Tickets for a school play sold for $7.50 for each adult and $3 for each child the total receipts for the 113 tickets sold were $663 find the number of adult ticket sold

Answers

Answer 1
7.5a+3c=663
a+c=113

Write a literal equation for c using the second equation.
c=-a+113

Substitute the value of c into the first equation
7.5a+3(-a+113)= 663
7.5a-3a+339=663
4.5a+339=663
4.5a=324
a=72

Final answer: 72 adult tickets sold

Check by finding the value of c and plugging both values in
(72)+c=113
c=41

7.5(72)+3(41)
663
True

Related Questions

The population of a town is modeled by the equation P = 16,581e0.02t where P represents the population t years after 2000. According to the model, what will the population of the town be in 2020?

Answers

2020 is 20 years after 2000, so put 20 where t is in the equation and evaluate.

P = 16,581e^(0.02·20) = 16,581e^0.4

P ≈ 24,736

The model predicts the population in 2020 will be about 24,736.

what is the 31st term of the sequence below?
-108, -90, -72, -54, ...

Answers

Answer:

432

Step-by-step explanation:

The form for finding the nth term of an arithmetic sequence is a(n) = b +(n-1)d, where a is the function of the nth term, b is the first number in the sequence, n is the nth term, and d is the common difference. Plugging in what we know we get:

a(31) = -108 + 30 x 18

multiply

a(31) = -108 + 540

add

a(31) = 432

PLEASE MARK BRAINLIEST

Write an appropriate inverse variation equation if y = 9 when x = 3.

Answers

[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------\\\\ \begin{cases} y=9\\ x=3 \end{cases}\implies 9=k3\implies \cfrac{9}{3}=k\implies \boxed{3=k} \\\\\\ thus\qquad y=3x[/tex]

Kim uses decals to decorate 5 cars and 2 motorbikes. She uses 2/3 of the decals on the cars and 2/5 of the remaining on the motorbikes. She has 6 decals left. How many decals does Kim use on each car?

Answers

She uesed 1/3 * 2/5 of the total decal the second time, which is 2/15. So she used 2/15 + 2/3 = 12/15 of the decal. Which means what's left is 3/15 of the initial number, since its 6, the total number is 30. Which means she used 20 in the car, 4 in each, and 4 on the motorcycle, 2 in each.

Jack and Andrea want to create a right triangle together using values of x and y and the polynomial identity to generate Pythagorean triples. If Andrea picks a value of x = 2, and the hypotenuse of the resulting right triangle is 5, what natural number value of y did Jack pick? y = 1 y = 2 y = 3 y = 4

Answers

A right triangle can be considered as a special type because the relationship of its sides can be described using the hypotenuse formula:

c^2 = a^2 + b^2

or

c^2 = x^2 + y^2

where,

c is the hypotenuse of the triangle and is the side opposite to the 90° angle

while a and b are the sides adjacent to the 90° angle

 

In the problem statement, we are given that one of the side has a measure of 2 = x, while the hypotenuse is 5 = c, therefore calculating for y:

y^2 = c^2 – x^2

y^2 = 5^2 – 2^2

y^2 = 21

y = 4.58

 

The natural number is the number before the decimal. Therefore the answer is:

y = 4

Answer:

it is now y=4, i swear!! I put this, and it was wrong!!!

Step-by-step explanation:

In how many ways can 5 starting positions on a basketball team be filled with 8 men who can play any of the positions?

Answers

8 men, 5 positions

 so multiply 8*7*6 =336

divide by 3*2 =6

336/6 =56

 56 different ways

how do you write an interger whose absolute value is greater than itself.

Answers

Integers include negative numbers as well as positive numbers and zero.

An example of a solution to your question is -2. Its absolute value is 2, which is more than -2.

All negative integers are valid solutions, though.

Let r(t)=⟨t2,1−t,4t⟩. calculate the derivative of r(t)⋅a(t) at t=5, assuming that a(5)=⟨−4,4,−5⟩ and a′(5)=⟨−5,9,3⟩

Answers

[tex]\mathbf r(t)=\langle t^2,1-t,4t\rangle[/tex]
[tex]\implies\mathbf r'(t)=\langle 2t,-1,4\rangle[/tex]

[tex]\dfrac{\mathrm d(\mathbf r(t)\cdot\mathbf a(t))}{\mathrm dt}\bigg|_{t=5}=\mathbf r'(5)\cdot\mathbf a(5)+\mathbf r(5)\cdot\mathbf a'(5)[/tex]
[tex]=\langle10,-1,4\rangle\cdot\langle-4,4,-5\rangle+\langle25,-4,20\rangle\cdot\langle-5,9,3\rangle[/tex]
[tex]=(-40-4-20)+(-125-36+60)[/tex]
[tex]=-165[/tex]

Given p(a)=0.40, p(b)=0.50. if a and b are independent, what is the value of p(a intersection b)?

Answers

Final answer:

The value of P(A intersection B) is 0.20.

Explanation:

Given that events A and B are independent, the probability of their intersection can be found by multiplying their individual probabilities. So, P(A ∩ B) = P(A) * P(B). From the given information, P(A) = 0.40 and P(B) = 0.50. Therefore, P(A ∩ B) = 0.40 * 0.50 = 0.20.

A telephone survey uses a random digit dialing machine to call subjects. the random digit dialing machine is expected to reach a live person 15% of the time. in eight attempts, what is the probability of achieving exactly two successful calls?

Answers

P([tex]r[/tex] successes in [tex]n[/tex] trials) = ⁿ[tex] C_{r} [/tex]×[tex] [P(Success)^{r}] [/tex]×[tex] [P(failure)]^{n-r} [/tex]

We have
[tex]n=8[/tex]
[tex]r=2[/tex]
[tex]P(Success)=0.15[/tex]
[tex]P(Failure)=0.85[/tex]

Substitute these values into the formula, we have
P( 2 success in 8 trials) = ⁸C₂ × (0.15)² × (0.85)⁶
P( 2 success in 8 trials) = 0.2376.... ≈ 0.24 = 24%
Final answer:

The probability of achieving exactly two successful calls in eight attempts in a telephone survey using a random digit dialing machine is approximately 0.324 or 32.4%.

Explanation:

To calculate the probability of achieving exactly two successful calls in eight attempts in a telephone survey using a random digit dialing machine, we can use the binomial distribution formula. The formula is:

P(x) = (nCx) * (p^x) * ((1-p)^(n-x))

Where:

P(x) is the probability of getting exactly x successful callsn is the total number of attemptsx is the number of successful callsp is the probability of reaching a live person

Plugging in the values from the question, we have:

P(2) = (8C2) * (0.15^2) * ((1-0.15)^(8-2)) = 28 * 0.0225 * 0.411771 = 0.3239965

Therefore, the probability of achieving exactly two successful calls in eight attempts is approximately 0.324 or 32.4%.

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Which of the following are true statements about any regular polygon? Check all that apply.

A. All of its angles measure 90.
B. It is a quadrilateral.
C. It is a closed figure.
D. It is a hexagon.
E. All of its angles have equal measures.
F. Its sides are congruent line segments.

Answers

Answer:

Statement C, E and F are true.        

Step-by-step explanation:

We have to find the true statements about a regular polygon.

Regular Polygon  

A regular polygon is a polygon that is equiangular that is all angles are equal in measure and equilateral that is all sides have the same length.

A) False

This is not a necessity that all angles measure 90 degrees.

B) False

It may or may not be a a quadrilateral.

C) True

All regular polygons are closed figure.

D) False

All regular polygons are not hexagon but hexagon is a polynomial.

E) True

All the angles of a regular polygon are equal.

F) True

Since all the sides of a regular polygon are equal, thus, its sides are congruent line segments.

Explain how the phrase "oh heck another hour of algebra" can help a student recall the trigonometric ratios

Answers

It's suppose to stand for OH AH OA which is for sine, cosine, and tangent. Sine, opposite divide by hypotenuse, cosine adjacent divided by hypotenuse, and tangent, opposite divided by adjacent. I personally like SOHCAHTOA more since it actually has the S,C, and T before what it means
Final answer:

The phrase "oh heck another hour of algebra" can help a student recall the trigonometric ratios by associating key words in the phrase with math concepts. The phrase contains words related to math, such as "algebra" and "hour," as well as a word similar to "angle." By linking these words to the trigonometric ratios, a student can better remember and understand them.

Explanation:

The phrase "oh heck another hour of algebra" can help a student recall the trigonometric ratios by focusing on the key words within the phrase. The phrase contains the words "algebra" and "hour," which are related to math, and the word "heck," which is similar to the word "angle." By associating these words with the phrase, a student can remember the trigonometric ratios, which involve angles and algebraic calculations. For example, the phrase can remind a student that the sine ratio involves the ratio of opposite and hypotenuse sides, similar to finding lengths in algebraic equations.

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IHELP ME OUT WITH THIS MATH QUESTION
f DE is a mid segment of the triangle, then the measure of AC:

7.5
15.
30.
None of the choices are correct.

Answers

The mid segment of the triangle is always // to the base and is equal to half this base, then


DE = (AC)/2

15 = (AC/2) → AC = 30 (3rd answer)

A single fair die is tossed. Find the probability of rolling a number greater than 4.

Answers

There are two numbers greater than four out of six total numbers so:

P(>4)=2/6

P(>4)=1/3
Final answer:

The probability of rolling a number greater than 4 with a single fair die is 1/3 or approximately 0.33. This is calculated as the number of desired outcomes (a roll of 5 or 6) divided by the total possible outcomes (1, 2, 3, 4, 5, or 6). The actual results of a short series of rolls may vary, but over time the results should average out to this probability.

Explanation:

The question is asking to calculate the probability of rolling a die and getting a number greater than 4. In a fair six-sided die, the possible outcomes of a single toss are 1, 2, 3, 4, 5, or 6, making the total possible outcomes 6. The outcomes greater than 4 are 5 and 6, which gives us 2 desired outcomes.

Remember, probability is calculated as the number of desired outcomes over the number of total possible outcomes. So in this case, the probability is 2 (the number of outcomes greater than 4) divided by 6 (the total number of outcomes when rolling a die) which gives a probability of 1/3 or approximately 0.33.

This suggests that if you throw the single fair die repeatedly over time, about one third of the results would show a number greater than 4. It's essential to remember this is a theoretical probability, and actual short-term results may vary, but they should correspond to this probability in the long run per the law of large numbers.

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What is the answer to this problme

Answers

w= 4 and x =-2 so____ -2 - 4 which equals -6
w= 4

x=-2

-2-4=-6

the answer is -6

How do i Divide z4 by z-3

Answers

Synthetic division:

3  |  1   0   0     0     0
... |  .    3   9   27   81
- - - - - - - - - - - - - - - -
... |  1   3   9   27   81

which translates to

[tex]\dfrac{z^4}{z-3}=z^3+3z^2+9z+27+\dfrac{81}{z-3}[/tex]

Average maintenance costs are $1.50 per machine-hour at an activity level of 8,000 machine-hours and $1.20 per machine-hour at an activity level of 13,000 machine-hours. assuming that this activity is within the relevant range, total expected maintenance cost for a budgeted activity level of 10,000 machine-hours would be closest to:

Answers

Assume that maintenance costs per machine may be modeled by the linear relation
C = a + bx
where
x = machine hours
a, b are constants.

When x=8,000 hours, C=$1.50, therefore
a + 8000b = 1.5            (1)

When x=13,000 hours, C=$1.20, therefore
a + 13000b = 1.2           (2)

Subtract (2) from (1).
a + 8000b - (a + 13000b) = 1.5 - 1.2
-5000b = 0.3
b = -6 x 10⁻⁵
From (1), obtain
a = 1.5 - 8000*(-6 x 10⁻⁵) = 1.98

Therefore
C = 1.98 - 6x10⁻⁵ x

When machine hours is x=10,000, obtain
C = 1.98 - 6x10⁻⁵ * 10000
    = 1.38

Answer: $1.38

What is the value 6,035

Answers

6035 theres nothing to take from or add to it

6- thousands
0-hundreds
3-tens
5-ones

Good luck on your assignment!

~MeIsKaitlyn

57​% of men consider themselves professional baseball fans. you randomly select 10 men and ask each if he considers himself a professional baseball fan. find the probability that the number who consider themselves baseball fans is​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four.

Answers

this was my question and I don't need the answer anymore!

(a) [tex]\( P(X = 5) \approx 0.234 \)[/tex]

(b) [tex]\[ P(X \geq 6) \approx 0.892 \][/tex]

(c) [tex]\[ P(X < 4) \approx 0.020 \][/tex]

To solve this problem, we can use the binomial probability formula since each man's response (considering themselves a baseball fan or not) is independent and there are only two possible outcomes (success or failure).

Given:

- Probability of success (considering themselves a baseball fan) [tex]\( p = 0.57 \)[/tex]

- Probability of failure (not considering themselves a baseball fan) [tex]\( q = 1 - p = 1 - 0.57 = 0.43 \)[/tex]

- Number of trials [tex]\( n = 10 \)[/tex]

We'll calculate the probabilities for each case:

(a) To find the probability that exactly five men consider themselves baseball fans:

[tex]\[ P(X = 5) = \binom{10}{5} \times (0.57)^5 \times (0.43)^{10 - 5} \][/tex]

(b) To find the probability that at least six men consider themselves baseball fans, we can find the probability of six, seven, eight, nine, and ten men being baseball fans, and then sum them up.

(c) To find the probability that less than four men consider themselves baseball fans, we need to find the probabilities of zero, one, two, and three men being baseball fans, and then sum them up.

Let's calculate each probability:

(a) [tex]\[ P(X = 5) = \binom{10}{5} \times (0.57)^5 \times (0.43)^{5} \][/tex]

(b) To find the probability of at least six men being baseball fans:

[tex]\[ P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) \][/tex]

(c) To find the probability of less than four men being baseball fans:

[tex]\[ P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) \][/tex]

We'll use these formulas to find the probabilities for each case. Let me do the calculations.

(a) To find the probability that exactly five men consider themselves baseball fans:

[tex]\[ P(X = 5) = \binom{10}{5} \times (0.57)^5 \times (0.43)^{5} \][/tex]

Using the binomial coefficient formula [tex]\(\binom{n}{k} = \frac{n!}{k!(n - k)!}\)[/tex], where [tex]\(n = 10\)[/tex] and [tex]\(k = 5\)[/tex]:

[tex]\[ \binom{10}{5} = \frac{10!}{5!(10 - 5)!} = \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1} = 252 \][/tex]

Now, we plug in the values:

[tex]\[ P(X = 5) = 252 \times (0.57)^5 \times (0.43)^{5} \][/tex]

[tex]\[ P(X = 5) \approx 0.234 \][/tex]

(b) To find the probability of at least six men being baseball fans:

[tex]\[ P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) \][/tex]

For each [tex]\(k = 6, 7, 8, 9, 10\)[/tex], we calculate [tex]\(P(X = k)\)[/tex] using the binomial formula and sum them up.

(c) To find the probability of less than four men being baseball fans:

[tex]\[ P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) \][/tex]

Similarly, for each [tex]\(k = 0, 1, 2, 3\)[/tex], we calculate [tex]\(P(X = k)\)[/tex] using the binomial formula and sum them up. Let me do the calculations.

(a) [tex]\( P(X = 5) \approx 0.234 \)[/tex]

(b) To find the probability of at least six men being baseball fans:

[tex]\[ P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) \][/tex]

Using the binomial formula for each [tex]\( k = 6, 7, 8, 9, 10 \)[/tex] and summing the probabilities:

[tex]\[ P(X \geq 6) \approx 0.892 \][/tex]

(c) To find the probability of less than four men being baseball fans:

[tex]\[ P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) \][/tex]

Using the binomial formula for each [tex]\( k = 0, 1, 2, 3 \)[/tex] and summing the probabilities:

[tex]\[ P(X < 4) \approx 0.020 \][/tex]

A box contains 5 plain pencils and 7 pens. A second box contains 3 color pencils and 3 crayons. One item from each box is chosen at random. What is the probability that a plain pencil from the first box and a color pencil from the second box are selected?

Answers

Multiply the two desired probabilities to find the answer.

5/12 is the probability for the plain pencil since there are 5 pencils out of 12 total items.

1/2 is the probability for the colored pencil since there are 3 colored pencils out of 6 total items. 3/6 simplifies to 1/2.

5/12*1/2= 5/24

Final answer: 5/24

,,,Help Please.. Question in the file.

Answers

so hmmm there are 5pennies in a nickel, and 10pennies in a dime and 25pennies in a quarter

now, in $6.10, there are 610 pennies

n = amount of nickels coins
d = amount of dime coins
q = amount of quarter coins

so... we know, there are 5*n or 5n pennies in the nickels, and 10*d or 10d pennies in the dimes and 25*q or 25q in the quarter coins, and we know their sum is 610 pennies total, thus

5n + 10d + 25q = 610

now, there are 4 more "n" then "d", so whatever "d" is, "n" is 4  more than that
n = d + 4

and twice as many "q" than "n", so, whatever "n" is, then
q = 2n

[tex]\bf 5n+10d+25q=610\implies n+2d+5q=122\qquad \begin{cases} n=d+4\\ q=2n\\ ------\\ q=2(d+4)\\ \qquad 2d+8 \end{cases} \\\\\\ \boxed{d+4}+2d+5\left( \boxed{2d+8} \right)=122[/tex]

solve for "d", to see how many dimes are there

what about the nickels? well, n = d + 4
what about the quarters?  well, q = 2d + 8

what is the unit rate

Answers

A unit rate tells the rate in lowest terms or the amount of one it has a denominator of 1
The ratio compares two quantities (in this case blue and white parts).
A unit rate (or unit ratio) describes how many units of the first type of quantity corresponds to one unit of the second type of quantity. In our case the first type of quantity is blue parts and the second is white parts, so we should find how many blue parts correspond to one white part.
The ratio is: 5/4
We will obtain the unit ratio if we divide each number with 4 in order to get 1 - as a second quantity.
So, (5/4)/(4/4)= (5/4)/1
The unit ratio is:
(5/4)/1.

Which set or sets does the number 15 belong to?

Answers

It belongs to rational,whole,integer,real. 

Hope this helped :)

a cell phone company offers two different monthly plans.plan a charges $41 for unlimited cell phone minutes plus $0.10 per text message.Plan b charges $31 for unlimited cell phone minutes plus $0.15 per text message.How many text messages must a customer send in order for the cost of plan a to be equal to cost of plan b?

Answers

41+0.10x = 31+0.15x

10 +0.10x=0.15x

10=0.05x

x=10/.05

x= 200 text messages


check 200*0.10 = 20 +41 =61

200*0.15 = 30+31 = 61

 they equal each other so number of texts is 200

3. A carpenter is framing a window with wood trim where the length of the window is 6 and 2\3 feet. If the width of the window is 7 and3\4 feet, how many feet of the wood is needed to frame the window?

Answers

We can see that window is in shape of rectangle. So the length of the required wood to frame window is equal to the perimeter of rectangle.

SO the length of rectangular window is [tex]= 6 \frac{2}{3} = \frac{20}{3} [/tex] feet.

Width of the rectangular window is = [tex]7 \frac{3}{4} = \frac{31}{4} [/tex] feet.

In general parameter of rectangle is = [tex]2(l+b)[/tex]

So the parameter of window is = [tex]2( \frac{20}{3} + \frac{31}{4}) = 2* \frac{(80+ 93)}{12} = 2* \frac{173}{12} = 28.834 [/tex]

So the required length of wood to frame window is = 28.834 feet

In a literal question what does f and c represent

Answers

If your talking about math, science, or weather f and c will most likely represent fahrenheit and celsius

Of 13 possible​ books, you plan to take 6 with you on vacation. How many different collections of 6 books can you​ take?

Answers

Taking into account the definition of combination, you can take 1716 different collections of 6 books.

Combination

Combinations of m elements taken from n to n (m≥n) are called all the possible groupings that can be made with the m elements in which the order in which the elements are chosen is not taken into account and repetition is not possible.

The combination is calculated by:

[tex]C=\frac{m!}{n!(m-n)!}[/tex]

The term "n!" is called the "factorial of n" and is the multiplication of all numbers from "n" to 1.

Collections of 6 books that you can take

In this case it is possible to apply a combination, not all the elements enter, the order in which the books are chosen does not matter, and they are not repeated.

Being m= 13 and n=6, the combination is calculated by:

[tex]C=\frac{13!}{6!(13-6)!}[/tex]

Solving:

[tex]C=\frac{13!}{6!7!}[/tex]

C= 1716

Finally, you can take 1716 different collections of 6 books.

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Tatiana wants to give friendship bracelets to her 32 classmates. She has 5 bracelets now. She can buy more bracelets in packages of 4. If p is the number of packages Tatiana needs to buy to have at least 32 bracelets, the inequality representing the problem is: 4p+5≥32 What is the minimum number of packages Tatiana needs to buy?

Answers

7 packages would equal 28 bracelets, then add the 5 she already has and you get 33 total bracelets. 

7 packages is the answer

Let

p--------> the number of packages Tatiana needs to buy

we know that

[tex] 4p+5 \geq 32\\ 4p \geq (32-5)\\ 4p \geq 27\\\\ p \geq \frac{27}{4} \\ \\ p \geq 6.75 [/tex]

therefore

the minimum number of packages does Tatiana needs to buy is [tex] 7 [/tex]

let's check

[tex] 7*4+5=33 [/tex] bracelets

[tex] 33 \geq 32 [/tex] ------> is ok

the answer is

the minimum number of packages is [tex] 7 [/tex]

Which of the following are solutions to the equation below? (4x - 1)2 = 11

Answers

(4x - 1)2 = 11
(4x - 1) = 22
4x - 1 = 22
4x = 23
x = 5.75

Answer:

X = - sqrt 12 / 4

X = sqrt 11 + 1 / 4

DE is parallel to XY. What is the value of X?

Answers

DE is parallel to XY
x = 85 (alternate interior angles)
answer is A. 85
Since two opposite angles (vertical)  about the intersection of two lines must equal to each other:

x=85°
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