The Mississippi River is about 4,000 kilometers long. An M&M is about 1 centimeter long. There are 100 centimeters in a meter, and 1,000 meters in a kilometer. Estimate how many M&Ms it would take to measure the length of the Mississippi River

Answers

Answer 1
To be able to determine the number of M&Ms that are needed in order to measure the length of Mississippi River, we convert the units to a common one. For this purpose, we convert kilometers to centimeter such that,
 
Length of Mississippi River = (4000 km)(1000 m/1 km)(100 cm/1 m)
                       = 400,000,000 cm

Since there are 400,000,000 cm in the entire length of the river, the answer would also be 400,000,000. 
Answer 2

To measure the approximately 4,000 km long Mississippi River with M&Ms, we will need about 400,000,000 M&Ms, as there are 100 cm in a meter and 1,000 m in a km.

The question involves estimating the length of the Mississippi River using the size of M&Ms as a unit of measurement. Since the river is about 4,000 kilometers long and the standard unit of length in the SI system is the meter, we need to convert kilometers to centimeters to match the size of an M&M, which is about 1 centimeter long. There are 100 centimeters in a meter, and 1,000 meters in a kilometer. Therefore, we have:

Convert kilometers to meters: 4,000 km x 1,000 m/km = 4,000,000 m.Convert meters to centimeters: 4,000,000 m x 100 cm/m = 400,000,000 cm.

Now, since each M&M is 1 centimeter, the number of M&Ms needed to measure the length of the Mississippi River is equal to the total number of centimeters:

400,000,000 M&Ms would be required to measure the approximate length of the Mississippi River.


Related Questions

Elspeth knows that PI r=9.42cm. What would she need to do to find the circumference?

Answers

Take that pi = 3.142

pi r = 9.42
r = 9.42/3.142 = 2.998
d = 2 x 2.998 = 5.996
Cricumference = 3.142 x 5.996 = 18.839 cm

You need to get the radius then multiply by 2 to get the diameter then you can get the circumference.

The answer would be A! :)

which of the following represents the factorization of the trinomal below

Answers

B is the correct answer. If you use the distributive property correctly you will see why.

(4x+3)(2x+1)= 8x^2+4x+6x+3
= 8x^2+10x+3


please vote my answer brainliest. thanks!

Don James wants to invest $55,000 to earn $6260 per year. he can invest in B-rates bonds paying 14% per year or in a certificate of Deposit (CD) paying 8% per year. How much money should be invested in each to realize exactly $6260 in interest per year?

Answers

don james payed for (CD) paying $6,337

You earn $20 per hour doing landscaping work your total earnings depend on the amount of hours you spend landscaping what is the independent variable

Answers

The amount earned per hour
The number of hours would be the independent (x-value), while the total amount you earn is the dependent variable.

What is the common ratio for the geometric sequence? 54,36,24,16... Enter your answer in the box.

Answers

The common ratio of the geometric sequence is: 2/3.

Common Ratio of a Geometric Sequence

Common ratio, r = a term divided by the consecutive term in the series.

Given the geometric sequence, 54,36,24,16...

common ratio (r) = 16/24 = 2/3.

24/36 = 2/3.

36/54 = 2/3.

Therefore, the common ratio of the geometric sequence is: 2/3.

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A professor has recorded exam grades for 20 students in his class, but one of the grades is no longer readable. If the mean score on the exam was 81 and the mean of the 19 readable scores is 85, what is the value of the unreadable score?

Answers

20 students....mean score of exam was 81...

x / 20 = 81
x = 81 * 20
x = 1620....this is the total of all the grades added up

(1620 - x) / 19 = 85
1620 - x = 85 * 19
1620 - x = 1615
-x = 1615 - 1620
-x = - 5
x = 5 <=== weird answer...but thats what I am getting

The value of the unreadable score is [tex]5[/tex]

It should be noted that the mean of numbers simply means the average of the numbers.

Since the mean score of the 20 students was 81, then the total score will be: [tex]= 20 * 81= 1620[/tex]

Then, since the mean score of the 19 students was 85, their total scores will be: = [tex]19 * 85 = 1615[/tex]

The value of the unreadable score will be:

[tex]= 1620 - 1615 = 5[/tex].

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Fractions EXPLAIN your answer.

Answers

Answer and explanation included in the photo

Find the exact value of cos pi/12 using half angle identities

Answers

[tex]\bf cos\left(\cfrac{{{ \theta}}}{2}\right)=\pm \sqrt{\cfrac{1+cos({{ \theta}})}{2}}\\\\ -------------------------------\\\\ \cfrac{\pi }{12}\cdot 2\implies \cfrac{\pi }{6}\qquad therefore\qquad \cfrac{\quad \frac{\pi }{6}\quad }{2}\implies \cfrac{\pi }{12}\qquad then \\\\\\ cos\left( \frac{\pi }{12} \right)\implies cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{1+cos\left( \frac{\pi }{6} \right)}{2}}[/tex]

[tex]\bf cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{\frac{2+\sqrt{3}}{2}}{2}} \\\\\\ cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{2+\sqrt{3}}{4}}\implies cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{4}} \\\\\\ cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\cfrac{\sqrt{2+\sqrt{3}}}{2}[/tex]

Answer:

[tex]\cos \left(\frac{\pi }{12}\right)=\frac{\sqrt{2+\sqrt{3}}}{2}[/tex]

Step-by-step explanation:

To find the exact value of [tex]\cos \left(\frac{\pi }{12}\right)[/tex] using half angle identities you must:

Write [tex]\cos \left(\frac{\pi }{12}\right)[/tex] as [tex]\cos \left(\frac{\frac{\pi }{6}}{2}\right)[/tex]

Using the half angle identity [tex]\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}[/tex]

[tex]\cos \left(\frac{\frac{\pi }{6}}{2}\right)=\sqrt{\frac{1+\cos \left(\frac{\pi }{6}\right)}{2}}[/tex]

Use the following identity: [tex]\cos \left(\frac{\pi }{6}\right)=\frac{\sqrt{3}}{2}[/tex]

[tex]\sqrt{\frac{1+\cos \left(\frac{\pi }{6}\right)}{2}}=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}[/tex]

Join [tex]1+\frac{\sqrt{3}}{2}[/tex]

[tex]1+\frac{\sqrt{3}}{2}=\frac{1\cdot \:2}{2}+\frac{\sqrt{3}}{2}=\frac{2+\sqrt{3}}{2}[/tex]

[tex]\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2} } =\sqrt{\frac{2+\sqrt{3}}{4}} =\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}=\frac{\sqrt{2+\sqrt{3}}}{2}[/tex]

Therefore,

[tex]\cos \left(\frac{\pi }{12}\right)=\frac{\sqrt{2+\sqrt{3}}}{2}[/tex]

justin sold 300 liter of soda at a baseball game.how much is this in milliliters?

Answers

If Justin sold 300 liters of soda, then he would have sold 300000 milliliters of soda. 1 liter= 1000 milliliters

Answer:

300,000 mililiters

Step-by-step explanation:

Remember that in international system the convertions are really easy because they are done 10 by 10, so from liters to mili, there are 3 spots, 1000, so there are 1000 mili-liters in a liter, so you just need to multiply the 300 liters of soda by 1000, which is 300,000 mililiters and that is what Justin sold at the baseball game in mililiters.

A random variable x takes four possible values, 0, 2, a, and b, where a and b are unknown numbers. if pr[x = 0] = 0.2, pr[x=2] = 0.4, pr[x = a] = 0.3, e[x] = 2.8 and it is the case that a + b = 6, what is the missing value of a ?
a.-1.0
b.5.0
c.7.0
d.cannot be determined without more information
e.none of the above

Answers

Final answer:

The missing value of the random variable X can be determined by solving the equation e[x] = 2.8 and substituting the known values. By solving the equation, we find that the missing value is c. 7.

Explanation:

a. In words, X = A random variable that takes four possible values: 0, 2, a, and b.

b. X~ A missing value that represent an unknown number for the random variable X.

c. In words, X = The missing value of the random variable X, denoted by a.

d. X A missing value that we need to determine.

In this case, the missing value of a can be found by substituting the known values into the equation a + b = 6. Since b = 6 - a, we can substitute this expression into the equation e[x] = 2.8 and solve for a. From the equation, we get 0.2(0) + 0.4(2) + 0.3(a) + 0.3(6 - a) = 2.8.

Solving this equation gives us a = 7. Therefore, the missing value of a is 7, so the correct answer is c.

Urn A contains 8 yellow balls and 6 red balls. Urn B contains 3 yellow balls and 9 red balls. Urn C contains 4 yellow balls and 11 red balls. An urn is picked randomly (assume that each urn is equally likely to be chosen), and then a ball is picked from the selected urn. What is the probability that the chosen ball came from urn B, given that it was a yellow ball? a) 0.2451 b) 0.0725 c) 0.2298 d) 0.0544 e) 0.5252 f) None of the above.

Answers

Final answer:

The probability that a chosen ball came from Urn B, given that it was a yellow ball, is 20%, which isn't reflected in any of the provided options, making (f) None of the above the right answer.

Explanation:

To answer the question, we first need to calculate the total number of yellow balls in all urns, which is, 8 (from Urn A) + 3 (from Urn B) + 4 (from Urn C) = 15. But we are interested only in the case where the yellow ball came from Urn B, the number of which is 3. So, the probability that a yellow ball came from Urn B represents the ratio of the number of yellow balls in Urn B to the total number of yellow balls. Thus, the probability would be calculated as 3 (yellow balls in Urn B) / 15 (total yellow balls) = 0.20 or 20%. Therefore, the correct answer in the given options is (f) None of the above.

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A food truck sells salads for $6.50 each and drinks for $2.00 each. The food truck’s revenue from selling a total of 209 salads and drinks in one day was $836.50. How many salads were sold that day? A) 77 B) 93 C) 99 D) 105

Answers

Create an equation to figure out how much salad was sold that day. S is for the number of salads. D is for the number of drinks.

$6.5s + $2d = $836.5
s + d = 209
s = 209 - d

Plug in the values. 

6.5 (209 - d) + 2d = 836.5

1358.5 - 6.5d + 2d = 836.5
-4.5d = -522
d = 116

s = 209 - 116
= 93

Answer: Letter B 

Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or post another question and send the link to me. -UnicornFudge aka Nadia 
its d I think I'm not sure I'm in class so I can't help that well

When integrating polar coordinates, when should one use the polar differential element, [tex]rdrd \theta [/tex]
and when should one just use[tex]drd \theta [/tex] ?

For instance, do you use the former or latter if changing to polar variables when solving a surface integral?

Answers

To answer your first question: Whenever you convert from rectangular to polar coordinates, the differential element will *always* change according to

[tex]\mathrm dA=\mathrm dx\,\mathrm dy\implies\mathrm dA=r\,\mathrm dr\,\mathrm d\theta[/tex]

The key concept here is the "Jacobian determinant". More on that in a moment.

To answer your second question: You probably need to get a grasp of what the Jacobian is before you can tackle a surface integral.

It's a structure that basically captures information about all the possible partial derivatives of a multivariate function. So if [tex]\mathbf f(\mathbf x)=(f_1(x_1,\ldots,x_n),\ldots,f_m(x_1,\ldots,x_n))[/tex], then the Jacobian matrix [tex]\mathbf J[/tex] of [tex]\mathbf f[/tex] is defined as

[tex]\mathbf J=\begin{bmatrix}\mathbf f_{x_1}&\cdots&\mathbf f_{x_n}\end{bmatrix}=\begin{bmatrix}{f_1}_{x_1}&\cdots&{f_m}_{x_n}\\\vdots&\ddots&\vdots\\{f_m}_{x_1}&\cdots&{f_m}_{x_n}\end{bmatrix}[/tex]

(it could be useful to remember the order of the entries as having each row make up the gradient of each component [tex]f_i[/tex])

Think about how you employ change of variables when integrating a univariate function:

[tex]\displaystyle\int2xe^{x^2}\,\mathrm dr=\int e^{x^2}\,\mathrm d(x^2)\stackrel{y=x^2}=\int e^y\,\mathrm dy=e^{r^2}+C[/tex]

Not only do you change the variable itself, but you also have to account for the change in the differential element. We have to express the original variable, [tex]x[/tex], in terms of a new variable, [tex]y=y(x)[/tex].

In two dimensions, we would like to express two variables, say [tex]x,y[/tex], each as functions of two new variables; in polar coordinates, we would typically use [tex]r,\theta[/tex] so that [tex]x=x(r,\theta),y=y(r,\theta)[/tex], and

[tex]\begin{cases}x(r,\theta)=r\cos\theta\\y(r,\theta)=r\sin\theta\end{cases}[/tex]

The Jacobian matrix in this scenario is then

[tex]\mathbf J=\begin{bmatrix}x_r&y_\theta\\y_r&y_\theta\end{bmatrix}=\begin{bmatrix}\cos\theta&-r\sin\theta\\\sin\theta&r\cos\theta\end{bmatrix}[/tex]

which by itself doesn't help in integrating a multivariate function, since a matrix isn't scalar. We instead resort to the absolute value of its determinant. We know that the absolute value of the determinant of a square matrix is the [tex]n[/tex]-dimensional volume of the parallelepiped spanned by the matrix's [tex]n[/tex] column vectors.

For the Jacobian, the absolute value of its determinant contains information about how much a set [tex]\mathbf f(S)\subset\mathbb R^m[/tex] - which is the "value" of a set [tex]S\subset\mathbb R^n[/tex] subject to the function [tex]\mathbf f[/tex] - "shrinks" or "expands" in [tex]n[/tex]-dimensional volume.

Here we would have

[tex]\left|\det\mathbf J\right|=\left|\det\begin{bmatrix}\cos\theta&-r\sin\theta\\\sin\theta&r\cos\theta\end{bmatrix}\right|=|r|[/tex]

In polar coordinates, we use the convention that [tex]r\ge0[/tex] so that [tex]|r|=r[/tex]. To summarize, we have to use the Jacobian to get an appropriate account of what happens to the differential element after changing multiple variables simultaneously (converting from one coordinate system to another). This is why

[tex]\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta[/tex]

when integrating some two-dimensional region in the [tex]x,y[/tex]-plane.

Surface integrals are a bit more complicated. The integration region is no longer flat, but we can approximate it by breaking it up into little rectangles that are flat, then use the limiting process and add them all up to get the area of the surface. Since each sub-region is two-dimensional, we need to be able to parameterize the entire region using a set of coordinates.

If we want to find the area of [tex]z=f(x,y)[/tex] over a region [tex]\mathcal S[/tex] - a region described by points [tex](x,y,z)[/tex] - by expressing it as the identical region [tex]\mathcal T[/tex] defined by points [tex](u,v)[/tex]. This is done with

[tex]\mathbf f(x,y,z)=\mathbf f(x(u,v),y(u,v),z(u,v))[/tex]

with [tex]u,v[/tex] taking on values as needed to cover all of [tex]\mathcal S[/tex]. The Jacobian for this transformation would be

[tex]\mathbf J=\begin{bmatrix}x_u&x_v\\y_u&y_v\\z_u&z_v\end{bmatrix}[/tex]

but since the matrix isn't square, we can't take a determinant. However, recalling that the magnitude of the cross product of two vectors gives the area of the parallelogram spanned by them, we can take the absolute value of the cross product of the columns of this matrix to find out the areas of each sub-region, then add them. You can think of this result as the equivalent of the Jacobian determinant but for surface integrals. Then the area of this surface would be

[tex]\displaystyle\iint_{\mathcal S}\mathrm dS=\iint_{\mathcal T}\|\mathbf f_u\times\mathbf f_v\|\,\mathrm du\,\mathrm dv[/tex]

The takeaway here is that the procedures for computing the volume integral as opposed to the surface integral are similar but *not* identical. Hopefully you found this helpful.

Find all the local maxima, local minima, and saddle points of the function

Answers

what function can you post it please and thank you

Final answer:

To find local maxima, minima, and saddle points, find critical points using the first derivative test and then apply the second derivative test.

Explanation:

To find the local maxima, local minima, and saddle points of a function, we first need to find the critical points. These are the points where the derivative of the function is either zero or undefined. To check whether each critical point is a local maxima, local minima, or saddle point, we use the second derivative test.

The second derivative test states that if the second derivative is positive at a critical point, then the point is a local minimum. If the second derivative is negative, then the point is a local maxima. If the second derivative is zero, the test is inconclusive.

By applying the second derivative test to each critical point, we can determine whether it is a local maxima, local minima, or saddle point.

Which property is shown in the following equation?

20 x 1 = 20

A. Zero property of multiplication

B. Identify property of multiplication

C. Negative one property of multiplication

D. Identify property of division

Answers

The answer for this question would be B) Identify property of multiplication or the second option because since the result 20 is the same as the 20 multiplied against 1. * I take no credit for the image below I just found it off google. ✅

Final answer:

The equation 20 x 1 = 20 demonstrates the Identity Property of Multiplication, which states that multiplying any number by one keeps its original value.

Explanation:

The property shown in the following equation 20 x 1 = 20 is the Identity Property of Multiplication. This property states that any number multiplied by one remains unchanged or that the number keeps its identity. The option B, Identify property of multiplication, is a typo, and it likely means to refer to the Identity Property of Multiplication. The options A, C, and D describe different properties that do not apply to this equation.

The Zero Property of Multiplication involves a multiplication where any number times zero is zero. The Negative One Property of Multiplication is not a standard mathematical property and seems to be a non-existent or misspelled option. The Identity Property of Division is not applicable as there is no division taking place in this equation.

A random sample of is selected from this population. find the probability that the sample mean is greater than 2.1 but less than 2.5.

Answers

its 2.2 less than 2.5 and greater than 2.1

What is the next letter a,z,e,b,I,y,o

Answers

The next letter in the sequence should be "C". This is because the odd numbered letters are vowels "A,E,I,O" and the even numbered letters are the are a letter from the end of the alphabet and then  number from the beginning e.g. "Z,B,Y" therefore the next letter in the sequence would have to be "C". If this question helped please make it Brainliest. Thanks.

given the rectangle below, which of the following transformations will map the figure onto itself?

Answers

The answer is the option B. rotate 90 degrees counterclokwise and then rotate 270 degrees counterclockwise.

See that two consecutive rotations counterclockwise are equivalent to one single roration counterclockwise as long as the angles sum up the same.

Given that 90° + 270 ° = 360° means that the two rotaions are equivalent to one 360° rotation, and so the final figure will be the same as the original figure.

2/5 of the students in your class are in band. Of these 1/4 play the saxophone. What fraction of your class plays the saxophone?2

Answers

2/5 are in band...of those, 1/4 play saxophone....so 1/4 of 2/5 play saxophone....." of " means multiply

1/4 * 2/5 = 2/20 which reduces to 1/10 <== 1/10 play saxophone

Answer:

1/10=10%

Step-by-step explanation:

In order to calculate this you just have to multiply the fraction of kids of your class that are in the ban by the number of kids that play the saxophone from those kids that are in the band:

[tex]\frac{2}{5} *\frac{1}{4}\\\frac{2*1}{4*5}\\\frac{2}{20}=\frac{1}{10}  \\\frac{1}{10}[/tex]

So we know that 1/10 or 1 out of 10 kids in your class play saxophone in the band, or 10%of the class plays saxophone in the band.

Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed

Answers

Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
                                                                     34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
                                                                             1.9

Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

A software designer is mapping the streets for a new racing game. All of the streets are depicted as either perpendicular or parallel lines. The equation of the lane passing through A and B is -7x + 3y = -21.5. What is the equation of the central street PQ?

Answers

Final answer:

The equation of the central street PQ can be found by using the negative reciprocal of the slope of the given street and a point on the central street. The equation is y - 4 = (-3/7)(x + 1).

Explanation:

To find the equation of the central street PQ, we need to determine the slope and y-intercept of the given equation. The equation -7x + 3y = -21.5 can be rearranged to y = (7/3)x - 21.5/3, which means the slope is 7/3 and the y-intercept is -21.5/3. Since the central street is perpendicular to the given street, its slope will be the negative reciprocal of 7/3, which is -3/7. Using the point-slope form of a line equation, we can write the equation of the central street PQ using point P(-1, 4) as follows:

y - 4 = (-3/7)(x + 1)

We can simplify this equation further if required.

Final answer:

To find the equation of street PQ, one must understand that parallel streets share the same slope, while perpendicular streets have slopes that are negative reciprocals. The given street AB has a slope of 7/3. The slope of PQ will either be 7/3 (if parallel) or -3/7 (if perpendicular), and additional information is needed to determine its y-intercept.

Explanation:

The subject question involves finding the equation of a street that is either parallel or perpendicular to another street, given in the form of a linear equation. The given equation of the street passing through points A and B is -7x + 3y = -21.5. To determine the equation of the central street PQ, which is either parallel or perpendicular, we need to use concepts of slope.

In the case of a parallel street, the slope must be the same as the slope of the given street, while for a perpendicular street, the slope would be the negative reciprocal of the given street's slope. Since we're not given additional information about the relationship between AB and PQ, we can only speculate based on the slope. The slope-intercept form of an equation, y = mx + b where 'm' represents the slope and 'b' represents the y-intercept, is useful in determining the proper equation for street PQ.

For the given equation, -7x + 3y = -21.5, we first need to rewrite it in slope-intercept form to identify the slope: 3y = 7x - 21.5, which simplifies to y = (7/3)x - 7.17. Here, the slope of the line is (7/3). Thus, the slope of street PQ will be either (7/3) if it's parallel, or -3/7 if it's perpendicular. To find the exact equation, we would need a point that street PQ passes through.

Suppose f−1 is the inverse of a differentiable function f and f(4) = 0, f′(4) = 1. find (f−1)′(0).

Answers

Give me a heart and I'll tell you the answer

rob cuts a 15-foot wire into 8 equal pieces.about how long is each piece ?

Answers

15/8 = 1.875 ft per piece....so each piece is just short of 2 ft
Divide 15 by 8 to get 1.875. Each piece is 1.875 feet long.

Please give me brainliest answer.

Find the limit. lim θ→0 sin(3θ) θ + tan(4θ)

Answers

Answer:

[tex]\displaystyle \lim_{\theta \to 0} \sin (3\theta)\theta + \tan (4\theta) = 0[/tex]

General Formulas and Concepts:

Pre-Calculus

Unit Circle

Calculus

Limits

Limit Rule [Variable Direct Substitution]:                                                             [tex]\displaystyle \lim_{x \to c} x = c[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \lim_{\theta \to 0} \sin (3\theta)\theta + \tan (4\theta)[/tex]

Step 2: Evaluate

Limit Rule [Variable Direct Substitution]:                                                    [tex]\displaystyle \lim_{\theta \to 0} \sin (3\theta)\theta + \tan (4\theta) = \sin(0) \cdot 0 + tan(0)[/tex]Simplify:                                                                                                         [tex]\displaystyle \lim_{\theta \to 0} \sin (3\theta)\theta + \tan (4\theta) = 0[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Mrs Rivera baked 112 cookies there are 28 students in her class how many cookies will each student receive

Answers

The students will each receive 4 cookies, you divide 112 from 28 and it is 4.

Final answer:

Each student will receive 4 cookies.

Explanation:

To find out how many cookies each student will receive, we need to divide the total number of cookies by the number of students. In this case, Mrs. Rivera baked 112 cookies and there are 28 students, so we can divide 112 by 28 to find the answer.

Divide 112 by 28: 112 ÷ 28 = 4Therefore, each student will receive 4 cookies.

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If p(a) = 0.25 and p(b) = 0.65, assuming independence of events, then p(a and
b.is:

Answers

0.25x0.65=0.1625
full answer

The Independent events is 0.1625.Events A and B are considered independent if the likelihood of each event's occurrence is unaffected by the occurrence of the other.

Find the independent events?

P(A/B) is equal to P(A.B)/P(B) by definition (A). P(A) = P(B) / P(B) (as A, B are Independent events).

Events A and B are considered independent if the likelihood of each event's occurrence is unaffected by the occurrence of the other. P(A) = P(AB) = 1/2, which suggests that the likelihood of event A occurring has not changed as a result of the occurrence of event B.

P(0.25) = P(0.25 * 0.65) = 1/2

P(0.25) = 0.1625.

The Independent events is 0.1625 .

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what is x in _-18x−45=-12_

Answers

Hello there~

-18x - 45 = -12

Let's start by adding 45 to both sides

-18x - 45 + 45 = -12 + 45

-18x = 33

Then divide both sides by -18

-18x/-18 = 33/-18

x = -11/6

I hope this helps!

Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels 20 miles per hour faster than the westbound train. If the two trains are 750 miles apart after 5 hours, what is the rate of the eastbound train?

Answers

east bound train = x

westbound train = x-20 ( 20 miles slower than east bound)

5x + 5(x-20) = 750

5x +5x -100=750

10x -100 = 750

10x =850

x = 850/10 = 85

east bound train is 85 mph

west bound train is 85-20 = 65 mph


check: 85*5 = 425

65*5 = 325

325+425 = 750

simplify the complex fraction. 9/y/6/y-7

Answers

[tex]\bf \cfrac{\quad \frac{9}{y}\quad }{\frac{6}{y-7}}\implies \cfrac{9}{y}\cdot \cfrac{y-7}{6}\implies \cfrac{9}{6}\cdot \cfrac{y-7}{y}\implies \cfrac{3}{2}\cdot \cfrac{y-7}{y}\implies \cfrac{3y-21}{2y}[/tex]

A microwave is placed on top of two boxes. One box is 2 feet 5 inches tall the other box is 3 feet 11 inches tall and the other microwave is 3 feet 3 inches tall how tall are they combined?

Answers

Combined they are 9 feet 7 inches tall.
9 feet and 7 inches or 115 inches
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