What is ΔH∘rxn for the following chemical reaction? CS2(g)+2H2O(l)→CO2(g)+2H2S(g) You can use the following table of standard heats of formation (ΔH∘f) to calculate the enthalpy of the given reaction. Element/ Compound Standard Heat of Formation (kJ/mol) Element/ Compound Standard Heat of Formation (kJ/mol) H(g) 218 N(g) 473 H2(g) 0 O2(g) 0 H2O(l) −285.8 O(g) 249 CS2(g) 116.7 H2S(g) −20.60kJ C(g) 71 CO2(g) −393.5kJ C(s) 0 HNO3(aq) −206.6 Express the standard enthalpy of reaction to three significant figures and include the appropriate units. View Available Hint(s)

Answer:

There are many possible combinations of atoms

Explanation:

Atoms in the periodic table can combine in a myriad of ways – sometimes quoted to approximately 10^78 combinations.  To understand the enormity, carbon (and its ability to form numbers combination with other elements) is the main element significant in the variations of organic life on earth.

Answer:

There are many possible combinations of atoms

Explanation:

This is based on the Law of Multiple Proportion. Two different elements can combine in different ratio to create multiple compounds. Let’s take the example of CO and CO₂. In carbon monoxide there is 1:1 ratio of C:O and in carbon dioxide the ration of C:O is 1:2. Because of the difference in combination ratios of the individual elements the two compounds have different physical and chemical property.

It is a star, since it glows and is very hot.

= 13.629 g of ZnCl2

The equation for the reaction.

Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g)

Number of moles of Zinc;

Moles = mass/RAM

          = 6.5 g/65g/mol

          = 0.1 moles

The mole ration of Zn : ZnCl2 is 1 : 1

Therefore, number of moles of ZnCl2 is 0.1 moles

Mass = moles × Molar mass

         = 0.1 ×136.286 g/mol

        = 13.629 g

Using the balanced equation Zn + 2HCl —> ZnCl₂ + H₂, we find that 6.5 g of Zinc produces 13.55 grams of Zinc Chloride.

First, let's write the balanced equation:

The number of moles of Zn is:

From the balanced equation, we know that 1 mole of Zn reacts to form 1 mole of ZnCl₂. Therefore, the number of moles of ZnCl₂ produced is:

Now, let's calculate the mass of ZnCl₂ produced:

Therefore, if 6.5 g of Zn is used, the mass of ZnCl₂ produced is 13.55 g.

Burning fossil fuels release energy in the form of heat.

The following molecules can exhibit hydrogen bonding as a pure liquid is NH3 (amonia), HC3 -- O -- OH (methanol), CH3CO2H (acetic acid)

Hydrogen bonding is directly connected to Nitrogen, Oxygen, and Fluoride and it (N, O, F) represents the hydrogen bonding. Whereas molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound

Identify which of the following molecules can exhibit hydrogen bonding as a pure liquid.

Grade:  9

Subject:  chemistry

Chapter:  hydrogen bonding

Keywords: hydrogen bonding, molecules, amonia, tetrafluoromethane, benzaldehyde

The molecules that exhibit hydrogen bonding are ammonia NH3, acetic acid CH3CO2H and H2C20H

Hydrogen bonding refer to am electrostatic force of attraction that exist between a hydrogen atom which is covalently bonded together to an atom that is more electronegative and another electronegative atom that have a lone pair of electrons. the hydrogen bond is the acceptor.

Therefore, The molecules that exhibit hydrogen bonding are ammonia NH3, acetic acid CH3CO2H and H2C20H.

The question is incomplete bit the options are gotten from another website. here are the options below.

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After electrolysing ZnI2, iodine crystals are formed, therefore, the answer is solid.

Answer:

[OH⁻] = 1.0 x 10⁻⁹ M.

Explanation:

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(1.0 x 10⁻⁵) = 1.0 x 10⁻⁹ M.

Answer:

A. mL/s.

Explanation:

Rate of the reaction = Δ[C]/Δt.

If we take the volume (mL) expressing the concentration. So, the unit of the rate of the reaction is (mL/s).

It is C. An increase of temperature results in an increase in kinetic energy of the molecules of the substance.  For example, in a gas the molecules will move about faster.

Answer:

3. ΔH = 0.30 kJ; 4. ΔH = -84.6 kJ

Step-by-step explanation:

Question 3:

We have three equations:  

(I)  S(r) + O₂ → SO₂;         ΔH = -296.06 kJ

(II) S(m) + O₂ ⟶ SO₂;     ΔH = -296.36 kJ

From these, we must devise the target equation:  

(III) S(r) ⟶ S(m);              ΔH = ?  

The target equation has 1S(r) on the left, so you rewrite Equation(I).

(IV) S(r) + O₂ ⟶ SO₂;      ΔH = -296.06 kJ  

Equation (IV) has 1SO₂ on the right, and that is not in the target equation.  

You need an equation with 1SO₂ on the left, so you reverse Equation (II).  

When you reverse an equation, you change the sign of its ΔH.  

(V)  SO₂ ⟶ S(m) + O₂ ;     ΔH = 296.36 kJ

Now, you add equations (IV) and (V), cancelling species that appear on opposite sides of the reaction arrows.

When you add equations, you add their ΔH values.

We get the target equation (III)

(IV) S(r) + O₂ ⟶ SO₂;       ΔH = -296.06 kJ  

(V)  SO₂ ⟶ S(m) + O₂;      ΔH =  296.36 kJ

(III) S(r) ⟶ S(m);                ΔH =       0.30 kJ

Question 4  

We have three equations:  

(I)  C + O₂ ⟶ CO₂;                                ΔH = -393.5 kJ

(II) H₂ + ½O₂ ⟶ H₂O;                           ΔH = -285.8 kJ

(III) 2C₂H₆ + 7O₂ ⟶ 4CO₂ + 6H₂O;     ΔH = -296.8 kJ

From these, we must devise the target equation:  

(IV) 2C + 3H₂ → C₂H₆; ΔH = ?  

The target equation has 2C on the left, so you double Equation(I).

When you double an equation, you double its ΔH.

(V) 2C + 2O₂ ⟶ 2CO₂;                          ΔH = -787.0 kJ

Equation (V) has 2CO₂ on the right, and that is not in the target equation.  

You need an equation with 2CO₂ on the left, so you reverse Equation (III) and divide it by 2.

(VI) 2CO₂ + 3H₂O ⟶ C₂H₆ + ⁷/₂O₂;     ΔH = 148.4 kJ

Equation (V) has 3H₂O on the left, and that is not in the target equation.

You need an equation with 3H₂O on the right. Triple Equation (III).

(VII) 3H₂ + ³/₂O₂ ⟶ 3H₂O;                   ΔH = -857.4 kJ

Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.

We get the target equation (IV).

(V)     2C + 2O₂ ⟶ 2CO₂;                      ΔH =  -787.0 kJ

(VI)   2CO₂ + 3H₂O ⟶ C₂H₆ + ⁷/₂O₂;     ΔH = 1559.8 kJ

(VII) 3H₂ + ³/₂O₂ ⟶ 3H₂O;                     ΔH = - 857.4 kJ

(IV)  2C + 3H₂ → C₂H₆;                            ΔH =    -84.6 kJ

acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.

so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base

(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.

Answer: a) [tex]C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)[/tex]

bronsted- lowry acid : [tex]H_2O[/tex]

conjugate base : [tex]OH^-[/tex]

bronsted- lowry base : [tex]C_5H_5N[/tex]

conjugate acid : [tex]C_5H_5NH^+[/tex]

b) [tex]HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)[/tex]

bronsted-lowry acid : [tex]HNO_3[/tex]

conjugate base : [tex]NO_3^-[/tex]

bronsted- lowry base : [tex]H_2O[/tex]

conjugate acid : [tex]H_3O^+[/tex]

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

a) [tex]C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)[/tex]

Here, [tex]H_2O[/tex] is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms [tex]OH^-[/tex] which is a conjugate base.

And, [tex]C_5H_5N[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]C_5H_5NH^+[/tex] which is a conjugate acid.

b) [tex]HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)[/tex]

Here, [tex]HNO_3[/tex] is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms [tex]NO_3^-[/tex] which is a conjugate base.

And, [tex]H_2O[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]H_3O^+[/tex] which is a conjugate acid.

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of carbon is 6 and its electronic configuration is [tex]1s^{2}2s^{2}2p^{2}[/tex].

Atomic number of oxygen is 8 and its electronic configuration is [tex]1s^{2}2s^{2}2p^{4}[/tex].

Atomic number of titanium is 2 and its electronic configuration is [tex][Ar]4s^{2}3d^{2}[/tex].

Atomic number of silicon is 14 and its electronic configuration is [tex][Ne]3s^{2}3p^{2}[/tex].

Therefore, we can conclude that out of the given options all the 4 elements have 2 unpaired electrons in the ground state.

Among Carbon (C), Oxygen (O), Titanium (Ti), and Silicon (Si), only Carbon (C) and Silicon (Si) have 2 unpaired electrons in their ground state.

The question is asking how many of the following elements: Carbon (C), Oxygen (O), Titanium (Ti), and Silicon (Si) have 2 unpaired electrons in the

ground state

. In a

ground state

, an atom's electrons are all in the lowest possible energy levels. Carbon has 2 unpaired electrons, as its electron configuration ends in 2s^22p^2. Silicon, similar to carbon, also has 2 unpaired electrons with electron configuration ending in 3s^23p^2. However, Oxygen (2s^22p^4) and Titanium (3d^24s^2) do not have 2 unpaired electrons in their ground state, the answer is therefore (d) 2.

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Answer : The number of valence electron present in an element is, 1

Explanation :

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.  

Number of electrons in an atom are determined by the electronic configuration.

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

The given electronic configuration of an element is,

[tex]1s^22s^1[/tex]

That means, the element has 1 valence electrons.

The element has 1 valence electron.

The electron configuration of an element is 1s22s1. To determine the number of valence electrons, we look at the highest energy level, which is indicated by the last number in the electron configuration. In this case, the highest energy level is the 2s level. Therefore, the element has 1 valence electron.

Answer:

1.0 x 10⁻⁸ M.

Explanation:

∵ [H⁺][OH⁻] = 10⁻¹⁴.

∵ [H⁺] = 100 [OH⁻].

∴ 100 [OH⁻][OH⁻] = 10⁻¹⁴.

∴ 100 [OH⁻]² = 10⁻¹⁴.

[OH⁻]² = 10⁻¹⁴/ 100 = 1.0 x 10⁻¹⁶.

∴ [OH⁻] = √(1.0 x 10⁻¹⁶) = 1.0 x 10⁻⁸ M.

Given the data from the question, the value of the concentration of the hydroxide ion OH¯ is 1×10¯⁸ M

This is simply a measure of the acidity / alkalinity of a solution.

The pH measures the hydrogen ion, H⁺ concentration while the pOH measures the hydroxide ion, OH¯ concentration

[H⁺] × [OH¯] = 10¯¹⁴

From the question given above, the following data were obtained:

[H⁺] × [OH¯] = 10¯¹⁴

100[OH¯] × [OH¯] = 10¯¹⁴

100 × [OH¯]² = 10¯¹⁴

Divide both side by 100

[OH¯]² = 10¯¹⁴ / 100

[OH¯]² = 10¯¹⁶

Take the square root of both side

[OH¯] = √(10¯¹⁶)

[OH¯] = 1×10¯⁸ M

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It is possible yes, however it is more likely not to happen. Stoves do not produce CO unless it is in use, and then you could relatively only get carbon monoxide poisoning if you were in a confined space.

Yes, you can get carbon monoxide poisoning from a gas stove if it is not properly adjusted or ventilated. CO is an odorless, colorless gas that can cause serious health effects, and carbon monoxide detectors are essential for detecting its presence.

Carbon monoxide (CO) is a colorless, odorless gas that can cause serious health issues such as headaches, dizziness, nausea, and even death when inhaled in large amounts. In a household setting, CO levels without gas stoves range from 0.5 to 5 parts per million (ppm), but near a gas stove, especially one that is poorly adjusted, levels can be significantly higher.
Carbon monoxide is produced from the incomplete combustion of hydrocarbon fuels, a process that can occur with gas stoves if they are not properly ventilated. Inhaling high levels of CO can replace oxygen in the blood, leading to serious health consequences. Using carbon monoxide detectors in the home is crucial for safety, as they can alert residents to dangerous levels of CO and help prevent carbon monoxide poisoning.

A group or family on the periodic table is one of the vertical sections on the table. A period is a horizontal section

The neutron. It is neutral and found inside the nucleus with positive protons.

I would say that bees play a vital role in our ecosystem because they produce honey which many animals on the food web eat. Though they are on the lower end of the food web it would still cause many problems because they pollinate flowers. If they did not do that anymore there would be problems with the flowers,etc. Biodiversity is another problem because without them there won’t be as much diversity in our ecosystem and some organisms might die out.

Final answer:

Bees are key pollinators vital for plant reproduction and food production. Their loss would significantly disrupt food webs and could lead to the collapse of ecosystems. The uncertainty of other pollinators filling their role makes bee conservation critical.

Explanation:

Bees play a crucial role in our ecosystems and their extinction would have dramatic consequences for biodiversity, food webs, and the global food supply. Bees are key pollinators, facilitating the reproduction of many flowering plants. The mutualistic relationship between bees and plants is essential for the production of fruits, vegetables, and nuts.

Pesticides, which have been known to kill bees, disrupt this balance and can lead to reduced food yields. The ecological importance of bees extends to their contribution to biodiversity, which is vital for the stability and health of ecosystems. If bees were to go extinct, not only would food production be jeopardized, but entire ecosystems could collapse, affecting all species within them, including humans.

Moreover, bees are part of complex food webs, and their loss would trigger a domino effect, potentially causing the extinction of other species. While some may posit that other pollinators would replace bees, the unique role bees play makes it uncertain that other species could fully compensate for their absence, particularly in the case of certain crops.

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

-Julie

0.5 M HBr, pOH = 13.5 ; Has the lowest pH

From the question;

pH = -Log [OH]

or pH = 14 - pOH

Therefore;

For 0.5 M HBr

[H+] = 0.5 M

pH = - Log [0.5]

     = 0.30

For;  pOH = 13.5

pH = 14 - pOH

     = 14 -13.5

     = 0.5

For; 0.05 M HCl

pH = - log [H+]

[H+] = 0.05

pH = - Log [0.05]

     = 1.30

For; pOH = 12.7

pH = 14 -pOH

     = 14 -12.7

     = 1.30

For;  0.005 M KOH,

pOH = - log [OH]

[OH-] = 0.005

pOH = - Log 0.005

        = 2.30

pH = 14 - 2.30

     = 11.7

For; pOH = 2.3

   pH = 14 -pOH

         = 14- 2.3

         = 11.7

Answer:

solution A, pOH = 1.5

0.5 M HBr, pOH = 13.5

Explanation:

I got it correct on e d g e n u i t y

Have a good day :D

C: incorrect. It caught you. There is only 1 molecule of C6H12O6 that you are given. That means there are 24 atoms in all for that glucose. Don't worry. I got caught as well. I was about to write a note saying that it should be the answer. It shouldn't.

A: has three atoms per molecule. There are 6.02 * 10^23 molecules - an incredibly large number which becomes 3 times its size when you ask about this in moles. Still A, large as it is , is not the answer.

B: H2O2 has 4 atoms per molecule. 4 mols have 4 * 6.02*10^23 atoms in a mol of H2O2.  Read this sentence and A very carefully. There is 1 mol of CO2 which equals 3 * 6.02*10^23 atoms in 1 mol of CO2 which has 6.02 * 10^23 molecules per mole. Be sure you understand the difference.

B is the answer.

D and E are parts of a mol. They are bigger than C (much) but much smaller than A or B.

The molecular weight has nothing to do with your answer. Please read B and A until you understand them.

C, ionic compounds have high boiling and melting points as the bonds are very strong and require tons of energy to break.

Answer:

Explanation:

I just did this question on my quiz and C was correct.

Answer:

B. Keq = [SO₃][NO]/[SO₂][NO₂].

Explanation:

Keq = [products]/[reactants].

∴ Keq = [SO₃][NO]/[SO₂][NO₂].

rate = k{A}^2{B}^2

When having a reaction both need to be included, so we know that D wouldn't work for us. But since they are being combined they would both be squared with 2. Then they would form compounds of C and D.

5Sb2O3 + 2SbCl3 -> 3Sb4O5Cl2

The coefficient of Sb2O3 in the equation is 5.

Final answer:

The coefficient of antimony(III) oxide in the balanced chemical equation for the reaction to produce Sb4O5Cl2(s) is 4.

Explanation:

The student is asking for the coefficient of antimony(III) oxide in the balanced chemical equation for the reaction to produce Sb4O5Cl2(s). This substance can be prepared by reacting antimony(III) oxide (Sb2O3) with antimony(III) chloride (SbCl3).

To find the coefficient, we need to balance the equation. Let's consider 'a' as the coefficient for Sb2O3 and 'b' for SbCl3. The possible reaction would be:

a Sb2O3(s) + b SbCl3(s) → Sb4O5Cl2(s)

By examining the stoichiometry, we find that for every 4 atoms of antimony, we should have 5 oxygen and 2 chlorine atoms on the reactant side as well. After balancing, we get:

4 Sb2O3(s) + 2 SbCl3(s) → Sb4O5Cl2(s)

Therefore, the coefficient of antimony(III) oxide is 4.

Answer:

The correct answer is: a. Southern California and Australia.

Explanation:

The solar power, in order to be more efficient and more productive, needs to be produced in places that have a lot of sunny days throughout the year. So the wisest and most practical thing to do is to install solar panels at places that are warm and sunny for most of the year. The southern part of California and most of Australia would be excellent choices for something like this. Both places have predominantly warm weather throughout the year, and more important, they have  a lot of sunny days throughout the year. That provides the perfect conditions for harvesting the solar energy and use it as an energy source.

Answer:

a

Explanation:

Answer:

3.98 x 10⁻⁴ M.

Explanation:

∵ pH = - log[H₃O⁺]

∴ 3.4 = - log[H₃O⁺].

∴ log[H₃O⁺] = - 3.4.

∴ [H₃O⁺] = 3.98 x 10⁻⁴ M.

Answer: The hydronium ion concentration for the solution is [tex]3.98\times 10^{-4}M[/tex]

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration or hydronium ion concentration present in a solution.

To calculate the pH of the reaction, we use the equation:

[tex]pH=-\log[H_3O^+][/tex]

We are given:

pH of the solution = 3.40

Putting values in above equation, we get:

[tex]3.40=-\log[H_3O^+][/tex]

[tex][H_3O^+]=3.98\times 10^{-4}M[/tex]

Hence, the hydronium ion concentration for the solution is [tex]3.98\times 10^{-4}M[/tex]

It is 25%. 25g ÷ 100g × 100% = 25%

According to what I know, if the water is pure, it always freezes at 0°C.

- Lee Hae :) Have a great day!

If 50 mL of boiling water is added to 100 mL of ice water and the entire mixture is put in a freezer, the water will freeze at 0 [tex]^oC[/tex].

Irrespective of the initial temperature, water always freezes when its temperature drops to zero degrees Celsius, 32 degrees Fahrenheit, or 273 Kelvin.

The freezing happens at the quoted temperature under standard atmospheric pressure and if the water is pure. At higher pressure, the freezing point is lower and at lower pressure, the freezing point increases.

Impurities also lower the freezing point of water

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pH = 4.20

pKa = -log(6.30 × 10^-5)

pKa = 4.20  

Moles of Benzoic acid = volume × molarity

                                      = 0.050L × 1.00M

                                      = 0.050moles benzoic acid  

Moles of the salt = 0.050L ×  1.00M

                           = 0.050 moles salt  

Therefore;

0.050mols / 0.1 L = 0.50M  

0.050mols / 0.1 L = 0.50M  

Thus;

pH = 4.20 + log(0.50/0.50)

pH = 4.20

From the calculations, the pH of the solution is 4.20

The pH is defined as the degree of acidity or alkalinity of a solution. We have to find the pH of the buffer using the Henderson–Hasselbalch equation.

Since, Ka = 6.30 × 10^-5

then pKa = -log(6.30 × 10^-5)

pKa = 4.20  

Number of moles of Benzoic acid = volume × molarity

= 0.050L × 1.00M = 0.050moles benzoic acid  

Number of moles of benzoate = 0.050L ×  1.00M = 0.050 moles

Total volume of solution = 50 mL + 50 mL = 100 mL or 0.1 L

Molarity of acid

0.050mols / 0.1 L = 0.50M  

Molarity of conjugate base

0.050mols / 0.1 L = 0.50M  

Hence;

pH = 4.20 + log(0.50/0.50)

pH = 4.20

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