the volume of pyramid shown above is 147.97units and the height is is 9.6 units find the length of one edge of the square base

Answers

Answer 1
The formula fro the volume of a pyramid with a square base is:
Volume = L * L * H / 3
L * L * 9.6 / 3 = 147.97
L * L = (3 * 147.97) / 9.6
L * L = 46.24
Let's take the square root of both sides.
L = sqrt(46.24) = 6.8
The length of one edge of the square base is 6.8 units.

Related Questions

A science experiment begins with a metal at −100° Celsius. The following function describes the temperature change per minute: f(x) = 89x − 100°. How will the graph of this function change if the metal is at 25° at the start of the experiment?

Answers

The function describes the the temperature change per minute:
f ( x ) = 89 x - 100°.
This is the graph of a linear function in the slope-intercept form:
y = m x + b
Starting point is - 100°, so b = - 100°
If the metal is at the temperature of 25° at the start of experiment, then it would be: b = 35°
The new equation: g ( x ) = 89 x + 25°
g ( x )  ||   f ( x )   ( parallel functions ),  25° - ( -100° ) = 125°
Answer: The graph of the function will translate vertically 125° up.  

Answer:

A

Step-by-step explanation:

Jacobysontop!

Over what interval of time in minutes was the jogger heart rate changing at the constant rate

Answers

The jogger was in a consistent rate in 2-3 minutes

We have a graph of the heart rate vs time.

We want to find on what interval the heart rate increases with a constant rate.

That interval is 3min ≤ t ≤ 4 min

The general function that increases with a constant rate is the general linear function:

y = a*x + b

Where a is the slope and also defines the constant rate of change.

Then the interval where the jogger heart rate changes at a constant rate is the part where we have a linear function (not the horizontal line, there the heart rate does not change).

Then the interval where the heart rate changes with a constant rate is:

3min ≤ t ≤ 4 min

If you want to learn more, you can read:

https://brainly.com/question/21670190

Anthony was tracking the increasing number of animals in the zoo. at 9

a.m., there were 56 animals. at 11

a.m., there were 60 animals. if anthony made the function f(x) = 2x − 38, what would the 2 represent? the number of animals at midnight the rate at which the number of animals was increasing the length of time he recorded for the total change in the number of animals

Answers

It’s a little surprising that this question didn’t come up earlier.  Unfortunately, there’s no intuitive way to understand why “the energy of the rest mass of an object is equal to the rest mass times the speed of light squared” (E=MC2).  A complete derivation/proof includes a fair chunk of math (in the second half of this post), a decent understanding of relativity, and (most important) experimental verification.


Answer:

2 would represent the rate at which the animals were increasing

Step-by-step explanation: This all comes back to the slope intercept form:

y = mx + b

2x is the slope, and the slope is the rate of which a point will increase or decrease.


If you had 5 green marbles and 8 red marbles, what's the probability that you'll pull out a marble that is green?

Answers

5+8 = 13 total marbles

5 are green

 so you would have a 5/13 probability of picking a green one

The formula v = (radical)64h can be used to find the velocity v in feet per second of an object that has fallen h feet. Find the velocity of an object that has fallen 23 feet. Round your answer to the nearest hundredth.

A ) 184 feet per second
B ) 306.93 feet per second
C ) 38.37 feet per second
D ) 736 feet per second

Answers

V = sqrt (64h)
V = sqrt (64 * 23)
V = sqrt 1472
V = 38.366 rounds to 38.37 ft <==

Answer:

The answer is the option C

[tex]V=38.37\ ft/sec[/tex]

Step-by-step explanation:

we have that

[tex]V=\sqrt{64h}[/tex]

In this problem we have

[tex]h=23\ ft[/tex]

Substitute in the formula and solve for V

[tex]V=\sqrt{64(23)}[/tex]

[tex]V=\sqrt{1,472}\ ft/sec[/tex]

[tex]V=38.37\ ft/sec[/tex]

There are 10 people in a room. if each person shakes hands with exactly 3 other people, what is the total number of handshakes?

Answers

30 handshakes

10x3=30

if a 24-day single payment loan has a periodic interest rate of 8.4% what is the approximate APR of the loan?
A. 201.6%
B. 127.8%
C. 12.8%
D. 20.2%

Answers

365 days by 24 = 15.20833 periods multiplied by 8.4 % = 127.8%

Answer:

Option B, 127.8%

Step-by-step explanation:

If a 24-day single payment loan has a periodic interest rate of 8.4%.

First we divide 365 by 24 to make periods of 24 days in one year.

365 ÷ 24 = 15.21

periodic interest rate of 8.4%

then Annual Percentage Rate = 15.21 × 8.4 = 1 27.76 ≈ 127.8%

127.8% is the approximate APR of the loan.

if 5(3x-7)=20 then what is 6x-8

Answers

5(3x-7)=20
15x-35=20
15x= 55
x= 55/15
x= 11/3

Plug this x value in.
6(11/3)-8
66/3 -8
22-8
14

Final answer: 14

4x-5=4x+10 solve for x

Answers

Final answer:

The equation 4x - 5 = 4x + 10 has no solution because subtracting 4x from both sides yields -5 = 10, which is a contradiction.

Explanation:

The equation 4x - 5 = 4x + 10 cannot be solved for x in the usual way because attempting to isolate x on one side will result in a contradiction. If we subtract 4x from both sides of the equation, we get -5 = 10, which is not true for any value of x. Therefore, this equation has no solution.

PLEASE HELP!!!!!!!dgbdgdbhdndcn

Answers

Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

Find the 5th term in the expansion of (x – 3y)8

Answers

Not sure what you mean by 5th term, I assume it's the term with the form x^3y^5

Then, you can use combination method:

C(8,3) * (-3)^5 = -13608

So, 5th term is -13608x^3y^5
so..  hmm using the binomial theorem

[tex]\bf (x-3y)^8\implies \begin{array}{llll} term&coefficient&value\\ -----&-----&-----\\ 1&&(x)^8(-3y)^0\\ 2&+8&(x)^7(-3y)^1\\ 3&+28&(x)^6(-3y)^2\\ 4&+56&(x)^5(-3y)^3\\ 5&+70&(x)^4(-3y)^4 \end{array}[/tex]

now... hmmm notice... the first term in the binomial, starts off with a highest exponent of 8, in this case, and the exponent gradually goes down by 1 in each term

whilst for the second term in the binomial, is the opposite, starts off with an exponent of 0, and the exponent gradually goes up in each element

to get the coefficients for the expansion.... well, notice, the coefficient for the expanded 2nd element is always the exponent of the binomial, in this case 8

now, the next element's coefficient is, "the current coefficient, times the exponent of the first term, divided by the exponent of the second term in the next element"

to make it less muddy.... hmmm how did we get +28 for the 3rd element?
well, 8*7/2, coefficient * (first term's exponent) / (second term's exponent on following element)

how did we get 70 for the 5th term?
well 56*5/4

[tex]\bf 70(x)^4(-3y)^4\implies 70x^4[(-3)^4y^4]\implies 70x^4[81y^4]\implies +5670x^4y^4[/tex]

How do you complete the square using fractions

Answers

alrighty
we will complete the squaer for ax²+bx+c=0 regardless of the values of a,b, or c
we will factor it into a(x-h)²=r

so
first group x terms
(ax²+bx)+c=0
factor out a
[tex]a(x^2+\frac{b}{a}x)+c=0[/tex]
take 1/2 of the linear coefinet and squaer it
[tex]\frac{1}{2} \space\ of \space\ \frac{b}{a}=\frac{b}{2a}[/tex]  square it to get [tex]\frac{b^2}{4a^2}[/tex]
add positive and negative of that inside parntheasees
[tex]a(x^2+\frac{b}{a}x+\frac{b^2}{4a^2}-\frac{b^2}{4a^2})+c=0[/tex]
factor perfect square
[tex]a((x+\frac{b}{2a})^2-\frac{b^2}{4a^2})+c=0[/tex]
expand
[tex]a(x+\frac{b}{2a})^2-\frac{b^2}{4a}+c=0[/tex]
and that's how you complete the square, just move the constants over to the left when you're done then divide both sides by a then square root both sides, remembering to take the positive and negative roots

Completing the square with fractions involves transforming the quadratic equation into a perfect square trinomial by adding the square of half the coefficient of x to both sides. This enables solving the equation more easily by then taking the square root of both sides and isolating x.

Completing the square using fractions involves a few steps tailored to work with fractional coefficients. To make it understandable, let's explain the process step by step:

Start with the quadratic equation and ensure it is in the form ax2 + bx + c = 0.Divide all terms by 'a' (the coefficient of x2) if 'a' is not equal to 1, to make the coefficient of x2 equal to 1.Rearrange the equation so that the constant 'c' is on the other side of the equation.Take half of the coefficient of x, which is now 'b/a', and square it. This value is added both sides of the equation to form a perfect square on one side.Rewrite the left side of the equation as a squared binomial.Finally, solve for x by taking the square root of both sides and then add or subtract the constant term.

For example, let's complete the square for the equation x2 + (3/2)x = 4. We take half of the coefficient of x, (3/2)/2 or 3/4, and square it to get 9/16. Adding 9/16 to both sides gives us (x + 3/4)2 = 4 + 9/16. Simplify the right side to get a single fraction, and then proceed to solve for x. Additionally, in some scenarios, we might need to multiply both the numerator and denominator by a skillfully chosen factor, such as 1/2, to facilitate simplifying or cancelling out terms.

Which complex number has a distance of √17 from the origin on the complex plane?
A;2 + 15i
B:17 + i
C:20 – 3i
D:4 – i

Answers

Let the complex number be x + iy

Then by the pythagoras therem

17  = x^2 + y^2

D will satisfy this equation

4^2 + (-1)^2  = 17

answer is D  4 - i

Answer:

The complex number 4-i has distance  [tex]\sqrt{17}[/tex] from origin.

D is correct

Step-by-step explanation:

We are given the absolute value of complex plane.

If complex number is a+ib then absolute value [tex]\sqrt{a^2+b^2}[/tex]

We have to check the absolute value of each option and check which is equal to [tex]\sqrt{17}[/tex]

Option A:  2+15i

[tex]d=\sqrt{2^2+15^2}=\sqrt{4+225}=\sqrt{229}\neq \sqrt{17}[/tex]

Option B:  17+i

[tex]d=\sqrt{17^2+1^2}=\sqrt{289+1}=\sqrt{290}\neq \sqrt{17}[/tex]

Option C:  20-3i

[tex]d=\sqrt{20^2+3^2}=\sqrt{400+9}=\sqrt{409}\neq \sqrt{17}[/tex]

Option D:  4-i

[tex]d=\sqrt{4^2+1^2}=\sqrt{16+1}=\sqrt{17}= \sqrt{17}[/tex]

Hence, The complex number 4-i has distance  [tex]\sqrt{17}[/tex] from origin.

Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, vertex B' has coordinates (5, ?).

Answers

check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
|B'B|=|OB|=10

so by the pythagorean theorem:

[tex]a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3} [/tex] units



Answer: [tex]5 \sqrt{3}[/tex]

The lifetime of a supertough aaa battery is normally distributed with mean of 28.5 hours and standard deviation of 5.3 hours. for a battery selected at random, what is the probability that the lifetime will be 25 hours or less?

Answers

To answer this item, we are first to determine the z-score of the presented data using the equation,

                          z-score = (x - μ) / σ

where x is the data, μ is the mean, and σ is the standard deviation.

Substituting the known values,

                          z-score = (25 - 28.5)/5.3

                          z-score = -0.66

This translates to a percentage equal to 25.46%.

Therefore, from the supertough aaa batteries, approximately 25.46% has a lifetime that is only about 25 hours or less. 

Two numbers, 3 and a, have a geometric mean of 9. Find the value of a.

Answers

The geometric mean of two numbers x and y is √(xy).

So, if the geometric mean of 3 and a is 9 =>

9 = √(3a)

=> 9^2 = 3a

=> a = 9^2 / 3

a = 81 / 3

a = 27

Answer: the value of a is 27.

Examine the graph at right. Then in a sentence suggest why the graph rises at 11:00am and drops at 1:15pm

Answers

The x-axis of the graph is the time while y-axis of the given plot is the money inside Lucy's purse in dollars. we can see that from 6 am to 11 am, Lucy's money is equal to about $60 while around 11 am it rose up to around $125 and then decreased to $100. This means that in the given range of time, only one transaction per time range was done by Lucy. One scenario here was that before lunch, say 11 am, her money was $60 and found out that she has to buy something after work, in which her money was not enough. She went to withdraw some cash that's why she had $125 in total and has to spend a portion of it at lunch with the remaining cash of $100. 

4xy - 9xy + -3xy Simplify the polynomial

Answers

-8xy is the answer to the question

8/3 , 2.28, 10/12 , 0.199 what number in the list above has the greatest value?

Answers

8/3 = 2.666
2.28
10/12 = 0.833
0.199

greatest value is : 8/3

Answer:

[tex]\frac{8}{3}[/tex] is the greatest value.

Step-by-step explanation:

The given numbers are [tex]\frac{8}{3}[/tex], 2.28, [tex]\frac{10}{12}[/tex], 0.199

In this question we have to find out greatest value.

So, first we convert all the values in decimals.

To convert [tex]\frac{8}{3}[/tex] in decimal form, we divide 8 by 3. The answer would be 2.67

2.28

[tex]\frac{10}{12}[/tex] = 0.83

0.199

Now we arrange these numbers in the increasing order.

0.199 < 0.83 < 2.28 < 2.67

So the greatest number is 2.67 that is [tex]\frac{8}{3}[/tex].

A quadratic equation is shown below:

9x2 − 16x + 60 = 0

 Describe the solution(s) to the equation by just determining the radicand. Show your work.

: Solve 4x2 + 8x − 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Answers

hello : 

help :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions

Denise is a professional swimmer who trains, in part, by running. she would like to estimate the average number of miles she runs in each week. for a random sample of 20 weeks, the mean is = 17.5 miles with standard deviation s = 3.8 miles. find a 99% confidence interval for the population mean number of miles denise runs. use a graphing calculator for this one and not the t chart from the book.

Answers

Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval

The degrees of freedom is 
df = n-1 = 19

We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.

The 99% confidence interval is
xbar +/- t*(s/√n)

t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)

Answer: The 99% confidence interval is (15.07, 19.93)
Final answer:

Using a 99% confidence level and the given data, the confidence interval for Denise's average weekly running mileage can be calculated using the sample mean, standard deviation, and z-score for the confidence level.

Explanation:

Denise, a professional swimmer, uses her running mileage as part of her training analysis. To estimate the population mean for the number of miles she runs weekly, we will calculate the 99% confidence interval using the sample mean and standard deviation from her 20 weeks of data. The formula for a confidence interval is:

CI = mean ± (z* × (s/sqrt(n)))

Where mean is the sample mean, z* is the z-score corresponding to the desired confidence level, s is the sample standard deviation, and n is the sample size.

The given data for Denise's running mileage is a mean (μ) of 17.5 miles and standard deviation (s) of 3.8 miles with a sample size (n) of 20 weeks. Since the sample size is greater than 30, we can use the z-distribution to approximate the t-distribution.

To find the appropriate z-score for a 99% confidence interval, we can use a graphing calculator or a z-table. The z-score for a 99% confidence level is approximately 2.576. Plugging the values into the confidence interval formula:

CI = 17.5 ± (2.576 × (3.8/sqrt(20)))

Calculating the margins of error and applying them to the sample mean, we will obtain the confidence interval for the average number of miles Denise runs in a week.

Could someone show me the work for 1/2 divided by 2/3 x 3/4

Answers

[tex]\bf \cfrac{1}{2}\div \boxed{\cfrac{2}{3}}\cdot \cfrac{3}{4}\implies \cfrac{1}{2}\cdot \boxed{\cfrac{3}{2}}\cdot \cfrac{3}{4}\implies \cfrac{1\cdot 3\cdot 3}{2\cdot 2\cdot 4}\implies \cfrac{9}{16}[/tex]

We generally report a measurement by recording all of the certain digits plus​ ______ uncertain​ digit(s).

Answers

We generally report a measurement by recording all of the certain digits plus one uncertain digit.

We generally report a measurement by recording all of the certain digits plus​ one uncertain​ digit.

What are significant figures?

In positional nomenclature, a number's real numbers are its dependable and essential digits for indicating how much of something there is.

If a measurement's result is expressed by a number with more digits than the measurement resolution permits, only those digits up to the measuring resolution's maximum are trustworthy, and only those digits could be significant figures.

Typically, we record all the confirmed digits of measurement together with one questionable digit.

To know more about significant figures:

https://brainly.com/question/29153641

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Which of the following statements is the converse of the statement "If each of two angles has a measure of 28 degrees, then the two angles are equal in measure"?

Answers

the converse would be

If the 2 angles are equal in measure the each of the 2 angles has a measure of 28 degrees.

AS you see in this example , the converse is not necessarily true.

Answer:

If two angles are equal in measure then each of the two angles has a measure of 28 degrees.

Step-by-step explanation:

The converse of a statement is found by switching the hypothesis and conclusion of a conditional statement.

The hypothesis is the part that comes after "if" and the conclusion is the part that comes after "then."

This means the hypothesis is "each of two angles has a measure of 28 degrees" and the conclusion is "the two angles are equal in measure."

This gives us the converse "If two angles are equal in measure then each of the two angles has a measure of 28 degrees."

Solve this equation using an algebraic method: (x + 4)( x - 4) = 9
Help me out please

Answers

You have to FOIL out the (x+4)(x-4) and then subrtract away the 9 in order to get a quadratic that you can solve for x.  As it is, you can't do it.
[tex](x+4)(x-4)= x^{2} -4x+4x-16= x^{2} -16[/tex]
Now if you move the 9 over with it, you get this:
[tex] x^{2} -16-9=0[/tex]
which simplifies to
[tex] x^{2} -25=0[/tex]
Now you can either solve this by recognizing that is the difference of perfect squares, or you can move the 25 over to the other side and take the square root of both sides, like this:
[tex] x^{2} =25[/tex]
[tex] \sqrt{ x^{2} } = \sqrt{25} [/tex]
[tex]x=+/-5[/tex]

If 5+3+2=151012, 9+2+4=183662, 8+6+3=482466, 5+4+5= 202504 , then 7+2+5= ?
a.141035
b.143510
c.143542
d.143524

Answers

A) is the right answer!

Line k is the perpendicular bisector of (line)PQ. If line k intersects (line)PQ at point R, which of the following statements must be true?
check all that apply
A. Line k bisects PQ
B. PR is congruent to QR
C. Line k intersects PQ at a 90 angle
D. Point R is the midpoint of line k
E. Line k is parallel to PQ

Answers

Ok

A B C are correct



          |
          |
_____|_____
          |

Answer:

A. Line k bisects PQ

B. PR is congruent to QR

C. Line k intersects PQ at a 90 angle

Step-by-step explanation:

A perpendicular bisector of a line is a segment that cuts right in the middle a line, and that segment forms a 90º degree angle with the line. This means that the point where the segment cuts the line would be exactly the half, making both resultant segments on the line congruent. So the options that are correct are ABC.

I I'm not good with math

Answers

a) total cost = 499 + 49.99x


b) x = 5 games

 total cost = 499 + 49.99(5) = 499 + 249.95 = 748.95

What do the parallel lines shown on segment BD and segment DC represent?

Answers

it means both sections are equal.

 so BD = 18 and DC = 18

For the function f(x) = –2(x + 3)2 − 1, identify the vertex, domain, and range. The vertex is (3, –1), the domain is all real numbers, and the range is y ≥ –1. The vertex is (3, –1), the domain is all real numbers, and the range is y ≤ –1. The vertex is (–3, –1), the domain is all real numbers, and the range is y ≤ –1. The vertex is (–3, –1), the domain is all real numbers, and the range is y ≥ –1.

Answers

we have

[tex]f(x)=-2(x+3)^{2}-1[/tex]

we know that

the equation of a vertical parabola in vertex form is equal to

[tex]y=a(x-h)^{2}+k[/tex]

where

[tex](h,k)[/tex] is the vertex

If [tex]a > 0[/tex] ------> then the parabola open upward (vertex is a minimum)

If [tex]a < 0[/tex] ------> then the parabola open downward (vertex is a maximum)

In this problem

the vertex is the point [tex](-3,-1)[/tex]

[tex]a=-2[/tex]

so

[tex]-2 < 0[/tex] ------> then the parabola open downward (vertex is a maximum)

The domain is the interval-------> (-∞,∞)

that means------> all real numbers

The range is the interval--------> (-∞, -1]

[tex]y\leq-1[/tex]

that means

all real numbers less than or equal to [tex]-1[/tex]

therefore

the answer is

a) the vertex is the point [tex](-3,-1)[/tex]

b)  the domain is all real numbers

c) the range is [tex]y\leq-1[/tex]

see the attached figure to better understand the problem

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