The ratio of the output work to input force is the _ of the machine ?

1. [tex]-8.78 \cdot 10^5 J[/tex]

The energy lost by the water is given by:

[tex]Q=m C_s \Delta T[/tex]

where

m = 3.0 kg = 3000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

[tex]\Delta T=10.0C-80.0C=-70.0 C[/tex] is the change in temperature

Substituting,

[tex]Q=(3000 g)(4.179 J/gC)(-70.0 C)=-8.78 \cdot 10^5 J[/tex]

2. [tex]3.24 \cdot 10^4 J[/tex]

The energy added to the aluminium is given by:

[tex]Q=m C_s \Delta T[/tex]

where

m = 0.30 kg = 300 g is the mass of aluminium

Cs = 0.900 J/g•°C is the specific heat

[tex]\Delta T=150.0 C-30.0C =120.0 C[/tex] is the change in temperature

Substituting,

[tex]Q=(300 g)(0.900 J/gC)(120.0 C)=3.24 \cdot 10^4 J[/tex]

3a. [tex]-5.6^{\circ}C[/tex]

The temperature change of the water is given by

[tex]\Delta T=\frac{Q}{m C_s}[/tex]

where

[tex]Q = -232 kJ=-2.32\cdot 10^5 J[/tex] is the heat lost by the water

[tex]m=10.0 kg=10000 g[/tex] is the mass of water

Cs = 4.179 J/g•°C is the specific heat

Substituting,

[tex]\Delta T=\frac{-2.32\cdot 10^5 J}{(10000g)(4.179 J/gC)}=5.6^{\circ}C[/tex]

3b. [tex]+10.2^{\circ}C[/tex]

The temperature change of the copper is given by

[tex]\Delta T=\frac{Q}{m C_s}[/tex]

where

[tex]Q = 1.96 kJ=1960[/tex] is the heat added to the copper

[tex]m= 500 g[/tex] is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

Substituting,

[tex]\Delta T=\frac{1960 J}{(500g)(0.385 J/gC)}=10.2^{\circ}C[/tex]

4. 42.9 g

The mass of the water sample is given by

[tex]m=\frac{Q}{C_S \Delta T}[/tex]

where

[tex]Q=4300 J[/tex] is the heat added

[tex]\Delta T=39 C-15 C=24C[/tex] is the temperature change

Cs = 4.179 J/g•°C is the specific heat

Substituting,

[tex]m=\frac{4300 J}{(4.179 J/gC)(24 C)}=42.9 g[/tex]

5. 115.5 J

The heat used to heat the copper is given by:

[tex]Q=m C_s \Delta T[/tex]

where

m = 5.0 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

[tex]\Delta T=80.0 C-20.0C =60.0 C[/tex] is the change in temperature

Substituting,

[tex]Q=(5.0 g)(0.385 J/gC)(60.0 C)=115.5 J[/tex]

6. 0.185 J/g•°C

The specific heat of iron is given by:

[tex]C_s = \frac{Q}{m \Delta T}[/tex]

where

Q = -47 J is the heat released by the iron

m = 10.0 g is the mass of iron

[tex]\Delta T=25.0-50.4 C=-25.4 C[/tex] is the change in temperature

Substituting,

[tex]C_s = \frac{-47 J}{(10.0 g)(-25.4 C)}=0.185 J/gC[/tex]

These questions relate to calculating heat energy changes using the concept of specific heat. Specific heat, an intensive property, is used to calculate how much heat is lost or gained during temperature changes of different substances. The formula q=mcΔT, where 'q' is heat energy, 'm' is mass, 'c' is specific heat and 'ΔT' is the temperature change, is used for the calculations.

The specific heat of a substance is an intensive property that defines how much heat energy is needed to raise 1 gram of the substance by 1 degree Celsius.

For the first question, when 3.0 kg of water is cooled from 80.0°C to 10.0°C, we use the formula q=mcΔT, where m is mass, c is specific heat and ΔT is the change in temperature. Substituting the given values, we get q = 3000g * 4.179 J/g°C *(10.0°C - 80.0°C) which gives -881,940 Joules (roughly -882 kJ). The negative sign indicates that heat energy is lost.

For the second question, we apply the same formula, with m=0.30 kg, c=0.900 J/g°C and ΔT = 150.0°C - 30.0°C, giving 32.4 kJ heat energy needed.

For the third question, we reverse the equation to solve for temperature. For 10.0 kg of water losing 232 kJ, ΔT = q / (mc), or 232,000J / (10,000g * 4.179 J/g°C), resulting in an approximately 5.54°C temperature loss. For 500g of copper gaining 1.96 kJ of heat, the equation gives a temperature change of about 10°C.

The same principles are applied to answer the remaining questions.

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All electromagnetic waves have the same speed when they're all in the same medium.

Note: Sound waves don't belong on this list, because they're not electromagnetic waves. The speed of sound in air is only about 0.0001 percent of the speed of electromagnetic waves in air.

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Answer: B.Heat is never converted completely into mechanical energy.

Explanation:

According to the second principle of thermodynamics:  

"The amount of entropy in the universe tends to increase over time"

However the first formulation of this law (by Sadi Carnot) states:

"There is an upper limit to the efficiency of conversion of heat to work, in a heat engine "

This means the heat cannot be completely transformed into mechanical energy in a machine. That is why a machine's effieciency is always less than 100%

Answer:

B

Explanation:

Use logic

A positron, or an anti-electron, is a particle with a positive charge and the mass of an electron.

Answer:

The boiling point of water is around 185.9ºF or 85.5ºC

Explanation:

The boiling point of water depends on the atmospheric pressure. So, the higher the elevation, the lower the atmospheric pressure, therefore the boiling point of water is lower as well. Assuming that sea level pressure is constant ,(760 mmHg, 29.92inches Hg or 14.69psi) the boiling point of water is 212ºF (100ºC). Approximately, for every 500 foot (150m) of elevation increase, the boiling point temperature decreases 1ºF (0.55ºC).

The imaginary second level is 60 dB more intense than the real level of the caller.

60 dB means a multiplication of  10⁶  = 1 million.

That's how many equally-talented callers it would take to be 60 dB louder than him.

The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.

Decibel is the unit of sound. Its symbol is ‘dB’. We can define decibel as:

A unit of measurement used to express the ratio of one value of a power or field quantity to another on a logarithmic scale, the logarithmic quantity being called the power level or field level, respectively.

60 dB = 10 log₁₀ (P₁/P)

120 dB =  10 log₁₀( P₂/P₀)

The man have to produce square of his intensity level to reach the pain level of 120 dB.

The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.

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Answer:

-3 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum.

In fact, the system squid+water inside is initially at rest, so the total momentum is zero:

[tex]p_i=0[/tex]

while the final momentum is:

[tex]p_f = m_s v_s + m_w v_w[/tex]

where

[tex]m_s=1.5 kg[/tex] is the mass of the squid

[tex]v_s[/tex] is the velocity of the squid

[tex]m_w = 0.10 kg[/tex] is the mass of water

[tex]v_w = 45 m/s[/tex] is the water velocity

Since the total momentum must be conserved,

[tex]p_i = p_f = 0[/tex]

So we have

[tex]m_s v_s + m_w v_w =0\\v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.10 kg)(45 m/s)}{1.5 kg}=-3 m/s[/tex]

where the negative sign means the direction is opposite to that of the water.

The final velocity of the squid after the ejection of the water is 3 m/s backwards.

The given parameters;

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

1.5(0) + 0.1(0) = 1.5v₁  +  45(0.1)

0 = 1.5v₁  + 4.5

1.5v₁ = -4.5

[tex]v_1 = \frac{-4.5}{1.5} \\\\v_1 = -3 \ m/s[/tex]

Thus, the final velocity of the squid after the ejection of the water is 3 m/s backwards.

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The sky appears blue because the blue wavelength of light from the sun is scattered more by the air molecules that the other colors. The sky appears with a red hue at dawn and sunsets because the red spectrum is able to pass through the longer atmosphere in the oblique angle while blue light is scattered well before.  

Answer: the scattering and reflection of light by dust particles

Explanation:

ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh this confused mee

Answer:

200

Explanation:

Melting point of a substance is 200.

The temperature at which a solid and liquid phase can coexist in equilibrium and the point at which matter transforms from a solid to a liquid is known as a substance's melting point. Pure solutions and liquids fall within this definition.

It is important to specify melting point because it relies on pressure. Melting point tables frequently use standard pressures like 100 kPa or 1 atmosphere. The liquefaction point is another name for the melting point.

The temperature at which a liquid changes to a solid (the reverse of melting) is the freezing point or crystallization point. The freezing point and the melting point do not necessarily occur at the same temperature.

Therefore, Melting point of a substance is 200.

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I believe it’s D, an applied force.

A reaction force seems to refer to Newton’s third law, but is relatively vague to be the answer to this question.

An expected force isn’t a concept nor the name of any subject of forces that is taught within the physics textbooks.

A positive force refers to direction, a negative force can have less, equal, or even more magnitude than the positive force, thus it contradicts itself. As that’s still a force that can push or pull.

So I believe it to be D.

A force that pushes or pulls is known as an applied force. Option D is correct.

Force is defined as an object in motion, and its rate of change of momentum is called force.

here,

A force applied to an object is one that is exerted on it by another object or by an external agent. This force can cause the object to accelerate or change direction. Pushing a book across a table, pulling a sled across the snow, or lifting a weight with a pulley are all examples of applied forces.

It is important to note that for every applied force, there is an equal and opposite reaction force, according to Newton's third law of motion. This means that when an object exerts a force on another object, the second object exerts an equal and opposite force back on the first object. This reaction force is also an applied force, and it can affect the motion of both objects involved.

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To determine the compression of the spring when a 4.0 kg object is dropped from 1.0 meter, we use the conservation of energy principle. The gravitational potential energy of the dropped object is converted into the spring's elastic potential energy. Calculations show the spring will compress approximately 9.0 cm.

We can solve the problem of the 4.0 kilogram object being dropped onto a spring by considering the conservation of energy. The gravitational potential energy at the height of 1.0 meter will convert into the elastic potential energy of the spring once the spring is compressed and the system momentarily comes to rest.

The gravitational potential energy (PE) can be calculated using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s2), and h is the height from which the object is dropped. Therefore, PE = 4.0 kg * 9.8 m/s2 * 1.0 m = 39.2 Joules.

The elastic potential energy stored in a compressed spring is given by the formula PEspring = 1/2 * k * x2, where k is the spring constant and x is the compression distance. Setting the gravitational potential energy equal to the spring's elastic potential energy gives 39.2 J = 1/2 * 850 N/m * x2. Solving for x gives x = sqrt((2 * 39.2) / 850) which approximately equals 0.09 meters or 9.0 cm.

Answer: less

Explanation:

Answer:

You forgot to put the question it's asking but its Gamma ray

Explanation:

Natalia is studying a wave produced in her magnetics lab. This wave can move through the empty space in a vacuum and carries a lot of energy.

What wave is Natalia most likely studying?

Gamma ray is the answer

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An object's gravitational potential energy is

(mass) x (gravity) x (height above ground) .

I don't see the object's speed anywhere in that formula, do you ?

An object's speed has no effect whatsoever on its potential energy ... only if it changes the object's height above ground.

The answer is C) Effluent

It makes them be three forces

The dielectric constant of the dielectric material is 3.5.

Given that the capacitance of the parallel-plate capacitor without the dielectric is 1.2 nF, and the capacitance increases by 3.0 nF when the gap is filled with the dielectric, we can find the dielectric constant using the equation:

C' = KC

Since the original capacitance is 1.2 nF and the increased capacitance is 1.2 + 3.0 = 4.2 nF, we can plug these values into the equation and solve for K:

KC = C'

K * 1.2 nF = 4.2 nF

K = 4.2 nF / 1.2 nF = 3.5

Therefore, the dielectric constant of the dielectric material is 3.5.

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The most common atom of iron has 26 protons and 30 neutrons in its nucleus. What are its atomic number, atomic mass, and number of electrons if it is electrically neutral? This atom has atomic number 26, atomic mass 56, and has 26 electrons.

Answer :The mass number is 56.

Explanation:

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons = 26+ 30 =56

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

Atomic number = Number of electrons = Number of protons = 26

Hence, neutrons and protons affects the mass number and thus the mass number will be 56.

Answer:

1/3

Explanation:

We can solve the problem by using the lens equation:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so

[tex]p=2f[/tex]

So we can find q from the equation:

[tex]\frac{1}{q}=\frac{1}{(-f)}-\frac{1}{p}=-\frac{1}{f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f[/tex]

Now we can find the magnification of the image, given by:

[tex]M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}[/tex]

Yes sirree !  Uh huh, uh huh.  Truer words are rarely spoken.

B because it is the only evidence that displays an effect from the field without contact

a) 14.4 m/s

The problem can be solved by using the law of conservation of total momentum; in  fact, the total initial momentum must be equal to the final total momentum:

[tex]p_i = p_f[/tex]

So we have:

[tex]m_g u_g + m_b u_b = m_g v_g + m_b v_b[/tex] (1)

where

[tex]m_b = m_g = m = 0.53 kg[/tex] is the mass of each ball

[tex]u_g = 14.4 m/s[/tex] is the initial velocity of the green ball

[tex]u_b = 0[/tex] is the initial velocity of the blue ball

[tex]v_g=0[/tex] is the final velocity of the green ball

[tex]v_b[/tex] is the final velocity of the blue ball

Simplifying the mass in the equation and solving for [tex]v_b[/tex], we find

[tex]v_b = u_g = 14.4 m/s[/tex]

b) 12.0 m/s

This time, the green ball continues moving after the collision at

[tex]v_g = 2.4 m/s[/tex]

So the equation (1) becomes

[tex]u_g = v_g + v_b[/tex]

And solving for [tex]v_b[/tex] we find

[tex]v_b = u_g - v_g = 14.4 m/s-2.4 m/s=12.0 m/s[/tex]

c) 13.5 m/s

This time, the green ball continues moving after the collision at

[tex]v_g = 0.9 m/s[/tex]

So the equation (1) becomes

[tex]u_g = v_g + v_b[/tex]

And solving for [tex]v_b[/tex] we find

[tex]v_b = u_g - v_g = 14.4 m/s-0.9 m/s=13.5 m/s[/tex]

Final answer:

To find the final speeds of the blue ball after the green ball collides with it, the conservation of momentum principle is used, considering the green ball's various final speeds post-collision for each situation. The final speeds of the blue ball are 14.4 m/s, 12.0 m/s, and 13.5 m/s, respectively.

Explanation:

The problem involves conservation of momentum during collisions, as the surface is considered frictionless, and energy is conserved during perfectly inelastic collisions (although the question does not specify if the collisions are perfectly elastic or inelastic).

To solve for the final speed of the blue ball in each given situation, we'll apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Calculating the Final Speeds

Final answer:

To find the position of the ball, y, in terms of time, t, we need to consider the forces acting on the ball. The weight of the ball and the force due to air resistance act in opposite directions. By using Newton's second law and integrating the velocity function, we can determine the position function of the ball.Therefore, the position of the ball, y, in terms of time, t, is given by y(t) = -(gt²)/2

Explanation:

To find the position of the ball, y, in terms of time, t, we need to consider the forces acting on the ball. The weight of the ball, mg, and the force due to air resistance, 4v, act in opposite directions. The net force can be calculated using Newton's second law, F = ma.

Using the equation F = ma, we have mg - 4v = ma. Rearranging the equation to solve for v, we get v = (mg - ma)/4. Substitute the given values of m = 0.096 kg, g = 9.8 m/s², and a = 0.075 m/s²into the equation to find v. Then, integrate the velocity function to find the position function y(t).

After solving the integration, we get y(t) = -(gt²)/2 + C, where C is the constant of integration. To find the value of C, we can use the initial condition y(0) = 0. Substituting the values, we find C = 0.

Therefore, the position of the ball, y, in terms of time, t, is given by y(t) = -(gt²)/2

Well, if the skydiver is at constant velocity, than there’s no acceleration, as stated by Newton’s first law. Thus the total net force would equate to 0. In order to make this statement true, the answer would have to be exactly 600 N.

Force is defined as the product of mass and acceleration .it is a vector quantity. The force acting on the skydiver must be 600 N which should be acting upward.

Force is defined as the action on any object that has the ability to change the shape, size, and direction of an object is in motion or in static condition.

It is a vector quantity defined as the product of mass and acceleration. Acceleration is the rate  change of velocity with respect to the time

Force is given by;

[tex]\rm {Force = Mass \times Acceleration}[/tex]

As the definition of acceleration if the velocity change is zero in that condition the force acting is zero. that's why force will also be zero

[tex]\rm {F +ma+mg =0 }[/tex]

If acceleration is zero in that condition

[tex]\rm {F =-mg }[/tex]

[tex]\rm {F = -600 N }[/tex]

where - ve shows the direction of force is negative

therefore a force of exactly 600 N is acting upward on the skydiver.

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Answer:

3.3 mT

Explanation:

First of all, we need to find the strength of the electric field between the two parallel plates.

We have:

[tex]\Delta V=200 V[/tex] (potential difference between the two plates)

[tex]d=1.0 cm=0.01 m[/tex] (distance between the plates)

So, the electric field is given by

[tex]E=\frac{\Delta V}{d}=\frac{200 V}{0.01 m}=2\cdot 10^4 V/m[/tex]

Now we want the electron to pass between the plates without being deflected; this means that the electric force and the magnetic force on the electron must be equal:

[tex]F_E = F_B\\qE=qvB[/tex]

where

q is the electron charge

E is the electric field strength

v is the electron's speed

B is the magnetic field strength

In this case, we know the speed of the electron: [tex]v=6.0\cdot 10^6 m/s[/tex], so we can solve the formula to find B, the magnetic field strength:

[tex]B=\frac{E}{v}=\frac{2\cdot 10^4 V/m}{6.0\cdot 10^6 m/s}=0.0033 T=3.3 mT[/tex]

The magnetic field strength will allow the electron to pass between the plates without being deflected is 0.0033 T.

The electric field strength of the electron is calculated as follows;

E = V/d

E = 200/(0.01)

E = 20,000 V/m

The magnetic field strength is related to electric field in the following formula;

qvB = qE

vB = E

B = E/v

B = (20,000)/(6 x 10⁶)

B = 0.0033 T

Thus, the magnetic field strength will allow the electron to pass between the plates without being deflected is 0.0033 T.

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the north end to the south end.

Answer

the answer is option A/ "north end to the south end"

Explanation:

Answer:

The electric potential (voltage) [tex]V[/tex] produced by a point charge [tex]Q[/tex], at any point in space, is given by the following equation:

[tex]V=k\frac{Q}{r}[/tex]

Where:

[tex]k=8.99(10)^{9} Nm^{2}/C^{2}[/tex] is the Coulomb's constant

[tex]r[/tex] is the distance  

The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.

Answer:

v=k*q/d

Explanation:

The formula v=k*q/r is also correct but in this case v=k*q/d was given as a choice.