Using the figure below A) What is the length of A'B'? B) Show your work/ explain how you got your answer. Question 10 options:

Answers

Answer 1
A
B
C
D
multiply them by 6 and add 3.5 to your answer and youll get the right one


Related Questions

A scientist now has exactly 4.365 liters of water in a container. There were 5 liters of water in the container, but some of the water evaporated.How much water evaporated from the container?

Answers

Finding the difference, subtract:

5 - 4.365
0.635 liters

Hope this helps!

Answer:

amount evaporated =  0.635 liters

Step-by-step explanation:

The scientist initially had 5 liters of water in a container . After evaporation took place he had only 4.365 liters of water remaining in the container.

The amount of water that evaporated can be computed when you remove the amount of water remaining after evaporation from the  initial amount before evaporation.

Mathematically,  

amount evaporated = initial amount before evaporation - amount remaining after evaporation

initial amount before evaporation = 5 liters

amount remaining after evaporation = 4.365 liters

amount evaporated =  5 - 4.365

amount evaporated =  0.635 liters

Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this case, approximately 1.25 billion years). suppose the minimum detectable amount is 0.1% and a dinosaur is dated with 40k to be 67 million years old. what is the maximum age of a fossil that we could date using 40k? (round your answer to one decimal place.)

Answers

The amount of substance left of a radioactive element of half life, [tex]t_{\frac{1}{2}}[/tex] after a time, t, is given by:

[tex]N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{ \frac{1}{2} }}[/tex]

Given that potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

[tex]0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\ \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\ \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\ \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\ \\ t=9.966(1.25)=12.5[/tex]

Therefore, the maximum age of a fossil that we could date using 40k is 12.5 billion years.
Final answer:

The maximum age of a fossil that could be dated using 40K is approximately 5.36 billion years.

Explanation:

Potassium-40 (40K) has a half-life of 1.25 billion years.

The minimum detectable amount for dating using 40K is 0.1%. If a dinosaur is dated using 40K to be 67 million years old, we can calculate the maximum age of a fossil that could be dated using 40K.

To find the maximum age, we can set up a proportion using the half-life of 40K:

(67 million years) / (1.25 billion years) = (x years) / (100%)

Solving for x, we get:

x = (67 million years) * (100%) / (1.25 billion years)

Calculating this, we find that the maximum age of a fossil that could be dated using 40K is approximately 5.36 billion years.

Solve for x. −2(x−3)−2x=18 Enter your answer in the box. x =

Answers

x=-3
−2(x−3)−2x=18(−2)(x)+(−2)(−3)+−2x=18(Distribute)−2x+6+−2x=18(−2x+−2x)+(6)=18(Combine Like Terms)−4x+6=18−4x+6=18Step 2: Subtract 6 from both sides.−4x+6−6=18−6−4x=12Step 3: Divide both sides by -4.−4x−4=12−4
-2(-×-3)-2x=18 the answer is...

x= -3

Write the equation of the line that passes through the points (1,4) and (5,8) in standard form.

Question 8 options:

x + 4y = 1


5x + 8y = 4


-2x + y = 5


-x + y = 3

Answers

D is your answer

plug in the x value and y value to the equation

when x = 1, and y = 4
-1 + 4 = 3

when x = 5, and y = 8
-5 + 8 = 3

hope this helps :D
Hi again Mr. Joseph!

Well, the correct answer is option D

-------------------------------------------------
We need to find the equation using two points.

But the trick is that you need to solve for y but not x
So let's solve for y
 - x + y = 3
Add x to both sides (Why? because we don't want x, so we need to get it out)
-x + y + x = 3 + x
y = x + 3
That's the correct equation.

They gave us (1,4)(5,8)
Use the slope formula and slope intercept form.
Do you know what the formula is?
Well, it looks like this
y = mx +b

So yeah, when we do all of that, we ended up having -x + y =3

Once again,
The correct answer is D

Best of luck with your studies!

Credit to my graphing calculator, here is how the points looks like on the graph


How many inches are there in 62 centimeters? there are 2.54 centimeters in 1 inch?

Answers

they're 157.5cm in 62 inches

M(3, 4) is the midpoint of mc010-1.jpg The coordinates of S are (4, 1). What are the coordinates of R?

Answers

midpoint formula : (x1 + x2) / 2, (y1 + y1) / 2
(4,1)....x1 = 4 and y1 = 1
(x,y)....x2 = x and y2 = y
sub
(4 + x) / 2 , (1 + y) / 2 = 3/4

(4 + x) / 2 = 3
4 + x = 3 * 2
4 + x = 6
x = 6 - 4
x = 2

(1 + y) / 2 = 4
1 + y = 4 * 2
1 + y = 8
y = 8 - 1
y = 7

ur other endpoint, R, is (2,7)

Answer:

its c

Step-by-step explanation:

What is the equation for the line of reflection that maps the trapezoid onto itself? x = 0 x = 3 y = 3 y = 0?

Answers

The correct answer is option 3. The equation for the line of reflection that maps the trapezoid onto itself is y = 3.

To determine the line of reflection for a trapezoid that maps onto itself, we need to identify the axis of symmetry.

We can analyze each one:

1. x = 0 represents a vertical line of reflection. If the trapezoid were reflected over this line, the left and right sides would be swapped. This would not map the trapezoid onto itself unless the trapezoid is symmetric about the y-axis, which is not specified.

2. x = 3 also represents a vertical line of reflection. This would reflect the trapezoid over a vertical line three units to the right of the y-axis. Again, this would not map the trapezoid onto itself unless the trapezoid is symmetric about the line x = 3, which is not specified.

3. y = 3 represents a horizontal line of reflection three units above the x-axis. If the trapezoid has its bases parallel to the x-axis and the midline of the trapezoid is at y = 3, then reflecting over this line would indeed map the trapezoid onto itself. This is because the top half of the trapezoid would be a mirror image of the bottom half across the line y = 3.

4. y = 0 represents a horizontal line of reflection along the x-axis. Reflecting the trapezoid over the x-axis would flip it upside down, which would not map the trapezoid onto itself unless the trapezoid is symmetric about the x-axis, which is not typical for a trapezoid.

The complete question is:

What is the equation for the line of reflection that maps the trapezoid onto itself?

1. x = 0

2. x = 3

3. y = 3

4. y = 0

A delivery truck travels 21 blocks north, 12 blocks east and 26 blocks south. what is its final displacement from the origin? assume the blocks are equal length.

Answers

The displacement is 13 blocks since its last position is 5 blocks south and separated 12 blocks east. We got 13 blocks by using triple phytagoras.
Final answer:

The truck's displacements in the North-South and East-West directions are calculated separately. The final displacement is 5 blocks South and 12 blocks East.

Explanation:

To solve this problem, we need to consider the truck's displacement in the North-South direction and the East-West direction separately.

 

Starting with the North-South direction, the truck moves 21 blocks North and then 26 blocks South. Thus, its total displacement in the North-South direction is 21 - 26 = -5 blocks. The negative sign indicates that the truck is 5 blocks South from its starting point.

 

Considering the East-West direction, the truck moves 12 blocks East. Therefore, its total displacement in the East-West direction is +12 blocks.

 

Overall, the displacement of the truck from the origin is 5 blocks South and 12 blocks East.

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Two students are to be selected at random from a class with 10 girls and 12 boys. what is the probability that both will be girls?

Answers

there is an 83% chance that it will be girls

The sum of twice a number and half the number is 10 ???

Answers

2x+x/2=10
4x/2+x/2=10
5x/2=10
5x=20
x=4

10+10/2 sum of 10+10 is 20 half is 10

What equation models the data in the table if d = number of days and c = cost?
Days Cost
2 44
3 66
5 110
6 132

c = 22d


d = 22c


c = d + 22


c = d + 22d

Answers

C = 22d is the correct answer because for every day the cost increases by 22 so two days mean the cost is equal to 22 (2)
Answer:

The equation that models the data in the table is:

                        [tex]c=22d[/tex]

Step-by-step explanation:

The table that represent the days and cost is given by:

       Days Cost

           2          44

           3          66

           5           110

           6          132

We see that the cost is a constant multiple of  the number of days.

i.e. the equation is given by:

             c=22d

i.e. the relationship is linear.

( Since, when d=2

we have: c=22×2=44

when d=3 we have:

c=22×3=66

and so on )

If f(x) = x2 + 7, what is the equation for f–1(x)?

Answers

Final answer:

To find the inverse of f(x) = x² + 7, replace f(x) with y and solve for x, resulting in the inverse function f–1(x) = √(x - 7), considering the domain x ≥ 7.

Explanation:

To find the inverse function of f(x) = x² + 7, we must first replace f(x) with y, giving us y = x² + 7. To find the inverse, we solve for x. We start by subtracting 7 from both sides to get y - 7 = x². Taking the square root of both sides, we get x = ±√(y - 7).

Since the square root has two values (positive and negative), we choose the one that matches the domain and range of the original function. If f(x) is defined for all nonnegative values of x, the inverse would be f–1(x) = √(x - 7). If f(x) includes negative values of x, then we would consider both, resulting in two different functions.

However, because we're dealing with f(x) that implies only one output for each input without restrictions, we consider the principal square root. Thus, the equation for the inverse function is f–1(x) = √(x - 7), considering the domain where x is greater than or equal to 7.

What are the steps for using a compass and straightedge to construct an equilateral triangle?

Drag the steps and drop them in order from start to finish.

Construct a point at one of the two intersection points of circle E and circle F and label this point G

.Construct ​ EG¯¯¯¯¯ ​ and ​ FG¯¯¯¯¯​ .

Construct ​ EF¯¯¯¯¯​

.Construct a circle with point E as the center and a circle with point F as the center with each circle having radius EF .

Answers

The steps for using a compass and straightedge to construct an equilateral triangle are as follows:

1. Construct a circle with point E as the center and a circle with point F as the center with each circle having radius EF

2. Construct line ​ EF

3. Construct a point at one of the two intersection points of circle E and circle F and label this point G

4. Construct line​ EG and line​ FG.

Jason drives 400 miles in 10 hours. Which unit of measure is most appropriate for speed?

Answers

40 MPH
 u just divide 400 by 10
the answer is 40 because 400÷10=40 miles and done

How many two-person conversations can occur at a party with 150 people?
  ---------------- conversations

Answers

Final answer:

There can be a total of 11,175 two-person conversations at the party.

Explanation:

In a party with 150 people, the number of two-person conversations that can occur can be calculated using the formula for combinations. Since each conversation involves two people, we need to choose 2 people from the total of 150. The formula for combinations is:

C(n, r) = n! / (r!(n-r)!)

Where n is the total number of people and r is the number of people we need to choose. Plugging in the values, we have:

C(150, 2) = 150! / (2!(150-2)!)

C(150, 2) = (150 ×149) / (2 ×1)

C(150, 2) = 11175

Therefore, there can be a total of 11,175 two-person conversations at the party.

Final answer:

At a party with 150 people, there can be 11175 unique two-person conversations, calculated using the combination formula 150C2.

Explanation:

The question is asking how many two-person conversations can occur at a party with 150 people. This is a classic combination problem where we need to calculate the number of unique pairs that can be made from 150 people. Since the order in which the pair is chosen does not matter, we use the combination formula nCr = n! / (r!(n-r)!), where 'n' is the total number of people and 'r' is the group size (in this case, 2 for a two-person conversation).

For 150 people, the calculation is:

150C2 = 150! / (2!(150-2)!) = 150! / (2! x 148!) = (150 x 149) / (2 x 1) = 11175.

Therefore, there can be 11175 unique two-person conversations at a party with 150 people.

Would you use SSS or SAS to prove the triangles​ congruent? If there is not enough information to prove the triangles by SSS or​ SAS, write​ "not enough​ information". Explain your answer

Answers

i would use the ssa becuause the sides of the triangles have two to three sides of length

A car travels 85 km from town a to town b, then 45 km from town b to town
c. the total trip took 1.5 h. what was the average speed of the car?

Answers

Final answer:

The average speed of the car is 86.67 km/h.

Explanation:

The average speed of a car can be calculated by dividing the total distance traveled by the total time taken. In this case, the car traveled 85 km from town A to town B and then 45 km from town B to town C, for a total distance of 85 km + 45 km = 130 km. The total trip took 1.5 hours. To find the average speed, divide the total distance by the total time: 130 km / 1.5 h = 86.67 km/h.

calculate the distance between the points A (-4,2) and B (15,6)

Answers

IN order to answer this you need to know the distance formula. The distance formula is: [tex]d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} [/tex] So now you need to plug in your variables. So it would look like this:[tex]d= \sqrt{(-4-15)^2+(2-6)^2} [/tex] Then solve for d. [tex]d= \sqrt{361+16} [/tex][tex]d= \sqrt{377} [/tex][tex]d=19.41[/tex] I hope this helps! 

Distance between the points A (-4, 2) and B (15, 6) is 19.41.

Here,

The points are A (-4, 2) and B (15, 6).

We have to find the distance between the points A (-4, 2) and B (15, 6).

What is Distance between two points?

Distance between two points A (x₁, y₁) and B (x₂, y₂) is given by:

[tex]D_{AB} = \sqrt{(x_{2}-x_{1} )^2+(y_{2} -y_{1} )^2}[/tex]

Now,

Distance between the points A (-4, 2) and B (15, 6) is;

[tex]D_{AB} = \sqrt{(15-(-4))^2+(6-2)^2}[/tex]

       [tex]= \sqrt{19^2+4^2}[/tex]

       [tex]= \sqrt{361+16}[/tex]

       [tex]= \sqrt{377}[/tex]

       [tex]= 19.41[/tex]

Hence, Distance between the points A (-4, 2) and B (15, 6) is 19.41.

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Find the Missing part of the unit rate: 40 students over 5 groups = ? Students over group

Answers

There will be 8 Students over each group
Final answer:

The missing part of the unit rate in the given situation is 8 students per group. This is obtained from dividing the total number of students (40) by the total number of groups (5).

Explanation:

To find the missing part of the unit rate, we'll need to divide the total number of students (40) by the total number of groups (5). This is because a unit rate describes how many units of the first type of quantity corresponds to one unit of the second type of quantity.

So in this case, the unit rate would be 40 ÷ 5 = 8. Therefore, the missing part of the unit rate is 8 students per group.

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Please help me , algebra math !!

Answers

check the picture below.

[tex]\bf A)\\\\ V(w)=(w+2)(w)\left( \cfrac{w+2}{4} \right)\implies V(w)=(w^2+2w)\left( \cfrac{w+2}{4} \right) \\\\\\ V(w)=\cfrac{w^3+2w^2+2w^2+4w}{4}\implies V(w)=\cfrac{w^3+4w^2+4w}{4} \\\\\\ B)\\\\ V(10)=\cfrac{(10)^3+4(10)^2+4(10)}{4}\implies V(10)=\cfrac{1000+400+40}{4} \\\\\\ V(10)=360[/tex]

what does it tell us?  hmmm when w = 10, h = 3 and l = 12, that just means is a short fat box like the one in the picture.

what is 2.31 divided by 3?

Answers

.77 is the answer. I hope this helps!
2.31 / 3, the answer is 0.77

If f(x)=3x^2-2x+4 and g(x)=5x^2+6x-8 find (f+g)(x)

Answers

(3x^2-2x+4)+(5x^2+6x-8) - Combine like terms
8x^2+4x-4
(f+g)(x)=8x^2+4x-4

The selling price, s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What is the formula solved for m?

Answers

s=c+mc
s-c=mc
(s-c)/c=m
m=(s-c)/c

Answer:

[tex]m=\frac{s-c}{c}[/tex]

Step-by-step explanation:

The given expression is

[tex]s=c+mc[/tex]

Now, to find the expression for [tex]m[/tex], we just have to isolate it. First, we have to move the term [tex]c[/tex] to the other side of the equation, and then to move the coefficient [tex]c[/tex], which is gonna pass to the other side dividing.

[tex]s=c+mc\\s-c=mc\\\frac{s-c}{c}=m\\m=\frac{s-c}{c}[/tex]

Therefore, the percent markup is defined as the difference between the selling price and cost, divided by that cost.

Suppose f is a linear function such that f(5) = 10 and f(9) = 3. find the equation for f.

Answers

f(x)=-1.75x+18.75
f(5)=-1.75*5+18.75=10
f(9)=-1.75*9+18.75=3

The equation for the function f would be; f(x) = -1.75x + 18.75.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Function is a type of relation, or rule, that maps one input to specific output.

Given that f is a linear function such that f(5) = 10 and f(9) = 3, then

Consider that the function of x would be;

f(x) = -1.75x + 18.75

Now plug x = 5 in the given function, if it satisfy the function

f(5) = -1.75(5) + 18.75

f (5) =10

Again plug x = 9 in the given function, if it satisfy the function

f(9) = -1.75(9) + 18.75

f(9) =3

Therefore, the equation for the function f would be; f(x) = -1.75x + 18.75.

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Find the polynomial equation of least degree with roots -1, 3, and (+/-)3i

Answers

The polynomial equation of least degree with the roots -1, 3, and (+/-)3i is x⁴ - 2x³ + 10x² + 2x - 27 = 0.

We have to find the polynomial equation of least degree with the given roots -1, 3, and (+/-)3i. As complex roots occur in conjugate pairs, if 3i is a root, then -3i must also be a root. Therefore, our polynomial will be of degree 4 since it has four roots in total.

The polynomial of least degree with roots x1, x2, x3, x4 can be expressed as:

(x - x1)(x - x2)(x - x3)(x - x4) = 0

Plugging in the roots given, we get:

(x + 1)(x - 3)(x - 3i)(x + 3i) = 0

To simplify this expression, let's first multiply the complex factors:

(x - 3i)(x + 3i) = x² - (3i)² = x² + 9

Now, multiply the remaining real factors with the result we just got:

(x + 1)(x - 3)(x² + 9) = 0

Expanding this, we obtain the polynomial equation:

x⁴ - 2x³ + 10x² + 2x - 27 = 0

This is the simplified equation of the polynomial with roots -1, 3, and (+/-)3i.

Which property is used to simplify the following expression?

3(y-14)
A.
commutative property
B.
distributive property
C.
associative property
D.
inverse property

Answers

 the answer is B. distributive
b distributive property is the answer

Suppose you kick a football and its movement can be modeled by a parabola. after 1 second its height is 15 feet above ground, after 2 seconds its height is 14 feet above ground, and after 3 seconds its height is 9 feet above ground.
a.find the equation of the parabola that models this behavior. y = -2x2 + 5x +12
b.after how many seconds does the ball hit the ground? 4 seconds

Answers

Jjhjdjdjdjfjdkldldkdkdbfbfbdbdjxhyxkfy

The equation of the parabola that models the movement of the football is y = -2x² + 5x + 12. The time at which the ball hits the ground is x = 4 seconds.

What is a quadratic equation?

The quadratic equation is defined as a function containing the highest power of a variable is two.

a. We know that the general form of the quadratic equation is y = ax² + bx + c, where a, b, and c are constants.

We are given three points that the football passes through: (1, 15), (2, 14), and (3, 9).

We can substitute these points into the quadratic equation and solve for a, b, and c.

For the first point, we have: 15 = a(1)² + b(1) + c

For the second point, we have: 14 = a(2)² + b(2) + c

For the third point, we have: 9 = a(3)² + b(3) + c

Solving this system of equations using elimination gives us:

a = -2

b = 5

c = 12

Therefore, the equation of the parabola that models the movement of the football is y = -2x² + 5x + 12.

b. To find the time at which the ball hits the ground, we can set the value of y equal to 0 and solve for x.

y = -2x² + 5x + 12

0 = -2x² + 5x + 12

-12 = -2x² + 5x

-2x² + 5x - 12 = 0

We can use the quadratic formula to solve for x:

x = (-5 +/- √(5² - 4(-2)(-12)))/(2(-2))

x = (-5 +/- √(25 + 96))/(-4)

x = (-5 +/- √(121))/(-4)

x = (-5 +/- 11)/(-4)

Therefore, x = 4 or x = -3/2.

The time at which the ball hits the ground is x = 4 seconds.

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Evaluate: −9^4

A) −36

B) −6,561

C) 36

D) 6,561

Answers

it would be b)-6561 not the others

Enter the solution to the inequality in the box.



7−3(x+5)+8x≤17

Answers

x eqauls 5 i used photo math

Answer:

The solution to the given inequality is (-∞,5].

Step-by-step explanation:

An inequality is a relation which makes a non-equal comparison between two numbers.

Given : 7-3(x+5)+8x≤17

=7-3(x+5)+8x ≤ 17

= 7- 3x - 15 + 8x ≤ 17

= -8 + 5x ≤ 17

Adding 8 on both sides:

= -8 +8+ 5x ≤ 17+8

= 5x ≤ 25

x ≤ 5

The solution to the inequality : (-∞,5].

You buy 12 tickets and the total is $120. a student ticket is $9 and an adult ticket is $12. how many student tickets did you buy

Answers

4 adult tickets were sold and 8 student tickets were sold.
How did I get this? 

First, let's see what information is given:
12 tickets sold
(S)tudent ticket = $9
(A)dult ticket = $12
Total cost = $120

So, we know student tickets plus adult tickets total up to $12. We can create an equation out of this: S + A = 12

And we know $9S + $12A = $120 

The variables represent the amount of tickets sold, which is unknown. 
A = 12 - S , substitute this into the second equation.

9s + 12(12-s) = 120
Distribute the 12 into the parenthesis.

9s + 144 - 12s = 120
Combine like terms

-3s + 144 = 120
Subtract both sides by 144, left side cancels out.

-3s = -24
s = -24/-3
s = 8 

So, 8 student tickets were sold. Plug the value of s into our first equation.

A = 12 - 8 
A = 4 (adult tickets)



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