25
Step-by-step explanation:
25
Round 506.57915 to the nearest hundredth.
Answer:
506.58
Step-by-step explanation:
Your welcome ;w;
Use the given information to find the minimum sample size required to estimate an unknown population mean μ.
How many business students must be randomly selected to estimate the mean monthly earnings of business students at one college? We want 95% confidence that the sample mean is within $140 of the population mean, and the population standard deviation is known to be $569.
A minimum sample size of 64 business students must be randomly selected to estimate the mean monthly earnings with 95% confidence within $140 of the true population mean, given the population standard deviation of $569.
Explanation:To find the minimum sample size required to estimate an unknown population mean μ with a certain level of confidence, we can use the formula:
n = (Z*σ/E)^2
Where:
n is the sample sizeZ is the Z-score corresponding to the desired confidence levelσ (sigma) is the population standard deviationE is the margin of errorFor a 95% confidence level, the Z-score is approximately 1.96. The population standard deviation σ is given as $569. The margin of error E is $140.
Plugging these values into the formula, we get:
n = (1.96*569/140)^2
n = (1114.44/140)^2
n = (7.96)^2
n = 63.4
Since the sample size must be a whole number, we would round up to the next whole number which gives us a minimum sample size of 64 business students that must be randomly selected to estimate the mean monthly earnings of business students at one college with the desired precision and confidence level.
Final answer:
To estimate the population mean with a 95% confidence level and a margin of error of $140, we use the formula n = (Z*σ/E)^2 with σ = $569. Using the z-score for 95% confidence (1.96), the calculation yields 119.44, which we round up to 120 business students needed for the sample.
Explanation:
Calculating Minimum Sample Size for Estimating a Population Mean
To determine the minimum sample size needed to estimate the mean monthly earnings of business students at one college with 95% confidence and a margin of error of $140, we use the formula for the sample size (n). The formula is derived from the properties of a normal distribution and the central limit theorem and is as follows:
n = (Z*σ/E)^2
where:
Z is the z-score corresponding to the desired confidence level (1.96 for 95% confidence),
σ (sigma) is the population standard deviation, and
E is the desired margin of error.
Plugging in the given values of σ = $569 and E = $140, we find:
n = (1.96 * 569 / 140)^2
n ≈ (10.924)^2
n ≈ 119.44
Since we cannot survey a fraction of a person, we round up to the nearest whole number. Therefore, 120 business students must be randomly selected to achieve the desired precision.
Kate has 48 softballs. She wants to divide them evenly among b softball bags. Which expression represents how many softballs she should put into each bag? a. 48/b, b. 48b, c. b/48, d. 48-b.
Answer:
A
Step-by-step explanation:
48 softballs
Divided among b bags
Divide 48 by b
48 ÷ b
Division expressions can also be written as fractions
Rewrite
48/b
The correct answer is A, 48/b
Hope this helps :)
Final answer:
Kate should use the expression 48/b to determine how many softballs go into each bag, which means dividing 48 softballs by the number of bags she has.
Explanation:
The expression that represents how many softballs Kate should put into each bag is 48/b. This expression shows that Kate will divide her total number of 48 softballs by the variable b, which represents the number of softball bags she has. The correct choice is therefore a. 48/b, which suggests that each bag will receive an equal share of the total softballs.
1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h
Answer:[tex](g,h)=(-2,2)[/tex]
Step-by-step explanation:
Given
Midpoint is [tex](-2,3)[/tex]
Endpoints are [tex]G(g,4)[/tex] and [tex]H(-2,h)[/tex]
Mid point of any two point is given by
[tex]x=\frac{x_1+x_2}{2}[/tex]
and [tex]y=\frac{y_1+y_2}{2}[/tex]
So,[tex]-2=\frac{g+(-2)}{2}[/tex]
[tex]-4=g-2[/tex]
[tex]g=-2[/tex]
Also
[tex]3=\frac{4+h}{2}[/tex]
[tex]6=4+h[/tex]
[tex]h=2[/tex]
Therefore [tex](g,h)=(-2,2)[/tex]
The magnitude, M, of an earthquake is defined to be M=log l/s, where l is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. Which equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake?
Answer:
M = Log (10S/S)
Step-by-step explanation:
We are told that the magnitude, M, of an earthquake is defined to be;
M = Log l/S
Where I is intensity and S is standard earthquake.
Now, we want to find the magnitude of an earthquake that is 10 times more intense than a standard earthquake
Since 10 times more intense than standard earthquake, it means that;
I = 10S
So plugging in 10S for I in the original equation for magnitude gives;
M = Log (10S/S)
Answer:It’s C on edge
Step-by-step explanation:
Peter measures the angles in a triangle.
He finds that the angles are 95°, 10° and 75º.
a)
Could he be correct?
b)
Explain your answer.
PLEASEEE HELPPP MEEE
solve for x
ANSWER CHOICES
a= -8
b= 2
c= 8
d= -6
Answer:
WHAT IS THE QUESTION WHAT IS X IN WHAT EQUATION!!!!!!!!
Step-by-step explanation:
Answer:
plzz i asked for brainliest on ur other question
Step-by-step explanation:
American adults are watching significantly less television than they did in previous decades. In 2016, Nielsen reported that American adults are watching an average of five hours and twenty minutes, or 320 minutes, of television per day. 1. Find the probability that an average American adult watches more than 300 minutes of television per day. Answer in three decimal places. 2. Find the probability that an average American adult watches more than 2,000 minutes of television per week. Answer in three decimal places.
Answer:
1. 0.869 = 86.9% probability that an average American adult watches more than 300 minutes of television per day.
2. 100% probability that an average American adult watches more than 2,000 minutes of television per week.
Step-by-step explanation:
To solve this question, we need to understand the poisson distribution and the normal distribution.
Poisson distribution:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\lambda[/tex] is the mean in the given interval, which is the same as the variance.
Normal distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
To approximate the Poisson to the normal, we use [tex]\mu = \lambda, \sigma = \sqrt{\lambda}[/tex]
1. Find the probability that an average American adult watches more than 300 minutes of television per day.
The mean is 320 minutes per day, so [tex]\lambda = 320, \mu = 320, \sigma = \sqrt{320} = 17.89[/tex]
This probability is 1 subtracted by the pvalue of Z when X = 300. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{300 - 320}{17.89}[/tex]
[tex]Z = -1.12[/tex]
[tex]Z = -1.12[/tex] has a pvalue of 0.131.
1 - 0.131 = 0.869
0.869 = 86.9% probability that an average American adult watches more than 300 minutes of television per day.
2. Find the probability that an average American adult watches more than 2,000 minutes of television per week.
A week has 7 days, so [tex]\lamda = 7*320 = 2240, \mu = 2240, \sigma = \sqrt{2240} = 47.33[/tex]
This probability is 1 subtracted by the pvalue of Z when X = 2000. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{2000 - 2240}{47.33}[/tex]
[tex]Z = -5.07[/tex]
[tex]Z = -5.07[/tex] has a pvalue of 0
1 - 0 = 1
100% probability that an average American adult watches more than 2,000 minutes of television per week.
The score distribution shown in the table is for all students who took a yearly AP statistics exam. An AP statistics teacher had 6565 students preparing to take the AP exam. Though they were obviously not a random sample, he considered his students to be "typical" of all the national students. What's the probability that his students will achieve an average score of at least 3?
Answer:
Step-by-step explanation:
The question is incomplete because the data is missing, i.e. the probability that you will score 5, 4, 3, 2, 1.
But it is resolved as follows:
[tex]P(x\geq 3) = P(\frac{x - m}{\frac{sd}{\sqrt{n} } } \geq \frac{3 - m}{\frac{sd}{\sqrt{n} }})\\\\[/tex]
where m is the mean and sd is the standard deviation.
the m is calculated by the sum of the multiplication of the score by the probability of this
that is to say,
score probability
5 0.2
4 0.3
3 0.1
2 0.3
1 0.1
m = 5*0.2 + 4*0.3 + 3*0.1 + 2*0.3 + 1*0.1
m = 3.2
However, the standard deviation will be calculated by
sd = [tex]\sqrt{\\}[/tex]∑[tex](x - m)^{2}*p[/tex]
that is, knowing the mean already, we can calculate the standard deviation, following the example:
sd =[tex]\sqrt{[(5-3.2)^2] *0.2 + [(4-3.2)^2] *0.3 + [(3-3.2)^2] *0.1 + [(2-3.2)^2] *0.3 + [(1-3.2)^2] *0.1 }[/tex]
sd = [tex]\sqrt{1.76}[/tex]
sd = 1.327
And also n = 5, because it's 5 scores. We replace in the initial equation:
[tex]P(x\geq 3) = P(Z \geq \frac{3 - 3.2}{\frac{1.327}{\sqrt{5} }})\\\\[/tex]
[tex]P(x\geq 3) = P(Z \geq -0.337)\\\\\\[/tex]
Therefore for the example the number z is -0.337, which if in the normal distribution table corresponds to 0.3520, that is the probability that the average is at least 3, for the example is 35.20 %.
Jimmy has 14 apples and 6 bananas. If he gives half of his fruit to Lisa, how many bananas did he give away? Please help
Answer:
3
Step-by-step explanation:
14/2=7 6/2=3 7+3=10 which is also half of 20 (20 is how many fruits he has) He gave away 3 bananas
Greta has watched 30 minutes of a movie. This is 20%
of the entire movie. How long is the movie?
Gary earned an average score of 77 on his first five quizzes. What score will he need on his next quiz to have an overall average of 79
Answer:
The next score he needs to have an overall average of 79 is 89.
Step-by-step explanation:
Gary earned an average score of 77 on his 5 quizzes . The number of score he needs to have an average of 79 can be calculated below.
average score = 77
number of quizzes = 5
sum of Garry score = a
a/5 = 77
cross multiply
a = 77 × 5
a = 385
let
the next score he needs be b to score an average of 79
average = 79
number of quizzes = 6
385 + b/6 = 79
cross multiply
385 + b = 474
b = 474 - 385
b = 89
The next score he needs to have an overall average of 79 is 89.
If p=2(a+b), then b=
Solving the equation p = 2(a + b) for b involves two steps: first dividing each side by 2, then subtracting 'a' from each side. This results in the final equation 'b = (p/2) - a'.
Explanation:To solve the equation p = 2(a + b) for b, you would first divide each side by 2 to isolate 'a + b'.
This gives you p/2 = a + b. Next, to isolate 'b', you would subtract 'a' from each side of the equation.
This gives you b = (p/2) - a, which is your final, simplified expression for 'b' in terms of 'p' and 'a'.
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A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers" children on the verge of reading. There are 19 children in Mr. Grimace's kindergarten class. Of these, 13 are pre-readers. Using the plus four confidence interval method, a 90% confidence interval for the difference in proportions of children in these classes that are pre-readers is -0.104 to 0.336.
1. Which of the following statements is correct?
a. This confidence interval is not reliable because the samples are so small.
b. This confidence interval is of no use because it contains 0, the value of no difference between classes.
c. This confidence interal is reasonable because the sample sizes are both at least 5.
d. This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population
Answer:
The correct answer is option (d).
Step-by-step explanation:
From the given example, the statement that is correct is, this confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.
This is because, In this scenario or setup, all the students are already part of the data. This is not a sample from a l population that is larger, but probably, the population itself.
6 friends share 3 apples. How much each friend receive?
Answer:
Each friend would receive Half (1/2) of an apple.
Each friend receives 1/2 apple.
What is the unitary method?The unitary method is a process by which we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.
Total number of friends = 6
Total number of apples = 3
The apple gets each friend is determined in the following steps given below.
[tex]\rm Each \ friend =\dfrac{Total \ Apple}{Total \ frineds}\\\\Each \ friend = \dfrac{3}{6}\\\\Each \ friend =\dfrac{1}{2}[/tex]
Hence, each friend receives 1/2 apple.
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A hyperbola centered at the origin has vertices at (0,±\sqrt(54) and foci at (0,±\sqrt(89)
Write the equation of this hyperbola
The equation of the hyperbola with vertices at[tex](0,±\sqrt{54}) and foci at (0,±\sqrt{89}) is \(\frac{y^2}{54} - \frac{x^2}{35} = 1\).[/tex]
To write the equation of a hyperbola, you need to know the values of a (which determines the distance from the center to the vertices) and c (which determines the distance from the center to the foci). The general equation for a hyperbola centered at the origin (h, k) with a vertical transverse axis is:
[tex]\(\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1\)[/tex]
Since the hyperbola is centered at the origin (0,0), this simplifies the equation:
[tex]\(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\)[/tex]
For this hyperbola, the vertices are at [tex](0,\(\pm\sqrt{54}\)), so a is \(\sqrt{54}\)[/tex]. The foci are at [tex](0,\(\pm\sqrt{89}\))[/tex], so c is [tex]\(\sqrt{89}\)[/tex]. To find b, we use the relationship [tex]c^2 = a^2 + b^2 (since e > 1)[/tex].
Calculating b, we have:
[tex]\(c^2 = a^2 + b^2\)[/tex]
[tex]\(89 = 54 + b^2\)[/tex]
[tex]\(b^2 = 35\)[/tex]
Thus, the equation of the hyperbola is:
[tex]\(\frac{y^2}{54} - \frac{x^2}{35} = 1\)[/tex]
The equation of the hyperbola is : [tex]\[ \frac{y^2}{54} - \frac{x^2}{35} = 1 \][/tex]
To write the equation of the hyperbola given its vertices and foci, we need to determine the major axis, minor axis, and eccentricity.
The vertices of the hyperbola are at [tex]\( (0, \pm \sqrt{54}) \)[/tex] and the foci are at [tex]\( (0, \pm \sqrt{89}) \).[/tex]
The distance from the center to a vertex is [tex]\( \sqrt{54} \)[/tex], which is the length of the semi-major axis, [tex]\( a \)[/tex]. The distance from the center to a focus is [tex]\( \sqrt{89} \),[/tex] which is the length of [tex]\( c \)[/tex], the distance from the center to a focus.
The relationship between [tex]\( a \), \( b \)[/tex] (the length of the semi-minor axis), and [tex]\( c \)[/tex] for a hyperbola is given by the equation [tex]\( c^2 = a^2 + b^2 \).[/tex]
Substituting the given values, we get:
[tex]\[ 89 = 54 + b^2 \][/tex]
[tex]\[ b^2 = 89 - 54 \][/tex]
[tex]\[ b^2 = 35 \][/tex]
So, [tex]\( b = \sqrt{35} \)[/tex].
The standard form equation of a hyperbola centered at the origin with vertices on the y-axis is:
[tex]\[ \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \][/tex]
Substituting [tex]\( a = \sqrt{54} \) and \( b = \sqrt{35} \),[/tex] we get:
[tex]\[ \frac{y^2}{54} - \frac{x^2}{35} = 1 \][/tex]
Therefore, the equation of the hyperbola is:
[tex]\[ \frac{y^2}{54} - \frac{x^2}{35} = 1 \][/tex]
This equation represents a hyperbola centered at the origin with vertices at [tex]\( (0, \pm \sqrt{54}) \) and foci at \( (0, \pm \sqrt{89}) \).[/tex]
An office supply company manufactures paper clips, and even tolerates a small proportion of those paper clips being ‘defective’ (or incorrectly shaped and/or twisted) in its outgoing product. (The company reasons that paper clips are so cheap, users will simply discard the occasional defective paper clip they might find in a box.) The average proportion of ‘defective’ paper clips is known to be 2% when the paper clip manufacturing process is ‘in control’. To monitor this issue, what should be the value of the upper control limit of a p-chart if the company plans to include 25 paper clips in each of its samples and use z-value of 3.0 to construct the chart? g
Answer:
0.104 (10.4%)
Step-by-step explanation:
[tex]UCL = \bar{p}+z(\sigma)[/tex]
[tex]\sigma = p(1-)) Vn = 1.02(1-202)) 5[/tex] = 0.028
[tex]\thereforeUCL = .02+(3x0.028)[/tex] = 0.104
[tex]\thereforeUCL[/tex]= 10.4%
One rectangular solid with a square base has twice the height of another rectangular solid with a square base with the same side length which statements about the two rectangular solids are true is it the bases are congruent the solids are similar and the ratio of the volume volumes of the first solid solid is eight One the volume of the first solid is twice as much is the volume of the second solid and if the dimensions of the second solid RX by X by H the first
Answer: A, D, E
Step-by-step explanation
What is the mean 9, 8, 12, 6, 10
Answer:
Mean = sum of elements/number of elements = (9 + 8 + 12 + 6 + 10)/5 = 9
Hope this helps!
:)
Answer:
9
Step-by-step explanation:
The mean is also called the average
Add up all the number
(9+8+ 12+ 6+ 10)
45
Then divide by the number of numbers
45/5 = 9
Leon started to try to transform the expressions 6g + (g + 2) + 3 to determine if it is equivalent to the expression 6 + 7g. His work is shown below. 6g + (g + 2) + 3 (6g + g) + 2 + 3 associative property 7g + 2 + 3 combine like variable terms Are the expressions 6g + (g + 2) + 3 and 6 + 7g equivalent?
Answer:
No
Step-by-step explanation:
I got it right on Instruction
Answer:
its No trust me
Step-by-step explanation:
A newspaper reported the results of a poll concerning topics that teenagers most want to discuss with their parents. In the the poll 37% of teenagers said they would like to talk with their parents about school. These and other percentages were based on a national sampling of 536 teenagers. Estimate the proportion of all teenagers that want more discussions with their parents about school. Use a 99% confidence level. Right-click this Excel file to open a worksheet template.
Answer:
Step-by-step explanation:
Confidence interval is written as
Sample proportion ± margin of error
Margin of error = z × √pq/n
Where
z represents the z score corresponding to the confidence level
p = sample proportion. It also means probability of success
q = probability of failure
q = 1 - p
p = x/n
Where
n represents the number of samples
x represents the number of success
From the information given,
n = 536
p = 37/100 = 0.37
q = 1 - 0.37 = 0.63
To determine the z score, we subtract the confidence level from 100% to get α
α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005
This is the area in each tail. Since we want the area in the middle, it becomes
1 - 0.005 = 0.995
The z score corresponding to the area on the z table is 2.53. Thus, confidence level of 99% is 2.58
Therefore, the 99% confidence interval is
0.37 ± 2.58 × √(0.37)(0.63)/536
= 0.37 ± 0.054
The lower limit of the confidence interval is
0.37 - 0.054 = 0.316
The upper limit of the confidence interval is
0.37 + 0.054 = 0.424
Therefore, with 99% confidence interval, the proportion of all teenagers that want more discussions with their parents about school is between 0.316 and 0.424
Use the Ratio Test to determine whether the series is convergent or divergent.
Σ[infinity] n = 1 (-1)^n - 1 3^n/2^nn^3
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
An aquarium at a pet store contains six fish; three yellow goldfish and three black goldfish. On Sunday, a customer came to the store and randomly selected three fish to purchase. Suppose you know the customer purchased a black goldfish. What is the probability that two yellow goldfish and a black goldfish remain in the tank after the customer has left? Please simplify your answer to a decimal value and circle your answer. Ensure you show your work.
Answer:
[tex]P=0.4737[/tex]
Step-by-step explanation:
First, we need to know that nCx give as the number of ways in which we can select x elements from a group of n. It is calculated as:
[tex]nCx=\frac{n!}{x!(n-x)!}[/tex]
Then, to select 3 fish in which at least one a them is a black goldfish we can:
1. Select one black goldfish and 2 yellow goldfish: There are 9 different ways to do this. it is calculated as:
[tex]3C1*3C2 =\frac{3!}{1!(3-1)!}* \frac{3!}{2!(3-2)!}=9[/tex]
Because we select 1 black goldfish from the 3 in aquarium and select 2 yellow goldfish from the 3 in the aquarium.
2. Select 2 black goldfish and 1 yellow goldfish: There are 9 different ways. it is calculated as:
[tex]3C2*3C1 =\frac{3!}{2!(3-2)!}* \frac{3!}{1!(3-1)!}=9[/tex]
3. Select 3 black goldfish and 0 yellow goldfish: There is 1 way. it is calculated as:
[tex]3C3*3C0 =\frac{3!}{3!(3-3)!}* \frac{3!}{0!(3-0)!}=1[/tex]
Now, we identify that just in part 2 (Select 2 black goldfish and 1 yellow goldfish), two yellow goldfish and a black goldfish remain in the tank after the customer has left.
So, the probability that two yellow goldfish and a black goldfish remain in the tank after the customer has left given that the customer purchased a black goldfish is equal to:
[tex]P=\frac{9}{9+9+1} =0.4737[/tex]
Because there are 19 ways in which the customer can select a black fish and from that 19 ways, there are 9 ways in which two yellow goldfish and a black goldfish remain in the tank.
) You want to rent an unfurnished one-bedroom apartment after you graduate from high school. The mean monthly rent for a random sample of 10 apartments advertised in the local newspaper is $940. The margin of error for a 95% confidence interval is $160. Find the 95% confidence interval for the mean monthly rent for unfurnished one-bedroom apartments available for rent in this community. Write your answer in this format: x to y
Answer:
$780 to $1100
Step-by-step explanation:
A confidence interval has two bounds. A lower bound and an upper bound. They are dependent of the sample mean and of the margin of error M.
In this problem:
Sample mean: $940
Margin of error: $160
The lower end of the interval is the sample mean subtracted by M. So it is 940 - 160 = $780
The upper end of the interval is the sample mean added to M. So it is 940 + 160 = $1100
So the answer is
$780 to $1100
Answer:
[tex]940-160=780[/tex]
[tex]940+160=1100[/tex]
So then we are 95% confident that the true mean for the monthly rent is between 780 and 1100
Step-by-step explanation:
For this case we can define the following random variable X as the monthly rent and we know the following properties given:
[tex]\bar X= 940 [/tex] represent the sample mean
[tex] ME = 160[/tex] represent the margin of error
n = 10 represent the sample size
The confidence interval for the true mean is given by:
[tex] \bar X \pm z_{\alpha/2} \sqrt{\frac{\sigma}{\sqrt{n}}}[/tex]
And is equivalent to:
[tex]\bar X \pm ME[/tex]
And for this case if we replace the info given we got:
[tex]940-160=780[/tex]
[tex]940+160=1100[/tex]
So then we are 95% confident that the true mean for the monthly rent is between 780 and 1100
which of the following is the inverse of f(x)=3-14x
Answer:
f(x)=-3+14x
Step-by-step explanation:
its the opposite
The inverse of the following function f(x)=3-14x will be [tex]f^-(x)[/tex] = [3 -f(x)]/14.
What is a function?A certain kind of relationship called a function binds inputs to essentially one output.
A function can be regarded as a computer, which is helpful.
A function is basically a relationship between which one variable will be dependent and another will be independent.
For example, let's say y = sinx then here x will be independent but y will be dependent.
In other words, the function is a relationship between variables, and the nature of the relationship defines the function for example y = sinx and y = x +9 like that.
Given that the function
f(x)=3-14x
⇒ f(x) + 14x =3
⇒ 14x = 3 -f(x)
⇒ x = [3 -f(x)]/14 hence, it will be the correct answer.
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A computer company shipped two new computers to a customer. These two computers were randomly selected from the 15 computers in stock. Unfortunately, the inventory clerk by mistake mixed up new computers with refurbished computers. As a result, the 15 computers in stock consisted of 11 new computers and 4 refurbished computers. If the customer received one refurbished computer, the company will incur a shipping and handling expense of $100 to replace that computer with a new computer. However, if both computers were refurbished, the customer would cancel the order and the company will incur a total loss of $1,000. If the customer received both computers as new, then there is no extra cost involved (i.e., zero loss). Find the expected value and standard deviation of the computer company's loss.
Answer:
Expected value of company loss = $99.01
Standard deviation = $226.91
Step-by-step explanation:
We first obtain the probability mass function of the company's losses based on the chances of the possible various number of refurbished computers in the customers order.
There are 15 total computers in stock.
There are 4 refurbished computers in stock.
There are 11 new computers in stock
The customer orders 2 computers. If there are no refurbished computers in the order, there are no losses on the company's part.
Probability of no refurbished computers in the order = (11/15) × (10/14) = 0.5238
The customer orders 2 computers. If there is only 1 refurbished computer in the order, there is a loss of $100 on the company's part.
Probability of 1 refurbished computers in the order = [(11/15) × (4/14)] + [(4/15) × (11/14)]
= 0.4191
The customer orders 2 computers. If there are 2 refurbished computer in the order, there is a loss of $1000 on the company's part.
Probability of 2 refurbished computers in the order = [(4/15) × (3/14)] = 0.0571
So, the Probabilty function of random variable X which represents the possible losses that the company can take on is given as
X | P(X)
0 | 0.5238
100 | 0.4191
1000 | 0.0571
Expected value of company loss is given as
E(X) = Σ xᵢpᵢ
xᵢ = each variable or sample space
pᵢ = probability of each variable
E(X) = (0 × 0.5238) + (100 × 0.4191) + (1000 × 0.0571) = $99.01
Standard deviation is obtained as the square root of variance.
Variance = Var(X) = Σx²p − μ²
where μ = E(X) = 99.01
Σx²p = (0² × 0.5238) + (100² × 0.4191) + (1000² × 0.0571) = 0 + 4191 + 57,100 = 61,291
Var(X) = Σx²p − μ²
Var(X) = 61291 − 99.01² = 51,488.0199
Standard deviation = √(51,488.0199) = $226.91
Hope this Helps!!!
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 49.0 and 54.0 minutes. Find the probability that a given class period runs between 50.75 and 51.25 minutes. Find the probability of selecting a class that runs between 50.75 and 51.25 minutes.
Answer:
The probability that a given class period runs between 50.75 and 51.25 minutes is 0.10.
Step-by-step explanation:
Let the random variable X represent the lengths of the classes.
The random variable X is uniformly distributed within the interval 49.0 and 54.0 minutes.
The probability density function of X is:
[tex]f_{X}(x)=\frac{1}{b-a};\ a<X<b,\ a<b[/tex]
Compute the probability that a given class period runs between 50.75 and 51.25 minutes as follows:
[tex]P(50.75<X<51.25)=\int\limits^{51.25}_{50.75}{\frac{1}{54-49}}\, dx\\\\=\frac{1}{5}\times [x]^{51.25}_{50.75}\\\\=\frac{51.25-50.75}{5}\\\\=0.10[/tex]
Thus, the probability that a given class period runs between 50.75 and 51.25 minutes is 0.10.
Answer: 0.050
I just did it and i got it right.
Researchers collected two different samples, X and Y, of temperatures, in degrees Celsius, of the habitat for Florida scrub lizards. The confidence interval 36±1.66 was constructed from sample X, and the confidence interval 36±1.08 was constructed from sample Y. Assume both samples had the same standard deviation.
Which of the following statements could explain why the width of the confidence interval constructed from X is greater than the width of the confidence interval constructed from Y?
A. The sample size of X is greater than the sample size of Y, and the confidence level is the same for both intervals.
B. The sample size of X is greater than the sample size of Y, and the confidence level used for the interval constructed from X is less than the confidence level used for the interval constructed from Y.
C. The sample size is the same for X and Y, and the confidence level used for the interval constructed from X is less than the confidence level used for the interval constructed from Y.
D. The sample size is the same for X and Y, and the confidence level is the same for both intervals.
E. The sample size is the same for X and Y, and the confidence level used for the interval constructed from X is greater than the confidence level used for the interval constructed from Y
Answer:
E. The sample size is the same for X and Y, and the confidence level used for the interval constructed from X is greater than the confidence level used for the interval constructed from Y
Step-by-step explanation:
Confidence interval formula is given as
CI = \bar{x} \pm z*(\sigma/\sqrt{n})
Here, we can see that the width of confidence interval is z*(\sigma/\sqrt{n}) , which is dependent only on z critical value, standard deviation (sigma) and sample size (n)
This simply entails that either z or n or both are greater for x as compared to y.
Option E is correct answer because x and y can have sample sizes, but if the z critical is greater for x, then the width will be larger.
The confidence interval tells about the probability where a value falls between a range. The interval constructed from X is greater than that of Y because the z value for X is greater than Y.
The confidence interval:[tex]CI = \bar{x} \pm z\times (\dfrac {\sigma}{\sqrt{n}})[/tex]
Where,
[tex]CI[/tex] = confidence interval
[tex]\bar{x}[/tex] = sample mean
[tex]z[/tex] = confidence level value
[tex]{s}[/tex] = sample standard deviation
[tex]{n}[/tex] = sample size
From the formula, confidence interval is the the directly proportional to the confidence level value, standard deviation, and population.
Since the standard deviation, and the population is constant,
Therefore, the interval constructed from X is greater than that of Y because the z value for X is greater than Y.
Learn more about The confidence interval:
https://brainly.com/question/2396419
In Bangladesh, approximately 50.6% of the population is male and 49.4% of the population is female. By the Law of Large Numbers, we can take this to mean that the probability that a randomly selected birth is that of a male child is 0.506 and the probability that a randomly selected birth is that of a female child is 0.494. In a randomly selected family with six children, what is the probability that at most 2 of the children are boys? What is the expected number of boys in a randomly selected family with six children?
Answer:
A) 0.015
B) 4 bous6
Step-by-step explanation:
That at most 2 of the selected children are male means that number of male must be less than or equal to 2
Pr (male) = 0.506
Pr (female) = 0.494
Pr (at most 2 males) = 0.506 x 0.506 x 0.494 x 0.494 x 0.494 x 0.494 = 0.015
Expected number of boys in a randomly selected number of 6 is
0.506 x 6 = 3.03
We round off to 4 boys
Can someone please help?
Answer:
x=±√7 -2
Step-by-step explanation: