Three deer, a, b, and c, are grazing in a field. deer b is located 64.9 m from deer a at an angle of 53.4 ° north of west. deer c is located 77.9 ° north of east relative to deer
a. the distance between deer b and c is 96.8 m. what is the distance between deer a and c

Final answer:

The initial velocity of the ball is approximately 14.9 m/s, found using kinematic equations considering the ball's upward motion against gravity over 1.3 seconds to pass a 2.00 m high window.

Explanation:

To determine the initial velocity of a ball thrown straight up, we can use the kinematic equations for uniformly accelerated motion. The ball passes a 2.00 m high window that starts 7.5 meters above the ground, and it takes 1.3 seconds to pass by the window. We'll use the following kinematic equation:

s = ut + 1/2at²

where s is the displacement (the height of the window), u is the initial velocity we want to find, t is the time (1.3 seconds), and a is the acceleration due to gravity (approximately -9.81 m/s², since it's upwards).

Plugging in the values, we have:

2.00 m = u(1.3 s) + 1/2(-9.81 m/s²)(1.3 s)²

Solving for u, the initial velocity of the ball is calculated to be the positive root of the resulting quadratic equation. After performing the algebraic manipulation, we find that the initial velocity is approximately 14.9 m/s.

To determine if a reaction happened in an Erlenmeyer flask, you can observe indicators such as color change, formation of a precipitate, and gas evolution.

In order to determine if a reaction happened in the Erlenmeyer flask, you can observe several indicators:

Additionally, other observations such as the release of energy (exothermic reaction) or absorption of energy (endothermic reaction) can provide further evidence of a reaction.

Final answer:

To calculate the acceleration of each plate, first find the force of kinetic friction using the mass of the plates and coefficients of friction. The acceleration can then be found by applying Newton's second law, considering the net force on each plate after friction is taken into account.

Explanation:

To determine the acceleration of each plate when three horizontal forces are applied, we first need to understand the role of static and kinetic friction. Given each plate has a mass of 10 kg, we can calculate the normal force (N) exerted by each plate, which is necessary for finding frictional forces. The normal force is equal to the weight of the plate, calculated as N = mg, where m is the mass and g is the acceleration due to gravity (9.8 m/s2). Thus, for a 10 kg plate, N = 10 kg × 9.8 m/s2 = 98 N.

The maximum static friction force that must be overcome to start moving the plate is calculated using Fₛ(max) = μsN, where μs is the coefficient of static friction (0.3). Therefore, Fₛ(max) = 0.3 × 98 N = 29.4 N. Once motion begins, the kinetic friction force applies, calculated using Fₘ = μkN, where μk is the coefficient of kinetic friction (0.2). Therefore, Fₘ = 0.2 × 98 N = 19.6 N. To find the acceleration of each plate, we apply Newton's second law of motion (F = ma), subtracting the kinetic friction force from the applied force, and solving for a.

Without specific values for the applied forces in the question, we've laid out the framework to calculate the acceleration. It's important to subtract the kinetic friction force from the applied force to find the net force before applying Newton's second law.

First, the cubic volume of water to be removed is calculated by multiplying length, width, and reduced depth of the pool. This equates to 81.25 cubic meters, which is 81250 liters. The time is then calculated by dividing total volume by pump rate, equating to 19345 seconds or approximately 5.40 hours.

The subject of this question is related to applied mathematics, specifically about volume and rates.

In order to determine how long it will take to lower the water level in the pool, first, we need to calculate the volume of the water to be removed. The volume can be calculated by multiplying the length, width, and height of the swimming pool. However, since we want the height to be 6.50 cm or 0.065 m, we use that as our height.

Volume = length x width x height = 50.0 m x 25.0 m x 0.065 m = 81.25 cubic meters. Since 1 cubic meter is equivalent to 1000 liters, the volume of water to be removed is 81250 liters.

Given that the pump removes water at a rate of 4.20 liters per second, we can determine the time by dividing the total volume by the rate of the pump.

Time = volume / rate = 81250 liters / 4.20 liters/sec = 19345 seconds or approximately 5.40 hours.

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Final answer:

The igneous rock in question, characterized by the presence of flattened pumice and small quartz and feldspar crystals, was likely formed by an explosive volcanic eruption. This is evidenced by the extrusive nature of pumice and the rapid cooling inferred from the small crystal sizes.

Explanation:

The igneous rock described contains flattened pieces of pumice and small crystals of quartz and feldspar. The presence of pumice, which is a vesicular felsic igneous extrusive rock with a very low density such that it can float on water, indicates that the rock was formed during an explosive volcanic eruption. This type of eruption releases lava that cools very quickly on the surface of the Earth, trapping gases within the rock and creating the vesicles or holes that define pumice. Hence, the rock exhibits characteristics of an extrusive igneous rock.

Moreover, the small crystal sizes of quartz and feldspar suggest rapid cooling as well. Large crystals are typically indicative of slow cooling within the Earth's crust, a feature of intrusive igneous rocks like granite. Given these characteristics, it is evident that the rock formed from an explosive eruption, which would have caused the rapid cooling and trapping of gas that are evident in the presence of pumice.

The force acting on a box in the back of a pickup truck, which accelerates forward, is due to static friction and is directed forward. This force ensures the box accelerates at the same rate as the truck, preventing it from sliding.

When a pickup truck accelerates forward, the force acting on a box due to the truck is directed forward. This force is the result of static friction between the box and the bed of the truck. The static friction force prevents the box from slipping by providing the necessary force to accelerate the box at the same rate as the truck. If the truck accelerates to the right, the frictional force acting on the box is also to the right. This force is a reaction to the box's tendency to remain in its state of rest, according to Newton's first law of motion, which says that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

The calculation of the maximum distance the truck can travel without the box sliding involves determining the static frictional force and using it to find the acceleration of the box. Given the coefficient of static friction (μ) is 0.24, and assuming the acceleration of gravity (g) is approximately 9.8 m/s², we use the equation for static friction F_s = μ N, where N is the normal force, equivalent to the weight of the box if we assume a horizontal surface and neglect air resistance.

The key to understanding this problem lies in recognizing the role of static friction in causing the box to accelerate together with the truck, rather than sliding. If the bed of the truck provides sufficient friction, it enables the box to move as one with the vehicle, demonstrating the practical application of Newton's laws of motion.

The force acting on the box due to the truck is directed to the right.

When the pickup truck accelerates to the right, a force is exerted on the box due to the truck bed's friction. Since the bed of the truck is sticky, the box does not slide. The direction of the frictional force acting on the box is also to the right, in the same direction as the truck's acceleration.

Here's a step-by-step explanation:

Therefore, the force acting on the box due to the truck is to the right.

The greatest possible distance from the mirror to the point where the reflected rays meet is infinite for a flat mirror, as the reflected rays never actually converge, creating a virtual image.

The greatest possible distance d from the mirror to the point where the reflected rays meet would be when the object distance do approaches the focal length f of the mirror from the right side, causing the image distance d to approach negative infinity, indicating that the reflected rays would never converge in real space. This situation describes the formation of a virtual image where the rays appear to come from. In a flat mirror, the focal length is technically at infinity since parallel rays remain parallel after reflection and never actually converge. Therefore, in a practical sense, when considering a flat mirror, the reflected rays appear to converge at a distance behind the mirror equal to the object's distance in front of the mirror, which is defined as d = -do.

The greatest possible distance (d) from the mirror to the point where the reflected rays meet is [tex]\( \frac{L}{2} \)[/tex], which is the focal length of the mirror when it is at the center of the spherical surface.

To understand why the greatest possible distance (d) from the mirror to the point where the reflected rays meet is [tex]\( \frac{L}{2} \)[/tex], let's consider the behavior of light rays reflecting off a mirror.

When a light ray reflects off a mirror, the angle of incidence is equal to the angle of reflection. This means that the path of the light ray before and after reflection are symmetric with respect to the normal to the mirror surface at the point of incidence.

For the reflected rays to meet at a point, they must converge. The best way to visualize this is to consider a light ray that travels parallel to the mirror's surface. After reflection, this ray will appear to come from a point behind the mirror, known as the focal point. The distance from the mirror to this focal point is the focal length of the mirror.

In the case of a flat mirror, the focal length is infinite because parallel rays remain parallel after reflection and do not converge to a single point. However, if we consider a spherical mirror, the focal length (f) is finite and is related to the radius of curvature (R) of the mirror by the equation [tex]\( f = \frac{R}{2} \)[/tex].

Now, let's consider the scenario where the mirror can be moved horizontally. The greatest possible distance (d) from the mirror to the point where the reflected rays meet would occur when the mirror is at the center of the spherical surface it is a part of. At this point, the focal point of the mirror would be at a distance equal to the focal length (f) from the mirror's surface.

Given that the length of the mirror is (L), and the radius of curvature (R) is equal to (L) (since the mirror is a segment of a sphere), we can substitute (R) with (L) in the focal length equation. Thus, the focal length (f) is [tex]\( \frac{L}{2} \)[/tex].

I like to solve first in SI units. So convert pressure into Pascal.

P = 207 psi = 1.427x10^6 Pa

The formula for hydrostatic pressure is:

P = ρ g h

where ρ is density of ocean water = 1025.1 kg/m^3, g is gravity = 9.81 m/s^2, h is height or depth

1.427x10^6 = 1025.1 * 9.81 * h

h = 141.92 m

Convert meters to inches:

h = 141.92 m = 5587.4 inches

The least amount of time required for a point on a wave to move from y = 0 to y = 12 cm is 12 seconds.

To determine the least amount of time required for a point on a wave to move from y = 0 to y = 12 cm, we need to consider the wave's velocity. Since the wave velocity is constant, the distance the wave travels is the wave velocity times the time interval. Therefore, we can calculate the time required by dividing the distance by the wave velocity.

In this case, we can assume the wave travels 12 cm in the positive y-direction. Let's say the wave velocity is 1 cm/s. To reach 12 cm, it would take 12 / 1 = 12 seconds. So, the least amount of time required for the point on the wave to move from y = 0 to y = 12 cm is 12 seconds.

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The magnitude of the gravitational force exerted on one sphere by the other three can be calculated using Newton's Law of Universal Gravitation. Using the given information, the magnitude of the gravitational force is approximately 2.97 x 10^-8 N.

The magnitude of the gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation:

Fg = (G * m1 * m2) / r2

Where Fg is the gravitational force, G is the gravitational constant (approximately 6.67 x 10-11 Nm2/kg2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.

In this case, the mass of each sphere is 8.5 kg and the distance between their centers is 0.52 m.

Calculating the gravitational force between one of the spheres and the three others, we use the formula and plug in the values:

Fg = (6.67 x 10-11 * 8.5 kg * 8.5 kg) / (0.52 m)2

Calculating the result, the magnitude of the gravitational force exerted on one sphere by the other three is approximately 2.97 x 10-8 N.

Since the rabbit is moving at constant velocity, therefore the acceleration is zero, hence the increase in distance over time would simply be:

x = v t

where v is velocity and t is time, x is distance

Since we are starting at x = 8.1 m, the equation of motion would therefore be:

x = 8.1 – 1.6 t

If the planet earth has no land masses, the idealized zonal precipitation pattern would likely have regions that are wet in the equator and there will be more of mid-latitudes if the earth has no land masses at all and it does not exist.

Answer: The distance traveled by boat is 5400 meters.

Explanation:

Speed is defined as the ratio of distance traveled to the time taken.

To calculate the distance traveled by boat, we use the equation:

[tex]\text{Spped of the boat}=\frac{\text{Distance traveled}}{\text{Time taken}}[/tex]

We are given:

Speed of the boat = 6 m/s

Time taken = 15 mins = 900 s     (Conversion factor:   1 min = 60 s)

Putting values in above equation, we get:

[tex]6m/s=\frac{\text{Distance traveled by boat}}{900s}\\\\\text{Distance traveled by boat}=(6m/s\times 900s)=5400m[/tex]

Hence, the distance traveled by boat is 5400 meters.

The average speed of the ball cannot be accurately determined without the total time or rate of deceleration. However, if we are simply looking for the average of the initial and final speeds, it would be 12.5 m/s.

The question involves calculating the average speed of a ball given its initial and final speeds. However, there is a discrepancy in the question as it initially mentions the ball rolls 6.0 meters but then asks for the average speed over 10 meters. Assuming the correct distance is 6.0 meters, the calculation of average speed requires us to know the total distance traveled and the total time taken.

To find the average speed, we use the formula:

Average Speed = Total Distance ÷ Total Time

The total distance traveled by the ball is given as 6.0 meters. Since we do not have the total time, we cannot calculate the average speed directly. Additionally, it's said that the ball's speed changes from 15 m/s to 10 m/s, which means that it is decelerating. However, with the information provided, we cannot accurately determine the ball's average speed without additional details such as the rate of deceleration or the time taken.

Assuming a typo in the question and that it's asking for the average of the initial and final speeds instead, we could simply calculate it by:

Average Speed = (Initial Speed + Final Speed) ÷ 2

In this case:

Average Speed = (15 m/s + 10 m/s) ÷ 2 = 12.5 m/s

However, this calculation assumes a linear change of speed, which might not be the case in a real-world scenario.

Answer:

A theory explaining the model of the Universe.

Explanation:

Steady State theory, proposed in 1948 by Sir Hermann Bondi, Thomas Gold, and Sir Fred Hoyle, suggests that the universe is always expanding while maintaining a constant average density. This is achieved as matter is continuously created to form new stars and galaxies at the same rate as that of old ones becoming non-observable. This occurs as a consequence of increasing distance and velocity of recession of old stars and galaxies.

As per this theory, Universe has no beginning and no end in time. If looked at it from a grand scale, the arrangement of galaxies and average density remain same.

Later observation of the Universe gave results contradictory to Steady State Theory. This has led to increase in support of Big Bang Model of the Universe.

The steady state theory in systems theory means state variables do not change over time, and in chemical kinetics, it refers to the steady-state approximation where an intermediate's concentration is assumed constant, aiding in the analysis of complex reactions.

The steady state theory refers to a concept in systems theory where a system or process is said to be in a steady state if its state variables, which define the behavior of the system, are not changing over time. In the context of chemical kinetics, this often pertains to the steady-state approximation, where the concentration of an intermediate in a reaction is assumed to be constant over time because its formation rate is equal to its consumption rate. This approximation simplifies the mathematical analysis of complex reactions and is particularly useful in enzyme kinetics, as proposed by Briggs & Haldane in 1925.

The steady-state assumption does not imply that the system is static or that there is an absence of reaction fluxes. Rather, it means that even though reactions are occurring and products are being formed, the internal metabolite concentrations and the fluxes (input and output fluxes) are maintained constant over time. This is a critical simplification that aids in metabolic modeling and the analysis of enzymatic reactions.

Final answer:

The acceleration of the ball rolling down the ramp is 0.2 m/s^2, calculated using the equation of motion for uniformly accelerated movement without initial velocity.

Explanation:

To calculate the acceleration of a ball that starts from rest and travels a certain distance down a ramp over a known time period, we can use the equations of motion for uniformly accelerated motion. It is given that the ball travels 0.9 meters in 3 seconds from rest.

The equation that relates distance (s), initial velocity (u), time (t), and acceleration (a) is:

s = ut + \frac{1}{2}at^2

Since the initial velocity u is 0 m/s (because the ball starts from rest), the equation simplifies to:

s = \frac{1}{2}at^2

Rearranging this equation to solve for acceleration yields:

a = \frac{2s}{t^2}

Plugging in the given values:

a = \frac{2 * 0.9 m}{(3 s)^2} = \frac{1.8 m}{9 s^2} = 0.2 m/s^2

Therefore, the acceleration of the ball is 0.2 m/s2.

A.)Diffraction, because light is bent around the clouds