Three cars are driving on a racetrack. The mean speed of the three cars is 100 miles per hour. Car X drives 109 miles per hour and Car Y drives 111 miles per hour. Use the mean to estimate the speed of Car Z. Then find the actual speed of Car Z.
Estimate the speed of Car Z. Choose the correct answer below.
A.
The speed of Car Z is about 100 miles per hour.
B.
The speed of Car Z is less than 100 miles per hour.
C.
The speed of Car Z is greater than 100 miles per hour.
D.
It is impossible to estimate the speed of Car Z.

Answers

Answer 1

Answer:

B

Step-by-step explanation:

The mean is the average found by adding the sum of the data points and dividing by the number of them. Here there are 3 cars whose speeds are 109, 111, and Z or unknown. The mean of them is 100. Solve for Z.

100 =(109+111+Z)/3

300=220+Z

80=Z

The speed of Car Z is less than 100.

Answer 2

The correct answer is B. The speed of Car Z is less than 100 miles per hour.

To estimate the speed of Car Z, we can use the given mean speed of the three cars. The mean speed is given as 100 miles per hour. Since Car X is driving at 109 miles per hour and Car Y is driving at 111 miles per hour, both of these speeds are above the mean. To maintain an average of 100 miles per hour, Car Z must be driving at a speed less than 100 miles per hour to balance the speeds of Car X and Car Y, which are pulling the average up.

To find the actual speed of Car Z, we can use the formula for the mean speed of the three cars:

[tex]\[ \text{Mean speed} = \frac{\text{Speed of Car X} + \text{Speed of Car Y} + \text{Speed of Car Z}}{3} \][/tex]

Given that the mean speed is 100 miles per hour, we can plug in the known values and solve for the speed of Car Z:

[tex]\[ 100 = \frac{109 + 111 + \text{Speed of Car Z}}{3} \][/tex]

Multiplying both sides by 3 to clear the denominator:

[tex]\[ 300 = 109 + 111 + \text{Speed of Car Z} \][/tex]

Adding the speeds of Car X and Car Y:

[tex]\[ 300 = 220 + \text{Speed of Car Z} \][/tex]

Subtracting 220 from both sides to isolate the speed of Car Z:

[tex]\[ \text{Speed of Car Z} = 300 - 220 \] \[ \text{Speed of Car Z} = 80 \text{ miles per hour} \][/tex]

Thus, the actual speed of Car Z is 80 miles per hour, which confirms our initial estimation that it is less than 100 miles per hour.


Related Questions

The product of two numbers is −72. One of the factors is −9, what is the other factor?

Answers

Answer:

8.

Step-by-step explanation:

-9 x x = -72.x = 8.

In all of the steps to solve this specific question, x is a variable to represent the other factor, that we are trying to find out the answer to, and our equation that we need to set up for this problem, is -9 times x equals -72, because -9 multiplied by the other factor that we are trying to solve for, which is x in this case, should equal -72. So then, to completely finish simplifying this equation, we need to divide -9 from both sides, so we can get our variable x, that we are trying to get the answer for, by itself. Then finally, you get x equal to 8, as our final, simplified answer. These are all of the steps to completely get the correct answer to your question.

Hope this helps!!!

Kyle.

What is the equation (4, 5) m=-1/4 solved in point slope form?

Answers

Answer:

y - 5 = -1/4(x - 4)

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

We have m = -1/4 and the point (4, 5). Substitute:

[tex]y-5=-\dfrac{1}{4}(x-4)[/tex]

What is the quadratic function f(x)=x^2+6x-2 In vertex form?
A:f(x)=(x-3)^2+7
B:f(x)=(x+3)^2+7
C:f(x)=(x-3)^2-11
D:f(x)=(x+3)^2-11

Answers

Answer: Option D

[tex]f(x)=(x+3)^2 -k[/tex]

Step-by-step explanation:

For a quadratic function of the form

[tex]ax ^ 2 + bx + c[/tex]

The x coordinate of the vertice is:

[tex]x =-\frac{b}{2a}[/tex]

In this case the function is:

[tex]f(x)=x^2+6x-2\\\\[/tex]

So

[tex]a=1\\b=6\\c=-2[/tex]

The x coordinate of the vertice is:

[tex]x=-\frac{6}{2*1}\\\\x=-3[/tex]

The y coordinate of the vertice is:

[tex]f(-3) = (-3)^2 +6(-3) -2\\\\f(-3)=-11[/tex]

The vertice is: (-3, -11)

The form e vertice for a quadratic equation is:

[tex]f(x)=(x-h)^2 +k[/tex]

Where

the x coordinate of the vertice is h and the y coordinate of the vertice is k.

Then h=-3 and k =-11

Finally the equation [tex]f(x)=x^2+6x-2\\\\[/tex] in vertex form is:

[tex]f(x)=(x+3)^2 -k[/tex]

Answer:

The correct answer option is D. f(x) = (x + 3)² - 11.

Step-by-step explanation:

We know that the standard form of a quadratic function is given by:

y = ax² + bx + c

The vertex form of a parabola is given by

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b / 2a and k = f(h)

In the given equation f(x) = x² + 6x - 2

a = 1, b = 6 and c = -2

Finding h:

h = -6 / (2 × 1)

h = -6/2

h = -3

Finding k:

k = 1(-3)² + 6(-3) + 3

k = 9 - 18 - 2

k = -11

Therefore, the given quadratic function in vertex form: f(x) = (x + 3)² - 11

A radius is _____ the diameter.

Answers

The answer is 1/2.

2r = d.

Hope this helps!

A Radius Of The Circle Is Always Half The Diameter. This Means That The Radius Is Half Way Across A Circle.

Suppose you roll a regular 6-faced die. What is the probability of rolling: a 6?, a 2?, and a 4?

Answers

3/6 because there are 6 sides and there are 3 numbers that you want to roll. They are even numbers so if you want to roll half of the numbers but not the other half well you have 3/6

Jason will use a 3 1/3 gallon pitcher to fill an empty 3/4 gallon water jug. How much water will he need in order to completely fill the water jug?

Answers

Answer:

Option B) Between 2 & 3 full pitchers

Step-by-step explanation:

Note  In this problem the volume of the pitcher is 1/3 gallon instead of 3 1/3 gallon

The options of the questions are

A) Between 1 & 2 full pitchers

B) Between 2 & 3 full pitchers

C) About 1/2 of a full pitcher

D) About 1/4 of a full pitcher

so

we know that

To find the number of water pitchers Jason will need to fill the water jug, we will divide the amount of water needed to fill the jug by amount of water in the pitcher

[tex](3/4)/(1/3)=9/4\ water\ pitchers[/tex]

Convert to mixed number

[tex]9/4\ water\ pitchers=(8/4)+(1/4)=2(1/4)\ water\ pitchers[/tex]

therefore

Is Between 2 & 3 full pitchers  

Final answer:

Despite having a 3 1/3 gallon pitcher, Jason will only need 3/4 gallon of water to fill his 3/4 gallon jug. The size of the pitcher doesn't matter, only the size of the jug.

Explanation:

Considering that Jason is seeking to fill a 3/4 gallon water jug with a 3 1/3 gallon pitcher, it is evident that the entire capacity of the pitcher will not be required. To determine precisely the volume of water required, we examine the jug's capacity. Given that the jug has a maximum volume of 3/4 gallon, that is the exact volume of water Jason will require to fill it. Regardless of the pitcher's volume, it's the jug's capacity, which is 3/4 gallon, that establishes the quantity of water needed. Consequently, 3/4 gallon is the volume of water he needs to fill the jug.

Learn more about Volume Measurement here:

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Grade 4
96. Shelly uses a scoop to fill a container with
flour. The scoop holds cup of flour.
If Shelly uses 12 scoops of flour to fill the
container, how many cups of flour does she
use?

Answers

Answer:

12

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Laverne already knew 2 appetizer recipes before starting culinary school, and she will learn 3 new
appetizer recipes during each week of school.
After 2 weeks of culinary school, how many total
appetizer recipes will Laverne know?

Answers

Answer:

the answer is 8

Step-by-step explanation:

You would do use the equation (3×2)+2=8

Hope this helps :)

Answer:

8 appetizer recipes.

Step-by-step explanation:

Given,

The number of appetizer recipes Laverne already knew = 2,

Also, she learns 3 new appetizer recipes during each week of school.

So, the additional number of recipes she learn in 2 weeks = 2 × 3 = 6,

Hence, the total  appetizer recipes she would know = The recipes she already knew + the additional number recipe she learnt in 2 weeks

= 2 + 6

= 8

chris bought 4 4/5 pounds of raisins. he shared the raisins equally between himself and five friends. how many raisins did each person get? i already know the answer but i just need to show the work. please answer quickly!!

Answers

first off let's convert the mixed fraction to improper fraction, and then do the division, since it was divided among all 6, he and 5 friends.

[tex]\bf \stackrel{mixed}{4\frac{4}{5}}\implies \cfrac{4\cdot 5+4}{5}\implies \stackrel{improper}{\cfrac{24}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{24}{5}\div 6\implies \cfrac{24}{5}\div \cfrac{6}{1}\implies \cfrac{24}{5}\cdot \cfrac{1}{6}\implies \cfrac{24}{6}\cdot \cfrac{1}{5}\implies \cfrac{4}{1}\cdot \cfrac{1}{5}\implies \cfrac{4}{5}[/tex]

Answer:

0.8 or 4/5

Step-by-step explanation:

4/5=.8 4.8/6=.8

DEFG is an isosceles trapezoid find the measure of E

Answers

Answer:

The last option (62 degrees)

Step-by-step explanation:

Angle F is the same measure as angle E, just like angle D is the same measure as G.

The measure of angle ∠E will be 62°. Then the correct option is D.

What is a trapezium?

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a trapezium, one pair of opposite sides are parallel.

DEFG is an isosceles trapezoid.

Then the angle ∠E and ∠F will be congruent.

∠E = ∠F

∠E = 62°

Then the correct option is D.

More about the trapezium link is given below.

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A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequence?

Answers

Answer:

[tex]\large\boxed{\left\{\begin{array}{ccc}t_1=375\\t_{n}=5t_{n-1}\end{array}\right}[/tex]

Step-by-step explanation:

[tex]t_n=75(5^n)\\\\t_{n+1}=75(5^{n+1})\\\\\text{The common ratio:}\ r=\dfrac{t_{n+1}}{t_n}\\\\\text{Substitute:}\\\\r=\dfrac{75(5^{n+1})}{75(5^n)}\qquad\text{cancel 75 and use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\r=5^{n+1-n}=5^1=5\\\\\text{Calculate}\ t_1.\ \text{Put}\ n=1\ \text{to}\ t_n:\\\\t_1=75(5^1)=75(5)=375\\\\\text{The recursive formula of a geometric sequence:}\\\\t_1\\t_n=(t_{n-1})(r)[/tex]

Answer:

t1=375, tn = 5tn-1, where n EN and >1

Step-by-step explanation:

USA test prep said so

The normal price of a jacket is £54 in a sale, the price is reduced by 30% what is the sale price

Answers

Answer:

£37.80

Step-by-step explanation:

To find the sale price of a jacket during a 30% off sale, first subtract 0.30 from 1.00, obtaining 0.70, and then multiply the regular price (£54) by 0.70:

0.70(£54) = £37.80

Final answer:

The sale price of the jacket after a 30% discount is applied to the original price of £54 is £37.80.

Explanation:

The student's question is about calculating the sale price of a jacket after a discount of 30% is applied to the normal price of £54. This is a typical percentage problem that can be solved using the following steps:

Calculate the discount amount by multiplying the original price by the discount rate.Subtract the discount amount from the original price to find the sale price.

To calculate the discount amount: 30% of £54 = 0.30 × £54 = £16.20.

Then, subtract the discount amount from the original price: £54 - £16.20 = £37.80.

Therefore, the sale price of the jacket is £37.80.

What is the vertex of the function f(x) = x2 + 12x?
0 (6-36)
(6.0)
(6.0)
(6 -36)
Mark this and retum
Save and Exit
SUR

Answers

Answer:

(-6, -36)

Step-by-step explanation:

The vertex [tex](h,k)[/tex] of a function of the form [tex]f(x)=ax^2+bx+c[/tex] is given by the formula:

[tex]h=\frac{-b}{2a}[/tex]

[tex]k=f(h)[/tex] in other words, we find h and then evaluate function at h to find k.

We know from our function that [tex]a=1[/tex], [tex]b=12[/tex].

Replacing values

[tex]h=\frac{-12}{2(1)}[/tex]

[tex]h=-\frac{12}{2}[/tex]

[tex]h=-6[/tex]

Now we can evaluate our function at -6 to find k:

[tex]k=f(h)=f(-6)[/tex]

[tex]k=(-6)^2+12(-6)[/tex]

[tex]k=36-72[/tex]

[tex]k=-36[/tex]

We can conclude that the vertex (h, k) of our function is (-6, -36)

Answer:

(-6,-36)

Step-by-step explanation:

The given function is

[tex]f(x)=x^2+12x[/tex]

We complete the square to write this function in the vertex form.

Add and subtract the square of half the coefficient of x.

[tex]f(x)=x^2+12x+6^2-6^2[/tex]

[tex]f(x)=x^2+12x+36-36[/tex]

The first three terms is now a perfect square trionomial

[tex]f(x)=(x+6)^2-36[/tex]

Or

[tex]f(x)=(x--6)^2-36[/tex]

The function is now in the form:

[tex]f(x)=a(x-h)^2+k[/tex]

where h=-6 and k=-36

The vertex is therefore (h,k)=(-6,-36)

Divide. Write your answer in simplest form.

5/6 ÷ 8

Answers

Answer:

5/48

Step-by-step explanation:

Answer:

5/48

Step-by-step explanation:

What is the slope of a line with the given coordinates (6,-4) and (-3,-7)

Answers

Answer:

m= 1/3

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

-4-(-7) / 6-(-3)

3/ 9

1/3

Someone help me out please

Answers

Answer:

Do you need work shown?

Step-by-step explanation:

(I don't know where to comment here)

OPTIONS OVER HERE AND FOR A BETTER VIEW OF THE QUESTION LOOK AT THE PICTURE THANK YOU AND PLEASE HELP!!!

Select the correct answer from each drop-down menu.

QUESTION

FOR THIS EXPRESSION, A = ((( 15 OR 4 OR 7 ))) . B = (( 7 OR 4 OR 15 ))) , C = ((( 4 OR 15 OR 7)))

Answers

Answer:

a = 15

b = 7

c = 4

Step-by-step explanation:

Given in the question an expression [tex]\sqrt[4]{15}^{7}[/tex]

This expression can be written as [tex]15^{\frac{7}{4} }[/tex]

As we know that roots are most often written using a radical sign, like this, [tex]\sqrt[n]{x}[/tex] But there is another way to represent the taking of a root.

You can use rational exponents instead of a radical. A rational exponent is an exponent that is a fraction. For example, [tex]\sqrt[n]{x}[/tex] can be written as [tex]x^{\frac{1}{n} }[/tex]

Secondly two powers having same base can be multiply

[tex]x^{n}(^{m})=x^{nm}[/tex]

Find the following bases.
a. 8% of ? = 20
b. 75% of ? = 30
c. 20% of ? = 45
d. 150% of ? = 36

Answers

It is pretty easy.

[tex]20 = x \times 0.08 \\ x = 20 \div 0.08 = 250[/tex]

[tex]30 = x \times 0.75 \\ x = 30 \div 0.75 = 40[/tex]

[tex]45 = x \times 0.20 \\ x = 45 \div 0.20 = 225[/tex]

[tex]36 = x \times 1.50 \\ x = 36 \div 1.5 = 24[/tex]

Answer:

a. 250

b. 40

c. 225

d. 24

Step-by-step explanation:

What would be the answer to this?

Answers

Answer:

D

Step-by-step explanation:

Distribute the negative 1 in the second group.

[tex]5k^4*-1=-5k^4 \\ 5k^3*-1=-5k^3 \\ -k*-1=k[/tex]

Now add by combining like terms.

[tex]3k^4-5k^4=-2k^4 \\ -2k^3-5k^3=-7k^3 \\ k+k=2k[/tex]

[tex]-2k^4-7k^3+2k[/tex]

A phone number contains 7 digits. How many different numbers can be made using the digits 0–9 if the first digit is not 0 and all of the digits can be repeated?

The Options are:
A. 10 × 96
B. 9 × 107
C. 9 × 106
D. 107

Answers

Answer:

[tex]9 \cdot 10^6[/tex]

Step-by-step explanation:

A phone number contains 7 digits. How many different numbers can be made using the digits 0–9 if the first digit is not 0 and all of the digits can be repeated

In 7 digit phone number, the first number cannot be 0

So only 1  to 9 are used to get the first digit. 9 numbers can be used

other digits can use number from 0 to 9. 10 number can be used

So possible numbers can be made is

[tex]9 \ times \ 10 \ times \ 10 \ times \ 10 \ times \ 10 \ times \ 10 \ times \ 10[/tex]

[tex]9 \cdot 10^6[/tex]

The correct option is C.[tex]\ 9 \times 10^6[/tex]

To solve the problem of finding how many different [tex]7[/tex]-digit phone numbers can be made using the digits [tex]0–9[/tex], with the first digit not being 0 and digits allowed to repeat, we can follow these steps:

1. First Digit Choices

The first digit has 9 possible choices ([tex]1[/tex] through [tex]9[/tex]) since it cannot be 0.

2. Remaining Digits Choices

Each of the remaining [tex]6[/tex] digits can be any of the [tex]10[/tex] digits ([tex]0[/tex] through [tex]9[/tex]).

So, the total number of different [tex]7[/tex]-digit phone numbers can be calculated by multiplying the number of choices for each digit:

[tex]\[9 \text{ choices for the first digit} \times 10 \text{ choices for each of the remaining 6 digits}\][/tex]

This can be represented mathematically as:

[tex]\[9 \times 10^6\][/tex]

Calculating [tex]\(10^6\)[/tex]

[tex]\[10^6 = 1,000,000\][/tex]

So,

[tex]\[9 \times 1,000,000 = 9,000,000\][/tex]

pls HURRY 12 Points!!!

what is the area of this trapezoid?



A:96 in²

B:132 in²

C:168 in²

D:1344 in²

Answers

Answer:

(B) 132 in²

Step-by-step explanation:

Top Length = 3 + 8 + 3 = 14 in

Bottom Length = 8 in

Area of the trapezoid

= 1/2 (14 + 8) x 12

= 1/2 (22) (12)

= 132 in²

Answer:

B

Step-by-step explanation:

The area (A) of a trapezoid is calculated using the formula

A = [tex]\frac{1}{2}[/tex] h (a + b)

where h is the perpendicular height and a, b the parallel bases.

here h = 12, a = AB = 8 and b = DC = 3+ 8 + 3 = 14

A = [tex]\frac{1}{2}[/tex] × 12 × (8 + 14) = 6 × 22 = 132 in² → B

How do I solve this?

Answers

Answer:

[tex]\large\boxed{x=\log_\frac{5}{3}5}[/tex]

Step-by-step explanation:

[tex]3^x=5^{x-1}\qquad\text{use}\ a^{n-m}=\dfrac{a^n}{a^m}\\\\3^x=\dfrac{5^x}{5^1}\qquad\text{multiply both sides by 5}\\\\5\cdot3^x=5^x\qquad\text{divide both sides by}\ 3^x\\\\5=\dfrac{5^x}{3^x}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\5=\left(\dfrac{5}{3}\right)^x\qquad\text{logarithm both sides}\ \log_\frac{5}{3}\\\\\log_\frac{5}{3}5=\log_\frac{5}{3}\left(\dfrac{5}{3}\right)^x\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log_\frac{5}{3}5=x\log_\frac{5}{3}\dfrac{5}{3}\qquad\text{use}\ \log_aa=1\\\\\log_\frac{5}{3}5=x[/tex]

What is the range of possible sizes for side x?

Answers

Answer:

all real numbers

Step-by-step explanation:

11.
ALGEBRA Zakama Hussein earned $77.00 in simple interest in 18 months ( 1.5 years) at an annual interest rate of 7%. How much money did she invest?

$1466.67

$1650.00

$85.22

$733.33

Answers

Answer:

$733.33

Step-by-step explanation:

The question is on finding the principal value

Formulae for simple interest

S.I= P×R/100×T where P is the invested amount of money, R is interest rate and T is time in years

Given that;

Simple interest=$77 , R=7% and T=1.5 years then

S.I= P×R/100×T...................substituting the values given

77=P×7/100 × 1.5

77=P×0.105

77/0.105 =P

$733.33=P

Explain the rule for multiplying two negative integers. Use a number line or algebra tiles to illustrate three examples. Make a sketch of your work.

Answers

Multiplying two negative numbers would always give you a positive product

Example 1) -2 * -1 = 2

Example 2) -5 * -4 = 20

Example 3) -10 * -3 = 30

The slope intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point slope form of the equation for this line?

A. y - 13 = 5(x - 2)

B. y + 13 = 5(x + 2)

C. y - 2 = 5(x - 13)

D. y + 2 = 5(x + 13)

Answers

Answer:

B. y+13=5(x+2)

Step-by-step explanation:

I personally do y=_+_(x-_) when solving these equations

Plug in -2 the x coordinate for (x- (-2) to be (x+3)

Plug in -13 for the y intercept.

5 from 5x is the slope.

Thus y=-13+5(x+3)

Then just move 13 to the other side

8x+10-2x=4(x-5) solve for x

Answers

Answer:

[tex]x=-15[/tex]

Step-by-step explanation:

[tex]8x+10-2x=4(x-5) \\ \\ 6x+10=4x-20 \\ \\ 2x=-30 \\ \\ x=-15[/tex]

x = -15

First, distribute the 4 to the x - 5 to get 8x + 10 - 2x = 4x - 20.

Now, subtract 4x and 10 from each side to get 4x - 2x = -30

Simplify the subtraction to get 2x = -30.

Divide both sides by 2 to get a final answer of x = -15.

A man walks 10 miles in x hours. How far does he walk in one hour?
Which expression represents this?
10+x miles
10x miles
10/x miles

Answers

Answer: It can't be 10 + x, it can't be 10x, so it will be 10/x

please mark as brainliest

Step-by-step explanation:

Answer:

[tex]\frac{10}{x} \ miles[/tex]

Step-by-step explanation:

Givens

A man walks 10 miles in x hours.

So, how far does he walk in one hour?

Basically, the question is asking the constant rate of change of the person's position. In other words, it's asking about the man's velocity: how many miles per hour.

The expression that represents this situation is

[tex]\frac{10}{x} \ miles[/tex]

Because, the problem refers to the ratio of change, which is the quotient between the distance traveled and the time that took to travel that distance.

Which of the following is equal to the rational expression when x does not equal -3 x^2-9/x+3

Answers

Answer:

x - 3

Step-by-step explanation:

Given

[tex]\frac{x^2-9}{x+3}[/tex]

Note that x² - 9 is a difference of squares and factors as

x² - 9 = (x + 3)(x - 3), thus

[tex]\frac{(x+3)(x-3)}{x+3}[/tex]

Cancel the x+ 3 factor on the numerator/ denominator leaving

x - 3 ← in simplified form

Final answer:

The simplified form of the given rational expression x²-9/x+3, provided x is not equal to -3, is x-3.

Explanation:

The given rational expression is x²-9/x+3. To simplify this expression, we can recognize that the numerator (x^2-9) is a difference of squares. In fact, we can rewrite the expression as (x+3)(x-3)/(x+3). As long as x doesn't equal -3 (to prevent division by zero), we can simplify the expression by canceling out the common factor of 'x+3' in both the numerator and denominator. Therefore, the simplified form of the rational expression is x-3 when x does not equal -3.

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Evaluate the determinant by using diaganals

Answers

Answer:

C. 26

Step-by-step explanation:

The question is on finding determinant of 3×3 matrix

General formulae is given by

if we have matrix (a  b  c)

                             (d  e  f)  

                              (g  h  i ) then the determinant will be given by

a× D( e f) - b × D (d f)  + c× D ( d e)

       (h  i)              (g i)              (g  h)

where D is the determinant

Evaluate

(a  b  c)     (-4  3  3)

(d  e  f)  =  (3  0  2)  = -4 ×D(0 2)  - 3×D (3 2) + 3×D (3 0)

 (g  h  i )     (3  1   1)                (1   1)           (3  1)           (3  1)

= -4 × {(I×0)-(1×2)} -3 {(3×1)-(3×2)} + 3 { (1×3)-(3×0)}

= -4 ×{-2} - 3×{-3} +3× {3}

=8+9+9= 26

Other Questions
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Which type does this?A) chemically-gated ion channelsB) G protein-linked receptorsC) cytoplasmic receptorsD) protein kinase receptors What are the functions of the sori found on the leaves Please help!Chapter 1"You know, hardly anyone ever needs to do a three-point turn anymore," said Justin, trying to help Becky calm down."Oh, so it's not a useful skill AND I am probably going to fail the driving test because I can't do it anyway," Becky said, raising her voice for emphasis. "That should make me feel like a million bucks when I flunk."Justin was riding with Becky so she could take her driving test. He had volunteered for the job because he thought she would be less nervous with him than with their mom, but so far, he wasn't sure he was making any difference."Slow down, your turn is coming up here," he said, looking ahead."I know, I know," she replied, "I've been here before rememberthe last time I flunked."Justin was pretty sure if he had let her miss the turn, things would only have deteriorated further, but he wasn't sure he was fond of being the scapegoat for Becky's anxiety."Listen, you need to take a few deep breaths," he said, hoping he could help her at least relax a bit. "Being nervous won't help you with the three-point turn or anything else you have to do. Hey, did you just take that turn without your turn signal on?" This was going to be harder than he thought."Stop yelling at me," Becky replied, clearly frustrated, "I can't concentrate.""Look, you need to stop and get yourself together here," Justin started. "It is not just about passing the driving test. I don't want to get in an accident, so pull into that parking lot."Becky drove into the office building's parking lot where Justin was pointing. Justin knew they were less than a mile from the licensing office, and if she continued in this condition, he'd be having this same discussion three months from now when she tried the test again for the third time."You need to get a grip," he started after she put the car in park, "because you have studied and practiced driving all year. You know this stuff inside and out, backwards and forwards. What are you so nervous about?""I don't know, I don't know," Becky wailed, resting her head on the steering wheel. "I just get so tired of failing."Listening quietly as Becky sobbed, Justin realized this was about much more than a driving test. He also knew if he didn't find a way to help Becky things would just get worse.Chapter 2Justin took a deep breath and collected his thoughts. Becky was an unbelievably consistent straight-A student. It was Justin who got the bad grades in school, and Justin who had to repeat every math class he'd ever taken. It was Justin who wished he could get the grades Becky got. Some things came easier for Justin: He was athletic, handy with tools, and good at making the best of whatever life threw at him. Mom called him her "lemons into lemonade" kid. But for the most part, Becky succeeded easily, whereas Justin had to work and work to just get a passing grade.Rather than having Becky catalogue all the things she supposedly "failed" at, Justin decided to try an alternative approach, one that wouldn't remind him of all the ways he had failed."Okay, Becky, let's assume for a moment you fail this test again. What is the worst thing that could happen?" he asked."I would be the oldest kid at school without a license and be humiliated," she replied. Justin thought he heard a bit of panic in her voice but continued with his plan."Yes, but won't we still have to drive to school together for at least one more year anyway?" he asked."Yes, but..." she started."And who will know, if you don't tell anyone except your friends, that you don't have your license? You know Mom can't afford another car just for you, right?""Yes," she said quietly."So what difference does it make, really," he said. "Another three months to wait in the grand scheme of your life doesn't seem like all that long, right?""I suppose not," she said.Justin could tell she was breathing more slowly now. "Besides," he said, "I would miss all the practice driving with you," and for good measure he reached over and pinched her arm."Ow," she said, hitting back at him, "that hurt.""So let's go do this, okay?"Okay," she said. Becky cranked up the car, backed slowly out of the parking spot and drove up to the parking lot's exit. Justin noticed, as they waited for the traffic to clear, that she had remembered the turn signal.Use Chapters 1 and 2 to answer the following question:Which line of dialogue most clearly presents the main conflict? (5 points)A) You know, hardly anyone ever needs to do a three-point turn anymoreB) I am probably going to fail the driving test because I can't do itC) Listen, you need to take a few deep breathsD) I would be the oldest kid at school without a license and be humiliated Steam Workshop Downloader