Answer:
[tex]F=\frac{s^2_2}{s^2_1}=\frac{0.8^2}{1.0^2}=0.64[/tex]
[tex]p_v =P(F_{15,10}<0.64)=0.2105[/tex]
Since the [tex]p_v > \alpha[/tex] we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation for the New sample it's significantly less than the variation for the Old sample at 5% of significance.
Step-by-step explanation:
Data given and notation
[tex]n_1 = 11 [/tex] represent the sampe size for the Old
[tex]n_2 =16[/tex] represent the sample size for the New
[tex]\bar X_1 =6.25[/tex] represent the sample mean for Old
[tex]\bar X_2 =5.95[/tex] represent the sample mean for the New
[tex]s_1 = 1.0[/tex] represent the sample deviation for Old
[tex]s_2 = 0.8[/tex] represent the sample deviation for New
[tex]\alpha=0.05[/tex] represent the significance level provided
Confidence =0.95 or 95%
F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:
[tex]F=\frac{s^2_2}{s^2_1}[/tex]
Solution to the problem
System of hypothesis
We want to test if the variation for New sample it's lower than the variation for the Old sample, so the system of hypothesis are:
H0: [tex] \sigma^2_2 \geq \sigma^2_1[/tex]
H1: [tex] \sigma^2_2 <\sigma^2_1[/tex]
Calculate the statistic
Now we can calculate the statistic like this:
[tex]F=\frac{s^2_2}{s^2_1}=\frac{0.8^2}{1.0^2}=0.64[/tex]
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_2 -1 =16-1=15[/tex] and for the denominator we have [tex]n_1 -1 =11-1=10[/tex] and the F statistic have 15 degrees of freedom for the numerator and 10 for the denominator. And the P value is given by:
P value
Since we have a left tailed test the p value is given by:
[tex]p_v =P(F_{15,10}<0.64)=0.2105[/tex]
And we can use the following excel code to find the p value:"=F.DIST(0.64,15,10,TRUE)"
Conclusion
Since the [tex]p_v > \alpha[/tex] we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation for the New sample it's significantly less than the variation for the Old sample at 5% of significance.
if the hypothesis test is conducted using a 0.05 level of significance, the calculated test statistic is 1.56. The option (d) is correct.
To test whether the new seed results in less variability in individual potato length compared to the old seed, we can perform an F-test for comparing variances.
The F-test statistic for comparing two variances is given by:
[tex]\[ F = \frac{s_1^2}{s_2^2} \][/tex]
where [tex]\( s_1^2 \)[/tex] is the variance of the old seed and [tex]\( s_2^2 \)[/tex] is the variance of the new seed. The larger variance should be the numerator to ensure the F-value is greater than or equal to 1.
Given data:
- Old Seed:
[tex]- \( n_1 = 11 \)\\ - \( \bar{x}_1 = 6.25 \) inches\\ - \( s_1 = 1.0 \) inch[/tex]
- New Seed:
[tex]- \( n_2 = 16 \)\\ - \( \bar{x}_2 = 5.95 \) inches\\ - \( s_2 = 0.80 \) inch[/tex]
First, calculate the variances:
- Variance of old seed, [tex]\( s_1^2 = (1.0)^2 = 1.0 \)[/tex]
- Variance of new seed, [tex]\( s_2^2 = (0.80)^2 = 0.64 \)[/tex]
Since [tex]\( s_1^2 \)[/tex] (old seed) is larger than [tex]\( s_2^2 \)[/tex] (new seed), we use:
[tex]\[ F = \frac{s_1^2}{s_2^2} = \frac{1.0}{0.64} \][/tex]
Now, calculate the F-value:
[tex]\[ F = \frac{1.0}{0.64} = 1.5625 \][/tex]
The calculated test statistic is approximately 1.56. Therefore, the correct answer is (d) 1.56.
The complete question is:
The Russet Potato Company has been working on the development of a new potato seed that is hoped to be an improvement over the existing seed that is being used. Specifically, the company hopes that the new seed will result in less variability in individual potato length than the existing seed without reducing the mean length. To test whether this is the case, a sample of each seed is used to grow potatoes to maturity. The following information is given: Old Seed - Number of Seeds = 11, Average length = 6.25 inches , Standard Deviation = 1.0 inches New Seed - Number of Seeds = 16, Average length = 5.95 inches Standard Deviation = 0.80 inches. On this data, if the hypothesis test is conducted using a 0.05 level of significance, the calculated test statistic is:
(a) 1.25
(b) 0.80
(c) 0.64
(d) 1.56
p = \left ( 1 - \frac{1}{2} \right )\left ( 1 - \frac{1}{3} \right )\left ( 1 - \frac{1}{4} \right )...\left ( 1 - \frac{1}{50} \right ) P is the product, indicated above, of all the numbers of the form 1 – \frac{1}{k}, where k is an integer from 2 to 50, inclusive. What is the value of P
Answer:
The value of p would be [tex]\frac{1}{50}[/tex]
Step-by-step explanation:
Given,
[tex]p = \left ( 1 - \frac{1}{2} \right )\left ( 1 - \frac{1}{3} \right )\left ( 1 - \frac{1}{4} \right )...\left ( 1 - \frac{1}{50} \right )[/tex]
[tex]p = \left ( 1 - \frac{1}{2} \right )\left ( 1 - \frac{1}{3} \right )\left ( 1 - \frac{1}{4} \right )...\left ( 1 - \frac{1}{49} \right )\left ( 1 - \frac{1}{50} \right )[/tex]
[tex]p=\frac{2-1}{2}.\frac{3-1}{3}.\frac{4-1}{4}......\frac{49-1}{49}.\frac{50-1}{50}[/tex]
[tex]p=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{48}{49}.\frac{49}{50}[/tex]
[tex]p=\frac{1.2.3.4.........48.49}{2.3.4........49.50}[/tex]
[tex]p=\frac{1}{50}[/tex]
Hence, the value of p is 1/50.
P is the product, indicated above, of all the numbers of the form , where k is an integer from 2 to 50, inclusive. Value of P is 2) 1/50.
To find the value of [tex]\( P \)[/tex], we can simply multiply all the terms together:
[tex]\[ P = \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{4}\right) \ldots \left(1 - \frac{1}{50}\right) \][/tex]
We start with [tex]\( k = 50 \)[/tex]. and go up to [tex]\( k = 50 \)[/tex]. Let's calculate it:
[tex]\[ P = \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{4}\right) \ldots \left(1 - \frac{1}{50}\right) \][/tex]
[tex]\[ P = \left(\frac{1}{2}\right)\left(\frac{2}{3}\right)\left(\frac{3}{4}\right) \ldots \left(\frac{49}{50}\right) \][/tex]
[tex]\[ P = \frac{1}{50} \][/tex]
So, the value of [tex]\( P \) is \( \frac{1}{50} \).[/tex]
[tex]p = \left ( 1 - \frac{1}{2} \right )\left ( 1 - \frac{1}{3} \right )\left ( 1 - \frac{1}{4} \right )...\left ( 1 - \frac{1}{50} \right[/tex]) P is the product, indicated above, of all the numbers of the form [tex]1 – \frac{1}{k}[/tex], where k is an integer from 2 to 50, inclusive. the value of P is [tex]\( P \) is \( \frac{1}{50} \).[/tex]
Question:-
[tex]p = \left ( 1 - \frac{1}{2} \right )\left ( 1 - \frac{1}{3} \right )\left ( 1 - \frac{1}{4} \right )...\left ( 1 - \frac{1}{50} \right )[/tex]
P is the product, indicated above, of all the numbers of the form [tex]1 – \frac{1}{k}[/tex], where k is an integer from 2 to 50, inclusive. What is the value of P ?
1.) [tex]\frac{1}{100}[/tex]
2.) [tex]\frac{1}{50}[/tex]
3.) [tex]\frac{1}{49}[/tex]
4.) [tex]\frac{49}{50}[/tex]
5.)[tex]\frac{99}{100}[/tex]
F n is a natural number then√n is (a) always a natural number (b)always an irrational number (c)always a rational number(d) sometimes a natural number and sometimes an irrational number
Answer:
(d) sometimes a natural number and sometimes an irrational number
Step-by-step explanation:
Consider the natural numbers 3 and 4:
√4 = 2, a natural number
√3 ≈ 1.73205080756887729352744634150..., an irrational number
How many numbers in the set {3, 13, 23, 33, . . .} can be written as the difference of two primes?
Answer:
1
Step-by-step explanation:
An odd number will be the difference of an even and an odd number. The only even prime is 2, so the other prime must end in 5. There is only one such.
Only 3 = 5 -2 can be written as the difference of primes.
Answer:
1
Step-by-step explanation:
Notice that when we subtract two integers, the difference can only be odd if one integer is even and one integer is odd (even - even = even and odd - odd = even). If one integer is even, then that integer is divisible by 2 and thus not prime. The only exception is 2, the only even prime number. So one of the primes must be 2. If we add 2 to each number in the set to find the other prime, we end up with $\{5, 15, 25, 35, \ldots\}$. All of the numbers in the set are divisible by 5, which means the only prime number in the set is 5. So the only number in the set $\{3,13,23,33, \ldots\}$ that can be written as the difference of two primes is $5-2=3$. The answer is $\boxed{1}$ number.
Yes I copied and pasted the proper answer from a different site. I didn't want to write it out.
The combined area of the photo and mat needs to be 224 square inches. The equation that represents the combined area is (2w+8)(2w+10)=224, where w represents the width of the mat around the photo.
The required width of the mat around the photo is given as 3 inches.
Given that,
The combined area of the photo and mat needs to be 224 square inches. The equation that represents the combined area is (2w+8)(2w+10)=224, where w represents the width of the mat around the photo.
The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.
here,
(2w + 8)(2w + 10) = 224
4w² + 16w + 20w + 80 = 224
4w² + 36w - 144 = 0
w² + 9w - 36 = 0
[w -3][w + 12] = 0
w = 3 and w = -12
Since the measure of width cannot be negative so -12 can be neglected.
w = 3 preferred,
Thus, the required width of the mat around the photo is given as 3 inches.
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The output of a process is stable and normally distributed. If the process mean equals 23.5, the percentage of output expected to be less than or equal to the mean: a. is 50%. b. is greater than 75%. c. cannot be determined without knowing the standard deviation value. d. is less than 25%
Answer:
Option a) 50% of output expected to be less than or equal to the mean.
Step-by-step explanation:
We are given the following in the question:
The output of a process is stable and normally distributed.
Mean = 23.5
We have to find the percentage of output expected to be less than or equal to the mean.
Mean of a normal distribution.
The mean of normal distribution divides the data into exactly two equal parts.50% of data lies to the right of the mean.50% of data lies to the right of the meanThus, by property of normal distribution 50% of output expected to be less than or equal to the mean.
Please help me with this problem
Answer:
domain: [0, 7]range: [-2, 4]is a function? YESStep-by-step explanation:
The domain is the horizontal extent, which is from x=0 to x=7.
The range is the vertical extent, which is from y=-2 to y=4.
The curve passes the vertical line test, so the relation IS A FUNCTION.
_____
The vertical line test asks whether any vertical line intersects the curve at more than one point. If so, the relation is NOT a function.
Select one of the factors of x3y2 + 8xy2 + 5x2 + 40.
a) (xy2 + 5)
b) (x2 + 4)
c) (xy2 − 5)
d) (x2 − 8)
Answer:
Option a - [tex]xy^2+5[/tex]
Step-by-step explanation:
Given : Polynomial [tex]x^3y^2+8xy^2+5x^2+40[/tex]
To find : Select one of the factors of polynomial ?
Solution :
The polynomial [tex]x^3y^2+8xy^2+5x^2+40[/tex]
We factor of above polynomial by taking common terms,
[tex]xy^2(x^2+8)+5(x^2+8)[/tex]
[tex](xy^2+5)(x^2+8)[/tex]
From the given options,
[tex]xy^2+5[/tex] is one of the factors of polynomial.
Therefore, option a is correct.
Suppose the time that it takes a certain large bank to approve a home loan is Normally distributed, with mean (in days) μ μ and standard deviation σ = 1 σ=1 . The bank advertises that it approves loans in 5 days, on average, but measurements on a random sample of 500 loan applications to this bank gave a mean approval time of ¯ x = 5.3 x¯=5.3 days. Is this evidence that the mean time to approval is actually longer than advertised? To answer this, test the hypotheses H 0 : μ = 5 H0:μ=5 , H α : μ > 5 Hα:μ>5 at significance level α = 0.01 α=0.01 .
Test hypothesis :
[tex]H_0 : \mu =5\\\\ H_a: \mu >5[/tex]
Since alternative hypothesis is right-tailed and population standard deviation is known σ = 1 , so we perform a right-tailed z-test.
Test statistic : [tex]z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
, where [tex]\overline{x}[/tex] = sample mean
[tex]\mu[/tex] = population mean
[tex]\sigma[/tex] =population standard deviation
n= Sample size
Substitute values, we get
[tex]z=\dfrac{ 5.3-5}{\dfrac{1}{\sqrt{500}}}[/tex]
[tex]z=\dfrac{ 0.3}{0.04472135955}\approx6.7[/tex]
Critical value for 0.01 significance level in z-table is 2.326.
Decision : Test statistic (6.7)> Critical value ( 2.326), it means we reject that null hypothesis.
i.e. [tex]H_a[/tex] is accepted.
We conclude that there is sufficient evidence that the mean time to approval is actually longer than advertised.
Sarah sent half of the Christmas cards to her friends,and Richard sent three eights of them to his friends. If there are 32 cards in all and Sarah and Richard want to send an even number of cards to their families. How many cards would Sarah's family get.
Answer:
Sarah family will get 2 cards
Step-by-step explanation:
The total number of cards is 32
Sarah sent half of the Christmas cards to her friends,= 1/2 *32= 16 cards for Sarah's friends
Richard sent three eights of them to his friends.
3/8 *32=12 cards for Richards friends
Total = 12+16= 28
Card left= 32-28=4
Since Sarah and Richard want to send an even number of cards to their families. Then Sarah's family and Richard's family will receive 2 apiece.
Sarah's family would receive 2 cards after accounting for the cards Sarah and Richard sent to their friends from the total of 32 cards.
Explanation:To solve how many Christmas cards Sarah's family will get, first calculate how many cards Sarah and Richard sent to their friends. Sarah sent half of 32, which is 16 cards. Richard sent three eights of 32, which can be calculated as (3/8) * 32 = 12 cards. Together, they sent 28 cards to their friends. Since there are 32 cards in total, the remaining cards for their families would be 32 - 28 = 4 cards. If these 4 cards are to be distributed evenly, both families would get 2 cards each. Thus, Sarah's family would get 2 cards.
Diego said that the answer to the question "how many groups of 5/6?" are in one is 6/5 or 1 1/5. Do you agree with the same explain your explain or show your reasoning
Answer: I agree with 6/5 and with 1 1/5
Step-by-step explanation: okay, to find the value of the amount of 5/6 in 1, we simply just divide 1 by 5/6
Taking a similar problem with different numbers. Let's the the amount of 2s in 10, we do 10/2 which equals 5, so we have 5 2s in 10, you get? 2,4,6,8,10
So dividing 1 by 5/6
I / (5/6)
Change since to multiplication
1 * 6/5
= 6/5
Changing this to a mixed fraction, we get 1 whole number, 1 over 5 = 1 1/5
Answer:Answer: I agree with 6/5 and with 1 1/5
Step-by-step explanation:
Step-by-step explanation: okay, to find the value of the amount of 5/6 in 1, we simply just divide 1 by 5/6
Taking a similar problem with different numbers. Let's the the amount of 2s in 10, we do 10/2 which equals 5, so we have 5 2s in 10, you get? 2,4,6,8,10
So dividing 1 by 5/6
I / (5/6)
Change since to multiplication
1 * 6/5
= 6/5
Changing this to a mixed fraction, we get 1 whole number, 1 over 5 = 1 1/5
(copied from another user) so credit to her
The graph of which function passes through (0,3) and has an amplitude of 3? f (x) = sine (x) + 3 f (x) = cosine (x) + 3 f (x) = 3 sine (x) f (x) = 3 cosine (x)
Answer:
[tex]f(x)=3*cosine(x)[/tex]
Step-by-step explanation:
We are looking for a trigonometric function which contains the point (0, 3), and has an amplitude of 3.
We know that for a sine function [tex]f(x)=sin(x)[/tex], [tex]f(0)= 0[/tex]; therefore the function we a looking for cannot be a sine function because it is zero at [tex]x=0[/tex].
However, the cosine function [tex]f(x)=cos(x)[/tex] gives non-zero value at [tex]x=0:[/tex]
[tex]f(0)=cos(0)=1[/tex]
therefore, a cosine function can be our function.
Now, cosine function with amplitude [tex]a[/tex] has the form
[tex]f(x)=a*cos(x)[/tex]
this is because the cosine function is maximum at [tex]x= 0[/tex] and therefore, has the property that
[tex]f(0)=a*cos(0)= a[/tex]
in other words it contains the point [tex](0, a)[/tex].
The function we are looking for contains the point [tex](0, 3)[/tex]; therefore, its amplitude must be 3, or
[tex]f(x)=3cos(x)[/tex]
we see that this function satisfies our conditions: [tex]f(x)[/tex] has amplitude of 3, and it passes through the point (0, 3) because [tex]f(0)=3[/tex]
Answer:
D
Step-by-step explanation:
edge
A set of five distinct positive integers has a mean of $1000$ and a median of $100$. What is the largest possible integer that could be included in the set?
Answer:
e = 4796
Step-by-step explanation:
given,
mean of five distinct positive number = 1000
median of the number = 100
100 is median means two number will be less than 100 and two number will be greater than 100.
let five number be
a , b, c, d, e
'e' should be the largest number
As 100 is median so 'c' = 100.
'a' and 'b' should be as small as possible and d should be the number nearest to 100.
As all the number are distinct so the least number be equal to 1 and 2
now d will be equal to 101 (nearest to 100)
now,
sum of the five number = 5 x 1000 = 5000
a + b + c + d + e = 5000
1 + 2 + 100 + 101 + e = 5000
e = 5000 - 204
e = 4796
hence, the largest number will be equal to e = 4796
5. Reggie picked 3 3/4 quarts of blueberries and 4 1/4 quarts of raspberries at a fruit farm. How many total quarts of berries did he pick? Show your work or explain your reasoning.
Answer:
Reggie picked total 8 quarts of berries.
Step-by-step explanation:
Given:
Amount of Blueberries picked by Reggie = [tex]3\frac{3}{4} [/tex] quarts
[tex]3\frac{3}{4}[/tex] can be Rewritten as [tex]\frac{15}{4}[/tex]
Amount of Blueberries picked by Reggie = [tex]\frac{15}{4}[/tex] quarts
Amount of Raspberries picked by Reggie = [tex]4\frac{1}{4} [/tex] quarts
[tex]4\frac{1}{4}[/tex] can be Rewritten as [tex]\frac{17}{4}[/tex]
Amount of Raspberries picked by Reggie = [tex]\frac{17}{4}[/tex] quarts
We need to find Total quarts of berries he picked from fruit farm.
So we can say Total quarts of berries he picked from fruit farm is equal to sum of Amount of Blueberries and Amount of Raspberries.
Framing in equation form we get;
Total Quarts of Berries = [tex]\frac{15}{4}+\frac{17}{4} = \frac{15+17}{4}=\frac{32}{4} = 8\ quarts[/tex]
Hence Reggie picked Total 8 quarts of berries.
Solve the exponential equation. Express the solution in terms of natural logarithms. Then use a calculator to obtain a decimal approximation for the solution.e^x = 22.8
Answer: x = ln 22.8; 3.13
Step-by-step explanation:
Given the exponential equation
e^x = 22.8
We apply ln to both sides since only natural logarithm can cancel out exponents.
lne^x = ln 22.8
x = ln 22.8
x = 3.13
What are the equations of the asymptotes of the graph of the function f (x) = StartFraction 3 x squared minus 2 x minus 1 Over x squared + 3 x minus 10 EndFraction?
x = –5, x = 2 and y = 3
x = –2, x = 5 and y = 3
x = 3, y = –5, and y = 2
x = 3, y = –2, and y = 5
Answer:
As x = -5, x = 2 and y = 3 are the equations of the asymptotes of the graph of the function [tex]f(x)=\frac{3x^{2} -2x - 1}{x^{2}+3x-10 }[/tex].
Therefore, x = -5, x = 2 and y = 3 is the right option.
Step-by-step explanation:
As the given function is
[tex]f(x)=\frac{3x^{2} -2x - 1}{x^{2}+3x-10 }[/tex]
Determining Vertical Asymptote:
The line x = L is a vertical asymptote of the function if if the limit of the function (one-sided) at this point is infinite.
In other words, it means that possible points are points where the denominator equals 0 or doesn't exist.
Such as
[tex]x^{2} +3x -10 = 0[/tex]
[tex](x-2)(x-5)=0[/tex]
[tex]x=2[/tex] [tex]or[/tex] [tex]x=-5[/tex]
x=−5 , check:
[tex]\lim_{x \to -5^{+}}({3x^{2}-2x-11 \over x^{2}+3x-10 }) = -\infty[/tex]
Since, the limit is infinite, then x = -5 is a vertical asymptote.
x = 2, check:
[tex]\lim_{x \to 2^{+}}({3x^{2}-2x-11 \over x^{2}+3x-10 }) = -\infty[/tex]
Since the limit is infinite, then x = 2 is a vertical asymptote.
Determining Horizontal Asymptote:
Line y=L is a horizontal asymptote of the function y = f(x), if either
[tex]\lim_{x \to \infty^{}}{f(x)=L}[/tex] or [tex]\lim_{x \to -\infty^{}}{f(x)=L},[/tex] and L is finite.
Calculating the limits:
[tex]\lim_{x \to \infty^{}}({3x^{2}-2x-11 \over x^{2}+3x-10 }) = 3[/tex]
[tex]\lim_{x \to -\infty^{}}({3x^{2}-2x-11 \over x^{2}+3x-10 }) = 3[/tex]
Thus, the horizontal asymptote is y=3.
So, x = -5, x = 2 and y = 3 are the equations of the asymptotes of the graph of the function [tex]f(x)=\frac{3x^{2} -2x - 1}{x^{2}+3x-10 }[/tex].
Therefore, x = -5, x = 2 and y = 3 is the right option.
Keywords: asymptote, vertical asymptote, horizontal asymptote, equation
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I believe the answer is a.
For each recipe, write a ratio that compares the number of parts of lemonade to the total number of parts.
Answer: Samantha's Recipe:
Ratio of lemonade = 2 1/2 : 6
Caden's Recipe:
Ratio of lemonade = 15 : 32
Step-by-step explanation:
Samantha's Recipe
3 1/2 parts cranapple juice
2 1/2 parts lemonade
Caden's Recipe
4 1/4 parts cranapple juice
3 3/4 parts lemonade
For each recipe, write a ratio that compares the number of parts of lemonade to the total number of parts.
Solution:
For Samantha's Recipe:
Total number of parts = cranapple juice parts + lemonade parts = 3.5 + 2.5 = 6.0
Ratio of lemonade to total number of parts = (2.5)/(6.0) = 2 1/2 : 6
For Caden's Recipe:
Total number of parts = cranapple juice parts + lemonade parts =(17/4)+(15/4) = (32/4) = 8
Therefore, Ratio of lemonade to total number of parts = (15/4) / (8) =(15)/(32) = 15:32
what is the difference between dependent variable independent variable vs response variable explanatory variable?
Answer:
Step-by-step explanation:
we are to distinguish between
dependent variable independent variable
vs
response variable explanatory variable
An independent variable is one which is not affected by any other variable for example, the amount we spend, the time we study ,etc.
An explanatory variable is a type of independent variable but not fully independent but depends on some factors.
Though explanatory and independent variables are practically used interchangeably the main difference is explanatory variable is not independent but explains the variations in the response varaible.
In experimental research, the independent variable is manipulated to observe its effect on the dependent variable, which is subsequently measured. Control variables are kept constant to ensure valid results. The dependent variable depends on the independent variable, such as the growth of plants depending on the amount of fertilizer applied.
In the context of experimental research, an independent variable, also known as an explanatory variable, is the one that is changed or controlled by the experimenter to examine its effect on another variable. On the other hand, a dependent variable, also referred to as a response variable, is what is measured or observed in the experiment to determine the effect of the independent variable.
For instance, if a study is conducted to see how the amount of fertilizer affects the growth of plants, the amount of fertilizer would be the independent variable because it is what the experimenter varies during the study. The growth of the plants, typically measured in height or biomass, would be the dependent variable because it is the result that is measured in response to the manipulation of the independent variable.
The control variables are equally crucial as they answer the question "What do I keep the same?" They need to be maintained consistently to ensure that the results are due only to the manipulation of the independent variable and not to other extraneous factors.
The authors of a study analyzing the effect of marital status on support for a football team would manipulate the marital status (independent variable) to measure the change in support or opposition for the team (dependent variable).
Susie, Meg, and Jane drive together to visit their grandma. Audit drive for 65 miles,and Meg drives 2 times as far as Susie. Then Jane drives twice as far as Susie and Meg combined. How far did Jane drive
Answer:
Jane has drive 390 miles to visit Grandma.
Step-by-step explanation:
Given:
Number of miles Susie drive = 65 miles
Meg drives 2 times as far as Susie.
It means Number of miles Meg drive is equal to twice the number of miles driven my Susie.
Framing equation we get;
Number of miles Meg drive = 2 × Number of miles Susie drive = [tex]65 \times 2=130\ miles[/tex]
Also Given:
Jane drives twice as far as Susie and Meg combined.
Number of Miles Driven by Jane is equal to twice the sum of Number of miles Susie drive and Number of miles Meg drive.
Framing equation we get;
Number of miles Meg drive = 2 × (Number of miles Susie drive + Number of miles Meg drive) = [tex]2\times (65+130) = 2\times 195 = 390\ miles[/tex]
Hence Jane has drive 390 miles to visit Grandma.
The Long family spent $38.62 for school supplies and $215.78 for new school clothes. They paid sales tax on their purchases. If the Long family paid $269.07 total, determine if they paid the correct amount.
A. The Long family paid $2.63 too little for their purchases.
B. The Long family paid the correct amount for their purchases.
C. The Long family paid $1.61 too much for their purchases.
D. The Long family paid $2.63 too much for their purchases.
Answer:
A. The Long family paid $2.63 too little for their purchases.
Step-by-step explanation:
We have been given that the Long family spent $38.62 for school supplies and $215.78 for new school clothes. They paid 6.8% sales tax on their purchases.
First of all, we will add both amounts as:
[tex]\$38.62+$215.78=\$254.40[/tex]
Now, we will find 6.8% of 254.40.
[tex]\text{Amount of tax paid}=\$254.40\times \frac{6.8}{100}[/tex]
[tex]\text{Amount of tax paid}=\$254.40\times0.068[/tex]
[tex]\text{Amount of tax paid}=\$17.2992[/tex]
Upon adding $254.40 and $17.2992, we will get total amount paid by Long family.
[tex]\text{Total amount paid by Long family}=\$254.40+\$17.2992[/tex]
[tex]\text{Total amount paid by Long family}=\$271.6992[/tex]
Now, we will subtract $271.6992 from $269.07:
[tex]\$269.07-\$271.6992[/tex]
[tex]-\$2.6292\approx -\$2.63[/tex]
Since the long family paid $2.63 less than actual amount, therefore, the Long family paid $2.63 too little for their purchases and option A is the correct choice.
Answer:
A
Step-by-step explanation:
will give brainliest for the CORRECT answer and 80 points please answer quickly
the weights (in ounces) of 14 different apples are shown below.
4.3 6.1 4.5 5.2 6.8 4.3 6.1 5.6 4.7 5.2 4.3 5.6 6.0 4.0
the measure of center is found to be 4.3 oz. which measure of center is used?
a:midrange
b:mean
c;median
d:mode
Answer: Median
Step-by-step explanation:
6(-3v+1)=5(-2v-2)(if there is no solution,type in ''no solution'')v= Answer
Answer:
v = 2
Step-by-step explanation:
Eliminate parentheses by using the distributive property.
-18v +6 = -10v -10
6 = 8v -10 . . . . . . . . . add 18v
16 = 8v . . . . . . . . . . . add 10
2 = v . . . . . . . . . . . . . divide by the coefficient of v
The answer is v = 2.
Answer:
v = 2
Step-by-step explanation:
6 (-3v + 1) = 5 (-2v - 2)
- 18v + 6 = - 10v - 10
- 18v + 10v = - 10 - 6
- 8v = - 16
- v = - 16/8
- v = - 2
v = 2
A dress is on sale for d dollars. The regular price is 3 times as much.
Janine has enough money to buy 2 dresses at the regular price.
How many dresses can Janine buy at the sale price?
Answer:
6 dresses
Step-by-step explanation:
Given: sales price is $d
Regular price is 3 times of sales price
Janine has money to buy 2 dresses at regular price.
Now, finding the number of dresses Janine can buy at the sales price, if sale price is d
Regular price= [tex]3\times d= 3d[/tex]
Janine has total money= [tex]3d\times 2= 6d[/tex] (∵ regular price is 3d)
∴ Number of dresses bought by Janine= [tex]\frac{Total\ money}{sale\ price\ of\ one\ dress}[/tex]
⇒ Number of dresses bought by Janine= [tex]\frac{6d}{d} = 6\ dresses[/tex]
∴ Number of dresses bought by Janine is 6.
A set of 15 different integers has a median of 25 and a range of 25. What is the greatest possible integer that could be in this set?A. 32
B. 37
C. 40
D. 43
E. 50
Answer:
Option D.
Step-by-step explanation:
It is given that a set of 15 different integers has a median of 25 and a range of 25.
Total number of integers is 15 which is an odd number.
[tex](\frac{n+1}{2}) th=(\frac{15+1}{2}) th=8th[/tex]
8th integers is median. It means 8th integers is 25.
7 different integers before 25 are 18, 19, 20, 21, 22, 23, 24.
It means the greatest possible minimum value is 18.
Range = Maximum - Minimum
25 = Maximum - 18
Add 18 on both sides.
25 +18 = Maximum
43 = Maximum
The greatest possible integer in the set is 43.
Therefore, the correct option is D.
Answer:
D. 43
Step-by-step explanation:
We have been given that a set of 15 different integers has a median of 25 and a range of 25.
Since each data point is different, so we can represent our data points as:
[tex]N_1,N_2,N_3,N_4,N_5,N_6,N_7,N_8, N_9,N_{10},N_{11},N_{12},N_{13},N_{14}, N_{15}[/tex]
Since there are 15 data points, this means that median will be 8th data point.
We have been given that median is 25, so [tex]n_8=25[/tex].
Since each data point is different, so 7 data points less than 25 would be:
18, 19, 20, 21, 22, 23, 24.
We know that range is the difference between upper value and lower value.
[tex]\text{Range}=\text{Upper value}-\text{Lower value}[/tex]
[tex]\text{Range}+\text{Lower value}=\text{Upper value}[/tex]
Upon substituting our given values, we will get:
[tex]25+18=\text{Upper value}[/tex]
[tex]43=\text{Upper value}[/tex]
Therefore, the greatest possible integer in this set could be 43 and option D is the correct choice.
34% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) through (c) below.
The sub-questions for this question are:
a) construct a binomial distribution using n=6 and p=0.34
b) graph the binomial distribution using a histogram and describe it's shape
c) what values of the random variable would you consider unusual? Explain your reasoning.
Answer:
a)
P(X=0) =0.0827
P(X=1) = 0.255
P(X=2) = 0.329
P(X=3) = 0.226
P(X=4) = 0.087
P(X=5) = 0.018
P(X=6) = 0.0015
b) graph D
c) x=5 and x=6
Step-by-step explanation:
a)
Formula for binomial distribution:
nCx(p^x)(q^(n-x))
Number of sample, n = 6
probability of success, p = 0.34
probability of failure, q = 1-p = 0.66
P(X=0) = 6C0(0.34^0)(0.66^6)
= 1*1*0.0827 = 0.0827
P(X=1) = 6C1(0.34^1)(0.66^5)
= 6*0.34*0.1252 = 0.255
P(X=2) = 6C2(0.34^2)(0.66^4)
= 15*0.1156*0.1897 = 0.329
P(X=3) = 6C3(0.34^3)(0.66^3)
= 20*0.0113 = 0.226
P(X=4) = 6C4(0.34^4)(0.66^2)
= 15*0.0058 = 0.087
P(X=5) = 6C5(0.34^5)(0.66^1)
= 6*0.003 = 0.018
P(X=6) = 6C6(0.34^6)(0.66^0)
= 1*0.0015 = 0.0015
b) the shape of the graph is the graph shape. Referring to the attachment, the correct graph is D
c) the unusual values would be x=6 and x=5, because those values are too small and lower than 0.05
John is planning to go to graduate school in a program that will take three years. John wants to have available $10,000 available each year for his school and living expenses.
If he earns 6% on his investments, how much must be deposited at the start of his studies for him to withdraw $10,000 a year for three years?
a) $10,000
b) $29,100
c) $30,000
d) $18,390
Answer:
d) $18,390
Step-by-step explanation:
Let X be the amount of money he deposited on the first year of his study.
The question says that he earns 6% on his investment without specifying the investment return time. However, normally it's annually, so let's assume his earning is 6% per annum.
Given that he did not make any withdrawal until the end of the first year, in 2nd year, he'll get the earning of his investment minus 10,000 to pay for his first year study
2nd year Y = X(1.06 ) - 10000
The same goes with 3rd year
3rd year Z = Y(1.06) - 10000
In worst case scenario, let's assume all of the money is used up at the end of third year
Z = 0
Y(1.06) - 10000 = 0
Substitute the first year into the equation:
Y(1.06) - 10000 = 0
(X(1.06)-10000)1.06 -10000 = 0
(1.06^2)X -1.06(10000) - 10000 = 0
X = (10000+10600)/1.06^2 = 18333.92
So the minimum deposit he needs to make to survive for the whole 3 years is $18333.92.
From the answer selection, the nearest value is d) $18,390
As Jupiter revolves around the sun, it travels at a speed of approximately 8 miles per second. Convert this speed to miles per minute. At this speed, how many miles will Jupiter travel in 5 minutes? Do not round your answers
Answer:
The answer to your question is
a) [tex]\frac{480 mi}{min}[/tex]
b) distance = 2400 mi
Step-by-step explanation:
a) 8 mi/s convert to mi/min
[tex]\frac{8 mi}{s} x \frac{60 s}{1 min} = \frac{8 x 60 mi }{min} = \frac{480 mi}{min}[/tex]
b) [tex]speed = \frac{distance}{time}[/tex]
distance = speed x time
distance = [tex]\frac{480 mi}{min} x 5 min[/tex]
distance = 2400 mi
Melanie bought 4 large gifts and 2 small gifts. Mary bought 1 large gift and 20 small gifts. Each small gift costs $10. They both spent the same amount of money. What's the price of one large gift?
Answer:the price of one large gift is $60
Step-by-step explanation:
Let x represent the cost of one large gift.
Melanie bought 4 large gifts and 2 small gifts. Since each small gift costs $10, it means that the total amount that Melanie spent is
4x + 2×10 = 4x + 20
Mary bought 1 large gift and 20 small gifts. It means that the total amount that Mary spent is
x + 20×10 = x + 200
They both spent the same amount of money. This means that
4x + 20 = x + 200
4x - x = 200 - 20
3x = 180
x = 60
To find the price of one large gift, we compare the total amount spent by Melanie and Mary. By setting up an equation and solving for the price of one large gift, we find that it is $60.
Explanation:To find the price of one large gift, we need to calculate the total amount spent on gifts by both Melanie and Mary and divide it by the total number of large gifts they bought. Melanie bought 4 large gifts and 2 small gifts, while Mary bought 1 large gift and 20 small gifts. Let's assume the price of one large gift is x.
The total amount spent by Melanie can be calculated as (4x + 2*10), since each small gift costs $10. The total amount spent by Mary can be calculated as (x + 20*10). Since both of them spent the same amount of money, we can set up the equation: 4x + 2*10 = x + 20*10.
Simplifying the equation, we get 4x + 20 = x + 200. Subtracting x from both sides, we get 3x + 20 = 200. Subtracting 20 from both sides, we get 3x = 180. Dividing both sides by 3, we find that x = 60. Therefore, the price of one large gift is $60.
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Prove that if the real-valued function f is strictly increasing, then f is oneto-one.
Answer:
See proof below
Step-by-step explanation:
Let x,y be arbitrary real numbers. We want to prove that if x≠y then f(x)≠f(y) (this is the definition of 1-1).
If x≠y, we can assume, without loss of generality that x<y using the trichotomy law of real numbers (without loss of generality means that the argument in this proof is the same if we assume y<x).
Because f is strictly increasing, x<y implies that f(x)<f(y). Therefore f(x)≠f(y) because of the trichotomy law, and hence f is one-to-one.
Cara grew 4inches in second grade and 3 inches in third grade. If Cara was 44 inches tall at the start of second grade, how tall is she at the end of third grade?
Answer:
Height of Cara at the end of the Third grade is 51 inches.
Step-by-step explanation:
Given:
Height of Cara at the start of second grade = 44 inches
In second grade she grew = 3 inches.
Hence height of Cara at the end of the second grade will be equal to sum of Height of Cara at the start of second grade and height she grew in second grade.
Framing the equation we get;
height of Cara at the end of the second grade = 44 + 4 = 48 inches
Also Given:
Height she grew in third grade = 3 inches
We need to find Height of Cara at end of third grade.
Hence height of Cara at the end of the Third grade will be equal to sum of Height of Cara at the end of second grade and height she grew in third grade.
Framing in equation form we get;
Height of Cara at the end of the Third grade = 48 + 3 = 51 inches
Hence Height of Cara at the end of the Third grade is 51 inches.
Answer:
51 inches
Step-by-step explanation:
44 + 4 + 3= 51
Can the positive integer p be expressed as the product of two integers, each of which is greater than 1?
Answer:
maybe
Step-by-step explanation:
If p is prime, then answer is NO. If p is not prime, the answer is YES.
__
Some positive integers are prime; some are not. We need to know more about p before we can give a better answer than this.