Answer:
8 and 13
Step-by-step explanation:
8+13 = 21
13-8 = 5
Please help and show work!!
A(1, 1), B(7, 1), C(1, 9)
AB = 7 - 1 = 6
AC = 9 - 1 = 8
Use the Pythagorean theorem:
AB² + AC² = BC²
Substitute:
BC² = 6² + 8²
BC² = 36 + 64
BC² = 100 → BC = √100 → BC = 10
The perimeter of ΔABC:
P = 6 + 8 + 10 = 24
Answer: 24 unitsGiven the function ƒ(x) = x 2 - 4x - 5
Identify the zeros using factorization.
Draw a graph of the function. Its vertex is at (2, -9).
Answer:
Zeros of the given function are x=5 and x=-1.
Step-by-step explanation:
f(x)=x^2-4x-5
f(x)=x^2+1x-5x-5
f(x)=x(x+1)-5(x+1)
f(x)=(x-5)(x+1)
To find zeros, we need to set f(x)=0
0=(x-5)(x+1)
0=(x-5) or 0=(x+1)
0=x-5 or 0=x+1
5=x or -1=x
Hence zeros of the given function are x=5 and x=-1.
We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.
That will give the final graph as attached below:
for x=0,
f(x)=x^2-4x-5
f(0)=0^2-4(0)-5
f(0)=0-0-5
f(0)=-5
Hence first point is (0,-5)
Similarly we can find more points.
Can someone please help me with these 3 answers. aiaf you can not see them make sure to click on the image.
School cafeteria holds 200 students mr Thompson’s class has 22 students who eat lunch in the cafeteria how many more students can still eat in the cafeteria when mr tomposons class has lunch
Answer: 198 students
Step-by-step explanation:
220-22=198students
Final answer:
After subtracting Mr. Thompson's class size of 22 students from the school cafeteria's capacity of 200, 178 students can still eat in the cafeteria.
Explanation:
The student's question pertains to the capacity of the school cafeteria and how many more students can be accommodated when a specific class is having lunch. If the cafeteria holds 200 students and Mr. Thompson's class has 22 students, we can calculate the number of additional students that can still eat in the cafeteria by subtracting Mr. Thompson's class size from the total capacity of the cafeteria.
To solve this, we perform the following subtraction:
Capacity of cafeteria - Number of students in Mr. Thompson's class = Number of remaining spots
200 - 22 = 178
Therefore, 178 students can still eat in the cafeteria when Mr. Thompson's class is having lunch.
WILL MARK BRAINLIEST!!!!
can anyone please answer all 6 questions? please it's realky important :) thank you so much xx
i will also give you a follow :)
Roger Ratkin, the owner of Roger’s Subs, has three employees who earn $500, $550, and $700, respectively. How much does Roger owe for the first 12 weeks for SUTA and FUTA? Assume a SUTA rate of 5.3% and a FUTA rate of .8%.
To calculate SUTA and FUTA for the first 12 weeks, calculate the taxable wages for each employee. Multiply the taxable wages by the respective tax rates to find the amount owed. Roger owes $371 for SUTA and $56 for FUTA for the first 12 weeks.
Explanation:To calculate the amount that Roger owes for SUTA (State Unemployment Tax Act) and FUTA (Federal Unemployment Tax Act) for the first 12 weeks, we need to calculate the taxable wages for each employee. The taxable wages for SUTA is the first $7,000 and for FUTA is the first $7,000 as well.
Since the three employees earn $500, $550, and $700 respectively, their total wages for the first 12 weeks would be $17,100 (12 weeks x ($500 + $550 + $700)). However, since SUTA and FUTA only consider the first $7,000 of wages, we can calculate the amount for each tax.
For SUTA, the total taxable wages would be $7,000. Using the SUTA rate of 5.3%, we can calculate the amount owed: $7,000 x 0.053 = $371.
For FUTA, the total taxable wages would also be $7,000. Using the FUTA rate of 0.8%, we can calculate the amount owed: $7,000 x 0.008 = $56.
Therefore, Roger owes $371 for SUTA and $56 for FUTA for the first 12 weeks for his three employees.
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The box plots below show the ages of college students in different math courses
Answer:
The statement that most accurately represents the data given is the 'The mean and median age are more likely to be the same for the students in Math 1.'
Step-by-step explanation:
The box and whisker plots given for the two sets of data show a few different things. Box and whisker plots first show us the median in a given set of data, which is the line in the middle of the box. For both Math 1 and Math 2, this line occurs at 19. The whiskers that extend from the box on either side represent the range, or lowest and highest numbers, in the data. For Math 1, the range is 17-21 and for Math 2, the range is 17-23. Since the range is more evenly distributed in Math 1, we can conclude that the mean, or average of the data, is most likely the same as the median of the data, which is 19.
Answer:
its d
Step-by-step explanation:
its d
What is the slope and y-intercept of the line represented by the equation below? 13x+8y=12
Answer:
see explanation
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 13x + 8y = 12 into this form
subtract 13x from both sides
8y = - 13x + 12 ( divide all terms by 8 )
y = - [tex]\frac{13}{8}[/tex] + [tex]\frac{3}{2}[/tex] ← in slope-intercept form
with slope m = - [tex]\frac{13}{8}[/tex] and y-intercept c = [tex]\frac{3}{2}[/tex]
Ari stocks shelves at a grocery store.He puts 35 cans of juice in each display case.The case has 4 shelves with an equal number of cans,and one shelf with only 3 cans.How many cans are on each of the equal shelves?
Answer:
There are 8 cans on each of the equal shelves
Step-by-step explanation:
Total number of cans put in display = 35
Shelves with equal no of cans = 4 Shelves
And one shelf displays only 3 cans
Therefore, 4 shelves with equal no of cans + 1 shelf with 3 cans = 35 cans
Let us assume equal no. of cans be x
We get, 4x + 3 = 35
4x = 35 - 3
4x = 32
x = 32 ÷ 4
x = 8
Thus, 4 shelves with equal no of cans contains 8 cans each.
If the Greatest Common Factor of L and M is 6, write the expression for the Least Common Multiple of these numbers.
Answer:
[tex]\frac{(L x M)}{6}[/tex]
Step-by-step explanation:
The greatest common factor is the greatest number that will divide two values. We have two values L and M. Each has numbers which multiply together to give the number. The highest value or most in common they share is 6. This is the GCF.
The least common multiple is the smallest positive number which is a multiple of the two. This means both L and M divide into it evenly.
We know L x M is a multiple because L and M will be factors of it. But we don't know its the least.
As an example if L= 42 and M = 60, they have GCF 6. We can multiply them to find a multiple 42 x 60 = 2520 but we don't know this is the smallest or least multiple we can find. If we divide by the GCF, 2520/6=420. Interestingly, 42 x 10 =420 and 60 x 7 =420. This means 420 is the least common multiple.
We can multiply (L x M) and then divide by the GCF of L & M to find the least common multiple.
[tex]\frac{(L x M)}{6}[/tex]
m ∠E = 60° and m ∠G = 85° what is m ∠L?
A: 180°
B: 45°
C: 35°
D: 85°
Answer:
The answer is C: 35°
Step-by-step explanation:
The sum of all angles in a triangle is 180°
So, 180°-(60°+85°)
= 180°-145°
= 35°
m∠L = 35°
Hope it helps!
please!!! help, urgent math problem!
Answer:
1
Step-by-step explanation:
Slope = change in y / change in x
Y-values: 9 and 2
x-values: 3 and -4
Change is the difference
9-2)/(3- (-4)) = 7/7 = 1
Answer:
The slope is 1
Step-by-step explanation:
To find the slope, we use the formula
m = (y2-y1)/(x2-x1)
where (x1,y1) and (x2,y2) are the points on the line
m = (9-2)/(3--4)
= (9-2) /(3+4)
= 7/7
=1
The slope is 1
Emergency !!
What is the value of X?
will give brainly
Answer:
83
Step-by-step explanation:
Theorem:
The measure of any exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.
The angle measuring x is an exterior angle.
The angles measuring x - 39 and x - 44 are the remote interior angles to the exterior angle.
According to the theorem:
x - 39 + x - 44 = x
2x - 83 = x
x - 83 = 0
x = 83
480 divided by 8 with remainder
Answer:
That would be 60, and there isn't a remainder.
Step-by-step explanation:
480÷8
Since there are 6 8's in 48, it would be that but you would add a zero, since it is four hundred. Hope this helps!
Answer: 60
Step-by-step explanation:
Set up the long division.
2 Calculate 48 ÷ 8, which is 6.
3 There is no remainder. We are done. Add ending zeroes to the final answer.
What is the equation of a line with a slope of -4 and a point (-2,5) on the line
Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept
Answer:
The equation of the line would be y = -4x - 3
Step-by-step explanation:
To find any equation when you have the slope and a point, start with point-slope form and then solve for y.
y - y1 = m(x - x1)
y - 5 = -4(x + 2)
y - 5 = -4x - 8
y = -4x - 3
Can you help me on this?
Answer:
y = 30
Step-by-step explanation:
We can use ratio's to solve this
40 20
----- = -----------
100 20 + y
Using cross products
40 * (20+y) = 20*100
Distribute
800 + 40y = 2000
Subtract 800 from each side
40y = 2000-800
40y = 1200
Divide by 40
y = 1200/40
y =30
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club
members decide to send 9 juniors to a tournament, how many different
possibilities are there?
2.) How many different ways can 3 cards be drawn from a deck of 52
cards without replacement?
3.) How many different ways can 3 cards be drawn from a deck of 52
cards with replacement?
4.) A corporation has 5 officers to choose from which 3 are selected
to comprise the board of directors. How many combinations are there?
5.) A combination lock has the numbers 1 to 40 on each of three
consecutive tumblers. What is the probability of opening the lock in
ten tries?
Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
The questions deal with computing combinatorial possibilities such as selecting members for a Chess Club tournament, drawing cards from a deck with and without replacement, determining the number of combinations for a board of directors, and calculating the probability of opening a combination lock within a limited number of tries.
1. Chess Club tournament possibilities: This can be calculated using the combination formula. The number of ways to select 9 juniors from 16 is given by the formula C(n, k) = n! / (k!(n-k)!) where n is the total number of items, and k is the number of items to choose. In this case, it is C(16, 9).
2. Ways to draw 3 cards without replacement: This also uses the combination formula because the order of drawing doesn't matter. It is C(52, 3).
3. Ways to draw 3 cards with replacement: Since each draw is independent and the card is replaced each time, it's simply 52 x 52 x 52 = 1,40,608.
4. Combinations for a board of directors: Choosing 3 officers from 5 to form a board is C(5, 3).
5. Probability of opening a combination lock: The total number of combinations is 40 x 40 x 40. With ten tries, the probability of opening the lock on each try is 1/64000.
Thus the probability of opening within ten tries is 10/64000.
find the number of scarfs of length half metre that can be made from Y metres of cloth
Answer:
2Y is the number of scarfs of length half metre that can be made from Y metres of cloth.
Step-by-step explanation:
To find the number of scarfs of length half metre that can be made from Y metre of cloth.
As per the given condition:
we have:
[tex]\text{Length of 1 scarf} = \frac{1}{2} m[/tex]
then;
Number of scarfs that can be made from Y metre of cloth = [tex]\frac{Y}{\frac{1}{2} } = Y \times 2 = 2Y[/tex]
Therefore, number of scarfs of length half metre that can be made from Y metres of cloth is, 2Y
Donna is ordering chocolate chip cookies for her company's picnic. The cookies are sold in packages of 6. She needs 336 cookies. How many packages should Donna buy?
Step-by-step explanation:
To find how many packages Donna should buy, we need to solve 336/6.
According to the question, there are 6 cookies in a package. This means that to find the number of packages Donna has to buy, we have to divide the the number of cookies per package, 6, from the total number of cookies, 336.
Step 1. (This is the only thing you need to do!)
336 ÷ 6 = 56 packages
If you want to double check your answer, just multiply 6 (the number of cookies) by 56 (the number of packages). This shows us how many cookies we'll get by buying 56 packages, which each have 6 cookies.
6 × 56 = 336 cookies
56 packages, which have 6 cookies each, will give us 336 cookies. Our answer is correct! :)
Karla, Ruby, Anna, and Megan each had a balance of $0 in her bank account on the first day of April. Here are their account balances on the second day:
Karla: $43
Ruby: -$25
Anna: -$48
Megan: $42
Whose account had the greatest change between the first and second days?
A.
Karla's
B.
Ruby's
C.
Anna's
D.
Megan's
PLZZ Healp
Answer:
Anna
Step-by-step explanation:
Compare the answers, and when you do that then you can see that anna had more money come in then the others.
Simplify each expression by combining like terms.
x^2 + x(x - y) + 10xy
x^2 + x(x - y) + 10xy
Distributive property.
x^2 + x^2 - xy + 10xy
Combine like terms.
2x^2 + 9xy
Factor x out of each term.
x(2x + 9y) is the fully simplified form of the original expression.A 3 mi cab ride cost $3.00 . A 6 mi can ride cost $4.80 find a linear equation that modes cost c as a function of distance d.
Answer:
c = 0.6d + 1.2
Step-by-step explanation:
Use distance as the independent variable and cost as the dependent variable. Each point (x, y) is (distance, cost).
The 3 mile ride for $3.00 gives you point (3, 3).
The 6 mile ride that cost $4.80 gives you point (6, 4.8).
Now you need to find the equation of the line that passes through points
(3, 3) and (6, 4.8).
y = mx + b
m = slope = (y2 - y1)/(x2 - x1) = (4.8 - 3)/(6 - 3) = 1.8/3 = 0.6
Use point (3, 3).
y = 0.6x + b
3 = 0.6(3) + b
3 = 1.8 + b
b = 1.2
The equation is
y = 0.6x + 1.2
Use c for cost and d for distance to get
c = 0.6d + 1.2
find the equation of a line with the given points.(put your answers in the form y=mx+b)(6,2)(5,5)
The slope-intercept form: y= mx + b
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (6, 2) and (5, 5). Substitute:
[tex]m=\dfrac{5-2}{5-6}=\dfrac{3}{-1}=-3[/tex]
Therefore we have y = -3x + b.
Put the coordinates of the point (5, 5) to the equation:
5 = -3(5) + b
5 = -15 + b add 15 to both sides
20 = b
Answer: y = -3x + 20Answer:
y = -3x + 20
Step-by-step explanation:
(a) Slope
The point-slope formula for a straight line is
y₂ - y₁ = m(x₂ - x₁) Insert the points
2 - 5 = m(6 - 5)
-3 = m×1
m = -3
=====
(b) y-intercept
y₂ - y₁ = m(x₂ - x₁)
y₂ - 5 = -3(x₂ - 5) Remove parentheses
y₂ - 5 = -3x₂ - 15 Add 5 to each side
y = -3x + 20
Which of the following expressions is equal to 2x^(2)+8?
(2x-4i)(x-2i)
(2x-4i)(x-2i)
(2x+4i)(x+2i)
(2x_2i)(x+6i)
Answer:
The expression equal to 2x^(2)+8 is:
First option (2x-4i)(x+2i)
Step-by-step explanation:
If we multiply
(2x-4i)(x+2i)=(2x)(x)+(2x)(2i)-(4i)(x)-4i(2i)
(2x-4i)(x+2i)=2x^(1+1)+4xi-4xi-8i^(1+1)
Simplifying:
(2x-4i)(x+2i)=2x^2-8i^2
and i^2=-1, then:
(2x-4i)(x+2i)=2x^2-8(-1)
Multiplying:
(2x-4i)(x+2i)=2x^2+8
Answer: (2x-4i)(x+2i)
Step-by-step explanation:
Consider functions f and g below.
f(x) = -9x^2 - 7x + 12
g(x) = 3x^2 - 4x - 15
Find f(x) - g(x).
A. -12x^2 - 11x - 3
B. 6x^2 - 11x + 27
C. -6x^2 + 3x - 3
D. -12x^2 - 3x + 27
Answer:
D
Step-by-step explanation:
f(x) - g(x) = -9x^2 - 7x + 12 - (3x^2 - 4x - 15) Remove the brackets
f(x) - g(x) = -9x^2 - 7x + 12 - 3x^2 + 4x + 15
f(x) - g(x) = -9x^2 - 3x^2 - 7x + 4x + 12 + 15
f(x) - g(x) = -12x^2- 3x + 27
Answer D
Answer:
Option D. -12x² - 3x + 27
Step-by-step explanation:
The given functions are f(x) = -9x² - 7x + 12 and g(x) = 3x² - 4x - 15
We have to find the value of f(x) - g(x)
f(x) - g(x) = (-9x² - 7x + 12) - (3x² - 4x - 15)
= -9x² - 7x + 12 - 3x² + 4x + 15
= (-9x² - 3x²) - (7x - 4x) + 12 + 15
= -12x² - 3x + 27
This value of f(x) - g(x) matches with option D.
Therefore, Option D. is the correct option.
A box of spaghetti at the grocery store is purchased for $1.60 wholesale and is marked up by 60 percent. Then, the store marks down the item by 20 percent. A customer wants to buy three boxes of spaghetti. How much will the customer pay, including paying 8 percent sales tax? Round your answer to the nearest cent.
Answer:
the answer is $8.29
Step-by-step explanation:
1.60 marked up by 60% in decimal form is .60
multiply that .60 by 1.60 and you get .64
you add .64 to 1.60 and you get 2.56
you multiply 2.56 by 3 and you get 7.68
you have a 8% sales tax so you multiply 0.08 by 7.68
you will get .61 you add that to 7.68 to get $8.29
Answer:
$6.64
Step-by-step explanation:
When the price of an item is marked up by a percentage, the new price (after markup) is result when the product of the percentage and the original price added to the original price.
The price after markdown is similar to the mark up except that the product of the percentage and the original price is subtracted from the original price.
Hence when a box of spaghetti at the grocery store is purchased for $1.60 wholesale and is marked up by 60 percent, the new price
=60% * $1.60 + $1.60
$2.56
If the store marks down the item by 20 percent, then the new price becomes
= $2.56 - 20% * $2.56
= $2.048
If a customer wants to buy 3, the price
= $2.048 * 3
= $6.144
Including 8% tax, the price becomes
=$6.144 + 8% * $6.144
= $6.63552
To the nearest cent
= $6.64
Darragh has a Golden Eagle coin in his collection with a mass of 13.551. An uncirculated Golden Eagle coin has a mass of 13.714g.
Answer:
0.163
Step-by-step explanation:
The mass difference between Darragh's Golden Eagle coin and an uncirculated one is 0.163g. This difference could be from various factors including wear and tear, oxidation, or minor variations in the minting process.
Explanation:The question relates to the difference in mass of an uncirculated Golden Eagle coin and one that is in Darragh's collection. First, we need to calculate the difference in mass. The mass of the uncirculated Golden Eagle coin is 13.714g and the mass of Darragh's Golden Eagle coin is 13.551g. By subtracting Darragh's coin mass from the uncirculated coin mass, we get a difference of 0.163g.
This means that Darragh's Golden Eagle coin is 0.163g lighter than an uncirculated one. This difference could be due to factors like wear and tear from handling the coin over time, oxidation, or even from slight variations within the minting process itself. As with any other measurement, there will be a minor uncertainty that should be considered in scientific contexts.
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help need more help in geometery
Answer:
can you post the question
Step-by-step explanation:
first ask the question
Answer:
What type of geometry? What is your question? Or are you looking for tutoring?
Step-by-step explanation:
Find the product write your answer in exponential form 6^9*6^9
Answer:
[tex]6^{18}[/tex]
Step-by-step explanation:
if the base is same we can add the exponential terms
her base is same which is 6. so we can add exponential terms
therefore
[tex]6^{9+9}[/tex]
[tex]6^{18}[/tex]
Hi! See the image attached
How many cubes with an edge length of 1/3 inch are needed to build a cube with an edge length of 1 inch?
The number of cubes needed with an edge length of [tex]\bold{\dfrac{1}{3}}[/tex] inches is needed to build a cube with an edge length of 1 inch is 27.
Given to us,the edge length of smaller cube, a = [tex]\bold{\dfrac{1}{3}}[/tex] inches
the edge length of the cube to be built, S = [tex]\bold{\dfrac{1}{3}}[/tex] inches
Volume of a Cubewe know that volume of a cube is given by (side)³.
[tex]\bold{Volume\ of\ cube = (side)^3}[/tex]
Volume of the smaller cubeVolume of the smaller cube = (edge length of the smaller cube)³
= a³
= [tex]\bold{(\dfrac{1}{3})^3}[/tex]
= [tex]\bold{\dfrac{1}{27}}[/tex] in.³
Volume of the cube to be buildVolume of the cube to be build = (edge length of the cube to be built)³
= S³
= 1³
= 1 in.³
solving,
Cubes of smaller length are needed for the larger cube
[tex]\bold{=\dfrac{Volume\ of\ the\ Larger\ cube}{Volume\ of\ the\ Smaller\ cube}}[/tex]
[tex]\bold{=\dfrac{1}{\dfrac{1}{27}}}[/tex]
[tex]\bold{=27}[/tex]
Hence, the number of cubes needed with an edge length of [tex]\bold{\dfrac{1}{3}}[/tex] inches is needed to build a cube with an edge length of 1 inch is 27.
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