what are the common parts of nucleotide?

Answers

Answer 1
sugar and phosphate are common parts
Answer 2
The three main/common parts of a nucleotide are:
A sugar (deoxyribose)
A phosphate (1 phosphorus atom bonded to 4 oxygen atoms)
One of 4 bases (Adenine, Guanine, Cytosine or Thymine)


Related Questions

An electric device delivers a current of 5 a to a device. how many electrons flow through this device in 5 s? (e = 1.60 × 10-19 c)

Answers

2*10^20 electrons Electron flow rate is given by I/e, where I is the current in amps and e is the electric charge constant, in coulombs. This will have units of electrons per second, so we must multiply by the time, t, in seconds. So the full equation is: N = (I*t)/e Plugging in: N = (5a * 5s)/(1.6*10^-19 c) N = 1.5625*10^20 electrons But since we only have 1 significant figure to work with, we state our final value as N = 2*10^20 electrons

1.5625.10²⁰ electrons are flowing through this device in 5 s

Further explanation

Electric current is the amount of electric charge that flows each unit of time

Electric current can also be a ratio between voltage and resistance

Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points

Electrons will flow through the conducting wire that functions as a conductor

The electric current itself can be divided into direct current (DC) or alternating current (AC)

Can be formulated:

[tex]{\displaystyle I = {\frac {Q} {t}},}[/tex]

Where

I is the electric current, Ampere (A)

Q is the electric charge, coulomb (C)

t is time, seconds (s)

An electric device delivers a current of 5 A within 5 s, so the charge is:

Q = I x t

Q = 5 x 5

Q = 25 C

Because 1 electron (e) has a charge of 1.60 × 10⁻¹⁹ C, so the total number of electrons flowing:

= 25 C: 1.60 × 10⁻¹⁹ C

= 15.625.10¹⁹

= 1.5625.10²⁰ e

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electric field

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magnetism

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2.0x10 ^ 20 electrons to pass through a point

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Keywords: electric current, electric charge, electrons, coulombs, amperes, seconds

White gold is an alloy that typically contains 60.0% by mass gold and the remainder is platinum. if 175 g of gold are available, how many grams of platinum are required to combine with the gold to form this alloy? answers

Answers

If a sample of white gold alloy contains 60 percent by mass of gold while the remaining is platinum, then the alloy would contain 40 percent by mass of platinum. Percentage by mass is the amount in mass units of a component in a mixture per 100 unit if mass of the total mixture. We are given the amount of gold available, this represents the 60 percent of the alloy. We calculate for the amount of platinum needed as follows:

Percent of platinum = mass of platinum / mass of gold + mass of platinum
0.40 = mass of platinum / 175 g + mass of platinum
mass of platinum = 117 g

A 125 ml volume of carbon tetrachloride has a mass of 192.5g. what is the density of the liquid

Answers

Hey there!

D = m / V

D = 192.5 / 125

D = 1.54 g/mL

Jupiter’s moon io was discovered to have high concentrations of sulfur oxides in its atmosphere. this, in combination with research into sulfur oxides relating to pollution on earth, has led to renewed interest in sulfur oxide compounds. one compound discovered on io was the blue disulfur trioxide. write the chemical formula for this compound.

Answers

S₂O₃ - disulfur trioxide

Answer:

[tex]S_2O_3[/tex]

Explanation:

Hello,

Nomenclature, is a powerful tool in chemistry to name chemical compounds to successfully distinguish among the thousands and thousands of existing molecular compounds. In rule to stipulate a chemical name y is via specifying the amount of the composing elements into the molecule, thus, the prefix di, accounts for two atoms and the prefix tri for three (this is related with the valence electrons the element has), in such a way, disulfur trioxide is represented with two sulfur atoms and three oxygen atoms, this is:

[tex]S_2O_3[/tex]

Which would be a novel molecule since the sulfur has been reported to have +2,+4 and +6 as the positive oxidation states which are possible to dovetail with oxygen as it is negative.

Kind regards.

I need help please The question it's on the picture

Answers

Peanut oil is a renewable source

4 . suppose you are setting up a reaction that requires an iodide salt and are planning to use sodium iodide. however, at the last minute you find that you are out of sodium iodide, so you must use potassium iodide instead. will you need to weigh out more, less, or the same mass of potassium iodide in order to get the same number of moles of iodide ions?

Answers

You will need to weight out less

Aluminum sulfide reacts with water to form aluminum hydroxide and hydrogen sulfide. identify all of the phases in your answer

Answers

This type of reaction is a metathesis. It involves double replacement of two reactants to yield two products, one of which is an insoluble product called precipitate. In this case, the complete balanced reaction would be

Al2S3(s) + 6 H2O(l) ⇒ 2 Al(OH)3 (aq) + 3 H2S(s)

Aluminum Sulfide (Al2S3) in room conditions is a solid. When it is dissolved in water, it creates an aqueous solution of Aluminum Hydroxide (Al(OH)3). The insoluble precipitate produced is a solid form of Hydrogen Sulfide (H2S). To know the phase of the reactants, you can refer to the Material Safety Datasheets to know the property characteristics of various elements and compounds.

After ensuring the equipment is turned off and unplugged what is the next step in cleaning large equipment by hand

Answers

Given that the equipment is stationary, we should remove particles (such as food and soil) from around the equipment.

This step ensures that large particles are removed and do not hinder the remaining process of cleaning. After doing so, the next step is to remove the removable parts of the machinery. After this has been done, the cleaning steps may be undertaken.

Calculate the hydroxide ion concentration in an aqueous solution that contains 3.50 Ã 10-4 m in hydronium ion

Answers

To determine the concentration of the hyroxide ion in the aqueous solution given, we need a relation between the hydronium ion concentration and the hydroxide ion concentration. For this case, we use the Kw or the water autoionization constant. It is a value which represents the self ionization of water when pure or in an aqueous solution. It ionizes into H+ ions and OH ions. Kw is equal to 1x10^-14 and is the product of the hydronium ion concentration and the hydroxide ion concentration. From this definition, we can calculate the concentration of the hydroxide ions as follows:

Kw = [H+][OH-]
1x10^-14 = 3.50 x10^-4 [OH-]
[OH-] = 2.857x10^-11 M
Final answer:

The hydroxide ion concentration in the solution is calculated to be 2.857 × 10^-11 M using the ion product of water (Kw) and the given hydronium ion concentration.

Explanation:

To calculate the hydroxide ion concentration in an aqueous solution that contains 3.50 Ã 10^-4 M in hydronium ion, you can use the relationship between the hydronium ion [H3O+] and hydroxide ion [OH-] concentrations in water which is known as the ion product of water (Kw).

At 25°C the ion product of water, Kw is 1.0 × 10-14 M^2. These ions are related through the equation [H3O+][OH-]= Kw, which is the mathematical representation of the ion product of water at a particular temperature.

Substitute the given hydronium ion concentration into the equation to calculate the hydroxide ion concentration: [OH-] = Kw / [H3O+]. So, [OH-] = (1.0 × 10-14 M^2) / (3.50 × 10^-4 M) = 2.857 × 10^-11 M. So, the hydroxide ion concentration in the solution is 2.857 × 10^-11 M.

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For the titration of 25.00 mL of 0.150 M HCl with 0.250 M NaOH, calculate:

(a) the pH when neutralization is 50% complete;

(b) the pH when 1.00 mL of NaOH is added beyond the equivalence point.

Answers

1) Chemical reaction

HCl        +       NaOH      --->      NaCl + H2O

25.0 ml            
0.150 M            0.250M

2) 50% completion => 0.025 l * 0.150 M * (1/2) = 0.001875 mol HCl consumed and 0.001875 mol HCl in solution

0.001875 mol HCl => 0.001875 mol H(+)

Volume = Volume of HCl solution + Volumen of NaOH solution added

Volume of HCl solution = 0.0250 l

Volume of NaOH = n / M = 0.001875 mol / 0.250M = 0.0075 l

Total volume = 0.0250 l + 0.0075 l = 0.0325 l

[H+] = 0.001875 mol / 0.0325 l = 0.05769 M

pH = - log [H+] = - log (0.05769) = 1.23

Answer: 1.23

3) Equivalence point

0.02500 l * 0.150 M = 0.250M * V

=> V = 0.02500 * 0.150 / 0.250 = 0.015 l

4) 1.00 ml NaOH added beyond the equivalence point

1.00 ml * 1 l / 1000 ml * 0.250 M = 0.00025 mol NaOH in excess

0.00025 mol NaOH = 0.00025 mol OH-

Volume of the solution = 0.02500 l + 0.015 l + 1.00/1000 l = 0.041 l

[OH-] = 0.00025 mol / 0.041 l = 0.00610 M

pOH = - log (0.00610) = 2.21

pH + pOH = 14 => pH = 14 - pOH = 14 - 2.21 = 11.76

Answer: 11.76

Final answer:

To calculate the pH at different points in the titration of HCl with NaOH, you need to consider the moles of reactants and products and use the Henderson-Hasselbalch equation.

Explanation:

In a titration of 25.00 mL of 0.150 M HCl with 0.250 M NaOH, the pH can be calculated at different points:

(a) When neutralization is 50% complete, we can assume that half of the HCl has reacted with NaOH. This means that the moles of HCl neutralized is half of the initial moles present. Use this information to calculate the moles of NaOH consumed and the remaining HCl. From there, you can use the Henderson-Hasselbalch equation to calculate the pH.

(b) When 1.00 mL of NaOH is added beyond the equivalence point, you can assume that all of the HCl has been neutralized and there is excess NaOH. Calculate the moles of NaOH consumed based on the volume added and use it to determine the concentration of NaOH remaining. Then, use the concentration of NaOH and the hydroxide ion concentration to calculate the pH.

When a compound containing c, h, and o is completely combusted in air, what reactant besides the hydrocarbon is involved in the reaction? express your answer as a chemical formula. identify the phase in your answer?

Answers

When a compound containing c, h, and o is completely combusted in air, the reactant besides the hydrocarbon that is involved in the reaction is, O2(g).

Hydrocarbons burn in air to form water and carbon dioxide as the only products.

Further Explanation  Hydrocarbons  Hydrocarbons are types of compounds that are mostly made up of hydrogen and carbon elements. However other hydrocarbons are made up of carbon, hydrogen and oxygen elements. The major types of hydrocarbons include, alkanes, alkenes, alkynes, alcohols, and alkanoic acids.  Alkanes are saturated hydrocarbons while alkenes and alkynes are unsaturated hydrocarbons containing only carbon and hydrogen atoms.  Alcohols and alkanoic acids contains hydrogen, oxygen and carbon atoms. Combustion of Hydrocarbons  Hydrocarbons burn in air to form carbon dioxide and water as the only products.

That is;

For hydrocarbons with carbon and hydrogen

CxHy + O2(g) = CO2(g) + H2O(g)  

For the compound containing carbon, hydrogen and oxygen  

CxHyOn + O2 = CO2(g) + H2O(l)

Examples  

Propane which is an alkane burns in air to form water and mineral salt.

C3H8(g) + O2(g) = CO2(g) + H2O(l)

Ethanol is a hydrocarbon in the homologous series of alcohols. It burns in air to form carbon(IV)oxide and water.

C2H5OH(l) + 3O2(g) = 2CO2(g) + 3H2O(l)

Keywords: Combustion, hydrocarbons  

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Level: High school

Subject: Chemistry  

Topic: Organic chemistry  

Sub-topic: Combustion of hydrocarbons

A sealed container holds 0.020 moles of nitrogen (n2) gas, at a pressure of 1.5 atmospheres and a temperature of 290 k. the atomic mass of nitrogen is 14.0 g/mol. the boltzmann constant is 1.38 × 10-23 j/k and the ideal gas constant is r = 8.314 j/ mol · k = 0.0821 l · atm/mol · k. the mass density of the gas is closest to

Answers

Data:

n = 0.020 moles

Gas: nitrogen (N2) gas

p = 1.5 atm

T = 290 k =

atomic mass of nitrogen = 14.0 g/mol.

the boltzmann constant is 1.38 × 10-23 j/k (it is not required to solve this problem)

ideal gas constant, R = 8.314 j/ mol · k = 0.0821 l · atm/mol · k.

Question: the mass density of the gas

Solution:

Formulas:

pV = nRT

mass density = mass / volume

mass = n * molar mass

molar mass = 2 * atomic mass = 2 * 14.0 g/mol = 28.0 g / mol

mass = 0.020 mol * 28 g/mol = 0.56 g

pV = nRT => V = nRT / p = 0.020 mol * 0.0821 (atm*l /K*mol) * 290K / 1.5 atm

V = 0.3175 liter = 317.5 ml

density = m / V = 0.56 g / 317.5 ml = 0.0018 g/ml = 0.0018 kg / l = 1.8 kg / m^3
Final answer:

To find the density of the nitrogen gas, we use the equation of state for ideal gases, PV=nRT and rearrange it to find Volume. We also calculate the mass of gas using the number of moles and molar mass. Finally, we get the density of nitrogen gas as 1.4 g/L.

Explanation:

To find the mass density of this nitrogen gas, we will use the equation of state for ideal gases given as PV=nRT. Where:

P is the pressure (given as 1.5 atm),V is the volume which we need to find,n is the number of moles (0.020 moles of N2),R is the universal gas constant (given as 0.0821 l · atm/mol · k),T is the temperature in Kelvin (290 K).

First, we rearrange the equation to solve for V (Volume): V = nRT/P. Substituting the given values, we find that volume V = (0.020 mol)(0.0821 l·atm/mol·K)(290 K) / 1.5 atm =  0.40 L.

Now, we compute the mass of the nitrogen gas. We know that the molar mass of molecular nitrogen N₂ is 28.01 g/mol, so the mass m of the gas is m = n*M = (0.020 mol)(28.01 g/mol) = 0.56 g.

Finally to get the density we take Density (ρ) = mass/volume = 0.56 g / 0.40 L = 1.4 g/L.

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As temperature increases, the ______________ of marble will also increase

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As temperature increases, the GRAIN SIZE of marble will also increases. Marble is a non foliated metamorphic rock. Metamorphic rocks are rocks that had change forms as a result of heat and pressure. Temperature and pressure have diverse effects on metamorphic rocks, but for marble, as the temperature increases, the grain size of the rock also increases.

Final answer:

The reactivity of marble increases with temperature due to the enlargement of calcite crystals and the recrystallization of the rock. Increased temperature can lead to a faster chemical reaction rate, especially with powdered marble, which has a larger surface area exposed for reactions.

Explanation:

As temperature increases, the reactivity of marble will also increase. Marble is comprised mainly of calcite, which is altered under heat or pressure to form calcium carbonate. When marble is exposed to high temperatures, such as around 400°C, and various confining pressures, its calcite crystals tend to grow larger and the rock recrystallizes, essentially transforming the limestone base into a denser and typically white rock, often with colorful markings due to impurities.

Moreover, the reaction rate with marble in chemical processes can be influenced by temperature and the physical form of the marble. For instance, powdered marble, with its increased surface area, reacts faster than larger marble chips. The smaller the marble particles, the more surface molecules are exposed, facilitating a quicker reaction when the temperature is raised.

Thus, in contexts such as artistic sculpting or architectural use, where marble's durability and aesthetic qualities are prized, understanding the impact of temperature on its reactivity and structure is crucial.

Starting with 0.250l of a buffer solution containing 0.250 m benzoic acid (c6h5cooh) and 0.20 m sodium benzoate (c6h5coona), what will the ph of the solution be after the addition of 25.0 ml of 0.100m hcl? (ka (c6h5cooh) = 6.5 x 10-5)

Answers

To determine the pH of the resulting solution, we need to determine the concentration of hydrogen ions in the solution. To do this we use, the acid dissociation constant of C6H5COOH. We do as follows:

C6H5COOH = H+ + C6H5COO-
C6H5COONa = Na+ + C6H5COO-
HCl = H+ + Cl-

Using the ICE table before adding HCl,
            C6H5COOH         H+         C6H5COO-
I              0.250                  0              0.20
C              -x                       x               x
---------------------------------------------------------------
E          0.250 - x              x             0.20+x

Ka = 6.5 x 10^-5 = x(0.20+x) / 0.250-x 
x = 8.12x10^-5 M
0.20+x = 0.2000812 M
0.250 - x = 0.24992 M

After addition of HCl,
[H+] = 8.12x10^-5 M (0.250 L) + 0.100 M (.025 L) / 0.025 +0.250 = 9.165x10^-3 M
[C6H5COO-] = 0.2000812 M (.250) / .025 + .250 =0.1819 M 
[C6H5COOH] = 0.24992 M ( .250 ) / .025 + .250 = 0.2272 M

      C6H5COOH         H+             C6H5COO-
I        0.2272        9.165x10^-3         0.1819
C         -x                       x                     x
---------------------------------------------------------------
E     0.2272 - x    9.165x10^-3+x    0.1819+x

 6.5 x 10^-5 =(9.165x10^-3+x )(0.1819+x) / 0.2272-x 
x = - 9.08x10^-3 M

pH = -log [9.165x10^-3 - 9.08x10^-3] =1.74

Answer: New pH will be 4.06 .

Explanation: The problem could easily be solved using Handerson equation. Handerson equaton is used to calculate the pH of buffer solution.

[tex]pH=pK_a+log(\frac{base}{acid})[/tex]

For the given problem, the buffer solution is a mixture of a weak acid(benzoic acid) and a salt of it, known as conjugate base(sodium benzoate).

When a strong acid is added to the buffer solution then it reacts with the base(benzoate ion) present in the buffer solution and produce a the weak acid(benzoic acid).

The reaction could be shown as:

[tex]C_6H_5COO^-(aq)+H^+(aq)\rightleftharpoons C_6H_5COOH(aq)[/tex]

First of all we calculate the initial moles of acid and base originally present in the buffer solution and for this the volume is multiplied by the molarity.

initial moles of benzoic acid = [tex]0.250L(\frac{0.250mol}{1L})[/tex]

= 0.0625 moles

initial moles of benzoate ion = [tex]0.250L(\frac{0.20mol}{1L})[/tex]

= 0.0500 moles

moles of HCl or [tex]H^+[/tex] added to the buffer = [tex]25.0mL(\frac{1L}{1000mL})(\frac{0.100mol}{1L})[/tex]

= 0.0025 moles

From the equation we have written above, HCl and benzoate ion react in 1:1 mol ratio. As HCl is limiting reactant, 0.0025 moles of it will react with exactly 0.0025 moles of benzoate ion and form 0.0025 moles of benzoic acid.

So, the moles of benzoic acid after addtion of HCl = 0.0625 + 0.0025 = 0.065 moles

moles of benzoate ion after addition of HCl = 0.0500 - 0.0025 = 0.0475 moles

Total volume of the solution = 0.250 L + 0.025 L = 0.275 L

concentration of benzoic acid = [tex]\frac{0.065mol}{0.275L}[/tex]

= 0.236M

concentration of benzoate ion = [tex]\frac{0.0475mol}{0.275L}[/tex]

= 0.173M

Pka is calcuulated from the given Ka value as:

[tex]pK_a=-logK_a[/tex]

[tex]pk_a=-log(6.5*10^-^5)[/tex]

[tex]pK_a[/tex] = 4.19

Let's plug in the values in the Handerson equation:

[tex]pH=4.19+log(\frac{0.173}{0.236})[/tex]

pH = 4.19 - 0.13

pH = 4.06

So, the pH of the solution after an addition of HCl will be 4.06 .

A pure silver ring contains 5.15×1022 silver atoms. how many moles of silver atoms does it contain? express the number of moles to two significant figures.

Answers

1 mole ------------------ 6.02x10²³atoms
(moles) -----------------5.15x10²² atoms

moles silver = ( 5.15x10²²) * 1 / 6.02x10²³ = 

moles silver = ( 5.15x10²²)  / 6.02x10²³ =

=> 0.085 moles of silver
Final answer:

To find the number of moles of silver atoms in the silver ring, divide the number of particles by Avogadro's number.

Explanation:

To find the number of moles of silver atoms in the silver ring, we can use Avogadro's number. Avogadro's number tells us that 1 mole of any substance contains 6.022 x 10^23 particles. In this case, we are given that the silver ring contains 5.15 x 10^22 silver atoms. We can use the following equation:

Number of moles = Number of particles / Avogadro's number

Substituting the given values, we get:

Number of moles = 5.15 x 10^22 silver atoms / (6.022 x 10^23 atoms/mol) ≈ 0.0855 mol ≈ 0.086 mol (rounded to two significant figures)

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Which are the more common types of solutions?

Answers

Hey there! :

1) Solid Solutions 

Solid solutions are formed only by solutes and solid solvents. In everyday life, the main examples of this type of solution are metallic alloys.

2) Liquid Solutions

Liquid solutions have liquid solvent, usually water, and solutes can be solid, liquid or gaseous.

3) Gaseous solutions

This kind of solution is formed by the only mixture of gases. Air is an example, as its approximate composition is 78% nitrogen gas, 21% oxygen gas and 1% of other gases.

Phosphorus has the molecular formula p4, and sulfur has the molecular formula s8. how many grams of phosphorus contain the same number of molecules as 7.88 g of sulfur?

Answers

1) Find the number of molecules in 7.88 g of sulfur

molar mass of S8 = 8*atomic mass of S = 8 * 32.0 g / mol = 256.0 g/mol

Number of moles  = mass in grams / atomic mass = 7.88 g / 256.0 g / mol = 0.0308 moles

2) Find the mass of 0.0308 moles of P4

mass = number of moles * molar mass

molar mass of P4 = 4 * atomic mass of P = 4 * 31 g/mol = 124 g/mol

mass of P4 = 0.0308 moles * 124 g/mol = 3.8192g ≈ 3.82 g.

Answer: 3.82 grams of P4 will have the same number of molecules as 7.88 g of S8 (that is 0.0308 moles of molecules)
Final answer:

To find the grams of phosphorus that contain the same number of molecules as 7.88 g of sulfur, use the concept of molar mass and Avogadro's number.

Explanation:

To determine the grams of phosphorus that contain the same number of molecules as 7.88 g of sulfur, we need to use the concept of molar mass and Avogadro's number. First, we calculate the number of moles of sulfur by dividing its mass by its molar mass. Then, we use the molar ratio between sulfur and phosphorus from their molecular formulas to calculate the number of moles of phosphorus. Finally, we multiply the number of moles of phosphorus by its molar mass to obtain the grams of phosphorus.

Step 1: Calculate the moles of sulfur:

moles of sulfur = mass of sulfur / molar mass of sulfur

Step 2: Calculate the moles of phosphorus:

moles of phosphorus = moles of sulfur × (molar ratio of phosphorus/sulfur)

Step 3: Calculate the grams of phosphorus:

grams of phosphorus = moles of phosphorus × molar mass of phosphorus

After performing these calculations using the given values, the grams of phosphorus that contain the same number of molecules as 7.88 g of sulfur is obtained.

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What are two things that characterize the practice of science

Answers

The two things that characterize the practice of science are empirical evidence and community consensus.

That is being able to get the evidence that proves a certain theory, hypothesis or assumption and being neutral in accepting or rejecting the evidence and the results. You should not be biased while drawing conclusions as if this happens, then these conclusions might not be exact or correct.

Which statement best describes the properties of metals?
A) they are shiny and bend without breaking
B) they are dull and are good electrical insulators
C) they conduct electricity well and are brittle
D) they can be flattened and do not conduct heat well

Answers

The correct option is A.

Metals have certain characteristics properties, they include the following: they are ductile, malleable, shiny, hard, lustrous, flexible and they are good conductor of heat and electricity. The malleability of metals refers to their ability to withstand bending and hammering without breaking. Metals are not dull, neither are they brittle, those are the properties of non metals.

Answer : The correct statement is, (A) they are shiny and bend without breaking

Explanation :

Metals : Metals are the elements that easily loose electrons and forms cations.

The properties of the metals :

Generally all the metals are hard except sodium and potassium are soft.They are malleable that means it can be molded into different shapes.They are ductile that means it can be molded into thin wire.They are good conductor of heat and electricity.

Non-metals : Non-metals are the elements that easily gain electrons to form an anion.

The properties of the non-metals :

They are non-malleable that means it can not be molded into different shapes.They are non-ductile that means it can not be molded into thin wire.They are poor conductor of heat and electricity.They are brittle in nature.

Hence, the best statement is, (A) they are shiny and bend without breaking

A solution's ph is a measure of what? strength or weakness acid dissociation constant hydronium ion concentration molarity percent composition

Answers

The answer would be strength. Because the Ph is the measurement of how strong or how high the hydronium ion in a solution

The pH is the potential of Hydrogen is a scale that is used to specify the acidity. In the acidic solution of H+ ions, the scale is logarithmic and indicates the concentration of hydrogen ions in the solution.

The pH value at 25° C is less than 7 is acidic. Those values greater than 7 are basic and those with just 7 are neutral like water.

Hence the option C that is hydronium ion concentration is correct.

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A certain reaction with an activation energy of 205 kj/mol was run at 485 k and again at 505 k . what is the ratio of f at the higher temperature to f at the lower temperature?

Answers

Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

K1 = A * e ^ (-Ea / RT1)

K2 = A* e ^(-Ea / RT2)

=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }

=> K1 / K2 = e ^ (2.0134494) ≈ 7.5

Answer: 7.5




Final answer:

The ratio of the frequency of effective collisions for a reaction at higher to lower temperature can be found using the Arrhenius equation, which illustrates that the reaction rate increases with temperature due to more molecules having sufficient energy to overcome the activation energy barrier.

Explanation:

The question revolves around the concept known as the Arrhenius equation, which describes how the rate of a chemical reaction is affected by changes in temperature and activation energy. The ratio 'f' represents the frequency of effective collisions leading to a reaction. The Arrhenius equation suggests that as temperature increases, the rate constant of the reaction also increases because a greater fraction of molecules will have the necessary energy to overcome the activation energy barrier.

To calculate the ratio of the frequency of effective collisions at two different temperatures for a reaction with an activation energy (Ea) of 205 kJ/mol, we use the Arrhenius equation:

K = Ae-(Ea/RT)

Where K is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant (8.314 J/mol K), and T is the temperature in kelvins. By taking the ratio of the rate constants at 505 K and 485 K (K2/K1), we can find the ratio of 'f' at the higher temperature to the lower temperature.

The analysis of the change in reaction mechanism with temperature typically shows that, as seen with a reaction with a lower activation energy of 54 kJ/mol, a temperature increase, even by 10 degrees Celsius, can significantly impact the reaction rate, often doubling it. While the exact ratio of 'f' would require computation, the concept remains that the reaction rate will increase with temperature due to the exponential factor in the Arrhenius equation.

A golf ball and bowling ball are moving and both have the same kinetic energy.Which one is moving faster? If they move at the same speed, which one has more kinetic energy?

Answers

it is the bowling ball because it is heavy.

A solid is placed in a solution. Which observation most likely indicates that a chemical reaction has occurred?

Answers

A change in color, odor, or texture   

(Also rust)

Calculate the hydroxide ion concentration for an aqueous solution that has a ph of 3.45

Answers

Final answer:

The hydroxide ion concentration for a solution with a pH of 3.45 can be calculated as 10^-10.55 M.

Explanation:

The hydroxide ion concentration for an aqueous solution with a pH of 3.45 can be calculated using the formula [OH-] = 10-pOH. Since pH + pOH = 14, we can find that the pOH is 14 - 3.45 = 10.55. Therefore, the hydroxide ion concentration is 10-10.55 M.

Learn more about Hydroxide ion concentration here:

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The hydroxide ion concentration for a solution with a pH of 3.45 is approximately 2.82 × [tex]10^{-11[/tex] M.

To calculate the hydroxide ion concentration for an aqueous solution with a pH of 3.45, we need to follow these steps:

Calculate the hydronium ion concentration [[tex]H3O^+[/tex]] using the formula: [[tex]H3O^+[/tex]] = 10-pH.Using the given pH of 3.45, calculate [[tex]H3O^+[/tex]]:
[[tex]H3O^+[/tex]] = 10-3.45 ≈ 3.55 × [tex]10^{-4[/tex] M.Determine the concentration of OH- ions using the relationship between [[tex]H3O^+[/tex]] and [[tex]OH^-[/tex]] given by the ion-product of water, Kw (1.0 × [tex]10^{-14[/tex] at 25°C):
[[tex]OH^-[/tex]] = Kw / [[tex]H3O^+[/tex]].Substitute the values into the formula:
[[tex]OH^-[/tex]] = 1.0 × [tex]10^{-14[/tex]/ 3.55 × 10-4 ≈ 2.82 × [tex]10^{-11[/tex] M.

The hydroxide ion concentration for the solution with a pH of 3.45 is approximately 2.82 × [tex]10^{-11[/tex] M.

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?

Answers

Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters


Which pair of atoms would form a covalent bond ?
calcium (Ca) and bromine (Br)
rubidium (Rb) and sulfur (S)
cesium (Cs) and nitrogen (N)
oxygen (O) and chlorine (Cl)

Answers

Salutations!

Which pair of atoms would form a covalent bond ?

Oxygen (O) and chlorine (CI) are the pair of atoms that would form a convalent bond.

Hope I helped!


Answer:

oxygen (O) and chlorine (Cl)

Explanation:

As the electronegativity of an element increases It is more likely to make an ionic bond. e.g. the metallic elements. On the moderate values of electronegativity, elements tend to make covalent bond.

Oxygen and chlorine will make covalent bond because the electronegativity difference between these two elements is 0,5 so there bond will be covalent in nature.

_______ are prophylactic agents used to treat bronchoconstriction.

Answers

Bronchodilators are prophylactic agents used to treat bronchoconstriction.

How many molecules of carbon dioxide are in 243.6 g of carbon dioxide?

Answers

Hey there ! 

Molar mass carbon dioxide:

CO2 = 44.01 g/mol

1) number of moles :

1 mole CO2 ------------- 44.01 g
(moles CO2) ------------ 243.6 g

moles CO2 = 243.6 * 1 / 44.01

moles CO2 = 243.6 / 44.01

=> 5.535 moles of CO2

Therefore:

1 mole -------------------- 6.02x10²³ molecules
5.535 moles ------------ ( molecules CO2)

molecules CO2 = 5.535 * ( 6.02x10²³) / 1

=> 3.33x10²⁴ molecules of CO2

The number of molecules of carbon dioxide present in 243.6 g of carbon dioxide is 3.33 × 10²⁴ molecules

From the question,

We are to determine the number of molecules of carbon dioxide that are in 243.6g of carbon dioxide

First, we will determine the number of moles of carbon dioxide present

Using the formula,

[tex]Number\ of\ moles\ = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of carbon dioxide = 44.01 g/mol

Number of moles of carbon dioxide = [tex]\frac{243.6}{44.01}[/tex]

Number of moles of carbon dioxide = 5.5351 moles

Now, for the number of molecules,

Using the formula,

Number of molecules = Number of moles × Avogadro's constant

Number of molecules = 5.5351 × 6.022 × 10²³

Number of molecules of carbon dioxide = 3.33 × 10²⁴ molecules

Hence, the number of molecules of carbon dioxide present in 243.6 g of carbon dioxide is 3.33 × 10²⁴ molecules

Learn more on calculating number of molecules here: https://brainly.com/question/14464650

Why do scientists need an accurate atomic model? Select one: A. The atom is the most important structure in the universe. B. It allows scientists to predict things about objects that are too small to see. C. Models allow scientists to avoid having to do real experiments. D. The atom cannot be divided into smaller particles.

Answers

B. it allows scientists to predict things about objects that are too small to see

Answer:

B. It allows scientists to predict things about objects that are too small to see.

Explanation:

Hello,

In science, we're always looking for the study of tinier things as long as we're interested about what the matter is made of. Several atomic models such as Bohr's, Rutherford's, Dalton's and the actual one have been proposed in order for us to understand how the protons, neutrons and electrons are assembled into the atom because they are too small to see (about 0.5 fm) thus, with that better understanding, we can research and develop novel applications for new materials based on the micromolecular behavior of the atom.

Best regards.

when this chemical equation is correctly balanced what is the coefficient of the nal molecule I2+Na2S2O3+Nal+Na2S4O6

Answers

I₂ + 2Na₂S₂O₃ → 2NaI + Na₂S₄O₆

k(NaI)=2

Correctly balancing a chemical equation involves adding coefficients to ensure the number of atoms for each element is equal on both sides. As the given equation has a typo, a general method for balancing equations and an example with sodium and chlorine was described.

The question asks about balancing a particular chemical equation to find the coefficient of NaI. However, the given equation seems to have a typographical error and is not complete. In the context of this question, let's address a general approach on how to balance a chemical equation:

Write down the unbalanced equation.

Determine the number of atoms of each element in the reactants and products.

Adjust coefficients (not subscripts) to get the same number of atoms of each element on both sides.

Repeat steps until all elements are balanced.

Check to ensure that the total charge is the same on both sides if the equation includes ionic species.

For example, the equation for the reaction of sodium (Na) with chlorine gas (Cl2) to form sodium chloride (NaCl) is balanced by placing a '2' in front of Na and NaCl:

2 Na (s) + Cl₂ (g) → 2 NaCl (s)

In this balanced equation, we see that the number of sodium and chlorine atoms are equal on both sides, confirming that the equation is correctly balanced.

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