The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, what is the partial pressure of gas c?

Evaporation and capillary action are required to work together to move water to the top of tall plants. Evaporation is a kind of condensation that happens in the form of a liquid as it transforms into the gas state when it approaches its boiling point.

Temperature, surface area and intermolecular forces are the factors which affect evaporation. Capillary action is the capacity of a liquid to move in confined areas without the help of forces, which are provided by outside like gravitational force which is due to earth.

These two phenomena are required to flow water or liquid to the top of tall plants.

You need evaporation and capillary action to move water to the top of tall plants.

I hope this helps :D

Environmental scientists and specialists are expected to be in demand as public awareness of environmental threats grows. These professionals will still be required to analyze environmental issues and create solutions that protect community health.

Due to the increased effects of climate change we have witnessed over the past ten years, employment opportunities in environmental science are more in demand than ever. Environmental scientists study problems like pollution and deforestation that concern us all.

Environmental scientists are expected to be in greater demand due to the growing need for environmental protection and responsible land and water resource management.

In their research, environmental scientists frequently employ scientific techniques and data analysis. Their conclusions are based on a careful examination of scientific evidence. In their analyses, they must take into account all potential strategies, interactions, and solutions.

Thus, Environmental scientists and specialists are expected to be in demand as public awareness of environmental threats grows.

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The answer is the water will boil. The water boils because of a reduction in the air pressure due to the reduced weight of air column above. This also reduces the collision of water molecules with air molecules at the surface hence allowing the water molecules to easily escape into the atmosphere. This means that the boiling point of the water is easily reached under low air pressure.

The water was at 20°C and when it was subjected to experience reduced pressure in a vacuum chamber where there was no exchange of energy was possible. The system was isolated from the surrounding and when the system was brought to low pressure of less than 18 mmhg the molecules of water expanded and the collision rate between the molecules increased which brought early boiling of the water molecules than normal conditions.

Final answer:

The molarity of acetic acid in the vinegar sample is determined by calculating the moles of NaOH used in the titration, which are equivalent to the moles of acetic acid, and then dividing by the volume of the vinegar sample.

Explanation:

The student's question pertains to the calculation of the molarity of acetic acid (HOAc) in a vinegar sample based on a titration experiment with sodium hydroxide (NaOH). To determine the molarity, we use the volume of NaOH added and the molarity of NaOH to calculate the moles of NaOH, which equals the moles of acetic acid due to the 1:1 stoichiometry in the reaction. The equation is:

Given that the volume of NaOH used is (19.35 mL - 0.15 mL) and the molarity of NaOH is 0.317 M, the calculation is as follows:

Moles of NaOH = (19.35 mL - 0.15 mL) × 0.317 M × (1 L / 1000 mL)

Moles of HOAc = Moles of NaOH

Molarity of HOAc = Moles of HOAc / 0.025 L

NaOH = 19.35 - 0.15 = 19.2 mL 19.2 mL x 0.317 M = 6.086 millimoles NaOH 6.086 mmol NaOH neutralized 6.086 mmol acetic acid 6.086 mmol acetic acid / 25.0 mL = 0.2435 mmol/mL = 0.2435 mol/L Acetic acid was 0.2435 M

Answer:

vinegar is made from the most basic ingredient

Explanation:

The solubility of M(OH)2 in a 0.202 M solution of M(NO3)2 is approximately 0.202 M.

To determine the solubility of M(OH)2 in a 0.202 M solution of M(NO3)2, we need to use the solubility product constant (Ksp) and solve for the molar solubility (M) of M(OH)2.

The equation for the dissolution of M(OH)2 is:

M(OH)2 → M²⁺ + 2OH⁻

Using the given Ksp value of 9.05 x 10-18, we can set up the expression for Ksp:

Ksp = [M²⁺] * [OH⁻]2

Since the molarity of M(NO3)2 is 0.202 M, the concentration of M²⁺ ions is also 0.202 M.

Let's assume the molar solubility of M(OH)2 is M. Therefore, the concentration of OH⁻ ions would be 2M (because of the 2:1 stoichiometric ratio).

Substituting the values into the expression for Ksp and solving for M, we get:

Ksp = (0.202)(2M)2

9.05 x 10-18 = 0.404 M²

Taking the square root of both sides:

M = 0.202 M

Therefore, the solubility of M(OH)2 in a 0.202 M solution of M(NO3)2 is approximately 0.202 M.

Metals lose electrons to become cations, and nonmetals gain those electrons to become anions, with the electrostatic attraction between these oppositely charged ions forming an ionic compound.

When metals bond with nonmetals, electrons are indeed transferred from the metal to the nonmetal, resulting in the formation of an ionic compound. This process involves a metal atom losing electrons to become a cation, which is a positively charged ion, while a nonmetal atom gains those electrons to become an anion, which is a negatively charged ion. The electrostatic attraction between the opposite charges of these ions holds the compound together.

For example, in the formation of sodium fluoride (NaF), sodium (Na) loses one electron to form a Na+ cation while fluorine (F) gains one electron to form an F- anion. The resulting compound, NaF, is stabilized by the strong attractions between the positively charged sodium ions and the negatively charged fluoride ions.

The formation of BF3(g) from its elements in their standard states is described by the equation B(s) + 3F2(g) -> BF3(g). The reaction involves the solid boron reacting with three moles of fluorine gas to form boron trifluoride gas.

The formation of BF3(g) from its elements in their standard states is represented by the following equation:

B(s) + 3F2(g) -> BF3(g)

This equation represents the formation of one mole of boron trifluoride (BF3) gas from boron in its standard state (solid) and fluorine in its standard state (gaseous). In this reaction, solid boron reacts with three moles of fluorine gas to form one mole of boron trifluoride gas. This type of equation is typically used in calculations involving energetics, for example when calculating the standard enthalpy change of formation.

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The formation of boron trifluoride (BF3) from its elements boron (B) and fluorine (F2) in their standard states is represented by the equation: B(s) + 3/2 F2(g) -> BF3(g).

Boron trifluoride (BF3) is formed from its elements boron (B) and fluorine (F2) in their standard states. The equation for the formation of BF3 from its elements in their standard states can be written as:

B(s) + 3/2 F2(g) -> BF3(g).

Here, solid boron (B) reacts with fluorine gas (F2) to form boron trifluoride gas (BF3). This process involves the breaking of F-F bonds in F2 and the formation of new B-F bonds in BF3. The total energy involved in this conversion is equal to the experimentally determined enthalpy of formation of the compound from its elements.

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Answer : The formula for an alkane which contained 42 hydrogen atoms is, [tex]C_{20}H_{42}[/tex]

Explanation :

The general representation of alkane is, [tex]C_nH_{2n+2}[/tex]

As we are given the number hydrogen atoms which is equal to 42. Now we have to determine the number of carbon atoms.

As,

[tex]2n+2=42\\\\2n=42-2\\\\2n=40\\\\n=\frac{40}{2}\\\\n=20[/tex]

Thus, the number of carbon atoms is, 20

Therefore, the formula for an alkane which contained 42 hydrogen atoms is, [tex]C_{20}H_{42}[/tex]

The limiting reactant is substance a because we need 8.85 mol based on the stoichiometry of the reaction, but only have 3.5 mol. Substances b and c have more than needed to react completely with a. Therefore, a is the reactant that will run out first, limiting the amount of product d that can be formed.

To determine the limiting reactant in the chemical reaction 3a+2b+c→2d, we first calculate the number of moles of each substance. We were given 3.5 mol of a, 5.9 mol of b, and 2.2 mol of c. Using the stoichiometric ratios from the balanced chemical equation, we calculate the amount of each reactant needed:

Since 8.85 mol of a is needed but only 3.5 mol is present, a is the limiting reactant. To find the excess reactants, we identify the amount of b and c that would react with the 3.5 mol of a:

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For the reaction shown here, 5.7 mol A is mixed with 3.2 mol B and 2.5 mol C. The limiting reactant is . B

By comparing the mole ratios of reactants A, B, and C to their stoichiometric coefficients, we find that B has the smallest mole ratio, making it the limiting reactant.

For the reaction 3A + 2B + C → 2D, we begin by comparing the mole ratios of the reactants given: 5.7 mol A, 3.2 mol B, and 2.5 mol C.

The limiting reactant is the one with the smallest mole ratio compared to the stoichiometric coefficients.

Since B has the smallest mole ratio (1.60), it is the limiting reactant.

Correct question is: For the reaction shown here, 5.7 mol A is mixed with 3.2 mol B and 2.5 mol C. What is the limiting reactant?
3A+2B+C→2D
a. A.
b. B.
c. C.
d. D

Answer:

[tex]2.46x10^{22}atoms[/tex]

Explanation:

Hello,

In this case, we need to compute the atoms of both phosphorous and oxygen, taking into account the following mass-mole-atoms relationship:

[tex]Molar,mass=31*2+16*5=142g/mol\\atomsP=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{2molP}{1molP_2O_5} *\frac{6.022x10^{23}atomsP}{1molP}=7.04x10^{21}atomsP\\atomsO=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{5molO}{1molP_2O_5} *\frac{6.022x10^{23}atomsO}{1molO}=1.76x10^{22}atomsO[/tex]

Now, by adding each result, we've got:

[tex]atoms=1.76x10^{22}atomsP+7.04x10^{21}atomsO=2.46x10^{22}atoms[/tex]

Best regards.

Final answer:

To find the total atoms in 0.830 g of P2O5, calculate its moles, then multiply by Avogadro's number and atoms per molecule, resulting in approximately 2.46×1022 atoms.

Explanation:

To determine the total number of atoms in 0.830 g of P2O5, we first need to calculate the number of moles of P2O5.The molar mass of P2O5 can be calculated by adding the molar masses of phosphorus (P) and oxygen (O) in the compound. The molar mass of phosphorus is 30.973761 g/mol, and the molar mass of oxygen is 15.9994 g/mol. Therefore, for P2O5:2P: (2 atoms)(30.973761 g/mol) = 61.947522 g/mol5O: (5 atoms)(15.9994 g/mol) = 79.9970 g/mol The molar mass of P2O5 = 61.947522 g/mol + 79.9970 g/mol = 141.944522 g/mol. Now, to find the number of moles of P2O5 in 0.830 g:Number of moles = mass / molar mass = 0.830 g / 141.944522 g/mol = 0.005846 mol. Since one molecule of P2O5 contains 2 atoms of phosphorus and 5 atoms of oxygen, totalling 7 atoms, the total number of atoms in the sample is calculated by multiplying the number of moles by Avogadro's number (6.022×1023 atoms/mol) and then by the number of atoms per molecule: Total number of atoms = 0.005846 mol × 6.022×1023 atoms/mol × 7 atoms/molecule = 2.46×1022 atoms.

When titanium undergoes elctron capture

22Ti + e-  21Sc + Ve

so on electron capture of titanium produces Scandium

so your answer is Sc

To calculate the grams of silane gas, SiH4, formed when 34.9 g of Mg2Si reacts with excess H2O, you need to use the balanced chemical equation and molar ratios. Determine the moles of Mg2Si, then use the molar ratio to find the moles of SiH4. Finally, convert the moles of SiH4 to grams using its molar mass.

To calculate the number of grams of silane gas (SiH4) formed when 34.9 g of Mg2Si reacts with excess H2O, we need to consider the molar ratios between Mg2Si and SiH4 in the balanced chemical equation:

2Mg2Si + 4H2O → 4Mg(OH)2 + SiH4

From the balanced equation, we can see that 2 moles of Mg2Si react to produce 1 mole of SiH4. First, calculate the number of moles of Mg2Si:

Moles of Mg2Si = 34.9 g / (2 * molar mass of Mg2Si)

Then, use the molar ratio to calculate the moles of SiH4 produced:

Moles of SiH4 = Moles of Mg2Si * (1 mole of SiH4 / 2 moles of Mg2Si)

Finally, convert the moles of SiH4 to grams using its molar mass:

Grams of SiH4 = Moles of SiH4 * molar mass of SiH4

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Answer: The equation is written below.

Explanation:

Copper is the 29th element of the periodic table having electronic configuration of [tex][Ar]3d^{10}4s^1[/tex]

When an atom looses an electron to form positive ion, it is called an oxidation reaction.

Copper will loose 1 electron to form +1 ion. The equation for the formation of copper (I) ion from neutral copper atom follows:

[tex]Cu\rightarrow Cu^++1e^-[/tex]

Hence, the equation is written above.

The correct answer is C) of the scientists and ideas that came before him.

Explanation:

Isaac Newton was a prominent physicist mainly known for his theories and ideas regarding gravity, motion, mechanics, among others that are still used today due to their relevance and accuracy. Despite this, Newton recognized in a letter "If I have seen further it is by standing on the shoulders of giants" which suggests Newton felt his theories and ideas were only possible due to previous theories and scientists that build the basis Newton used. Indeed, Newton's predecessors such as Kepler or Galilei were necessary for Newton and also he had the support of contemporary scientists. Thus, in this quote, Newton said that his advances were only possible because of the scientists and ideas that came before him.

The pH of Marco's saliva indicates its acidity, and with a pH of 6.1, the hydrogen ion concentration, [H3O+], is approximately 0.0000008 M.

The subject of your question is related to the concentration of hydrogen ions in a solution, which comes under the field of chemistry. The pH of a solution is a way to measure the acidity or alkalinity of a liquid and is calculated by the formula pH = -log[H3O+]. If Marco's saliva has a pH of 6.1, we can use this formula to calculate the concentration of hydrogen ions, or [H3O+], in his saliva.

To find [H3O+], simply reverse the formula: [H3O+] = 10^-pH. So for Marco's saliva with a pH of 6.1, [H3O+] = 10^-6.1. This gives a hydrogen ion concentration of approximately 0.0000001 M or to seven decimal places, 0.0000008 M.

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The hydrogen ion concentration of Marco's saliva, determined from its pH of 6.1 using the formula [H+] = 10^(-pH), is approximately 7.943 × 10^(-7) Molar. This implies a relatively low concentration of hydrogen ions, indicative of a slightly acidic environment.

The pH of a solution is a measure of its acidity or alkalinity and is defined as the negative logarithm (base 10) of the hydrogen ion concentration. The formula for pH is given by pH = -log[H+], where [H+] is the hydrogen ion concentration.

In the case of Marco's saliva with a pH of 6.1, we can use the formula to find the hydrogen ion concentration.

pH = -log[H+]

6.1 = -log[H+]

To find [H+], we can rewrite the equation as:

[H+] = 10^(-pH)

Substituting the pH value:

[H+] = 10^(-6.1)

Calculating this gives the hydrogen ion concentration:

[H+] = 7.943 × 10^(-7)

Rounded to seven decimal places, the hydrogen ion concentration of Marco's saliva is approximately 0.0000008. Therefore, the hydrogen ion concentration is 7.943 × 10^(-7).

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Explanation:

It is known that when working with an electrical appliance then your hands must be dry because otherwise an electrical shock might occur.

Water is a good solvent and electrons can flow through it easily. Also, your work station must be dry also as it might also lead to an electrical shock.

Your plug must be pull on because otherwise some amount of electric current will still flow into the circuit. And, there are chances of getting an electric shock.

Hence, we can conclude that actions which are appropriate and safe when working with electrical equipment are as follows.

 the answer is that high energy photons are what gamma rays consist of

Answer:

The answer on Ed is C :

VI /n1 = V2 / n2.

Explanation:

Final answer:

To find the pressure at an altitude of 2500 m, set up a proportion using the given pressures at sea level and 1000 m altitude.

Explanation:

The question asks for the pressure at an altitude of 2500 m. We are given that the pressure at sea level is 102.2 kPa and 87.9 kPa at h = 1000 m. Since the rate of change of pressure with respect to altitude is proportional to the pressure itself, we can set up a proportion. Let p be the pressure at 2500 m:

(102.2 kPa - 87.9 kPa) / (0 m - 1000 m) = (p - 87.9 kPa) / (2500 m - 1000 m)

Find the value of p, which gives the pressure at an altitude of 2500 m.

Whether CO or CO₂ is produced when a fuel burns depends on the availability of oxygen; ample oxygen leads to CO₂, limited oxygen to CO. Stoichiometry and bond energies are also important factors in combustion reactions, which release energy used in power and electricity, while also impacting the environment.

The production of either carbon monoxide (CO) or carbon dioxide (CO₂) when a fuel burns is largely determined by the availability of oxygen during the combustion process. In a reaction where there is ample oxygen, such as 2C₈H₁₈ (l) + 25O₂(g) → 16CO₂(g) + 18H₂O(g) + heat, the carbon in the fuel is fully oxidized to CO₂. However, with a limited oxygen supply, incomplete combustion occurs, leading to the production of carbon monoxide. For instance, 2 C (s) + O₂(g) → 2 CO(g) demonstrates how limited oxygen creates a predominance of CO. The precise stoichiometry of reactants and the strength of chemical bonds involved in the reaction play a critical role in the energy released during the combustion process. When we burn fuels such as paraffin, coal, propane, and butane, these chemical changes release huge amounts of energy that we utilize for power and electricity. At the same time, carbon dioxide (a greenhouse gas) is released, impacting the environment negatively.

The chemical reaction involving Mg(OH)2 and HCl is:

Mg(OH)2  +  2HCl  -->  MgCl2  +  2H2O

So we see that for every 2 moles of HCl, 1 mole of Mg is reacted.

Calculating for moles HCl:

moles HCl = 0.300 M * 0.215 L

moles HCl = 0.0645 mol

The moles Mg then is:

moles Mg = 0.0645 mol * (1 / 2)

moles Mg = 0.03225 mol

0.03255 moles of Mg is used for neutralizing 0.3 M 245 ml [tex]\rm Mg(OH)_2[/tex].

The chemical reaction of the reaction of Mg with water yields Magnesium hydroxide.

The neutralization reaction of [tex]\rm Mg(OH)_2[/tex] with HCl will be:

[tex]\rm Mg(OH)_2\;+\;2\;HCl\;\rightarrow\;MgCl_2\;+2\;H_2O[/tex]

For neutralizing 1 mole of magnesium hydroxide 2 moles of HCl are required.

The moles  of HCl in the question are:

moles = [tex]\rm molarity\;\times\;\dfrac{1000}{Volume\;(ml)}[/tex]

moles of HCl = 0.3 [tex]\rm \times\;\dfrac{1000}{215}[/tex]

moles of HCl = 0.0645 moles.

The moles of Mg required are half of HCl.

Moles of Mg = [tex]\rm \dfrac{0.0645}{2}[/tex]

Moles of Mg = 0.03225.

0.03255 moles of Mg is used for neutralizing 0.3 M 245 ml [tex]\rm Mg(OH)_2[/tex].

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The units that express heat capacity are J/ °C; J/K; and cal/ °C

Heat capacity is the amount of heat required to increase the temperature of a determined amount of substance.

As the heat capacity increases, more heat will need to be given to the substance to increase its temperature.

Heat capacity is expressed mathematically as:

[tex]\lim_{\Delta T \to 0} \frac{Heat}{\Delta Temperature}[/tex]

So that means that Heat capacity will have units of Heat (in J or cal) over temperature (in °C or K).

Have a nice day!

its a or J/°C, J/K, cal/°C, cal/K

Explanation: