what is 7 over (fraction bar) (8×4)+90÷9 ÷ (6^3)^-2 × 9 over (fraction bar) 6(5+4) = ?????
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Note: " (8 * 4) + 90 ÷ 9 " = " (8 * 4) + (90 ÷ 9) " = "32 + 10 = 42" .
We can rewrite the "fraction":
7 / [ (8 * 4) + 90 ÷ 9 ] ; as: [tex] \frac{7}{42}[/tex] ;
and can reduce this value to (and rewrite as): " [tex] \frac{1}{6}[/tex] " ;
{ since: " [tex] \frac{7}{42}[/tex] = [tex] \frac{7/7}{42/7} [/tex] = [tex] \frac{1}{6}[/tex]" .}.
Note: The "fraction" : [tex] \frac{9}{6(5+4)} [/tex] ; the "9/6" cancel to "3/2" ;
{Since: "9÷3 = 3" ; and since: "6÷3 = 2" ).
So rewrite: [tex] \frac{9}{6(5+4)} [/tex] ; as:
[tex] \frac{3}{2(5+4)} [/tex] ;
Note: [tex] \frac{3}{2(5+4)} [/tex] ;
= [tex] \frac{3}{2(9)} [/tex] ;
= [tex] \frac{3}{18} [/tex] ;
→ Note: [tex] \frac{3}{18} [/tex] ; can be reduced to; & rewritten as:
" [tex] \frac{1}{6} [/tex] " ;
→ {since: " [tex] \frac{3}{18} [/tex] = [tex] \frac{3/3}{18/3} [/tex] ;
= [tex] \frac{1}{6} [/tex] ;
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Note that: (6²) ⁻² = 6⁽ ² * ⁻²⁾ = 6⁻ ⁴ ;
= [tex] \frac{1}{6^4} [/tex] ;
_________________________________________________________
So, we can rewrite our expression as:
[tex] \frac{1}{6}[/tex] ÷ [tex] \frac{1}{6^4} [/tex] * [tex] \frac{1}{6}[/tex] ;
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Note:
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[tex] \frac{1}{6}[/tex] ÷ [tex] \frac{1}{6^4} [/tex] * [tex] \frac{1}{6}[/tex] ;
= ( [tex] \frac{1}{6}[/tex] ÷ [tex] \frac{1}{6^4} [/tex] ) * [tex] \frac{1}{6}[/tex] ;
= ( [tex] \frac{1}{6}[/tex] * [tex] \frac{6^4}{1} [/tex] ) * [tex] \frac{1}{6}[/tex] ;
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Start with :
________________________________________________________
→ ( [tex] \frac{1}{6}[/tex] * [tex] \frac{6^4}{1} [/tex] ) ;
The "6" in the " [tex] \frac{1}{6}[/tex] " ; cancels to a "1" ;
and the "6⁴ " in the " [tex] \frac{6^4}{1} [/tex] ) " ; cancels to a "6³ " ;
→ {Since: "6⁴ / 6 = 6⁴ / 6¹ = 6⁽⁴ ⁻ ¹⁾ = 6³ ;
→ and we have: [tex] \frac{1}{1}[/tex] * [tex] \frac{6^3}{1} [/tex] ;
→ The " [tex] \frac{1}{1}[/tex] " can be eliminated; since "1÷1= 1 " ;
and since: any value, divided by "1", equal that same value; & since "any value, multiplied by "1"; equals that same value" ;
________________________________________________________
We have: " 6³ " .
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Now, we multiplied this value, " 6³ " , by " [tex] \frac{1}{6}[/tex] " ;
→ 6³ * [tex] \frac{1}{6}[/tex] ;
= [tex] \frac{6^3}{1} [/tex] * [tex] \frac{1}{6}[/tex] ;
Note: The "6³ " cancels out to "6² " ; and the "6" cancels out to "1" ;
{since: "6³ ÷ 6 = 6³ ÷ 6¹ = 6⁽³ ⁻ ¹⁾ = 6² " ;
and since: "6 ÷ 6 = 1 " ; ________________________________________________________
→ The answer is: 6² = 6 * 6 = 36 ;
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The answer is: " 36 " .
________________________________________________________
Related Questions
Danielle earns a 7.25% commission on everything she sells at the electronic store where she works,.she also earns a base salary of $750 per week .how mcuh did she earn last week if she sold 4,000 in electronics merchandice?
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($4,000 × 0.0725 + $4,000 ) + $750
Now, all you have to do is solve it. You would start in the parenthesis using the order of operation (PEMDAS).
($4,000 × 0.0725 + $4,000 ) + $750
$4290 + $750 = $5,040
Danielle made $5,040 last week.
I hope this helps!
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What is the value of 3/4÷6/7
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When would you use a drawing of comparison bars for word problem
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Answer: Comparison bars are a display tool for solving the scenario in which two elements are compared with the difference is either known or unknown.
There are three kinds of use of comparison bars in word problem such as 1) If difference is unknown then A-B=Difference[where A -bigger quantity, B-smaller quantity]. 2) If bigger quantity is unknown then A=Difference-B 3) If smaller quantity is unknown then B=Difference-A.
A drawing of comparison bars, also known as a bar graph, can be used in word problems when there is a need to compare different entities or categories. It is particularly useful in situations where quantitative data needs to be visually represented and compared. For example, if you are given data about the sales of different types of fruits in a grocery store, you can use a bar graph to compare the sales of each fruit.
Explanation:A drawing of comparison bars, also known as a bar graph, can be used in word problems when there is a need to compare different entities or categories. It is particularly useful in situations where quantitative data needs to be visually represented and compared. For example, if you are given data about the sales of different types of fruits in a grocery store, you can use a bar graph to compare the sales of each fruit.
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An architect is designing a house in which a 104 square foot room and a 130 square foot room share a wall what is the greatest possible integer length of the shared wall -- THIS QUESTION WAS ASKED AND ANSWERED. BUT ANSWERED INCORRECTLY. NOTE THE ANSWER GIVEN CHANGED THE DIMENSIONS TO 140 FROM 104. AND THIS WEBSITE WILL NOT ALLOW ME TO REPORT THAT.
Answers
Then, the area of both squares have x as common factor.
So, x is the greatest common factor of 104 and 130.
You should know how to calculate the greatest common factor of two integers.
Just find the prime factors and choose the common factors raised to the lowest exponent.
104 = (2^3) (13)
130 = (2) (5)(13)
=> the greatest common factor is 2 * 13 = 26, and that is the greatest possible integer length of the shared wall.
Answer: 26
Pls Answer!!!!!
The following graph shows the number of soccer games a team won in each of their first three seasons. Explain how you could redraw the graph so that the change in wins between the three Seasons does not seem so great.
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In the gragh that is shown, the scale used is 1 grid unit to represent 1 goal, if we may change the scale to something like 1 grid unit to represent 2 goals or 1 grid unit to represent 3 goal, then the change in wins between the three seasons will not seem so great
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Answers
Answer:
Each student is gonna sell 13 candy bars, and there is gonna be 1 bar unsold, because they sold equal amount of candy bars.Step-by-step explanation:
If there are 4 students, they need to sell 53 candy bars, and they will sell the same amount each one, we just have to divide:
[tex]\frac{53}{4} =13.25[/tex], or [tex]13\frac{1}{4}[/tex]
Because the division is not exact, we have a remainder of 1.
This can be interpreted as 1 candy is not sold, because they are gonna sell equally, so in that case each one would sell 13 candy bars, and one will be unsold.
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w=width
l=length
So it is 2(665)+2(421)=2172
he graph of the function f(x) = –(x + 6)(x + 2) is shown below.
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Answer:
Which statement about the function is true?
⇒ The function is increasing for all real values of x where
x < –4.
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Both the domain and range of this function are all real numbers.
The two things that typically limit a domain are dividing by zero and taking the square root of a negative. Since this function does not have a square root or a denominator, then you must be able to use all real numbers.
The price of 6 pretzels is $5.10. Simon and Sofia bought 8 pretzels and shared the cost equally. How much did each person pay?
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12.75 is 25% of what number
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The number that would have 12. 75 being 25 percent of it would be 51.
How to find the number ?To find the number of which 12. 75 is 25 %, you can set up a proportion and solve for the unknown number ( let's call it " x ").
You can write the proportion as:
( 25 / 100 ) * x = 12. 75
Now, simplify the left side of the equation:
( 1 / 4 ) * x = 12.75
To solve for x, multiply both sides by 4 to isolate x:
x = 12. 75 * 4
x = 51
So, 12. 75 is 25% of the number 51.
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Simplify the following expression. +−16x2+−5x3x29
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(Assuming that the "x" signifies a multiplication sign, rather than a variable.)
Follow PEDMAS.
[tex]=+(-16)*2+(-5)*3*29[/tex]
Simplify.
[tex]=-16*2-5*3*29[/tex]
[tex]=-32-5*3*29[/tex]
[tex]=-32-15*29[/tex]
[tex]=-32-435[/tex]
[tex]=-467[/tex]
Hope this helps.
-Benjamin
math question answer a b and c hurry answer each one
Answers
so we have Δd/Δt=8.8min
Δd= 8.8Δt
d=∫8.8Δt-------(1)
b. d should be positive because the diver is ascending at a positive rate relative to depth
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t=d/r = 32.12/8.8 min
t= 3.65min
c) About 3 minutes and 39 seconds = 3.65 minutes
joe is playing a game with a regular die.If the number that turns up is even he will gain 5 times the number that comes up.If its odd,he will lose 10 times the number that comes up.He tosses a 3 express results as an integer
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3 - 30 = -27
Three fourths of w plus 5 is one half of a increased by nine. I neeed to turn into an equation!
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A bag contains 20 balls numbered from 1 to 20. Two balls are selected at the same time from the bag. What is the probability that the two numbers selected do NOT differ by 12
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Please help!!! I dont know how to do this!!please
Answers
add 3 to both sides.
now you should have 4d=16
divide by 4 on both sides
your answer would be d=4
For ALL of the equations, you want to solve for the variable (letter) and get it by itself. So,
#1- The equation is 3n + 5 = 6. We want to subtract 5 from the left side, so 3n can be by itself. BUT, if we subtract 5 from the left, we also need to do it to right side. The equation is now: 3n = 1. We then want "n" by itself, so we need to divide "n" by 3 to get "n" by itself. Again, if we do it to the left side, we need to do it to the right. After you simplify, the equation simplifies to: n = 1/3 (in decimal form, the decimal would be repeating {0.33333}).
#2- The equation is 4 + 5x = 1. To get "5x" by itself on that side, let's subtract 4 to that side and the right side. After you do that, it'll be: 5x = -3. Then divide "x" by 5 to each side. The answer is: x= -3/5 (-0.6).
#3- The equation is 4y - 15 = -10. If we want "4y" by itself, we will do the opposite of subtracting 15 to adding 15 to both sides. After you do that, it'll be: 4y = 5. To finish it off, divide "y" by 4 to both sides. That will get you with:
y = 5/4 (1.25).
#4- The equation is 3 - 4d = 13. To get 4d by itself, let's subtract 3 to each side. That'll leave you with: -4d = 10. Now divide d by "-4" to both sides. The answer is: d = -10/4 (-2.5).
#5- The equation is 8 = 9x - 7. Let's add 7 to each side so that 9x can be by itself. After we do that, it's simplified to: 15 = 9x. Finish it off by dividing "x" by 9 to both sides. That'll leave you with the answer: x = 15/9 (in decimal form, this decimal would be repeating {1.66666}).
Anyone can fix my mistakes if they are wrong. I hope this helps!
May
How do I write this number in scientific notation 0.0072
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Hope this helps
If its not too much trouble it would mean a lot if I could have brainliest because I have a BIG unit test coming up and I really need points so I can ask questions. :)
3-74. Mentally calculate the following products. Use the rule for decimal multiplication to write an equation in which the decimal point is written in the correct location. Homework Help ✎ (−0.04)(−0.1) (0.03)(−0.02) (0.7)(0.4) Stacey said, “Stephanie, look at my answer to the last problem, 0.7 · 0.4 = 0.28. Usually when I multiply, I get a bigger answer than the numbers I start with. Twenty-eight hundredths, 0.28, is less than either 0.4 or 0.7. I must have made a mistake.” Stephanie responded, “Well, one half times one half is one fourth, and one fourth is less then one half. I think when you multiply by a fraction or decimal less than one, you get less than you started with.” Write a sentence or two about who you think is correct and why.
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Final answer:
Stephanie is right; when you multiply decimals less than one, the result is smaller than the original numbers. The multiplication of (-0.04)(-0.1) is 0.004, (0.03)(-0.02) is -0.0006, and (0.7)(0.4) is 0.28. These examples illustrate the rule correctly.
Explanation:
Stephanie is correct in her explanation to Stacey. When multiplying two numbers where one or both numbers are less than one, the product will be smaller than the original numbers. This is because you are essentially taking a fraction of each number. Let's confirm this by calculating the products of the given examples.
Multiplication of Negative Decimals: The product of negative decimals will be positive (since a negative times a negative equals a positive). For (-0.04)(-0.1), the product is 0.004.Multiplication of Mixed Decimals: The product of a positive and a negative decimal will be negative. For (0.03)(-0.02), the product is -0.0006.Multiplication of Positive Decimals: As in Stacey's example, (0.7)(0.4) equals 0.28, which is indeed less than either 0.4 or 0.7 because you're multiplying fractions of a whole number.Moreover, in scientific notation, moving the decimal and using placeholders is crucial for accurate answers. Multiplying 2.4 by 100 moves the decimal two places to the right, giving us 240.
Recipe A makes 5 dinner rolls using 1 c of flour. Recipe C makes 45 rolls using 10 c of flour. Which recipe requires the most flour per roll?
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When calculating how much flour is used per roll in each recipe, recipe C (at 0.22 cups per roll) uses more flour per roll than recipe A (at 0.2 cups per roll).
Explanation:To determine which recipe uses the most flour per roll, we first need to calculate the flour-per-roll for each recipe. For recipe A, it makes 5 dinner rolls using 1 cup of flour. So, the flour-per-roll for recipe A is
1 cup of flour ÷ 5 rolls = 0.2 cups per roll
. For recipe C, it makes 45 rolls using 10 cups of flour. So, the flour-per-roll for recipe C is
10 cups of flour ÷ 45 rolls = 0.22 cups per roll
. Comparative analysis shows that recipe C requires more flour per roll than recipe A.
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In a similar triangle, they have to be proportional
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3 pages in 1 hour is the answer.
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8 - 1/3x = 16
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