldspar, clay minerals, pyrite, siderite in small percentages.

Hence the rocks can be easily be identified by the white to grayish color and presence of lime content in rocks.

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A wheel rotating at 2000 rpm is braked and comes to rest in 30 seconds. How many revolutions did the wheel rotate through before coming to rest?

Answers

ω = 2000 rpm, initial angular speed.
[tex]\omega = (2000 \, \frac{rev}{min} )*(2 \pi \, \frac{rad}{rev} )*( \frac{1}{60}\, \frac{min}{s} ) = 209.4395 \, \frac{rad}{s} [/tex]
t = 30 s, the time for the wheel to come to rest.

Calculate the angular deceleration, α.
w - αt = 0
(209.4395 rad/s) - (α rad/s²)*(30 s) = 0
α = 6.9813 rad/s²

The angular distance traveled, θ, is given by
ω² - 2αθ = 0
θ = ω²/(2α)
   = 209.4395²/(2*6.9813)
   = 3141.6 rad

The number of revolutions is
3141.6/(2π) = 500

Answer: 500 revolutions

During a softball game, a shortstop catch a ground ball. The action forces is the ball pushing on the glove. What is the reaction?

A. The fielder pushing on the ball

B. The ball pushing on the ground

C. The glove pushing on the ball

D. The ground pushing on the ball

Answers

The reaction force would be the exact opposite of the action. In this case, choice (c) would be the most correct. If the action is the ball pushing the glove, the reaction would then be the glove pushing back on the ball.

Answer:

The answer is C. The glove pushing on the ball. I took a test that had this exact question and it was correct.

In a bwr or pwr, steam is generated with a temperature of about 290 °c. if river water used to receive waste heat has a temperature of 20 °c, what is the maximum possible (ideal) conversion efficiency of the reactor's thermal energy into electrical energy? nuclear power plants typically have conversion efficiencies of 34%. why is this efficiency less than the ideal efficiency?

Answers

the answer is The power will decrease to 75 percent of its previous value

Final answer:

Efficiency comparison between theoretical and actual values in power plants due to various factors.

Explanation:

The maximum theoretical efficiency of a heat engine operating between 300°C and 27°C can be calculated using the Carnot efficiency formula.

The ideal efficiency in this case would be 67%.

The actual efficiency of nuclear power plants is lower than the ideal efficiency due to losses in energy conversion, limitations of materials, and safety considerations.

Efficiency in real-world applications is affected by factors like temperature limitations, friction losses, and energy transfer inefficiencies.

Ball 1 is thrown into the air and it follows the trajectory for projectile motion shown in the drawing. at the instant it is at the top of its trajectory, ball 2 is dropped from rest at the same height. just before they reach the ground, the velocity of ball 1 has a horizontal component vx and a vertical component vy. ball 2 only has a vertical component. which ball has the greater vertical component?

Answers

The two balls have the same vertical velocity. This is because they begin they're downward motion at the same time. Downward motion is determined by gravity and air resistance in the vertical dimension, which are both equal for the two balls. Therefore, the vertical component of velocity is the same.

Which statement about the horizontal distance covered by a projectile launched at an angle less than 90° is true?

Answers

The answer is A because the distance covered is equal time intervals is the same or equal.

Answer:

The distance covered in equal time intervals is equal.

Explanation:

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. you may want to review ( pages 293 - 295) . part a if a boat and its riders have a mass of 1000 kg and the boat drifts in at 1.3 m/s how much work does sam do to stop it

Answers

The work done by Sam to stop the coming boat in the amusement park is  [tex]\boxed{845\,{\text{J}}}[/tex].

Further Explanation:

As the boat in the amusement park is moving at a certain velocity, the boat has the kinetic energy stored in it. This kinetic energy of the boat is due to the motion of the boat.

Sam needs to do the work against this energy of the boat to bring it to rest.

The initial kinetic energy of the boat is expressed as:

[tex]\begin{aligned}{K_i}&= \frac{1}{2}m{v^2}\\&=\frac{1}{2} \times 1000 \times {\left( {1.3} \right)^2}\\&= \frac{{1690}}{2}\,{\text{J}}\\&= 8{\text{45}}\,{\text{J}}\\\end{aligned}[/tex]

The boat is brought to rest finally. So, the final kinetic energy of the boat will be  .

The amount of work required to be done by Sam will be equal to the change in kinetic energy of the boat.

[tex]\begin{aligned}W&= {K_f} - {K_i}\\&=0 - 845\\&=- 845\,{\text{J}}\\\end{aligned}[/tex]

Here, the negative work done means that the work is to be done by Sam on the boat in the opposite direction to stop it.

Thus, the work done by Sam to stop the coming boat in the amusement park is  [tex]\boxed{845\,{\text{J}}}[/tex].

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Answer Details:

Grade: College

Subject: Physics

Chapter: Work-Energy Theorem

Keywords:  Sam’s job, amusement park, slow down, boats in the long ride, kinetic energy, work done, boat drift at 1.3m/s, to stop the boat, energy stored in boat.

Final answer:

Sam performs -650 Joules of work to bring the boat to a halt. The negative sign is conventionally used to show that energy has been removed from the system.

Explanation:

To answer your question, we will use the physics concept of work and kinetic energy. Work done on an object is equal to the change in its kinetic energy. In this case, Sam has to stop the boat from its current speed to a rest state. That means the initial kinetic energy of the boat is 0.5*1000 kg*(1.3 m/s)^2 and the final kinetic energy is 0, since it's stopped.

The work Sam does stopping the boat is equal to the change in kinetic energy, which is final kinetic energy - initial kinetic energy. This will result in -650 Joules.

The negative sign indicates that energy has been taken out of the system - in this case by Sam slowing down the boat. It's important to note, however, that in the real world work has to be done against things such as water resistance, but these factors were not included in the question and therefore not considered in the answer.

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Compute the flux of the vector field f⃗ =xi⃗ +yj⃗ +zk⃗ through the surface s, which is a closed cylinder of radius 1, centered on the x-axis, with −1≤x≤1, and oriented outward.

Answers

Final answer:

To compute the flux of a vector field through a closed cylinder, we can calculate the flux through the flat ends (which is zero) and the curved surface. Using the formula for flux, we can integrate the vector field over the curved surface to find the flux. Finally, the total flux is the sum of the fluxes through the flat ends and the curved surface.

Explanation:

To compute the flux of the vector field ᴳᵃ = ᴿxᵃ + ᴿyᵃ + ᴿzᵃ through the surface s, which is a closed cylinder of radius 1, centered on the x-axis, with -1 ≤ x ≤ 1, and oriented outward, we can use the formula:

∫ ᴳᵃ · ᵙA = ∫ ᴳᵃ · ᵣ ᴾ/

Calculate the flux through the flat ends of the cylinder. Since the normal vector points in the same direction as the vector field, the flux through each end is zero.Calculate the flux through the curved surface of the cylinder. Since the normal vector is perpendicular to the vector field, the flux through the curved surface can be computed as:

∫ ᴳᵃ · ᵣ ᴿ = ∫ ᴿxᵃ · ᵣ ᴿ + ∫ ᴿyᵃ · ᵣ ᴿ + ∫ ᴿzᵃ · ᵣ ᴿ

Substituting the values, we get:

∫ ᴳᵃ · ᵣ ᴿ = ∫ (x)(dx)(dz) + ∫ (y)(dy)(dz) + ∫ (z)(dz)(dx)

Integrating with respect to x, y, and z within the given limits, we can find the flux through the curved surface. Finally, the total flux through the surface s is the sum of the fluxes through the flat ends and the curved surface.

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Final answer:

To compute the flux of the vector field through the surface of a closed cylinder, we can use Gauss's Law for Electromagnetism. The flux is given by the surface integral of the dot product between the vector field and the outward normal vector over the surface. First, compute the flux through the flat ends of the cylinder. Next, compute the flux through the curved surface. Add the flux through the flat ends and the curved surface to obtain the total flux through the surface.

Explanation:

To compute the flux of the vector field ƒ = xi + yj + zk through the surface S, which is a closed cylinder of radius 1 centered on the x-axis, we can use Gauss's Law for Electromagnetism. The flux is given by the surface integral of the dot product between the vector field and the outward normal vector over the surface S.

First, compute the flux through the flat ends of the cylinder. Since the vector field is perpendicular to the surface at these points, the dot product simplifies to the magnitude of the vector field times the area of the end faces. Next, compute the flux through the curved surface. Use the fact that the outward normal vector is parallel to the vector field at each point on the curved surface. Therefore, the dot product simplifies to the magnitude of the vector field times the area of the curved surface. Add the flux through the flat ends and the curved surface to obtain the total flux through the surface S.

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The table lists the values for two parameters, x and y, of an experiment. What is the approximate value of y for x = 4.0?

x y
2.5 6.25
9.4 88.36
15.6 243.63
19.5 380.25
25.8 665.64




11.00

17.85

24.10

43.20

Answers

Solving for the two unknowns using systems of linear equations (substitution or elimination method):
m= 11.9; b=-23.5

y=11.9x - 23.5
y=11.9*4-23.5
y=24.1
Therefore when x=4, the approximate value of y is 24.1

Answer:

The approximate value for x=4 is y=24.1

Explanation:

A practical method easy to use is the linear interpolation. In this procedure, the approximation is done using the secant line between the two nearest points. In this particular case those points are:

P1: (2.5,6.25)

P2:(9.4,88.36)

Where the first coordinate corresponds to the x coordinate and the second coordinate to the y coordinate. The expression to compute the secant line is:

[tex]y-yo=m*(x-xo)[/tex]

Here m is the slope of the line and is calculated from:

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

And xo, yo could be the x and y coordinate of any of P1 or P2 points. Thus, for the present coordinates:

[tex]m=\frac{88.36-6.25}{9.4-2.5}[/tex]

[tex]m=11.9[/tex]

Choosing P1 coordinates as the xo and yo coordinates:

[tex]y-6.25=11.9*(x-2.5)[/tex]

Them replacing the estimation value of x=4 and solving for y:

[tex]y-6.25=11.9*(4-2.5)[/tex]

[tex]y=11.9*(1.75)+6.25[/tex]

[tex]y=24.1[/tex]

What is the approximate size of the smallest object on the earth that astronauts can resolve by eye when they are orbiting 250 km above the earth? assume λ = 500 nm and a pupil diameter of 5.00 mm?

Answers

Final answer:

The approximate size of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth is approximately 8.2 mm.

Explanation:

The approximate size of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth can be calculated using the formula for the minimum resolvable angle, which is given by:

θ = 1.22 * (λ / D)

where θ is the minimum resolvable angle, λ is the average wavelength of light (500 nm), and D is the diameter of the pupil (5.00 mm).

By rearranging the formula and solving for D, we can find:

D = λ / θ = (500 nm) / (1.22 * (250 km))

After converting the units to meters, we get:

D ≈ 8.2 mm

Therefore, the approximate size of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth is approximately 8.2 mm.

Learn more about size of smallest object on Earth here:

https://brainly.com/question/42794654

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Thin, cylindrical receptor cells in the retina that are highly sensitive to light are called?

Answers

rod photoreceptors- cylindrical in shape; sensitive to light; found in the retina; one of the two types of photoreceptors (rods and cones)

"copernicus demonstrated that the earth was not the center of the solar system. we now know that our solar system is not the center of our galaxy, and that our galaxy is not the center of the universe. so let me suggest that in all probability none of us should take ourselves so seriously that we think we are the center of everything." the previous passage is best described as __________.

Answers

Final answer:

The passage explains the Copernican Principle and its implications on our understanding of our place in the universe.

Explanation:

The passage you provided can be best described as an explanation of the Copernican Principle and its implications on our understanding of our place in the universe. The Copernican Principle, named after Nicolaus Copernicus, states that Earth is not the center of the solar system, and this idea has expanded to understand that our solar system is not the center of our galaxy and our galaxy is not the center of the universe. This perspective reminds us that we should not view ourselves as the center of everything.

Can you build a particle accelerator at home ?

Answers

No, I know what you are talking about it is the flash right! I love that show!!!!!!!!!!!!!!!!!!!!!!!!!  Also it is scientifically impossible but you could build a portrait of it, i know I want to become the flash too! good luck!

Building a high-energy particle accelerator similar to SLAC or CERN's Large Hadron Collider at home is not feasible due to technical and space requirements. However, a simple Van de Graaff generator can be constructed for demonstration purposes.

Building a particle accelerator at home is an incredibly ambitious project and not realistically achievable for the high-energy collisions seen in facilities like SLAC and CERN. These complex machines often span large distances, like the 27 kilometers of the Large Hadron Collider (LHC), and require sophisticated technologies to accelerate particles to speeds close to the speed of light and manage their path using powerful magnets. A simple form of a particle accelerator, like a Van de Graaff generator, can be built for educational purposes, but it cannot produce the high energy needed to explore subatomic particles. Major limitations for building small, high-energy accelerators include the need for large radii to achieve higher energies, as exemplified by CERN's LHC, and the theoretically impossible size required for an accelerator that could reach Planck energy, as explained in Challenge 39, page 83 of the textbook reference.

Instruments on board the trmm (tropical rainfall measuring mission) satellite show 3d images of very tall rain columns called _____.

Answers

These columns are called hot towers

A 1.20 g sample of an unknown has a volume of 1.73 cm what is the density of the unknown

Answers

1.73 divide by 1.20=1.4416

Final answer:

The density of the unknown substance with a mass of 1.20 g and volume of 1.73 cm³ is found by dividing the mass by the volume, yielding approximately 0.694 g/cm³.

Explanation:

The question involves calculating the density of an unknown substance given its mass and volume. To find the density, the formula Density = Mass/Volume is used. In this case, the mass of the unknown substance is 1.20 grams (g) and its volume is 1.73 cubic centimeters (cm³).

Using the formula:

Density = Mass/Volume
Density = 1.20 g / 1.73 cm³
Density = 0.693641618497 g/cm³

Thus, the density of the unknown is approximately 0.694 g/cm³ (rounded to three decimal places).

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