what is 694 divided by 41 and what is the remainder please help thank you

Using permutations, there are 6720 sequences of ringing the church bell before the church service.

A permutation is a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangements matters.

[tex]_{n} P_{r}=\frac{n !}{(n-r) !}\\\\_{8} P_{5} = \frac{8 !}{(8-5) !}\\\\_{8} P_{5} = 6720[/tex]

Number of permutations of bells = 6720

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Answer with explanation:

Number of Envelopes possessed by the person = 6

Probability of selecting an Envelope is equal to [tex]/frac{1}{6}[/tex].

It is given that,three envelopes contains $ 533 check and another 3 Envelope contain $ 1039 check.We can consider that any of three checks contain $ 533 and another three $ 1089.

Expectation

[tex]E(x)=x_{1}p_{1}+x_{2}p_{2}+x_{3}p_{3}+x_{4}p_{4}+x_{5}p_{5}+x_{6}p_{6}\\\\\frac{1}{6} \times [533+533+533+1039+1039+1039]\\\\=\frac{1}{6} \times [4716]\\\\=786[\tex]

E(x)=786          

Answer:

f(x)=45x

Step-by-step explanation:

if the home is 495 miles away, 11 hours would take to drive home.

f(11)=45X11=495

a) When the interest rate is increased by 1%, the simple interest increases from $180 to $240, a difference of $60.

b) When the time (period) is increased by 1 year, the simple interest increases from $180 to $216, a difference of $36.

Simple interest is the interest system that does not compute interest on the accumulated interest.

Unlike the compound interest system, simple interest calculates interest on the principal for each period.

Interest rate = 3%

Principal deposit = $1,200

Investment period = 5 years

Simple interest at 3% = Principal x Rate x Time

= $180 ($1,200 x 3% x 5)

Simple interest at 4% = Principal x Rate x Time

= $240 ($1,200 x 4% x 5)

Simple interest at 3% = Principal x Rate x Time

= $216 ($1,200 x 3% x 6)

Simple interest at 4% = Principal x Rate x Time

= $288 ($1,200 x 4% x 6)

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Increasing the interest rate from 3% to 4% on a $1200 deposit for 5 years raises the simple interest from $180 to $240, while extending the time from 5 to 6 years at the initial rate results in a raise from $180 to $216 in simple interest.

Understanding Simple Interest with Changes in Rate and Time

Simple interest is calculated by multiplying the principal amount, the interest rate, and the time the money is borrowed or invested. Using the provided example, if you deposit $1200 at a simple interest rate of 3% for 5 years, the interest is calculated as follows:

$1200 times 0.03 times 5 = $180

If the interest rate increases by 1%, the new interest rate becomes 4%. Thus, the simple interest for the increased rate is:

$1200 times 0.04 times 5 = $240

Therefore, an increase of 1% in the interest rate raises the simple interest earned from $180 to $240, an increase of $60.

If the time is increased by 1 year while keeping the original interest rate of 3%, the new time period is 6 years. The simple interest for the increased time is:

$1200 times 0.03 times 6 = $216

Extending the time by 1 year increases the total simple interest from $180 to $216, which is an extra $36 earned.

Answer:

the answer is a

Step-by-step explanation:

Jamal use 1/2 yards of ribbon

Jamal used 1/3 yard of ribbon to tie a package and 1/6 yard of ribbon to tie a bow. How many yards of ribbon did Jamal use?

Jamal used 1/3 yard of ribbon to tie a package and 1/6 yard of ribbon to tie a bow. Therefore the total of ribbon Jamal used is:

[tex]\frac{1}{3} + \frac{1}{6} = \frac{2}{6} +\frac{1}{6}= \frac{3}{6} or \frac{1}{2}[/tex] yards of ribbon

How many yards of ribbon did Jamal use? Jamal use 1/2 yards of ribbon

The yard (yd) is English unit of length comprises 3 feet or 36 inches. It is by international agreement standardized as exactly 0.9144 meters. Yard is defined as a measurement of length that equals 3 feet or 36 inches. An example of a yard is the length measurement that is used to sell fabric.

A ribbois a thin band of material, typically cloth but also plastic or sometimes metal, used as decorative binding and tying.

We also can draw 1/3 yard of ribbon as 33.333% of all yards, and 1/6 as 16.6666% of all yards as shown in the picture below.

Grade:  5

Subject:  math

Chapter:  yards

Keywords:   ribbon, yard, package, bow, tie

The exponential equation that models the number of bacteria in hours is N = 8000 * (1 + 0.125)^t. The doubling time of the bacteria is 5.55 hours.

To find an exponential equation that models the number of bacteria in hours, we can use the formula: N = N0 * (1 + r)^t.

Where:

Plugging in the values, we have:

9000 = 8000 * (1 + r)^1

Dividing both sides by 8000, we get:

1.125 = 1 + r

Subtracting 1 from both sides, we find:

0.125 = r

Therefore, the exponential equation that models the number of bacteria in hours is: N = 8000 * (1 + 0.125)^t.

To find the doubling time of the bacteria, we can use the formula: t = log(2)/log(1 + r).

Plugging in the value of r (0.125), we have:

t = log(2)/log(1 + 0.125)

Using a calculator, we find that t is approximately 5.5452 hours. Rounded to the nearest 0.01 hours, the doubling time of the bacteria is 5.55 hours.

The expression (3ab)(-5ab) is equivalent to [tex]-15a^2b^2[/tex], calculated by multiplying the coefficients (3 and -5) to get -15 and squaring the variables ab to get [tex]a^2b^2[/tex].

The expression in question, (3ab)(-5ab), involves the multiplication of two terms. To find an expression equivalent to (3ab)(-5ab), we simply need to multiply the coefficients and then multiply the variables. The coefficients here are 3 and -5, and when we multiply them, we get -15. Since the variable part is 'ab' for both terms, we multiply 'a' by 'a' to get a2 and 'b' by 'b' to get b2. Combining these, we get the final equivalent expression:

(3ab)(-5ab) = [tex]-15a^2b^2[/tex].

This is an example of reversing the distributive law and turning it into the factors or multiples. We see that expressions that, when evaluated, produce the same value are considered equivalent.

there are 5040 ways for the three men and four women to stand in line at the checkout counter if we only consider their gender.

To determine the number of ways the three men and four women can stand in line at the checkout counter if we only consider their gender, we can use the concept of permutations.

There are 3 men and 4 women, so there are a total of (3 + 4 = 7) people in line.

We need to arrange these 7 people in a line. Since the order matters, we use permutations.

The number of ways to arrange (n) objects is given by (n) (n factorial).

So, the number of ways the 7 people can stand in line is [tex]\(7\).[/tex]

[tex]\[ 7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040 \][/tex]

Therefore, there are 5040 ways for the three men and four women to stand in line at the checkout counter if we only consider their gender.

The statement is true. The curl of the gradient of a smooth function is always zero.

The statement is true, **if f is a smooth function**, then curl(grad f) = 0 i + 0 j + 0 k.

The gradient of a scalar function f is given by grad f = ∇f. The curl of a gradient is always zero, which means that the curl of grad f is equal to zero.

This is because the curl measures the rotation or circulation of a vector field, and a gradient is a vector field that represents the rate of change of a scalar function in each direction. Since a scalar function does not have any rotation or circulation, the curl of grad f is zero.

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The width of the border is required.

The width of the border is 0.5 m.

l = Length of lawn = 7 m

w = Width of lawn = 5 m

x = Width of border

The figure of the lawn has been attached.

The area of the border will be [tex]6.25\ \text{m}^2[/tex] so,

[tex]x(x+7)+5x=6.25\\\Rightarrow x^2+7x+5x=6.25\\\Rightarrow x^2+12x-6.25=0\\\Rightarrow 100x^2+1200x-625=0\\\Rightarrow x=\dfrac{-1200\pm \sqrt{1200^2-4\times100\left(-625\right)}}{2\times100}\\\Rightarrow x=0.5,-12.5[/tex]

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The logistic function is [tex]S[/tex] shaped curve which use to determine the statistical distribution over the energy states of a system.

The time will take for 2,700 student to hear the rumor is 2.495 days.

Given:

The given logistic function is,

[tex]R(t)=\frac{3000}{1+Be^{kt}}[/tex]

As per the question, at initial stage 5 students heard the rumor. At initial stage [tex]t=0[/tex].

Calculate the constant [tex]B[/tex] at initial stage.

[tex]R(t)=\frac{3000}{1+Be^{kt}}\\R(0)=\frac{3000}{1+Be^{k\times 0}}\\R(0)=\frac{3000}{1+B}[/tex]

Substitute [tex]R(0)=5[/tex].

[tex]\begin{aligned}5=\frac{3000}{1+B}\\1+B= \frac{3000}{5}\\B=599\\\end[/tex]

As per the question, after 1 day 149 students heard the rumor. After 1 day stage [tex]t=1[/tex].

[tex]R(t)=\frac{3000}{1+Be^{kt}}\\R(1)=\frac{3000}{1+Be^{k\times 1}}\\R(1)=\frac{3000}{1+B^k}[/tex]

Substitute [tex]R(1)=149[/tex] and [tex]B=599[/tex].

[tex]\begin{aligned}149=\frac{3000}{1+599e^k}\\e^k=\frac{(3000-1149)}{(599)(149)} \\\end{aligned}[/tex]

Calculate the time take to hear rumor by 2,7000 students.

[tex]\begin {aligned}2700=\frac{3000}{1+599(\frac{3000-149}{599\times 149})^t }\\\frac{3000}{2700}-1 =599(\frac{3000-149}{599\times 149})^t }\\t=\frac{ln(\frac{1}{(599)(9)})}{ln(\frac{3000-149}{599\times 149}) }\\t=2.495\:\rm days\\\end{aligned}[/tex]

Thus, the time will take for 2,700 student to hear the rumor is 2.495 days.

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