Two different compounds are obtained by combining nitrogen with oxygen. the first compound results from combining 46.7 g of n with 53.3 g of o, and the second compound results from combining 17.9 g of n and 82.0 g of o. calculate the ratio of the mass ratio of o to n in the second compound to the mass ratio of o to n in the first compound. express your answer numerically.

Answers

Answer 1
First:

46.7 g of N with 53.3 g of O,

=> mass ratio O to N = 53.3 / 46.7 = 1.1413

Second

17.9 g of N and 82.0 g of O.

mass ratio of O to N = 82.0 / 17.9 = 4.5810

Third

Ratio of the mass ratio of O to N in the second compound to the mass ratio of O to N in the first compound =

= 4.5810 / 1.1413 = 4.013 ≈ 4

Answer: 4
Answer 2
Final answer:

The mass ratio of oxygen to nitrogen in the first compound is 1.1413, and in the second compound, it is 4.5810. The ratio of these mass ratios is approximately 4.015.

Explanation:

The question involves calculating the mass ratio of oxygen to nitrogen for two nitrogen-oxygen compounds and then finding the ratio of these mass ratios.

For the first compound:
Mass of O: 53.3 g
Mass of N: 46.7 g
Mass ratio of O to N: 53.3 g / 46.7 g = 1.1413

For the second compound:
Mass of O: 82.0 g
Mass of N: 17.9 g
Mass ratio of O to N: 82.0 g / 17.9 g = 4.5810

Now, we calculate the ratio of the mass ratio of the second compound to that of the first compound:
4.5810 / 1.1413 = 4.015

Therefore, the ratio of the mass ratio of oxygen to nitrogen in the second compound to the first one is approximately 4.015.


Related Questions

What should happen when a piece of copper is placed in 1m hcl?
a. the copper is dissolved by the acid.
b. the copper is dissolved by the acid with the release of hydrogen gas.
c. the copper bursts into greenish flames.
d. nothing happens?

Answers

Final answer:

Nothing happens when a piece of copper is placed in 1M hydrochloric acid because copper is not reactive enough to displace hydrogen from the acid and no observable chemical reaction occurs.

Explanation:

When a piece of copper is placed in 1M hydrochloric acid (HCl), the correct option would be d. nothing happens. Copper is a less reactive metal and does not react with hydrochloric acid to produce hydrogen gas or any other substances. Reactions such as those with zinc in hydrochloric acid form hydrogen gas because zinc is a more active metal and can displace hydrogen from the acid. However, copper does not have sufficient reactivity to do this, and so when copper is placed into hydrochloric acid, there is no observable chemical reaction.

261 nm to millimeters

Answers

the answer is 0.000261 millimeters

In the metric system, a millimeter measures length. The word "milli" is derived from the Latin word "mille," which means one thousandth. A millimeter is therefore one-thousandth of a meter. A millimeter is represented by the letter "mm." Here 261 nm is 0.000261 millimeters.

A nanometer is a length measurement that is one billionth of a meter. The nanometer is denoted by the sign "nm" in the international system of units, sometimes known as SI units. One nanometer can be represented as 1 x 10⁻⁹ meters in scientific notation.

Here,

1 mm = 1000000 nm

261 nm = 0.000261 mm

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0.000261 millimeters

Calculate the ph of a 0.060 m carbonic acid solution, h2co3(aq), that has the stepwise dissociation constants ka1 = 4.3 × 10-7 and ka2 = 5.6 × 10-11.

Answers

1) First dissociation

H2 CO3    =    H(+) + HCO3(-)          Ka1 = 4.3 * 10^ -7

0.06 - x              x          x

Ka1 = x^2 / (0.06 - x) = 4.3 * 10^ - 7

A low Ka => x << 0.06 => 0.06 -x ≈ 0.06

=> Ka1 ≈ x^2 / 0.06 => x^2 ≈ 0.06 * Ka1 = 0.06 * 4.3 * 10^-7

=> x ≈ √[ 2.58 * 10 ^ -8] = 1.606 * 10^ - 4 = 0.0001606

2) Second dissociation

          HCO3(-)    =   H(+) + CO3(2-)         Ka2 = 5.6 * 10^ - 11

0.0001606 - y            y             y

Ka2 ≈ y^2 / 0.0001606 => y = √[0.0001606 * 5.6* 10^ -11]

y = 9.48 * 10^ -8

3) [H+] = x + y = 1.607 * 10^ -4

4) pH = - log [H+] = 3.79

Answer: 3.79
Final answer:

To calculate the pH of a 0.060 M carbonic acid solution, first, consider the first dissociation of the H2CO3. Calculate [H+] by taking the square root of Ka1 x [H2CO3]. Finally, express [H+] in terms of pH. The calculated pH is 3.69.

Explanation:

To calculate the pH of a 0.060 M carbonic acid solution, we have to consider the stepwise dissociation of the carbonic acid, denoted by its dissociation constants Ka1 and Ka2. To see how this works, let's look at the first dissociation of H2CO3:

H2CO3(aq) =  H+(aq) + HCO3- (aq)

Ka1 = [H+][HCO3-]/[H2CO3]

Given, [H2CO3] = 0.060 M and Ka1 = 4.3 × 10-7, we can solve for [H+]. According to the ICE (Initial, Change, Equilibrium) approach, we approximate [H+] by the square root of Ka1 x [H2CO3]. Therefore, [H+] = √(4.3 × 10^-7 × 0.060) = 2.04 x 10^-4. We may ignore the second dissociation (Ka2) as it contributes negligibly to [H+].

Finally, we express [H+] in terms of pH. pH is the negative log to the base 10 of [H+], hence, pH = -log[H+] = -log(2.04 x 10^-4) = 3.69

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When titrating a strong monoprotic acid and koh at 25°c, the ph will be less than 7 at the equivalence point. ph will be greater than 7 at the equivalence point. titration will require more moles of base than acid to reach the equivalence point. ph will be equal to 7 at the equivalence point. titration will require more moles of acid than base to reach the equivalence point?

Answers

By definition titraion of a monoprotic acid with means that the equivalence point implies netrality of the solution, which is pH = 7.

So, the answer is that pH will be equal to 7 at the equivalence.

Given that the acid is monoprotic and KOH has one OH- radical per molecule of KOH, the titration will require the same number of moles of acid than base to reach the equivalence point, as you can see in this equation, representing the monoprotic acid as HA:

 HA + KOH = K(+) + A(-) + H2O => 1 mol HA per 1 mol KOH.

Answer:

yes

Explanation:

because u right

Matter is neither created nor destroyed in a chemical reaction

Answers

This is true according to the Law of Conservation of Mass.

Hope this helps! :)

Give the common name for the structure. ethyl isopropyl ketone tert-butyl ethyl ketone sec-butyl ethyl ketone ethyl isobutyl ketone isobutyl methyl ketone

Answers

The structure for this question is attached. I think the correct answer would be the fourth option. The common name of the structure would be ethyl isobutyl ketone. Other name would be 2-methyl-3-pentanone. It has a chemical formula of C7H14O or (CH3)2CHCH2C(O)CH2CH3. It is classified as an aliphatic ketone and is used as a solvent and a reagent in laboratory experiments. It is a VOC or volatile organic compound. This compound can also be found at times in normal human biofluids and in feces for about 25% of the population. At normal conditions, it exists as a solid compound. 
Final answer:

Common names for ketones include the names of the alkyl groups attached to the carbonyl group followed by 'ketone'. Ethyl methyl ketone is an example with an ethyl group and a methyl group.

Explanation:

The common names for ketones are typically derived by naming the alkyl groups attached to the carbonyl group, followed by the word ketone. For the ketones listed:

Ethyl isopropyl ketone refers to a ketone with an ethyl group and an isopropyl group attached to the carbonyl.Tert-butyl ethyl ketone has a tertiary butyl group and an ethyl group attached.Sec-butyl ethyl ketone consists of a secondary butyl group and an ethyl group attached.Ethyl isobutyl ketone has an ethyl group and an isobutyl group attached.Isobutyl methyl ketone, also known as 3-methyl-2-butanone, has an isobutyl group and a methyl group attached.

For example, the ketone with four carbon atoms, with an ethyl group and a methyl group on either side of the carbonyl, is commonly known as ethyl methyl ketone.

A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what is the molecular formula of the compound?

Answers

1) mass composition

N: 30.45%
O: 69.55%
   -----------
   100.00%

2) molar composition

Divide each element by its atomic mass

N: 30.45 / 14.00 = 2.175 mol

O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

Divide both by the smaller number

N: 2.175 / 2.175 = 1

O: 4.346875 / 2.175 = 1.999 = 2

5) Empirical formula: NO2

6) mass of the empirical formula

14.00 + 2 * 16.00 = 46.00 g

7) Find the number of moles of the gas using the equation pV = nRT

=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)

=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4

The molecular formula of the compound given the percentages and conditions is determined to be N₂O₄ by converting mass percentages to moles, using the ideal gas law to find molar mass, and then refining the empirical formula.


Finding the Molecular Formula:

To determine the molecular formula of the compound with 30.45% nitrogen (N) and 69.55% oxygen (O) by mass, we will follow several steps:

Determine the empirical formula:
Molar masses: N = 14.01 g/mol, O = 16.00 g/mol
Convert mass percentages to moles:
N: 30.45 g / 14.01 g/mol = 2.174 mol
O: 69.55 g / 16.00 g/mol = 4.347 mol
Find the simplest ratio:
N: 2.174 / 2.174 = 1
O: 4.347 / 2.174 = 2

Empirical formula: NO₂Find the molecular weight using the ideal gas law:
P = 775 mm Hg = 1.019 atm, V = 389 mL = 0.389 L, T = 0.00°C = 273.15 K
Use PV = nRT: n = PV/RT = (1.019 atm * 0.389 L) / (0.0821 atm·L/mol·K * 273.15 K) = 0.0174 mol
Molar mass: 1.63 g / 0.0174 mol = 93.68 g/molDetermine the molecular formula:
Empirical formula mass: 14.01 g/mol (N) + 2 * 16.00 g/mol (O) = 46.01 g/mol
Molecular formula mass / Empirical formula mass: 93.68 g/mol / 46.01 g/mol ≈ 2
Molecular formula: (NO₂)₂ = N₂O₄

The molecular formula of the compound is N₂O₄.

A sample of chromium oxide is 76.5% chromium by weight. what is the simplest formula of the oxide?

Answers

CrO as we need to find the empirical formula (simplest formula) not molecular formula 

The nuclide as-76 has a half-life of 26.0 hours. if a sample of as-76 weighs 344 g, what mass of as-76 remains after 538 minutes?

Answers

The amount of substance after t hours with the given half-life can be calculated through the equation,

                     A(t)  = A(o) x (0.5)^(t/h)

where A(t) is the amount after t hours, A(o) is the original amount, h is the half-life.

Substituting the known values from the given,

It must be noted that the number of minutes should be converted first to hours by dividing it by 60. 

                  A(t) = (344 g) x (0.5)^((538/60)/26))
                       A(t) = 270.86 g
Thus, the amount of as-76 after 538 minutes is approximately 270.86 g. 

The mass of [tex]\(\text{As-76}\)[/tex] remaining after 538 minutes is approximately [tex]\( 270.38 \text{ g} \).[/tex]

To determine the remaining mass of [tex]\(\text{As-76}\)[/tex] after 538 minutes given its half-life of 26.0 hours, we can use the concept of radioactive decay.

First, convert the given time from minutes to hours:

[tex]\[ 538 \text{ minutes} \times \frac{1 \text{ hour}}{60 \text{ minutes}} = 8.97 \text{ hours} \][/tex]

Next, we use the formula for radioactive decay:

[tex]\[ N(t) = N_0 \left( \frac{1}{2} \right)^{\frac{t}{t_{1/2}}} \][/tex]

Plug in the values:

[tex]\( N_0 = 344 \text{ g} \)[/tex][tex]\( t = 8.97 \text{ hours} \)[/tex][tex]\( t_{1/2} = 26.0 \text{ hours} \)[/tex]

Calculate the fraction of the substance remaining after 8.97 hours:

[tex]\[ N(t) = 344 \left( \frac{1}{2} \right)^{\frac{8.97}{26.0}} \][/tex]

First, compute the exponent:

[tex]\[ \frac{8.97}{26.0} \approx 0.344 \][/tex]

Now calculate the remaining mass:

[tex]\[ N(t) = 344 \left( \frac{1}{2} \right)^{0.344} \][/tex]

[tex]\[ N(t) = 344 \times 0.786 \][/tex]

[tex]\[ N(t) \approx 270.38 \text{ g} \][/tex]

So, the mass of [tex]\(\text{As-76}\)[/tex] remaining after 538 minutes is approximately [tex]\( 270.38 \text{ g} \).[/tex]

4). How does the Stoichiometry of a reaction (balanced equation) affect reaction Rate?


Answers

The stoichemistry is to do with the conservation of mass in a chemical reaction so that the mass of the reactants equals the mass of the products. The reaction rate will be affected in such a way that the reaction will proceed at such a rate as required to produce an equal  amount of product so that as the product amount approaches the reactant amount then the rate of the reaction should slow down.

Which agency publishes the food code

Answers

Food code is like sort of a guide to ensure that the food is presented according decent standards, unadulterated and correctly presented to the customer.
It is published every four years by the " U.S Food and Drug Administration".

Final answer:

The United States Food and Drug Administration (FDA) publishes the food code, providing guidelines and regulations for safe food handling and production.

Explanation:

The agency that publishes the food code is the United States Food and Drug Administration (FDA). This agency issues codes that regulate the production, handling, and sale of food in the United States. Details about harmful microorganisms found in food and related aspects are also released by the FDA, as shown in their 'Bad Bug Book'.

The FDA's food codes serve as a model and guide for strengthening food safety by detailing specific procedures and practices required to prevent foodborne illnesses. Different from USDA, which conducts research and provides data on food and nutrition, the FDA directly oversees the food safety and integrity. Thus, when it comes to food code, the FDA should be the top-priority source.

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At what temperature will 0.100 molal (M) NaCl(aq) boil?
Kb= 0.51 C kg mol^-1

Answers

The increase of the boling point of a solution is a colligative property.

The formula for the increase of the normal boiling point of water is:

ΔTb = Kb * m

Where m is the molallity of the solution and Kb is the molal boiling constant in °C/mol.

ΔTb = 0.51 °C / m * 0.100 m = 0.051 °C.

So, the new boiling temperature is Tb = 100°C + 0.051°C = 100.051 °C.

Answer: 100.051 °C

Which of these are equal to 6.02 x 1023 particles?

12.01 g carbon (C)

44.08 g of silicon dioxide (SiO2)

16 g of ozone (O3)

16.04 g of carbon tetrahydride (CH4)

Answers

16.04 g of carbon tetrahydride (CH4) and 12.01 g carbon (C)

Answer:

Carbon and carbon tetrahydride (methane).

Explanation:

Hello,

In this case, it is not necessary to compute the particles for all the given masses, it is enough by knowing each substance's moles by knowing their molar mass and subsequently proof they equals 1 mole as long as 1 mole equals 6.022x10²³ which is the Avogadro's number; in such a way, the molar masses are:

[tex]M_C=12.01g/mol\\M_{SiO_2}=60.08g/mol\\M_{O_3}=48g/mol\\M_{CH_4}=16.04g/mol[/tex]

Therefore, the two cases are carbon and carbon tetrahydride or methane as shown below:

[tex]ParticlesC=12.01gC*\frac{1molC}{12.01gC}*\frac{6.022x10^{23}particlesC}{1molC} =6.022x10^{23}particlesC\\ParticlesCH_4=12.01gCH_4*\frac{1molCH_4}{12.01gCH_4}*\frac{6.022x10^{23}particlesCH_4}{1molCH_4}=6.022x10^{23}particlesCH_4[/tex]

Best regards.

Which is an endothermic process?


the process in which a substance loses heat energy



the process in which a substance loses kinetic energy



the process in which the molecular motion of a substance decreases



the process in which a substance gains energy


Answers

Answer: Option (d) is the correct answer.

Explanation:

Endothermic process is a process in which energy or heat is absorbed by reactant species.

For example, melting of ice cubes is an endothermic process as it is absorbing heat from the surrounding and gives a cooling effect.

Thus, we can conclude that the process in which a substance gains energy is an endothermic process.

Answer:

The process in which a substance gains energy.

Explanation:

In an endothermic process, a system absorbs energy from the surroundings, therefore increasing its internal energy.

Which is an endothermic process?

the process in which a substance loses heat energy. NO. This is an exothermic process because energy is transferred from the system to the surroundings.the process in which a substance loses kinetic energy. NO. According to the Law of Conservation of Energy, the total energy of an isolated system remains constant, that is, it cannot be created nor destroyed, only transferred and transformed from one form to another. In this case, kinetic energy lost by the substance is gained by the surroundings, so it is an exothermic process.the process in which the molecular motion of a substance decreases. NO. This is connected to the previous option. If molecular motion decreases it is because kinetic energy is being lost and transferred to the environment, in an exothermic process.the process in which a substance gains energy. YES. This coincides with the definition of an endothermic process.

Write the net ionic equation for the equilibrium that is established when potassium hypochlorite is dissolved in water.

Answers

Final answer:

When potassium hypochlorite is dissolved in water, it dissociates into potassium ions and hypochlorite ions. Thus, the net ionic equation for this process is: KClO(s) -> K+(aq) + ClO-(aq).

Explanation:

The net ionic equation represents the actual reaction happening in solution, excluding the spectator ions. When potassium hypochlorite (KClO) is dissolved in water, it dissociates completely into potassium ions (K+) and hypochlorite ions (ClO-).

So, the complete ionic equation is: KClO(s) -> K+(aq) + ClO-(aq).

The net ionic equation is the same as the complete ionic equation because there are no spectator ions in this case. Thus, the net ionic equation for the equilibrium that is established when potassium hypochlorite is dissolved in water is: KClO(s) -> K+(aq) + ClO-(aq)

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The net ionic equation for the equilibrium established when potassium hypochlorite dissolves in water involves only the hypochlorite ion reacting with water to form hypochlorous acid and hydroxide ion.

When potassium hypochlorite (KClO) is dissolved in water, it dissociates into potassium (K+) ions and hypochlorite (ClO-) ions.

Potassium is a spectator ion and does not participate in the equilibrium reaction that is established in the solution. Therefore, the net ionic equation for the equilibrium when potassium hypochlorite is dissolved in water only involves the hypochlorite ion and water.

The equation is as follows:

ClO-(aq) + H2O(l) ---> HClO(aq) + OH-(aq)

This equation represents the equilibrium between the hypochlorite ion and the hypochlorous acid and hydroxide ion in aqueous solution.

Compute the mass percent of carbon, hydrogen, nitrogen, and oxygen in caffeine, C8H10N4O2

Answers

Molar mass of caffeine: 194

Carbon percentage: 12*8 / 194 = 49%

Hydrogen: 10 / 194 = 5%

Nitrogen: 14*4 / 194 = 29%

Oxygen: 16*2 / 194 = 16%
mass percentage of C = 49.48%
mass percentage of H =5.19%
mass percentage of N =28.86
mass percentage of O = 16.48

If δh°rxn and δs°rxn are both positive values, what drives the spontaneous (favored) reaction and in what direction at standard conditions?

Answers

Final answer:

If δh°rxn and δs°rxn are both positive values, the reaction is spontaneous and favored at standard conditions.

Explanation:

If δh°rxn and δs°rxn are both positive values, the reaction is spontaneous and favored at standard conditions. This is because a positive value of δh°rxn indicates an exothermic reaction, releasing energy, while a positive value of δs°rxn indicates an increase in disorder or randomness, which is favorable for a reaction to occur. Therefore, both factors - the release of energy and the increase in disorder - drive the reaction in the forward direction.

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Which process does not involve a chemical change? 1. cleaning the shower with lime away 2. burning charcoal on the grill 3. boiling water 4. digesting food?

Answers

3. Boiling water is just a physical change because the only change is in the state of matter and not in the chemical structure of the water.

H2O(l)-->H2O(g)

Final answer:

Boiling water does not involve a chemical change, unlike cleaning the shower with lime away, burning charcoal on the grill, and digesting food.

Explanation:

The process that does not involve a chemical change is boiling water.

Boiling water is a physical change because it does not result in the formation of new substances. When water is boiled, it changes from a liquid to a gas, but the chemical composition of water remains the same.

On the other hand, cleaning the shower with lime away, burning charcoal on the grill, and digesting food all involve chemical changes. Cleaning the shower with lime away involves a chemical reaction to remove lime deposits. Burning charcoal on the grill involves the combustion of carbon compounds. Digesting food involves the breakdown of complex molecules into simpler ones by enzymes in the digestive system.

The equilibrium constant, kp, equals 3.40 at 25°c for the isomerization reaction: cis-2-butene ⇌ trans-2-butene. if a flask initially contains 1.00 atm of each gas, in what direction will the system shift to reach equilibrium?

Answers

Answer:

The reaction will proceed to the right (favoring the products).

Explanation:

Let's consider the following isomerization reaction.

cis-2-butene ⇌ trans-2-butene

To predict in what direction will shift to reach equilibrium, we have to calculate the reaction quotient (Qp).

[tex]Qp=\frac{p(trans-2-butene)}{p(cis-2-butene)} =\frac{1.00}{1.00} =1.00[/tex]

Since Qp (1.00) < Kp (3.40), the reaction will proceed to the right, so that the pressure of the product increases, the pressure of the reactant decreases, and Qp reaches the value of Kp.

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly. In order to get the best results, the student should: A.keep the temperature of the water constant for all three trials B.repeat each trail multiple times C.use the same water container for all three trails D.all of above

Answers

the answer is d all of the above

Answer:

All of the above.

Explanation:

The stirring provides an aid to dissolve. So as compared to a not stirred solution the stirred and vigorously stirred solution will show rapid and more solubility of salt.

In order to study any phenomenon or an experiment we should perform the experiment with same conditions in all the trials. It minimizes the errors.

so we have to keep temperature constant, and the same water container in all the three trials. It gives accuracy to the result

Now the repetition is again required but for precision.

The solute dissociates slightly in the solvent. how will the slight dissociation affect the reported

Answers

The solute dissociates slightly in the solvent. The slight dissociation can be shown can be shown in the solubility product constant. An example is when the reported If a cell is placed inside a solution that has a higher concentration of solute than on the inside of the cell, the movement of water will move out of the cell, causing it to shrivel. The movement is affected on how much concentration is with the system and surrounding. It moves from a higher concentration to a lower concentration of solute. 

What does it mean for a weak acid to be in equilibrium?

A) The acids only slightly dissociate and readily undergo reverse reaction.

B)The position of equilibrium in weak acids lies more to the right than to the left.

C)At equilibrium there is a small amount of HA and more A- and H+

D) At equilibrium there is the same amount of HA, A- and H+

Answers

A) The acids only slightly dissociate and readily undergo reverse reaction.

for example:

acetic acid
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq)

nitrous acid
HNO₂(aq) ⇄ H⁺(aq) + NO₂⁻(aq)

carbonic acid
H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq)
HCO₃⁻(aq) ⇄ H⁺(aq) + CO₃²⁻(aq)

What is the effect of an insoluble impurity, such as sand, on the observed melting point of a compound?]?

Answers

The effect of an insoluble impurity, such as sand, on the observed melting point of a compound would be none. It will not depress or elevate the melting point of the compound. Instead, it would affect the reading if you are trying to determine the melting point of the compound. This is because you might be missing  the actual melting point of the compound since you will be waiting for the whole sample to liquify. You would not be able to determine exactly that temperature because of the insoluble impurity would have a different melting point than that of the compound.

Final answer:

The presence of an insoluble impurity such as sand in a compound causes a lower observed melting point and a broader melting range, known as melting point depression. The impurity disrupts the crystal lattice, lowering the energy required for the substance to melt, and physically hinders a uniform melting process.

Explanation:

Effect of Insoluble Impurities on Melting Point

The presence of an insoluble impurity, such as sand, in a compound can alter its melting point. Typically, the observed melting point of a compound with impurities is lowered and the range over which melting occurs is broadened. This phenomenon is known as melting point depression, which is akin to freezing point depression. The introduction of an insoluble impurity disrupts the orderly crystal lattice of a pure substance, thereby requiring less energy to break the intermolecular forces among the molecules when heat is applied. Consequently, the substance starts to melt at a lower temperature.

When a compound undergoes melting, impurities like sand do not integrate into the crystal lattice. Instead, they remain as separate entities. As the majority component (for instance, a pure chemical) begins to melt, it may form small pools of liquid, which do not contain the impurity. Since the sand is insoluble, it doesn't contribute to the solution phase and hence doesn't affect the liquid's composition or properties directly. However, the presence of the sand broadens the range over which the compound melts because it can physically hinder the melting process. This leads to a melting range rather than a sharp melting point.

In practice, the presence of impurities can be identified by a melting point that is lower than expected for the pure compound and by a broader range of temperatures over which melting occurs, which is indicative of a less pure substance. Such a broad range is due to the impure solid melting at various temperatures, influenced by the amount and distribution of the impurity.

The ka value for acetic acid, ch3cooh(aq), is 1.8Ã 10â5 m. calculate the ph of a 1.40 m acetic acid solution.

Answers

1) Equlibrium reaction

CH3COOH (aq) = CH3COO(-) (aq) + H(+) (aq)

2) Equilibrium constant

Keq = Ka = [CH3COO-] [H+] / [CH3COOH]

3) Equilibrium concentrations

                  CH3COOH      CH3COO-     H+

start               1.40                  0              0
react                  x                   0              0
produced           0                   x              x

equilibrium     1.40 - x            x               x

=> Ka = x * x / (1.40 - x)

Approximation: given that Ka is very small x <<< 1,40 and 1.40 - x  ≈ 1.40

=> Ka ≈ x^2 / 1.40

=> x^2 ≈ 1.40Ka = 1.40 * 1.8 * 10^ - 5 = 2.52 * 10^-5

=> x ≈ √(2.52 * 10^-5) ≈ 5.02 * 10^ -3 M

4) pH = log 1 / [H+]

[H+] = x = 5.02 * 10^-3M

=> pH ≈ log (1 / 5.02 * 10^-3) ≈ 2.3

Answer: 2.3

Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?

Answers

Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr

What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP?

Answers

The general gas law equation that is formed by combining the three laws of Boyle, Charle and Guy Lussac is written as:
(PV/T)1 = (PV/T)2
STP conditions means that T= 273 kelvin and P = 1 atmospheric pressure
Based on the above rule, we calculate V2 as follows:
(4.25*55)/500 = (1*V)/273
V2 = 127.599 liters

Extra notes:
Boyles law: volume and pressure of a certain mass of gas are inversely proportional provided that the temperature is constant
Charle's law: volume and temperature of a certain mass of gas are directly proportional provided that the pressure is constant
Guy Lussac's law: pressure and temperature of a certain mass of gas are directly proportional provided that the volume is constant

How many milliliters of 0.100 m naoh are needed to neutralize 50.00 ml of a 0.150 m solution of acetic acid (ch3cooh), a monoprotic acid?

Answers

The neutralization reaction is

NaOH + CH3COOH = Na(+) + CH3COO(-) + H2O

At the neutralization point all the CH3COOH will have reacted, so you are only interested in the reactant ratio:

1 mol of NaOH reacts with 1 mol of CH3COOH.

The formula of molarity is M = n / V => n = M*V

=> M1 * V1 = M2 * V2 => V2 = M1 * V1 / M2

=> V2 = 50.00 ml * 0.150 M / 0.100 M = 75 ml

Answer: 75 ml

Note: M1 = 50.00 ml

          V1 = 0.150 M

         M2 = 0.100 M

Asked: V2?

Answer: First, first realize the reaction:

               NaOH + CH3COOH = Na (+) + CH3COO (-) + H2O

              Second, enter all known numbers into the molarity formula:

                M = n / V

                 n = M * V

                M1 * V1 = M2 * V2

                V2 = M1 * V1 / M2

                V2 = 50.00 ml * 0.150 M / 0.100 M

                V2 = 75 ml

So, the NaOH needed to neutralize 50.00 ml of a solution of 0.1150 m of acetic acid (ch 3 co) is 75 ml.

Further Explanation

In chemistry, molarity (abbreviated M) is one measure of the concentration of the solution. The molarity of a solution expresses the number of moles of a substance per liter of solution. For example, 1.0 liter of solution contains 0.5 mol of compound X, so this solution is called a 0.5 molar (0.5 M) solution. Generally, the concentration of aqueous aqueous solutions is expressed in molar units. The advantage of using molar units is the ease of calculation in stoichiometry because the concentration is expressed in moles (proportional to the actual number of particles). The disadvantage of using this unit is inaccuracy in volume measurement. Also, the volume of a liquid changes with temperature, so the molarity of the solution can change without adding or reducing any substances. Also, in a solution that is not very thin, the molar volume of the substance itself is a function of concentration, so the molarity-concentration relationship is not linear.

A neutralization reaction is a reaction where acids and bases react in aqueous solution to produce salt and water. The liquid sodium chloride that is produced in a reaction is called salt. Salt is an ionic compound consisting of cations from bases and anions from acids. Salt is an ionic compound that is not an acid or a base.

Strong-base Strong Acid Reaction

When the same amount of strong acid such as hydrochloric acid is mixed with a strong base such as sodium hydroxide, the result is a neutral solution. The reaction product does not have the characteristics of either acid or base.

Reactions Involving Weak Acids or Weak Bases

Reactions where at least one component is weak generally do not produce a neutral solution.

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Grade: College

Subject: Chemistry

keywords: molarity

find the midpoint of AB if A(-3,8) and B(-7,-6)

Answers

In order to determine the coordinates of a midpoint, the formula used is:

M(x,y) = ((x₁+x₂)/2 , (y₁+y₂)/2)

Plugging in the values from the given points,

M(x,y) = ((-3-7)/2 , (8-6)/2)

M(x,y) = (-5 , 1)

The coordinates of the midpoint are (-5,1)

The midpoint of AB is (-5,1), if A(-3,8) and B(-7,-6).

How to find out the midpoint of coordinates?

The midpoint of coordinates is found by measuring the distance between two endpoints and dividing the obtained result by 2. Apart from this, one more method is there which is to add the two X-coordinates of the endpoints and divide them by 2. The same concept is applied to the Y-coordinates as well.

According to the question,

A = (-3,8) and B = (-7,-6).

The formula is as follows:

M(x,y) = ((x₁+x₂)/2 , (y₁+y₂)/2).

Putting the above values in the mentioned formula, we get:

M(x,y) = ((-3-7)/2 , (8-6)/2).

M(x,y) = (-5 , 1).

Therefore, the midpoint of AB is (-5,1), if A(-3,8) and B(-7,-6).

To learn more about the Midpoint of coordinates, refer to the link:

https://brainly.com/question/28308761

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How many carbon atoms are in the longest chain?

Answers

 The answer is 9. The \ / and | are my best representations of the c-c bonds in yahoo. 
Start your numbering from the long chain neartest the bottom of the page and it goes like this: 
1 is very start( the furthest down carbon) 
2 is the only carbon connected to the first carbon \ 
3 is the only carbon connected to the second carbon | 
4 is the only carbon connected to the third carbon \ 
5 is the carbon chain pointing up | 

Then start going right. 
6 is the carbon to the right of 5 / 
7 is the carbon to the right of 6 \ 
8 is the carbon to the right of 7 / 
9 can be either of the 2 single lines coming off of 8( it doesn't matter which one because each will result in a carbon bond with a methyl bond off of it) 

That is all there is too it. My guess is that this is what you did when you got 8 but you forgot to count the very first carbon. I hope this helps.

The surface areas of four solutes are 2 mm2, 6 mm2, 10 mm2, and 4 mm2. Which solute will dissolve the quickest?

A) 2 mm2
B) 4 mm2
C) 6 mm2
D) 10 mm2

Answers

Your answer is D) 10 mm2

The answer is D.

10 mm2

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