What is a type of science that studies earth and and space

Answer:

Part a)

y = 30.625 m

Part b)

v = 24.5 m/s

Explanation:

Part a)

As we know that brick will hit the floor after t = 2.50 s

so here we will have

[tex]y = v_i t + \frac{1}{2}at^2[/tex]

[tex]y = 0 + \frac{1}{2}(9.8)(2.50^2)[/tex]

[tex]y = 30.625 m[/tex]

Part b)

velocity of the brick just before it will strike the ground is given as

[tex]v_f = v_i + at[/tex]

[tex]v_f = 0 + (9.8)(2.5)[/tex]

[tex]v_f = 24.5 m/s[/tex]

Part c)

Each leg of the stool decreases in length by approximately 1.40 × 10⁻⁴% when the 70 kg man sits on it.

Calculate the force exerted on each leg:

Given: mass (m) = 70 kg, acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mass × acceleration = 70 kg × 9.8 m/s² = 686 N

Determine the original length of the legs:

Let's assume the height of the stool is 1 meter (100 cm).

Calculate the cross-sectional area of each leg:

Given the diameter of each leg is 2.5 cm, the radius (r) is 1.25 cm or 0.0125 m.

Area (A) = π × r²

Area ≈ 3.14 × (0.0125 m)² ≈ 4.91 × 10⁻⁴ m²

Determine the modulus of elasticity of Douglas fir:

Let's assume E = 10 × 10⁹ N/m².

Calculate the change in length for each leg:

Using the formula for axial deformation:

Change in length (ΔL) = (Force × Length) / (Area × Modulus of Elasticity)

ΔL = (686 N × 1 m) / (4.91 × 10⁻⁴ m² × 10 × 10⁹ N/m²)

ΔL ≈ 1.40 × 10⁻⁶ m

Calculate the percentage decrease in length:

Percentage decrease = (Change in length / Original length) × 100%

Percentage decrease = (1.40 × 10⁻⁶ m / 1 m) × 100%

Percentage decrease ≈ 1.40 × 10⁻⁴ %

So, each leg of the stool decreases in length by approximately 1.40 × 10⁻⁴% when the 70 kg man sits on it.

The question probable may be:

A three-legged wooden bar stool made out of solid Douglas firhas legs that are 2.5 cm in diameter.

When a 70 kg man sits on thestool, by what percent does the length of the legs decrease?Assume, for simplicity, that the stool's legs are vertical and thateach bears the same load.

The pitch of a note is determined by its frequency, with higher frequencies leading to higher pitches. The quality, or timbre, of a note depends on the shape of the waveform, influenced by various frequencies and phases of sound waves. These aspects combine to give each note its unique character.

The quality and pitch of a note depend on different aspects of sound waves. The pitch of a note is primarily determined by its fundamental frequency, which is measured in hertz (Hz). A higher frequency results in a higher pitch, making a note sound “sharper” or higher on the musical scale. For example, the piano note middle C has a frequency of 261.63 Hz. Musical intervals, like the octave, are based on the doubling of frequencies.

On the other hand, the quality or timbre of a note depends on the waveform's shape, which is influenced by the frequencies and phases of other sound waves produced alongside the fundamental frequency. This complexity allows us to distinguish between different instruments playing the same note due to the variety in waveforms. The timbre is what makes the same note played on a trumpet distinctly different from the same note played on a clarinet.

In summary, while pitch is a direct correlation to the frequency of sound, quality or timbre involves the intricate interplay of multiple frequencies and their waveform shapes, contributing to the unique character of each musical note.

Answer:

Initial speed, u = 2.03 m/s

Explanation:

Flea jumps to a height of, h = 21.1 cm = 0.211 m

As it leaves the ground, its final speed, v = 0

Acceleration, a = -g

Let u is the initial speed of the flea. It can be calculated as :

[tex]v^2-u^2=2as[/tex]

[tex]-u^2=2\times (-9.8)\times 0.211[/tex]

u = 2.03 m/s

So, the initial speed of the flea as it leaves the ground is 2.03 m/s. Hence, this is the required solution.

Answer: The efficiency of the lever is 80%.

Explanation:

An efficiency is the measure of how much wok or energy is conserved in a given process. It is defined as the ratio of output work and input work. If the energy is totally conserved in a process, the the percentage efficiency will be 100%.

Mathematically,

[tex]\%\text{ efficiency}=\frac{W_{out}}{W_{in}}\times 100[/tex]

Where,

[tex]W_{out}[/tex] = Work done by the lever = 20 J

[tex]W_{in}[/tex] = Work put in the lever = 25 J

Putting values in above equation, we get:

[tex]\%\text{ efficiency}=\frac{20}{25}\times 100\\\\\%\text{ efficiency}=80\%[/tex]

Hence, the efficiency of the lever is 80%.

Alice and Tom reach the lake simultaneously due to gravity's independence from their initial horizontal velocities. The correct answer is (E).

Let us consider the concept of horizontal motion and vertical motion of a projectile (in this case, Alice and Tom) are independent of each other when there is no air resistance.

This means that the horizontal velocity does not affect the vertical motion.

Both Alice and Tom are subject to the same gravitational acceleration, and since they are both falling vertically, they will reach the surface of the lake at the same time.

So, the correct answer is (E). Alice and Tom will reach the surface of the lake at the same time.

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Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below.

(A) alice and tom dive from an overhang into the lake below.

(B) tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s.

(c) neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first.

(D) alice reaches the surface of the lake first.
(E) alice and tom will reach the surface of the lake at the same time.

Both Alice and Tom will reach the surface of the lake at the same time because their times to hit the water depend only on the vertical distance and gravitational acceleration.

Alice and Tom both dive from the same overhang into a lake below.

Both Alice and Tom experience the same vertical acceleration and fall the same vertical distance, hence, they will both reach the surface of the lake at the same time.

The length of a tropical year is approximately 365.242199 days, or approximately 31556926 seconds. Therefore, the number of seconds in two and a half tropical years is approximately 78892315 seconds.

The tropical year is based on the time it takes the Earth to revolve around the sun, and is the basis of our calendar. This time period lasts approximately 365.242199 days. To find the number of seconds in a tropical year, we need to first convert this period into hours, minutes, and then seconds. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. Here's the calculation:

So, one tropical year is approximately 31556926 seconds.

To find out the number of seconds in two and a half tropical years, we simply multiply this number by 2.5:

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Final answer:

Bernoulli's equation is a form of the conservation of energy principle in fluid flow. It states that the sum of pressure, kinetic energy, and potential energy is constant at any two points in an incompressible, frictionless fluid.

Explanation:

Bernoulli's equation is a form of the conservation of energy principle in fluid flow. It states that the sum of pressure, kinetic energy, and potential energy is constant at any two points in an incompressible, frictionless fluid.

For example, if a fluid flows through a pipe with varying diameters, according to Bernoulli's equation, the pressure decreases as the fluid velocity increases.

This concept is important in the study of fluid mechanics and is used to analyze and predict the behavior of fluids in various applications.

The percent accuracy is 10⁻⁵%. It is determined by the formula of percent accuracy.

Given information:

Distance of satellite = 20,000km

= 2 x 10⁷ m

Uncertainty = 2 meter

Uncertainty refers to a lack of exactness or precision in measurement, calculation, or prediction. It represents the degree of doubt or error associated with a particular value or result. Uncertainty is an essential concept in various fields, including science, engineering, statistics, and decision-making.

The formula to determine percent accuracy is:

[tex]\rm Percent \ accuracy= \frac{Uncertainty}{Measured d\ distance} \times 100[/tex]

Substituting the values in the formula:

[tex]\rm Percent \ accuracy = \frac{2}{2\times 10^7}\times 100 \\\rm Percent \ accuracy = \frac{1}{10^5} \\[/tex]

Simplifying:

Percent accuracy = 10⁻⁵%.

Therefore, the percent accuracy is 10⁻⁵%.

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Answer:

10 calories

Explanation:

The thermal energy needed to increase the temperature of a substance is given by

[tex]Q=m C \Delta T[/tex]

where

m is the mass of the substance

C is the specific heat of the substance

[tex]\Delta T[/tex] is the increase in temperature

In this problem, the mass of the ice is m=20 g, the specific heat is C=0.5 calories/gram°C, and the increase in temperature is [tex]\Delta T=1^{\circ}[/tex]. Therefore, the energy required is

[tex]Q=(20 g)(0.5 cal/g^{\circ}C)(1^{\circ}C)=10 cal[/tex]

Answer:

[tex]108\ N[/tex]

Explanation:

Mass of object, [tex]m=1.50\ kg.[/tex]

Length of string, [tex]r=0.50\ m.[/tex]

Tangential speed, [tex]v_t=6.0\ m/s.[/tex]

Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.

Here , object moves along the ends of string. Therefore, radius is equal to length of string.

[tex]F=\dfrac{m \times v_t^2}{r}.[/tex]

Putting values of m,v and r in above equation.

We get, [tex]F=\dfrac{1.50\times (6.0)^2}{0.50} \ N=108 \ N.[/tex]

Hence, this is the required solution.

If the mass of the crate is doubled but the initial velocity is not changed, the crate slides distance d before stopping.

[tex]\texttt{ }[/tex]

Let's recall the formula of Kinetic Energy as follows:

[tex]\large {\boxed {E_k = \frac{1}{2}mv^2 }[/tex]

Ek = Kinetic Energy ( Newton )

m = Object's Mass ( kg )

v = Speed of Object ( m/s )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial height = h₁ = 26 m

final height = h₂ = 16 m

initial speed = v₁ = 0 m/s

coefficient of friction = μ

gravitational acceleration = g

distance = d

Asked:

final speed = v₂ = ?

Solution:

We will use Work and Energy formula to solve this problem as follows:

[tex]W = \Delta Ek[/tex]

[tex]-f d = Ek_{final} - Ek_{initial}[/tex]

[tex]-\mu N d = \frac{1}{2}m (v_f)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2}m (v_f)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2}m (0)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2} m (v_i)^2[/tex]

[tex]\mu g d = \frac{1}{2} (v_i)^2[/tex]

[tex]d = \frac{1}{2} (v_i)^2 \div ( \mu g )[/tex]

[tex]\boxed {d = \frac { (v_i)^2 } { 2 \mu g } }[/tex]

[tex]\texttt{ }[/tex]

From information above we can conclude that the distance is independent to the mass of the crate.

If the mass of the crate is doubled but the initial velocity is not changed, the crate slides the same distance d before stopping.

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

If the mass of the crate is doubled while maintaining the same initial velocity, the stopping distance will be halved. This is due to the doubled frictional force from the increased mass. Therefore, the crate will slide a distance of d/2 before coming to a stop.

Thus, the crate will slide half the distance before stopping if the mass is doubled but the initial velocity is unchanged.

Final answer:

The magnitude of the average acceleration the football player experiences is 38.02 m/s², and the direction of the acceleration is backward, towards the line of scrimmage.

Explanation:

To calculate the magnitude and direction of the average acceleration experienced by the football player, we use the following kinematic equation:

a = (v_f - v_i) / t

Where:

Given:

Now we can plug these values into our equation to find a:

a = (0 - 7.68 m/s) / 0.202 s

a = -7.68 m/s / 0.202 s

a = -38.02 m/s2

The negative sign indicates that the acceleration is in the opposite direction of the player's initial motion. Since the player was moving forward and came to a stop, the acceleration is directed backward, towards the line of scrimmage.

Michael Jordan's takeoff speed for his 47.2-inch vertical leap would be approximately 4.85 m/s, calculated using the kinematic equation for vertical motion.

To find Michael Jordan's takeoff speed, we can use the kinematic equation for vertical motion without air resistance: vf^2 = vi^2 + 2 * a * d, where vf is the final velocity (0 m/s at the peak of the jump), vi is the initial velocity (takeoff speed we want to find), a is the acceleration due to gravity (-9.81 m/s^2), and d is the vertical leap distance.

First, we convert the vertical leap from inches to meters: 47.2 inches = 1.2 meters (approximately).

Now, we can set vf to 0 m/s and solve for vi:

0 = vi^2 + 2 * (-9.81) * 1.2

vi^2 = 2 * 9.81 * 1.2

vi = sqrt(2 * 9.81 * 1.2)

vi ≈ 4.85 m/s (rounded to two decimal places)

Therefore, Michael Jordan's takeoff speed would be approximately 4.85 m/s.

Final answer:

To calculate the electric field magnitude at a distance from a charged rod, determine the charge per unit length and use the electric field formula.

Explanation:

Electric Field and Charged Rod:

To find the magnitude of the electric field at a distance from a charged rod, you can use the formula for the electric field of a long, charged rod. Given the total charge on the rod and its length, you can calculate the charge per unit length. Then, apply the formula to find the electric field at the specified location.

Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m).

The point then lies on the y-axes at d = 0.03 m.

from symmetry, the field at that point will be ascending along the y-axes.

A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point.

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength.

All in all, the infinitesimal field strength from the charge between x and x+dx is:

dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2)

Therefore, upon integration,

E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2.

This gives:

E = k lambda L / (d sqrt((L/2)^2 + d^2) )

But lambda L = Q, the total charge on the rod, so

E = k Q / ( d * sqrt((L/2)^2 + d^2) )

In order to maintain equilibrium and have a downslope acceleration of 0.64 m/s² with a 2.3 kg mass, the right-hand mass should be approximately 0.15 kg.

In physics, the question is referring to the concept of equilibrium through the force of gravity. When a downtrend pushes left-hand mass with a certain acceleration, it implies that any other force (potentially from another mass on the opposite direction) counteracts. This counteraction or the right-hand mass is what we are now to calculate.

Assuming there is no friction, the force acting on the left-hand mass (F1) can be calculated using Newton's second law of motion, F = ma where m is the mass and a is the acceleration, yielding F1 = 2.3 kg * 0.64 m/s² = 1.472 N

For equilibrium to be maintained, the force due to the right-hand mass (F2) must equal F1. Therefore, if g is the acceleration due to gravity (9.81 m/s²), the right-hand mass (m2) can be found using the formula m2 = F1 / g, simplifying to m2 = 1.472 N / 9.81 m/s² = 0.15 kg.

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Actually we could create a triangle in this case. The hypotenuse is the radius of Earth plus the height above the earth, while the two sides are the radius of Earth and the scope of vision.

That is:

(6,400,000 m + 100 m)^2 = (6,400,000 m)^2 + b^2

b^2 = 1,280,010,000

b = 35,777.23 m

You can see 35,777.23 m far.

The puma, cougar, or mountain lion leaves the ground to make a leap with a speed of approximately 8.32 m/s.

To find the speed at which the animal leaves the ground, we can use the kinematic equation for projectile motion:

[tex]\[v = \sqrt{2gh},\][/tex]

where [tex]\(v\)[/tex] is the speed, [tex]\(g\)[/tex] is the acceleration due to gravity (approximately [tex]\(9.81 \, \text{m/s}^2\))[/tex], and [tex]\(h\)[/tex] is the vertical height.

Given that the height  [tex]\(h\)[/tex] is 13.7 ft, we first convert it to meters:

[tex]\[h = 13.7 \, \text{ft} \times 0.3048 \, \text{m/ft} = 4.1756 \, \text{m}.\][/tex]

Substituting [tex]\(h\)[/tex] into the equation, we have:

[tex]\[v = \sqrt{2 \times 9.81 \, \text{m/s}^2 \times 4.1756 \, \text{m}} \approx 8.32 \, \text{m/s}.\][/tex]

Answer: B. standard deviation

Explanation:

In statistics , Standard deviation is a term which is used to to represent the measure of dispersion of data from the mean-value.

It is used to determine how closely the data values are with the mean of the entire data.

It is the average distance from each data value to the mean.

Hence, the average distance between the variable scores and the mean in a set of data is the standard deviation.