Two wires are stretched between two fixed supports and have the same length. One wire A there is a second-harmonic standing wave whose frequency is 660 Hz. However, the same frequency of 660 Hz is the third harmonic on wire B. (a) Is the fundamental frequency of wire A greater than, less than, or equal to the fundamental frequency of wire B? Explain. (b) How is the fundamental frequency related to the length L of the wire and the speed v at which individual waves travel back and forth on the wire? (c) Do the individual waves travel on wire A with a greater, smaller, or the same speed as on wire B? Give your reasoning.

It would take about 3 days

Hope this helps have a good day....

It takes about 3 days or less than a week

(a) same direction as the electron's initial velocity

The direction of the acceleration is opposite to the direction of the velocity of the electron. This means that the electron is feeling a repulsive force, in a direction opposite to its initial velocity.

For a negative charge, we know that the electrostatic force and the electric field have opposite directions, because in the formula

[tex]F=qE[/tex]

q is negative. Therefore, the electric field must be in the same direction as the initial velocity of the electron.

(b) [tex]1.76\cdot 10^{-4}m[/tex]

When the electron comes to rest, all its initial kinetic energy has been converted into electric potential energy. So we can write

[tex]K = \Delta U[/tex]

[tex]\frac{1}{2}mv^2= qEd[/tex]

where

[tex]m=9.11\cdot 10^{-31} kg[/tex] is the electron mass

[tex]v=5.85\cdot 10^6 m/s[/tex] is the electron initial speed

[tex]q=1.6\cdot 10^{-19}C[/tex] is the magnitude of the electron charge

[tex]E=5.55\cdot 10^5 N/C[/tex] is the electric field

[tex]d[/tex] is the distance covered

Solving the equation for d, we find

[tex]d=\frac{mv^2}{2qE}=\frac{(9.11\cdot 10^{-31} kg)(5.85\cdot 10^6 m/s)^2}{2(1.6\cdot 10^{-19}C)(5.55\cdot 10^5 N/C)}=1.76\cdot 10^{-4}m[/tex]

which corresponds to 0.17 mm.

(c) [tex]6\cdot 10^{-11} s[/tex]

First of all, we need to find the electrostatic force acting on the electron:

[tex]F=qE=(-1.6\cdot 10^{-16}C)(5.55\cdot 10^5 N/C)=-8.88\cdot 10^{-14} N[/tex]

Now we can find the acceleration of the electron:

[tex]a=\frac{F}{m}=\frac{-8.88\cdot 10^{14} N}{9.11\cdot 10^{-31} kg}=-9.75\cdot 10^{16} m/s^2[/tex]

(the acceleration is negative because it is opposite to the electron's direction of motion)

And now we can find the time taken for the electron to stop to a velocity of v=0 starting from [tex]u=5.85\cdot 10^6 m/s[/tex]:

[tex]a=\frac{v-u}{t}\\t=\frac{v-u}{a}=\frac{0-(5.85\cdot 10^6 m/s)}{-9.75\cdot 10^{16} m/s^2}=6\cdot 10^{-11} s[/tex]

(d)  [tex]5.85\cdot 10^6 m/s[/tex]

When it returns to the starting point, all the electric potential energy gained by the electron through the distance d will be re-converted back into kinetic energy. If there is no loss of energy, therefore, this means that the electron will have the same kinetic energy it had at the beginning of the motion: therefore, its speed will be equal to its initial speed, [tex]5.85\cdot 10^6 m/s[/tex].

In this case the wavelength would be 3.14 m.

The wavelength of the wave formed by guitar string is 1.8 m.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

One wavelength is 2/3 of the length of the string. The wavelength related to the length of string by

λ = 2/3 L

A nylon guitar string vibrates in a standing wave pattern. Harmonics only occur in 1/2 wavelength increments, so the third harmonic would be 3/2 wavelengths on the2.7 m string.

Substitute the value, we get

λ = 2/3  x 2.7

λ = 1.8 m

Thus, wavelength of the wave formed by guitar string is 1.8 m.

Learn more about wavelength.

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Answer:

A half-life is the time required for one half of the nuclei in a radio- active isotope to decay.

Explanation:

A radio-active isotope is an isotope which undergoes radioactive decay.

Radioactive decay is a spontaneous process in which the nucleus of an atom changes its state (turning into a different nucleus, or de-exciting), emitting radiation, which can be of three different types: alpha, beta or gamma.

The half-life of a radio-active isotope is the time required for half of the nuclei of the initial sample to decay.

The law of radio-active decay can be expressed as follows:

[tex]N(t) = N_0 (\frac{1}{2})^{t/t_{1/2}}[/tex]

where

N(t) is the number of undecayed nuclei left at time t

N0 is the initial number of nuclei

t is the time

[tex]t_{1/2}[/tex] is the half-life

We see that when [tex]t=t_{1/2}[/tex] (that means, when 1 half-life has passed), the number of undecayed nuclei left is

[tex]N(t) = N_0 (\frac{1}{2})^{t_{1/2}/t_{1/2}}=N_0 (\frac{1}{2})^1=\frac{N_0}{2}[/tex]

So, half of the initial nuclei.

Based on the very tip of the arrow the best answer would be; 3.3cm

But i could very well be wrong and it may be 3.35, but i would say 3.3 if it just wants to the nearest 10th

Answer:

The significant figures is 3.3 cm.

Explanation:

Significant :

Significant figures of a number are numbers that have significance to contribute to its resolution of measurements.

Centimeter is unit of length.

According to figure,

The significant figures is

[tex]l = 3.3\ cm[/tex]

Hence, The significant figures is 3.3 cm.

D A heat engine that uses heat to do work

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

[tex]\eta = \frac{W}{Q_{in}}[/tex]

where

W is the useful work done by the engine

[tex]Q_{in}[/tex] is the heat in input to the machine

In this problem, we have:

[tex]Q_{in}=600 kJ[/tex] is the heat absorbed

[tex]W=600 kJ-175 kJ=425 kJ[/tex] is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

[tex]\eta = \frac{425 kJ}{600 kJ}=0.71 = 71\%[/tex]

(a) [tex]737^{\circ}C[/tex]

The efficiency of an engine can also be rewritten as

[tex]\eta = 1-\frac{T_C}{T_H}[/tex]

where

[tex]T_C[/tex] is the absolute temperature of the cold sink

[tex]T_H[/tex] is the temperature of the source

In this problem, the temperature of the sink is

[tex]T_C = 20^{\circ}C + 273=293 K[/tex]

So we can re-arrange the equation to find the temperature of the source:

[tex]T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C[/tex]

Final answer:

To address the question, the source temperature is derived using the Carnot efficiency equation, revealing it must be higher than 20°C for the engine to operate. The thermal efficiency is calculated to be 70.83%, representing the work done versus heat absorbed ratio.

Explanation:

A Carnot heat engine's efficiency and the temperatures of its heat reservoirs are interconnected through the principles of thermodynamics. Given that a Carnot heat engine receives 600 kJ of heat from a source and rejects 175 kJ to a sink at 20°C, we can determine both the temperature of the source and the engine's thermal efficiency.

Calculation of the Source Temperature

To find the source temperature, we use the Carnot efficiency formula: Efficiency = 1 - (QC/QH), where QC is the heat rejected to the cold sink, and QH is the heat received from the hot source. First, we calculate the engine's efficiency: Efficiency = 1 - (175kJ/600kJ) = 0.7083.

Because the Carnot efficiency is also given by Efficiency = 1 - (TC/TH), where TC = 293K (equivalent to 20°C), we can rearrange for TH: TH = TC / (1 - Efficiency). After substituting the known values, we find the temperature of the source to be higher than the sink, as expected.

Thermal Efficiency of the Heat Engine

The thermal efficiency of the Carnot engine is calculated to be 70.83%, which means that 70.83% of the heat input from the source is converted to work, while the remainder is rejected to the sink.

Answer:

[tex]4.9\cdot 10^{-6}[/tex]

Explanation:

The Coulomb force on the bee is:

[tex]F_E=qE[/tex]

where

[tex]q=40 pC=40\cdot 10^{-12} C[/tex] is the charge of the bee

[tex]E=120 N/C[/tex] is the magnitude of the electric field

Substituting into the formula,

[tex]F_E=(40\cdot 10^{-12} C)(120 N/C)=4.8\cdot 10^{-9} N[/tex]

The gravitational force on the bee is

[tex]F_G = mg[/tex]

where

[tex]m=0.10 g=1\cdot 10^{-4}kg[/tex] is the bee's mass

[tex]g=9.8 m/s^2[/tex] is the gravitational acceleration

Substituting into the formula,

[tex]F_G = mg=(1\cdot 10^{-4}kg)(9.8 m/s^2)=9.8\cdot 10^{-4} N[/tex]

So, the ratio between the two forces is

[tex]\frac{F_E}{F_G}=\frac{4.8\cdot 10^{-9} N}{9.8\cdot 10^{-4} N}=4.9\cdot 10^{-6}[/tex]

Answer:

The have equal momentum

Explanation:

The change in momentum of each cart is equal to the impulse given to the cart:

[tex]\Delta v = I = F \Delta t[/tex]

where

F is the average force exerted on the cart

[tex]\Delta t[/tex] is the contact time

In this case, the force F applied to both carts is the same, and the contact time is the same for both carts (1 s). Therefore, the change in momentum of the two carts is the same.

However, both carts at the beginning have a momentum of zero (because they start from rest): this means that their final momentum will be equal, since they gain the same amount of momentum [tex]\Delta p[/tex].

Due to the relationship in the momentum equation, (p = mv) and equal forces applied on the two carts, both the plastic and the lead cart will have equal momentum irrespective of their mass differences.

The momentum of the plastic cart and the lead cart will be equal. This is because momentum is the product of mass and velocity (p = mv). As equal forces are applied for the same duration, according to Newton's second law of motion, the acceleration a = F/m is equal for both carts. As the smaller plastic cart has less mass, it will have a greater velocity, while the larger lead cart, having more mass, will have a lesser velocity. However, because of the relationship in the momentum equation (p = mv), these different velocities will effectively cancel out the mass differences, resulting in equal momentum for the two carts.

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The Luminosity Decreases.

Answer:

Ampere (A)

Explanation:

The rate of electron flow in a circuit corresponds to the current in the circuit, defined as:

[tex]I=\frac{Q}{t}[/tex]

where Q is the amount of charge that passes through a given point in the circuit in a time interval of t.

The charge Q is measured in Coulombs (C), while the time t is measured in seconds (s), so the unit of measurement of the current is

[tex][I]=\frac{[C]}{[s]}[/tex]

and this unit is called Ampere, and it is indicated with [A].

The maximum emf in the coil depends on

Maximum flux linkage in the coil:

[tex]\phi_\text{max} = B\cdot A\cdot N = 0.59\;\text{T}\times(0.08 \times 0.30)\;\text{m}^{2} \times 505 = 7.2\;\text{Wb}[/tex].

Frequency of the rotation:

[tex]f = 120\;\text{rev}\cdot\text{min}^{-1} = 2 \;\text{rev}\cdot\text{s}^{-1}[/tex].

Angular velocity of the coil:

[tex]\omega = 2\;\pi\;\text{rev}^{-1}\times 2\;\text{rev}\cdot\text{s}^{-1} = 4 \pi \;\text{s}^{-1}[/tex].

Maximum emf in the coil:

[tex]\epsilon_\text{max} = \omega\cdot\phi_\text{max} = 4\;\pi \times 7.2\;\text{Wb} = 90\;\text{V}[/tex].

Emf varies over time. The trend of change in emf over time resembles the shape of either a sine wave or a cosine wave since the coil rotates at a constant angular speed. The question states that emf is "zero at t = 0." As a result, a sine wave will be the most appropriate here since [tex]\sin{0} = 0[/tex].

[tex]\displaystyle \epsilon(t) = \epsilon_\text{max}\cdot \sin{(\omega\cdot t)}[/tex].

Make sure that your calculator is in the radian mode.

[tex]\displaystyle \epsilon\left(\frac{\pi}{32}\right) = 90\;\text{V}\times \sin\left(4\;\pi\times \frac{\pi}{32}\right) = 85\;\text{V}[/tex].

Consider the shape of a sine wave. The value of [tex]\displaystyle \sin\left(\omega \cdot t\right)[/tex] varies between -1 and 1 as the value of [tex]t[/tex] changes. The value of [tex]\epsilon[/tex] at time [tex]t[/tex] depends on the value of [tex]\sin(\omega \cdot t)[/tex].

[tex]\sin(\omega \cdot t)[/tex] reaches its first maximum for [tex]t\ge 0[/tex] when what's inside the sine function is equal to [tex]\pi/2[/tex].

In other words, the first maximum emf occurs when

[tex]\omega \cdot t = \dfrac{\pi}{2}[/tex],

where

[tex]\sin{\omega \cdot t} = 1[/tex],

and

[tex]\epsilon = \epsilon_\text{max}[/tex].

[tex]\displaystyle t = \frac{\pi}{2}/\omega = \frac{1}{8} = 0.125\;\text{s}[/tex].

Final answer:

The maximum emf induced in the coil is 9.67 V. The instantaneous value of the emf at t = π/32 s is 4.67 V. The smallest value of t for which the emf will have its maximum value is approximately 0.395 seconds.

Explanation:

Answer:

(a) To find the maximum emf induced in the coil, we can use the formula: emf = NABω, where N is the number of turns, A is the area of the coil, B is the magnetic field strength, and ω is the angular velocity of the coil.

Given:

Substituting these values into the formula, we can calculate the maximum emf:

emf = 505 × 0.024 m² × 0.59 T × 12.57 rad/s = 9.67 V

Therefore, the maximum emf induced in the coil is 9.67 V.

(b) To find the instantaneous value of the emf at t = π/32 s, we can use the equation: emf = emfmaxsin(ωt), where emfmax is the maximum emf and ω is the angular velocity of the coil.

Given:

Substituting these values into the equation, we can calculate the instantaneous emf:

emf = 9.67 V × sin(12.57 rad/s × π/32 s) = 4.67 V

Therefore, the instantaneous value of the emf in the coil at t = π/32 s is 4.67 V.

(c) The smallest value of t for which the emf will have its maximum value can be found by solving the equation: ωt = π/2, where ω is the angular velocity of the coil.

Given:

Solving for t:

t = π/2ω = π/2(12.57 rad/s) ≈ 0.395 s

Therefore, the smallest value of t for which the emf will have its maximum value is approximately 0.395 seconds.

The two nuclear forces are not responsible for this property.

Gravitational is far too weak to make a transformer work.

The answer is electromagnetic.

The electromagnetic force is responsible for the induction in a transformer. It's due to the production and interaction of electric and magnetic fields, following Faraday's Law of electromagnetic induction.

The fundamental force responsible for the induction in a transformer is the Electromagnetic Force. This is due to the production and interaction of electric and magnetic fields in the transformer. The function of a transformer is primarily based on Faraday's Law of electromagnetic induction which states that a change in magnetic field within a closed loop of wire induces an electromotive force (EMF) in the wire. When you apply alternating current in the primary coil, it creates a constantly changing magnetic field around the secondary coil. This changing magnetic field induces a voltage in the secondary coil, either increasing or decreasing it based on the number of turns in both the coils.

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Galilean Telescope or Refracting Telescope uses a convergent (plano-convex or bi-convex) objective lens and a divergent (plano-concave or bi-concave) eyepiece lens. Galilean telescopes produce upright images.Galileo’s best telescope magnified objects about 30 times. Because of flaws in its design, such as the shape of the lens and the narrow field of view, the images were blurry and distorted. Despite these flaws, the telescope was still good enough for Galileo to explore the sky. The Galilean telescope could view the phases of Venus, and was able to see craters on the Moon and four moons orbiting Jupiter.  

The Newtonian telescope is a type of reflecting telescope invented by the British scientist Sir Isaac Newton using a concave primary mirror and a flat diagonal secondary mirror. Newton’s first reflecting telescope was completed in 1668 and is the earliest known functional reflecting telescope. The Newtonian telescope's simple design makes them very popular with amateur telescope makers.Newtonian telescopes are usually less expensive for any given aperture than comparable quality telescopes of other types. And a short focal ratio can be more easily obtained, leading to wider field of view.  

The eyepiece is located at the top end of the telescope. Combined with short f-ratios this can allow for a much more compact mounting system, reducing cost and adding to portability, Which was not in the Case of Galilean Telescope.

Answer:

1.) is warmer than

2.) heats up faster than

3.) less dense than

Explanation:

e2020

Answer:

1. 2:Is warmer than

2. 1:Heats up faster than

3. 1:Less dense than

Answer:

Linear momentum

Explanation:

The most likely conservation candidate is the linear momentum. The law of momentum conservation states that the sum of momenta before and after an (elastic or inelastic) collision will remain constant.

The kinetic energy is another possible, but less likely suspect. It is conserved in elastic collisions (i.e., those with no kinetic energy loss), but we are not told this collision is assumed elastic. In fact the real setup would be nowhere close to an elastic collision, as the stick lies on ice, which hasn't be zambonied for an entire period of rough skating, there's rough surface and the stick's shaft is also slightly stuck to the surface through frost. So when the puck hits the stick, a portion of its kinetic energy is spent to unstick the stick and get it moving. And so, kinetic energy is not conserved.

Angular momentum is not applicable with the puck-stick scenario.  

In the described scenario, both angular and linear momentum are likely to be conserved, while kinetic energy may not be due to potential energy conversion during the impact.

In this scenario regarding an ice hockey puck hitting a hockey stick on ice, both angular momentum and linear momentum would likely be conserved. The conservation of angular momentum comes into play as the hockey puck changes its direction, and linear momentum is conserved as long as there are no external forces acting on it, as is the case in this scenario. On the other hand, kinetic energy would not necessarily be conserved because some energy might be converted into other forms such as heat or sound during the impact.

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A) [tex]3.25\cdot 10^7 m/s[/tex]

Assuming the electrons start from rest, their final kinetic energy is equal to the electric potential energy lost while moving through the potential difference [tex]\Delta V[/tex]:

[tex]K=\frac{1}{2}mv^2 = q\Delta V[/tex]

where

[tex]m=9.11\cdot 10^{-31}kg[/tex] is the mass of each electron

v is the final speed of the electrons

[tex]q=1.6\cdot 10^{-19}C[/tex] is the charge of the electrons

[tex]\Delta V=3.0 kV=3000 V[/tex] is the potential difference

Solving the equation for v, the speed, we find

[tex]v=\sqrt{\frac{2q\Delta V}{m}}=\sqrt{\frac{2(1.6\cdot 10^{-19}C)(3000 V)}{9.11\cdot 10^{-31} kg}}=3.25\cdot 10^7 m/s[/tex]

B) Centripetal acceleration, [tex]3.82\cdot 10^4 m/s^2[/tex], in units of g: 3898 g

When the electrons cross the region of the magnetic field, they experience a magnetic force which is perpendicular to their trajectory: therefore they start moving in a circular motion. The acceleration they experience is not tangential, but centripetal, and it is given by

[tex]a_c = \frac{v^2}{r}[/tex]

where v is the speed and r the radius of the trajectory.

We can equate the magnetic force exerted on the electrons to the centripetal force:

[tex]qvB=ma_c[/tex]

and isolate [tex]a_c[/tex] to find the centripetal acceleration:

[tex]a_c = \frac{qvB}{m}=\frac{(1.6\cdot 10^{-19} C)(3.25\cdot 10^7 m/s)(0.67 T)}{9.11\cdot 10^{-31} kg}=3.82\cdot 10^4 m/s^2[/tex]

And since [tex]g=9.81 m/s^2[/tex], the acceleration can be rewritten as

[tex]a_c = \frac{3.82\cdot 10^4 m/s^2}{9.81 m/s^2}=3898 g[/tex]

c)  [tex]2.76\cdot 10^{10} m[/tex]

The radius of the circular trajectory can be found by using the formula for the centripetal acceleration:

[tex]a_c = \frac{v^2}{r}[/tex]

Solvign for r, we find

[tex]r=\frac{v^2}{a_c}=\frac{(3.25\cdot 10^7 m/s)^2}{3.82\cdot 10^4 m/s^2}=2.76\cdot 10^{10} m[/tex]

Final answer:

In a black-and-white CRT television, electrons are accelerated by a voltage and then steered by a magnetic field. The speed of electrons can be found using a known formula, and the centripetal acceleration they experience is due to the magnetic force. The radius of their circular path is also calculable from the electron's mass, velocity, and the magnetic field strength.

Explanation:

When electrons are accelerated by a voltage of 3.0 kV (kilovolts) in a black-and-white CRT (cathode-ray tube) television, they gain kinetic energy that is converted from the electric potential energy supplied by the voltage. The formula to find the speed of an electron after acceleration is given by №(√m·V·e), where e is the charge of the electron (1.60 x 10-19 C) and m is the mass of the electron (9.11 x 10-31 kg). The speed is then given by velocity = √(2·V·e/m). Plugging in the numbers, we can find the speed of the electrons.

Regarding part B, since the magnetic force acts perpendicular to the velocity of the electrons, it does not do work on the electrons, meaning the speed of the electrons does not change, but rather, the direction of their velocity changes. Therefore, the acceleration the electrons experience is centripetal acceleration, which keeps the electrons in a circular path, and is given by ac = v2/r, where v is the velocity and r is the radius. To compare this acceleration to g (the acceleration due to gravity), we need the ratio ac/g.

The radius of the circular path, when the electron completes a full circular orbit influenced by a magnetic field, can be determined using the formula r = m·v/(e·B), where B is the magnetic field strength. The radius provides us with valuable information about the steering mechanism in the CRT display.

B. The moon is located between the Sun and Earth

Answer:

B.

hope this helps!!!!

Anytime an object applies a force to another object, there is an equal and opposite force back on the original object. This is known as an action-reaction.

A. The person pushes against the car and the car pushes back

Answer :

correct choice is option A  

Motors convert electrical energy into mechanical energy. Generators convert mechanical energy into electrical energy.

Explanation :

Their difference is described as;

  Premise MOTOR

GENERATOR

Final answer:

Motors convert electrical energy into mechanical energy, while generators convert mechanical energy into electrical energy.

Explanation:

Motors and generators are similar in structure but have opposite functions. A motor converts electrical energy into mechanical energy, while a generator converts mechanical energy into electrical energy. Both motors and generators have a coil mounted on an axel within a magnetic field.

When the coil of a motor rotates, the change in magnetic flux induces an electromotive force (emf) according to Faraday's law of induction. Thus, a motor also acts as a generator when its coil rotates.

On the other hand, a generator works by sending a current through a loop of wire located in a magnetic field. The magnetic field exerts torque on the loop, causing it to rotate and generate mechanical work out of the electrical current initially sent in.

Answer:

[tex]\sqrt{2}v[/tex]

Explanation:

The work done on the object at rest is all converted into kinetic energy, so we can write

[tex]W=\frac{1}{2}mv^2[/tex]

Or, re-arranging for v,

[tex]v=\sqrt{\frac{2W}{m}}[/tex]

where

v is the final speed of the object

W is the work done

m is the object's mass

If the work done on the object is doubled, we have W' = 2W. Substituting into the previous formula, we can find the new final speed of the object:

[tex]v'=\sqrt{\frac{2W'}{m}}=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2}v[/tex]

So, the new speed of the object is [tex]\sqrt{2}v[/tex].

(a) 196 N

At terminal speed, the velocity of the box is constant: this means that its acceleration is zero, so according to Newton's second Law, the resultant of the forces acting on the box is zero. Since there are only two forces acting on the box:

- The weight, acting downward: [tex]W = mg[/tex]

- The air resistance, acting upward: [tex]R[/tex]

It means that at terminal speed, the two forces are balanced:

[tex]W-R=0[/tex]

So we have:

[tex]R=W=mg=(20 kg)(9.8 m/s^2)=196 N[/tex]

(b) 637 N

The exercise is exactly identical as before, but this time the mass of the box is different: m = 65 kg. Therefore, the air resistance in this case will be:

[tex]R=W=mg=(65 kg)(9.8 m/s^2)=637 N[/tex]

At terminal speed, the air resistance force matches the gravitational force acting on the object. For a 20 kg box, the force is 196 N, and for a 65 kg box, it is 637 N. This shows that air resistance increases with speed and mass.

Air Resistance and Terminal Speed

When an object falls from a height, it initially accelerates due to gravity. However, as its speed increases, the air resistance acting upwards on it also increases. Eventually, the air resistance force becomes equal to the force of gravity, and the object stops accelerating; this constant speed is known as terminal velocity.

(a) Terminal Speed for 20 kg Box

For the box with a mass of 20 kg, the force of gravity (weight) is given by:

[tex]F_{gravity}[/tex] = m imes g

where m = 20 kg and g = 9.8 m/s² (acceleration due to gravity).

Therefore, the weight of the box is:

[tex]F_{gravity}[/tex] = 20 kg imes 9.8 m/s² = 196 N

When the box reaches terminal speed, the air resistance force acting upwards is equal in magnitude to the force of gravity acting downwards. Thus, the magnitude of the air resistance force is: 196 N

(b) Terminal Speed for 65 kg Box

For the box with a mass of 65 kg, the force of gravity is:

[tex]F_{gravity}[/tex] = 65 kg imes 9.8 m/s² = 637 N

At terminal speed, the air resistance force acting upwards balances the weight of the box. Thus, the magnitude of the air resistance force is: 637 N

In summary, the air resistance force is equal to the gravitational force acting on the object at terminal velocity, which depends on the mass of the object.

Limiting factors are resources or other factors in the environment that can lower the population growth rate. ... The carrying capacity (K) is the maximum population size that can be supported in a particular area without destroying the habitat. Limiting factors determine the carrying capacity of a population.

Limiting factors are environmental conditions that hinder the increase of a certain population in an ecosystem. On the other hand, carrying capacity is the highest population size that an environment can sustain. These two are related in that the limiting factors determine an environment's carrying capacity.

In biology, limiting factors are conditions in an environment that limit the growth or survival of a population within an ecosystem. Examples include scarcity of food, insufficient habitat space, or occurrence of diseases. Carrying capacity, denoted as K, on the other hand, is the maximum population size that a particular environment can sustain indefinitely, given the food, habitat, water, and other necessities available in that environment.

Warehousing factors and carrying capacity are intimately connected: the occurrence of limiting factors affects the carrying capacity of an environment. When a given population reaches its carrying capacity, the limiting factors cause the growth rate to slow down and eventually settle at a plateau. Therefore, these limiting factors play a critical role in determining and regulating an environment's carrying capacity. Summer weather conditions, for example, might lead to the proliferation of a particular resource, boosting an environment's carrying capacity for that year.

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Using Newton's Second Law for Rolling Motion and centripetal force formulas, the magnitude of the net force exerted on a 41 g ball rolling at 55 rpm on a 64-cm-diameter track is calculated to be approximately 0.4307 Newtons.

To find the magnitude of the net force that the track exerts on the ball, we apply Newton's Second Law to Rolling Motion. We begin by converting the rotational speed to angular velocity: 55 rpm (revolutions per minute) is equivalent to 55 × 2π rad/60s ≈ 5.7596 rad/s. The radius (r) of the circular path is half the diameter, hence r = 64 cm / 2 = 32 cm = 0.32 m.

The ball experiences centripetal force due to its circular motion, which is defined as F = m × ω² × r, where m is the mass, ω is the angular velocity, and r is the radius. Plugging in the values, we get F = 0.041 kg × (5.7596 rad/s)² × 0.32 m ≈ 0.4307 N.

Therefore, the magnitude of the net force that the track exerts on the ball, considering rolling friction is neglected, is 0.4307 Newtons.

The net force exerted by the track on the ball is 0.435 N, calculated using the ball's mass, track radius, and angular velocity. This force is derived by finding the centripetal force required for circular motion.

To find the magnitude of the net force that the track exerts on a ball, we first identify the necessary parameters. The mass of the ball is 41 g, which we convert to kg (0.041 kg). The diameter of the track is 64 cm, giving us a radius of 0.32 m. The ball moves with a frequency of 55 rpm, which we convert to angular velocity.

Therefore, the magnitude of the net force that the track exerts on the ball is 0.435 N.

Answer

The correct formula for weight is F = m*g where g is the gravitational acceleration.

All over the earth's surface, g is slightly different. The mass does not change no matter where you are. We should be measuring out weights in Newtons, not in kg. So the unit of weight in the metric system is 9.8 about * mass in kg.

Stop reading. This is your answer.

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Notes

It was hard enough to get people to change over to kg never mind newtons. Canada, which is on the metric system, still gives the price of food in pounds. Or if not, in grams if the container is small enough.

Cashews cost 19$ Canadian per 906 grams which is roughly 2 pounds.

Oranges are $1.27 a pound and that is the way they are listed in Walmart.

10 pounds of potatoes are 4.95 dollars.

I'm sure you get the point. We use kg for certain things and retain pounds for others.  

The last choice is the correct one.

Resonance in an electrical circuit comprising a resistor, an inductor, and a capacitor connected in series occurs when the inductive reactance equals the capacitive reactance. These reactances represent the effective resistance offered to alternating current by capacitors and inductors, respectively.

In an electrical circuit containing a resistor, an inductor, and a capacitor connected in series, resonance occurs when the inductive reactance equals the capacitive reactance. Reactance is a term used to describe the magnitude of the effective resistance offered by an inductor or a capacitor to the alternating current (AC). The capacitive reactance (Xc) varies inversely with the frequency of the AC and the capacitance, while the inductive reactance (Xl) varies directly with both the AC frequency and the inductance. In resonance, these two values balance each other out, resulting in the circuit behaving as if only the resistance is present.

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The visible emission lines of hydrogen indicate that only certain energies are permissible for its electron. This is due to quantum mechanics, affirming that electrons within atoms exist at distinct energy levels, and emit light of specific wavelengths when transitioning between levels.

The four lines in the visible emission spectrum of hydrogen tell us that only certain energies are allowed for the electron in a hydrogen atom. This is related to the principle of quantum mechanics where an electron in an atom can only exist in discrete energy levels.

When the electron jumps from a higher energy level to a lower one, it emits light of a specific wavelength. The lines we see in the hydrogen emission spectrum represent these wavelengths. Hence, these lines don't mean there are four electrons in an excited hydrogen atom, nor that the hydrogen molecules have the formula H₄. Also, using a stronger prism would not lead to the observation of more lines, but would merely spread the existing lines out more.

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Hey,

i am here to help you................

The house needs sound absorbing materials in the walls so that reveberation  dosen't happens and can here clearly what people will be saying in the house

It is also used in cinema halls also

I believe that this answer was heplful.

Answer:

[tex]c=3\cdot 10^8 m/s[/tex]

Explanation:

All electromagnetic waves travel in a vacuum at the same speed, regardless of their frequency. The magnitude of their velocity is

[tex]c=3\cdot 10^8 m/s[/tex]

This value is one of the universal constant and it is called speed of light.

According to Einstein's theory of special relativity, the value of c is the same for all inertial frames (it means that we measure always the same value of c in a vacuum, even if we are moving with respect to the light).

However, the speed of the electromagnetic waves decreases as they move through a medium. In particular, their speed decreases according to the equation:

[tex]v=\frac{c}{n}[/tex]

where n is called index of refraction of the medium.

Answer:

The velocity of electromagnetic waves is nearly equal to 3 × 108 m/s.

Explanation:

All electromagnetic waves travel at the same speed in a vacuum. The value of their velocity does not depend neither on their frequency, nor on their wavelength.

The magnitude of their velocity is known as speed of light (labelled with c), and it is one of the universal physical constant:

[tex]c=2.998 \cdot 10^8 m/s[/tex]

The velocity of electromagnetic waves changes instead when they travel in a medium (in particular, their speed decreases)

The velocity of all electromagnetic waves in a vacuum is 3 × 10^8 m/s, which is the speed of light and a fundamental physical constant.

In a vacuum, all electromagnetic waves travel at the same speed, which is the speed of light, approximately 3 × 10^8 m/s. This is one of the fundamental physical constants and is denoted by the symbol c. Regardless of their wavelength or frequency, electromagnetic waves propagate through space at this constant velocity. Therefore, the velocity of all electromagnetic waves in a vacuum is 3 × 10^8 m/s.