To determine the density of an object, which set of instruments would be helpful?

Answer:

g/cm^3

Explanation:

grams is the unit of mass and cm cubed is the unit of volume.

the equation for density is mass over volume (d=m/v)

Answer:

D. a control or constant

Explanation:

Just took it

The amount of water given to each plant would be considered an independent variable. Therefore option C is correct.

An independent variable is a factor that the researcher deliberately manipulates or changes in an experiment to observe its effect on the dependent variable.

In this case, the independent variable is the amount of time spent in the sunlight. The researcher intentionally varies the exposure to sunlight between the two plants.

Therefore, the amount of water given to each plant is a control or constant, while the amount of time spent in the sunlight is the independent variable in this experiment.

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Answer:

B.  

more than 150 meters

Explanation:

As we know that the range of projectile motion on the surface of earth is given by the formula

[tex]R = \frac{v^2sin(2\theta)}{g}[/tex]

so here on the surface of earth the gravity is given as g = 9.8 m/s/s

now if the golf ball is hit on the surface of earth then it range is given as R = 150 m

while if we hit the ball at surface of mercury then on the surface of mercury the gravity will be g = 3.7 m/s/s

so due to decrease in the magnitude of gravity the range on the surface of mercury will be more than 150 m

Answer:

B. More that 150 meters.

Explanation:

:)

The acceleration due to gravity, or g (exp), will decrease if the experiment is conducted 10 kilometers above sea level. This is because the force of gravity reduces as you move further from the Earth's surface.

The acceleration due to gravity, or g (exp), is expected to decrease if the experiment is repeated at a place 10 kilometers above the sea-level. This is because the force of gravity decreases as the distance from the center of the Earth increases.

Essentially, the further you move away from the Earth's surface, the weaker the gravitational force gets. This is due to the fact that gravity is dependent on distance. So, being 10 kilometers above sea level would result in a slightly lower acceleration due to gravity.

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Answer:

The water cycle will affect the climate by causing rain and snow.

Explanation:

if temperatures increase more rainfall will occur because more water evaporates in the air.

The basketball is thrown horizontally and the time of flight is approximately 0.648 seconds.

In this problem, a basketball is passed from one player to another at the same level. The initial speed of the ball is 7.1 m/s and it travels a distance of 4.6 m. To determine the initial direction of the ball, we need to consider that the ball is caught at the same level from which it was thrown, meaning it has no vertical displacement. Therefore, the initial direction of the ball is horizontal.

To find the time of flight, we can use the equation:

time = distance / speed

Plugging in the values given:

time = 4.6 m / 7.1 m/s = 0.648 s

So, the time of flight of the ball is approximately 0.648 seconds.

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Answer:

The answer is: Many are associated in pairs, trios, groups or clusters, and their distribution in filamentary structures.

Explanation:

Galaxies rarely appear isolated and their distribution in the Universe is not uniform. Many are associated in pairs, trios, groups of some tens or clusters of up to a few thousand. These groups are held together by gravitation.

The large-scale distribution of galaxies seems to indicate that they are concentrated along large filamentary structures.

The answer is: Many are associated in pairs, trios, groups or clusters, and their distribution in filamentary structures.

The object fell a distance of 396.9 meters before hitting the ground.

To calculate the distance an object falls in a given time ignoring air resistance, we use the formula for the distance covered under constant acceleration: d =  rac{1}{2} g t^2, where d is the distance, g is the acceleration due to gravity (

9.8 m/s2), and t is the time in seconds. Substituting the given time of 9.0 seconds into the equation, the distance is calculated as d =  rac{1}{2}  imes 9.8  imes 9.0^2, which equals 396.9 meters. This equation is derived from basic kinematic principles that govern the motion of objects in free fall, assuming gravity is the only force acting on the object.

Answer:

When copper carbonate is heated, it decomposes to form a black residue. This black residue is actually copper(II) oxide. Along with this black residue, carbon-dioxide is released.

The law of conservation of mass holds true. 123.6 g of copper carbonate decomposes to 79.6 g of copper oxide and (123.6 g-79.6 g=44 g) 44 g of carbon-dioxide.

If you opened the valve on a bicycle tire, the air inside of the tire will come out and the pressure it exert will be less.

When air is pumped into a bicycle tube, the tube gets inflated due to the air pressure exerted by the collisions of gas molecules in air with the inner walls of the rubber tube. This air pressure makes the tyres feel hard.

When the temperature cools down, the air within the tire shrinks. In the same way, when the temperature rises, the air within the tire expands.

Due to the air being compressed in a small space, the air is pressurized and when the valve is open it causes a loss in pressure making the air gush out.

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the force is gravity holding them

Final answer:

The Earth's crust is composed of igneous, metamorphic, and sedimentary rocks, examples of which include granite (igneous), basalt (igneous), and limestone (sedimentary).

Explanation:

The three types of rock in the Earth's crust are igneous, metamorphic, and sedimentary. Igneous rocks, like granite and basalt, form when magma or lava cools and solidifies. Sedimentary rocks form from the compaction and cementation of various substances, including pre-existing rock fragments or mineral precipitation. Limestone is an example of a sedimentary rock formed from precipitated minerals. Metamorphic rocks arise from the transformation of existing rock types through heat and pressure, resulting in a change in mineral composition or structure.

Answer:

B. C + O2 ------> CO2

Explanation:

i took the test

The right option is; C) the abyssal zone of the ocean

The anglerfish are likely to be found in the abyssal zone of the ocean.  

The abyssal zone is the bottomless layer of the pelagic zone of the ocean that has the bathyal zone located on it.  The abyssal zone is at depths of 4,000 to 6,000 metres, and it remains permanently in darkness. This zone is a food limited environment because it lacks nutrients. The temperature of the zone is around 2 to 3 °C and has continuous cold.

Final answer:

Inertia is the property of an object to maintain its state of motion or rest unless acted upon by a net external force, as described by Newton's first law of motion. This law, also known as the law of inertia, indicates that an object will continue in its state of constant velocity unless a force causes a change.

Explanation:

How is Inertia Related to Newton's First Law of Motion?:

Inertia is directly related to Newton's first law of motion, often referred to as the law of inertia. Newton's first law states that a body at rest remains at rest, and a body in motion remains in motion at a constant velocity unless acted upon by a net external force. This tendency of an object to resist changes in its state of motion or rest is known as inertia. Essentially, inertia is the reason why an object remains at rest or carries on moving at the same speed in a straight line unless a net force acts upon it.

Newton's laws are fundamental in the study of motion under the influence of forces, particularly in inertial frames of reference. Forces, which are described by Newton's laws, are always vectors with both magnitude and direction, and arise from interactions among objects. Newton's first law serves as a definition of an inertial frame of reference, and thus, any frame where the law is valid is considered inertial.

Answer:

80 ft/s

Explanation:

Use III equation of motion

V^2 = U^2 + 2g h

Here, U = 0, g = 32 ft/s^2, h = 100 ft

V^2 = 0 + 2 × 32 ×100

V^2 = 6400

V = 80 ft/s

Answer:

2 m

Explanation:

Because there will be the greatest amount of force when they are closest together.

The distance at which the greatest gravitational force is exerted by one object on another if Two objects of the same mass are in a room should have the shortest distance, so option A is correct.

The universal force of attraction operating on all matter is known as gravity, usually spelled gravitation, in mechanics. The weakest known force in nature, it is by far and does not influence how everyday matter's internal properties are determined.

Measurements of gravity around the Earth, other planets, and the Moon, as well as experiments on the nature of gravitation, have greatly improved as a result of the launch of spacecraft and the research that has resulted from it.

The formula for the gravitational force is inversely proportional to the square of the distance between two objects,

Thus, to get the maximum gravitational force, the mass is to be at the lowest separation.

Therefore, the distance at which the greatest gravitational force be exerted by one object on another if Two objects of the same mass are in a room should have the shortest distance.

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The speed of the satellite is approximately [tex]\(3311 \, \text{m/s}\)[/tex] when the force acting on it is 87.4 N.

The gravitational force [tex](\(F_{\text{gravity}}\))[/tex] acting on the satellite is given by [tex]\(F_{\text{gravity}} = \frac{GMm}{r^2}\)[/tex], where [tex]\(G\)[/tex] is the gravitational constant, [tex]\(M\)[/tex] is the mass of the Earth, [tex]\(m\)[/tex] is the mass of the satellite, and [tex]\(r\)[/tex] is the distance from the center of the Earth to the satellite.

The centripetal force [tex](\(F_{\text{centripetal}}\))[/tex] required for circular motion is [tex]\(F_{\text{centripetal}} = \frac{m v^2}{r}\)[/tex], where [tex]\(v\)[/tex] is the speed of the satellite.

In a circular orbit, the gravitational force provides the centripetal force, so [tex]\(F_{\text{gravity}} = F_{\text{centripetal}}\)[/tex]:

[tex]\[\frac{GMm}{r^2} = \frac{m v^2}{r}\][/tex]

Solve for \(v\):

[tex]\[v = \sqrt{\frac{GM}{r}}\][/tex]

Now, substitute the given values:

[tex]\[v = \sqrt{\frac{(6.67 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2) \times (5.97 \times 10^{24} \, \text{kg})}{(3.00 \times 10^7 \, \text{m} + 6.37 \times 10^6 \, \text{m})}}\][/tex]

Calculating the expression to find the speed of the satellite. I'll do the math for you.

[tex]\[v = \sqrt{\frac{(6.67 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2) \times (5.97 \times 10^{24} \, \text{kg})}{(3.00 \times 10^7 \, \text{m} + 6.37 \times 10^6 \, \text{m})}}\][/tex]

[tex]\[v = \sqrt{\frac{(6.67 \times 10^{-11} \times 5.97 \times 10^{24})}{(3.00 \times 10^7 + 6.37 \times 10^6)}}\][/tex]

[tex]\[v = \sqrt{\frac{3.9879 \times 10^{14}}{3.637 \times 10^7}}\][/tex]

[tex]\[v \approx \sqrt{1.097 \times 10^7}\][/tex]

[tex]\[v \approx 3311 \, \text{m/s}\][/tex]

Therefore, the speed of the satellite is approximately [tex]\(3311 \, \text{m/s}\)[/tex] when the force acting on it is 87.4 N.