Answer:
Let x be the number.
It is given that a 15 : 9 aspect ratio and a screen that is 42 inches.
Aspect ratio states that the ratio of the display image’s width to its height.
Then;
Width of the television of(w) = 15x
and height of the television(h) = 9x.
Since, television is in the form of Rectangle.
And it is also, given that the screen is 42 inches .
⇒Diagonal of the television(D) = 42 inches
Using formula of diagonal of the rectangle :
[tex]D^2 =w^2+h^2[/tex]
Substitute the given values to solve for x;
[tex]42^2 = (15x)^2+(9x)^2[/tex]
[tex]1764 = 225x^2 + 81x^2 = 306x^2[/tex]
or
[tex]x^2 = \frac{1764}{306} = 5.76[/tex]
[tex]x = \sqrt{5.76} = 2.4[/tex]
Then:
width of the television (15x) = 15(2.4) = 36 inches and
Height of the television (9x) = 9(2.4) = 21.6 inches.
Therefore, the actual dimensions of the television are;
width = 36 inches and height = 21.6 inches.
6 painters can paint the fence in 15 hours. How long would it take 5 workers to do the same job?
Answer:
12.5 hours
Step-by-step explanation:
15/6 is 2.5. 2.5 is how many hours per worker. 5 times 2.5 is 12.5 hours
5x-6=19 what is the variable
Answer:
x=5
Step-by-step explanation:
5x-6=19
first you add 6 to both sides now you have 5x=25 then you divide by 5 on both sides then you get x=5
Question
5x-6=19 what is the variable
Answer:
5Step-by-step explanation:
5x - 6 = 19
5x = 19 + 6
5x = 25
x = 25 : 5
x = 5
15PTS!!
What is the best approximation of the solution to the system to the nearest integer values?
(−2, 6)
(7, −2)
(6, −2)
(−2, 7)
Answer:
(-2,6)
Step-by-step explanation:
The solution to a system of equations is where the two graphs intersection. By looking at the graph we can see that they cross at an x coordinate of approximately -2.4 and at a y coordinate of just above 6. We do not have to be too specific since we just have to be to the nearest integer.
(-2,6)
complete the following statement given: QXR=NYC a.QX= ? b. Y=?
Answer:
Step-by-step explanation:
The given congruent triangles △QXR and △NYC mean that corresponding sides and angles are equal. Hence, line segment QX equals NY and angle Y equals angle X.
The symbols △QXR and △NYC stand for two triangles which are mentioned to be congruent. Congruency in triangles means they have the same size and shape. This implies that the corresponding sides and angles of the two triangles are equal.
a) As per the congruency of the triangles, line segment QX in triangle △QXR would be congruent to corresponding segment in triangle △NYC, which is NY. Hence, line segment QX = NY.
b) Referring to the same principle, angle Y in triangle △NYC should be equal to its corresponding angle in triangle △QXR. Considering the order of the letters in triangles, angle Y would correspond to angle X. Hence, angle Y = angle X.
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If the odds against an event are 2:7 ,then the pobability that the event will fail to occur is__?
Answer:
The probability will be 2/7.
Hope this helps :D
The probability that the event will fail to occur is 7:9 .
How to calculate the probability that event will fail to occur having given odds against -Given that the odds against an event is 2:7 or 2/7.
The meaning of odds against an event is the ratio of the number of times the respective event does not happen compared to the number of times the event occur .
So for the given problem, it refers that for every 2 occurrences that the event does not occur there will be 7 occurrences that it will happen.
Thus the total number of occurrences of the event is (2 + 7) = 9
This means that the event will occur definitely 2 times in every 9 times total outcome.
The probability that the event will occur is 2/9 or 2:9 .
Therefore the probability that the event will fail to occur is 1 - 2/9 = 7/9 or 7:9 .
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Charlotte is running at a rate of 9\,\dfrac{\text{km}}{\text{h}}9
h
km
.
What is Charlotte's speed in \dfrac{\text{m}}{\text{s}}
s
m
?
Step-by-step explanation:
Given speed of Charlotte in kilometer per hour = 9 km/h
We need to find the Charlotte's speed in meter per second.
We know 1 kilometer = 1000 meter
And 1 hour = 3600 seconds.
Plugging those values of km and hour in given speed in km/h, we get
[tex]9\ \frac{km}{h} = 9\times \ \frac{1000m}{3600 seconds}[/tex]
[tex]=\frac{10m}{4s}= 2.5\ m/s[/tex].
Therefore,
Charlotte's speed in meter/second is 2.5m/s.Answer:
Speed of Charlotte in a Unit which includes Km and hour [tex]=9 \frac{\text{Km}}{\text{hour}}[/tex]
1 Km=1000 meter
1 hour=60 minutes=3600 seconds
Speed of Charlotte in a Unit which includes meter and second is
[tex]=\frac{9 \times 1000}{3600}\frac{\text{meter}}{\text{seconds}}\\\\=\frac{90}{36}\frac{\text{meter}}{\text{seconds}}\\\\=\frac{5}{2}\frac{\text{meter}}{\text{seconds}}[/tex]
PLEASE HELP!
If food costs $520.00 and your total budget is $2,100.00, what percent of your budget is spent on food?
<3 Please explain how to do it. :)
Answer:
24.7619048 %
Step-by-step explanation:
The percent spent on food
food/total
520/2100
.247619048
This is in decimal form
Multiply by 100 to change it to percent
24.7619048 %
A shoreline is eroding at a rate of 1/3 foot per 3 months.how many feet are eroding per year
Answer:
1 1/3 feet per year
Step-by-step explanation:
Steps:
1. How many months per year? 12.
2. 12 divided by 3 (number of months) =4
3. multiply 1/3 and 4.
4. Your answer is 4/3 or 1 1/3 feet per year.
The shoreline is eroding at a rate of 4/3 feet per year, which is approximately 1.33 feet per year, calculated by multiplying the 3-month erosion rate of 1/3 foot by 4.
The question is about calculating the annual rate of shoreline erosion given the erosion rate for a specific shorter period. If a shoreline is eroding at a rate of 1/3 foot per 3 months, we can find the yearly erosion rate by multiplying that rate by the number of 3-month periods in a year, which is 4 (since there are 12 months in a year).
To calculate:
Multiply the 3-month erosion rate by 4:
(1/3 foot per 3 months) x 4 (3-month periods in a year) = 4/3 feet per year
Therefore, the shoreline is eroding at a rate of 4/3 feet, or approximately 1.33 feet, per year.
Hello, I have a question about quadratic equations. I don’t know how to slove these:
1. (x-6)(2x-6)=20
2. (x+3) ² = 8x+12
3. (3x-1)(x+5)=3x ²
can somebody help me?
Answer:
Step-by-step explanation:
Answer:
1.X= 8 or 1
2.X= 3 or -1
3. X = 5/14
Step-by-step explanation:
1. Expanding your original equation (x-6)(2x-6)=20) , you get 2x^2-18x+36=20. Then, subtract 20 from both sides. You get 2x^2-18x+16=0. Now this is a standard Quadratic equation. Use the quadratic Formula to solve this, you get X= 8 or 1.
2. 1. Expand : x²+6x+9-8x-12=0 2. Simplify : x^2-2x-3=0 3. Solve as a quadratic equation : x= 3 or -1.
3. Same thing as the first one!
Hope I helped! <3
Please help with the figure below
Answer:
<1 =33
<2 = 147
<4 = 147
Step-by-step explanation:
Angle 1 equals angle 3 because they are vertical angles. Vertical angles are opposite angles made by two intersecting lines.
<1 = <3
<1 = 33
Angle 2 and <3 are supplementary angles because they form a straight line. The add to 180 degrees
<2 + <3 = 180
<2 + 33 = 180
Subtract 33 from each side
<2 +33-33 = 180-33
<2 = 147
Angle 2 equals angle 4 because they are vertical angles
<2 = <4
<4 = 147
a deck 48 cards is divided equally among 6 colors if red is one of the colors in the deck what is the probability that the first card drawn will be red
Martin will earn $20 per hour at a new job. During training, he will earn $15 per hour. What percent of Martin's regular hourly rate will he earn during training?
Answer:the answer is 75%
Step-by-step explanation:
Martin will earn 75% of his regular hourly rate during his training period, which is calculated by dividing the training hourly rate ($15) by the regular hourly rate ($20) and multiplying by 100%.
Explanation:To determine what percent of Martin's regular hourly rate he will earn during training, we need to compare his training wage to his regular wage. Martin's regular hourly rate is $20 per hour, and during training, he earns $15 per hour.
The percentage can be calculated using the formula:
Percent Earned During Training = (Training Hourly Rate / Regular Hourly Rate) x 100%
Now, plug in Martin's earnings:
Percent Earned During Training = ($15 / $20) x 100%
Percent Earned During Training = 0.75 x 100%
Percent Earned During Training = 75%
Therefore, Martin will earn 75% of his regular hourly rate during his training period.
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6x-14=2-10x what is the x
[tex]6x-14=2-10x\qquad\text{add 14 to both sides}\\\\6x=16-10x\qquad\text{add 10x to both sides}\\\\16x=16\qquad\text{divide both sides by 16}\\\\\boxed{x=1}[/tex]
[tex]Check:\\\\6x-14=6(1)-14=6-14=-8\\\\2-10x=2-10(1)=2-10=-8\\\\CORRECT[/tex]
Answer:
x=1
Step-by-step explanation:
6x-14=2-10x
First step is to add 10x to each side
6x+10x-14=2-10x+10x
16x-14=2
Now add 14 to each side
16x-14+14=2+14
16x=16
Divide each side by 16 to isolate x
16x/16 =16/16
x =1
the length of a rectangle is 4 times its width. write an expression for the area of the rectangle.
If,
a + b = 8,
ab + c + d = 23,
ac + bd = 28, and
cd = 12,
find the values of a, b, c, and d.
Answer: There are four possible solutions
a = 3, b = 5, c = 6, d = 2a = 4, b = 4, c = 3, d = 4a = 4, b = 4, c = 4, d = 3a = 5, b = 3, c = 2, d = 6Step-by-step explanation:
I was unable to manipulate this system to develop solvable equations, so I made a table consisting of 7 rows with the following 5 columns:
a (values of 1 thru 7)b (values of 7 thru 1)a·b (multiplying column 1 by column 2)c + d (subtracting column 3 from 23)cd=12 (two addends from column 4 that create a product of 12)Table 1
[tex]\begin{array}{c|c|c|c|c}{a&b&ab&c+d&cd\\1&7&7&16&\text{null}\\2&6&12&11&\text{null}\\3&5&15&8&2,6\\4&4&16&7&3,4\\5&3&15&8&6,2\\6&2&12&11&\text{null}\\7&1&7&16&\text{null}\\\end{array}[/tex]
I used the valid solutions (rows 3 thru 5) to determine which combinations satisfied ab + cd = 28.
Table 2
[tex]\begin{array}{c|c|c|c|c}a&b&c&d&ab+cd\\3&5&2&6&6+11=17\\3&5&6&2&18+10=28^*\\4&4&3&4&12+16=28^*\\4&4&4&3&16+12=28^*\\5&3&2&6&10+18=28^*\\5&3&6&2&30+6=36\\\end{array}[/tex]
* represent the valid solutions
If f(x)=x2-2x and g(x) = 6x+4, for which values of x does (f+g)(x)=0
[tex]f(x)=x^2-2x;\ g(x)=6x+4\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=0\Rightarrow(x^2-2x)+(6x+4)=0\\\\x^2+(-2x+6x)+4=0\\\\x^2-4x+4=0\\\\x^2-2x-2x+4=0\\\\x(x-2)-2(x-2)+0\\\\(x-2)(x-2)=0\iff x-2=0\\\\\boxed{x=2}[/tex]
How to study for Hesi exam
From net earnings of 740 per month Lisa Jones must spend 200 for her portion of the rent on an apartment she shares with two friends what percent of her net income is her rent payment
Answer:
27% of her net income is her rent payment
Step-by-step explanation:
Net earnings = $740
Lisa spend $200 for rent payment
We need to find out what percent of net earning is her rent payment
Let x be the percentage
x% of net income = rent
x% * 740 = 200
[tex]\frac{x}{100} * 740 = 200[/tex]
Multiply both sides by 1004
740x = 20000
divide both sides by 740
x=27.02702703
So its approximately 27%
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule A(n)=-3+(n-1)(-2.2)
[tex]A(n)=-3+(n-1)(-2.2)=-3+(n)(-2.2)+(-1)(-2.2)\\\\A(n)=-3-2.2n+2.2=-0.8-2.2n\\\\\text{Substitute n = 1, n = 4, n = 10}:\\\\A(1)=-0.8-2.2(1)=-0.8-2.2=-3\\\\A(4)=-0.8-2.2(4)=-0.8-2.2(4)=-0.8-8.8=-9.6\\\\A(10)=-0.8-2.2(10)=-0.8-22=-22.8[/tex]
A model is created to show 5 thousands blocks, 4 hundreds blocks, and 9 ones blocks. How would this number be written in standard form?
Answer:
Five thousand- four hundred and nine.
Step-by-step explanation:
Really need help please Quadratic Equation?
A model rocket is launched with an initial upward velocity of 30 m/s. The rockets height h ( in meters) after t seconds is givenby the following.
h=30t-5t^2
Find all values of t for which the rockets height is 10 meters.
Round your answers to the nearest hundredth
Answer:
t = 0.35, t = 5.65
Step-by-step explanation:
You are given h = 30t - 5t^2. Put this in standard form order (ax^2 + bx + c) by switching the two terms.
h = -5t^2 + 30t
Now you want to find all the values of t for which the rocket's height is 10 meters, so your equation will be equal to 10 instead of h, because 10 is the height you are solving for.
10 = -5t^2 + 30t
Make the entire equation equal to 0 by subtracting 10 from both sides.
0 = -5t^2 + 30t - 10
To solve this quadratic equation, the easiest way would be to use the quadratic formula: [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Identify your a, b, and c values in the standard form equation (a = -5, b = 30, c = -10) and substitute these values into the quadratic formula.[tex]\frac{-(30)\pm\sqrt{(30)^2-4(-5)(-10)} }{2(-5)} \rightarrow \frac{-30\pm\sqrt{900-200=700} }{-10} \rightarrow \frac{-30\pm\sqrt{700} }{-10}[/tex]
We have (-30 ± sqrt 700)/-10.
Use a calculator to input the two solutions and solve for them; (-30 + sqrt 700)/-10 and (-30 - sqrt 700)/-10.
[tex]\frac{-30+\sqrt{700} }{-10} = 0.35[/tex]
[tex]\frac{-30- \sqrt{700} }{-10} =5.65[/tex]
The quadratic formula is used to solve the equation h = 30t - 5t^2 when h is set to 10 meters, yielding two times at which the rocket's height is 10 meters: approximately 0.59 seconds and 3.41 seconds.
10 = 30t - 5t2
Moving all terms to one side we get:
5t2 - 30t + 10 = 0
To simplify, we divide the entire equation by 5:
t2 - 6t + 2 = 0
Now we can apply the quadratic formula:
t = √ (62 - 4*1*2) )/ (2*1)
Calculating under the square root, we get:
t = (6 √ (36 - 8) )/ 2
t = (6 ± √28) / 2
Thus, the two solutions for t are:
t = (6 + √28) / 2 and t = (6 - √28) / 2
Rounded to the nearest hundredth, the values of t are approximately 0.59 s and 3.41 s. The rocket reaches a height of 10 meters at these two instances during its flight - once when ascending and once when descending.
cindy can bake 36 cupcakes in 1 hour. she needs a total of 144 cupcakes. she has already made 18 cupcakes. how many hours will it take cindy to bake the rest? write and solve the equation.
Answer:
The answer would be 4 more hours.
Step-by-step explanation:
Since she can make 36 cupcakes in 1 hour,
144 divided by 36 is 4, so it would take four more hours to make the rest.
Hope I helped! God bless you :-)
In ΔABC, m∠A = 40°, m∠B = 60°. Find m∠C. (Hint: Draw the auxiliary line BD parallel to the line segment AC and take a look at the same side and the alternate interior angles)
Answer:
The measure of angle C is 80 degree.
Step-by-step explanation:
Given information: In ΔABC, ∠A = 40° and ∠B = 60°.
Draw the auxiliary line BD parallel to the line segment AC.
If a transversal line intersects the pair of parallel line, then the alternate interior angles are same.
The angle 1 and 2 are alternate interior angles of angle A and B respectively. Therefore angle 1 is equal to angle A and angle 2 is equal to angle C.
Angle 1,2 and B are supplementary angles because they lie on a straight line, therefore their sum is 180 degree.
[tex]\angle 1+\angle B+\angle 3=180^{\circ}[/tex]
[tex]\angle A+\angle B+\angle =180^{\circ}[/tex]
[tex]40^{\circ}+60^{\circ}+\angle C=180^{\circ}[/tex]
[tex]\angle C=180^{\circ}-100^{\circ}[/tex]
[tex]\angle C=80^{\circ}[/tex]
The angle sum property is another way to solve this problem.
According to the angle sum property, the sum of interior angles of a triangle is 180 degree.
Therefore the measure of angle C is 80 degree.
point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form
Answer:
[tex]4\sqrt{10}[/tex]
Step-by-step explanation:
We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).
To find the length of segment AB we will use distance formula.
[tex]\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Upon substituting coordinates of point A and point B in distance formula we will get,
[tex]\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}[/tex]
[tex]\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}[/tex]
[tex]\text{Distance between point A and point B}=\sqrt{16+144}[/tex]
[tex]\text{Distance between point A and point B}=\sqrt{160}[/tex]
[tex]\text{Distance between point A and point B}=4\sqrt{10}[/tex]
Therefore, the length of segment AB is [tex]4\sqrt{10}[/tex].
Josh has five-eighths of a foot of plywood. To finish building the deck, he needs five times that amount. How many feet of plywood does Josh need?
A. 3 feet
B. 3 one-half feet
C. 3 one-eighth feet
D. 3 two-ninths feet
Josh needs 3 and one-eighth feet of plywood to finish building his deck. This conclusion is derived from multiplying the amount of plywood he currently has (5/8 feet) by 5.
Explanation:The problem stated tells us that Josh has five-eighths of a foot of plywood and he needs five times that amount to finish building the deck. We can solve this problem by performing a simple multiplication operation. The method to solve it would be: 5/8 (amount of plywood Josh has) * 5 (amount of plywood required) = 25/8 = 3 1/8 feet. Therefore, Josh needs 3 and one-eighth feet of plywood to finish building his deck.
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What ranges of scores have a frequency of 1
Answer:
20-30 & 40-50
Step-by-step explanation:
To find which range of scores have a frequency of 1, let's break it all down into separate ranges.
20-30: 1
30-40: 2
40-50: 1
50-60: 2
60-70: 6
70-80: 9
80-90: 13
90-100: 5
We can see in our different ranges that the range 20-30 and 40-50 have a frequency of 1.
How did we find this?
Analyze the chart and find which area shows the range, the bars are the frequencies of the different ranges.
What is the 6th term in the arithmetic sequence defined by the explicit formula
an=8n-3?
Answer: The 6th term is 45
Step-by-step explanation:
for the 6th term you would substitute 6 for n
an = 8n - 3
an = 8 * 6 - 3
an = 48 - 3
an = 45
How do I even do this?
Answer:
[tex]y\leq -x-5[/tex]
Step-by-step explanation:
First you find the equation of the line. Start by finding the slope of the line, using the two points given: (-5,0), (0,-5).
[tex]\frac{0--5}{-5-0} = \frac{5}{-5} = -1[/tex]
The y intercept is -5.
Your equation is then y = -1x-5.
To find which inequality to use, plug in a point within your region and see if the statement is true. I would choose (-3,-3)
-3 __ -1(-3)-5
-3 __ -2 you would fill this in with a <, so that is what goes in your equation. since the line is solid and not dotted, you include the underline in the sign.
a−2>4. What is a's solution?
How do you do this
Help please
Thanks
It's a linear function. We need only two points to the plotting of the graph.
[tex]5x-y=5\qquad\text{subtract 5x from both sides}\\\\-y=-5x+5\qquad\text{change the signs}\\\\y=5x-5\\\\for\ x=0\to y=5(0)-5=0-5=-5\to(0,\ -5)\\\\for\ x=1\to y=5(1)-5=5-5=0\to(1,\ 0)[/tex]