The submarine is traveling at a depth of 152 feet below sea level. The submarine was given instructions to rise 63 feet and then drop 84 feet. Write an expression that describes this situation

Answers

Answer 1
The expression should be -152+63-84

Related Questions

How do I solve 9a-7=110

Answers

You'll need to isolate 9a on the left side of this equation
Please add 7 to both sides of the eqn, obtaining 9a = 117.

Solve for a by dividing both sides by 9:  a = 117/9 = 13 (answer)
[tex]9a-7=110[/tex] 

[tex]9a=110+7 [/tex] 

[tex]9a=117 [/tex] 

[tex]a= \dfrac{117}{9} [/tex] 

[tex]a=13[/tex]

Hey guys, I need help answering this question for my Algebra 2 class.

Answers

Put into standard form:  y^2 - 20x - 6y - 51 = 0
We can see immediately that this is a horiz. parabola, because y is squared, not x.  Because y^2 and x are both positive, we know that the parabola opens to the right.  Where is the vertex?

y^2 - 6y + 9 - 9 -51 = 20 x (after completing the square)
Then (y-3)^2 - 60 = 20x, or   (1/20)(y-3)^2 -3 = x, or (1/20)(y-3)^2=x+3
The vertex is at (-3,3).  


Comparing       (1/20)(y-3)^2=x+3   to   x-h = 4p(y-3)^2, we see that p = 1/80

The focus is p units to the right of the vertex, at (-3+1/80, 3).

The directrix, a vertical line, is p units to the left of the vertex, at x = -3-1/80.

Please ask questions if need be.

Convert 4 fluid ounces of soap per quart of water to cups of soap per gallon of water.

Answers

Attached a solution and showed work.

The perimeter of a rectangular field is 264 yards. If the width of the field is 54 yards, what is its length?

Answers

P = 2(L + W)
P = 264
W = 54

264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards
First, we must multiple the width by two. Then, we subtract the perimeter by that number. Next, we divide the number we have by two.

54 * 2 = 108
264 - 108 = 156
156 / 2 = 78

The perimeter is 78 yards.

a skirt that usually sells for $40 is on sale for $30. What is the discount percent?
A) 20%
B) 25%
C) 27%
D) 30%

Answers

That would be B) 25% off. Hope this helps!
Using "x" as the unknown, the equation would be 40x=30. Solving for x, you get ".75" or 75% meaning that 30 is 75% of 40. The discount, is just the difference between "x" and 100%, so 100%-75% is 25%. The answer is (B) 25%.

How to find the sum of the forces in the y direction of an elevator?

Answers

The way to calculate the sum of the forces in the y direction of an elevator; has been outlined below

Equilibrium of Forces

If you are in an elevator by itself, then the combined system of you and the elevator could have 3 possible situations which are;

The elevator has no acceleration because it is standing still or moving with constant velocity.The elevator has an upward acceleration because it is accelerating upward, or decelerating while it's way down.The elevator has a downward acceleration since it is accelerating down, or decelerating while on the way up.

Now, in the vertical y direction, there are three forces namely;

The force of gravity.A downward normal force.An upward force from the tension in the cable holding the elevator.

Thus, the sum of forces in the y-direction with the normal force acting on you from the elevator are any of the following;

N = mg;  provided that the elevator is at rest or moving at constant velocity.

N = mg + ma; Provided that the elevator has an upward acceleration.

N = mg - ma; Provided that the elevator has a downward acceleration.

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Final answer:

In an elevator at rest, the sum of the forces in the y direction is equal to the weight of the person.

Explanation:

If the elevator is at rest, the sum of the forces in the y direction is equal to zero. This means that the upward force exerted by the scale, Fs, must be equal to the downward force exerted by the weight of the person, w. According to Newton's third law, Fs and Fp (the force exerted by the person on the scale) are equal in magnitude and opposite in direction.

To find the value of Fs, we can apply Newton's second law, which states that the net force in the y direction is equal to the mass of the object times its acceleration. In this case, the net force is Fs - w and the acceleration is zero. Therefore, Fs = w.

So, the sum of the forces in the y direction of the elevator is equal to the weight of the person.

In the 30-60-90 triangle below side s has a length of ___ and the hypotenuse has a length of

Answers

 this is a right-angled triangle. 
so, h^2 = s^2 + 1 
 


However, if we have two sides of the same length, we should have a isosceles triangle, meaning that two of the angles are the same. However, this is not the case here. 

 the only possible answer is , s = sqrt(3) and h = 2

In a 30-60-90 triangle, the side opposite the 30-degree angle (s) has a length of "s," and the hypotenuse has a length of "2s."

The side opposite the 60-degree angle is "s√3."

We have,

In a 30-60-90 triangle, the sides are in a specific ratio:

x, x√3, and 2x,

where x is the length of the shortest side (opposite the 30-degree angle).

Step 1:

Identify the shortest side (opposite the 30-degree angle).

Let's assume the length of the shortest side (opposite the 30-degree angle) is "s."

Step 2:

Find the other side lengths.

The side opposite the 60-degree angle is s√3.

The hypotenuse is twice the length of the shortest side, so it is 2s.

Thus,

In a 30-60-90 triangle, the side opposite the 30-degree angle (s) has a length of "s," and the hypotenuse has a length of "2s."

The side opposite the 60-degree angle is "s√3."

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Manuel stores his favorite CDs in a box like the one shown

Answers

Volume equals = (length)(height)(width) so V= (15)(7)(10)

An investment firm recommends that a client invest in bonds rated AAA, A, and B. The average yield on AAA bonds is 4%, on A bonds 6%, and on B bonds 11%. The client wants to invest twice as much in AAA bonds as in B bonds. How much should be invested in each type of bond under the following conditions?
A.  The total investment is $26,000, and the investor wants an annual return of $1,620 on the three investments.
B.  The values in part A are changed to $38,000 and $2,360, respectively
A.  The client should invest $(?) in AAA bonds, $(?)in A bonds, and $(?)in B bonds.

Answers

Part A.

1) Variables:

X: amount invested in AAA bonds

Y: amount invested in A bonds

Z: amount invested in B bonds.

2) Return:

4%* X + 6% * Y + 11% * Z = 1620

3) Investment:

 X + Y + Z = 26,000

4) Ratio between AAA and B bonds.

X = 2*Z

5) Solution of the system of equations:

Replace X with 2Z in the two first equations:

2Z * 4% + Y * 6% + Z * 11% = 1620

=> 0.08Z + 0.06Y + 0.11Z = 1620

=> 0.19Z + 0.06Y = 1620

2Z + Y + Z = 26,000

=> 3Z + Y = 26,000 => Y = 26,000 - 3Z

Replace Y with 26,000 - 3Z

0.19Z + 0.06(26,000 - 3Z) = 1620

0.19Z + 1560 - 0.18Z = 1620

0.01Z = 1620 - 1560

0.01Z = 60

Z = 60 / 0.01 = 6000

=> X = 2*6000 = 12,000

=> Y = 26,000 - 12,000 - 6,000 = 8,000

Answer: 12,000 in bonds AAA, 8,000 in bonds A, and 6000 in bonds B.

Part B.

2) Return:

0.04X + 0.06 Y + 0.11Z = 2360

3) Investment:

 X + Y + Z = 38,000

4) Ratio between AAA and B bonds.

X = 2Z

5) Solution of the system of equations:

Replace X with 2Z in the two first equations:

=> 0.08Z + 0.06Y + 0.11Z = 2360

=> 0.19Z + 0.06Y = 2360

2Z + Y + Z = 38,000

=> 3Z + Y = 38,000 => Y = 38,000 - 3Z

Replace Y with 38,000 - 3Z

0.19Z + 0.06(38,000 - 3Z) = 2360

0.19Z + 2280 - 0.18Z = 2360

0.01Z = 2360 - 2280

0.01Z = 80

Z = 80 / 0.01 = 8000

=> X = 2*8000 = 16,000

=> Y = 38,000 - 16,000 - 8000 = 14,000

Answer: 16,000 in AAA bonds, 14,000 in A bonds, and 8,000 in B  bonds.

subtract the fractions and simplify the answer 7 8/9-5 3/5

Answers

One way in which to do this problem would involve subtracting 5 from 7 (result:  2) and then subtracting 3/5 from 8/9.
To subtract 3/5 from 8/9, you'd need to find the lowest common denominator (LCD) of 3/5 and 8/9, convert both fractions to have this LCD, and then subtract.

The LCD is (5)(9)=45.  Then 8/9 and 3/5 become 40/45 and 27/45.

Subtracting 27/45 from 40/45 results in the fraction 13/45.
Then the full solution is  2 13/45.

You could also do this problem by converting  7 8/9    and   5 3/5 into improper fractions:

71/9 - 28/5.  Again, the LCD is 45.  Can you rewrite both fractions with 45 as the common denominator and then perform the subtraction?
Final answer:

To subtract the fractions 7 8/9 and 5 3/5, first convert them into improper fractions. Then, adjust them to the common denominator (45 in this case) and subtract to get the answer of 2 13/45.

Explanation:

To begin, we need to convert these mixed fractions (7 8/9 and 5 3/5) into improper fractions. 7 8/9 equals 71/9 (since 7*9 + 8 = 71) and 5 3/5 equals 28/5 (since 5*5 + 3 = 28). Now, we can subtract these fractions by finding a common denominator or a number that 9 and 5 mutually divide into. This number is 45. Therefore, we adjust these fractions to have the denominator of 45, getting 355/45 and 252/45. The subtraction of these adjusted fractions equals 103/45. That can be simplified into 2 13/45.

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3m-5m-12=7m-88-5

plz show all work

Answers

3m - 5m - 12 = 7m - 88 - 5

-2m - 12 = 7m - 88 - 5 

-2m - 12 = 7m - 93

-12 = 7m - 93 + 2m

-12 = 9m - 93

-12 + 93 = 9m

81 = 9m

9 = m

hope that helps, God bless!

You are 5 feet tall and cast an 8-foot shadow. A lamppost nearby casts a shadow that is 20 feet. Which equation can you use to solve for the height (h) of the lamppost?

A. 5/8 = h/20
B. 8/5= h/20
C. 5/9 = h/20
D. 5/20 = h/8

Answers

I would say A. Just because your height and the lamppost's height is a like term, like the length of the shadow. So 5/8 = h/20. But i may be wrong.

Answer:

A. 5/8 = h/20

Step-by-step explanation:

Topic: Triangle Similarity

As you can see in the image you can paint the problem that way, it means that each side of the triangle is a multiplier from the other one same side, so you can build a relation as follows:

[tex]\frac{5}{h} = \frac{8}{20} \\[/tex]

you can re arrange the equality as

[tex]\frac{5}{8} = \frac{h}{20}[/tex]

as you can ssee you just reached the option A. 5/8 = h/20

What is 27 multiplied by 36 worked out?

Answers

    1
    4
    36
    27
 x___ 
    252
    72
   _____
    972

A book has a front and a back and 400 pages. The front and back cover are each 0.9mm thick measured to 1 decimal place. Each page is 0.13 mm thick measured to 2 decimal places. Calculate the minimum thickness of the book.

Answers

Answer:

The answer is actually 5.17 centimeters

Step-by-step explanation:

The question is asking you to calculate the minimum thickness so you have to find the lowest bounds.

The covers are 0.9 mm to 1 d.p so the minimum thickness is 0.85 because that is the lowest bound.

The pages are 0.13 mm to 2 d.p so the minimum thickness is 0.125 as that is the lowest bound.

0.85  x 2 = 1.7 and 0.125 x 400 = 50

50 + 1.7 = 51.7 which is the minimum length.

Final answer:

The minimum thickness of a book with 400 pages, each 0.13mm thick, and two covers, each 0.9mm thick, is calculated to be 53.8mm.

Explanation:

The minimum thickness of a book can be calculated by summing the thickness of the covers and all the pages. We are given that each cover is 0.9mm thick and each page is 0.13mm thick. To find the minimum thickness of the book, we multiply the thickness of each page by the total number of pages and then add the thicknesses of the front and back covers.

To calculate:

Thickness of all pages: 400 pages × 0.13 mm/page = 52 mm

Thickness of both covers: 2 covers × 0.9 mm/cover = 1.8 mm

Total minimum thickness: 52 mm + 1.8 mm = 53.8 mm

The minimum thickness of the book is therefore 53.8 mm.

The length of a rectangle is three times its width. If the area of the rectangle is 192 ft^2, find its perimeter

Answers

Answer: 64 feet.

Explanation:
Perimeter formula: 2l + 2w
Area formula: l•w
Length = 3w
Area = 192 ft[tex] ^{2} [/tex]
192 = (3w) • w 
192 = 3[tex] w^{2} [/tex]
192 ÷ 3 = 3[tex] w^{2} [/tex] ÷ 3
64 = [tex] w^{2} [/tex] 
[tex] \sqrt{64} [/tex] = [tex] \sqrt{ w^{2} } [/tex]
8 = w 

Width = 8
Length = 3(8) = 24 
Perimeter = 2(24) + 2(8) = 64 feet.

Lets x = width
length = 3x

A = length times width
A = x * 3x
192 = 3x^2
192/3 = x^2
64 = x^2
8 = x

so width = 8
length = 3x = 3(8) = 24

P = 2(L + W)
P = 2(24 + 8)
P = 2(32)
P = 64

answer
P = 64 feet

Please help with homework (it's not 40 or 60) also please say how to work out if you can

Answers

If the original volumes of liquid is represented by x, we have x=x for A and B. Since 120mL is poured from A to B, A loses 120 mL (x-120) and B gains 120 mL (x+120). Since we know that B contains 4 times as much liquid as A is now (x-120), we have 4*(x-120)=(x+120)=B. Using the distributive property, we get 4x-480=x+120. Adding 480 to both sides, we get 4x=x+600. After that, we can subtract both sides by x to get 3x=600. Lastly, we can divide both sides by 3 to get x=200=the original amount of liquid. Since A=x-120, we get A=200-120=80


A survey of 2,000 doctors showed that an average of 3 out of 5 doctors use brand X aspirin. How many doctors use brand X aspirin? (Hint: Solve for X

Answers

You would use cross multiplication:

X/2,000 = 3/5
Multiply: 2,000*3= 6,000
Divide: 6,000/5
Answer: 1,200 doctors use brand x

Set up a proportion for the problem below:

15 is 1 1/2% of what number?

Please answer ASAP!! Thank you :)

Answers

let's say that number is "x", therefore "x" is the 100%, and we know that 15 is 1 and 1/2% of that,

[tex]\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ x&100\\ 15&1\frac{1}{2} \end{array}\implies \cfrac{x}{15}=\cfrac{100}{1\frac{1}{2}}\implies \cfrac{x}{5}=\cfrac{100}{\frac{3}{2}}\implies \cfrac{x}{5}=\cfrac{\frac{100}{1}}{\frac{3}{2}} \\\\\\ \cfrac{x}{5}=\cfrac{100}{1}\cdot \cfrac{2}{3}\implies \cfrac{x}{5}=\cfrac{200}{3}[/tex]

Suppose w=xy+yz, where x=e2t, y=2+sin(4t), and z=2+cos(7t).
a. use the chain rule to find dwdt as a function of x, y, z, and t. do not rewrite x, y, and z in terms of t, and do not rewrite e2t as x.

Answers

basically find the individual derivatives nd put it back into the mother derivative
i.e
dx/dt = 2e^2t
dy/dt= 4cos 4t
dZ/dt = -7sin 7t
now
from
W=xy+yz
dw/dx = y ( by partial differentiation)
dw/dy= x+z
dw/dz= y

now Dw/dt = ⅓{ (dx/dt×dw/dx) + (dy/dt×dw/dy)+(dz/dt×dw/dz)

dw/dt = ⅓{ (2e^2t×y) + (4cos4t×(x+z) + (-7sin7t×y)}
= ⅓{ 2ye^2t + 4(x+z)Cos4t - 7ySin7t}

pheww
that should help...

Final answer:

To find dwdt using the chain rule, differentiate w=xy+yz, where x=e^2t, y=2+sin(4t), and z=2+cos(7t), as functions of t, apply partial derivatives and multiply by dx/dt, dy/dt, and dz/dt.

Explanation:

The student asked how to use the chain rule to find dwdt as a function of x, y, z, and t, without rewriting x, y, and z in terms of t, and keeping e2t as x. Given w=xy+yz, where x=e2t, y=2+sin(4t), and z=2+cos(7t), we apply the chain rule to differentiate w for t, remembering that x, y, and z are all functions of t. To find debt, we derive each component individually and sum their contributions. The calculation involves taking partial derivatives of w to x, y, z, multiplied by their respective derivatives to t (dx/dt, dy/dt, dz/dt).

A student is taking a test. He has 37 questions left. If the test has 78 questions

Answers

a. Let x  represent the number of questions finished.
b. The equation is  x + 37 = 78 , and solving yields  x = 41 .
c. The student finished 41 questions.

a. Define a variable for the unknown value. Let  x  represent the number of questions the student has finished.

b. Write and solve the equation. The total number of questions is the sum of the questions finished and the questions left:  x + 37 = 78 . Now solve for  x :

x = 78 - 37 = 41

So, the student has finished 41 questions.

c. Answer the question with the correct units. The student has finished 41 questions out of the total 78. Therefore, the student has [tex]\( \frac{41}{78} \)[/tex] of the test complete. To express this as a percentage, multiply by 100:

[tex]\[ \frac{41}{78} \times 100 \approx 52.56\% \][/tex]

The student has finished approximately 52.56% of the test.

Que. A student is taking a test. He has 37 questions left. If the test has 78 questions, how many questions has he finished? a. Define a variable for the unknown value. Let ...........represent............
b. Write and solve the equation.
c. Answer the question with the correct units........

Find f '(−5), if f(x) = (−4x2 − 2x)(−x2 − 9)

Answers

*Answer*
x+0 or x=-0.63297

heres step by step
−5x=(−4x2−2x)(−x2−9)−5x=4x4+2x3+36x2+18x
heres step by step

Step 1: Subtract 4x^4+2x^3+36x^2+18x from both sides

−5x−(4x4+2x3+36x2+18x)=4x4+2x3+36x2+18x−(4x4+2x3+36x2+18x)−4x4−2x3−36x2−23x=0

Step 2: Factor left side of equation

x(−4x3−2x2−36x−23)=0Step 3: Set factors equal to 0.x=0 or −4x3−2x2−36x−23=0x=0 or x=−0.63297

Answer: the answer is -2192

In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points for solving a hard puzzle. Tina solved a total of 50 puzzles playing this game, earning 1,950 points in all. How many hard puzzles did Tina solve? A) 10 B) 15 C) 25 D) 35

Answers

The answer is C. 25...

Answer:

B) 15

Step-by-step explanation:

In order to solve this we have to create a system of equations, where the easy puzzles are represented by x, and the hard puzzles are y, so you just have to multiply that for the points to get the total points in all:

30x+60y=1950

If the player did 50 in total:

x+y=50

Now we just solve for x in the second equation and then insert that into the first equation:

x=50-y

30(50-y)+60y=1950

1500-30y+60y=1950

30y=450

y=450/30

y=15

So we know that Tina solved 15 hard puzzles.

6× 532 expanded form

Answers

three thousand one hundred ninty-two

How many 5-digit numbers (including leading 0s) are there with no digit appearing exactly two times?

Answers

total numbers if all  digits are different = 10P5  = 10! / 5!  =  30

30240 are 5-digit numbers (including leading 0s) are there with no digit appearing exactly two times

What is Number system?

A number system is defined as a system of writing to express numbers.

By means of Permutation we solve this

The term permutation refers to a mathematical calculation of the number of ways a particular set can be arranged.

The formula for permutation is [tex]^{n}P_{r} =\frac{n!}{(n-r)!}[/tex]

n is total number of objects

r is number of objects selected

We need to find 5-digit numbers (including leading 0s) are there with no digit appearing exactly two times

¹⁰P₅=10!/(10-5)!

=10!/5!

=10×9×8×7×6×5!/5!

=30240

Hence, 30240 are 5-digit numbers (including leading 0s) are there with no digit appearing exactly two times

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The picture shows a triangular island Which expression shows the value of Q?

Answers

In trigonometric ratios, the cos (x) = adjacent over hypotenuse.

Therefore, in the diagram,  cos (55°) = s/q
To isolate q, divide both sides by s
cos (55°) / s = 1/ q
Then flip both numerators and denominators (raise both sides to the power of -1)
q = s / cos (55°)

Answer is D

S/cos 55• the answer D

1 and 2/5(-3/5) in simplest form

Answers

(-6/25) hope this helps ;)

The answer is (-6/25).

find the missing value in the ratio table .

Answers

9 will be your answer

5 x 3 = 15, therefore, 3 x 3 = 9

because you multiplied 3 for 5, you will be doing the same for 3, which means 3 x 3

hope this helps
ratios are nothing but equivalent fractions

3/5 = 9/15 = 12/20...so ur missing number is 9


which of the following is a correct interpretation of the expression -2+(-7)

Answers

I think the answer is negative 9.  

The correct interpretation of -2 + (-7) is that "the number 7 is to the left of -2 on the number line".

The correct interpretation of the expression -2 + (-7) which is results in -9.

Let's break this down:

-2 is our starting point on the number line. + (-7) means we move 7 units to the left of -2 (since adding a negative number is equivalent to subtraction).

When we move 7 units left from -2, we land on -9.

Thus, -2 + (-7) results in -9, which confirms that we have moved 7 to the left of -2 on the number line.

Complete question:

Which of the following is a correct interpretation of the expression -2 + (-7)?

Choose 1 answer:

The number that is 2 to the left of 7 on the number lineThe number that is 2 to the right of 7 on the number lineThe number that is 7 to the left of −2 on the number lineThe number that is 7 to the right of −2 on the number line

What must the distance be between charges of +2.35 and −1.96 for the attractive force between them to be the same as that between charges of +4.06 and −2.11 separated by a distance of 2.26 pm?

Answers

The distance between charges of +2.35 and −1.96,  should be approximately 1.566 picometers (pm).

Coulomb's law states that the force (F) between two point charges is given by:

F =[tex]\dfrac{(k \times q1 \times q2)}{r^2}[/tex]

Where:

The electrostatic force between the charges is F

k is Coulomb's constant, approximately equal to 8.99 × 10^9 N m²/C².

The magnitudes of the two charges are [tex]q_1[/tex] and [tex]q_2[/tex].

The distance between the charges is r.

Given that the charges are +2.35 and −1.96, we'll call the distance between them x (in pm). Similarly, for charges +4.06 and −2.11, the distance is given as 2.26 pm.

Setting up the equation:

For the first pair of charges (q1 = +2.35 C and q2 = −1.96 C):

F1 =[tex]\dfrac{(k \times |2.35 \times (-1.96)|)}{x^2}[/tex]

For the second pair of charges (q1 = +4.06 C and q2 = −2.11 C):

F2 =[tex]\dfrac{(k \times |4.06 \times (-2.11)|)}{(2.26)^2}[/tex]

Since the forces are said to be equal, we have:

F1 = F2

The solution of the expression for x is given by:

[tex]\dfrac{(k \times |2.35 \times (-1.96)|}{x^2}[/tex] =[tex]\dfrac{(k \times |4.06 \times (-2.11)|)}{(2.26)^2}[/tex]

|[tex]\dfrac{(2.35 \times (-1.96)}{x^2}[/tex]| =[tex]\dfrac{|4.06 \times (-2.11)|}{ (2.26)^2}[/tex]

[tex]{(2.35 \times 1.96)} {x^2}[/tex] = [tex]\dfrac{(4.06 \times 2.11)} { (2.26)^2}[/tex]

[tex]x^2[/tex] =[tex]\dfrac{(2.35 \times 1.96 \times (2.26)^2} {(4.06 \times 2.11)}[/tex]

[tex]x^2[/tex] = 2.450206485

x ≈ [tex]\sqrt{2.450206485[/tex]

x ≈ 1.566 pm

Therefore, the distance between charges of +2.35 and −1.96,  should be approximately 1.566 picometers (pm).

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Final answer:

To find the distance between charges of +2.35 and -1.96 for the attractive force to be the same, use Coulomb's Law to calculate the force between charges of +4.06 and -2.11 separated by a distance of 2.26 pm. Then solve for the distance using the same formula and the calculated force value.

Explanation:

To find the distance between charges of +2.35 and -1.96 for the attractive force to be the same as between charges of +4.06 and -2.11, we can use Coulomb's Law. The formula for calculating the force between two charges is F = k * (|q1 * q2| / (d^2)) where k is the proportionality constant and d is the distance between the charges.

First, we calculate the force between charges of +4.06 and -2.11. Let q1 = +4.06, q2 = -2.11, and d = 2.26 pm. Plugging these values into the formula, we get:

F = (1/47e) * (|4.06 * -2.11| / (2.26^2))

Next, we can find the distance between charges of +2.35 and -1.96 such that the attractive force is the same. Let q1 = +2.35, q2 = -1.96, and F = the value we calculated earlier. Rearranging the formula to solve for d, we get:

d = sqrt((|q1 * q2| / (F * k)))

If the food is good or if I eat too much, I'll exercise. How do you write this compound statement in symbols.

Answers

Let
Y=the food is yummy
O=overeat
E=exercise
Note:
&cup; = or
->  if ... then

(Y&cup;O)->E

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