Answer:
The band members of sixth graders are 28.
The band members of seventh graders are 14.
The percentage of the band members eighth graders are 40% .
Step-by-step explanation
Formula
[tex]Percentage = \frac{Part\ value\times 100}{Total\ value}[/tex]
As given
There are 70 students in the school band.
40% of them are sixth graders, 20% are seventh graders, and the rest are eighth graders.
Now first find out the band members are sixth graders .
Percentage = 40%
Total value = 70
Put in the formula
[tex]40 = \frac{Number\ of\ band\ members\ are\ sixth\ graders\times 100}{70}[/tex]
[tex]Number\ of\ band\ members\ are\ sixth\ graders = \frac{40\times 70}{100}[/tex]
[tex]Number\ of\ band\ members\ are\ sixth\ graders = \frac{2800}{100}[/tex]
[tex]Number\ of\ band\ members\ are\ sixth\ graders = 28[/tex]
Therefore the number of band members are from sixth graders are 28 .
Now first find out the band members are seventh graders .
Percentage = 20%
Total value = 70
[tex]20 = \frac{Number\ of\ band\ members\ are\ seventh\ graders\times 100}{70}[/tex]
[tex]Number\ of\ band\ members\ are\ seventh\ graders = \frac{20\times 70}{100}[/tex]
[tex]Number\ of\ band\ members\ are\ seventh\ graders = \frac{1400}{100}[/tex]
[tex]Number\ of\ band\ members\ are\ seventh\ graders = 14[/tex]
Therefore the number of band members are from seventh graders are 14.
Now find out the percentage of the eighth graders of the band members.
Total number of band members = sixth graders members + seventh grade members + eighth graders members
As sixth graders members = 28
seventh grade members = 14
Total number of band members = 70
Put in the above
70 = 28 + 14 + eighth graders members
70 - 42 = eighth graders members
28 = eighth graders members
Put in the percentage formula
[tex]Percentage = \frac{28\times 100}{70}[/tex]
[tex]Percentage = \frac{2800}{70}[/tex]
Percentage = 40%
Therefore the percentage of the band members are eighth graders is 40 %.
Answer:
The band members of sixth graders are 28.
The band members of seventh graders are 14.
The percentage of the band members eighth graders are 40% .
Step-by-step explanation
Formula
As given
There are 70 students in the school band.
40% of them are sixth graders, 20% are seventh graders, and the rest are eighth graders.
Now first find out the band members are sixth graders .
Percentage = 40%
Total value = 70
Put in the formula
Therefore the number of band members are from sixth graders are 28 .
Now first find out the band members are seventh graders .
Percentage = 20%
Total value = 70
Step-by-step explanation:
Therefore the number of band members are from seventh graders are 14.
Now find out the percentage of the eighth graders of the band members.
Total number of band members = sixth graders members + seventh grade members + eighth graders members
As sixth graders members = 28
seventh grade members = 14
Total number of band members = 70
Put in the above
70 = 28 + 14 + eighth graders members
70 - 42 = eighth graders members
28 = eighth graders members
Put in the percentage formula
Percentage = 40%
Therefore the percentage of the band members are eighth graders is 40 %.
A circle has an arc of length 48(3.14) that is intercepted by a central angle of 120°
what is -2 sqrt20 - sqrt125
Answer:
-9sqrt(5)
Step-by-step explanation:
-2 sqrt20 - sqrt125
Lets simplify the square roots
sqrt(ab) = sqrt(a)sqrt(b)
-2 sqrt(4) sqrt(5) - sqrt(25) sqrt(5)
-2 *2sqrt(5) - 5sqrt(5)
-4sqrt(5) -5sqrt(5)
-9sqrt(5)
The taxpayer had a qualifying child who is not disabled and who turned 13 on may 31, 2017. They paid a child care provider to care for the child for the entire year while they worked. How many months of child care expenses can they deduct on their tax return?
Answer:
5 months
Step-by-step explanation:
The taxpayer can only deduct the first five months of the qualifying child. May is the fifth month. On June 1st, the qualifying child is going to be 14 years old. Therefore he cannot be included in work-related expenses as specified in the Publication 503 - Main Content from the IRS. Please see the Working-Related Expenses, Indent (b) which is as follows:
(b) The parent of your qualifying person if your qualifying person is your child and under age 13.
Carolina is mowing lawns for a summer job. For every mowing job, she charges an initial fee plus \$6$6 for each hour of work. Her total fee for a 44-hour job, for instance, is \$32$32. Let F(t)F(t) denote Carolina's fee for a single job FF (measured in dollars) as a function of the number of hours tt it took her to complete it.
Answer:
y=8+6t
Step-by-step explanation:
Answer:
[tex]F(t)=6t+8[/tex].
Step-by-step explanation:
Let t represent number of hours.
We have been given that Carolina charges $6 for each hour of work. So amount charged for t hours of work would be [tex]6t[/tex].
Let us find initial cost by subtracting charges for 4 hours from 32 as:
[tex]\text{Initial cost}=32-4\times 6[/tex]
[tex]\text{Initial cost}=32-24[/tex]
[tex]\text{Initial cost}=8[/tex]
The total cost for t hours of work would be initial cost plus cost per hour: [tex]6t+8[/tex].
Our required function would be [tex]F(t)=6t+8[/tex].
In ?ABC, the measure of ?C=90°, the measure of ?A=30°, and CA = 68 feet. Find the length of BC to the nearest foot
Answer:
39 feet
Step-by-step explanation:
Since the triangle is right we can use the tan ratio to find BC
tan 30° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{BC}{68}[/tex]
multiply both sides by 68
68 tan 30° = BC ⇒ BC ≈ 39 feet ( to nearest foot )
What is the smallest possible integer value of x in order for the product of 720 and x to result in a perfect square?
Answer:
x = 5
Step-by-step explanation:
720 = 2^4 × 3^2 × 5
√720 = 2^2 × 3 × √5
√(720×5) = 2^2 × 3 × 5
sin(x)/1-cos(x) - 1-cos(x)/sin(x) = 2cot(x)
let's recall the pythagorean identity that sin²(θ) + cos²(θ) = 1.
[tex]\bf \cfrac{sin(x)}{1-cos(x)}-\cfrac{1-cos(x)}{sin(x)}=2cot(x) \\\\[-0.35em] ~\dotfill\\\\ \cfrac{sin(x)}{1-cos(x)}-\cfrac{1-cos(x)}{sin(x)}\implies \cfrac{[sin(x)]^2-[1-cos(x)]^2}{sin[1-cos(x)]} \\\\\\ \cfrac{[sin^2(x)]-[1^2-2cos(x)+cos^2(x)]}{sin[1-cos(x)]}\implies \cfrac{sin^2(x)-1+2cos(x)-cos^2(x)}{sin[1-cos(x)]} \\\\\\ \cfrac{sin^2(x)-[\underline{sin^2(x)+cos^2(x)}]+2cos(x)-cos^2(x)}{sin[1-cos(x)]} \\\\\\ \cfrac{sin^2(x)-sin^2(x)-cos^2(x)+2cos(x)-cos^2(x)}{sin[1-cos(x)]}[/tex]
[tex]\bf \cfrac{-2cos^2(x)+2cos(x)}{sin[1-cos(x)]}\implies \cfrac{2cos(x)[-cos(x)+1]}{sin[1-cos(x)]}\implies \cfrac{2cos(x)[\underline{1-cos(x)}]}{sin[\underline{1-cos(x)}]} \\\\\\ \cfrac{2cos(x)}{sin(x)}\implies 2\cdot \cfrac{cos(x)}{sin(x)}\implies 2cot(x)[/tex]
The expression 24(1−x) gives the discounted price of a pair of shorts, where x is the percent of the discount written in decimal form.
What does 1−x represent in the expression?
percent of original price being paid
original price of shorts
discount price of the shorts
percent of discount
Answer:
1-x represents the percent of the original price being paid.
Step-by-step explanation:
The expression 24(1−x) gives the discounted price of a pair of shorts, where x is the percent of the discount written in decimal form.
For example , 10% is the discount percentage
1 - 10% = 90% will be the percentage of original price to be paid
Here x represents the percent of the discount
so 1-x represents the percent of the original price being paid.
Answer:
percent of original price being paid
Step-by-step explanation:
The time a basketball player spends in the air when shooting a basket is called the "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation equals=4t squared 4t2. suppose that a basketball player has a vertical leap of 44 feet 1111 inches. find the hang time for this leap.
Answer: 1.1 seconds
Step-by-step explanation:
leap = 4t² ; leap = 4 ft 11 inches, find t
[tex]4\frac{11}{12} = 4t^2[/tex]
[tex]\frac{59}{12} = 4t^2[/tex]
[tex]\frac{59}{48} = t^2[/tex]
[tex]\sqrt{\frac{59}{12}} = \sqrt{t^2}[/tex]
[tex]\sqrt{1.23} = t[/tex]
1.1 = t
The manufacturer ID number for Proctor and Gamble is (037000) and the item number for a box of Bounce Fabric Softener is (80049). What is the valid UPC?
A) 0-37000-80049-9
B) 0-37000-80049-1
Eliminate
C) 1-37000-80049-1
D) 1-80049-37000-0
Answer:
A) 0-37000-80049-9
Step-by-step explanation:
For a standard bar code, it consists of a five digit manufacturer number and a five digit product number. Check digits are a single digit computed from the other characters in the string of numbers. Check digits are on the far right.
Add the odd number digits: 0+7+0+8+0+9 = 24.
Multiply the result by 3: 24 × 3 = 72.
Add the even number digits: 3+0+0+0+4 =7.
Add the two results together: 72 + 07 = 79.
The last digit is 9
Answer:b
Step-by-step explanation: USA test prep
Verify the identity.
cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided by cotangent of x
Identity to verify:
[tex]\dfrac{\cot x}{1+\csc x}=\dfrac{\csc x-1}{\cot x}[/tex]
Recall that
[tex]\cos^2x+\sin^2x=1[/tex]
Divide both sides by [tex]\sin^2x[/tex] and we get
[tex]\cot^2x+1=\csc^2x[/tex]
or
[tex]\cot^2x=\csc^2x-1=(\csc x-1)(\csc x+1)[/tex]
So if we multiply the numerator and denominator of
[tex]\dfrac{\cot x}{1+\csc x}[/tex]
by [tex]\csc x-1[/tex], we get
[tex]\dfrac{\cot x(\csc x-1)}{(1+\csc x)(\csc x-1)}=\dfrac{\cot x(\csc x-1)}{\csc^2x-1}=\dfrac{\cot x(\csc x-1)}{\cot^2x}[/tex]
Then as long as [tex]\cot x\neq0[/tex], we can cancel terms to end up with
[tex]\dfrac{\csc x-1}{\cot x}[/tex]
and establish the identity.
A gardener is planting two types of trees: Type A is 8 feet tall and grows at a rate of 3 inches per year. Type B is 7 feet tall and grows at a rate of 4 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.
Answer:
Exactly 12 years it will take for these trees to be the same height
Step-by-step explanation:
Slope intercept form: An equation of line is in the form of [tex]y = mx+b[/tex] where m is the slope or unit rate and b is the y-intercepts.
Let x represents the time in years and y represents the height of the tree.
Use conversion:
1 ft = 12 inches
As per the given statement:
Type A is 8 feet tall and grows at a rate of 3 inches per year.
⇒unit rate per year = 3 inches = [tex]\frac{1}{4}[/tex] ft
Then, we have;
[tex]y =\frac{1}{4}x + 8[/tex] ......[1]
Similarly for;
Type B is 7 feet tall and grows at a rate of 4 inches per year.
⇒unit rate per year = 4 inches = [tex]\frac{1}{3}[/tex] ft
then;
[tex]y =\frac{1}{3}x + 7[/tex] .....[2]
To find after how many years it will take for these trees to be the same height.
Since, trees to be the same height;
⇒equate [1] and [2], to solve for x;
[tex]\frac{1}{4}x + 8 = \frac{1}{3}x +7[/tex]
Subtract 7 from both sides we get;
[tex]\frac{1}{4}x + 8-7= \frac{1}{3}x +7-7[/tex]
Simplify:
[tex]\frac{1}{4}x + 1= \frac{1}{3}x[/tex]
Subtract [tex]\frac{1}{4}x[/tex] from both sides we get;
[tex]1= \frac{1}{3}x-\frac{1}{4}x[/tex]
Simplify:
[tex]1 = \frac{x}{12}[/tex]
Multiply both sides by 12 we get;
x = 12
Therefore, exactly it will take for these trees to be the same height is, 12 years
What's the product of 42⁄3 and 111⁄4 ?
A. 83⁄7
B. 56⁄135
C. 442⁄12
D. 521⁄2
Change the mixed numbers to the impropert fractions:
[tex]4\dfrac{2}{3}=\dfrac{4\cdot3+2}{3}=\dfrac{14}{3}\\\\11\dfrac{1}{4}=\dfrac{11\cdot4+1}{4}=\dfrac{45}{4}[/tex]
[tex]4\dfrac{2}{3}\cdot11\dfrac{1}{4}=\dfrac{14}{3}\cdot\dfrac{45}{4}=\dfrac{7}{1}\cdot\dfrac{15}{2}=\dfrac{105}{2}=52\dfrac{1}{2}\to\boxed{D.}[/tex]
Who does this describe? The country was in chaos, but this scholar helped bring order to society through his teachings about family and government relationships, and the Golden Rule.
A. Siddhartha Gautama
B. Ramayana
C. Asoka
D. Confucius
Answer:
The correct answer is D. This statement describes Confucius.
Step-by-step explanation:
Confucius was a Chinese philosopher, whose teachings had a great influence in China, Korea, Japan and Vietnam. According to tradition, he was born in the city of Qufu, in the Kingdom of Lu, now part of Shandong Province. He is said to have become Minister of Justice in Lu's kingdom. After being forced to resign, he toured the small kingdoms of northeast and central China, explaining his ideas about governance.
He emphasizes his philosophy of morality, right social relationships, justice and honesty, both in personal life and in government. During the Han Dynasty period in China, his teachings became the official philosophy of the state. His teachings were introduced to Europe by the Jesuit Matteo Ricci, the first to Latinize his name as "Confucius."
Jewish people light a menorah on each of the 8 nights. On the first night, 1 candle plus the shamash candle is lit. On the second night, 2 candle plus the shamash candle is lit, and so forth. Over the course of Chanukah, how many candles are lit in all??
Answer:
Step-by-step explanation:
General Remark
Let's start with the long way.
Each day 1 traditional candle (shamash) is lit along with a number of candles representing that day of Chanukah. I'm taking it that a new Shamash candle must be used each day.
Total Candles = 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 44
Givens
a = 2L = 9n = 8Formula
Sum = (a + L)*n/2
Solution
Sum = (2 + 9)*8/2Sum = (11)*4Sum = 44If this is wrong can you tell me what assumption I'm making that is incorrect.
Answer: Your answer is Hanukkah
Which number sentence correctly solves this problem? There were 52,165 people at the soccer game on Friday. There were 49,872 people at the game on Saturday. What is the total attendance for the two days? A. 52,165 – 49,872 = 2,293 B. 52,165 – 49,872 = 17,713 C. 52,165 + 49,872 = 92,037 D. 52,165 + 49,872 = 102,037
Answer: D.
Step-by-step explanation:
52,165 + 49,872 = 102,037
A store had 88 diet sodas.The ratio of diet sodas to regular sodas was 8:4.How many regular sodas were there?
Answer:
44
Step-by-step explanation:
diet : regular = 8:4
=> 88:44
Please help! Urgent! Will mark brainliest!
Lamar wanted to explain why the measure of angle 5 is equal to the sum of the measures of angles 1 and 3.
Which geometry concepts should be used in Lamar’s work?
A) supplementary angles and the sum of the measures of interior angles of a triangle
B) complementary angles and the sum of the measures of interior angles of a triangle
C) supplementary angles and vertical angles
D) the sum of the measures of interior angles of a triangle and vertical angles
Answer:
B
Step-by-step explanation:
Because the angles make up the interior parts of the triangle without the extra endings
Answer: The answer would be B
An elephant can run 1/4 of a mile in 36 seconds. At this rate, which expression can be used to determine how fast an elephant runs in miles per hour?
A) 36seconds/1/4 mile = 25 miles per hour
B) 1/4 mile/36 seconds=144 miles per hour
C) 1/4 mile/36 seconds= 25miles per hour
D) 36 seconds/1/4 mile= 144 miles per hour
Answer:
an elephant can run 25 miles per hour
Step-by-step explanation:
60 minutes x 60 seconds = 3,600 seconds in an hour
3600 / 36 = 100
100 x .25 = 25 miles an hour
ughhhh please help me i don’t wanna fail again
Answer:
Step-by-step explanation:
Start with (1,2) . One of the pairs has to begin with a 1. Look around to see which set of points has a 1 for the x value.
B and C do. So all you have gotten rid of is A and D. D looks like it might work, but it really does not. It has - 1 as it's starting point. The point must start with 1.
The next step is to find the distance between the 2 given points. The y value for the two points already on the graph is the same so they do not contribute anything to the distance. -3 and 1 are 4 units apart.
1 and ? must also be 4 units apart. Only D does. 1 and -3 are the x values 2 and 6 are the y values. The answer is B
An object moves according to the law s = t2 + 5t - 8. what is the exact rate of change of s with respect to t when t = 1.5 seconds?
Answer:
ds/dt =8 when t =1.5
Step-by-step explanation:
s = t^2 + 5t - 8
We want to find ds/dt
ds/dt = 2t +5
evaluated when t=1.5
ds/dt = 2(1.5) +5
ds/dt = 3+5
ds/dt =8 when t =1.5
Replace t with 1.5 seconds and solve for s:
s = 1.5^2 + 5(1.5) -8
s = 2.25+7.5-8
s= 9.75 -8
s = 1.75
Rate of change is S/t
Rate of change = 1.75 / 1.5
Rate of change of s = 1.17
Solve the quadratic equation by completing the square.
2x² - 20x + 48 = 0
So firstly, we need to isolate the x terms onto one side. To do this, subtract 48 on both sides of the equation:
[tex]2x^2-20x=-48[/tex]
Next, divide both sides by 2:
[tex]x^2-10x=-24[/tex]
Next, we are gonna make the left side of the equation a perfect square. To find the constant of this soon-to-be perfect square, divide the x coefficient by 2 and then square the quotient. Add the result onto both sides of the equation:
[tex]-10 \div 2=-5\\(-5)^2=25\\\\x^2-10x+25=1[/tex]
Now, factor the left side:
[tex](x-5)^2=1[/tex]
Next, square root both sides of the equation:
[tex]x-5=\pm 1[/tex]
Next, add 5 to both sides of the equation:
[tex]x=5\pm 1[/tex]
Lastly, solve the left side twice -- once with the plus sign and once with the minus sign.
[tex]x=6,4[/tex]
AnswerIn short, x = 6 and 4
Answer: x = 4 x = 6
Step-by-step explanation:
2x² - 20x + 48 = 0
2x² - 20 x + _____ = -48 + ______ subtracted 48 from both sides
2(x² - 10x + _____ ) = 2(-24 + _____ ) factored out 2 from both sides
x² - 10x + _____ = -24 + _____ divided both sides by 2
x² - 10x + 25 = -24 +25 added 25 to both sides
↓ ↑ ↑
[tex]\dfrac{-10}{2}=(-5)^2[/tex] [tex]\bigg(\dfrac{b}{2}\bigg)^2[/tex] makes a perfect square
(x - 5)² = 1 simplified
[tex]\sqrt{(x-5)^2} =\sqrt{1}[/tex] took square root of both sides
x - 5 = ± 1 simplified
x - 5 = 1 x - 5 = -1 split into two separate equations
x = 6 x = 4 solved for x
PLEASE HELP!!
Given: e || f and g is a transversal
Prove: 1 8
Given that e || f and g is a transversal, we know that 4 5 by the alternate interior angles theorem. We also know that 1 4 and 8 5 by the . Therefore, 1 8 by the transitive property.
Answer:
Vertical angle property
Step-by-step explanation:
We are given that e is parallel to f and g is a transversal. Using the alternate interior angles property, ∠4=∠5 which is given.
Since, g is a transversal of the two parallel lines e and f, then ∠1=∠4 and ∠8=∠5 by the vertical opposite angle property.
Hence, ∠1≅∠8 by the transitive angle property.
Answer:
verticle angles theorem
Step-by-step explanation:
hope this helps :)
A 54-kg jogger is running at a rate of 3 m/s. What is the kinetic energy of the jogger? A. 18 J B. 81 J C. 162 J D. 243 J
[tex]\displaystyle\bf\\\text{\bf kinetic energy}=\frac{mv^2}{2}=\frac{54\times3^2}{2}=27\times9=\boxed{\bf243~J} \\\\\text{\bf Correct answer: D.}[/tex]
Answer:
The answer would be be D.243 j
Step-by-step explanation:
Convert Fahrenheit to Celsius is C=5/9(F-32) convert 18c to Fahrenheit
Answer:
-7.77778
If you use google it will help u
is 2i a real or complex root?
By definition, i = sqrt(-1) because it is used to solve the equation x^2+1 = 0 or x^2 = -1, which has no real number solutions.
Since i is imaginary or complex, then so is 2i
You can express it as 2i = 0+2i to be in the form a+bi with a = 0 as the real part and b = 2 as the imaginary component.
WILL GIVE BRAINLIEST
Solve for x
Answer:
6x^2 +81x - 17
---------------------
7x-15
Step-by-step explanation:
We cannot solve for x since this is an expression
((6x+9) (x+12) -sqrt(49+76) ^2
--------------------------------------------
(49+7x) -64
Lets simplify the numerator
((6x+9) (x+12) -sqrt(49+76) ^2
Simplify what is inside the last parentheses
((6x+9) (x+12) -sqrt(125) ^2
Squaring a square root leaves the original number
((6x+9) (x+12) -(125)
FOIL the first two terms
First 6x*x = 6x^2
Outer: 6x*12 = 72x
Inner: 9x
Last : 9*12 = 108
Add them together
6x^2 +72x+9x+108 = 6x^2 +81x+108
Subtract the 125
6x^2 +81x+108-125
6x^2 +81x - 17
Now lets simplify the denominator
(49+7x) -64
49+7x-64
7x-15
6x^2 +81x - 17
---------------------
7x-15
Becki put some stamps into her stamp collection book she put 14 stamps on each page if she completely filled 16 pages how many stamps did she put in the book?
Answer:
224 stamps.
Step-by-step explanation:
We have been given that Becki put 14 stamps on each page.
To find the total number of stamps that Becki put in the book we will multiply the number of stamps put on each page by the number of completely filled pages.
[tex]\text{The total number of stamps in the book}=14\times 16[/tex]
[tex]\text{The total number of stamps in the book}=224[/tex]
Therefore, Becki put 224 stamps in the book.
To find out how many stamps Becki added to her collection, we multiply the number of stamps per page, which is 14, by the number of filled pages, which is 16, resulting in a total of 224 stamps.
To determine how many stamps Becki put into her stamp collection book, we need to calculate the total number of stamps populated over the completely filled pages. She placed 14 stamps on each page and filled 16 pages. The total number of stamps is the product of the number of stamps on each page and the number of pages filled.
The formula we will use is:
Total stamps = Number of stamps per page x Number of filled pages
Substituting the given values:
Total stamps = 14 stamps/page x 16 pages = 224 stamps
Therefore, Becki put 224 stamps in her stamp collection book.
Use the substitution method to solve the system of equations
You solve the substitution method to solve a system of equality by expressing one variable in terms of the other using one equation, and then plugging this expression in the other(s).
In this case, the first equation gives us a way to express n in terms of m. So, we can replace every occurrence of n in the second equation with the given formula.
The result is
[tex] 14m+2n=-8 \iff 14m+2(-7m-4)=-8 \iff 14m-14m-8=-8 \iff -8=-8 [/tex]
So, the second equation turned to be an equality, i.e. an equation where both sides are the same.
This implies that the system has infinitely many solutions, because every couple [tex] (n,m) [/tex] such that [tex] n=-7m-4 [/tex] is a solution to the system, because it satisfies both equations: the first is trivially satisfied, whereas the second is an identity, and as such is satisfied by any value of the variable.
Drag one model next to each situation. The correct model for each group represents that situation
The question involves creating and analyzing scientific models, collaborating in groups to build and refine these models based on experimental evidence, and engaging in critical thinking about their accuracy and limitations.
Explanation:The question involves students creating and analyzing models that represent certain scientific situations. Creating a model is a fundamental part of scientific inquiry as it helps in visualizing and understanding complex concepts. Students are tasked with exchanging and labeling pictures or drawings of their models, which aids in the development of the communication of scientific ideas. They then apply their models to specific situations, test these models, and note the outcomes to assess the accuracy and limitations of the models they have built. This process involves critical thinking, collaboration, and application of scientific knowledge.
Moreover, students are required to modify their models based on experimental evidence and discussions about the limitations of their models. When building models of atoms, for example, students must consider basic ratios, an understanding of atomic structure, and the unique characteristics of the element they are representing.
The complete question is:Drag one model next to each situation. The correct model for each group represents that situation