Ther are 120 crayons and 30 pieces of paper to give to students. what is the largest number of students to have in class so each student gets equal number of crayons and equal number of paper?

The sentence 'k is less than zero' can be translated into the inequality 'k < 0', where 'k' can be any value that is less than zero. The inequality for the word sentence 'k is less than zero' is k < 0.

The sentence 'k is less than zero' can be translated into an inequality as 'k < 0'. This is an inequality to represent a situation where 'k', a variable, takes values that are less than zero. It's a way of understanding the relationship of 'k' to zero in mathematical terms. For example, -1, -2, -3, etc. are all numbers that meet this less than zero inequality because they are less than zero.

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Answer:

Teachers 4 and Students 100, Teachers 5 and Students 125

Step-by-step explanation:

Going by the chart, by each teacher, the students are increasing by 25. The only ones to follow this pattern is 4:100 and 5:25

The approximate solution for the given system of equations y = 2x2 – 2 and y = –0.5x + 4 is C. x = 1. This is the value of x where the two graphs intersect, thus making both equations true.

The question is asking for the solution to the system of equations given by y = 2x2 – 2 and y = –0.5x + 4. Solving a system of equations means finding the value of x that makes both equations true. In other words, we're looking for the point where the two graphs intersect.

To find this value, we can set the two equations equal to each other and solve for x:

2x2 – 2 = -0.5x + 4

This simplifies to 2x2 + 0.5x - 6 = 0. Solving this quadratic equation can give us multiple solutions for x, but since the question is multiple choice, we can check which of the given options is a solution. Plugging the options into the equation reveals that option C. x = 1 is the correct answer, satisfying the equation.

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 1.1      Factoring:  x3-81 

Theory : A difference of two perfect cubes,  a3 - b3 can be factored into
              (a-b) • (a2 +ab +b2)

Proof :  (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0+b3 =
            a3+b3

Check :  81  is not a cube !! 
Ruling : Binomial can not be factored as the difference of two perfect cubes

 1.2    Find roots (zeroes) of :       F(x) = x3-81
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q  then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -81. 

 The factor(s) are: 

of the Leading Coefficient :  1
 of the Trailing Constant :  1 ,3 ,9 ,27 ,81 

 Let us test ....

Polynomial Roots Calculator found no rational roots

 2.1      Solve  :    x3-81 = 0 

 Add  81  to both sides of the equation : 
                      x3 = 81 
When two things are equal, their cube roots are equal. Taking the cube root of the two sides of the equation we get:  
                      x  =  ∛ 81  

 Can  ∛ 81 be simplified ?

Yes!   The prime factorization of  81   is
   3•3•3•3  
To be able to remove something from under the radical, there have to be  3  instances of it (because we are taking a cube i.e. cube root).

∛ 81   =  ∛ 3•3•3•3   =
                3 • ∛ 3 

The equation has one real solution
This solution is  x = 3 • ∛3 = 4.3267 

Answer:

The initial value is  

✔ 1/3

The simplified base is  

✔ 27

The domain is  

✔ all real numbers

The range is  

✔ y > 0

Step-by-step explanation:

To calculate mean and standard deviation for a binomial distribution, use the formulas μ = np and σ = √npq. Ensure both np and nq are greater than five to use the normal approximation.

To find the mean (μ) and standard deviation (σ) for a binomial distribution, you use the formulas μ = np and σ = √npq respectively. Here, 'n' represents the number of trials, 'p' is the probability of success on a single trial, and 'q' is the probability of failure on a single trial, which is calculated as q=1-p.

If you want to determine whether you can use the normal approximation to the binomial, it is essential to ensure that both np and nq are greater than five. This is because the normal approximation is most accurate when the binomial distribution is symmetrical, which typically occurs when both np and nq exceed five.

Yeah it's B:17.8 I agree with you

To determine two numbers where their difference is 16, and their ratio is 5:7, we let the smaller number be 5x and the larger one be 7x, solve for x with the equation 7x - 5x = 16, and find that the numbers are 40 and 56.

To find two numbers with a difference of 16 and a ratio of 5:7, first let's denote the smaller number as 5x and the larger number as 7x. The difference between the two numbers is 16, so we can write the equation 7x - 5x = 16.

Solving for x gives us 2x = 16 or x = 8. Thus, the two numbers we are looking for are 5x = 5 × 8 = 40 and 7x = 7 × 8 = 56.

Check: The difference between 56 and 40 is indeed 16, and the ratio of 40 to 56 simplifies to 5:7, confirming our solution.

volume = l x w x h

1.5 x 1.5 x 1.5 = 3.375 cubic feet

3.375 * 57 = 192.375 pounds

In his piggy bank, Dan has 10 nickels, 20 dimes and 5 quarters.

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

Assume that he had [x] nickels, [y] dimes and [z] quarters. Then we can write -

x = y + 5

x + y + z = 35

x/20 + y/10 + z/4 = 6

Now, the equation → x/20 + y/10 + z/4 = 6, can be written as → (x + 2y + 5z) = 120

We can write, the equations as -

x = y + 5

x + y + z = 35

x + 2y + 5z = 120

Solving the simultaneous equations, we get -

y + 5 + y + z = 35

2y + z = 30         Eq [1]

y + 5 + 2y + 5z = 120

3y + 5z = 115        Eq [2]

Plot Eq[1] and Eq[2] on graph. The point of intersection of both will give the values of y and z.

z = 20

y = 5

We can then find [x] as -

x = y + 5 = 10

x = 10

Therefore, in his piggy bank, Dan has 10 nickels, 20 dimes and 5 quarters.

To solve more questions on equation modelling, visit the link below-

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The volume and the surface area of the rectangular prism will be 66mm and 166mm² respectively.

Length = 11m

Width = 1mm

Height = 6mm

The volume of the rectangular prism will be:

= Length × Width × Height

= 11mm × 1mm × 6mm

= 66mm

The surface area of the rectangular prism will be:

= 2(wl + hl + hw)

= 2(11 + 66 + 6)

= 2(83)

= 166

Therefore, the surface area of the rectangular prism will be 166mm²

In conclusion, the volume and the surface area of the rectangular prism will be 66mm and 166mm² respectively.

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Answer:

Step-by-step explanation: vertical angel

The expression that represents the situation is:

                    $ 600+12x

cost of lot is: $ x

This means that 12 times the lot on which it was built is: $ 12x

Also, it is given that:

A house costs $600 more than 12 times the lot on which it was built.

This means that the total cost of the house is:

600 plus the total cost of the lot on which it was built.

i.e.   The expression that represents the total cost of the house is:

                      $ 600+12x

Answer:  The required number of cups of frozen mango is 1.125.

Step-by-step explanation:  Given that a smoothie recipe calls for [tex]2\dfrac{1}{4}[/tex] cups of frozen mango and the recipe serves two.

We are to find the number of cups of frozen mango that is needed to serve one.

We will be using the UNITARY method to solve the problem.

We have

The number of cups of frozen mango that needs to serve two is

[tex]2\dfrac{1}{4}=\dfrac{9}{4}=2.25.[/tex]

Therefore, the number of frozen mango that needs to serve one is given by

[tex]\dfrac{2.25}{2}=1.125.[/tex]

Thus, the required number of cups of frozen mango is 1.125.