what are the 2 forms of memory retrieval?

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Answer:

Discovered by Sir Isaac Newton, this law states that every object in the universe that has mass attracts every other object in the universe that has mass. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between their centers. When applying this to a situation with two objects, the object with the smaller mass will do most of the moving because the other object has too much inertia to move any noticeable amount.

Explanation:

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Let the direction are given as follows

[tex]+x = east[/tex]

[tex]-x = west[/tex]

[tex]+y = North[/tex]

[tex]-y = South[/tex]

now for the above displacement

it moves east for 5 m so it is

[tex]x_1 = 5[/tex]

then goes north for 3 m

[tex]y_1 = 3[/tex]

then goes west for 2 m

[tex]x_2 = -2 m[/tex]

now total displacement in East or x direction

[tex]x = x_1 + x_2 = 5 - 2 = 3m[/tex]

total displacement in North of Y direction

[tex]y = 3m[/tex]

so final coordinates are

[tex]x = 3, y = 3[/tex]

Part b)

position vector is given as

[tex]r = x\hat i + y\hat j[/tex]

[tex]r = 3\hat i + 3\hat j[/tex]

so the magnitude of the vector is given as

[tex]|r| = \sqrt{3^2 + 3^2}[/tex]

[tex]|r| = 3\sqrt3[/tex]

I might want to do fire related crime examination as it would be so magnificent to dissect or research on the off chance that it was illegal conflagration or an inadvertent. It is cool to examine a blast and see where it originated from and who may have done it.

Discovering where everything started and having it lead me to every one of these focuses would energize.

Arson or explosion investigation and evidence testing are careers that suit those with interests in criminal justice, chemistry, and forensic science. Arson and explosion investigators determine the causes of fires and explosions, which can be highly stressful due to the potential legal consequences. Evidence testing is more laboratory-based, using science to provide evidence in court cases, which can be appealing for those who enjoy the sciences.

Whether one would enjoy a career in arson or explosion investigation, or in evidence testing entirely depends on an individual's interests and skills. People who are drawn to these fields often have an interest in criminal justice, chemistry, and forensic science. These careers require analytical thinking, an eye for details, and the ability to problem-solve under pressure.

Arson and explosion investigators work on determining the causes of fires and explosions. This can be appealing to those who enjoy solving complex problems and have an interest in safety and prevention measures. However, it can also be a highly stressful profession, as the results of your investigation can have significant legal and personal consequences for those involved.

Evidence testing, on the other hand, is more focused on laboratory work. This work involves testing materials found at crime scenes to provide scientific evidence that can be used in a court case. This can be rewarding to those who enjoy chemistry, biology, or physics. It can also be a challenging career, as the accuracy of your results is paramount and can greatly impact the outcomes of criminal cases.

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The fastest in speed of sound is steel. The slowest in speed of sound is oxygen. Hope this helped! I don't really know how to answer this but by looking at the table it looks like this can be one of the conclusions.

The measurements in the table allow for the following conclusion: Stiff and dense materials like steel and granite allow sound to propagate extremely fast (5-6 km/s) while lower density ones, like the fluids, reduce this speed to about 1.5km/s, with the lowest-density media (gases) allowing for only order of hundreds of m/s.

The measurements are consistent with a model of energy propagation consisting of spheres (modeling the molecules) and springs connecting them (modeling the molecular bonds). It can be shown that the mass of the spheres and the stiffness of the springs are factors in speed of energy propagation.

When a compass is placed within a magnetic field, it aligns in a direction parallel to the field.

At the point when a compass is put inside an attractive field, it adjusts toward a path parallel to the field.

Hope this helps ^_^

Experiment reliability can be maximized through employing control and experimental groups, careful manipulation and measurement of independent and dependent variables, and using random selection and assignment.

The combination of variables that will make an experiment the most reliable includes the implementation of control groups and experimental groups, the careful manipulation and measurement of independent and dependent variables, and the usage of random selection and assignment of subjects to prevent bias.

Control groups, that receive a placebo, allow for comparison and control for potential confounding factors that might impact the results. The independent variable, which is manipulated by the researcher, should ideally be the only significant difference between the experimental and control groups. The dependent variable is then measured to assess the effect of the independent variable.

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The reliability of an experiment can be enhanced by controlling the independent variable, establishing a control group, using a double-blind study design, and random assignment of subjects. Consistent experimental procedures and control of lurking variables also contribute to the reliability.

The reliability of an experiment can be enhanced by a careful combination of variables, specifically pertaining to the design and execution of the experiment. One key aspect is the control of the independent variable, which is the variable that is manipulated or changed in the experiment.

Moreover, the establishment of a control group is paramount for comparison. The control group acts as a benchmark and remains unexposed to the experimental manipulation, further controlling for any chance factors that might influence the results of the study.

The experiment's reliability can also be significantly improved by incorporating a double-blind study design. This methodology involves keeping both researchers and participants unaware of the group assignments, reducing the chance of expectancy or bias affecting the results. Random assignment of subjects to treatment groups also helps to limit the influence of lurking variables. These are variables which are not considered in the study but that may affect the results and hence, the validity of the findings.

The careful control of these variables, along with consistent experiment procedures, can increase the reliability of an experiment.

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Motion graph:

Hurricanes gain strength by using warm ocean waters as their primary energy source. The warm water evaporates and condenses, releasing latent heat, fueling the storm's intensification and driving its powerful winds.

Warm ocean waters and favourable atmospheric conditions strengthen hurricanes. Latent heat from warm, moist ocean air rising and condensing into clouds and rain powers them. Latent heat release fuels the storm. Warm, wet air rises, lowering surface pressure. Air fills this low-pressure area, rotating and organising the storm. The Coriolis effect, induced by Earth's rotation, spins the storm, strengthening it.

Hurricanes need low vertical wind shear, which limits wind speed and direction with height. Low wind shear lets the storm intensify vertically. Hurricanes receive energy from warm ocean waters, latent heat release, minimal wind shear, and the Coriolis effect.

To know more about energy source

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Answer:

Option (2)

Explanation:

The earth is comprised of denser materials such as iron and nickel and other siderophile elements in the core and silicate materials in the mantle. The temperature at the core of the earth is extremely high that generates a force, that allows the molten materials (magma) to rise up from the bottom of the mantle towards the crust, in the form of convection currents. This upward movement of magma forces the lithospheric plates to move.

Thus, magma rises from the bottom of the mantle towards the crust.

Hence, the correct answer is option (2).

a)

Y₀ = initial position of the stone at the time of launch = 0 m

Y = final position of stone = 20.0 meters

a = acceleration = - 9.8 m/s²

v₀ = initial speed of stone at the time of launch = 30.0 m/s

v = final speed = ?

Using the equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

v² = 30² + 2 (- 9.8) (20 - 0)

v = 22.5 m/s

b)

Y₀ = initial position of the stone at the time of launch = 0 m

Y = maximum height gained

a = acceleration = - 9.8 m/s²

v₀ = initial speed of stone at the time of launch = 30.0 m/s

v = final speed = 0 m/s

Using the equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

0² = 30² + 2 (- 9.8) (Y - 0)

Y = 46 m

(a)The speed of the stone when it reaches [tex]20.0 m[/tex] is approximately [tex]22.5 m/s[/tex]

(b)The maximum height it reaches is approximately [tex]45.9 m[/tex].

Let's analyze the motion of the stone in two parts: finding its speed at a height of 20.0 meters and its maximum height.

(a) Speed at [tex]20.0 m[/tex]

We can use the following kinematic equation:

[tex]v^2 = u^2 + 2as[/tex]

Initial speed [tex]u = 30.0 \, \text{m/s}[/tex]

Acceleration [tex]a = -9.8 \, \text{m/s}^2[/tex] (since gravity acts downwards)

Displacement [tex]s = 20.0 \, \text{meters}[/tex] (upward positive)

Substituting in the given values:

[tex]v^2 = 30.0^2 + 2(-9.8)(20.0)\\\\v^2 = 900 - 392\\\\v^2 = 508[/tex]

Hence:

[tex]v = \sqrt{508} \approx 22.5 \, \text{m/s}[/tex]

(b) Maximum Height

At maximum height, the speed ([tex]v[/tex]) will be 0. Using the same kinematic equation:

[tex]0 = 30.0^2 + 2(-9.8)s0 = 900 - 19.6s[/tex]

Solving for [tex]s[/tex]:

[tex]s = \frac{900}{19.6} \approx 45.9 \, \text{meters}[/tex]

Thus, the highest point the stone may reach is roughly [tex]45.9 m[/tex].

Solution:

Step wise solution

Let r1 be the distance from the Earth to the point where

the gravitational accelerations are the same and let r2 be the distance

from the Moon to that point.

Then, r1+ r2 = r12 = 383,000 km.

Let Re be the radius of earth

and let Rm be the radius of moon

Let, ge be the gravity of earth

and let gm be the gravity of moon

The fact that the gravitational attractions by the Earth and the Moon

at this point are equal leads to the equation

gE(Re/r1)=gM(Rm/r2)

9.8(6380/r1)=1.62(1738/r12-r1)              

(here, Re=6380, gE=9.8m/s^2,  gM=1.62m/s^2 and r12=383,000 km

9.8*6380/(1.62*1738)=r1/(383000-r1)

therefore,

r1=344,770 km

Hope this answer wil help you

Answer:

Calculate the distance between the center of the earth and the center of the moon at which the gravitational force exerted by the earth on an object is equal in magnitude to the force exerted by the moon on the object

Explanation:

solution steps

The answer is D; A substance that dissolves another substance.

D. Solvent is a substance that dissolves another substance.

One variable is changed at a time

We know that, Power is defined as rate of doing work

Power = Work ÷ time  Watts,

Given ; Force = 200 N

            Distance = 25 m , and time (t) = 10 s.

            First determine the work, Work = Force × distance

                                                                 = 200 ×  25

                                                             W = 5000 J

            Now, Power =  5000 ÷ 10

                                 = 500 W

Let after time "t" the Position of A and B are in such a way that A is heading to B and its velocity makes some angle with x axis

So the relative speed of A with respect to B in horizontal direction is given as

[tex]\frac{dx}{dt} = u - vcos\theta[/tex]

relative motion in y direction is given as

[tex]\frac{dy}{dt} = 0 - vsin\theta[/tex]

from first equation we can say

[tex]\int dx = \int u dt - \int vcos\theta dt[/tex]

[tex]0 = uT - v\int cos\theta dt[/tex]

[tex]\int cos\theta dt = \frac{uT}{v}[/tex]

now in the direction of approach of each other

[tex]\frac{dr}{dt} = ucos\theta - v[/tex]

[tex]\int dr = \int ucos\theta dt - \int vdt[/tex]

[tex]0 - d = u\int cos\theta dt - vT[/tex]

[tex]- d = u(\frac{uT}{v}) - vT[/tex]

[tex]T = \frac{vd}{v^2 - u^2}[/tex]

black white green and gold

Answer:   Q= Air resistance

Description:

The box release two forces acts on it, when it is falling from the building.

1. Its weight,  2. Air resistance

The answer is Air resistance

Because the primary waves travel before the secondary waves, and therefore arrive first.

Since the lamps are identical, the current divides equally through them... 0.6A through each lamp.

You don't have to worry about voltage drop or the value of the resistor to make that 9 volt drop to happen. The current is divided evenly by the two lamps. If the ammeter reads 1.2 amps before the current goes into the lamps then since this is a parallel circuit, the lamps will divide up the current evenly between them.

That's another way of saying each one will get 1.2 amps /2 = 0.6 amps.

Heat required to raise the temperature of water is given as

[tex]Q = ms\Delta T[/tex]

here we know that

[tex]m = mass = 200 mL = 0.200 kg[/tex]

initial temperature = 15 degree C

final temperature = 40 degree C

specific heat capacity = 4186 J/kg C

now by the above formula we will have

[tex]Q = 0.200 (4186) (40 - 15) = 20930 J[/tex]

Initially, the experiment has only potential energy (since total energy is the sum of kinetic and potential energy). And at the end, the experment has only kinetic energy.

To increase the speed of the go-cart, 250 J of work and energy must be done on it.

To find the work done on the go-cart, we can use the work-energy theorem. The work done is equal to the change in kinetic energy of the go-cart.

The initial kinetic energy of the go-cart is given by K_i = (1/2)mv^2, where m is the mass of the go-cart and v is its initial velocity. Plugging in the values, we have K_i = (1/2)(20 kg)(5 m/s)^2 = 250 J.

The final kinetic energy of the go-cart is given by K_f = (1/2)mv^2, where m is the mass of the go-cart and v is its final velocity. Plugging in the values, we have K_f = (1/2)(20 kg)(10 m/s)^2 = 500 J.

The change in kinetic energy is ΔK = K_f - K_i = 500 J - 250 J = 250 J.

Therefore, 250 J of work must be done on the go-cart to increase its speed from 5 m/s to 10 m/s.

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Given data

mass (m) = 13 kg

             F₁ = 13 × 9.8 = 127.4 N

air resistance (F₂ ) = 9 N, acts in opposite direction

            Net force is defined as sum of all forces

              Fnet = F₁ - F₂

                       = 127.4 - 9

                       = 118.4 N

Net force acting on the object is 118.4 N

The potential energy of a 1,300 kg car at the edge of a cliff 1,500 m high would be approximately 19,094,500 Joules or 19.1 MJ. This calculation utilizes the formula for potential energy, PE = m*g*h.

The calculation of Potential Energy is based on the formula PE = m*g*h. In this formula, 'm' represents the mass of the object, 'g' stands for the gravitational force (approximately 9.81 m/s² on Earth), and 'h' indicates the height above the ground. For a car with a mass of 1,300 kg at the edge of a cliff 1,500 m above the ground, the calculation would look like this.

PE = 1,300 kg * 9.81 m/s² * 1,500 m

This results in a potential energy of approximately 19,094,500 Joules, or 19.1 MJ. This amount of energy would be converted to kinetic energy if the car were to fall from the cliff, assuming no other energies are involved (like air resistance or friction).

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The potential energy of a 1,300 kg car at the edge of a cliff 1,500 m above the ground is approximately 19,108,500 Joules. The calculation uses the formula PE = mgh. Substituting the given values into the formula provides this result.

Potential energy due to gravity is given by the formula:

PE = mgh

where:

m = mass of the object (1,300 kg)

g = acceleration due to gravity (9.81 m/s²)

h = height above the ground (1,500 m)

Now, substituting these values into the formula:

PE = 1300 kg x 9.81 m/s² x 1500 m

PE ≈ 19,108,500 Joules

Hence, the potential energy of the car is approximately 19,108,500 Joules.

Weight is defined as attraction force of Earth on an object

It is given by formula

F = mg

when spring balance is used to measure the weight of an object then it means

[tex]F_s = F_g[/tex]

spring force is balanced by gravitational force

so the unit to measure this force is given by NEWTON(N)

so answer would be Newton(N)

Correct

Lithium fluoride is created due to the increased stability in the completion of fluorine's outer shell. By moving one electron from lithium, its outer shell is now full (with two). Additionally, by adding this electron to fluorine, it gains a full, stable octet.

The formation of lithium fluoride (seen here) is due to the increased stability in the completion of fluorine's outer shell, therefore the correct answer is option B.

The octet rule is the rule that explains that an atom should have filled with eight electrons in its valence shell for the most stable state.

For example, an Oxygen atom that has six electrons in the outermost shell needs two more electrons in its valence shell to form a stable atom.

In the formation of the lithium fluoride the lithium atom which has an extra electron in its outermost shell transfer it to the fluorine atom which has one less electron in its outermost shell so that it can compete with its octet.

The bond formed between the lithium and the fluorine atoms in the lithium fluoride is of an ionic nature where one electropositive and one electronegative atom are involved and the bond is formed by the transfer of the electron.

thus, The formation of lithium fluoride is because of the increased stability in the completion of fluorine's outer shell, therefore the correct answer is option B.

Learn more about the Octet rule from here

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If one neutron is added to a helium nucleus, the result is

Change of mass of nucleus. :D