What is the area of rhombus ABCD ? Enter your answer in the box. Do not round at any steps. units² Rhombus A B C D on a coordinate plane with vertex A at 1 comma 0, vertex B at 7 comma negative 2, vertex C at 1 comma negative 4, and vertex D at negative 5 comma negative 2. Point P is at negative 3.8 comma 1.6. Dashed segments join point P to point D and point P to point A, forming right angle D P A.

The solution to the equation 2/9w=24 is found by multiplying both sides by the reciprocal of 2/9, which is 9/2, to isolate w. Simplifying further, we get w = 54.

To solve the equation 2/9w=24, we start by isolating the variable w. To do this, we can multiply both sides of the equation by the reciprocal of the fraction that is multiplying w, which is 9/2.

The steps are as follows:

So the solution to the equation is w=54.

To solve the equation 2/9w = 24, multiply both sides of the equation by the reciprocal of 2/9. Simplify the expression to find the value of w, which is 108.

To solve the equation 2/9w = 24, we need to isolate the variable w. To do this, we can multiply both sides of the equation by the reciprocal of 2/9, which is 9/2. This gives us:

w = 24 * (9/2)

Simplifying the right side, we have:

w = 24 * 9 / 2

w = 216 / 2

w = 108

Therefore, the solution to the equation is w = 108.

4 Aces, 4 2's, 4 3's 4 4's

= 16 cards total out of 52 cards

 so probability would be 16/52 which reduces to 4/13

the probability of selecting a card smaller than 5 is [tex]\ = \frac{2}{5} \).[/tex]

Step 1

To calculate the probability of selecting a card with a number smaller than 5 (considering the ace as 1), we need to determine how many cards meet this condition and divide it by the total number of cards in the deck.

There are 4 suits in a standard deck of cards, each with cards numbered from 1 to 10 (excluding face cards).

For each suit, the numbers smaller than 5 are 1, 2, 3, and 4.

Step 2

So, for each suit, there are 4 cards smaller than 5.

Since there are 4 suits, the total number of cards smaller than 5 is [tex]\(4 \times 4 = 16\).[/tex]

Step 3

The total number of cards in the deck is [tex]\(4 \times 10 = 40\)[/tex], considering 4 suits with 10 cards each.

Therefore, the probability of selecting a card smaller than 5 is [tex]\( \frac{16}{40} = \frac{2}{5} \).[/tex]

Answer:

it will take less than one day.

Step-by-step explanation:

A circuit board manufacturer can produce 2,000 boards per hour.

If the company has a 10 hour work shift.

manufacturer can produce in one day  = 2000 × 10 = 20,000

To produce 16,500 boards, they need time = 16,500 ÷ 2000  = 8.25 hours

The company will take to produce 16,500 boards in 8.25 hours less than one day.

1/4a + 1/3a +8 =22

1st step add like terms:

1/4a +1/3a = 3/12a +4/12a = 7/12a

7/12a +8 =22

2nd step subtract 8 from each side:

7/12a = 14

3rd step divide both sides by 7/12 to get a:

a = 14 / 7/12

a = 24

Answer:

.

Step-by-step explanation:

1/4a + 1/3a +8 =22

1st step add like terms:

1/4a +1/3a = 3/12a +4/12a = 7/12a

7/12a +8 =22

2nd step subtract 8 from each side:

7/12a = 14

3rd step divide both sides by 7/12 to get a:

a = 14 / 7/12

a = 24

Answer:

The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are [tex]n^3t^2[/tex] and [tex]nt^4[/tex].

The factored form of each term is

[tex]n^3t^2=n\times n\times n\times t\times t[/tex]

[tex]nt^4=n\times t\times t\times t\times t[/tex]

To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

[tex]LCM(n^3t^2,nt^4)=n\times n\times n\times t\times t\times t\times t[/tex]

[tex]LCM(n^3t^2,nt^4)=n^3t^4[/tex]

The LCM of given terms is [tex]n^3t^4[/tex]. Therefore the correct option is C.

Answer: C) n 3t^4

Step-by-step explanation:

Definition : The least common multiple (LCM) of any two expressions is the smallest expression that is divisible by both expressions.

Given expressions : [tex]n^3 t^2 \text{ and } nt^4[/tex]

Factorization form of [tex]n^3 t^2 \text{ and } nt^4[/tex] will be :

[tex]n^3 t^2 =n\times n\times n\times t\times t[/tex]

tex]nt^4 =n \times t\times t\times t\times t[/tex]

The least common multiple of [tex]n^3 t^2 \text{ and } nt^4[/tex] :

[tex]n^3 t^2 =n\times n\times n\times t\times t\times t\times t=n^3t^4[/tex]

Hence, the LCM of   [tex]n^3 t^2 \text{ and } nt^4=n^3t^4[/tex]

Thus , the correct answer is option C).

Answer: addition

Step-by-step explanation:

Rounding 871 to the nearest ten gives us 870.

We have,

To round 871 to the nearest ten, we look at the ones digit, which is 1.

If the ones digit is 5 or greater, we round up to the next ten.

If the ones digit is less than 5, we round down to the previous ten.

In this case, the ones digit is 1, which is less than 5.

Therefore, we round down.

Rounding 871 to the nearest ten gives us 870.

Thus,

Rounding 871 to the nearest ten gives us 870.

Learn more about expressions here:

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This would be a 20% decrease. Since your going from 70 to 56, you would have a percentage of 20 for your decreasing percentage. The difference total is -14.

Step-by-step explanation:

Total Number = 70

Difference of two numbers = 70-56

= 14

Converting into percent = 14/70×100

= 20%