The Mole #2
Avogadro's Number
PLEASE HELP ASAP! due tmr will give brainliest!

The Mole #2Avogadro's Number PLEASE HELP ASAP! Due Tmr Will Give Brainliest!

Answers

Answer 1

The solution is here,

given mass of copper wire(m)=25 g

no. of moles in given mass of Cu=0.393

a) no. of atoms= no. of moles×avogardo's number

=0.393×6.023×10^23=2.36 ×10^23 atoms

b) 25 g of Cu wire has 0.393 moles

so 200 g of Cu wire has 0.393/25 × 200=3.144 mol.

no. of atoms= 3.144×2.023×10^23=1.89×10^24 atoms.

c) 25 g of Cu wire has 2.36×10^23 atoms

so 5 g of Cu wire has (2.36×10^23)/25 × 5

=4.72×10^22 atoms

( b can also be solve like c)


Related Questions

Bromine can be classified as a

Answers

Answer:

Halogen / salt-former

Explanation:

Bromine is classified as an element in the 'Halogens' section which can be located in group 7 of the Periodic Table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts".

Which one of these is a gas
NaNo3
KL
KCL
NH3

Answers

Answer:

nano3 is a solid so its not that one it has to be NH3

Explanation:

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Final answer:

The substance among the given options that is a gas is NH3 or ammonia, as indicated by (g) for gaseous state in the provided reference list.

Explanation:

Among the substances listed — NaNO3, KL, KCL, and NH3 — the one that is a gas is NH3, also known as ammonia. From the reference information provided, NH3 is indicated as NH3(g), where (g) denotes that it is in the gaseous state at standard temperature and pressure. The other substances NaNO3, KL (which seems to be a typo and should likely be KI), and KCL (KCl) are solids as indicated by the (s) in the reference list provided.

NH3 is a common gas known for its pungent odor and is used in various applications, including household cleaning products and fertilizers.

A chemical process dissolves 500 milligrams of iron oxide every 20 minutes. How long would it take this reaction to dissolve 2 lbs of iron oxide?

Answers

Answer:

[tex]\boxed{\text{25 da}}[/tex]

Explanation:

Step 1. Convert pounds to milligrams

(a) Pounds to grams

[tex]\text{Mass} = \text{2 lb} \times \dfrac{\text{454 g}}{\text{1 lb}} = \text{910 g}[/tex]

(b) Grams to milligrams

[tex]\text{Mass} = \text{910 g} \times \dfrac{\text{1000 mg}}{\text{1 g}} = \text{910 000 mg}[/tex]

Step 2. Calculate the time

(a) Milligrams to minutes

[tex]t = \text{910 000 mg}} \times \dfrac{\text{20 min}}{\text{500 mg}} = \text{36 000 min}[/tex]

(b) Minutes to hours

[tex]t = \text{36 000 min} \times \dfrac{\text{1 h}}{\text{60 min}} = \text{610 h}[/tex]

(c) Hours to days

[tex]t = \text{ 610 h} \times \dfrac{\text{1 da}}{\text{24 h}} = \text{25 da}[/tex]

It will take [tex]\boxed{\textbf{25 da}}[/tex]to dissolve the iron oxide.

Answer : The time taken for the reaction is 36363.64 minutes.

Explanation :

First we have to convert the mass of iron oxide from milligram to pounds (lbs).

[tex]1\text{ lbs}=453592mg[/tex]

or,

[tex]1mg=\frac{1}{453592}\text{ lbs}[/tex]

As, [tex]1mg=\frac{1}{453592}\text{ lbs}[/tex]

So, [tex]500mg=\frac{500mg}{1mg}\times \frac{1}{453592}\text{ lbs}=0.0011\text{ lbs}[/tex]

Now we have to calculate the time taken for the reaction.

As, [tex]0.0011\text{ lbs}[/tex] of iron oxide take time = 20 minutes

As, [tex]2\text{ lbs}[/tex] of iron oxide take time = [tex]\frac{2\text{ lbs}}{0.0011\text{ lbs}}\times 20\text{ minutes}=36363.64\text{ minutes}[/tex]

Therefore, the time taken for the reaction is 36363.64 minutes.

Select the correct answer. Which of the following tests could be safely used to distinguish a strong base from a weak base? A. taste B. touch C. litmus paper D. electrical conductivity

Answers

Answer: Option (D) is the correct answer.

Explanation:

Bases are the substances that release hydroxide ions when dissolved in water.

A strong base will dissociate completely in water and give more number of hydroxide ions [tex](OH^{-})[/tex]. Whereas a weak base will slightly dissolve to give hydroxide ions [tex](OH^{-})[/tex] in water.

So, a strong base will have high electrical conductivity and a weak base will have low electrical conductivity.

Since, both are bases (strong base and weak base) therefore, both of them will have bitter taste, slippery texture and they will turn red litmus into blue.

Hence, we can conclude that electrical conductivity tests could be safely used to distinguish a strong base from a weak base.

Litmus paper tests could be safely used to distinguish a strong base from a weak base. The correct answer is C.

To distinguish a strong base from a weak base, one can use litmus paper as a safe and effective method. Litmus paper is a pH indicator that changes color in response to the acidity or basicity of a solution.

When a strong base, such as sodium hydroxide (NaOH), comes into contact with litmus paper, it will cause a dramatic color change, typically from red to blue in the case of blue litmus paper.

This is because strong bases have a high concentration of hydroxide ions (OH-) and can rapidly accept protons (H+), leading to a significant increase in pH.

On the other hand, a weak base, such as ammonia (NH3), will also cause a color change but to a lesser extent or more slowly, reflecting its lower ability to accept protons compared to a strong base.

The pH change will be less dramatic, and the color change on the litmus paper may be less pronounced or take longer to occur.

The other options are not suitable for distinguishing between strong and weak bases:

A. Taste -

Tasting chemicals is extremely dangerous and should never be done. It does not provide a safe method to distinguish between strong and weak bases.

B. Touch -

While some bases may feel slippery or soapy to the touch due to the formation of soap-like substances when they react with oils on the skin, this method is not safe and does not provide a clear distinction between strong and weak bases.

D. Electrical conductivity -

Both strong and weak bases can conduct electricity if they are ionic and dissociate into ions in solution. Therefore, electrical conductivity cannot be used to distinguish between the strength of bases.

In summary, litmus paper is the safest and most reliable method among the options provided to distinguish a strong base from a weak base based on the degree of color change and the speed of the reaction.

Which of the following is used in pencils?

A. Graphite
B. Silicon
C. Charcoal
D. Phosphorous

Which of the following metals forms an amalgam with other metals?

A. Tin
B. Mercury
C. Lead
D. Zinc

Answers

Answer:

1st answer:  A. Graphite

2nd answer:  B.  Mercury

Explanation:

What is the scientific notation of 696,000 kilometers

Answers

Hello There!

The Answer Is In Image Provided.

Your Unit Is Still Kilometers

a gas at pressure 4.4 atm and 32.14 L has a new volume of 72 L, what is the new pressure

Answers

Answer:

[tex]\boxed{\text{2.0 atm}}[/tex]

Explanation:

If the temperature is constant, the only variables are pressure and volume, so we can use Boyle’s Law.

p₁V₁ = p₂V₂

Data:

p₁ = 4.4 atm; V₁ = 32.14 L

p₂ = ?;           V₂ = 72     L

Calculation:

4.4 × 32.14 = p₂ × 72

141 = 72p₂

[tex]p_{2} = \dfrac{141}{72} = \textbf{2.0 atm}[/tex]

The new pressure is [tex]\boxed{\textbf{2.0 atm}}[/tex]

How many miles of beryllium chloride BeCl2 are needed to make 130 ml of a 0.025 M solution

Answers

Answer:

= 0.00325 moles of beryllium

Explanation:

Molarity or concentration is given by the formula;

Molarity = Number of moles/Volume in L

Therefore, to get the number of moles

Moles = Molarity × Volume

           = 0.025 M × 0.13 L

           = 0.00325 moles of beryllium

The critical pressure of carbon dioxide is 72.7 atm what is this value in units of pascals

Answers

Answer:

7366.328 kPa.

Explanation:

The critical pressure of carbon dioxide is 72.7 atm.

To convert from atm to kPa, we use the relation that:

1.0 atm = 101.325 kPa.

Applying conversion factor:

The conversion factor = (101.325 kPa/1.0 atm)

∴ The critical pressure of carbon dioxide (in kPa) = (72.7 atm)(101.325 kPa/1.0 atm) = 7366.328 kPa.

Answer:

= 7366.328 kPa.

Explanation:

(72.7 atm)(101.325 kPa/1.0 atm)

= 7366.328 kPa.

To ensure that the air in the shuttle remains free of excess CO2, engineers test the air-purification system. they combine 1.000 × 103 g LiOH with 8.80 × 1 02 g CO2. The reaction produces 3.25 × 102 g H2O. What is the limiting reactants in this test reaction? What is the theoretical yield of this test reaction?

Answers

The

balanced reaction is:

2LiOH + CO2 = Li2CO3 + H2O

We

are given the amount of the reactants to be reacted. This will be the starting point of our

calculations. To determine the limiting reactant, we convert the amounts from grams to moles.

1.000 × 10^3 g LiOH  (1 mol / 25.95 g) = 38.54 mol LiOH

8.80 × 10^2 g CO2 ( 1mol / 44.01 g) = 20.00 mol CO2

From the balanced reaction, the molar ratio of the reactants is 2:1. This means that every two mole of lithium hydroxide, 1 mole of carbon dioxide is needed. It is clear that, from the given amounts, CO2 is the limiting reactant.

Answer: The limiting reagent is carbon dioxide and theoretical yield of the reaction is 360 g.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]      .....(1)

For LiOH:

Given mass of LiOH = [tex]1.00\times 10^3g[/tex]

Molar mass of LiOH = 23.95 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of LiOH}=\frac{1.00\times 10^3g}{23.95g/mol}=41.75mol[/tex]

For carbon dioxide:

Given mass of carbon dioxide = [tex]8.8\times 10^2g[/tex]

Molar mass of carbon dioxide = 44 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of carbon dioxide}=\frac{8.8\times 10^2g}{44g/mol}=20mol[/tex]

The chemical equation for the reaction of lithium hydroxide and carbon dioxide gas follows:

[tex]2LiOH(s)+CO_2(g)\rightarrow Li_2CO_3(s)+H_2O(l)[/tex]

By Stoichiometry of the reaction:

1 moles of carbon dioxide reacts with 2 moles of lithium hydroxide.

So, 20 moles of carbon dioxide will react with = [tex]\frac{2}{1}\times 20=40mol[/tex] of lithium hydroxide.

As, given amount of lithium hydroxide is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon dioxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of carbon dioxide produces 1 mole of water

So, 20 moles of carbon dioxide will produce = [tex]\frac{1}{1}\times 20=20moles[/tex] of water

Now, calculating the theoretical yield of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 20 moles

Putting values in equation 1, we get:

[tex]20mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=360g[/tex]

Hence, the limiting reagent is carbon dioxide and theoretical yield of the reaction is 360 g.

Calculate the number of moles of methane (CH4)needed to produce 7.84 g of water (H2O).​

Answers

Answer:

0.218 mol.

Explanation:

Firstly, we need to write the balanced reaction:

CH₄ + 2O₂ → CO₂ + 2H₂O,

It is clear that 1 mol of CH₄ reacts with 2 mol of O₂ to produce 1 mol of CO₂ and 2 mol of H₂O.

We need to calculate the no. of moles of 7.84 g H₂O:

n = mass/molar mass = (7.84 g)/(18.0 g/mol) = 0.436 mol.

Using cross multiplication:

1 mol of CH₄ is needed to produce → 2 mol of H₂O, from stichiometry.

??? mol of CH₄ is needed to produce → 0.436 mol of H₂O.

∴ The no. of moles of CH₄ = (1 mol)(0.435 mol)/(2 mol) = 0.218 mol.

A material has a volume of 63.0 cm3 and a mass of 28 grams.  What is the density of the material in g/cm3 to the correct number of significant figures?

Answers

Answer:

0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

Explanation:

Knowing that:

d = m/V,

where, d is the density of the material (g/cm³).

m is the mass of the material (m = 28 g).

V is the volume of the material (V = 63.0 cm³).

∴ d = m/V = (28 g)/(63.0 cm³) = 0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

What's the inner core of the Jovian planets made of? A. Hydrogen compounds, solid rock, and metals B. Bacteria fossils, hydrogen compounds, and ice crystals C. Helium gas, hydrogen gas, and rocks D. Metals, helium gas, and hydrogen gas

Answers

Answer:

A. Hydrogen compounds, solid rock, and metals

Explanation:

The Jovian planets, also referred to as outer planets, are the four planets that are in the outer half of the solar system. These planets are gas giants, and they are mostly made out of gases, having much larger sizes and masses than the terrestrial planets. The inner cores of these planets also differ from the cores of the terrestrial planets. The inner cores of these planets are made out of rocks, metals, and hydrogen compounds. In general their cores are the size of the Earth, though they are much more massive.

Answer: The inner core of the Jovian planets are made of: Hydrogen compounds, solid rock, and metals.

What is the name of the ionic compound RbCI

Answers

It would be Rubidium chloride.

Ammonia reacts with oxygen to produce nitric acid (HNO3) and water. What mass of nitric acid, in grams, can be made from 405 g of ammonia?
Express the mass to three significant figures and include the appropriate units.


Answers

Final answer:

The mass of nitric acid that can be produced from 405 g of ammonia is approximately 1500 g, when rounded to three significant figures.

Explanation:

To determine the mass of nitric acid that can be made from 405 g of ammonia, we first need to write the balanced chemical equation for the reaction between ammonia and oxygen:

4NH3 + 5O2 -> 4HNO3 + 6H2O

This equation tells us that 4 moles of ammonia (NH3) react to produce 4 moles of nitric acid (HNO3).

The molar mass of ammonia (NH3) is approximately 17.03 g/mol. Therefore, 405 g of ammonia is equivalent to 23.77 moles (405 g / 17.03 g/mol). So, we can produce the same amount of moles of nitric acid (23.77 moles).

The molar mass of nitric acid (HNO3) is approximately 63.01 g/mol. Therefore, the mass of nitric acid that can be made from 405 g of ammonia is approximately 1497 g (23.77 moles x 63.01 g/mol). This value should be reported to three significant figures: 1500 g.

Learn more about Chemistry here:

https://brainly.com/question/13428382

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A compressor takes 0.50 m3 of a gas at 33°C and 760 mmHg and compresses it to 0.10 m3, cooling it to -55°C at the same time. What is the pressure of the gas at these new conditions? 3.7 x 10-4 mmHg 68 mmHg 2,700 mmHg 1.0 mmHg

Answers

Answer:

2,700 mmHg.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have two different values of V, P and T:

P₁V₁T₂ = P₂V₂T₁

P₁ = 760 mmHg, V₁ = 0.50 m³, T₁ = 33°C + 273 = 306.0 K.

P₂ = ??? mmHg, V₂ = 0.10 m³, T₂ = - 55°C + 273 = 218.0 K.

∴ P₂ = P₁V₁T₂/V₂T₁ = (760 mmHg)(0.50 m³)(218.0 K)/(0.10 m³)(306.0 K) = 2707.0 mmHg ≅  2,700 mmHg.

Answer:

2,700 mmHg.

Explanation:

O
Use the periodic table to determine which of the
following could be an isotope of bromine (Br).
Check all that apply.
Z = 79, A = 196
O Z= 35, A= 79
A= 79, N= 44
Z = 44, N= 44
O
DONE
Intro​

Answers

Answer:

The second and third option are isotopes of Bromine

Z=  35 A = 79

A = 79  N= 44

Explanation:

Step 1: What are isotopes ?

⇒ Elements  with same atomic number (Z) ( this means the same number of electrons and protons) but a different number of neutrons (N)

The atomic number (visible on the periodic table) is the number of protons.

The atomic mass is  the sum of the protons (Z) and neutrons (N), and is showed as 'A'. So A = Z+N

If we look at the periodic table, we can see that the atomic number of bromine (Z) = 35. This means the amount of protons = 35. Since isotopes have the same amount of protons, all isotopes of bromine, have 35 protons.

1) Z = 79, A = 196

Z = protons = electrons .So this element has 79 protons, as well as 79 electrons.

196 = 79 + N ⇒ N = 196 - 79 = 117 neutrons

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Gold (Au): 196Au

2) Z = 35 , A = 79

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons.

79 =35 + N ⇒ N = 79 - 35= 44 neutrons

⇒Since it does have 35 protons, it is an isotope of Bromine. This isotope has 44 neutrons

⇒ This is 79Br, which is a stable isotope of Bromine.

3) A=79, N = 44

Z = A - N ⇒ Z = 79 - 44 = 35

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons. It also has 44 neutrons.

⇒Since it does have 35 protons, it is an isotope of Bromine, with 44 neutrons: 79Br

4) Z = 44, N = 44

Z = protons = electrons .So this element has 44 protons, as well as 44 electrons.

A = 44 + 44 ⇒ A = 88  

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Ruthenium (Ru) : 88Ru

⇔So the second and third option are isotopes of Bromine

3.00 moles of helium gas (He) are in a container with a volume is 2.00 liters and a temperature is at 298 K. What is the approximate pressure in kilopascals?

Answers

Answer:

3718.628 kPa.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = ??? atm).

V is the volume of the gas in L (V = 2.0 L).

n is the no. of moles of the gas in mol (n = 3.0 mol).

is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 298.0 K).

∴ P = nRT/V = (3.0 mol)(0.0821 L.atm/mol.K)(298.0 K)/(2.0 L) = 36.7 atm.

To convert from atm to kPa:

∵ 1.0 atm = 101.325 kPa.

∴ P = (36.7 atm)(101.325 kPa/1.0 atm) = 3718.628 kPa.

a lithium atom has three electrons.A fluorine has 9 protons and 9 electrons,with 7 electrons in its outer energy level.Using a diagram,explain how an atom of lithium an an atom of fluorine combine by ionic bonding

Answers

The lithium atom provides the fluorine atom with one electron making both atoms stable. Fluorine has a better positive charge than lithium so fluorine will attract the electron. Now, the atoms fuse together to form an ionic bond and making lithium fluoride. Ionic bonds are caused by the attraction between two forces of atoms.

Answer:

The lithium atom has one electron in its outer shell, so it loses that one electron and becomes a [tex]Li^{1+}[/tex] ion. The fluorine atom has 7 electrons in its outer shell so it gains that one electron and becomes a [tex]F^{1-}[/tex] ion. The electrostatic force of attraction between the two ions, because of their charges, bonds them together in an ionic bond to make [tex]LiF[/tex], Lithium Fluoride.

Couldn't add a diagram, but hope it helps.

The climate of a place also depends upon the amount of water in the air. How do the rising temperatures around Earth affect the amount of water in the air? A) The water in the air evaporates because the temperature of air is rising. B) There is more water in the air because the rate of evaporation increases. C) The water in the air decreases because the water on Earth starts evaporating. D) There is less water in the air because the evaporated water falls down as rain.

Answers

Answer:

B) There is more water in the air because the rate of evaporation increases

Explanation:

As the temperatures rise across the globe, the rate of evaporation also increases, resulting in more water in the air. The reason for the increased evaporation is that the ice sheets and glaciers are melting, thus there's more liquid water. The more liquid water there is, the more evaporation there will be. As the evaporation increases, there will be an increase in the formation of clouds, thus there will be more precipitation around the world, gradually leading to warmer and wetter climate.

When magnesium chloride reacts with water, 5.85)L HCLg is produced. How many moles of HCL is produced​

Answers

Answer: 650 moles

Explanation: so converted in grams just to make it easy for me, its 5850 g of water right, which is 325 moles of water

so here's the balanced equation

MgCl2 + H20 ==> 2HCl + MgO

thus 1 mole of h20 gives us 2 moles of hcl, so 325 x 2 = 650 moles of hcl

A reaction has ∆H = −356 kJ and ∆S = −36 J/K. Calculate ∆G (kJ) at 25°C.

Answers

Answer: -345.2 KJ

Explanation: As we know that ,dG=dH-TdS

T=25+273=298 K

dG= -356 x1000-298(-36)= -356000+10728

=-345272 j

= -345.2 KJ

2. A solution is made by adding 1.23 mol of KCl to 1000.0 g of water. Assume that the
density of water (and the resulting solution) is 1.00 g/mL.
a. Calculate the formula weight of KCl.
b. Calculate the mass of KCl in grams.
c. Calculate the percent by mass of KCl in this solution.
d. Calculate the molarity of the solution.

Answers

Answer:

a. 74.55 g/mol.

b. 91.70 g.

c. 8.40%.

d. 1.23 mol/L.

Explanation:

a. Calculate the formula weight of KCl.

∵ Formula weight of KCl = atomic weight of K + atomic weight of Cl

atomic weight of K = 39.098 g/mol, atomic weight of Cl = 35.45 g/mol.

Formula weight of KCl = atomic weight of K + atomic weight of Cl = 39.098 g/mol + 35.45 g/mol = 74.548 g/mol ≅ 74.55 g/mol.

b. Calculate the mass of KCl in grams.

we can use the relation:

no. of moles (n) = mass/molar mass.

∴ mass of KCl = n*molar mass = (1.23 mol)*(74.55 g/mol) = 91.69 g ≅ 91.70 g.

c. Calculate the percent by mass of KCl in this solution.

The mass % of KCl = (mass of KCl/mass of the solution) * 100.

mass of KCl = 91.70 g,

mass of the solution = 1000.0 g of water + 91.70 g of KCl = 1091.70 g.

∴ The mass % of KCl = (91.70 g/1091.70 g)*100 = 8.399% ≅ 8.40%.

d. Calculate the molarity of the solution.

Molarity is the no. of moles of solute per 1.0 L of the solution.

M = (no. of moles of KCl)/(Volume of the solution (L))

no. of moles of KCl = 1.23 mol,

Volume of the solution = mass of water / density of water = (1000.0 g)/(1.00 g/mL) = 1000.0 mL = 1.0 L.

M = (1.23 mol)/(1.0 L) = 1.23 mol/L.

Final answer:

a. The formula weight of KCl is 74.55 g/mol. b. The mass of KCl in grams is 91.39 g. c. The percent by mass of KCl in the solution is 9.14%. d. The molarity of the solution is 1.23 M.

Explanation:

a. The formula weight of KCl (potassium chloride) can be calculated by summing the atomic masses of potassium (K) and chlorine (Cl). The atomic mass of K is 39.10 g/mol and the atomic mass of Cl is 35.45 g/mol. Therefore, the formula weight of KCl is 39.10 g/mol + 35.45 g/mol = 74.55 g/mol.

b. To calculate the mass of KCl in the solution, we need to convert the given amount of KCl in moles to grams. Since 1 mole of KCl has a mass of 74.55 g (as calculated in part a), 1.23 mol of KCl will have a mass of 1.23 mol x 74.55 g/mol = 91.39 g.

c. The percent by mass of KCl in the solution can be calculated by dividing the mass of KCl (91.39 g, as calculated in part b) by the mass of the solution and multiplying by 100%. The mass of the solution is given as 1000.0 g. Therefore, the percent by mass of KCl in the solution is (91.39 g / 1000.0 g) x 100% = 9.14%.

d. The molarity of the solution can be calculated by dividing the number of moles of KCl by the volume of the solution in liters. The number of moles of KCl is given as 1.23 mol and the volume of the solution is 1000.0 g of water, which is equivalent to 1000.0 mL or 1.0000 L. Therefore, the molarity of the solution is 1.23 mol / 1.0000 L = 1.23 M.

Practice Explaining Heat Flow
Examine the image showing a pan of boiling
eggs on a gas burner. What is the path of heat
flow?

a) hot gas - pan -> eggs - water
b) pan ->hot gas - eggs > Water
c) burning gas - pan -* water - eggs
d) eggs — water - burner - pan
e) pan - water - eggs - burner
Dona​

Answers

Answer:

The right choice is "burning gas → pan → water → eggs"

Explanation:

Heat will flow from the body of higher temperature to the cooler body.

So, heat will firstly flow from burning gas to pan by conduction then to the water in contact with pan then to the egg present inside the water.

So, the right choice is :

"burning gas → pan → water → eggs"

Answer: Option (c) is the correct answer.

Explanation:

When two objects of different temperature come in contact with each other then heat will flow from hot object to cold object. This process of transfer of heat is known as conduction.

For example, a pan of boiling  eggs on a gas burner will have transfer of heat from gas burner to the pan and then heat will flow from water to the eggs.

This process is also a conduction process.

Thus, we can conclude that the path of heat  flow will be as follows.

        [tex]\text{burning gas} \rightarrow \text{pan} \rightarrow \text{water} \rightarrow \text{eggs}[/tex]

Select all the correct answers.

An uncovered pot of water lies out in the sun. Which statements correctly describe what happens at the surface of the liquid water?

The vapor pressure remains constant regardless of the water temperature.
The vapor pressure is produced by water molecules that have evaporated.
The vapor pressure increases as the Sun heats the water in the pot.
Evaporation stops once the vapor pressure reaches a certain point.
Evaporation and condensation both occur on the liquid’s surface.

Answers

Answer:

I believe two correct statements are;

The vapor pressure is produced by water molecules that have evaporated.

The vapor pressure increases as the Sun heats the water in the pot.

Explanation:

When an uncovered pot of water lies out in the sun then the vapor pressure is produced by water molecules that have evaporated and increases as the Sun heats.

What is vapor pressure?

Vapor pressure is a property of the substance which may change into gaseous state.

When an uncovered pot of water lies out in the sun, then the vapor pressure is produced by the water molecules of the surface phase and they get evaporated. And due to heat transfer by the sun in the form of sunlight vapor pressure of water also increases, which results into more evaporation.

Hence, option (2) and (3) is correct it means vapor pressure increases as the sun heats the water in the pot and they get evaporated.

To know more about vapor pressure, visit the below link:

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If you had a 0.5 M KCl solution, how much solute would you have in moles, and what would the solute be?

Since KCl has a molecular weight of 74.5, how many grams/L would this be?

Answers

Answer:

37.25 grams/L.

Explanation:

Molarity (M) is defined as the no. of moles of solute dissolved per 1.0 L of the solution.

M = (no. of moles of KCl)/(volume of the solution (L))

∵ no. of moles of KCl = (mass of KCl)/(molar mass of KCl)

∴ M = [(mass of KCl)/(molar mass of KCl)]/(volume of the solution (L))

∴ (mass of KCl)/(volume of the solution (L)) = (M)*(molar mass of KCl) = (0.5 M)*(74.5 g/mol) = 37.25 g/L.

So, the grams/L of KCl = 37.25 grams/L.

In a 0.5 M KCl solution, there are 0.5 moles of KCl per liter. Given the molecular weight of KCl is 74.5 g/mol, this would translate to 37.25 grams of KCl per liter.

If you have a 0.5 M KCl solution, this means that the concentration of KCl in the solution is 0.5 moles per liter. To find the amount of solute in moles, you would simply use the concentration of the solution and the volume of the solution. In this case, if you have a 1-liter solution, you will have 0.5 moles of KCl, since the concentration is 0.5 M.

To convert this amount in moles to grams, you will need to use the molecular weight of KCl, which is given as 74.5 g/mol. By multiplying the number of moles by the molecular weight, you get the grams of the solute:

0.5 moles × 74.5 g/mol = 37.25 grams of KCl

Therefore, in a 1-liter solution of 0.5 M KCl, you would have 37.25 grams of KCl.

14. Which of the following is an example of an epeirogenic process?
O
O A. A rift valley forms at a divergent boundary where two plates are stretched apart.
B. A large plateau forms in the interior of a continental plate when a large section of the plate rises evenly due to an even expansion of the underlying mantle
O C. Mountains form along a convergent plate boundary when two plates collide, causing rock to bunch and buckle upward
O D. Mountains form along a convergent plate boundary when an oceanic plate slips beneath a continental plate, resulting in an upward force on the continental plate

Answers

Answer:

A large plateau forms in the interior of a continental plate when a large section of the plate rises evenly due to an even expansion of the underlying mantle. B.

Answer: Option (A) and (D)

Explanation: Epeirogenic process refers to the uplifting and sinking of the continental crust. It is the vertical movement of the crust due to certain mechanisms. Divergent movement of the plates leads to the thinning of the crust and in the convergent plate boundary between a continent and oceanic plate, creates an accretionary wedge that increases the vertical height of the crust. It is not related to the continental collision and plateaus are the stable part of the continent where there is not much change in the thickness of the crust.

Thus the correct answers are (A) and (D)

How to make slime without glue or cornstarch​

Answers

Hopefully this is close to what you looking for

One way :

-Dawn soap

-some water

-Salt crystals

-Put in freezer for a few hours

-StarGaze

(if this doesn't work comment)

I suggest using a little bit first, to see if it works for you.

what is the concentration of an NaOH solution that requires 50 mL of a 1.25 M H2SO4 solution to neutralize 78.0 ml of NaOH​

Answers

Answer:

The answer is the concentration of an NaOH = 1.6 M

Explanation:

The most common way to solve this kind of problem is to use the formula  

C₁ * V₁ = C₂ * V₂

In your problem,

For NaOH

C₁ =??     v₁= 78.0 mL = 0.078 L

For H₂SO₄

C₁ =1.25 M     v₁= 50.0 mL = 0.05 L

but you must note that for the reaction of NaOH with H₂SO₄

2 mol of NaOH raect with 1 mol H₂SO₄

So, by applying in above formula

C₁ * V₁ = 2 * C₂ * V₂ (C₁ * 0.078 L) = (2*  1.25 M * 0.05 L)C₁ = (2*  1.25 M * 0.05 L) / (0.078 L) = 1.6 M  

So, the answer is the concentration of an NaOH = 1.6 M

if .40 L if water is added to the volume of cup 3, what would be the new molarity of a 2 M solution of kool-aid

Answers

Answer:

0.7692 M ≅ 0.77 M.

Explanation:

It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.It can be expressed as:

(MV) before dilution = (MV) after dilution.

M before dilution = 2.0 M, V before dilution = 0.25 L.

M after dilution = ??? M, V after dilution = 0.25 L + 0.40 L = 0.65 L.

M after dilution = (MV) before dilution/(V) after dilution = (2.0 M)(0.25 L)/(0.65 L) = 0.7692 M ≅ 0.77 M.

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