Answer:
The answer is D~all of these
Solid carbon (C) can burn in oxygen (O2). Select
the answer that completes this chemical equation
correctly.
C + O2 →?
CO2
C+2O
Answer:
The complete chemical equation is as;
C + O₂ → CO₂
Explanation:
According to law of mass conservation the mass in isolated system can neither be created nor be destroyed. Applying this law to given synthesis reaction means that,
(i) If there is one carbon atom on left hand side of the equation (reactant side) then there must be on e carbon on right hand side (product side) of the equation.
(ii) If there are two oxygen atoms on left hand side of the equation (reactant side) then there must be two oxygen atoms on right hand side (product side) of the equation.
Hence, from equation it is proved that it obeys the said law and the number of atoms on both side are equal i.e.
Reactant Side Product Side
Carbon 1 1
Oxygen 2 2
What must be included when descubing the displacement of an object?
Direction
Explanation:
In describing the displacement of a body, the directional attribute must be included or added to it.
Displacement is a vector quantity.
It is a length of path taken from start to finish of the motion of a body.
Coupled with this, the direction of the travel must also be included.
For example, Sam traveled in from Alaska to Florida with a displacement of 1000km south-east.
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If a gas is cooled from 425.0K to 275.15K and the volume is kept constant what final pressure would result if the original pressure was 770.0 mm Hg?
Answer: 498.51mmHg
Explanation:
First let us analyse what was given from the question:
T1 = 425K
T2 = 275.15K
P1 = 770 mmHg
P2 =?
Using the general gas equation
P1V1/T1 = P2V2/T2
But we were told from the question that the volume is constant. So, our equation becomes:
P1/T1 = P2/T2
770/425 = P2 /275.15
Cross multiply to express in linear form:
P2 x 425 = 770 x 275.15
Divide both side by 425, we have:
P2 = (770 x 275.15) /425
P2 = 498.51mmHg
72.0 grams of water how many miles of sodium with react with it?
Answer:
[tex]\large \boxed{\text{8.00 mol}}[/tex]
Explanation:
We will need a balanced chemical equation with masses, moles, and molar masses.
1. Gather all the information in one place:
Mᵣ: 18.02
2Na + H₂O ⟶ 2NaOH + H₂
m/g: 72.0
2. Moles of H₂O
[tex]\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g H$_{2}$O}} = \text{3.996 mol H$_{2}$O}[/tex]
3. Moles of Na
The molar ratio is 2 mol Na/1 mol H₂O.
[tex]\text{Moles of Na} = \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}[/tex]
Final answer:
To find out how many moles of sodium would react with 72.0 grams of water, we calculate moles of water using its molar mass and then apply the stoichiometry of the reaction between sodium and water. We conclude that 4 moles of sodium would react with 72.0 grams of water.
Explanation:
The question appears to contain a typo and seems to ask how many moles of sodium would react with 72.0 grams of water.
Molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, to find out how many moles of water we have in 72.0 grams, we use the formula:
moles of H₂O = mass of H2O / molar mass of H₂O
moles of H₂O = 72.0 g / 18.02 g/mol = 4 moles of H₂O
The reaction between sodium (Na) and water (H₂O) typically forms sodium hydroxide (NaOH) and hydrogen gas (H2). The balanced chemical equation for this reaction is:
2Na + 2H₂O → 2NaOH + H2
From the balanced reaction, we can see that 2 moles of Na are required to react with 2 moles of H₂O. This means, to react with 4 moles of H₂O, we would need 4 moles of Na.
How many Cobalt atoms do you need to have 1245 milligrams of cobalt?
No. of atoms included in 1245 mg is 0.127 *[tex]10^{23}[/tex] atoms.
Answer:
Explanation:
We know that we can determine the number of atoms in any given amount of sample by dividing the given weight to the atomic mass of the particular sample and then multiplying it with avagadro's number.
So, here the atomic mass of cobalt is 58.9 amu.
Thus,
No.of atoms = [tex]\frac{1245 mg}{58.9g} * 6.023 * 10^{23}[/tex]
No. of atoms included in 1245 mg is 0.127 *[tex]10^{23}[/tex] atoms.
As we know that atomic mass of any element contains avagadro's number of atoms. So in order to find the number of atoms in a given weight of sample, we have to follow the above procedure.
No. of atoms included in 1245 mg is 0.127 *[tex]10^{23}[/tex] atoms.
A flask containing 5.98mL of a liquid weighs 163.4 g with the liquid in the flask and 154.9 when empty. Calculate the density of the liquid in g/mL to the correct number of significant digits
Answer:
1.42 g/mL
Explanation:
The mass per unit volume is called as density. It is an intensive property and its value doesn't depend upon the amount of a substance.
It is given as,
Density = Mass / Volume
Data Given:
Mass of Liquid + Flask = 163.4 g
Volume of Liquid = 5.98 mL
Mass of empty Flask = 154.9 g
Mass of Liquid = 163.4 g - 154.9 g = 8.5 g
Formula Used:
Density = Mass / Volume
Density = 8.5 g / 5.98 mL
Density = 1.42 g/mL
histamines are an important chemical in the body . what is their purpose in the immune system
Answer:
Histamine is a protein produced by mast cells in the body. It plays a very important role in the immune system of the body. Histamine is released in the body when affected by an allergen, e.g, pollen or animal dander. The immune system of the body will respond to such allergen by making more mucus in the nose by releasing histamine. There will be sneezing, itching, coughing and runny nose in response. This is a basic defense of the body's immune system to not enter any particle inside the body.
Use the drop-down menus to complete each sentence.
Protists are part of the domain
Protists make up the kingdom
Answer:
protists are part of the domain eukarya
protists make up the kingdom protista
hope this helps x
What is the role of the fungus in the food web shown?
boa constrictor
beetle -
coati
poison dart frog
sloth
strangler fig
fungus
fruit bat
Fungi play a crucial role in the food web shown as they are decomposers. They break down dead organic matter, such as dead plants and animals, and recycle the nutrients back into the ecosystem.
What is the role of microbes in food web system ?Microbes, or microorganisms, play important roles in food webs and ecosystem functioning. They can be found at all trophic levels of the food web, from primary producers to top predators, and their activities have significant impacts on the cycling of energy and nutrients.
In this food web, the fungus likely feeds on dead organic matter produced by the other organisms in the ecosystem, such as the sloth and the fruit bat.
This recycling of nutrients helps to maintain the balance of the ecosystem and supports the growth of other organisms in the food web, such as the strangler fig which may benefit from the nutrients provided by the decomposing organic matter.
Without decomposers like fungi, dead organic matter would accumulate in the ecosystem, leading to nutrient depletion and the eventual collapse of the food web.
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A gas is contained in a thick-walled
balloon. When the pressure changes
from 18.7 psi to 20.2 psi, the volume
changes from 0.475 L to 1.054 L and
the temperature changes from
K to 465 K.
Answer:
T₁ = 194 K
Solution:
Data Given:
Initial Temperature = T₁ = ??
Final Temperature = T₂ = 465 K
Initial Pressure = P₁ = 18.7 psi
Final Pressure = P₂ = 20.2 psi
Initial Volume = V₁ = 0.475 L
Final Volume = V₂ = 1.054 L
Formula Used:
Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,
P V = n R T
where; R = Universal Gas Constant = 0.082057 atm.L.mol⁻¹.K⁻¹,
Taking number of moles and R constant we can have following formula for initial and final states,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for T₁,
T₁ = P₁ V₁ T₂ / P₂ V₂
Putting values,
T₁ = (18.7 psi × 0.475 L × 465 K) / (20.2 psi × 1.054 L)
T₁ = 194 K
Answer:
194 K
Explanation:
A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1." CO 2 + H 2 O C 6 H 12 O 6 + O 2
Final answer:
In a balanced chemical equation, if a coefficient is "1", it is typically left blank. Coefficients are used to ensure the same number of each atom on both sides of the equation and represent relative amounts of reactants and products in the simplest whole-number ratio.
Explanation:
The student's question is about understanding how coefficients are represented in a balanced chemical equation. When balancing chemical equations, it's important to adjust coefficients to ensure the same number of atoms of each element are on both sides of the equation. If a coefficient is "1", it is typically not written explicitly. For example, the balanced chemical equation for photosynthesis is 6CO2 + 6H2O → C6H12O6 + 6O2, where the coefficient of 1 for glucose is understood and therefore left blank. It's also critical to understand that coefficients should be in the simplest whole-number ratio, and they represent the relative amounts of substances involved in the reaction. For instance, when methane reacts with oxygen to yield carbon dioxide and water, the coefficients indicate a ratio of 1:2:1:2 for methane, oxygen, carbon dioxide, and water respectively.
the standard boiling point of an ideal solution of a given composition is a constant or not?
Answer:
The standard boiling point of an ideal solution is 100 degree celsius for a given composition. Mostly all given solution of a given composition is a constant (boiling point 100 degrees) but not all composition is constant.
Explanation:
Answer:
the standard boiling point of an ideal solution of a given composition is constant. The normal boiling point of an ideal solution such as water is 99.97 °C (211.9 °F) at a pressure of 1 atm (i.e., 101.325 kPa).
Explanation:
What are the two main sources of energy in the water cycle?
gravitational energy and thermal energy
kinetic energy and thermal energy
gravitational energy and mechanical energy
hydro energy and gravitational energy
Answer:
Gravitational energy and thermal energy
Explanation:
A water cycle is a product of gravitational energy from the earth and thermal energy from the sun.
A water cycle is driven around with the help of hydroelectric energy. Now hydroelectric energy is a product of potential energy that is converted into kinetic energy, with the help of gravitational energy, which again is also acquired from thermal energy from the sun.
Therefore, the correct answer is gravitational energy and thermal energy.
A piece of jewelry has a mass of 83.2 grams. What is its density?
Answer:
u gotta have the volume of it
Explanation:
cz u need 2 comnues pour appliquer Roe=masse ÷ volumeThe specific heat of fat is 0.45 cal/(g ⋅ °C) (1.9 J/g °C) and the density of fat is 0.94 g/cm30.94 g/cm3. How much energy (in calories and joules) is needed to heat 10 cm310 cm3 of fat from room temperature ( 25 °C25 °C) to its melting point ( 35 °C35 °C)?
Answer:
5878.6 j
1.405 cal
Explanation:
Given data:
Specific heat of fat = 0.45 cal/g.°C or 1.9 j/g.°C
Density of fat = 30.94 g/cm³
Initial temperature = 25°C
Final temperature = 35°C
Energy needed = ?
Volume of fat = 10 cm³
Solution:
First of all we will calculate the mass of fat from given density and volume.
d = m/v
30.94 g/cm³ = m/ 10 cm³
m = 30.94 g/cm³ × 10 cm³
m = 309.4 g
Now we will calculate the energy needed for fat.
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 35°C - 25°C
ΔT = 10°C
Q = m.c. ΔT
Q = 309.4 g . 1.9 j/g.°C . 10°C
q = 5878.6 j
In calories,
5878.6 / 4184 = 1.405 cal
The energy required to heat 10cm3 of fat from 25°C to 35°C is calculated using the specific heat formula. The calculations in calories and joules are 42.3 cal and 178.6 Joules respectively.
Explanation:To calculate the amount of energy needed to heat 10 cm3 of fat from 25 °C to 35 °C, we have to understand the concept of specific heat, which is the energy required to raise the temperature of 1 gram of a substance by 1 °C. Here, we are dealing with the substance fat, which has a specific heat of 0.45 cal/(g ⋅ °C) or 1.9 J/g °C and a density of 0.94 g/cm3.
First, determine the mass of the fat using the formula mass = volume × density. Here, volume is 10 cm3 and density is 0.94 g/cm3, which gives us a mass of 9.4 g. The change in temperature (ΔT) we need is from 25°C to 35°C, hence ΔT = 35 - 25 = 10 °C.
The energy required can then be calculated using the formula energy = mass × specific heat × ∆T. For calories, the calculation is energy = 9.4g × 0.45 cal/(g °C) × 10 °C = 42.3 cal. For Joules, the calculation is energy = 9.4 g × 1.9 J/(g °C) × 10°C = 178.6 Joules.
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Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
1. Did your data support your hypothesis? Use evidence to explain.
2. Which material refracted the light rays the most: air, water, or glass?
3. Which material refracted the light rays the least: air, water, or glass?
4. How does density affect refraction?
5. Diamonds are a very dense material. Predict what would happen to the light ray if you projected it from air through a diamond.
6. Explain where you observe reflection, refraction, and absorption of light in your everyday activities.
1. Yes, the data supported my hypothesis.
2. Water refracted the light rays the most.
3. Air refracted the light rays the least.
4. Density affects refraction because the denser the material, the slower the speed of light in that material.
5. The light ray would be refracted very strongly.
6. Reflection, refraction, and absorption of light can be observed in mirrors, aquariums, and sunglasses.
Summary of lab results:
The light rays were refracted the most when they passed from air into water.The light rays were refracted the least when they passed from air into glass.The density of a material affects how much it refracts light. The denser the material, the more it refracts light.If a light ray is projected from air through a diamond, it will be refracted very strongly.Reflection, refraction, and absorption of light can be observed in many everyday activities. For example, when you look in a mirror, you are seeing a reflection of yourself. When you look at a fish in an aquarium, you are seeing the refraction of light as it passes from the water into the air. And when you wear sunglasses, you are absorbing some of the sunlight, which helps to protect your eyes.
Interpretation of the results:
The results of the lab supported my hypothesis that the denser the material, the more it would refract light. The light rays were refracted the most when they passed from air into water, which is the denser of the two materials. The light rays were refracted the least when they passed from air into glass, which is the least dense of the three materials.
The density of a material affects how much it refracts light because the denser the material, the slower the speed of light in that material. When light travels from a less dense material to a denser material, it slows down and bends towards the normal. When light travels from a denser material to a less dense material, it speeds up and bends away from the normal.
The results of this lab can be used to explain many everyday phenomena, such as why diamonds sparkle so much. Diamonds are very dense materials, so they refract light very strongly. This is why when you look at a diamond, you see a rainbow of colors.
Reflection, refraction, and absorption of light in everyday activities:
Reflection, refraction, and absorption of light are all around us in our everyday activities. Here are a few examples:
Reflection: When you look in a mirror, you are seeing a reflection of yourself. This is because the mirror reflects light back to your eyes.Refraction: When you look at a fish in an aquarium, you are seeing the refraction of light as it passes from the water into the air. This is why the fish appears to be in a different location than it actually is.Absorption: When you wear sunglasses, you are absorbing some of the sunlight. This helps to protect your eyes from the harmful effects of the sun's raysTo learn more about refraction, here
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Final answer:
In the lab investigation, glass refracted light the most, air the least, and density was found to significantly affect the degree of light refraction. A light ray passing through a diamond would exhibit a substantial amount of refraction due to the diamond's high density.
Explanation:
Conclusion: Interpretation of Lab Results
To conclude the investigation on refraction phenomena, it is essential to analyze the data collected and compare it to our initial hypothesis. When examining whether the data supported the hypothesis, it is crucial to reference specific evidence from the experiment. The hypothesis, in this case, may have been concerning the relationship between density and refraction of light through different materials.
Regarding which material refracted light rays the most, glass typically has a higher index of refraction compared to air and water, indicating that light rays bend more when passing through glass. Conversely, air refracted the light rays the least among the three because it has the lowest density and index of refraction.
Density is directly related to refraction; denser materials have higher indexes of refraction and therefore bend light to a greater degree. Given that diamonds are highly dense, a light ray projected from air through a diamond would undergo significant refraction, resulting in a high degree of bending.
In daily life, reflection can be observed in mirrors, refraction when looking at objects submerged in water, and absorption when objects do not reflect or transmit light visibly. Recalling these phenomena can aid in understanding their application and significance.
Find the mass . 2.40 mol NaOH
Answer:
Explanation:
5.6 mol
Answer: 96g
Explanation:
To find the mass of 2.40mol of NaOH, we must first obtain the molar mass of NaOH. This is illustrated below:
Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol
From the question, we were asked to find the mass of 2.4moles of NaOH. This is done by the formula:
Mass = number of mole x molar Mass
Mass of NaOH = 2.4 x 40
Mass of NaOH = 96g
For the reaction
CH3OH + O2 → HCO2H + H2O ,
what is the maximum amount of HCO2H
which could be formed from 8.02 mol of
CH3OH and 15.49 mol of O2?
368.92 g of HCOOH could be formed.
Explanation:
First we have to write the balanced equation as,
CH₃OH + O₂ → HCOOH + H₂O
Here the question said that 8.02 mol of CH₃OH and 15.49 mol of O₂.
In the above reaction methanol and oxygen is used in 1:1 ratio, but the moles are lesser in case of methanol, so CH₃OH is the limiting reagent.
Now by making use of 8.02 moles of methanol, we can produce 8.02 mol of HCOOH.
Molar mass of HCOOH is 46 g/mol.
So mass of HCOOH formed is moles ×molar mass of HCOOH.
8.02 moles × 46 g/mol = 368.92 g of HCOOH could be formed.
What madd of boron trifluoride can be made from 30.0g of fluorine
Mass of boron trifluoride is 35.768 g.
Firstly we need to write the balanced chemical equation involved in this question:
[tex]2B(s)+ 3F_2(g)[/tex] → [tex]2BF_3(g)[/tex]
It is given that:
Mass of fluorine= 30.0 g
So, we need to calculate moles of Fluorine
∵ Molar mass of fluorine= 38 g/mol
[tex]n= \frac{m}{M} = \frac{30.0g}{38 gmol^{-1}} = 0.789 mol[/tex]
Now, for 3 moles of F₂ ; 2 moles of BF₃ are produced.
So, for 0.789 moles of F₂, number of moles of BF₃ will be:
[tex]\frac{2}{3} *0.789=0.526 \text{mol}[/tex]
Moles of BF₃ =0.526 mol
∵ Molar mass of boron trifluoride =67.8 g/mol
Thus, mass of boron trifluoride can be calculated as:
[tex]m=n*M= 0.526*67.8=35.662 g[/tex]
⇒Mass of boron trifluoride is 35.768 g.
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Not among the offered possibilities as the closest option is 53.0 grams. Using the stoichiometry of the balanced chemical equation for the reaction between boron (B) and fluorine to make boron trifluoride, we can calculate the mass of boron trifluoride (BF₃) that can be produced from 30.0 grams of fluorine (F₂).
The chemical formula is B + 3 F₂ BF₃, which is balanced.
One mole of boron combines with three moles of fluorine to form one mole of boron trifluoride, as shown by the equation.
First, we must change the amount of fluorine from grams to moles: (30.0 grams F₂) / (38.00 grams/mole F₂) = 0.789 moles F₂.
According to the stoichiometry, 3 moles of fluorine are converted into 1 mole of boron trifluoride. As a result, the amount of BF₃ that was created is similarly 0.789 moles.
Finally, by utilizing its molar mass, we can determine the mass of BF₃:
53.49 grams BF₃ are equal to (0.789 moles BF₃) times (67.81 grams/mole BF₃).
As a result, 30.0 grams of fluorine may be used to produce around 53.49 grams of boron trifluoride.
The estimated number is not exactly matched by any of the available response options. The response would be: Not among the offered possibilities as the closest option is 53.0 grams.
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Decomposition NH3 =
Answer:
h2*
Explanation:
A car travels at 70 mi/h and uses gasoline at a rate of 11 km/L. How many gallons of
gas are needed for a 3.0 hours trip?
The car would need approximately 7.73 gallons of gasoline for a 3.0-hour trip at a speed of 70 mi/h, and fuel efficiency of 11km/L.
Explanation:To calculate how many gallons of gas are needed for a 3.0-hour trip, we must first figure out the total distance the car travels. With a speed of 70 miles per hour (mi/hr), the car would cover 70 mi/hr x 3 hours = 210 miles.
Next, we will have to convert miles to kilometers since the fuel consumption rate is given in kilometers per liter (km/L). So, 210 miles ≈ 321.87 kilometers (using conversion factor 1 mile ≈ 1.60934 kilometers).
The car uses gasoline at a rate of 11 kilometers per liter. Therefore, it would consume 321.87 kilometers ÷ 11 km/L ≈ 29.26 liters of gas.
Finally, since gas is usually measured in the U.S. in gallons, we need to convert liters to gallons. 29.26 liters ≈ 7.73 gallons (using conversion factor 1 liter ≈ 0.264172 gallons).
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Calculate the mass (in grams) of 3.913 x 1023 molecules of AICI3
Answer: 85.8 g AlCl3
Explanation:
Convert molecules of AlCl3 to moles using the Avogadro's number
Convert moles of AlCl3 to mass using its molar mass.
3.913x10²³ molecules AlCl3 x 1mole AlCl3 / (6.022x10²³ molecules AlCl3) X 132g AlCl3/ 1 mole AlCl3
= 85.8 g AlCl3
The Pfund series of lines in the emission spectrum of hydrogen corresponds to transitions from higher excited states to the n = 5 orbit. Calculate the wavelength of the second line in the Pfund series to three significant figures. In which region of the spectrum does it lie?
Answer:
[tex]\large \boxed{\text{4650 nm}}[/tex]
Explanation:
The second line in the Pfund series corresponds to a transition from n = 7 to n = 5.
To calculate the wavelength of the transition, we can use the Rydberg equation:
[tex]\dfrac{1}{\lambda} = R_{H}\left ( \dfrac{1 }{n_{1}^{2}} - \dfrac{1 }{n_{2}^{2}} \right )[/tex]
where
[tex]R_{H} = 1.097 \times 10^{7} \text{ m}^{-1}[/tex]
If n₁ = 5 and n₂ = 7
[tex]\begin{array}{rcl}\dfrac{1}{\lambda} & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{1 }{5^{2}} - \dfrac{1 }{7^{2}} \right )\\\\ & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{1 }{25} - \dfrac{1 }{49} \right )\\\\ & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{49 - 25 }{49 \times25}\right )\\\\& = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{24 }{1225}\right )\\\\ & = & 2.149 \times 10^{7}\text{ m}^{-1}\\\end{array}\\[/tex]
[tex]\begin{array}{rcl}\lambda & = & \dfrac{1}{2.149 \times 10^{7}\text{ m}^{-1}}\\\\ & = & 4.65 \times 10^{-6} \text{ m}\\ & = & \mathbf{4650} \textbf{ nm}\\\end{array}\\\text{The wavelength of the line is $\large \boxed{\textbf{4650 nm}}$, which is in the $\textbf{infrared region}$}.[/tex]
The calculated wavelength for the second line in the Pfund series is 4.65 x 10^-6 m (4650 nm), positioning it within the infrared spectrum.
Rydberg Equation:
The Rydberg equation is employed to calculate the wavelength (λ) of light emitted or absorbed during electronic transitions in hydrogen-like atoms.
"1/λ = RH (1/n₁² - 1/n₂²)"
Given Values:
We are given the Rydberg constant (RH) as "1.097 x 10^7 m^-1" and the principal quantum numbers (n₁ = 5 and n₂ = 7).
Substitute Values:
Substituting the known values into the Rydberg equation:
"1/λ = 1.097 x 10^7 (1/5² - 1/7²)"
Evaluate Exponents:
Calculating the squares in the denominators:
"1/λ = 1.097 x 10^7 (1/25 - 1/49)"
Find Common Denominator:
Combining the fractions over a common denominator (1225):
"1/λ = 1.097 x 10^7 (49 - 25)/1225"
Combine Terms:
Simplifying the expression:
"1/λ = 1.097 x 10^7 (24/1225)"
Calculate:
Performing the multiplication:
"1/λ = 2.149 x 10^7 m^-1"
Reciprocal to Find Wavelength:
Taking the reciprocal to find the wavelength:
"λ = 1/(2.149 x 10^7)"
Final Result:
Converting the numerical result to scientific notation:
"λ = 4.65 x 10^-6 m"
= 4650nm
This detailed calculation ensures a comprehensive understanding of each step involved in determining the wavelength.
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WILL MARK BRAINLIEST
Write a paragraph that explains the difference and similarities between solid, liquid, and gas particle motion.
Answer:
They all vibrate, but they all move differently.
Explanation:
Similarities: They all consist of particles and vibrate, just at different frequencies.
Differences: The particles in solids move slowly and vibrate. In liquids, they move a bit quicker and slide past one another. They will also take the shape of the container they're in. In gases, they move freely at high speeds and also taking the shape of the container.
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What is the electrical charge of an atom that has LOST one electron?
Question 3 options:
A)
Positive
B)
Negative
C)
Neutral
Answer:
positive
Explanation:
lost of negative electron leaves one more positive charges than negative charges.
A 12.5L container of neon had a pressure change
from 937.57 Pa to 262 52 Pa What is the new
volume?
Answer: V= 44. 6 L
Explanation: use Boyle's Law
P1V1 = P2V2
Derive to find V2:
V2 = P1V1 / P2
= 937.57 Pa( 12.5 L ) / 262.52 Pa
= 44.6 L
Which gas law (choices are Charles’ Law, Gay-Lussac’s Law, or Boyle’s Law) explains each scenario:
Air bags help lessen injuries in an automobile crash.
A helium balloon decreases in size when you put it into a freezer.
A can of spray paint will explode if tossed into a fire
Air bags help lessen injuries in an automobile crash. --> Boyle's law
A helium balloon decreases in size when you put it into a freezer. --> Charle's law
A can of spray paint will explode if tossed into a fire --> Gay Lussac's Law
Explanation:
- Boyle's law states that for a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas (p) is inversely proportional to its volume (V):
[tex]p \propto V[/tex]
- Charle's law states that for a fixed mass of an ideal gas kept at constant pressure, the volume of the gas (V) is proportional to its absolute temperature (T):
[tex]V\propto T[/tex]
- Gay-Lussac's Law states that for a fixed mass of an ideal gas kept at constant volume, the pressure of the gas (p) is proportional to the absolute temperature (T):
[tex]p\propto T[/tex]
We can now use these three laws to explain the mentioned phenomena:
Air bags help lessen injuries in an automobile crash. --> Boyle's law. In fact, as the volume of the gas inside the air bag increases, the pressure exerted by the gas inside decreases, and since the temperature is constant, the pressure exerted by the airbag on the passenger will be lower.
A helium balloon decreases in size when you put it into a freezer. --> Charle's law. When the balloon is put into the freezer, its temperature decreases, and since the pressure inside the freezer is approx. constant, the volume of the balloon decreases as well.
A can of spray paint will explode if tossed into a fire --> Gay Lussac Law. Due to the fire, the temperature of the gas inside the can increases; since the volume is constant, the pressure will increase, and at some point it will be large enouth to cause the can to explode.
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The scenarios involving air bags, helium balloons in a freezer, and an exploding can of spray paint are explained by Gay-Lussac's Law and Charles's Law, relating to the pressure, temperature, and volume of gases.
Explanation:The gas laws that explain each scenario provided are based on the relationships between pressure, volume, and temperature for a gas.
Air bags helping to lessen injuries in an automobile crash is explained by Gay-Lussac's Law, which relates pressure and temperature at constant volume.A helium balloon decreasing in size when put into a freezer is an example of Charles's Law, as it involves the correlation between volume and temperature at constant pressure.The explosion of a can of spray paint when tossed into a fire is again due to Gay-Lussac's Law, where the temperature increase leads to a pressure increase in a confined space potentially causing an explosion if the pressure exceeds the can's ability to contain it.how does sweating help us to keep our body cool ?
Answer:
Sweat gland release moisture on the skin, cooling and relaxing the skin
Explanation:
Sweat gets sunken into your skin so it won't evaporate much.
Sweat is mainly water with a little bit of salts.
Whenever sweat evaporates, it tends to cool down the skin.
What compounds break up into ions in solution?
A. Compounds with both the () and (aq) state symbols
O
O
B. Compounds with both the (s) and (aq) state symbols
c. Only compounds with the (aq) state symbol
O
O
D. Only compounds with the (1) state symbol
Answer:
only compounds with the (aq) state symbol
Only compounds with the an aqueous (aq) state symbol break up into ions in solution.
What is an aqueous solution?The solution in which water is present as solvent. The solute dissolved in water and form an ions which is surrounded by water molecules.
What is compounds?The substance formed by the combination of the two or more different chemical elements is called compounds.Example: Water(H2O), Carbondioxide(CO2), sodium chloride(NaCl) etcTo learn more about aqueous solution here.
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How many liters of carbon monoxide at STP are needed to react with 4.80 g of
oxygen gas to produce carbon dioxide?
2CO(g) + O2(g) → 2C02(g)
6.72 L of Carbon Monoxide (CO) is needed.
Explanation:
First from the mass of the oxygen in grams is converted into moles and then it is proportionate to the moles of CO and then it is converted into its Volume in litres ( L).
4.8 g of O₂ × 1 mol of O₂× 2 mol CO ×22.4 L CO / (32 g of O₂ × 1 mol of O₂ × 1 mol of CO) = 6.72 L CO
The volume of CO reacted with oxygen at STP has been 6.72 L.
The moles of reactant and product in a balanced chemical equation has been given by the stoichiometric coefficient.
The balanced chemical equation for the formation of carbon dioxide has been:
[tex]\rm 2\;CO\;+\;O_2\;\rightarrow\;2\;CO_2[/tex]
Computation for the volume of CO reactedThe balanced chemical equation has been giving the information of 2 moles of CO reacted with a mole of oxygen.
The available moles of oxygen in 4.80 g has been:
[tex]\rm Moles\;=\;\dfrac{Mass}{Molar\;mass}\\\\ Moles\;O_2=\dfrac{4.80}{32}\\\\ Moles\;O_2=0.15\;mol[/tex]
The available moles of oxygen has been 0.15 mol.
The moles of CO reacted has been given by the stoichiometric coefficient of the balanced equation as:
[tex]\rm 1\;mol\;O_2=2\;mol\;CO\\0.15\;mol\;O_2=0.30\;mol\;CO[/tex]
The moles of CO reacted has been 0.30 mol.
The volume of a mole of gas at STP has been 22.4 L. The volume of 0.30 mol CO has been:
[tex]\rm 1\;mol=22.4\;L\\\\0.30\;mol=\dfrac{22.4}{1}\;\times\;0.30\;L\\\\ 0.30\;mol=6.72\;L[/tex]
The volume of CO reacted with oxygen has been 6.72 L.
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