Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the second force is applied at 60° to the plane of the door. Which force exerts the greater torque about the door hinge?

A. the first force (applied perpendicular to the door)
B. Both forces exert equal non-zero torques
C. Both forces exert zero torque
D. the second force

Answer:

0.83999 m

0.20999 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s = 189 cm

[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 1.89=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.89\times 2}{9.81}}\\\Rightarrow t=0.62074\ s[/tex]

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

[tex]t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.62074}{3}\\\Rightarrow t'=0.206913\ s[/tex]

For second drop time is given by

[tex]t''=2t'\\\Rightarrow t''=2\times 0.2069133\\\Rightarrow t''=0.4138266\ s[/tex]

Distance from second drop

[tex]s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.4138266^2\\\Rightarrow s=0.839993\ m[/tex]

Distance from second drop is 0.83999 m

Distance from third drop

[tex]s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.206913^2\\\Rightarrow s=0.20999\ m[/tex]

Distance from third drop is 0.20999 m

Answer:

107.52 J

Explanation:

force (f) = 42.8 N

angle of force (θ) = 16.5 °

distance  (d) = 2.62 m

find the work done.

work done = force x distance

resolving the force we have = 42.8 x cos (16.5) = 41.04 N

work done = 41.04 x 2.62 = 107.52 J

A negative charge moving in the direction of an electric field will have its potential energy increased and the electric field will do negative work on the charge.

When a negative charge moves in the direction of an electric field, it experiences a force in the opposite direction to the electric field. This force does work on the charge, but since the charge is negative and the electric field does work in the direction opposite to the charge's movement, several things happen:

Therefore, out of the provided statements, the ones that are true are:

Answer:

e. all three objects possess charges of the same sign.

Explanation:

We know that objects with same polarity will repel each other while objects with opposite polarity will attract each other. Here objects A and B repel each other which means they possess the charge of same polarity. Objects B and C also repel each other which means that they also possess the same polarity (sign).

This means that A and C will also repel each other. All the three objects possess the charge with same polarity.

Answer: a) The speed in km/hr is 54.7.

b) The speed in m/s is 15.2

Explanation:

a) The conversion used from miles to km is:

1 mile = 1.61 km

34.0 miles= [tex]\frac{1.61}{1}\times 34.0=54.7km[/tex]

We are asked: 34.0 miles/hr = ? km/hr

Thus 34.0 miles/hr = [tex]\frac{54.7}{1}=54.7km/hr[/tex]

Therefore, the speed in kilometer per hour is 54.7 km/hr

b) The conversion used from miles to m is:

1 mile = 1610 m

34.0 miles= [tex]\frac{1610}{1}\times 34.0=54740m[/tex]

The conversion used from hour to sec is:

1 hour = 3600 sec

We are asked: 34.0 miles/hr = ? m/s

Thus 34.0 miles/hr = [tex]\frac{54740m}{3600s}=15.2m/s[/tex]

Therefore, the speed in meters per second is 15.2 m/s

Final answer:

Bicyclists in the Tour de France traveling at 34.0 mi/h have a speed of approximately 54.72 km/h and 15.20 m/s after conversion.

Explanation:

To convert the speed of bicyclists in the Tour de France from miles per hour to kilometers per hour and meters per second, we can use the following conversion factors:

1 mile = 1.60934 kilometers

1 hour = 3600 seconds

(a) To convert 34.0 mi/h to km/h, multiply by the conversion factor:

34.0 mi/h imes 1.60934 km/mi = 54.7176 km/h

(b) To convert 54.7176 km/h to m/s, multiply by the conversion factor:

54.7176 km/h imes (1000 m / 1 km) imes (1 h / 3600 s) = 15.199 m/s

Therefore, a speed of 34.0 mi/h is approximately 54.72 km/h and 15.20 m/s.

Answer:

the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates is 57.6 m/s

Explanation:

Given information:

diameter of the disc, d  = 11 cm, r = 5.5 cm = 0.055 m

angular speed ω = 10000 rev/min = (10000 rev/min)(2π rad/rev)(1/60 min/s)

                             = 1000π/3 rad/s

to calculate the maximum angular speed we can use the following formula

ω = v/r

v = ωr

  = (1000π/3)(0.055)

  = 57.6 m/s

Answer:

37.96usd , 9.49usd

Explanation:

From the data given we have

cost of electricity= $0.13,

and annual cost of electricity is express as

Annual cost= power *hours*days*cost of electricity

note the unit of power must be in kilowatt(Kw),

a. to determine the cost of running 100w we first convert to kw

[tex]1w=0.001kw\\100w=0.1kw\\[/tex]

Hence the annual cost of running it 8.00 hours per day is calculated as

[tex]annual cost=0.1*8*365*0.13\\annual cost=37.96 USD[/tex]

b. to determine the cost of running 25w we first convert to kw

[tex]1w=0.001kw\\25w=0.025kw\\[/tex]

Hence the annual cost of running it 8.00 hours per day is calculated as [tex]annual cost=0.025*8*365*0.13\\annual cost=9.49 USD[/tex]

Hence from the answers we can conclude that less amount of money required to run the 25w incandescent bulb compare to the 100w

Answer:

0.74 m/s

Explanation:

given,

time taken by the ramp to cover cliff , t = 64 s

acceleration = 0.37 m/s²

distance traveled by the belt

 [tex]x = v_{belt}t_{belt}[/tex]

Clifford  is moving with constant acceleration

 [tex]x = v_ot + \dfrac{1}{2}at^2[/tex]...(1)

initial velocity is equal to zero

 [tex]x =\dfrac{1}{2}at^2[/tex]........(2)

equating equation (1) and (2)

[tex]v_{belt}t_{belt}=\dfrac{1}{2}at^2[/tex]

[tex]v_{belt}t_{belt}=\dfrac{1}{2}a(\dfrac{1}{4}\times t_{belt})^2[/tex]

[tex]v_{belt}=\dfrac{1}{32}a t_{belt}[/tex]

[tex]v_{belt}=\dfrac{1}{32}\times 0.37 \times 64[/tex]

[tex]v_{belt}= 0.74\ m/s[/tex]

Speed of the belt is equal to 0.74 m/s

Answer:

increasing the distance between the objects

decreasing the mass of one of the objects

decreasing the mass of both objects

Explanation:

The complete question would be:

Which changes would result in a decrease in the gravitational force between two objects? Check all that apply.

increasing the distance between the objects

decreasing the distance between the objects

increasing the mass of one of the objects

increasing the mass of both objects

decreasing the mass of one of the objects

decreasing the mass of both objects

---------------------------------------------------------------------------------------

Gravitational force between two objects can be computed using the formula:

[tex]Fg = G\dfrac{Mm}{r^2}[/tex]

Where:

Fg is the gravitational force (Newtons or N)

G is the gravitational constant (6.674⋅10⁻¹¹N(m/kg)²)

M is the mass of one object (Kilograms or Kg)

m is the mass of the other object (Kilograms or Kg)

r is the distance between the two objects (m)

Now notice the relationship between the mass and gravitational force. Their relationship is direct, meaning as the value of one goes up, the other goes up and the reverse holds true. If the mass of one or both of the objects decreases, the gravitational force also decreases.

Now look at the relationship between the distance between the objects and the gravitational force-- they are indirect. This means that as one increases, the other decreases. So if we increase the distance between the objects, the gravitational force between them decreases as well.

Answer:

increasing the distance between the objects

decreasing the mass of one of the objects

decreasing the mass of both objects

Explanation:

Explanation:

Consider the horizontal motion of ball

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 44.7 m/s

        Acceleration, a = 0 m/s²  

        Displacement, s = 16.1 m      

     Substituting

                      s = ut + 0.5 at²

                      16.1 = 44.7 x t + 0.5 x 0 x t²

                      t = 0.36 s

      Time taken to travel 16.1 m is 0.36  seconds

Now we need to find how much ball travel vertically during this 0.36 seconds.

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 9.81 m/s²  

        Time, t = 0.36 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 0.36 + 0.5 x 9.81 x 0.36²

                      s = 0.64 m

     The baseball drops by 0.64 meter.

Answer:W = -5.808J

Explanation:

Given:

Mass of hoop,m=120kg

Centre of mass speed of hoop,v= 0.220m/s

Rotational inertia,I= mr^2

I=120r^2

Kinetic energy of hoop= Linear kinetic energy + Rotational kinetic energy

K= (1/2mv^2) + (1/2Iw^2)

But w= (v/r)^2

K= (1/2mv^2) + (1/2×120r^2(v/r)^2)

K = (1/2×120×0.220^2) + (1/2×120×0.220^2)

K= 5.808J

To stop the hoop,its final kinetic energy must be zero,

Workdone = Kfinal-Kinitial = 0 - 5.808

W= -5.808J

The recoil velocity of the canoe is calculated using conservation of momentum. The horizontal component of the stone's velocity is first determined, and the stone's momentum is then used to find the canoe's recoil. The direction of recoil is opposite to the stone's horizontal velocity component.

The recoil velocity of a stationary object after projecting an object can be calculated using the principle of conservation of momentum.

Since the person and the canoe are initially motionless, the total momentum before the stone is thrown must be equal to the total momentum afterwards.

Step-by-Step Explanation

The direction of the canoe's recoil will be opposite to the stone's horizontal component of velocity since momentum is conserved and no external horizontal forces are acting on the system.

Answer:

Explanation:

a) Deceleration due to gravity along the inclined plane is given by:

  g*Sin(∅)= 9.8*Sin(37)=5.9 m/s^2.

Since acceleration is constant, we can use equation of motion along the plane. [tex]V^{2} = U^{2} +2as[/tex]

where V: final velocity, U:initial Velocity, a:Acceleration and s:distance

0=[tex]4.4^{2} + 2*-5.9*s[/tex] (-ve because it is against gravity)

It will go 1.64 meters up the plane

b) Force due to friction = Coeff. of friction * Normal Force

Normal Force = mg*Cos(∅) = 9.8*3.8*Cos(37) = 29.75;

Coeff of friction = 0.47;

Force due to friction = 0.47*29.75 = 13.98 N

Force due to gravity : 3.8*5.9 = 22.42;

Total force after adding friction = 22.42 + 13.98 = 36.4 N

New Acceleration = 36.4/3.8 = 9.58;

Applying the equation of motion used above with acceleration = 9.58;

It will go 1.01 meters up the plane.

c) Thermal energy due to friction = Max potential energy without friction - max potential energy after friction.

Potential energy w.o friction(m*g*h) = 3.9 * 9.8 * 1.64*Sin(37) = 37.72 Joules

Potential energy with friction(m*g*h)= 3.9 * 9.8 * 1.01*Sin(37) = 23.23 Joules

Energy due to friction = 37.72 - 23.23 = 14.49 Joules

Answer:Area cleaned by the 7-in wiper blade=22

72sq in

Explanation: In a windshield the wiper moves in a semi circle. The angle in a semi circle is 180°

Let A= Total area

A= 2×9×3.1461×(93/180)

A=29.22squareinch

Let a be area cleaned by the 7-inch wiper

a=29.22 - 2(9-7)×3.1461×(93/180)

a=29.22 - 6.502

a= 22.72sqin

Answer:

The area of the portion of the windshield cleaned by the 7-in wiper blade is 62.49 in²

Explanation:

Given

Length of blade = 9 inches

Angle of rotation = 93°

We're to calculate the area of the portion of the windshield cleaned by the 7​-in wiper​ blade?

We'll solve this by using area of a sector.

Area of a sector = ½r²θ

where θ is in radians.

So, angle of rotation (93°) must first be converted to radians

Converting 93º to radians, we get 31π/60

The area of the region swept out by the wiper blade = (area of the sector where r = 9 and

θ = 31π/60) - (area of the sector where r = (9-7) and θ = 31π/60).

We're making use of 9-7 because that region is outside the boundary of the 7in blade

So Area = ½*9²*31π/60 - ½*2²*31π/60

Area = ½*31π/60(9²-7²)

Area = 31π/120 * (81 - 49)

Area = 31π/120 * 32

Area = 992π/120

Area = 62.49151386765697 in²

Area ≈ 62.49 in²

Hence, the area of the portion of the windshield cleaned by the 7-in wiper blade is 62.49 in²

Answer:

A. The angular velocity of Point 1 and Point 2 are the same

B. The angular acceleration is equal.

C. Tangential velocity of Point 1 is greater than Point 2

D. The tangential acceleration of point1 is greater than point 2

E. The centripetal acceleration of Point 2 is greater than point 1

Explanation:

- Since angular velocity is angular displacement of Point divided by time and since they are in the same line perpendicular to the axis, that means angular velocity is equal.

The tangential speed is the measure of how quickly an object is traveling along a circular path and two object with the same angular velocity but different radius would have different tangential speed.

-The tangential acceleration is the measure of how quickly the tangential velocity changes and is angular acceleration multiplied by the radius from the centre of circle so since point 1 has a bigger radius, it would have a greater tangential acceleration.

The centripetal acceleration is the effect on the body traveling in a circular path and is directed towards the center of the circle and it is inversely proportional to the radius so the bigger the radius the smaller the centripetal acceleration.

Point 1 on the rim of the wheel has the greater tangential speed, while both points have the same angular velocity and angular acceleration.

In this scenario, point 1, located on the rim of the wheel, has the greater tangential speed (c) since it travels a larger circle with a larger radius in the same amount of time as point 2. However, both points have the same angular velocity (a) since they are both attached to the same rigid wheel and rotate at the same rate. Additionally, both points experience the same angular acceleration (b) since they are undergoing circular motion with the same angular speed. The tangential acceleration (d) and centripetal acceleration (e) are not required to answer the question as the problem does not provide information regarding the tangential or centripetal forces acting on the points.

Answer: The dimensions are length 600metres and breadth= 300 metres

Explanation:

Area of rectangle =l × b

L b =180,000

b = 180,000/L ....... equation 1

Perimeter of rectangle =2L + b

P = 2(180,000)/L + L

P= 360,000/L +L

dp/dL= -360,000/L^2 +1

L^2= 360,000

L= Squareroot of 360,000

L=600m

b= 180,000/600

b= 300m

The required dimensions will be "600 by 300". A complete solution is below.

According to the question,

No fencing along river so,

By taking the derivative, we get

→ [tex]f'(x) = -\frac{180000}{y^2+2} =0[/tex]

                  [tex]\frac{180000}{y^2} = 2[/tex]

                       [tex]y^2 = \frac{180000}{2}[/tex]

                       [tex]y^2 = 90000[/tex]

                        [tex]y = \sqrt{90000}[/tex]

                           [tex]= 300[/tex]

and,

→ [tex]x = \frac{180000}{300}[/tex]

     [tex]= 600[/tex]

Thus the above answer is right.    

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Answer:

A wind turbine turns wind energy into electricity using the aerodynamic force from the rotor blades.

Explanation:

Answer:

10.28571 hp

Explanation:

[tex]W_{shaft}[/tex] = Shaft output power = 104 hp

[tex]\eta[/tex] = Average efficiency = 91%

Electric work done rate is given by

[tex]W_{el}=\dfrac{W_{shaft}}{\eta}[/tex]

The rate of heat supply is given by

[tex]Q=W_{el}-W_{shaft}\\\Rightarrow Q=W_{shaft}(\dfrac{1}{\eta}-1)\\\Rightarrow Q=104(\dfrac{1}{0.91}-1)\\\Rightarrow Q=10.28571\ hp[/tex]

The heat supply by the motor to the engine compartment at full load is 10.28571 hp

Final answer:

The magnitude of the average force acting on the 555 g ball during the collision is approximately 347.39 N. This is calculated using the impulse-momentum theorem, as the product of the average force and the contact time equals the change in momentum.

Explanation:

The student's question pertains to the concept of impulse and the average force exerted during a collision, which are foundational topics in dynamics, a branch of Physics. To find the magnitude of the average force acting on the ball during the collision, we can use the impulse-momentum theorem. The impulse exerted on an object is equal to the change in momentum of the object, and it can also be calculated as the average force times the time period of the force's application.

The formula for impulse (I) is given by:
I = F_avg × Δt

Where F_avg is the average force, and Δt is the time interval for which the force is exerted.

The change in momentum (Δp) is given by:
Δp = m(v_f - v_i)

Here, m is the mass of the object, v_f is the final velocity, and v_i is the initial velocity. For the ball in question:

First, we calculate the change in momentum, Δp:
Δp = 0.555 kg × (-12.1 m/s - 14.9 m/s) = 0.555 kg × (-27 m/s) = -15.285 kg·m/s

Because impulse equals change in momentum, we have:
F_avg × Δt = Δp
F_avg = Δp / Δt
F_avg = -15.285 kg·m/s / 0.044 s
F_avg ≈ -347.39 N

The negative sign indicates that the force's direction is opposite to the initial direction of the ball. However, the question asks for the magnitude, so we take the absolute value: |F_avg| ≈ 347.39 N.

Answer:

E = 4.01×10^6 N/C

direction is toward q2

Explanation:

q1 = q2 = 12micro-C = 12×10^-6C

r1 = 18cm = 0.18m

r2 = 40cm = 0.40m

k = 9×10^9

E1 = kq1/(r1)²

E1 = 3.33×10^6 N/C

E2 = kq2/(r2)²

E2 = 6.75×10^5 N/C

Enet = E1 + E2

= 3.33×10^6 + 6.75×10^5

= 4.01×10^6 N/C

direction is toward q2

Answer:

the force experienced by both particles will be of same magnitude as the magnitude of charge is same for both particles but with different sign, the acceleration of both particles will be same in magnitude but opposite in direction, the direction of free electron will be opposite to the direction of electric field whereas the direction of proton will be in the direction of electric field,

Explanation:

the force experienced by both particles can be calculated by the formula

F=|q|E

the acceleration can be calculated by Newton's 2nd law i.e F=ma

the direction of electric field is always towards the positive charge so proton will be directed towards electric field and free electron will be directed away from the electric field.

Answer:

The change in temperature of 576.9°C will produce an elongation of 9 inches per feet in steel.

Explanation:

The formula for linear expansion of a material is:

ΔL = αLΔT

where, ΔL = change in length

             L = Original length

           ΔT = Change in temperature

             α = coefficient of linear expansion

For steel, α = 13 x 10^-6 /°C

                L = 100 ft

                ΔL = (9 in)(1 ft/12 in) = 0.75 ft

Therefore,

0.75 ft = (13 x 10^-6 /°C)(100 ft)ΔT

ΔT = 576.9°C

Answer:

Avoidant attachment pattern

Explanation:

The Attachment theory proposes that there are 4 attachment styles:

Secure attachment

Anxious attachment

Avoidant attachment

Anxious-Avoidant attachment

A child who does not seek their mother when they leave and are unbothered by the fact that the mother is not around shows the avoidant attachment pattern. The child is independent and self-directed, thus does not seek intimacy. These types of people are assumed to be fearful or avoidant when it comes to intimacy and commitment, as the theory suggests.

Differentiating it from the other style:

Secure attachment pattern show comfort in intimacy. They easily display interest to other parties, but at the same time, they do not necessarily seek intimacy as they are capable of being alone as well.

Anxious attachment on the other hand, is more like a needy and clingy type of behavior. They seek companionship more desperately and always needs reassurance.

Anxious-avoidant attachment is a more aggressive (in a defensive sense) type. They totally avoid commitment or any form of intimacy. What makes them different is the distrust. They do not trust anyone that tries to get close to them and can sometimes emotionally vent out, (verbally or physically) if anyone attempts to get to know them.

Answer:

Plenum cabling

Explanation

As the plenum cabling are fire resistent so it will not cause the toxic components in case of fire.

Answer:

Iaas

Explanation:

Infrastructure as a service (IaaS) is an online service that supplies high-level APIs that are used to derefer various low-level information such as physical computing resources, location, data partitioning, scaling, protection, backup etc. of the underlying network infrastructure

Cloud computing is a cloud service that uses software to emulate hardware capabilities, such as increasing or decreasing bandwidth or storage to meet changing needs.

The cloud service that uses software to emulate hardware capabilities, such as increasing or decreasing bandwidth or storage to meet changing needs, is cloud computing.

In cloud computing, virtualization technology is used to create virtual instances of the hardware resources, allowing them to be dynamically allocated or scaled up/down as needed.

For example, Amazon Web Services (AWS) offers a cloud service called  (Elastic Compute Cloud) that allows users to create virtual servers with customizable specifications, such as CPU, memory, and storage.

Users can easily increase or decrease these resources based on their requirements, without the need for physical hardware changes.

Other cloud services like Microsoft Azure, G o o g l e Cloud Platform, and IBM Cloud also provide similar capabilities, allowing organizations to optimize their resource allocation and cost efficiency.

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Answer:

The answer is 3213.6 grams.

Explanation:

In meters the room dimensions are 3.05-3.2-6.86.

Total volume of the room is:

[tex]3.05*3.2*6.86=66.95[/tex]

66.95 m3.

The density of carbon monoxide is 48 g/m3. Then total grams is present in a room measuring:

[tex]66.95*48=3213.6[/tex]

Answer:

493.02 g.

Explanation:

Density = mass/volume

mass = density×volume

m = D×V ............................ Equation 1

m = mass of the aluminum foil, D = Density of the aluminum foil, V = volume of the aluminum foil.

V = L×W×H................... Equation 2

Where L = length of the aluminum foil, W = wide of the aluminum foil, H = thickness of the aluminum foil.

Given: L = 59.3 yd = 59.3×0.9144 m = 54.224 m, W = 13 in = 13×0.0254 m = 0.3302 m, H = 0.00040 in = 0.00040×0.0254 m = 0.0000102 m.

Substituting into equation 2

V = 54.224×0.3302×0.0000102

V = 0.0001826 m³ = (0.0001826×1000000) cm³

V = 182.6 cm³

Also given D = 2.70 g/cm³

Substitute into equation 1

m = 2.7×182.6

m = 493.02 g.

The mass in grams of the foil = 493.02 g.

Answer:

B. Parameter.

Explanation:

After inspecting all of 55,000 kg of meat stored at the Wurst Sausage Company, it was found that 45,000 kg of the meat was spoiled.

The data above is described as a parameter because the data describes the entire population (the meat). the difference between statistic and parameters are statistic is used to describe a sample whereas parameter is used to describe the population.

The data indicating that 45,000 kg out of 55,000 kg of meat was spoiled at the Wurst Sausage Company is considered a parameter. This is because it describes the entirety of the meat stored.

In this situation, the information about the 55,000 kg of meat, of which 45,000 kg was spoiled, is described as a parameter. A parameter is a number that describes a population, in this case, the entirety of meat stored at the Wurst Sausage Company. Whereas a statistic is a numeral that describes a sample, in this case, if they only inspected a portion of the meat storage, then the result would be a statistic.

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Answer:

Option A and B

Explanation:

In the parallel connection, the capacitors that are connected in parallel have the same potential difference across each capacitor as the battery. Therefore, statement A is correct.

Charge (Q), capacitance (C) and voltage across capacitor (V) is related with each other as follows:

Q = C ×V

As capacitance is not same for all the capacitors, therefore each capacitor carries different charge. Therefore, statement C is incorrect.

As potential difference across each capacitor is same, therefore, capacitor with the largest capacitance carry the most charge. Therefore, statement B is correct.

Therefore, statements A and B are correct.

Answer:

Option A and B is correct

Explanation:

When two or more capacitors are connected in parallel, the equivalent capacitance of the circuit is the sum of capacitance of all the capacitors.

C = C₁ + C₂+ C₃+....

The potential difference across each capacitor is equal. Thus, option A is correct.

The total charge is the sum of the charge on stored in each capacitor.

Q = Q₁ + Q₂+ Q₃+....

Q = CV

Since the voltage is same across each capacitor, the capacitor which has largest capacitance has the most charge. Thus, option B is correct.

Answer:

The speed of the boxes are 1 m/s.

Explanation:

Given that,

Mass of box = 1 kg

Mass of another box = 2 kg

Suppose 1 kg box moves with 3 m/s speed.

We need to calculate the speed of the boxes

Using formula of conservation of momentum

[tex]m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v[/tex]

Where, u = initial velocity

v = final velocity

Put the value into the formula

[tex]1\times3+2\times0=(1+2)v[/tex]

[tex]v=\dfrac{3}{3}[/tex]

[tex]v=1\ m/s[/tex]

Hence, The speed of the boxes are 1 m/s.

After the collision, the speed of the two boxes will reduce due to lost in kinetic energy associated with inelastic collision.

The given parameters;

Apply the principle of conservation of linear momentum to determine the final velocity of the two boxes after collision.

m₁u₁  +  m₂u₂  = v(m₁  +  m₂)

1(u₁) + 2u₂ = v(3)

u₁ + 2u₂ = 3v

Where;

u₁ and u₂ are the initial velocity of the first and second box respectively

v is the final velocity of the two boxes

Thus, we can conclude that after the collision, the speed of the two boxes will reduce due to lost in kinetic energy associated with inelastic collision.

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