Alpha particles are respective to the helium-4 ion. Therefore it has a mass of four and a positive charge of two. The correct answer is the mass number increases by 4.
If a nucleus emits an alpha particle, the mass number decreases by 4
What is an alpha particle?An alpha particle is essentially identical to a helium nucleus. An alpha particle has a mass of four units and a positive charge of two units just as the helium nucleus.
Hence, if a nucleus emits an alpha particle, the mass number decreases by 4 while the atomic number decreases by two.
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Both fructose and glucose have an empirical formula of CH2O and a molecular mass of 180.15948 g/mol. Determine the molecular formula.
A)
CH2O
B)
C3H8O3
C)
C6H12O6
D)
C8H16O8
Answer:
C) C₆H₁₂O₆.
Explanation:
We can determine the molecular formula by calculating the molecular mass of different choices.Molecular mass = ∑(no. of atoms * atomic mass).
A) CH₂O:
molecular mass = atomic mass of C + 2*atomic mass of H + atomic mass of O = (12.0 g/mol) + (2 * 1.0 g/mol) + (16.0 g/mol) = 30.0 g/mol.
B) C₃H₈O₃:
molecular mass = 3(atomic mass of C) + 8(atomic mass of H) + 3(atomic mass of O) = 3(12.0 g/mol) + 8(1.0 g/mol) + 3(16.0 g/mol) = 92.0 g/mol.
C) C₆H₁₂O₆:
molecular mass = 6(atomic mass of C) + 12(atomic mass of H) + 6(atomic mass of O) = 6(12.0 g/mol) + 12(1.0 g/mol) + 6(16.0 g/mol) = 180.0 g/mol.
D) C₈H₁₆O₈:
molecular mass = 8(atomic mass of C) + 16(atomic mass of H) + 8(atomic mass of O) = 8(12.0 g/mol) + 16(1.0 g/mol) + 8(16.0 g/mol) = 240.0 g/mol.
So, the right choice is: C) C₆H₁₂O₆.
The molecular formula of the compound is the C₆H₁₂O₆. The correct option is C.
The empirical formula of the fructose and the glucose = CH₂O
The molecular mass of the compound = 180.15948 g/mol
The empirical formula mass of the molecule, CH₂O = 12 + 2(1) + 16 = 30 g/mol
The number of empirical formula units = 180.15948 g/mol / 30 g/mol
The number of empirical formula units = 6
The molecular formula of the compound = 6( CH₂O)
The molecular formula of the compound = C₆H₁₂O₆
Therefore, the molecular formula of the compound is C₆H₁₂O₆. The option C is correct.
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I need help with this question I don’t understand it at all!!!
Answer:
C-14 => N-14 + β⁻
Explanation:
C-14 over time decays by beta emission to N-14. Before decay, C-14 nucleus contains 6 protons and 8 neutrons. It is accepted that a neutron (n°) is composed of 1 proton (p⁺) and 1 electron (e⁻). Beta emission indicates loss/discharge of a high energy e⁻ from the nucleus of C-14 leaving 7 protons and 7 neutrons. The number of protons defines the element, N-14 as a product of the decay process with the β particle (high energy electron) the other. To check, remember, the ∑mass Reactants = ∑mass Products (superscript numbers) and ∑reactant charges = ∑product charges (subscript numbers
₆C¹⁴ => ₇N¹⁴ + ₋₁e° or, C-14 => N-14 + β
2Al + 6HCl ? 2AlCl3 + 3H2 If the chemical reaction produces 129 grams of AlCl3, how many grams of H2 are also produced?
Answer:B 2.92
Explanation: its correct my guy
Answer:
2.83848 grams of [tex]H_{2}[/tex] are produced
Explanation:
Assuming that the reaccions continues until the total consumption of the reagents, it is possible to establish:
1 mol Al = 1 mol [tex]AlCl_{3}[/tex]
2 mol [tex]AlCl_{3}[/tex] = 3 mol [tex]H_{2}[/tex]
Then, by looking at the periodic table, it is possible to know the molar wheigt of the compounds:
1 mol Al = 29.9815 gr
1 mol [tex]H_{2}[/tex] = 2 gr
1 mol [tex]AlCl_{3}[/tex] = 136.3405 gr
Reeplacing the moles with the respectly wheights of compounds:
29.9815 gr Al = 136.3405 gr [tex]AlCl_{3}[/tex]
X gr Al = 129 gr [tex]AlCl_{3}[/tex]
So, 129 grams of [tex]AlCl_{3}[/tex] equals to 28.3673 grams of Al.
Then, following the same line of thought:
29.963 gr Al (2 moles) = 6 gr [tex]H_{2}[/tex] (3 moles)
28.3673 gr Al = Y gr [tex]H_{2}[/tex]
So, 28.3673 grams of Al equals to 2.8384 grams of [tex]H_{2}[/tex].
A saturated solution of silver nitrate is prepared in 100g of water at 20c. The solution is then heated to 50c. How much more silver nitrate must now be added to obtain a saturated solution?
Answer:
233 g.
Explanation:
It is known that:The solubility of silver nitrate at 20.0°C is 222 g per 100 g of water.
The solubility of silver nitrate at 50.0°C is 455 g per 100 g of water.
∴ We need to add (455 g - 222 g = 233 g) of AgNO₃ to obtain a saturated solution at 50.0°C.
Why is the greenhouse effect important to life on earth
Answer:
Because Greenhouse gases let the sun's light shine onto the Earth's surface, but they trap the heat that reflects back up into the atmosphere. And this way, they act like the glass walls of a greenhouse. This greenhouse effect also keeps the Earth warm enough to sustain life.
Explanation:
Answer:
greenhouse gases trap heat for the earth so if it was unavaible no heat would be conserved
Explanation:
How does solar activity affect Earth?
When the sun becomes active, the occurrences of phenomena such as solar flares, coronal mass ejection become frequent. The amount of high-energy particles and extreme shortwave radiation released, such as X-rays and UV, will also increase. These phenomena affect the ionosphere of the Earth's atmosphere the most.
what do the symbols tell you about the conditions of the reaction shown to the right check all boxes that apply
Answer:
Sorry but erm was their supposed to be a image attach with it
Explanation:
Answer: options 1 and 4
Explanation:
How do you do problem bii??
Answer:
Explanation:
Trick question. The cathode is where the reduction reaction takes place. The reduction reaction is the gain of electrons.
Pb+2 + 2e^- ===> Pb The eo for that is - 0.126.
The minus sign indicates that the Pb^2+ is not overjoyed at taking on those two electrons. If it had a say in the matter, it would rather be giving up electrons. In other words, it would rather be the oxidizing equation which would look like this
Pb ===> Pb+2 + 2e^- and the oxidizing potential would be eo = + 0.126
That's what moving right and moving left means. If the eo is - then the preferred reaction is the opposite one.
This is a real language problem and if Znk answers you can take his answer to the bank.
Answer:
[tex]\boxed{\text{(b) (ii) 0.34 V}}[/tex]
Explanation:
If electrons flow from Pb to X through the external circuit, the Pb electrode must be the anode.
The standard reduction potential for Pb²⁺ is -0.126 V.
When we write the half-reaction for the oxidation, the standard oxidation potential for Pb must be 0.126 V.
The cell reactions are:
E°/V
Anode: Pb ⇌ Pb²⁺ + 2e⁻ 0.126
Cathode: X²⁺ + 2e⁻ ⟶ X x
Overall: Pb + X²⁺ ⟶ Pb²⁺ + X 0.47
0.126 + x = 0.47
x = 0.47 – 0.126 = 0.34 V
[tex]\text{The reaction at the X electrode is a reduction,}\\\text{so its standard reduction potential is }\boxed{\textbf{0.34 V}}[/tex]
Neils Bohr published his model of the atomic structure in 1913. He introduced the theory of electrons traveling in orbits around the atom's nucleus, with electrons orbiting only in certain orbits called shells. Each shell can contain a fixed number of electrons.
According to this model of the atom, the chemical properties of an element are mainly determined by
A)
the number of electrons in the outer shells.
B)
the number of electrons in the inner shells.
C)
the total number of electrons in all shells.
D)
the difference between number of electrons and protons.
Elim
Answer:
A) the number of electrons in the outer shells.
Explanation:
The Bohr's model of the atoms shows that electrons orbits the nucleus in energy levels that are discrete and quantised. Orbital electrons are pulled by the nucleus. The nuclear pull is strongest on the shells closer to the nucleus and weakest as we reach the outermost sphere.
From this model, we see that chemical properties are governed by how much electrons an atom is ready to lose from its outermost shell in which the energy is the lowest. It is the electrons in the outermost shell or valence shell that determines how atoms would behave chemically.
Answer:
A
Explanation:
Of the reactions involved in the photodecomposition of ozone (shown below), which are photochemical? 1. o2 (g) + hν → o (g) + o (g) 2. o (g) + o2 (g) + m (g) → o3 (g) + m* (g) 3. o3 (g) + hν → o2 (g) + o (g) 4. o (g) + o (g) + m (g) → o2 (g) + m* (g)
Answer:
The answers are...
Explanation:
2 and 4.
Explain why a balloon expands when taken to a higher elevation if the temperature remains constant? A) The decrease in atmospheric pressure allows the balloon wall to become more elastic. B) The decrease in atmospheric pressure relative to pressure inside the balloon causes it to expand. C) The increase in atmospheric pressure pushes the walls of the balloon outward thus making it larger. D) The increase in atmospheric pressure forces the gases to push harder on the balloon increasing its size.
Answer:
It seens like B would be the correct answer because the higher you go the less pressure is on the outside. think of it like a vacuum chamber, when you suck the air out there is less pressure on the inside, therefor if you were to put a balloon inside a vacuum chamber it would have a similar effect to the balloon high in the atmosphere
Explanation:
Answer:B
Explanation:
I did the USA testprep
If a wave has a wavelength of 13 meters and a period of 0.005, what's the velocity of the wave? A. 2,600 m/s B. 260 m/s C. 1,300 m/s D. 1,560 m/s
Answer:
V = 2600ms⁻¹
Explanation:
Given parameters:
Wavelength(λ) = 13meters
Period (T) = 0.005s
Period(T) is the time it takes for a full cycle of vibration to pass through. It's unit is in seconds (s)
The Velocity of waves is expressed as:
V = fλ
Where f = frequency(s⁻¹)
Frequency of a wave is the number of waves that passes through a point per unit time
f = 1/T
Where T is the period
We can therefore express Velocity of waves as a function of period
V = λ/T
Inputing the parameters, we have:
V = 13m / 0.005s
V = 2600ms⁻¹
Answer:
B) 2,600 m/s
Explanation:
Which pair of elements would most likely bond to form a covalently bonded compound?
Two non-metals pair of elements would most likely bond to form a covalently bonded compound.
What is an element?
It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.
Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.
The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.Elements combine to form compounds.
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Elements that are likely to form a covalent bond are typically nonmetals with similar electronegativity values, which leads to the sharing of electrons, as exemplified by the bonding of hydrogen and oxygen to form water (H₂O).
The question 'Which pair of elements would most likely bond to form a covalently bonded compound?' falls under the subject of Chemistry. When determining whether a pair of elements will likely form a covalent bond, we consider their electronegativity. Covalent bonds generally occur between nonmetallic elements that have similar electronegativity values, meaning they have a comparable ability to attract electrons.
For example, hydrogen (H) and oxygen (O) are both nonmetals and form a covalent bond to create water (H₂O). Another pair of elements that commonly form a covalent bond is nitrogen (N) and hydrogen (H), which combine to form ammonia (NH₃). These elements do not have markedly different electronegativities, which favors the sharing of electrons rather than the transfer of electrons which is characteristic of ionic bonding.
On the other hand, metals and nonmetals such as sodium (Na) and chlorine (Cl) tend to form ionic bonds, where electrons are transferred from one atom to another, due to their large difference in electronegativities.
What do coefficients represent in a balanced equation?
Answer:
relative numbers of each molecule or formula unit
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Explanation:
How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?
Answer:
2.92 gExplanation:
1) Data:
a) V = 500.0 ml = 0.500 liter
b) M = 0.100
c) mass = ?
2) Formulae:
a) Molarity: M = n / V
b) Number of moles: n = mass in grams / molar mass
3) Solution
a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol
b) molar mass NaCl = 58.443 g/mol
c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g
Answer: 2.92 g
Final answer:
To prepare a 0.100 M solution, you will need 2.922 grams of sodium chloride.
Explanation:
To calculate the grams of sodium chloride required to prepare a 0.100 M solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to convert the volume of the solution from milliliters to liters:
500.0 mL = 0.5000 L
Next, we can use the formula to solve for moles of sodium chloride:
0.100 M = moles of NaCl / 0.5000 L
Since the molar mass of sodium chloride (NaCl) is 58.44 g/mol:
moles of NaCl = 0.100 M x 0.5000 L = 0.0500 moles
Finally, we can use the moles of sodium chloride to calculate the grams:
grams of NaCl = moles of NaCl x molar mass = 0.0500 moles x 58.44 g/mol = 2.922 g
What can acid rain do to buildings and statues
The chemicals that acid rain contains can have damaging effects on objects like buildings, monuments, statues, and cars.
Its components can make paint to be peel, stone construction appears old, worn down which reduces the architectural value and beauty.
ExplanationDepending on how acidic the rain is, it can obliterate these constructions to a brutal degree.
First, components like sulfurous, sulfuric and nitric acids mix with air and rain. Then they react with calcite or calcium-based compounds in marble and limestone and dissolve calcite.
The dry depositions of acidic particles contribute severely to the corrosion of construction materials, building paints, stones like marble, limestones and various type of granites.
Acid rains aggravate the life value of buildings and architectural structures.
What is the maximum volume of 0.10 m naoh that can be completely neutralized by 25 milliliters of 0.20 m hcl?
Answer:
50. mL
Explanation:
A solution of benzene in methanol has a transmittance of 28% in a 1.00 cm cell at a wavelength of 254 nm. only the benzene absorbs light at this wavelength, not the methanol. what will the solution's transmittance become (in the same 1.00 cm cell) if the original benzene solution is diluted 10-fold with methanol?
Answer:
[tex]\boxed{88 \%}[/tex]
Explanation:
[tex]A = \epsilon cl\\A = -\log T\\\epsilon cl = -\log T[/tex]
ε and l are constants.
If there are two different concentrations of benzene,
[tex]\dfrac{c_{2}}{c_{1}} = \dfrac{\log T_{2}}{\log T_{1}}[/tex]
Data:
c₁ = c₁; c₂ = 0.1c₁;
T₁ = 0.28: T₂ = ?
Calculation:
[tex]\dfrac{0.10c_{1}}{c_{1}} = \dfrac{\log T_{2}}{\log 0.28}\\\\\log T_{2}= 0.10 \times \log0.28 = -0.0553\\\\T_{2} = 10^{-0.0553} = 0.88 \\\\\boxed{T_{2} = \textbf{88 \%}}[/tex]
Why is thermal energy produced not generally usable to do work? A. Because the thermal energy dissipates too quickly and is not concentrated enough to be used B. Because this energy is lost to the universe C. Because thermal energy is a form of energy that cannot be used to do any work D. Because thermal energy does not have the same equivalent to do work as other forms
Answer:
A sounds like the best answer to me because thermal energy can cool very quickly if its hot
Explanation:
Answer: Option a
Explanation: Thermal energy can be defined as using heat as a form of energy for doing work. It can be used for various processes.
But there is a problem associated with this energy, that is the thermal energy dessipiates very fastly and so it cannot be used as a form of energy for doing work.
It cools down very fastly and so it cannot be used as a source.
An ethylene gas torch requires 3200 L of gas at 3.00 atm What will be the pressure of the gas if ethylene is supplied by a 250.0 L tank?
Answer:
38.4L
Explanation:
Given parameters of the ethylene gas:
Initial Volume V₁ = 3200L
Initial pressure P₁ = 3atm
Final Volume V₂ = 250L
Final pressure P₂ = ?
We need information about the unknown final pressure.
Based on the given parameters, we can apply Boyle's law. The law states that "the volume of a fixed mass of a gas is inversely proportional as the pressure changes if temperature is constant".
NB: We assume that the torch provides a constant source of heat.
The law is expressed mathematically as:
P₁V₁ = P₂V₂
Making the unknown P₂ the subject of the equation gives:
P₂ = P₁V₁ / V₂
P₂ = 3200x3/250
P₂ = 9600/250
P₂ = 38.4L
Pressure of the gas = 38.4L
Using Boyle's Law, we determined that the pressure of ethylene gas will be 38.4 atm when transferred from 3200 L at 3.00 atm to a 250.0 L tank.
To determine the final pressure of the ethylene gas when transferred into a different volume, we can use Boyle's Law.
Boyle's Law states that for a given mass of gas at constant temperature, the volume of the gas is inversely proportional to the pressure of the gas.Boyle's Law Formula
The formula used is :P₁V₁ = P₂V₂
Where:
P₁ = initial pressure (3.00 atm)V₁ = initial volume (3200 L)P₂ = final pressure (to be determined)V₂ = final volume (250.0 L)Rearranging the formula to solve for P₂ :
P₂ = [tex]\frac{P_{1} V_{1} }{V_{2} }[/tex]
Substituting in the given values:P₂ = [tex]\frac{3.00\times 3200 }{250.0}[/tex]P₂ = [tex]\frac{9600}{250.0}[/tex]P₂ = 38.4 atmTherefore, the pressure of the gas in the 250.0 L tank will be 38.4 atm.
Oxygen will have a positive oxidation number when combined with
Oxygen has a positive oxidation number when combined with fluorine, the most electronegative element, which always has an oxidation number of -1. This is an exception to oxygen's usual -2 oxidation state.
Explanation:Oxygen will have a positive oxidation number when combined with fluorine. This is because fluorine is more electronegative than oxygen, which is typically seen with an oxidation number of -2, except in this special case as well as in peroxides where it has an oxidation number of -1. Fluorine, the most electronegative element, always has an oxidation number of -1, and it is the only element with which oxygen can have a positive oxidation number.
For example, in compounds like dioxygen difluoride (O2F2), oxygen has a positive oxidation state. This is an exceptional situation, as oxygen usually exhibits a negative oxidation state due to its high electronegativity, only surpassed by fluorine. Remember, the sum of oxidation numbers in a compound must balance out to zero, or the charge of the ion if it is a polyatomic ion.
Which has the higher boiling point, C3H8 or C8H10? Explain your reasoning.
Answer:C8H10
Explanation:
The greater the number of carbon molecules in the atom, the greater the boiling point
A compound is composed of 85.64% carbon and 14.36% hydrogen. The compound has a formula mass of 42.08 grams. What is the molecular formula?
Answer:
The molecular formula is C₃H₆Explanation:
1) Assume 100 g of substace:
Carbon, C: 85.64% × 100 g = 85.64 gHydrogen, H: 14.36% × 100 g = 14.36 g2) Convert the masses in grams to number of moles
moles = mass in grams / atomic massatomic mass of C: 12.011 g/molatomic mass of H: 1.008 g/molCalculations:
C: 85.64 g / 12.011 g/mol = 7.130 molH: 14.36 g / 1.008 g/mol = 14.25 mol3) State the ratio of moles.
Divide the number of moles of each element by the least number of moles:
C: 7.130 mol / 7.130 mol = 1.0 molH: 14.25 mol / 7.130 mol = 2.0 mol4) Set the empirical formula:
CH₂5) Calculate the mass of one mol of the empirical formula:
CH₂: 12.011 g/mol + 2× 1.088 g/mol = 14.027 g/mol6) Calculate how many times the mass of the empirical formula is contained in the mass of the molecular formula:
42.08 g / 14.027 g = 2.9999 = 37) Set the molecular formula:
Multiply each subscript of the empirical formula by the previos ratio: 3
C: 1 × 3 = 3H: 2 × 3 = 6Conclusion: the molecular formula is C₃H₆
Answer:
C₃H₆
Explanation:
Consider the unbalanced equation for the oxidation of butene.
C4H8 + 6O2 CO2 + H2O
For each molecule of C4H8 that reacts, how many molecules of carbon dioxide and water are produced?
Answer:
B- 4 molecules carbon dioxide 4 molecules water
Explanation:
Just took this on edg.
When 0.5 g of powdered iron (III) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Iron (III) oxide was not used up in the reaction. Based on the information, which of the following is likely to increase the rate formation of the products? Replacing the powdered iron oxide with its cubical crystals Using 150 cm3 of hydrogen peroxide Removing iron oxide from the reaction mixture Using 1.0 gram of iron oxide
Answer:
Using 1.0 gram of iron oxide.
Explanation:
Rate of the reaction depends on many factors:The concentration of the reactants.
The surface area of the reactants or catalyst.
The amount of the catalyst.
Hydrogen peroxide is the reactant and iron (III) oxide is the catalyst.
If we display the various choices:Replacing the powdered iron oxide with its cubical crystals:
This will decrease the surface area of the catalyst exposed to the solution, so the rate formation of the products will decrease.
Using 150 cm³ of hydrogen peroxide:
The volume of the reactant does not affect the concentration of the reactants, so changing the volume has no effect on the rate formation of the products.
Removing iron oxide from the reaction mixture:
Removing the catalyst will decrease (may stop) the rate formation of the products.
Using 1.0 gram of iron oxide:
This will increase the amount of the catalyst used, and so it will increase the rate formation of the products.
So, the right choice is:
the rate formation of the products
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
AlCl3 + Br2 → AlBr3 + Cl2
Answer:
65.08 g.
Explanation:
For the reaction, the balanced equation is:2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,
2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.
Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:n = mass/molar mass = (36.2 g)/(133.34 g/mol) = 0.2715 mol.
Using cross multiplication:
2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.
0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.
∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.
∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass = (0.4072 mol)(159.808 g/mol ) = 65.08 g.
Answer: 65.2 grams
Explanation:
Which part of the hydrocarbon name tells you the amount of carbon in the molecule?
The leading numbers
Ending
The ending numbers
Prefix
Answer:
Prefix
Explanation:
Hydrocarbon are organic compounds that are made up of hydrogen atoms and carbon atoms.The root name of a hydrocarbon is based on whether the hydrocarbon form a chain or a ring.A prefix to the hydrocarbon name comes before the molecule and is based on the number of carbon atoms in the hydrocarbon. For example, a chain eight carbon atoms would be using prefix oct-.The prefix of the hydrocarbon name indicates the amount of carbon in the molecule, derived from the longest continuous carbon chain within the compound, according to IUPAC nomenclature.
The part of the hydrocarbon name that tells you the amount of carbon in the molecule is the prefix. The prefix is determined by the number of carbon atoms in the longest continuous carbon chain. For example, the prefix for a hydrocarbon with three carbon atoms would be 'prop' and the full name for an alkane with this number of carbons would be propane. This naming system is part of the International Union of Pure and Applied Chemistry (IUPAC) rules for nomenclature, which provides a systematic way to name hydrocarbons and other organic compounds.
Hydrocarbon compounds with different numbers of carbon atoms use specific numerical prefixes such as 'meth-' for one carbon, 'eth-' for two, 'prop-' for three, up to 'dec-' for ten, and beyond. The ending of the hydrocarbon name, such as '-ane', '-ene', or '-ol', indicates the type of hydrocarbon or functional group but does not tell you about the number of carbon atoms.
What effect does the concentration of reactants have on the rate of a reaction apex?
Concentration of reactant mostly accelerates the rate of a reaction(at a higher concentration, reactants collide more often).
Explanation:
When there is more concentration of reactants then it means there are more number of molecules. Hence, then there will be more number of collisions taking place in the chemical reaction.
As a result, rate of reaction will increase with increase in concentration.
On the other hand, when there is decrease in concentration of reactants then it means less number of reactant molecules are taking part in the chemical reaction.
Hence, there will be less number of collisions between the molecules due to which there will be decrease in the rate of reaction.
You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1105 M NaOH. If you add 20.00 mL of HCOOH to the beaker before titrating, approximately what volume of NaOH will be required to reach the end point? View Available Hint(s) You are given a solution of (formic acid) with an approximate concentration of 0.20 and you will titrate this with a 0.1105 . If you add 20.00 of to the beaker before titrating, approximately what volume of will be required to reach the end point? 11.1 mL 20.0 mL 72.4 mL 36.2 mL
Answer:
[tex]\boxed{\text{36 mL}}[/tex]
Explanation:
1. Write the balanced chemical equation.
[tex]\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O[/tex]
2. Calculate the moles of HCOOH
[tex]\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}[/tex]
3. Calculate the moles of NaOH.
[tex]\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}[/tex]
4. Calculate the volume of NaOH
[tex]c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}[/tex]
The volume of NaOH required to reach the end point is 36.2 mL
We'll begin by writing the balanced equation for the reaction.
HCOOH + NaOH —> HCOONa + H₂O
From the balanced equation above,
The mole ratio of the acid, HCOOH (nA) = 1
The mole ratio of the base, NaOH (nB) = 1
Finally, we shall determine the volume of the base, NaOHFrom the question given above,
Molarity of base, NaOH (Mb) = 0.1105 M
Volume of acid, HCOOH (Va) = 20 mL
Molarity of acid, HCOOH (Ma) = 0.2 M
Volume of base, NaOH (Vb) =?MaVa / MbVb = nA/nB
(0.2 × 20) / (0.1105 × Vb) = 1
4 / (0.1105 × Vb) = 1
Cross multiply
0.1105 × Vb = 4
Divide both side by 0.1105
Vb = 4 / 0.1105
Vb = 36.2 mLThus, the volume of the base, NaOH is 36.2 mL
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Radium-223 is a radioactive isotope with a half-life of 11.4 days. how long (in days) will it be before 87.5% of the sample has decayed?
The decay constant here is 0.0607 day⁻¹. The sample will remains 34 days before its 87.5 decays.
What is nuclear decay?Heavy radioactive isotopes undergo decomposition into light nucleus by the emission of charged particles such as alpha or beta particles. The radioactive decay is a first order reaction. Thus, the decay constant k can be written as:
K = 1/t ln (W0/ Wt)
W0 is the initial amount of the sample an Wt be the weight after time t.
K can be related to the half time as follows:
k = 0.693/t1/2.
Given that, half life of the Ra sample is 11.4 days.
k = 0.693 / 11.4
= 0.0607 day⁻¹.
12.5 % of the sample remains after 87.5 % is decayed. The time take to decay its 87.5 % is :
t = ln (W0/Wt) / k
= ln (100/12.5) / 0.0607
= 34.4 days.
Therefore, the sample will remains 34.4 days before 87.5 % of it is decayed.
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Final answer:
Radium-223 will take approximately 11.1 days for 87.5% of the sample to decay, based on its half-life of 11.4 days.
Explanation:
11.1 days
83
Because each nuclide has a specific number of nucleons, a particular balance of repulsion and attraction, and its own degree of stability, the half-lives of radioactive nuclides vary widely. For example: the half-life of 203 Bi is [tex]1.9 × 10^19[/tex] years; 232 Ra is 24,000 years; 222 Rn is 3.82 days; and element-111 (Rg for roentgenium) is 1.5 × 10-³ seconds. The half-lives of a number of radioactive isotopes important to medicine are shown Table 21.2, and others are listed in Appendix M.