THIS IS FOR A REVIEW NOT A TEST.
what would N be? I don’t really understand how to find it.

Moisture, rising unstable air, and a lifting mechanism etc.  are the main features of severe thunderstorm. Hence, option a is correct.

Thunderstorm is resulting from the collision of clouds accompanied with an electric current producing the lightning. Severe thunderstorms produce convective instability .

It brings about a significant negative buoyancy in conjunction with thunderstorm downdrafts. Intense evaporation, negative buoyancy, and a powerful downdraft are produced as the dry air entrains with the cloud's wet air.

Hail that is falling undergoes less melting because to evaporative cooling. Severe thunderstorms also causes tilting of storms, displaces updraft from downdraft; Creates a vacuum affect at the top of storms; helps sustains the intensity and verticality of the updraft.

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Final answer:

Severe thunderstorms require moisture, rising unstable air (updrafts), and a lifting mechanism. These storms form in conditions of atmospheric instability, often involving lifting caused by convection, orographic uplift, or encounters between different air masses such as cold fronts and warm fronts.

Explanation:

Severe thunderstorms are complex weather systems that require specific atmospheric conditions to form. Based on the information provided, the elements that severe thunderstorms have with them include moisture, rising unstable air, and a lifting mechanism. Rising unstable air, also known as updrafts, is a crucial component for the development of thunderstorms. This unstable air rises and cools, leading to water vapor condensing into clouds. The process of condensation releases latent heat, which further fuels the updrafts, causing the thunderstorms to intensify.

Different lifting mechanisms can lead to the formation of thunderstorms, including convection, orographic uplift, and weather fronts such as cold fronts and warm fronts, where air masses of different temperatures collide, forcing the warmer air to rise. This process leads to atmospheric instability, which is a critical condition for thunderstorm formation.

Answer: the answer is D

Explanation:

Answer:

D. zinc and hydrochloric acid.

Explanation:

Step 1: The balanced equation:

Zn + 2HCL → ZnCl2 + H2

Step 2:

All chemical reactions involve both reactants and products. Reactants are substances that start a chemical reaction, and products are substances that are produced in the reaction.

This means the substances on the left side, Zinc (Zn)  and hydrochloric acid (HCl) are the reactants and will react with eachother, to form the products Zinc chloride (ZnCl2) and hydrogen gas (H2).

Option A: is not correct because zinc chloride and hydrogen are the products

Option B: is not correct because there is no hydrogen carbonate in the reaction

Option C: is not correct because there is no zinc chlorate, neither water in the reaction

The correct answer is D. zinc and hydrochloric acid.

The correct answer is (B) average molecular speed.

The correct answer is (B) average molecular speed.

According to the kinetic molecular theory, the average kinetic energy of gas molecules is directly proportional to their temperature. Since the temperature is the same for both the H2 and O2 gases, they will have the same average kinetic energy. However, the average molecular speed is inversely proportional to the square root of the molar mass. Since H2 has a lower molar mass than O2, it will have a higher average molecular speed.

The correct answer is a. average molecular kinetic energy.

At standard temperature and pressure (STP), all ideal gases have the same average molecular kinetic energy regardless of their molar mass or any other properties. This is a consequence of the kinetic molecular theory of gases, which states that the average kinetic energy of gas particles is directly proportional to the temperature of the gas in Kelvin. Since both samples are at the same temperature, they have the same average molecular kinetic energy.

 To understand why the other options are incorrect, let's consider each one:

 b. average molecular speed: According to the kinetic molecular theory, the average molecular speed of a gas is inversely proportional to the square root of its molar mass. Since hydrogen (H2) has a molar mass of approximately 2 g/mol and oxygen (O2) has a molar mass of approximately 32 g/mol, the average molecular speed of H2 will be greater than that of O2 at the same temperature.

 c. volume: According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain the same number of moles. Therefore, a 0.50 mol sample of H2 gas will occupy twice the volume of a 1.0 mol sample of O2 gas at STP.

 d. effusion rate: The rate of effusion of a gas is inversely proportional to the square root of its molar mass (Graham's law). Since H2 has a lower molar mass than O2, H2 will effuse more quickly than O2.

 e. density: The density of a gas is directly proportional to its molar mass. Since O2 has a higher molar mass than H2, a 1.0 mol sample of O2 gas will have a higher density than a 0.50 mol sample of H2 gas at STP.

Therefore, the only property that is the same for both gas samples at STP is their average molecular kinetic energy.

Answer:

Option 3 is the true one

Explanation:

1 mole of carbon atoms contains a mass of 12 g. So If you have 6 moles, you have six times the number of particles that are in 12 grams of carbon-12.

1 mol of anything occupies 6.02x10²³ particles (NA)

Answer : The correct option is, You have six times the number of particles that are in 12 grams of carbon-12.

Explanation :

As we are given that the number of moles of substance is, 6 moles.

First we have to calculate the moles of carbon-12.

[tex]\text{Moles of carbon}=\frac{\text{Mass of carbon}}{\text{Molar mass of carbon}}[/tex]

Mass of carbon = 12 g

Molar mass of carbon = 12 g/mol

[tex]\text{Moles of carbon}=\frac{12g}{12g/mol}=1mol[/tex]

Now we have to calculate the number of particles in 12 g of carbon-12.

1 mole of carbon-12 contains [tex]6.022\times 10^{23}[/tex] number of particles.

Now we have to calculate the number of particles in 6 mole of substance.

As, 1 mole of substance contains [tex]6.022\times 10^{23}[/tex] number of particles.

So, 6 mole of substance contains [tex]6\times 6.022\times 10^{23}[/tex] number of particles.

From this we conclude that, we have six times the number of particles that are in 12 grams of carbon-12.

Hence, the correct option is, You have six times the number of particles that are in 12 grams of carbon-12.

Answer:

Answer in explanation

Explanation:

The atomic mass can be defined as the addition of the number of protons and neutrons in the nucleus of an atom. When we talk of atomic mass, we are considering the mass of a particular isotope.

The average atomic mass or otherwise called the relative atomic mass is the atomic mass of the element itself. It has been calculated by taking into consideration the atomic masses of all the contributing isotopes existing in nature.

For example we have carbon 14 and carbon 12. While 14 is the atomic mass of that isotope, 12 is the relative atomic mass of the carbon atom. The abundance in nature of the different isotopes will dictate where the final atomic mass will lean

The new volume of the gas is 0.109 L.

To find the new volume of the gas, we can use the combined gas law formula:

P1V1/T1 = P2V2/T2

Where P1 is the initial pressure, V1 is the initial volume, T1 is the initial temperature, P2 is the final pressure, V2 is the final volume, and T2 is the final temperature.

In this case, we are given:

P1 = 1.0 atm, V1 = 100.0 mL = 0.100 L, T1 = 25.0 ℃ = 298 K

P2 = 1.0 atm (since the pressure remains the same), T2 = 50.0 ℃ = 323 K

Substituting the values into the formula, we can solve for V2:

(1.0 atm)(0.100 L) / (298 K) = (1.0 atm)(V2) / (323 K)

Cross-multiplying and solving for V2, we find:

V2 = (1.0 atm)(0.100 L)(323 K) / (298 K) = 0.109 L

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Answer : The resulting concentration of [tex]Na^+[/tex] ion is, 4.5 M

Explanation : Given,

Concentration of [tex]Na_2CO_3[/tex] = [tex]M_1[/tex] = 3.0 M = 3.0 mol/L

Volume of [tex]Na_2CO_3[/tex] = [tex]V_1[/tex] = 70 mL = 0.07 L

Concentration of [tex]NaHCO_3[/tex] = [tex]M_2[/tex] = 1.0 M = 1.0 mol/L

Volume of [tex]NaHCO_3[/tex] = [tex]V_2[/tex] = 30 mL = 0.03 L

First we have to calculate the moles of [tex]Na_2CO_3[/tex] and [tex]NaHCO_3[/tex]

[tex]\text{Moles of }Na_2CO_3=\text{Concentration of }Na_2CO_3\times \text{Volume of }Na_2CO_3=3.0mol/L\times 0.07L=0.21mol[/tex]

and,

[tex]\text{Moles of }NaHCO_3=\text{Concentration of }NaHCO_3\times \text{Volume of }NaHCO_3=1.0mol/L\times 0.03L=0.03mol[/tex]

Now we have to calculate the moles of [tex]Na^+[/tex] ions.

As, 1 mole of [tex]Na_2CO_3[/tex] will give 2 moles of [tex]Na^+[/tex] ions

So, 0.21 moles of [tex]Na_2CO_3[/tex] will give [tex]2\times 0.21=0.42[/tex] moles of [tex]Na^+[/tex] ions

and,

As, 1 mole of [tex]NaHCO_3[/tex] will give 1 mole of [tex]Na^+[/tex] ions

So, 0.03 moles of [tex]NaHCO_3[/tex] will give 0.03 moles of [tex]Na^+[/tex] ions

So,

Total number of moles of [tex]Na^+[/tex] ions = 0.42 + 0.03 =0.45 mole

Total volume of both solution = 70 mL + 30 mL = 100 mL = 0.1 L

Now we have to calculate the concentration of [tex]Na^+[/tex] ions.

[tex]\text{Concentration of }Na^+=\frac{\text{Moles of }Na^+}{\text{Volume of solution}}=\frac{0.45mol}{0.1L}=4.5mol/L=4.5M[/tex]

Therefore, the resulting concentration of [tex]Na^+[/tex] ion is, 4.5 M

To find the resulting concentration of Na+, calculate the moles of Na+ ions in each compound and then add them together. Finally, divide the total moles of Na+ ions by the total volume of the solution to find the concentration of Na+.

To find the resulting concentration of Na+, we need to calculate the total amount of Na+ ions present in the solution after the reaction occurs. We can do this by calculating the moles of Na+ ions in each compound and then adding them together.

First, calculate the moles of Na2CO3:

3.0 M Na2CO3 * 0.070 L = 0.210 mol Na2CO3

Next, calculate the moles of NaHCO3:

1.0 M NaHCO3 * 0.030 L = 0.030 mol NaHCO3

Now, add the moles of Na+ ions:

0.210 mol Na2CO3 + 0.030 mol NaHCO3 = 0.240 mol Na+

Finally, calculate the resulting concentration of Na+:

0.240 mol Na+ / (0.070 L + 0.030 L) = 2.0 M concentration of Na+

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Answer:

The particles are spread evenly throughout the dispersion medium, which can be a solid, liquid, or gas. Because the dispersed particles of a colloid are not as large as those of a suspension, they do not settle out upon standing

Explanation:

My teacher asked us this question We had to answer it.

pls thank me

Final answer:

Colloidal particles remain suspended in a dispersion medium due to their small size that allows Brownian motion to keep them from settling, and the Tyndall effect distinguishes them by scattered light. Particles in a suspension settle out due to their larger size.

Explanation:

The reason why particles in a colloid stay suspended in a liquid, as opposed to particles in a suspension which settle out, is due to the size of the dispersed particles. Particles in a suspension are larger and will settle upon standing, but colloidal particles are small enough that Brownian motion counteracts the effects of gravity, maintaining the particles in suspension. Additionally, colloidal particles may be either hydrophilic, with an affinity for water, which prevents them from aggregating, or hydrophobic, in which case they are often stabilized by surfactants to remain dispersed.

Another key feature of colloids is the Tyndall effect, where light is scattered by the particles in the colloid. This effect can make colloidal mixtures appear cloudy or opaque, which differentiates them from true solutions, where such scattering does not occur because the dissolved species are at the molecular or ionic level and too small to scatter light.

The given question is incomplete. The complete question is as follows.

Which of the following best helps explain why an increase in temperature increases the rate of a chemical reaction?

(a)   at higher temperatures, high-energy collisions happen less frequently.

(b)  at low temperatures, low-energy collisions happen more frequently.

(c)   at higher temperatures, less-energy collisions happen less frequently.

(d)  at higher temperatures, high-energy collisions happen more frequently

Explanation:

When we increase the temperature of a chemical reaction then molecules of the reactant species tend to gain kinetic energy. As a result, they come into motion which leads to more number of collisions within the molecules.

Therefore, chemical reaction will take less amount of time in order to reach its end point. This means that there will occur an increase in rate of reaction.

Thus, we can conclude that the statement at higher temperatures, high-energy collisions happen more frequently, best explains why an increase in temperature increases the rate of a chemical reaction.

Answer:

Number of moles of LiF produced by F₂ are less so it will limiting reactant.

Explanation:

Given data:

Mass of lithium = 1.1 g

Mass of F₂ = 1.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2Li + F₂ → 2LiF

Number of moles of Li:

Number of moles = mass/ molar mass

Number of moles = 1.1 g / 6.94 g/mol

Number of moles = 0.2 mol

Number of moles of F₂:

Number of moles = mass/ molar mass

Number of moles = 1.8 g / 38 g/mol

Number of moles = 0.05 mol

Now we will compare the moles of Li and F₂ with LiF.

                      Li                :               LiF

                       2                :                 2

                     0.2               :               0.2

                      F₂                :              LiF

                       1                  :               2

                      0.05             :           2×0.05 = 0.1 mol

Number of moles of LiF produced by F₂ are less so it will limiting reactant.

Answer:

3

Explanation:

NaCl + AgNO₃ ———> NaNO₃ + AgCl.

Firstly, we will need to calculate the number of moles of AgCl produced. That is equal to the mass produced divided by the molar mass of AgCl.

The molar mass of AgCl = 108 + 35.5 = 143.5g/mol

The number of moles is thus 1.32/143.5 = 0.0092 moles

Since silver nitrate and silver chloride contains one atom of silver, it is only possible that their mole ratios are equal. Hence we say that 0.0092 moles of silver nitrate hydrate was dissolved.

Now we go on to calculate the molar mass of the silver nitrate hydrate.

The molar mass is simply the mass divided by the number of moles.

That is 2.06/0.0092 = 223.9 = 224g/mol

We can now calculate the value of x from here.

AgNO3.xH2O

(108 + 14 + 48) + x(2+ 16) = 224

170 + 18x = 224

18x = 224 - 170 = 54

18x = 54

x = 54/18 = 3

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

[tex]\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}[/tex].

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be [tex]\rm 30 \% \times 100\; g = 30\; g[/tex] of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio [tex]\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}[/tex]:

[tex]\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}[/tex].

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

[tex]\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%[/tex].

The percent composition of CaCO3 in a sample that contains 30% calcium by weight is 75%. This is calculated by dividing the actual weight % of calcium in the sample by the weight % of calcium in pure CaCO3, and multiplying by 100.

The subject of this question is the calculation of the percent composition of a compound, which comes under the realm of Chemistry, specifically, Stoichiometry. In this question, we are examining a sample of calcium carbonate (CaCO3) reported to contain 30% calcium (Ca). We are to determine the percent of CaCO3 present in the sample.

Given that the molar mass of CaCO3 is 100 grams, 30% of this is calcium, that equates to 30 grams of calcium. Calcium's contribution to the molar mass of CaCO3 is 40 g/mol, so in a 100 g sample of pure CaCO3, calcium would naturally account for 40%. However, in our sample, the calcium content is lower at 30%. Thus, the sample is not 100% pure CaCO3. To calculate the percent composition of CaCO3 in this sample, we divide calcium's actual proportion of the sample by its proportion in pure CaCO3, and multiply by 100. Hence, (30/40)*100 = 75%.

Therefore, the sample is 75% CaCO3.

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Answer:

Swelling of the red blood cells occurs.

Explanation:

Answer:

At 580.4 K of temperature will the gas reach a pressure of 825kPa

Explanation:

If the gas is stored in a tank, at 273K (as initial temperature) let's apply Charles Gay Lussac law, where the volume doesn't change and the number of moles neither.

If the volume keeps on constant, pressure is been modified directly proportional to absolute T°.

P1 / T°1 = P2 / T°2

388kPa / 273K = 825kPa / T°2

(388kPa / 273K) . T°2 = 825kPa

T°2= 825kPa . 273K/388 kPa

T°2 = 580.4K

Answer:

[tex]M=147.014 g/mol[/tex]

Explanation:

The atomic weights of the elements:

Ca=40.078 g/mol

Cl=35.453 g/mol

H=1.008 g/mol

O=15.999 g/mol

The calcium chloride dihydrate:

[tex]M=(40.078+35.453*2+2*2*1.008+2*15.999)g/mol[/tex]

[tex]M=147.014 g/mol[/tex]

Final answer:

Strontium (Sr) in period 3 of the periodic table has chemical properties similar to calcium (Ca) because they are both alkaline earth metals in group 2 with 2 valence electrons.

Explanation:

Since calcium is an alkaline earth metal, it shares similar chemical properties with other elements in group 2 of the periodic table. The answer would be strontium (Sr), as it is placed directly below calcium in group 2, and elements in the same group typically have similar properties due to their similar valence electron configurations.

Strontium has 2 valence electrons like calcium and tends to form +2 cations when reacting.

To determine the number of grams of H2 formed when 4.52 moles of Na reacts with an excess of water, use the balanced chemical equation and the molar mass of H2.

To determine the number of grams of H2 formed when 4.52 moles of Na reacts with an excess of water, we first need to balance the chemical equation. The balanced equation for the reaction between Na and water is:
2Na + 2H2O → 2NaOH + H2

From the balanced equation, we can see that for every 2 moles of Na that react, 1 mole of H2 is formed. Therefore, if 4.52 moles of Na react, we expect to produce half that amount of moles of H2.

Number of moles of H2 = (4.52 moles of Na) / 2 = 2.26 moles of H2

To convert the moles of H2 to grams, we need to use the molar mass of H2, which is 2 g/mol.

Mass of H2 = (2.26 moles of H2) * (2 g/mol) = 4.52 grams of H2

Answer:

242.862 grams is the theoretical yield of the reaction.

Nitrogen gas is a limiting reactant.

Hydrogen gas is an excessive reactant.

Explanation:

[tex]N_2+3H_2\rightarrow 2NH_3[/tex]

Moles of nitrogen gas = [tex]\frac{200.0 g}{28 g/mol}=7.143 mol[/tex]

Moles of hydrogen gas = [tex]\frac{200.0 g}{2 g/mol}=100.0 mol[/tex]

According to reaction, 1 mole of nitrogen reacts with 3 moles of hydrogen gas.

Then 7.413 moles of nitrogen will react with:

[tex]\frac{3}{1}\times 7.413 mol=21.428 mol[/tex] of hydrogen gas.

Moles of hydrogen that will react with 7.143 moles of nitrogen gas is less than the moles of hydrogen gas we have. This means that hydrogen gas is in an excessive reactant.

Nitrogen gas is in less amount hence limiting reactant.

Since, moles of nitrogen are in limiting amount so the amount of ammonia formed will depend upon moles of nitrogen gas.

According to reaction ,1 mole of nitrogen gives 2 moles of ammonia.

Then 7.143 moles of nitrogen will give:

[tex]\frac{2}{1}\times 7.143 mol=14.286 mol[/tex] of ammonia

Mass of 14.286 moles of ammonia :

= 14.286 mol × 17 g/mol=  242.862 g

242.862 grams is the theoretical yield of the reaction.

Answer:

η = 0.5686

Explanation:

Isentropic compressor efficiency (η):

* η = Isentropic compressor work / real compressor work = Ws / Wreal

∴ Wreal = 76 KW = 76 KJ/s

first law:

∴ Q = 0 ....adiabatic compressor

∴ ΔU = CvΔT

∴ W = - PδV

⇒ ΔU = W ,,,,,isentropic process adiabatic

⇒ CvΔT = - PδV

ideal gas:

⇒ (R + Cv / R) Ln(T2/T1) = Ln (P2/P1)

∴ Cv = 3/2 R....monoatomic ideal gas

∴ R = 8.314 E-3 KJ/K.mol

∴ P1 = 90 KPa

∴ P2 = 800 KPa

∴ T1 = 25 °C ≅ 298 K

∴ r He = 2 Kg/min

⇒ (5/2) Ln(T2/T1) = Ln(800/90) = 2.185

⇒ Ln (T2/T1) = 0.874

⇒ T2/T1 = e∧0.874 = 2.3963

⇒ T2 = (2.3963)(298 K) = 714.094 K

⇒ Ws = CvΔT = (3/2 R)(714.094 - 298 ) = 5.1891 KJ/mol

∴ Mw He = 4.0026 g/mol

⇒ Ws = ( 5.1891 KJ/mol)(mol / 4.0026 g)(1000 g/Kg)(2Kg/min)(min/60s)

⇒ Ws = 43.2144 KJ/s

⇒ η = 43.2144 KJ/s / 76 KJ/s = 0.5686

Answer:

[tex]Frequency=2.88\times 10^{14}\ s^{-1}[/tex]

Explanation:

The relation between frequency and wavelength is shown below as:

[tex]c=frequency\times Wavelength [/tex]

c is the speed of light having value [tex]3\times 10^8\ m/s[/tex]

Given, Wavelength = 1040 nm

Also, 1 m = [tex]10^{-9}[/tex] nm

So,  

Wavelength = [tex]1040\times 10^{-9}[/tex] m

Thus, Frequency is:

[tex]Frequency=\frac{c}{Wavelength}[/tex]

[tex]Frequency=\frac{3\times 10^8}{1040\times 10^{-9}}\ s^{-1}[/tex]

[tex]Frequency=2.88\times 10^{14}\ s^{-1}[/tex]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

[tex]-w=\frac{dm}{dt}[/tex]

w is the mass flow

m is the mass of salt

[tex]-v*C=\frac{dm}{dt}[/tex]

v is the volume flow

C is the concentration

[tex]C=\frac{m}{V+(6-3)*L/min*t}[/tex]

[tex]-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}[/tex]

[tex]-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}[/tex]

[tex]-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}[/tex]

[tex]-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}[/tex]

[tex]-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)[/tex]

[tex]-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)[/tex]

[tex]m=90kg*[2000L/(2000L+3*L/min*t)][/tex]

a) Initially: t=0

[tex]m=90kg*[2000L/(2000L+3*L/min*0)]=90kg[/tex]

b) t=210 min (3.5 hr)

[tex]m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg[/tex]

c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

To find the amount of salt initially in the tank, divide the amount of salt by the initial volume of water and multiply by the initial volume of water. After 3.5 hours, find the new amount of salt by subtracting the salt loss and adding the salt gain. As time approaches infinity, the concentration of salt in the tank will approach 0 kg/L.

(a) To find the amount of salt initially in the tank, we use the formula: amount of salt = initial concentration of salt * initial volume of water. The initial concentration of salt can be found by dividing the amount of salt (90 kg) by the initial volume of water (2000 L). So, the initial concentration of salt is 90 kg / 2000 L = 0.045 kg/L. Now, we can find the amount of salt initially in the tank by multiplying the initial concentration of salt by the initial volume of water: 0.045 kg/L * 2000 L = 90 kg.

(b) After 3.5 hours, the amount of salt in the tank can be found using the formula: new amount of salt = initial amount of salt - salt loss + salt gain. The salt loss can be found by multiplying the drain rate (3 L/min) by the time (3.5 hours) and the initial concentration of salt (0.045 kg/L). The salt gain can be found by multiplying the incoming water rate (6 L/min) by the time (3.5 hours) and the concentration of salt in the incoming water, which is 0 kg/L. So, the new amount of salt = 90 kg - (3 L/min * 3.5 hours * 0.045 kg/L) + (6 L/min * 3.5 hours * 0 kg/L). Solve the equation to find the new amount of salt after 3.5 hours.

(c) As time approaches infinity, the concentration of salt in the solution in the tank will approach the concentration of the incoming water (0 kg/L), since the incoming water has no salt. Therefore, the concentration of salt in the tank as time approaches infinity is 0 kg/L.

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Answer:

Hormones

Explanation:

Hormones are chemical messengers released in one part of the body as chemical messengers into the bloodstream to achieve target results in another part of the body. The endocrine system is responsible for regulation of the internal environment (homeostasis).

Answer:

0,33atm

Explanation:

For the reaction:

NH₄HS(s) ⇌ H₂S(g) + NH₃(g)

kp is defined as:

kp = 0.11 = P(H₂S) P(NH₃) (1)

Where P(H₂S) and P(NH₃) are partial pressures of each compound.

In equilibrium, if in your system the only addition is of NH₄HS(s), the partial pressures and the concentration of each compound are:

NH₄HS: I - x

-Where I is an initial concentration that is not relevant for the problem and x is the NH₄HS that reacts-

H₂S(g): x

NH₃(g): x

Replacing in (1):

0.11 = X×X

0.11 = X²

0.33 = X

That means P(NH₃) is 0.33 atm

I hope it helps!

The partial pressure of NH3(g) is  0.33 atm.

Number of moles of NH4HS = 46.5 g/51 g/mol = 0.91 moles

Given that;

PV =nRT

P = ?

V = 5.0−L

n =  0.91 moles

R = 0.082 atm LK-1mol-1

T =  250°C + 273 = 523 K

Making P the subject of the formula;

P = nRT/V

P = 0.91 moles ×  0.082 atm LK-1mol-1 × 523 K / 5.0−L

P = 7.8 atm

We must now set up the ICE table;

              NH4HS(s) ⇌   H2S(g)     +          NH3(g)

I            7.8 atm              0                           0

C           -x                      +x                          +x

E          7.8 - x               x                            x

We know that;

Kp = pH2S  × pNH3

Note that NH4HS is a pure solid and does not get into the equation

Kp = 0.11

0.11 = x^2

x = √0.11

x = 0.33 atm

Since partial pressure of H2S = partial pressure of NH3 = x

The partial pressure of NH3(g) = 0.33 atm.

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Answer:

Partial pressure O₂  = 1.78 atm

Explanation:

We can apply the mole fraction to solve the question:

Moles of gas / Total moles = Partial pressure of gas / Total pressure

Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles

2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm

(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂  → 1.78 atm

Answer:

The partial pressure of oxygen is 1.45 atm

Explanation:

Step 1: Data given

Number of moles of hydrogen = 1 mol

Number of moles of helium = 2.5 mol

Number of moles of oxygen = 2 mol

Total pressure = 4 atm

Step 2: Calcualte total number of moles

Total number of moles = number of moles of hydrogen + number of moles of helium + number of moles of oxygen = 1 + 2.5 + 2 = 5.5 mol

Step 3: Calculate mol fraction of oxygen

Mol fraction oxygen = 2 mol / 5.5 mol = 0.3636

Step 4: Calculate partial pressure of oxygen

Partial pressure of oxygen = mol fraction of oxygen * total pressure

Partial pressure of oxygen = 0.3636 * 4 atm = 1.45 atm

The partial pressure of oxygen is 1.45 atm

Answer: The value of [tex]x_1,x_2,x3\text{ and }x_4[/tex] are 2, 3, 12 and 6 respectively.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

A balanced chemical equation always follow this law.

For the given chemical reaction, the balanced equation follows:

[tex]2C_6H_6+3O_2\rightarrow 12C+6H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of benzene reacts with 3 mole of oxygen gas to produce 12 moles of carbon and 6 moles of water

From the above reaction:

[tex]x_1=2\\x_2=3\\x_3=12\\x_4=6[/tex]

Hence, the value of [tex]x_1,x_2,x3\text{ and }x_4[/tex] are 2, 3, 12 and 6 respectively.

The balanced equation for the complete combustion of benzene is 2C6H6 + 15O2 → 12CO2 + 6H2O, which means x1=2, x2=15, x3=12, and x4=6.

The complete combustion of benzene (C6H6) forms carbon dioxide (CO2) and water (H2O). To balance the chemical equation for this reaction, each atom on the reactant side must be equal to the total number of the same atom on the product side. The chemical equation for the combustion of benzene is:

2C6H6 + 15O2 → 12CO2 + 6H2O

Here, x1 is 2, x2 is 15, x3 is 12, and x4 is 6. Hence, the balanced chemical equation is 2 moles of benzene reacting with 15 moles of oxygen to produce 12 moles of carbon and 6 moles of water.

Answer:

Rh-negative mothers and Rh-positive baby boys.

Explanation:

At least three research studies have proven that Rh incompatibility can be a potential risk factor for schizophrenia, this happens because the mother is Rh-negative (no protein coded) and the fetus is Rh-positive and therefore the mother's immune system responds to the baby's Rh protein leading to hypoxia, anemia and abnormal glial development with a higher risk for baby boys.

I hope you find this information useful and interesting! Good luck!

Answer:

c) 35 fl oz

Explanation:

Hello,

In this case, to compute the recommended amount of calcium that the teenager must drink, one performs the following relationship:

[tex]8.0-fl \ oz -->298mg\\x-->1,300mg[/tex]

Solving for [tex]x[/tex], one gets:

[tex]x=\frac{8.0-fl \ oz *1,300mg}{298mg} \\x=35-fl \ oz[/tex]

Best regards.

Final answer:

To meet the calcium RDA of 1,300 mg, a teenager would need to drink approximately 34.9 fl oz of reduced-fat milk, which is closest to 35 fl oz (answer option c). This calculation involves dividing the RDA by the amount of calcium per 8 fl oz of milk and multiplying the result by 8.

Explanation:

The question involves calculating the quantity of milk required for a teenager to meet their recommended dietary allowance (RDA) of calcium. An 8.0 fl oz glass of reduced-fat milk contains 298 mg of calcium. To determine how many fluid ounces of milk are needed to get the entire recommended amount of calcium, one would divide the RDA of calcium for teenagers, which is 1,300 mg, by the amount of calcium in one glass of milk.

Here is the calculation: 1,300 mg (RDA for calcium) ÷ 298 mg (calcium per glass of milk) = 4.3624161.

Since we cannot have a fraction of a fluid ounce if we are considering actual glasses to be consumed, we round up to the nearest whole number, which would suggest a teenager needs to drink at least 5 glasses of milk. However, in terms of exact fluid ounces needed, it would be 4.3624161 × 8 fl oz = 34.9 fl oz, which is closest to answer option c)

Explanation:

In liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

So, when at 298 K and 1 atm [tex]Br_{2}[/tex] exists in liquid state and [tex]Cl_{2}[/tex] exists as a gas then it means there occurs strong force of attraction between the molecules of [tex]Br_{2}[/tex] due to which it exists in liquid form.

Thus, we can conclude that at 298 K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas. This provides evidence that, under these conditions, the forces among [tex]Br_2[/tex] molecules are greater than those among [tex]Cl_2[/tex] molecules.

The statement that at 298K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas provides evidence that forces among Br2 molecules are greater than those among Cl2 molecules.

FORCE OF ATTRACTION:

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Answer:

d orbital

Explanation:

Given that:-

The principal quantum number, n = 3

The acceptable values of azimuthal quantum number, l are:-

l = 0 , 1 , 2

l = 0 corresponds to s orbital which can accomodate 2 electrons.

l = 1 corresponds to p orbital which can accomodate 6 electrons.

l = 2 corresponds to d orbital which can accomodate 10 electrons.

Thus, the highest energy orbital is: - d orbital

Answer:

Oxygen will dissolve more in H2O at 5 atm and 20 °C than at 5 atm 80 °C

Option B is correct.

Explanation:

Step 1: Data given

Pressure = 5 atm

Temperature = 20 °C or 80 °C

Step 2:

At low pressure, a gas has a low solubility. Decreased pressure allows more gas molecules to be present in the air, with very little being dissolved in solution.  At high(er) pressure, a gas has a high solubility.

This means the higher the pressure the more the gas will dissolve. Since The pressure stays constant, it depends on the temperature.

The solubility of gases in liquids decreases with increasing temperature.

This means the gas will dissolve more with a lower temperature.

Oxygen will dissolve more in H2O at 5 atm and 20 °C than at 5 atm 80 °C

Under the following sets of conditions the most O₂ (g) be dissolved in H₂O(l) is a. 5 atm 80 degree celsius

The most O₂ will dissolve in water under the conditions of 5 atm pressure and 20 °C temperature due to the principles of Henry's Law.

Application of Henry's Law

Given two sets of conditions:

We know that gases are more soluble in liquids at lower temperatures.

Conclusion

Thus, the most O₂(g) would dissolve in H₂O(l) under the conditions of 5 atm and 20 °C.

Correct question is: under which of the following sets of conditions would the most O₂ (g) be dissolved in H₂O(l)?
a. 5 atm 80 degree celsius
b. 5 atm 20 degree celsius