What does each letter stand for in the formula p=v x i?

The correct answer is option d. Electromagnetism can repel which is why the electromagnetic force can be used to demonstrate how like charges behave when they come together.

Electromagnetic force, one of the fundamental forces in nature, governs the interactions between electrically charged particles. Like charges (charges of the same sign) experience a repulsive force when they come together, according to Coulomb's law.

This repulsion is a characteristic behavior of electromagnetic interactions, where positively charged particles repel other positively charged particles, and similarly for negatively charged particles.

Why other options are not correct:

Option a is incorrect because electromagnetic force is actually known for having an infinite range, meaning it acts over any distance, although its strength decreases with distance according to the inverse-square law.

Option b is not entirely accurate because while the range is effectively infinite, it does not explain why like charges behave a certain way.

Option c is incorrect because like charges do not attract; they repel each other.

The complete question:

Which best explains why the electromagnetic force can be used to demonstrate how like charges behave when they come together?

a. Electromagnetism has a very small range.

b. Electromagnetism has a infinite range.

c. Electromagnetism can attract.

d. Electromagnetism can repel.

THE ANSWER IS D YOUR WELCOME:)

The minimum distance the truck can stop in without the box sliding into the cab is equal to 77m.

The equations of motion can represent the relation between the initial and final velocity, acceleration, displacement, and time of a moving object.

The equations of motions are usually represented as shown below:

[tex]v = u +at\\S = ut +\frac{1}{2}at^2\\v^2 -u^2 = 2aS[/tex]

Given, the final velocity of the truck, v = 100 Km/h

The third equation of motion: v²- u² = 2ad

v² - 0 = 2 × a × d

a = v²/2d

The coefficient of static friction between the box and the truck = 0.54

We know that, F = ma = [tex]\mu_{s}m g[/tex]

[tex]a = \mu_{s} g[/tex]

[tex]{\displaystyle \frac{v^2}{2d} = \mu_s g[/tex]

(100)²/2d = 0.54 × 9.8

d = 73 m

Therefore, the minimum distance the truck can stop is equal to 73m.

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The direction of the resultant displacement of the dog is determined as 58.2⁰.

How to calculate the direction of the resultant displacement?

The direction of the resultant displacement of the dog is calculated by applying the following formula as shown below.

The sum of the x - component of the displacement;

Dx = 11 m  - 30 m x cos(55)

Dx = - 6.21 m

If the dog must end the run 10 m south of her original starting point, then the resultant displacement in y - direction is 10 m.

Dy = - 10 m

The direction of the resultant displacement of the dog is;

tan θ = Dy / Dx

tan θ = -10 / -6.21

tan θ = 1.61

θ = arc tan (1.61)

θ = 58.2⁰

To find the rate at which the man and woman are moving apart, calculate the distance each has traveled and add their speeds since they are moving in opposite directions. The man traveled 2400 ft and the woman 3600 ft in their respective times, and the rate at which they are moving apart 15 minutes after the woman starts walking is 6 ft/s.

The student's question involves determining the rate at which two people are moving apart after a certain amount of time has passed, with one walking north and the other south from different starting points. To solve this, we can use the concept of relative velocity in one dimension, as the paths of the man and the woman are perpendicular to each other.

Firstly, we calculate the distance the man has walked in 20 minutes (since he started 5 minutes before the woman). At 2 ft/s, he would have walked 2 ft/s × 1200 s = 2400 ft north of point P. The woman, having started 5 minutes later, would have walked for 15 minutes at 4 ft/s, so she would have walked 4 ft/s × 900 s = 3600 ft south of her starting point.

When calculating the rate at which they are moving apart, we need to consider the sum of their speeds as they are moving in opposite directions. The man's speed is 2 ft/s and the woman's speed is 4 ft/s, so the rate at which they are moving apart is 2 ft/s + 4 ft/s = 6 ft/s.

The answer is False, not two factors there are many factors that affect our environment.

The surrounding where we live with all the needs, nature, food, air and our life needed things can be said to be environment. In this environment human were causing many unwanted and environment affecting things.

Factors affecting environment are as follows:

So, there are not only two factors that affect our environment.

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Answer: v1o/v2o=0.8518777161

Explanation:

using the equation from an answer in part A (https://brainly.com/question/14482074)

cancel out L and g and input the other variables in the ratio

((10kg+0.006kg)/0.006kg)sqrt(2(1-cos(4.3))) = 125.1276088 m/s = v1o

((10kg+0.012kg)/0.012kg)sqrt(2(1-cos(10.1))) = 146.8844723 m/s = v2o

v1o/v2o=0.8518777161

Short answer:

So that the cyclist does not slide back down

Long answer:

The main forces a cyclist must conquer are air resistance and gravity. Air resistance increases exponentially with speed. In the switch from cycling on a flat road to hiking a hill, the decreased speed reduces air resistance to the point where drafting other riders offers small benefit. At this point, smaller cyclists, who have finer power-to-weight ratios, will be able to break away from the peloton. Climbing skill can be improved by minimizing weight, and also by pedalling at a constantly elevated rhythm. Large cyclists can attain greater downhill speeds, but on mountainous courses smaller cyclists still have a benefit. 

Answer:

P.E=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)

Explanation:

What is the potential energy of the two-spring system after the point of connection has been moved to position (x, y)? keep in mind that the unstretched length of each spring ℓ is much less than l and can be ignored (i.e., ℓ≪l). express the potential in terms of k, x, y, and l?

potential energy is equal to the kinetic energy

potential energy is energy at rest while kinetic energy is energy due to motion

P=U

P=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)

k=elastic constant of the pring system

x,y are the position

a) In this case the forces are the centrifugal force Fcp, which is directed horizontally toward the wall; the force of static friction Ff with the wall, directed upward; the normal force Fn by the wall, which is directed away the wall; the force of gravity Fg, directed downwards. Then we have that the horizontal forces are all equal in magnitude; similarly the vertical forces are also all equal in magnitude.

b) The minimum coefficient s occurs when force of gravity is equals the max friction force, that is

Fg = Ff,max

m g = s Fn

Also, the normal force has equal magnitude to the centrifugal force:

m g = s Fcp

m g = s m w^2 r

g = s w^2 r

s = g / (r w^2)

With values: g = 9.81 m/s^2; r = 2.5 m; and w = 2pi * 0.60 = 3.77 rad/s; we find

s = 9.81 / (2.5 * 3.77^2) = 0.276

The minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].

Further Explanation:

As the cylinder start to rotate, the people standing against the wall remain stick to the wall. So if we draw the free body diagram of the person, then we can see the balanced forces acting on person's body.

Given:

The rate of rotation of the cylinder is [tex]0.60\text{ rev}/\text{s}[/tex].

The radius of the cylinder is [tex]2.50\text{ m}[/tex].

Concept:

The friction force between the person’s body and the inner surface is balanced by the gravitational firce acting on the person's body.

[tex]\boxed{f_\text{friction}=f_\tect{gravity}}[/tex]                                                   ...... (1)

The force of friction acting on the person's body is:

[tex]f_\text{friction}=\mu N[/tex]

Here, [tex]N[/tex] is the normal reaction,  [tex]\mu[/tex] is coefficient of static friction.

The gravitational force acting on the person's body is:

[tex]f_\text{gravity}=mg[/tex]

Here, [tex]m[/tex] is mass of the body, and [tex]g[/tex] is the acceleration due to gravity.

Substitute [tex]\mu N[/tex] for [tex]f_\text{friction}[/tex] and [tex]mg[/tex] for [tex]f_\text{gravity}[/tex] in equation (1).

[tex]{\begin{aligned}\mu N&=mg\\\mu&=\dfrac{mg}{N}\end{aligned}[/tex]

The Normal force acting on the person's body is balanced by the centrifugal force acting on the persion due to the rotation of the cylinder.

[tex]\boxed{f_\text{normal}=f_\text{centrifugal}}[/tex]                                                  ...... (2)

The centrifugal force acting on the person's body is:

[tex]f_\text{centrifugal}=m\omega^2r[/tex]

Here, [tex]\omega[/tex] is the angular speed of the cylinder, [tex]r[/tex] is the radius of the cylinder.

Substitute [tex]m\omega^2r[/tex] for [tex]f_\text{centrifugal}[/tex] in equation (2).

[tex]N=m\omega^2r[/tex]

Substitute the value of [tex]N[/tex] in equation of static friction coefficient.

[tex]\begin{aligned}\mu&=\dfrac{mg}{m\omega^2r}\\&=\dfrac{g}{\omega^2r}\end{aligned}[/tex]

The acceleration due to gravity on the surface of Earth is [tex]9.81\text{ m}/\text{s}^2[/tex].

The angular speed of rotation of the cylinder is given as:

[tex]\begin{aligned}\omega&=2\pi\times\text{Revolutions per second}\\&=2\pi\times0.6\\&=3.77\text{ rad}/\text{s}\end{aligned}[/tex]

Substitute the values of [tex]\omega[/tex], [tex]g[/tex] and [tex]r[/tex] in above expression.

[tex]\begin{aligned}\mu&=\dfrac{9.81}{(3.77)^2\times2.5}\\&=\dfrac{9.81}{35.53}\\&=0.276\end{aligned}[/tex]

Thus, the minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].

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Answer Details:

Grade: Senior school

Subject: Physics

Chapter: Circular motion

Keywords:

Amusement park, ride, spindle top, six flags, texas, vertical cylinder, hollow, 2.5m, 0.60 rev/s, dropped about, minimum static friction coefficient, rotation rate 0.60.

To reduce the dissipated power by 10% while maintaining the same leakage current, the voltage needs to be reduced in such a way that the new power dissipation equals 90% of the original power, due to the direct proportionality between power and voltage in the formula P = IV.

The question asks: If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? Power dissipation in an electrical circuit is described by the formula P = IV, where P is the power in watts, I is the current in amperes, and V is the voltage in volts.

To find the new voltage required to reduce the power dissipation by 10%, we first have to understand that if the leakage current remains constant, the power reduction is directly proportional to the reduction in voltage. Given the initial power Pm = 1.0 × 10³ W, reducing this power by 10% results in Pnew = 0.9Pm = 0.9 × 1.0 × 10³ W.

Since P = IV and I remains constant, the new power equation after reduction can be written as 0.9Pm = I × Vnew. Substituting the values and assuming the initial current remains unchanged, we solve for Vnew, resulting in a voltage reduction proportionate to the desired 10% power reduction.

The nurse's push must equate to the frictional force for the cart to move at a constant velocity. Since the push is at an angle, its horizontal component, which opposes friction, is calculated and set equal to the friction. Solving for the force exerted by the nurse yields the answer.

This is a physics problem related to force, friction, and motion. To keep the cart at a constant velocity, the net force exerted on it must be zero, as per Newton's second law. This means that the frictional force, which opposes the direction of motion, should be equal to the applied force, which is the nurse's push.

The nurse's push is exerted at an angle, so we have to decompose it into horizontal and vertical components. The horizontal component is the one that actively works against the friction and it can be calculated using the formula: F_Horizontal = F_Nurse cos θ, where 'F_Nurse' is the force applied by the nurse and 'θ' is the angle of the push. Since this component must equal the frictional force, we can rearrange the equation and solve for 'F_Nurse': F_Nurse = Friction / cos θ. Plugging in the known values for friction (65 N) and angle (36 degrees), we can find the magnitude of force the nurse must exert to move the cart at a constant velocity in newtons.

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To move the cart at a constant velocity, the nurse must exert a force of approximately 79.3 Newtons at a downward angle of 35 degrees below the horizontal. The force of friction and the horizontal component of the nurse's force must be equal for the cart to move at a constant velocity.

To calculate the force the nurse must exert to move the cart at a constant velocity, we need to consider the forces acting on the cart. In this case, the force of friction and the force exerted by the nurse are the main forces. The force exerted by the nurse can be broken down into horizontal and vertical components. The horizontal component of the force is responsible for overcoming the force of friction. Since the cart is moving at a constant velocity, the net force in the horizontal direction is zero. To find the magnitude of the force the nurse must exert, we can use trigonometry to find the horizontal component of the force.

The horizontal component of the force can be found using the equation:

F_h = F_n * cos(theta)

Where F_h is the horizontal component of the force, F_n is the total force exerted by the nurse, and theta is the angle of the force below the horizontal. Substituting the values into the equation, we get:

F_h = F_n * cos(35 degrees) = F_n * 0.819

Since the net force in the horizontal direction is zero, the horizontal component of the force must be equal to the force of friction. Therefore, we can write the equation:

F_h = F_f = 65 N

Substituting the value of the force of friction and the expression for the horizontal component of the force, we can solve for the magnitude of the force the nurse must exert:

F_n * 0.819 = 65 N

F_n = 65 N / 0.819 = 79.3 N

The nurse must exert a force of approximately 79.3 Newtons to move the cart at a constant velocity.

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Answer: Both are Brittle

Explanation:

Metals are lustrous, malleable and ductile. Metals are good conductors of heat and electricity.

Non-metals are poor conductors of heat and electricity. Non-metals are brittle and non-lustrous elements.

Elements which have properties between metals and non-metals are known as metalloids.

Some mettaloids are lustrous and conductors of electricity. One property that these elements share with non-metals is that these are brittle i.e. they can easily break.

The property metalloids share with nonmetals is [tex]\boxed{{\text{Both are brittle}}}[/tex].

Further explanation:

Nonmetals:

Elements that gain electrons in a chemical reaction are non-metals. They are the electronegative element that has high ionization energy. Non-metals are either gas, liquid or solid. Nonmetal oxides react with bases and form salts.

Properties of Nonmetals:

Physical State: Most non-metals exist in the form of gas and solid. The exception includes bromine that exists as liquid at room temperature.

Non-Malleable and Ductile: They are brittle and cannot be transformed into wires.

Conduction: Poor conductor of heat.

Luster: Non-metals have no metallic luster.

Melting and Boiling Point: Melting point of non-metals is lower than metals. Also, it is highly variable.

Metalloid:

An element that is a mixture of metals and nonmetals is called metalloids. The six known metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium.

Properties of Metalloids:

Metalloids are metallic brittle solids.

Mostmetalloids are semiconductors and thermal conductors.

Some metalloids conduct electricity like metals.

1. Metalloids are brittle and also nonmetals are very brittle. Hence, both metalloids and nonmetals have this property. Hence option 1 is correct.

2. Metalloids can be either shiny or dull but nonmetals are dull. Hence, option 2 is incorrect.

3. Metalloids have melting points as similar to metals whereas nonmetals have melting points lower than metals. Hence, option 3 is incorrect.

4. Some metalloids conduct electricity like metals whereas nonmetal does not conduct electricity. Hence, option 4 is incorrect.

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Answer details:

Grade: High School

Subject: Chemistry

Chapter: Metals and non-metals

Keywords: metalloids, brittle, lustrous, conductors, melting point, nonmetals, low, metals, high and shiny.

it is known that a shark can travel at a speed of 15 meters/second then the shark can go 150 meters in 10 seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second.

average speed = total distance /Total time

As given in the problem it is known that a shark can travel at a speed of 15 meters/second,

speed of the shark = 15 meters/second

time taken by the shark = 10 seconds

The total distance covered by the shark in 10 seconds = speed ×time

The total distance covered by the shark in 10 seconds  = 15×10

                                                                                            = 150 metes

Thus, the shark can go 150 meters in 10 seconds.

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Final answer:

The change in internal energy of the system is 296 kJ, calculated using the first law of thermodynamics by adding the heat absorbed by the system (186 kJ) to the work done on the system by the surroundings (110 kJ).

Explanation:

The question involves the concept of change in internal energy of a system which is a part of thermodynamics in Chemistry. To determine the change in internal energy, we use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat (Q) added to the system minus the work (W) done by the system on the surroundings.

In this case, the system absorbs 186 kJ of heat and the surroundings do 110 kJ of work on the system. As work is done on the system, it is treated as positive input of energy. Therefore, the change in internal energy (ΔU) for the system can be calculated as follows:

ΔU = Q + W

ΔU = 186 kJ + 110 kJ

ΔU = 296 kJ

The change in internal energy of the system is 296 kJ, assuming all quantities are in the same units (in this case, kilojoules).

Final answer:

To find the height from which the ball was thrown, we can use the equations of motion for projectile motion. The ball was thrown from a height of 44.1 meters.

Explanation:

To find the height from which the ball was thrown, we can use the equations of motion for projectile motion. Since the ball is thrown horizontally, the initial vertical velocity is 0. We can use the equation h = (1/2) g t^2, where h is the height, g is the acceleration due to gravity, and t is the total time the ball is in the air.

Using the given values, we can substitute g = 9.8 m/s^2 and t = 3 s into the equation to solve for h: h = (1/2) * 9.8 m/s^2 * (3 s)^2 = 44.1 m.

Therefore, the ball was thrown from a height of 44.1 meters.

The wavelength of a radio photon from an AM radio station that broadcasts at 1080 kilohertz is approximately 27.8 centimeters.

The wavelength of a radio photon from an AM radio station can be calculated using the formula:

wavelength = speed of light/frequency

Given that the frequency is 1080 kilohertz (or 1080,000 hertz), we need to convert it to megahertz (MHz) by dividing it by 1000. So the frequency is 1080 MHz.

Now, we can substitute the values into the formula:

wavelength = 3 x 10^8 meters per second / 1080 x 10^6 hertz

Performing the calculation, we get:

wavelength = 0.278 meters, or approximately 27.8 centimeters.

The minimum coefficient of static friction needed for the deli owner to set up her display board with an angle of 30° between the two sides is 0.577.

The problem asks for the minimum coefficient of static friction needed for the board to remain stable in a 'V' position. The forces acting on the board in this scenario would be gravity, which acts downward, and the force of static friction, which acts to prevent the board from sliding. The weight of the board acts at the center of gravity, which is at the midpoint of the height of the 'V'.

We need to consider the forces acting horizontally and vertically. Vertically, the total force must be zero, so the gravitational force (weight of the board) equals twice the vertical component of the force of friction. Horizontally, the net force must be zero as well, so the two horizontal forces of friction (one on each board) must balance each other.

Using the formula for the force of friction (friction = normal force x coefficient of friction), and knowing that for each side the normal force equals half the weight of the board, we can establish an equation and solve for the coefficient of friction.

Setting up these relationships, solving for the coefficient of friction gives us a value of tan(30°), which is 0.577. Thus, the minimum coefficient of static friction needed would be 0.577 to keep the board stable at an angle of 30°.

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Answer:

I TOOK THE TEST! the answer is INCREASES AND ENERGY INCREASES!

Answer: 290 J

Explanation:

1) Data:

i) Max's mass = 15 kg

ii) Maya in a sled's mass = 20 kg

iii) slippery snow ⇒ no friction

iv) F = 12 N

v) α = 15°

vi) d = 25 m

2) Physical principles and formula

i) The mechanical workg, W, developed by a constant force, F, that has an angle α with the displacement d, is given by the formula:

W = F × d × cos(α).

ii) The mass of Max is not relevant for the problem, nor the mass of the sled, since the fact that there is not friction, results in that the only force acting is F (12 N, α = 12°).

3) Solution:

W = 12 N × 25m × cos (15°) ≈ 290 J

Work done by Max on the sled is about 290 J.

[tex]\texttt{ }[/tex]

Let's recall the Kinetic Energy and Work formula as follows:

[tex]\boxed {E_k = \frac{1}{2}mv^2 }[/tex]

Ek = kinetic energy ( J )

m = mass of object ( kg )

v = speed of object ( m/s )

[tex]\texttt{ }[/tex]

[tex]\boxed {W = F d}[/tex]

W = work done ( J )

F = force ( N )

d = displacement ( m )

Let us now tackle the problem!

[tex]\texttt{ }[/tex]

Given:

mass of Max = m = 15 kg

mass of Maya and sled = M = 20 kg

magnitude of force = F = 12 N

direction of force = θ = 15°

displacement = d = 25 m

Asked:

work done by Max = W = ?

Solution:

[tex]W = F_x \ d[/tex]

[tex]W = ( F \cos \theta ) d[/tex]

[tex]W = ( 12 \times \cos 15^o ) \times 25[/tex]

[tex]W \approx 290 \texttt{ J}[/tex]

[tex]\texttt{ }[/tex]

Work done by Max on the sled is about 290 J.

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Mathematics

Chapter: Energy

the answer it actually 388800