What causes the development of most clouds and precipitation in the atmosphere?

The evidence supporting the wave model of light is its ability to travel fastest through a vacuum. This property is due to its wave nature, which allows it to propagate without needing a medium.

The piece of evidence that supports the wave model of light is that light travels fastest through a vacuum. This is because, according to wave theory, light is a type of electromagnetic wave that doesn't need a medium to propagate, thus it can travel through empty space (a vacuum) at its highest speed, approximately 299,792 kilometers per second. Other properties such as reflection or causing electrons to be released from a metal surface also occur, but they can be explained by both wave and particle models.

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Light reflects when it hits a surface, which supports the model of light as a wave. correct answer is 2. Light reflects when it hits a surface.

Light is known to exhibit a dual wave-particle nature. Light as a wave is supported by phenomena such as interference and diffraction.

Of the given choices, the piece of evidence that supports the model of light as a wave is that light reflects when it hits a surface. Reflection is a behavior consistent with wave theory because waves can bounce off surfaces.

This behavior is explained by wave theory, demonstrating light's dual wave-particle nature. Interference and diffraction are additional examples supporting light's wave-like properties.

complete question:

Light is described as having a dual wave-particle nature. Which piece of evidence provides support for the model of light as a wave?

Answer:

Answer is D.

Explanation:

Hope my answer has helped you!

Answer:

hydrophilic

Explanation:

hydrophobic means it hates water so a hydrophobic material would separate from the water and just sit there (an example of this is oil)

Answer:

at 100°Celsius water starts to boil

For this case we have that by definition, the boiling temperature (boiling is the passage from liquid to gaseous state) of the water is dependent on the pressure to which the liquid is exposed.

At sea level, the boiling water temperature occurs at 100 degrees Celsius.

Answer:

100 degrees Celsius

Answer:

Circle or pie graph is used to show how a part of something relates to the whole.

Explanation:

Pie graphs are easy to read and can present a very clear picture of the relationships.

Question:

The type of graph used to show how a part of something relates to the whole is which of the following? a. circle graph b. bar graph c. line graph d. direct proportion

Answer:

The type of graph used to show how a part of something relates to the whole is circle graph.

Explanation:

Circle graph also denoted as pie chart. It is generally used to show data analyzed in a small group. The circle graph is made in different parts based on the difference in the properties of the sample. It generally shows the relative analysis of each property for a given set of samples.

So, each parts in the circle graph will tell us the percentage of a property among the other properties present in the sample. Like we can say, if in a class of 100 students, 25 students are girls and 75 students are boys can be drawn in circle graph with two parts having smaller area for girl students and bigger area parts for boy students.

Answer:

E) it absorbs a lot of heat when it melts because of hydrogen bonding

Choices:

A) it is composed only of water

B) it floats

C) it dilutes the taste

D) people like to chew it

E) it absorbs a lot of heat when

Answer:

E) it absorbs a lot of heat when it melts because of hydrogen bonding

Explanation:

Answer:

F is 250 N

d is 0 m

F x d

=250 x 0

=0

The answer is 0.0 J.

Answer:

0.0 J

Explanation:

Answer:

true

Explanation:

if the lens is curved differently or the material is changed then it would affect where the image is which is calculated using the focal point.

sorry I know I'm late but please let me know if I'm right, mark brainliest, and have a great day :)

(a) [tex]24.6 m/s^2[/tex]

At a distance r=R from the centre of the planet, there is no effect due to the outer shell: so, the gravitational field strength at r=R is only determined by the gravity produced by the core of the planet.

So, the strength of the gravitational field is given by

[tex]g= \frac{GM}{R^2}[/tex]

where

G is the gravitational constant

M = 6.24 × 10^24 kg is the mass of the core of the planet

R = 4.11 × 10^6 m is the radius of the core

Substituting into the equation, we find

[tex]g= \frac{(6.67\cdot 10^{-11})(6.24\cdot 10^{24} kg)}{(4.11\cdot 10^6 m)^2}=24.6 m/s^2[/tex]

(b) [tex]13.7 m/s^2[/tex]

at distance r=3R from the centre, the particle feels the effect of gravity due to both the core of the planet and the outer shell between R and 2R.

So, we have to consider the total mass that exerts the gravitational attraction at r=3R, which is the sum of the mass of the core (M) and the mass of the shell (4M):

M' = M + 4M = 5M

Therefore, the gravitational acceleration at r=3R will be

[tex]g'= \frac{G(5M)}{(3R)^2}=\frac{5}{9}\frac{GM}{R^2} = \frac{5}{9}g[/tex]

And susbstituting

g = 24.6 m/s^2

found in the previous part, we find

[tex]g' = \frac{5}{9} (24.6 m/s^2)=13.7 m/s^2[/tex]

The gravitational acceleration at point R is approximately 9.85 m/s².  the gravitational acceleration at point 3R is approximately 1.09 m/s².

The formula for gravitational acceleration:

g = (G × M) / r²

where:

g is the gravitational acceleration,

G is the gravitational constant,

M is the mass of the planet,

and r is the distance from the center of the planet.

Given:

M = 6.24 × 10²⁴ kg

R = 4.11 × 10⁶ m

(a) At point R:

g = (G × M) / R²

g = (6.674 × 10⁻¹¹ × 6.24 × 10²⁴) / (4.11 × 10⁶)²

g = 9.85 m/s²

Therefore, the gravitational acceleration at point R is approximately 9.85 m/s².

(b) At point 3R:

g = (G × M) / (3R)²

g = (6.674 × 10⁻¹¹ × 6.24 × 10²⁴) / (3 × 4.11 × 10⁶)²

g = 1.09 m/s²

Therefore, the gravitational acceleration at point 3R is approximately 1.09 m/s².

To know more about the gravitational acceleration:

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Answer:

an atom is about a trillion times smaller then a speck of dust.

Explanation:

hope this helps :)

An atom is 4 times smaller than a speck of dust when both are compared.

The average radius of an atoms is  about 0.1 nm ( 0.1 x 10⁻⁹ m).

The average radius of a speck of dust is about 0.1 x 10⁻⁵ m.

The ratio of these particles can be compared as follows;

[tex]ratio = \frac{0.1 \times 10^{-4}}{0.1 \times 10^{-9}} = 10^4[/tex]

Thus, we can conclude that when a speck of dust is compared to an atom, an atom will be 4 times smaller than a speck of dust.

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1) The total amount of energy in the universe remains constant.

4) Energy can be converted from one form to another.

5) Energy cannot be created or destroyed.

Best describes energy

Law of conservation of energy is the principle of physics according to which the energy of interacting bodies or particles in a closed system remains constant.

Total energy of any system always remains  constant . Also from law of conservation of energy it can be stated as energy can neither be created nor be destroyed ,it only transforms form one form to other form .

hence , option 1) : The total amount of energy in the universe remains constant.

4) Energy can be converted from one form to another.

5) Energy cannot be created or destroyed.

Best describes energy

learn more about  law of conservation of energy

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Answer:

1, 3, 4, 5

Explanation:

took on edge

Answer:

Explanation:

I suppose it has to do with the way the diagram is drawn. The heat does not reflect which makes both A and B incorrect.

C would have nothing to do with either reflection or refraction.

That only leaves D which is the answer.

The work done by the electric force to move a 1 c charge between two points is calculated by multiplying the charge by the electric potential difference between those points.

The work done by the electric force to move a 1 c charge from point a to point b depends on the electric potential difference, or voltage, between points a and b. The work done is calculated by the equation: Work = Charge * Electric Potential Difference. If we know the electric potential difference between points a and b, we can substitute it into the equation to find the work done. For example, if the potential difference between a and b is 5 volts, the work done to move a 1 c charge would be 1 c * 5 V = 5 Joules.

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Answer:energy times mass

Explanation: yeh

It doesn't matter whether the capacitor happens to be charged or not.  It can be charged to 1/2 volt, or it can be charged to 1 thousand volts, or it can be totally uncharged and wrapped in tissue in a box on the shelf.  None of that has any effect on its capacitance.  Whatever capacitance it has, that's what it has.

In order to increase its capacitance, you would have to . . .

-- increase the area of the plates,

or

-- move the plates closer together,

or

-- fill the space between the plates with a substance that has a greater dielectric constant than air has.

The capacitance of an air-filled capacitor can be increased by reducing the distance between plates, increasing their surface area, or using a material with a higher dielectric constant in place of air.

In physics, the capacitance of an air-filled charged capacitor can be increased by three main ways: reducing the distance between the plates, increasing the surface area of the plates, and using a material with a higher dielectric constant in place of air.

Reducing the distance between the plates increases the electric field between the plates, so more charge can be stored. Increasing the surface area of the plates provides more space for charge to accumulate, thereby increasing the capacitance. Using a dielectric material with a higher dielectric constant than air in between the plates can also enhance the capacitor's ability to store charge.

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In general, sound (mechanical wave) travels faster in solids than in liquids or gases. This is because the speed of the mechanical waves is determined by a relationship between the elastic properties of the medium in which they are propagated and the mass per unit volume of the medium (that is: density).

In other words: The speed of sound varies depending on the medium through which the sound waves travel.

In addition, it varies with changes in the temperature of the medium. This is because an increase in temperature means that the frequency of interactions between the particles that transport the vibration increases, hence this increase in activity increases the speed. That is why the speed of sound in a gas is not constant, but depends on the temperature.

For example, the higher the air temperature, the greater the velocity of propagation.

Answer:

the type of medium and the temperature of the medium

Explanation:

edge quiz 2021

Hello There!

The law of conservation of mass states that Matter/substances/energy  can not be created or destroyed, it can only be transferred from state to state.

To calculate the average surface temperature of the star Sigma, you can use Wien's displacement law, which states that the wavelength of the peak intensity of radiation is inversely proportional to the temperature of the star. Using this equation, the average surface temperature of Sigma is 1 K.

To calculate the average surface temperature of the star Sigma, we can use Wien's displacement law. According to the law, the wavelength of the peak intensity of radiation is inversely proportional to the temperature of the star. The equation for the law is:

λmax = b / T

where λmax is the peak wavelength, T is the temperature, and b is Wien's displacement constant (approximately 2.8978 x 10-3 K·m).

In this case, we're given the peak intensity of radiation as 2 x 106 nm. Converting nm to meters:

2 x 106 nm = 2 x 106 x 10-9 m = 2 x 10-3 m

Substituting the values into the equation:

2 x 10-3 m = (2.8978 x 10-3 K·m) / T

Solving for T:

T = (2.8978 x 10-3 K·m) / (2 x 10-3 m)

T = 1.4489 K

Rounding to the nearest whole number, the average surface temperature of Sigma is 1 K.

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With the exception of Asthma, all of those things, and a lot more that you don't want, could result from untreated diabetes.

Answer:

B. Numbness In Hands and Feet

C. Exhaustion

D. Weight Loss

E. Blurred Vision

Answer:

. The percentage water vapor in surface air varies from 0.01% at -42 °C (-44 °F) to 4.24% when the dew point is 30 °C (86 °F).

hope this helps :)

Explanation:

Answer:

0 to 4 percent

Explanation:

Water vapor varies by volume in the atmosphere from a trace to about 4%. Therefore, on average, only about 2 to 3% of the molecules in the air are water vapor molecules. The amount of water vapor in the air is small in extremely arid areas and in location where the temperatures are very low (i.e. polar regions, very cold weather). The volume of water vapor is about 4% in very warm and humid tropical air.

So, why can't the amount of water vapor in the air be greater than 4%? The answer is because temperature sets a limit to how much water vapor can be in the air. Even in tropical air, once the volume of water vapor in the atmosphere approaches 4% it will begin to condense out of the air (rain). The condensing of water vapor prevents the percentage of water vapor in the air from increasing. If temperatures were much warmer, there would be a potential to have more than 4% water vapor in the atmosphere. Think about the steam trapped in a tea kettle. The very warm temperatures and higher pressures allow for a large amount of water vapor to exist in the air within the tea kettle. Just from watching the steam leave the tea kettle, one can get an idea of the water vapor density within that kettle. The amount of water vapor within the air in the kettle is greater than 4%.

If the earth's oceans were placed on the planet Venus, the ocean water would boil into the atmosphere and produce a very dense steam (current surface temperatures on Venus are 900 degrees Fahrenheit with an average sea level pressure of 92,000 millibars, or 92 times that of Earth). Under this amount of enormous heat and pressure (hot enough to melt lead), water vapor would well exceed 4% of the atmosphere by volume. As a note, Venus does not have any significant amounts of water vapor; the atmosphere of Venus is 96% carbon dioxide and 3.5% nitrogen.

SO! Temperature determines the maximum amount of water vapor that can exist in the air. The higher the temperature, the greater the potential percentages of water vapor in the air, up to a maximum of approximately 4%.

Explanation:

It is now clear that light behaves as a wave and as a particle. It should be noted that the first to propose the corpuscular theory of light was Issac Newton, while the wave theory was initially proposed by Christian Huygens, who was contemporaneous with Newton.

Now, focusing on the corpuscular theory, Newton proposed that light is composed of tiny massless particles, traveling in a straight line and at high speed. In addition, he used the reflection phenomenon of the of light to show that it behaved like particles that when hitting a mirror were reflected by a perfectly elastic collision.

Answer:

Light does not need a medium to travel.

Explanation:

Sound is not a transverse wave; it is a longitudinal wave, with variations in pressure moving in the direction of the wave. Light and radio are electromagnetic and transverse waves, with electric and magnetic fields oscillating perpendicular to the direction of propagation.

The question you are asking about waves concerns whether they are transverse waves or longitudinal waves. Transverse waves involve a disturbance that moves perpendicular to the direction of the wave's travel. On the other hand, longitudinal waves involve disturbances that move in the same direction as the wave's travel. In your list, sound waves are the ones that are not transverse; they are longitudinal. Sound waves in air and water are composed of periodic variations in pressure that travel through the fluid medium.

In contrast, light waves and radio waves are types of electromagnetic waves, and they are inherently transverse waves. This means that the electric and magnetic fields oscillate perpendicular to the direction of wave propagation. Therefore, the correct answer to which one is not transverse is sound.

In nuclear fission, a heavy nucleus splits into two smaller, more stable nuclei, releasing a large amount of energy. These smaller nuclei are more stable because they are closer to the most stable nuclear configuration found in nickel and iron-sized nuclei.

Nuclear fission is the process in which a heavy nucleus splits into two smaller, more stable nuclei, accompanied by the release of energy. This occurs particularly with nuclei that have a mass number higher than 92. During fission, the original nucleus divides into two fragments that are not necessarily equal in size, but are usually closer to the size of iron-56, which is the most stable size for a nucleus. A notable example is the fission of uranium-235, where the nucleus splits into two smaller fragments and releases additional free neutrons and energy in the form of gamma rays.

The larger nucleus undergoing fission must rearrange its nucleons towards a configuration that is closer to that of the most stable nuclei, which are around the size of nickel and iron. This implies that during fission, the resulting nuclei are generally smaller and more stable compared to the original one. Therefore, the correct description of what forms in nuclear fission is two smaller, more stable nuclei (Option A).

Answer:

solid form

Explanation:

Heat is transferred by conduction in a solid form.

Answer:

Positrons are spontaneously emitted from the nuclei of potassium -37

Explanation:

Answer: potassium 37

Explanation:

The wavelength of an electromagnetic wave with a frequency of 8 ⋅ 10^14 Hz and speed of 3 ⋅ 10^8 m/s, calculated using the formula λ = V / F, is approximately 3.75 ⋅ 10^-7 meters.

To find the wavelength of an electromagnetic wave with a known frequency and speed, you can use the formula λ = V / F, where λ is the wavelength, V the speed of light, and F the frequency of the wave

Given that V (the speed of light) = 3 ⋅ 10^8 m/s and the frequency (F) = 8 ⋅ 10^14 Hz, substituting these values into the formula gives: λ = (3 ⋅ 10^8 m/s) / (8 ⋅ 10^14 Hz) .

Solving this equation, we find that the wavelength (λ) of the electromagnetic wave is approximately 3.75 ⋅ 10^-7 meters.

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Answer:

a change in position

a change in velocity

acceleration

a connection between acceleration, velocity,  and position

Explanation:

This physics lab is about studying the principles of motion. It involves measuring and recording the distance and time taken by a cart on a track to understand Newton's laws of motion, speed, and acceleration.

In this physics lab, the core principle being explored is motion. The student is expected to use a cart and a track set up to investigate and learn more about motion by measuring and recording the time that it takes the cart to cover specific distances. The motion of an object is dictated by the principles of physics, particularly Newton's laws of motion. In this case, the cart's motion on the track is described primarily by the first two of these laws.

The first law, also known as the inertia law, suggests that an object will retain its state of motion unless acted upon by an external force. This principle may help explain why the cart continues to move even after you stop applying force. The second law pertains to how the velocity of an object changes when it is subjected to an external force. By measuring different aspects of the cart’s motion, such as the distance it travels and the time it takes, students can calculate the speed and acceleration of the cart under different conditions. This direct, hands-on approach is a practical way to understand Newton’s laws and the concepts of speed and acceleration.

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Answer: The electron moves slower than the speed of light

Explanation:

The de Broglie wavelength [tex]\lambda[/tex] is given by the following formula:

[tex]\lambda=\frac{h}{p}[/tex] (1)

Where:

[tex]h=6.626(10)^{-34}\frac{m^{2}kg}{s}[/tex] is the Planck constant

[tex]p[/tex] is the momentum of the atom, which is given by:

[tex]p=m_{e}v[/tex] (2)

Where:

[tex]m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg[/tex] is the mass of the electron

[tex]v[/tex] is the velocity of the electron  (the value we want to find)

Substituting (2) in (1):

[tex]\lambda=\frac{h}{m_{e}v}[/tex] (3)

Finding [tex]v[/tex] :

[tex]v=\frac{h}{m_{e}\lambda}[/tex] (4)

[tex]v=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(3.31(10)^{-10}m/s)}[/tex] (5)

Finally:

[tex]v=2.197(10)^{6} m/s[/tex]>>> This is the velocity of the electron, which compared to the [tex]v=3(10)^{8} m/s[/tex] of the light is quite slower.

The electron's speed relative to the speed of light is calculated using the de Broglie wavelength formula, which determines the velocity of the electron. The formula is rearranged to solve for velocity and the given details are inserted into the formula to obtain the answer.

The electron's speed can be determined in relation to the speed of light using the de Broglie wavelength formula, which states that an electron's wavelength equals Planck's constant (6.63 x 10^-34 m^2 kg/s) divided by the electron's momentum. Momentum is the product of mass and velocity. The speed of the electron is then calculated by rearranging the formula to solve for velocity.

Given:
de Broglie wavelength, λ = 3.31×10−10 m
Mass of electron, m = 9.11x10^-31 kg
Planck's constant, h = 6.63 x 10^-34 m^2 kg/s
Speed of light, c = 3.00×10^8 m/s

Calculation:
Velocity of the electron, v = h / (m * λ)
The velocity of the electron relative to the speed of light is therefore v/c.

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