To rent a certain meeting room, a college charges a reservation fee of $37 and an additional fee of $5.70 per hour. The chemistry club wants to spend less than $59.80 on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room? Use t for the number of hours the meeting room is rented, and solve your inequality for t

Answers

Answer 1

Answer: t < 4  hours

Step-by-step explanation:

Renting = $37 + t x $5.70

If $37 + t$5.70 < $59.80

t$5.70 < $59.80 - $37  

t$5.70 < $22.80

t < $22.80/$5.70  

t < 4 hours

[tex]\textit{\textbf{Spymore}}[/tex


Related Questions

Which equation has the same solution as this equation? x^2-16x+12=0

Answers

Final answer:

Another equation that shares the same solutions as x²-16x+12=0 is 2x² - 32x + 24 = 0. This equation is the initial equation multiplied by 2 and thus would produce the same solutions when the quadratic formula is applied.

Explanation:

The equation given is a quadratic equation, which is in the form ax²+bx+c = 0. The solutions of a quadratic equation are given by the formula: -b ± √b² - 4ac / 2a. This formula can be used to find the solutions of any other quadratic equation. For the given equation, x²-16x+12=0, the values of a, b, and c are 1, -16, and 12 respectively. So, another equation with the same solutions could be 2x² - 32x + 24 = 0. This equation has the same solutions because it's simply the initial equation multiplied by 2, so this doesn't change the results of the quadratic formula.

Learn more about Quadratic Equations here:

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Convert theta= 3pi/4 to rectangular form.
A. y= -1
B. y= 1
C. y= x
D. y= -x
E. x= -1

Answers

[tex]\theta=\dfrac{3\pi}{4}=\pi-\dfrac{\pi}{4}\\\\y=\tan\theta x\\\\y=\left(\tan\dfrac{3\pi}{4}\right)x\\\\y=\left(\tan\left(\pi-\dfrac{\pi}{4}\right)\right)x\\\\y=\left(\tan\left(-\dfrac{\pi}{4}\right)\right)x\\\\y=\left(-\tan\dfrac{\pi}{4}\right)x\\\\y=-1x\\\\\boxed{y=-x}\to\boxed{D.}[/tex]

Answer:

If you are doing it on edge it is x+y=0

Step-by-step explanation:

x+y=0 when you solve for y it equals -x( y=-x)

Quinn is twice as old as karl and four years older than parker. The sum their ages is 21. How old is Parker

Answers

Answer:

Parker is 6 years old

Step-by-step explanation:


Answer:

Parker is 6 years old

Step-by-step explanation:

Let q, p, k represent the ages of Quinn, Parker, and Karl, respectively.

... q = 2k . . . . . . Quinn is twice as old as Karl

... q = p+4 . . . . . Quinn is 4 years older than parker

... q + p + k = 21 . . . . the sum of their ages is 21

_____

We can use the first two equations to find Karl's age in terms of Parker's.

... p+4 = q = 2k

... (p+4)/2 = k

Now, we can substitute for q and k in the last equation.

... (p+4) +p +(p+4)/2 = 21

... 5/2p +6 = 21 . . . . . . collect terms

... p = (2/5)(21 -6) . . . . subtract 6, multiply by 2/5

... p = 6 . . . . . . Parker is 6 years old

How much of the 8% solution should we use to make 100g of a 3% solution?
This is all I have don't ask me any questions I don't know anything else about this

Answers

Answer:

37.5 g

Step-by-step explanation:

The final solution will contain 3% × 100 g = 3 g of solute. This amount of solute will be found in w grams of 8% solution, where ...

... 3 = 0.08 × w

... 3/0.08 = w = 37.5 . . . . . grams of 8% solution

Answer:

37.5 grams

Step-by-step explanation:

;)

A rectangle has a length of 4 inches and a width of x inches. The value of the perimeter of the rectangle is equal to the value of the area of the rectangle. What is the value of x?

Answers

Final answer:

To find the value of x in a rectangle with a length of 4 inches, set up the equation 2(4 + x) = 4x and solve for x. The value of x is 4 inches.

Explanation:

To find the value of x, we need to set up an equation using the given information. The perimeter of a rectangle is equal to twice the length plus twice the width. The area of a rectangle is equal to the length times the width. So, we can set up the equation: 2(4 + x) = 4x. Next, solve the equation for x:

8 + 2x = 4x

8 = 4x - 2x

8 = 2x

4 = x

Therefore, the value of x is 4 inches.

If GF is a midsegment of CDE, find CD.

A. 3.4

B. 6.8

C. 13.6

D. 14

Answers

Answer:

C


Step-by-step explanation:

Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:

[tex]\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}[/tex]

We can now cross multiply and solve for CD:

[tex]\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}[/tex]

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

[tex]CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0[/tex]

By using quadratic formula [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex] and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:

[tex]\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2[/tex]


Since the expression for CD is [tex]\frac{15x^2+16x+3.2}{2x+3}[/tex] , we plug in [tex]x=2[/tex] into this expression to find value of CD:

[tex]\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6[/tex]

The correct answer is C

Answer:

C. 13.6

Step-by-step explanation:

We have been given that GF is a mid-segment of CDE.

Since we know that mid-segment of a triangle is half the length of its parallel side.

We can see that ED is parallel to GF , so measure of GF will be half the measure of ED. We can represent this information as:

[tex]GF=\frac{1}{2}ED[/tex]

Let us substitute given value of GF and ED to find our x.

[tex]2x+3=\frac{1}{2}(5x+4)[/tex]

Multiply both sides of equation by 2.

[tex]2*(2x+3)=2*\frac{1}{2}(5x+4)[/tex]

[tex]2*(2x+3)=5x+4[/tex]

[tex]4x+6=5x+4[/tex]

[tex]6=5x+4-4x[/tex]

[tex]6=x+4[/tex]

[tex]6-4=x[/tex]

[tex]2=x[/tex]

We can see that triangle CFG is similar to triangle CDE, so we will use proportions to find length of CD.

[tex]\frac{CF}{GF}=\frac{CD}{ED}[/tex]

Substitute given values.

[tex]\frac{3x+0.8}{2x+3}=\frac{CD}{5x+4}[/tex]

Upon substituting x=2 in our equation we will get,

[tex]\frac{3*2+0.8}{2*2+3}=\frac{CD}{5*2+4}[/tex]

Let us simplify our equation.

[tex]\frac{6+0.8}{4+3}=\frac{CD}{10+4}[/tex]

[tex]\frac{6.8}{7}=\frac{CD}{14}[/tex]

[tex]14*\frac{6.8}{7}=CD[/tex]

[tex]2*6.8=CD[/tex]

[tex]13.6=CD[/tex]

Therefore, CD equals 13.6 and option C is the correct choice.

For what values of x does the following hold true:
a. (5x+3)^2=5(x+3)
b. (3x+10)^2=3(x+10)
c. (3x−8)^2=3x^2−8x

Answers

Answer:

a. x ∈ {-1.2, 0.2}

b. x ∈ {-4 2/3, -1 2/3}

c. x ∈ {2 2/3, 4}

Step-by-step explanation:

For this sort of exercise, I find a graphing calculator to be very handy. While the one shown in the attachment (Desmos) can solve the equation as written, I find it convenient to recast the equation to the form f(x) = 0. The calculator finds the values of zero crossings very nicely. Some, like my TI-84, will show the value to 8 or 10 significant digits. Here, 4 digits is sufficient to determine the exact solution.

_____

If you want to work these by hand, you rewrite them to standard form, then use factoring, completing the square, or the quadratic formula to solve them.

a. 25x² +30x +9 -5x -15 = 0 . . . . subtract the right side

... 25x² +25x -6 = 0 . . . . . . . . . . . collect terms

... (5x+6)(5x-1) = 0 . . . . . . . . . . . . . factor (the graphing calc helps here)

... x = -6/5, 1/5

b. 9x² +60x +100 -3x -30 = 0 . . . . subtract the right side

... 9x² +57x +70 = 0 . . . . . . . . . . . . collect terms

... (3x +14)(3x +5) = 0 . . . . . . . . . . . factor

... x = -14/3, -5/3

c. 9x² -48x +64 -3x² +8x = 0 . . . . . subtract the right side

... 6x² -40x +64 = 0 . . . . . . . . . . . . collect terms

... 3x² -20x +32 = 0 . . . . . . . . . . . . factor out 2

... (3x -8)(x -4) = 0 . . . . . . . . . . . . . . factor

... x = 8/3, 4

A plant has a initial height of 1 inch and grows at a constant rate of 3 inches each month. A second plant that also grows at a constant rate has an initial height of 4 inches and is 28 inches taller after 1 year. After how many months are the plant the same height?

Answers

3 months, I remember a question like this awhile back.


Answer: that would be 3 months.

Step-by-step explanation:

Eric is 6 1/6 feet tall and his brother is 5 3/4 feet tall. Eric is how many feet taller than his brother?

A. 1/5 feet

B. 5/12 feet

C. 7/12 feet

D. 3/4 feet

Answers

6 1/6
5 3/4
=
6x6+1= 37
5x4+3=23
having a total when subtracted of 14 divide that by the both of them so 7. I'm gonna say c.

Answer:

B. 5/12 feet

Step-by-step explanation:

We know that Eric is [tex]6\frac{1}{6}[/tex] feet tall while his brother is [tex]5\frac{3}{4}[/tex] feet tall. We are supposed to find out how many feet is Eric taller than his brother.

So basically we have to find the difference between the height of the two brothers.

First, let's just change the mixed numbers to improper fractions:

[tex]6\frac{1}{6}[/tex] = [tex]\frac{37}{6}[/tex]

[tex]5\frac{3}{4}[/tex]=  [tex]\frac{23}{4}[/tex]

Now taking their difference:

[tex]=\frac{37}{6} -\frac{23}{4}\\\\=\frac{148-138}{24}\\\\=\frac{10}{24}\\\\=\frac{5}{12}[/tex]

Therefore, Eric is 5/12 feet taller than his brother.

Tiffany answered 90% of the questions on her math test correctly. There were 50 questions on the test. how many questions did Tiffany answer correctly?

Answers


Multiply the total number of questions by the percent:

50 questions x 90% =

50 x 0.90 = 45


She answered 45 questions correctly.



please help me asap!

Answers

Answer:

2968.30 cm cube.

Step-by-step explanation:

Given is a cone and top of it is a hemisphere of radius 9 cm.

Cone has height as 17 and radius same 9 cm.

We have to find the volume of the compound shape

We find that the volume would be the sum of that of hemisphere of radius 9 cm and cone of height 17, and radius 9 cm.

Volume of compound shape = volume of cone+Volume of hemisphere

= [tex]\frac{1}{3} \pi r^{2} h+\frac{2}{3} \pi r^{3}[/tex]

substitute for h and r in the equation

Required volume =

[tex][tex]\frac{1}{3}\pi  r^{2} (h+2r) = \frac{1}{3}\pi  9^{2} (17+2(9))\\= 1441.99+1526.31\\=2968.30[/tex][/tex]

So answer is 2968.30 cm cube.

=


As a promotion, a clothing store draws the name of one of its customers each week. The prize is a coupon for the store. If the winner is not present at the drawing, he or she cannot claim the prize, and the amount of the coupon increases for the following week's drawing. The function f(x) = 20 (1.2)^x gives the amount of the coupon in dollars after x weeks of the prize going unclaimed. {{ x is the exponent on (1.2). }}

(A) What is the percent increase each week?

(B) What is the original amount of the coupon? (the initial value)

(C) What is the amount of the coupon after 2 weeks of the prize going unclaimed?

(D) After how many weeks of the prize going unclaimed will the amount of the coupon be greater than $100?

Answers

The given formula is f(x) = 20(1.2)^x

The formula is the starting amount multiplied by 1 + the percentage raised to the number of weeks.


A) the percent increase is 20% ( 1.2 in the formula is 1 +20% as a decimal)

B) the original amount is $20

C) for 2 weeks, replace x with 2 and solve:

20(1.2)^2

20(1.44) = $28.80

After 2 weeks the coupon is $28.80

D)  To solve for the number of weeks (x) set the equation equal to $100:

100 = 20(1.2)^x

Divide both sides by 20:

5 = 1.2^x

Take the natural logarithm of both sides:

ln(5) = ln(1.2^x)

Use the logarithm rule to remove the exponent:

ln(5) = x ln(1.2)

Divide both sides by ln(1.2)

x = ln(5) / ln(1.2)

Divide:

X = 8.83

At 8.83 weeks the coupon would be $100, so after 9 weeks the coupon would be greater than $100

The answer is 9 weeks.

The amount, A, in milligrams, of radioactive material remaining in a container can be modeled by the exponential function A(t)=5(0.5)^0.25t where T is time, in years. Based on this model how many years does it take for half of the original radioactive material to be left remaining?

Answers

Answer:

4 years

Step-by-step explanation:

The exponent of 0.5 is 1 when t=4. So, half the original amount will be remaining when t=4.

A local garden club had 14 members with a mean age of 34. Then two new members joined. One was 24 years old, and the other was 36 years old. How did the mean age change after they joined? The mean age increased. The mean age decreased. It isn't possible to determine how the mean would change. The mean age stayed the same.

Answers

Answer:

The mean age decreased.

Step-by-step explanation:

I find it convenient to look at the additions with respect to the current mean age.

The current total age is 14×34. We have added members with ages (34 -10) and (34 +2), so the new total age is ...

... (34×14) + (34 -10) + (34 +2) = (16×34) - 8

Dividing this total by 16 will give the new mean age. (We already know it is less than 34.)

... ((16×34) -8)/16 = 34 - 1/2 = 33 1/2 . . . new mean age; a decrease

Math true or false

Septima investing money into two different accounts at the same time. the system of inequalities represent the balance of each account where x represents the number of years the money has been invested.
Math! Please help! Please explain your answers.

Answers

Answer:

FalseFalseTrue

Step-by-step explanation:

Since the given expression represents the account balance, the initial amount (when x=0) is $500 in Account A, and $100 in Account B. (Less money was invested in account B.)

The growth rate of each account is $1.03 per year.* (The growth rate ($/year) is identical for each account.)

The total of the initial amounts invested is $500 +100 = $600.

_____

* Comment on growth rate

Since the account balance is shown as greater than or equal to the given expression, there appears to be the possibility that adjustments are made to the account balance by some means other than the growth predicted by this inequality. For example, if the balance in Account A is $900 at the end of 1 year, the inequality will still be true, but the extra $398.97 will be in addition to the $1.03 growth predicted by this expression.

This means we really cannot say what the growth rates of the accounts might be, except that it is a minimum of $1.03 per year in each account.

_____

Comment on the expressions

More usually, we would expect to see an account balance have the equation a = 400·1.03^x. That is, the interest rate would be 3% and it would be compounded annually. The expression 400 + 1.03x is very unusual in this situation.

Which relation is displayed in this table? x y

5 5

A. {(5,  5), (6,  −6), (8,  7), (−9,  9)} 8 7

6 -6

-9 9

B. {(5,  5), (−6,  6), (7, 8), (9,  −9)}



C. {(−5,  5), (−6,  6), (−8,  7), (−9,  9)}



D. {(5, −5), (6, −6), (8, −7), (9, −9)}

Answers

Answer:

A. {(5,  5), (6,  −6), (8,  7), (−9,  9)}

Step-by-step explanation:

Compare the table contents to the ordered pairs in each relation. The first pair of table values, (5, 5) matches relations A and B, but not C or D.

The second pair of table values (8, 7), matches relation A, but not B. Since all pairs of table values show up in relation A, and we have rejected relations B, C, and D as inappropriate choices, the answer is A.

Ming is given the following function and asked to find b. f(x)=15(b)x If f(4) = 1215, what is one possible value of b?

Answers

Step-by-step explanation:

f(x) = 15(b)x

f(4) = 1215

15(b)4 = 1215

(15)(4)b = 1215

60b = 1215

60b / 60 =  1215 / 60

b = 20.25

Check the answer

15 * 20.25 * 4 = 1215

Answer:

3

Step-by-step explanation:

if you did this on prepworks its 3.

1215=15(b)4  

121515=(b)4

81=b4

92=b4

(32)2=b4

34=b4

b = ±3

Ralph wants to purchase a renters insurance policy for his new apartment. His insurance company charges an annual premium of 16.53% of the approximate value of the items he owns and is keeping in his apartment. Below is a list of items Ralph made of the items he has in his apartment that he would like to be insured with his policy. What will Ralph’s annual renters insurance premium be? Ralph's Stuff Value TV $150 VCR $60 DVD Player $100 Stereo $80 Sofa $200 Entertainment Center $100 Microwave $40 Coffee Maker $20 Computer $850 Bicycle $200 Coin Collection $600 Pictures/Posters $175 a. $17.88 b. $35.48 c. $214.58 d. $425.65 Please select the best answer from the choices provided A B C D Mark this and return

Answers

Answer:

d. $425.65

Step-by-step explanation:

The total value of Ralph's stuff is ...

... 150 + 60 + 100 + 80 + 200 + 100 + 40 + 20 + 850 + 200 + 600 + 175 = 2575

The premium is 16.53% of that, so is ...

... 0.1653 × 2575 = 425.65

Answer:

The insurance company charges an annual premium of $425.65 .

Option (d) is correct .

Step-by-step explanation:

As given

Ralph wants to purchase a renters insurance policy for his new apartment.

His insurance company charges an annual premium of 16.53% of the approximate value of the items he owns and is keeping in his apartment.

Total amount of the items he owns and is keeping in his apartment = TV cost + VCR cost + DVD Player cost + Stereo cost + Sofa cost + Entertainment centre cost  +  Microwave cost + Coffee Maker cost +  Computer cost + Bicycle cost  +  Coin Collection cost  + Pictures/Posters cost

Putting all the values in the above

Total amount of the items he owns and is keeping in his apartment = $150 + $60 +$100 + $ 80 + $200 + $100 + $40 + $20 + $850 + $ 200 + $ 600 + $ 175

Total amount of the items he owns and is keeping in his apartment = $ 2575

16.53 % is written in the decimal form .

[tex]= \frac{16.53}{100}[/tex]

= 0.1653

Insurance company charges an annual premium = 0.1653 × Total amount of the items he owns and is keeping in his apartment .

                                                                                   = 0.1653 × 2575

                                                                                   = $ 425.65 (Approx)

Therefore the insurance company charges an annual premium of $425.65 .

Option (d) is correct .

In an airplane 35% of the passengers are children they’re 140 children on the airplane how many passengers are on the airplane

Answers

Answer:

there are 49 passengers

Step-by-step explanation: 35%=0.35

0.35*140= 49


Evaluate the expression 3a+2b/2 when a = -3 and =-4

Answers

3a+2b/2=3×(-3)+2×(-4/2)
=-9-4
=-13

The solution of the expression 3a+2b/2 is -13 when a = -3 and b = -4

What is the expression?

Expressions are defined as mathematical statements that have a minimum of two terms containing variables or numbers.

What are Arithmetic operations?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

The operator that performs the arithmetic operation is called the arithmetic operator.

Operators which let do a basic mathematical calculation

+ Addition operation: Adds values on either side of the operator.

For example 4 + 2 = 6

- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.

for example 4 -2 = 2

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

Given the expression as :

⇒ 3a + 2b/2

when a = -3 and b = -4

Substitute the values of a and b

⇒ 3 × (-3) + 2 × (-4/2)

⇒ -9 - 4

-13

Hence, the solution of the expression 3a+2b/2 is -13 when a = -3 and b = -4

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Three hundred people were asked to choose their favorite of the following ice cream flavors: vanilla, chocolate, or strawberry. Which of the following fractions is the best estimate for the number of people that chose vanilla?

1/3 1/4 1/10 1/2

Answers

Answer:

I believe it would still be considered 1/2

Step-by-step explanation:


Answer:

1/2

Step-by-step explanation:


What isn't the volume of the cylinder below? Radius 8 height 3

Answers

Answer: The volume is 603.19, so whichever answer doesn't equal that.


Step-by-step explanation:

V= πr^2h

V= π(8)^2(3)

V= 603.19

Volume = 192πunits³

Work is provided in the image attached.

Write the expression 2a+b in the form of a fraction with a denominator of: b

Answers

[tex]2a+b=\dfrac{2ab}{b}+\dfrac{bb}{b}=\dfrac{2ab}{b}+\dfrac{b^2}{b}=\boxed{\dfrac{2ab+b^2}{b}}[/tex]

Select Linear or Nonlinear for each function. Function Linear Nonlinear y=5x+1 y=23 y=1−2x2

Answers

The correct classification for each function is as follows:

1. [tex]\( y = 5x + 1 \)[/tex] - Linear

2. [tex]\( y = 23 \)[/tex] - Linear

3. [tex]\( y = 1 - 2x^2 \)[/tex]- Nonlinear

A linear function is one that can be written in the form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] and [tex]\( b \)[/tex] are constants, and [tex]\( x \)[/tex] is the independent variable. The graph of a linear function is a straight line.

1. For the function [tex]\( y = 5x + 1 \)[/tex], we can see that it is already in the form of a linear equation with [tex]\( m = 5 \)[/tex] and [tex]\( b = 1 \)[/tex]. Therefore, this function is linear.

2. The function [tex]\( y = 23 \)[/tex] is a constant function. Although it does not have an [tex]\( x \)[/tex] term, it can still be considered linear because it can be written as [tex]\( y = 0x + 23 \)[/tex], where the slope [tex]\( m = 0 \)[/tex] and the y-intercept [tex]\( b = 23 \)[/tex]. The graph of this function is a horizontal line, which is a special case of a linear function.

3. The function [tex]\( y = 1 - 2x^2 \)[/tex] contains an [tex]\( x^2 \)[/tex] term, which makes it a quadratic function. Quadratic functions are nonlinear because their graphs are parabolas, not straight lines. The presence of the [tex]\( x^2 \)[/tex] term means that the rate of change of [tex]\( y \)[/tex] with respect to [tex]\( x \)[/tex] is not constant, which is a key characteristic of nonlinear functions. Therefore, this function is nonlinear.

On the main street, the tourists walked for s km with a speed of v km/hour. On the side road, the tourists walked twice the distance that they covered on the main street. How much time t (in hours) did the tourists spend if it is known that on the side road they walked with a speed that was 2 km/hour less than their speed on the main road? Find t when s=10, v=6.

Answers

Answer:

6 2/3 hours

Step-by-step explanation:

We assume the time of interest is the total time spent on the main road and side road.

In each case, ...

... time = distance/speed

On the main road, ...

... tmain = s/v

On the side road, ...

... tside = (2s)/(v -2)

Then the total time spent is ...

... ttotal = tmain + tside

... = s/v + (2s)/(v -2)

For s=10 and v=6, this is ...

... ttotal = 10/6 + 2·10/(6 -2) = 5/3 + 20/4 = 5/3 + 5 . . . . hours

... ttotal = 6 2/3 hours

Answer:

6 hr 40 min

Step-by-step explanation:

Abby buys 1 sheet of stickers. 5 strips of ten and 9 singles. How many stickers did she buy?

Answers

59 stickers on one sheet

Write 2^100 as an exponent with a base of 32.

Answers

Answer:

2 is a factor 5 times

Step-by-step explanation:

2 x 2 x 2 x 2 x 2 =32

Barney works as a car salesman and earns $175 for every car that he sells. He has fixed expenses of $3100 every month. He has laid out his projected variable expenses as well as his projected car sales for the first 6 months of next year.
. EXPENSES VARIABLE                     CARS SOLD
january 2,600                                              32
feb 3,200                                                     36
march 1,600                                                   26
may 800                                                           22
which month will barney sell enough cars to pay for all his monthly expenses ?

Answers

Answer:

feb

Step-by-step explanation:

When the number of cars needed to be sold to meet fixed plus variable expenses is subtracted from the number of cars projected to be sold, the result is negative for all months listed except February. In that month, Barney covers is expenses.

We have computed ...

... (expected car sales) - (needed car sales)

where ...

... (needed car sales) = (variable expenses + fixed expenses)/(income per car sold)

For January, this calculation gives ...

... 32 - (2600 +3100)/175 = 32 -32.571 = -0.571

That is, Barney does not project he will sell enough cars to pay his January expenses.

In February, the result is 0, which means he will sell enough cars in February to pay all his monthly expenses.

△ABC @ △DEF. Find the measures of the given angles or the lengths of the given sides

BC = 3z + 2, EF = z + 6

Answers

Answer:

BC = EF = 8

Step-by-step explanation:

Assuming you mean BC ≅ EF, then ...

... 3z +2 = z +6

... 2z = 4 . . . . . . . . add -2-z

... z = 2 . . . . . . . . . divide by 2

BC = EF = 2+6 = 8

Final answer:

The question is about finding the measures of given sides and angles in similar triangles. By setting up a proportion between the given sides BC and EF, we can solve for the variable 'z'. This 'z' can then be used to find the sides and angles of the triangles.

Explanation:

In the case of the problem, we're dealing with the concept of similar triangles in geometry. Since △ABC is similar to △DEF, this means that the corresponding sides are in proportion, and corresponding angles are equal.

Given that BC = 3z + 2 and EF = z + 6, we can write a proportion: BC/EF = 3z+2 / z+6, because the lengths of the corresponding sides of these two similar triangles should be in ratio.

Then you can solve this equation for the variable 'z', which will give us the values for sides BC and EF. If necessary,  you can also find the measure of the angles using the values of 'z'.

Learn more about Similar triangles here:

https://brainly.com/question/32489731

#SPJ2

I forgot how to this can someone help please

Answers

Answer:

1728

Step-by-step explanation:

You could write it like this

5.4 * 10^5 * 3.2 * 10^-3  

You could do this by multiplying the numbers first

5.4 * 3.2 = 17.28

Now work with the powers of 10

10^5 * 10^-3 = 10^(5 - 3) = 10^2

10^2 = 100

So the answer is 17.28 * 100 = 1728

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